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Create and use Object Variable

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3

How do I create an "Object" variable with two fields inside and assign value to these fields through this "for":

 for(RecordTypeInfo info: Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) 
 if(info.isAvailable()) 
 //Here i would add the value of the variables "info.getRecordTypeId(), info.getName()"
 //in Object Name and Id fields.

 //myObject.Name = info.getName();
 //myObject.Name = info.getRecordTypeId();
 
 

I imagined an object variable like:

Object myObject = Name, Id

But I don't think that's how you create it. And if it is not ideal to use variable "Object" what would it be?

apex lightning

share|improve this question

asked 8 hours ago

Diego Edargo PessoaDiego Edargo Pessoa

1822 bronze badges

New contributor

Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

3

How do I create an "Object" variable with two fields inside and assign value to these fields through this "for":

 for(RecordTypeInfo info: Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) 
 if(info.isAvailable()) 
 //Here i would add the value of the variables "info.getRecordTypeId(), info.getName()"
 //in Object Name and Id fields.

 //myObject.Name = info.getName();
 //myObject.Name = info.getRecordTypeId();
 
 

I imagined an object variable like:

Object myObject = Name, Id

But I don't think that's how you create it. And if it is not ideal to use variable "Object" what would it be?

apex lightning

share|improve this question

asked 8 hours ago

Diego Edargo PessoaDiego Edargo Pessoa

1822 bronze badges

New contributor

Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

How do I create an "Object" variable with two fields inside and assign value to these fields through this "for":

 for(RecordTypeInfo info: Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) 
 if(info.isAvailable()) 
 //Here i would add the value of the variables "info.getRecordTypeId(), info.getName()"
 //in Object Name and Id fields.

 //myObject.Name = info.getName();
 //myObject.Name = info.getRecordTypeId();
 
 

I imagined an object variable like:

Object myObject = Name, Id

But I don't think that's how you create it. And if it is not ideal to use variable "Object" what would it be?

apex lightning

share|improve this question

asked 8 hours ago

Diego Edargo PessoaDiego Edargo Pessoa

1822 bronze badges

New contributor

Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

 for(RecordTypeInfo info: Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) 
 if(info.isAvailable()) 
 //Here i would add the value of the variables "info.getRecordTypeId(), info.getName()"
 //in Object Name and Id fields.

 //myObject.Name = info.getName();
 //myObject.Name = info.getRecordTypeId();
 
 

Object myObject = Name, Id

share|improve this question

asked 8 hours ago

Diego Edargo PessoaDiego Edargo Pessoa

1822 bronze badges

New contributor

Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 8 hours ago

Diego Edargo PessoaDiego Edargo Pessoa

1822 bronze badges

New contributor

Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 8 hours ago

Diego Edargo PessoaDiego Edargo Pessoa

1822 bronze badges

New contributor

Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 8 hours ago

Diego Edargo PessoaDiego Edargo Pessoa

1822 bronze badges

2 Answers
2

active

oldest

votes

3

You can use List<Object> and List<List<Object>> to store different object like an array. Here is example

string name='Dhanik';
string id='111';
List<Object> myObject = new List<Object>name,id;
List<List<Object>> objects=new List<List<Object>>();
objects.add(myObject);
integer num1=1;
myObject = new List<Object>name,num1;
objects.add(myObject);
system.debug('myObject:' + objects);
system.debug('myObject:' + objects[0]);

share|improve this answer

answered 8 hours ago

Dhanik Lal SahniDhanik Lal Sahni

95733 silver badges1111 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! @Dhanik Lal Sahni
  
  – Diego Edargo Pessoa
  7 hours ago
  

  
  
  
  

add a comment | 

2

It is better to create separate strongly typed Apex class, if you want to use this data in lightning component.

public class RecordTypeInfoObj 
 @AuraEnabled
 public Id recordTypeId get;set;
 @AuraEnabled
 public String name get;set;

 public RecordTypeInfoObj(Id recordTypeId, String name) 
 this.recordTypeId = recordTypeId;
 this.name = name;
 

List<RecordTypeInfoObj> recTypeList = new List<RecordTypeInfoObj>();
for(RecordTypeInfo info : Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) 
 if(info.isAvailable()) 
 recTypeList.add(new RecordTypeInfoObj(info.recordTypeId, info.name));
 

In lightning component define the following attribute

<aura:attribute name="listOfRecordTypoInfos" type="RecordTypeInfoObj[]" />

share|improve this answer

answered 7 hours ago

BlackCatBlackCat

34711 silver badge1111 bronze badges

add a comment | 

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3

You can use List<Object> and List<List<Object>> to store different object like an array. Here is example

string name='Dhanik';
string id='111';
List<Object> myObject = new List<Object>name,id;
List<List<Object>> objects=new List<List<Object>>();
objects.add(myObject);
integer num1=1;
myObject = new List<Object>name,num1;
objects.add(myObject);
system.debug('myObject:' + objects);
system.debug('myObject:' + objects[0]);

share|improve this answer

answered 8 hours ago

Dhanik Lal SahniDhanik Lal Sahni

95733 silver badges1111 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! @Dhanik Lal Sahni
  
  – Diego Edargo Pessoa
  7 hours ago
  

  
  
  
  

add a comment | 

3

You can use List<Object> and List<List<Object>> to store different object like an array. Here is example

string name='Dhanik';
string id='111';
List<Object> myObject = new List<Object>name,id;
List<List<Object>> objects=new List<List<Object>>();
objects.add(myObject);
integer num1=1;
myObject = new List<Object>name,num1;
objects.add(myObject);
system.debug('myObject:' + objects);
system.debug('myObject:' + objects[0]);

share|improve this answer

answered 8 hours ago

Dhanik Lal SahniDhanik Lal Sahni

95733 silver badges1111 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! @Dhanik Lal Sahni
  
  – Diego Edargo Pessoa
  7 hours ago
  

  
  
  
  

add a comment | 

You can use List<Object> and List<List<Object>> to store different object like an array. Here is example

string name='Dhanik';
string id='111';
List<Object> myObject = new List<Object>name,id;
List<List<Object>> objects=new List<List<Object>>();
objects.add(myObject);
integer num1=1;
myObject = new List<Object>name,num1;
objects.add(myObject);
system.debug('myObject:' + objects);
system.debug('myObject:' + objects[0]);

share|improve this answer

answered 8 hours ago

Dhanik Lal SahniDhanik Lal Sahni

95733 silver badges1111 bronze badges

string name='Dhanik';
string id='111';
List<Object> myObject = new List<Object>name,id;
List<List<Object>> objects=new List<List<Object>>();
objects.add(myObject);
integer num1=1;
myObject = new List<Object>name,num1;
objects.add(myObject);
system.debug('myObject:' + objects);
system.debug('myObject:' + objects[0]);

share|improve this answer

answered 8 hours ago

Dhanik Lal SahniDhanik Lal Sahni

95733 silver badges1111 bronze badges

answered 8 hours ago

Dhanik Lal SahniDhanik Lal Sahni

95733 silver badges1111 bronze badges

answered 8 hours ago

Dhanik Lal SahniDhanik Lal Sahni

95733 silver badges1111 bronze badges

2

It is better to create separate strongly typed Apex class, if you want to use this data in lightning component.

public class RecordTypeInfoObj 
 @AuraEnabled
 public Id recordTypeId get;set;
 @AuraEnabled
 public String name get;set;

 public RecordTypeInfoObj(Id recordTypeId, String name) 
 this.recordTypeId = recordTypeId;
 this.name = name;
 

List<RecordTypeInfoObj> recTypeList = new List<RecordTypeInfoObj>();
for(RecordTypeInfo info : Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) 
 if(info.isAvailable()) 
 recTypeList.add(new RecordTypeInfoObj(info.recordTypeId, info.name));
 

In lightning component define the following attribute

<aura:attribute name="listOfRecordTypoInfos" type="RecordTypeInfoObj[]" />

share|improve this answer

answered 7 hours ago

BlackCatBlackCat

34711 silver badge1111 bronze badges

add a comment | 

2

It is better to create separate strongly typed Apex class, if you want to use this data in lightning component.

public class RecordTypeInfoObj 
 @AuraEnabled
 public Id recordTypeId get;set;
 @AuraEnabled
 public String name get;set;

 public RecordTypeInfoObj(Id recordTypeId, String name) 
 this.recordTypeId = recordTypeId;
 this.name = name;
 

List<RecordTypeInfoObj> recTypeList = new List<RecordTypeInfoObj>();
for(RecordTypeInfo info : Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) 
 if(info.isAvailable()) 
 recTypeList.add(new RecordTypeInfoObj(info.recordTypeId, info.name));
 

In lightning component define the following attribute

<aura:attribute name="listOfRecordTypoInfos" type="RecordTypeInfoObj[]" />

share|improve this answer

answered 7 hours ago

BlackCatBlackCat

34711 silver badge1111 bronze badges

add a comment | 

It is better to create separate strongly typed Apex class, if you want to use this data in lightning component.

public class RecordTypeInfoObj 
 @AuraEnabled
 public Id recordTypeId get;set;
 @AuraEnabled
 public String name get;set;

 public RecordTypeInfoObj(Id recordTypeId, String name) 
 this.recordTypeId = recordTypeId;
 this.name = name;
 

List<RecordTypeInfoObj> recTypeList = new List<RecordTypeInfoObj>();
for(RecordTypeInfo info : Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) 
 if(info.isAvailable()) 
 recTypeList.add(new RecordTypeInfoObj(info.recordTypeId, info.name));
 

In lightning component define the following attribute

<aura:attribute name="listOfRecordTypoInfos" type="RecordTypeInfoObj[]" />

share|improve this answer

answered 7 hours ago

BlackCatBlackCat

34711 silver badge1111 bronze badges

public class RecordTypeInfoObj 
 @AuraEnabled
 public Id recordTypeId get;set;
 @AuraEnabled
 public String name get;set;

 public RecordTypeInfoObj(Id recordTypeId, String name) 
 this.recordTypeId = recordTypeId;
 this.name = name;
 

List<RecordTypeInfoObj> recTypeList = new List<RecordTypeInfoObj>();
for(RecordTypeInfo info : Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) 
 if(info.isAvailable()) 
 recTypeList.add(new RecordTypeInfoObj(info.recordTypeId, info.name));
 

<aura:attribute name="listOfRecordTypoInfos" type="RecordTypeInfoObj[]" />

share|improve this answer

answered 7 hours ago

BlackCatBlackCat

34711 silver badge1111 bronze badges

answered 7 hours ago

BlackCatBlackCat

34711 silver badge1111 bronze badges

answered 7 hours ago

BlackCatBlackCat

34711 silver badge1111 bronze badges