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The more + the + comparative degree
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Number in overlapping range
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Number in overlapping range
Shortest Port ScannerFinding Not-Quite-Prime NumbersA newly discovered number: bleen!Safety in numbersDo the circles intersect?Date within range?count ones in rangeThe first, the last, and everything betweenIs this Pascal's Matrix?Is it double speak?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
You are given two integers between lets say 1 and 12, one and two
and a integer between lets say 0 and 4 which is called range.
The challange is to decide if one is inside or equal the range from two ± range.
The range is restarting with 1 (one) after 12 (two) and vise versa.
For example, if one = 2, two = 11 and range = 3, the result is true, as one is the the range [8, 9, 10, 11, 12, 1, 2].
The input has to be 3 seperated integers, the order doesn't matter. Input via string with seperators possible. But the Input has to consist of numbers reading as '10' and not 'A' e.g.
Test cases:
one=7 two=6 range=0 result=false
one=5 two=6 range=1 result=true
one=8 two=11 range=3 result=true
one=1 two=11 range=3 result=true
one=2 two=10 range=3 result=false
one=11 two=1 range=2 result=true
one=6 two=1 range=4 result=false
one=12 two=1 range=3 result=true
Shortest valid answer in bytes wins.
code-golf decision-problem
edited 8 hours ago
Arnauld
90.1k7 gold badges105 silver badges366 bronze badges
asked 10 hours ago
Tom UngerTom Unger
142 bronze badges
New contributor
Tom Unger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
|
show 7 more comments
$begingroup$
You are given two integers between lets say 1 and 12, one and two
and a integer between lets say 0 and 4 which is called range.
The challange is to decide if one is inside or equal the range from two ± range.
The range is restarting with 1 (one) after 12 (two) and vise versa.
For example, if one = 2, two = 11 and range = 3, the result is true, as one is the the range [8, 9, 10, 11, 12, 1, 2].
The input has to be 3 seperated integers, the order doesn't matter. Input via string with seperators possible. But the Input has to consist of numbers reading as '10' and not 'A' e.g.
Test cases:
one=7 two=6 range=0 result=false
one=5 two=6 range=1 result=true
one=8 two=11 range=3 result=true
one=1 two=11 range=3 result=true
one=2 two=10 range=3 result=false
one=11 two=1 range=2 result=true
one=6 two=1 range=4 result=false
one=12 two=1 range=3 result=true
Shortest valid answer in bytes wins.
code-golf decision-problem
edited 8 hours ago
Arnauld
90.1k7 gold badges105 silver badges366 bronze badges
asked 10 hours ago
Tom UngerTom Unger
142 bronze badges
New contributor
Tom Unger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Welcome to the site! While this challenge is understandable, there are still a few issues. For example, why between 1 and 12, and 0 and 4 particularly? Also, please keep in mind that homework questions are not on-topic here, so if this is homework (or similar), I'd recommend loosening the requirements of the challenge (allowing the integers/range to be any number, etc.). Finally, what do you mean by "Restarting with 1 after 12 and vise versa."?
$endgroup$
– caird coinheringaahing
10 hours ago
$begingroup$
@cairdcoinheringaahing Hey thank you, I picked those numbers randomly, but two has to be bigger than one. How big the range is does not really matter. With restarting I mean that your range overlaps overtwoso ifoneis 2 andtwois 11 and therangeis 3,oneis still inside the range because it restarts attwowithone
$endgroup$
– Tom Unger
10 hours ago
$begingroup$
So ifoneis 2,twois 11, andrangeis 3, is the task basically to check ifoneis in the list[8, 9, 10, 11, 12, 1, 2]? That the range cycles round if it goes out of bounds?
$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
Exactly, sorry If my description was irritating
$endgroup$
– Tom Unger
9 hours ago
1
$begingroup$
oneandtworeally should be calledAandBfor the sake of clarity. Also, it's still unclear IMO what is given as input and what is a constant. Are $1$ and $12$ the input values, or are the input values guaranteed to be in $[1..12]$?
$endgroup$
– Arnauld
9 hours ago
|
show 7 more comments
$begingroup$
You are given two integers between lets say 1 and 12, one and two
and a integer between lets say 0 and 4 which is called range.
The challange is to decide if one is inside or equal the range from two ± range.
The range is restarting with 1 (one) after 12 (two) and vise versa.
For example, if one = 2, two = 11 and range = 3, the result is true, as one is the the range [8, 9, 10, 11, 12, 1, 2].
The input has to be 3 seperated integers, the order doesn't matter. Input via string with seperators possible. But the Input has to consist of numbers reading as '10' and not 'A' e.g.
Test cases:
one=7 two=6 range=0 result=false
one=5 two=6 range=1 result=true
one=8 two=11 range=3 result=true
one=1 two=11 range=3 result=true
one=2 two=10 range=3 result=false
one=11 two=1 range=2 result=true
one=6 two=1 range=4 result=false
one=12 two=1 range=3 result=true
Shortest valid answer in bytes wins.
code-golf decision-problem
edited 8 hours ago
Arnauld
90.1k7 gold badges105 silver badges366 bronze badges
asked 10 hours ago
Tom UngerTom Unger
142 bronze badges
New contributor
Tom Unger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
You are given two integers between lets say 1 and 12, one and two
and a integer between lets say 0 and 4 which is called range.
The challange is to decide if one is inside or equal the range from two ± range.
The range is restarting with 1 (one) after 12 (two) and vise versa.
For example, if one = 2, two = 11 and range = 3, the result is true, as one is the the range [8, 9, 10, 11, 12, 1, 2].
The input has to be 3 seperated integers, the order doesn't matter. Input via string with seperators possible. But the Input has to consist of numbers reading as '10' and not 'A' e.g.
Test cases:
one=7 two=6 range=0 result=false
one=5 two=6 range=1 result=true
one=8 two=11 range=3 result=true
one=1 two=11 range=3 result=true
one=2 two=10 range=3 result=false
one=11 two=1 range=2 result=true
one=6 two=1 range=4 result=false
one=12 two=1 range=3 result=true
Shortest valid answer in bytes wins.
code-golf decision-problem
code-golf decision-problem
edited 8 hours ago
Arnauld
90.1k7 gold badges105 silver badges366 bronze badges
asked 10 hours ago
Tom UngerTom Unger
142 bronze badges
New contributor
Tom Unger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited 8 hours ago
Arnauld
90.1k7 gold badges105 silver badges366 bronze badges
asked 10 hours ago
Tom UngerTom Unger
142 bronze badges
New contributor
Tom Unger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 8 hours ago
Arnauld
90.1k7 gold badges105 silver badges366 bronze badges
edited 8 hours ago
Arnauld
90.1k7 gold badges105 silver badges366 bronze badges
edited 8 hours ago
Arnauld
90.1k7 gold badges105 silver badges366 bronze badges
90.1k7 gold badges105 silver badges366 bronze badges
asked 10 hours ago
Tom UngerTom Unger
142 bronze badges
New contributor
Tom Unger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 hours ago
Tom UngerTom Unger
142 bronze badges
asked 10 hours ago
Tom UngerTom Unger
142 bronze badges
142 bronze badges
New contributor
Tom Unger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Tom Unger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
Welcome to the site! While this challenge is understandable, there are still a few issues. For example, why between 1 and 12, and 0 and 4 particularly? Also, please keep in mind that homework questions are not on-topic here, so if this is homework (or similar), I'd recommend loosening the requirements of the challenge (allowing the integers/range to be any number, etc.). Finally, what do you mean by "Restarting with 1 after 12 and vise versa."?
$endgroup$
– caird coinheringaahing
10 hours ago
$begingroup$
@cairdcoinheringaahing Hey thank you, I picked those numbers randomly, but two has to be bigger than one. How big the range is does not really matter. With restarting I mean that your range overlaps overtwoso ifoneis 2 andtwois 11 and therangeis 3,oneis still inside the range because it restarts attwowithone
$endgroup$
– Tom Unger
10 hours ago
$begingroup$
So ifoneis 2,twois 11, andrangeis 3, is the task basically to check ifoneis in the list[8, 9, 10, 11, 12, 1, 2]? That the range cycles round if it goes out of bounds?
$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
Exactly, sorry If my description was irritating
$endgroup$
– Tom Unger
9 hours ago
1
$begingroup$
oneandtworeally should be calledAandBfor the sake of clarity. Also, it's still unclear IMO what is given as input and what is a constant. Are $1$ and $12$ the input values, or are the input values guaranteed to be in $[1..12]$?
$endgroup$
– Arnauld
9 hours ago
|
show 7 more comments
$begingroup$
Welcome to the site! While this challenge is understandable, there are still a few issues. For example, why between 1 and 12, and 0 and 4 particularly? Also, please keep in mind that homework questions are not on-topic here, so if this is homework (or similar), I'd recommend loosening the requirements of the challenge (allowing the integers/range to be any number, etc.). Finally, what do you mean by "Restarting with 1 after 12 and vise versa."?
$endgroup$
– caird coinheringaahing
10 hours ago
$begingroup$
@cairdcoinheringaahing Hey thank you, I picked those numbers randomly, but two has to be bigger than one. How big the range is does not really matter. With restarting I mean that your range overlaps overtwoso ifoneis 2 andtwois 11 and therangeis 3,oneis still inside the range because it restarts attwowithone
$endgroup$
– Tom Unger
10 hours ago
$begingroup$
So ifoneis 2,twois 11, andrangeis 3, is the task basically to check ifoneis in the list[8, 9, 10, 11, 12, 1, 2]? That the range cycles round if it goes out of bounds?
$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
Exactly, sorry If my description was irritating
$endgroup$
– Tom Unger
9 hours ago
1
$begingroup$
oneandtworeally should be calledAandBfor the sake of clarity. Also, it's still unclear IMO what is given as input and what is a constant. Are $1$ and $12$ the input values, or are the input values guaranteed to be in $[1..12]$?
$endgroup$
– Arnauld
9 hours ago
$begingroup$
Welcome to the site! While this challenge is understandable, there are still a few issues. For example, why between 1 and 12, and 0 and 4 particularly? Also, please keep in mind that homework questions are not on-topic here, so if this is homework (or similar), I'd recommend loosening the requirements of the challenge (allowing the integers/range to be any number, etc.). Finally, what do you mean by "Restarting with 1 after 12 and vise versa."?
$endgroup$
– caird coinheringaahing
10 hours ago
$begingroup$
Welcome to the site! While this challenge is understandable, there are still a few issues. For example, why between 1 and 12, and 0 and 4 particularly? Also, please keep in mind that homework questions are not on-topic here, so if this is homework (or similar), I'd recommend loosening the requirements of the challenge (allowing the integers/range to be any number, etc.). Finally, what do you mean by "Restarting with 1 after 12 and vise versa."?
$endgroup$
– caird coinheringaahing
10 hours ago
$begingroup$
@cairdcoinheringaahing Hey thank you, I picked those numbers randomly, but two has to be bigger than one. How big the range is does not really matter. With restarting I mean that your range overlaps over
two so if one is 2 and two is 11 and the range is 3, one is still inside the range because it restarts at two with one$endgroup$
– Tom Unger
10 hours ago
$begingroup$
@cairdcoinheringaahing Hey thank you, I picked those numbers randomly, but two has to be bigger than one. How big the range is does not really matter. With restarting I mean that your range overlaps over
two so if one is 2 and two is 11 and the range is 3, one is still inside the range because it restarts at two with one$endgroup$
– Tom Unger
10 hours ago
$begingroup$
So if
one is 2, two is 11, and range is 3, is the task basically to check if one is in the list [8, 9, 10, 11, 12, 1, 2]? That the range cycles round if it goes out of bounds?$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
So if
one is 2, two is 11, and range is 3, is the task basically to check if one is in the list [8, 9, 10, 11, 12, 1, 2]? That the range cycles round if it goes out of bounds?$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
Exactly, sorry If my description was irritating
$endgroup$
– Tom Unger
9 hours ago
$begingroup$
Exactly, sorry If my description was irritating
$endgroup$
– Tom Unger
9 hours ago
1
1
$begingroup$
one and two really should be called A and B for the sake of clarity. Also, it's still unclear IMO what is given as input and what is a constant. Are $1$ and $12$ the input values, or are the input values guaranteed to be in $[1..12]$?$endgroup$
– Arnauld
9 hours ago
$begingroup$
one and two really should be called A and B for the sake of clarity. Also, it's still unclear IMO what is given as input and what is a constant. Are $1$ and $12$ the input values, or are the input values guaranteed to be in $[1..12]$?$endgroup$
– Arnauld
9 hours ago
|
show 7 more comments
16 Answers
16
active
oldest
votes
$begingroup$
JavaScript (ES6), 38 bytes
(a,b,r)=>((a=a<b?b-a:a-b)>6?12-a:a)<=r
Try it online!
JavaScript (Node.js), 53 bytes
Silly branchless method. Expects BigInts. Returns $0textn$ or $1textn$.
(a,b,r)=>0x4C5C038B885n>>((a-=b)*a+347n*r)%282n%46n&1n
Try it online!
answered 8 hours ago
ArnauldArnauld
90.1k7 gold badges105 silver badges366 bronze badges
$endgroup$
add a comment |
$begingroup$
Python 2, 52 bytes
lambda a,b,c:a in[i%12or 12for i in range(b-c,b-~c)]
Try it online!
Python 2, 52 bytes
lambda a,b,c:any(set(range(b-c,b-~c))&a,a-12,a+12)
Try it online!
Python 3, 50 bytes
lambda a,b,c:any(*range(b-c,b-~c)&a,a-12,a+12)
Try it online!
answered 9 hours ago
TFeldTFeld
18.3k3 gold badges14 silver badges57 bronze badges
$endgroup$
add a comment |
$begingroup$
Jelly, 10 8 10 bytes
ŒR’+%12‘Ɠe
Try it online!
Saved 2 bytes thanks to Mr. Xcoder
+2 bytes due a bug if one = 12
I believe this meets the criteria. Takes one from STDIN, range as left argument and two as right argument
answered 10 hours ago
caird coinheringaahingcaird coinheringaahing
7,6763 gold badges31 silver badges86 bronze badges
$endgroup$
$begingroup$
ŒR+%12Ɠe(ŒRis (inclusive) range from $-|z|$ to $|z|$) saves 2 bytes. Takesonefrom STDIN,rangeas the first argument andtwoas the second argument. Try it online!
$endgroup$
– Mr. Xcoder
9 hours ago
$begingroup$
@Mr.Xcoder So it does! Thanks
$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
Your solution has the same problem as my 05AB1E answer had: it fails ifoneis12(i.e.one=12; two=1; range=3should result in truthy).
$endgroup$
– Kevin Cruijssen
8 hours ago
1
$begingroup$
@KevinCruijssen I believe that is fixed, but I'm on mobile so haven't fully tested it
$endgroup$
– caird coinheringaahing
8 hours ago
add a comment |
$begingroup$
Java 10, 70 38 bytes
(o,t,r)->((o=o<t?t-o:o-t)>6?12-o:o)<=r
-32 bytes by porting @Arnauld's JavaScript answer.
Try it online.
Explanation:
(o,t,r)-> // Method with three integer parameters and boolean return-type
((o=o<t?t-o:o-t) // Replace `o` with abs(t-o)
>6? // And if it's smaller than 6:
12-o // Use 12-o
: // Else (it's larger than or equal to 6):
o // Use o itself
)<=r // And check if that is smaller than or equal to r
answered 8 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
$endgroup$
add a comment |
$begingroup$
05AB1E, 11 8 bytes
αD12α‚ß@
-3 bytes by porting @Arnauld's JavaScript answer, so make sure to upvote him!
Inputs in the same order as the challenge description: one; two; range.
Try it online or verify all test cases.
Explanation:
$temp=lvert two-onervert$
$result=rangegeq min(temp,lvert12-temprvert)$
α # Take the absolute difference between the first two (implicit) inputs one & two
D # Duplicate it
12α # And take the absolute difference with 12
‚ß # Pair, pop, and push the minimum of the two values on the stack
@ # And check if the (implicit) input range is larger than or equal to this value
# (after which the result is output implicitly)
answered 9 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
$endgroup$
add a comment |
$begingroup$
Wolfram Language (Mathematica), 24 bytes
Abs@Mod[#-#2,12,-6]<=#3&
Try it online!
answered 8 hours ago
RomanRoman
6251 silver badge6 bronze badges
$endgroup$
add a comment |
$begingroup$
Perl 5, 63 bytes
sub fgrep$_[0]==$_%12,(1..36)[11+$_[1]-$_[2]..11+$_[1]+$_[2]]
Try it online!
Ungolfed:
sub f
my($one, $two, $range) = @_;
my @n = (1..36);
return 0 + grep $one==$_%12, @n[ 11+$two-$range ..
11+$two+$range ];
answered 8 hours ago
Kjetil S.Kjetil S.
7072 silver badges5 bronze badges
$endgroup$
add a comment |
$begingroup$
Haskell, 42 bytes
t#r=(`elem`[1+(n-1)`mod`12|n<-[t-r..t+r]])
two # range returns a function which when applied to one returns a Bool.
Try it online!
answered 8 hours ago
Leo TenenbaumLeo Tenenbaum
1,5782 gold badges7 silver badges16 bronze badges
$endgroup$
add a comment |
$begingroup$
Japt, 11 bytes
aV
aC mU §W
Try it
answered 8 hours ago
Embodiment of IgnoranceEmbodiment of Ignorance
4,9861 silver badge30 bronze badges
$endgroup$
add a comment |
$begingroup$
Ruby, 45 characters
->o,t,r[*1..12].rotate(t-r-1)[0..r*2].any?o
Nothing fancy, just a chance to use Array#rotate.
Sample run:
irb(main):001:0> ->o,t,r[*1..12].rotate(t-r-1)[0..r*2].any?o[2, 11, 3]
=> true
Try it online!
answered 7 hours ago
manatworkmanatwork
16.7k4 gold badges38 silver badges72 bronze badges
$endgroup$
add a comment |
$begingroup$
Python 2, 31 bytes
lambda o,t,r:5-r<(o-t+6)%12<7+r
Try it online!
Python 2, 33 bytes
lambda o,t,r:abs((o-t+6)%12-6)<=r
Try it online!
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
$endgroup$
add a comment |
$begingroup$
Haskell, 27 bytes
o%t=(abs(mod(o-t+6)12-6)<=)
Try it online!
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
$endgroup$
add a comment |
$begingroup$
Charcoal, 11 bytes
‹⁵⁺Ｎ↔⁻⁶↔⁻ＮＮ
Try it online! Link is to verbose version of code. Takes the size of the range as the first input. Output uses Charcoal's default Boolean format of - for true, nothing for false. Explanation:
ＮＮ Two inputs
↔⁻ Absolute difference
⁶ Literal 6
↔⁻ Absolute difference
⁺Ｎ Plus range
‹⁵ Is greater than 5
answered 3 hours ago
NeilNeil
87.3k8 gold badges46 silver badges183 bronze badges
$endgroup$
add a comment |
$begingroup$
R, 48 bytes
function(a,b,r)a%in%c(9:12,1:12,1:4)[-r:r+b+4]
Try it online!
Pretty straightforward, I struggled for a while to find the best way to test if a was in the given range. There is likely a method I haven't seen or tried yet.
answered 3 hours ago
Sumner18Sumner18
7202 silver badges8 bronze badges
$endgroup$
add a comment |
$begingroup$
Julia 1.0, 35 bytes
f(o,t,r)=o in@.mod(t-1+(-r:r),12)+1
Try it online!
answered 2 hours ago
user3263164user3263164
1313 bronze badges
$endgroup$
add a comment |
$begingroup$
Stax, 7 bytes
₧╝g╙╖²╞
Run and debug it
It takes input as space separated [range] [one] [two] and outputs 0 for false, 1 for true.
In pseudo-code:
d = abs(one - two)
return min(d, 12 - d) <= range
Hm, that's probably almost a python submission.
answered 1 hour ago
recursiverecursive
7,85115 silver badges31 bronze badges
$endgroup$
add a comment |
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16 Answers
16
active
oldest
votes
16 Answers
16
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
JavaScript (ES6), 38 bytes
(a,b,r)=>((a=a<b?b-a:a-b)>6?12-a:a)<=r
Try it online!
JavaScript (Node.js), 53 bytes
Silly branchless method. Expects BigInts. Returns $0textn$ or $1textn$.
(a,b,r)=>0x4C5C038B885n>>((a-=b)*a+347n*r)%282n%46n&1n
Try it online!
answered 8 hours ago
ArnauldArnauld
90.1k7 gold badges105 silver badges366 bronze badges
$endgroup$
add a comment |
$begingroup$
JavaScript (ES6), 38 bytes
(a,b,r)=>((a=a<b?b-a:a-b)>6?12-a:a)<=r
Try it online!
JavaScript (Node.js), 53 bytes
Silly branchless method. Expects BigInts. Returns $0textn$ or $1textn$.
(a,b,r)=>0x4C5C038B885n>>((a-=b)*a+347n*r)%282n%46n&1n
Try it online!
answered 8 hours ago
ArnauldArnauld
90.1k7 gold badges105 silver badges366 bronze badges
$endgroup$
add a comment |
$begingroup$
JavaScript (ES6), 38 bytes
(a,b,r)=>((a=a<b?b-a:a-b)>6?12-a:a)<=r
Try it online!
JavaScript (Node.js), 53 bytes
Silly branchless method. Expects BigInts. Returns $0textn$ or $1textn$.
(a,b,r)=>0x4C5C038B885n>>((a-=b)*a+347n*r)%282n%46n&1n
Try it online!
answered 8 hours ago
ArnauldArnauld
90.1k7 gold badges105 silver badges366 bronze badges
$endgroup$
JavaScript (ES6), 38 bytes
(a,b,r)=>((a=a<b?b-a:a-b)>6?12-a:a)<=r
Try it online!
JavaScript (Node.js), 53 bytes
Silly branchless method. Expects BigInts. Returns $0textn$ or $1textn$.
(a,b,r)=>0x4C5C038B885n>>((a-=b)*a+347n*r)%282n%46n&1n
Try it online!
answered 8 hours ago
ArnauldArnauld
90.1k7 gold badges105 silver badges366 bronze badges
edited 7 hours ago
answered 8 hours ago
ArnauldArnauld
90.1k7 gold badges105 silver badges366 bronze badges
answered 8 hours ago
ArnauldArnauld
90.1k7 gold badges105 silver badges366 bronze badges
answered 8 hours ago
ArnauldArnauld
90.1k7 gold badges105 silver badges366 bronze badges
90.1k7 gold badges105 silver badges366 bronze badges
add a comment |
add a comment |
$begingroup$
Python 2, 52 bytes
lambda a,b,c:a in[i%12or 12for i in range(b-c,b-~c)]
Try it online!
Python 2, 52 bytes
lambda a,b,c:any(set(range(b-c,b-~c))&a,a-12,a+12)
Try it online!
Python 3, 50 bytes
lambda a,b,c:any(*range(b-c,b-~c)&a,a-12,a+12)
Try it online!
answered 9 hours ago
TFeldTFeld
18.3k3 gold badges14 silver badges57 bronze badges
$endgroup$
add a comment |
$begingroup$
Python 2, 52 bytes
lambda a,b,c:a in[i%12or 12for i in range(b-c,b-~c)]
Try it online!
Python 2, 52 bytes
lambda a,b,c:any(set(range(b-c,b-~c))&a,a-12,a+12)
Try it online!
Python 3, 50 bytes
lambda a,b,c:any(*range(b-c,b-~c)&a,a-12,a+12)
Try it online!
answered 9 hours ago
TFeldTFeld
18.3k3 gold badges14 silver badges57 bronze badges
$endgroup$
add a comment |
$begingroup$
Python 2, 52 bytes
lambda a,b,c:a in[i%12or 12for i in range(b-c,b-~c)]
Try it online!
Python 2, 52 bytes
lambda a,b,c:any(set(range(b-c,b-~c))&a,a-12,a+12)
Try it online!
Python 3, 50 bytes
lambda a,b,c:any(*range(b-c,b-~c)&a,a-12,a+12)
Try it online!
answered 9 hours ago
TFeldTFeld
18.3k3 gold badges14 silver badges57 bronze badges
$endgroup$
Python 2, 52 bytes
lambda a,b,c:a in[i%12or 12for i in range(b-c,b-~c)]
Try it online!
Python 2, 52 bytes
lambda a,b,c:any(set(range(b-c,b-~c))&a,a-12,a+12)
Try it online!
Python 3, 50 bytes
lambda a,b,c:any(*range(b-c,b-~c)&a,a-12,a+12)
Try it online!
answered 9 hours ago
TFeldTFeld
18.3k3 gold badges14 silver badges57 bronze badges
edited 9 hours ago
answered 9 hours ago
TFeldTFeld
18.3k3 gold badges14 silver badges57 bronze badges
answered 9 hours ago
TFeldTFeld
18.3k3 gold badges14 silver badges57 bronze badges
answered 9 hours ago
TFeldTFeld
18.3k3 gold badges14 silver badges57 bronze badges
18.3k3 gold badges14 silver badges57 bronze badges
add a comment |
add a comment |
$begingroup$
Jelly, 10 8 10 bytes
ŒR’+%12‘Ɠe
Try it online!
Saved 2 bytes thanks to Mr. Xcoder
+2 bytes due a bug if one = 12
I believe this meets the criteria. Takes one from STDIN, range as left argument and two as right argument
answered 10 hours ago
caird coinheringaahingcaird coinheringaahing
7,6763 gold badges31 silver badges86 bronze badges
$endgroup$
$begingroup$
ŒR+%12Ɠe(ŒRis (inclusive) range from $-|z|$ to $|z|$) saves 2 bytes. Takesonefrom STDIN,rangeas the first argument andtwoas the second argument. Try it online!
$endgroup$
– Mr. Xcoder
9 hours ago
$begingroup$
@Mr.Xcoder So it does! Thanks
$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
Your solution has the same problem as my 05AB1E answer had: it fails ifoneis12(i.e.one=12; two=1; range=3should result in truthy).
$endgroup$
– Kevin Cruijssen
8 hours ago
1
$begingroup$
@KevinCruijssen I believe that is fixed, but I'm on mobile so haven't fully tested it
$endgroup$
– caird coinheringaahing
8 hours ago
add a comment |
$begingroup$
Jelly, 10 8 10 bytes
ŒR’+%12‘Ɠe
Try it online!
Saved 2 bytes thanks to Mr. Xcoder
+2 bytes due a bug if one = 12
I believe this meets the criteria. Takes one from STDIN, range as left argument and two as right argument
answered 10 hours ago
caird coinheringaahingcaird coinheringaahing
7,6763 gold badges31 silver badges86 bronze badges
$endgroup$
$begingroup$
ŒR+%12Ɠe(ŒRis (inclusive) range from $-|z|$ to $|z|$) saves 2 bytes. Takesonefrom STDIN,rangeas the first argument andtwoas the second argument. Try it online!
$endgroup$
– Mr. Xcoder
9 hours ago
$begingroup$
@Mr.Xcoder So it does! Thanks
$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
Your solution has the same problem as my 05AB1E answer had: it fails ifoneis12(i.e.one=12; two=1; range=3should result in truthy).
$endgroup$
– Kevin Cruijssen
8 hours ago
1
$begingroup$
@KevinCruijssen I believe that is fixed, but I'm on mobile so haven't fully tested it
$endgroup$
– caird coinheringaahing
8 hours ago
add a comment |
$begingroup$
Jelly, 10 8 10 bytes
ŒR’+%12‘Ɠe
Try it online!
Saved 2 bytes thanks to Mr. Xcoder
+2 bytes due a bug if one = 12
I believe this meets the criteria. Takes one from STDIN, range as left argument and two as right argument
answered 10 hours ago
caird coinheringaahingcaird coinheringaahing
7,6763 gold badges31 silver badges86 bronze badges
$endgroup$
Jelly, 10 8 10 bytes
ŒR’+%12‘Ɠe
Try it online!
Saved 2 bytes thanks to Mr. Xcoder
+2 bytes due a bug if one = 12
I believe this meets the criteria. Takes one from STDIN, range as left argument and two as right argument
answered 10 hours ago
caird coinheringaahingcaird coinheringaahing
7,6763 gold badges31 silver badges86 bronze badges
edited 8 hours ago
answered 10 hours ago
caird coinheringaahingcaird coinheringaahing
7,6763 gold badges31 silver badges86 bronze badges
answered 10 hours ago
caird coinheringaahingcaird coinheringaahing
7,6763 gold badges31 silver badges86 bronze badges
answered 10 hours ago
caird coinheringaahingcaird coinheringaahing
7,6763 gold badges31 silver badges86 bronze badges
7,6763 gold badges31 silver badges86 bronze badges
$begingroup$
ŒR+%12Ɠe(ŒRis (inclusive) range from $-|z|$ to $|z|$) saves 2 bytes. Takesonefrom STDIN,rangeas the first argument andtwoas the second argument. Try it online!
$endgroup$
– Mr. Xcoder
9 hours ago
$begingroup$
@Mr.Xcoder So it does! Thanks
$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
Your solution has the same problem as my 05AB1E answer had: it fails ifoneis12(i.e.one=12; two=1; range=3should result in truthy).
$endgroup$
– Kevin Cruijssen
8 hours ago
1
$begingroup$
@KevinCruijssen I believe that is fixed, but I'm on mobile so haven't fully tested it
$endgroup$
– caird coinheringaahing
8 hours ago
add a comment |
$begingroup$
ŒR+%12Ɠe(ŒRis (inclusive) range from $-|z|$ to $|z|$) saves 2 bytes. Takesonefrom STDIN,rangeas the first argument andtwoas the second argument. Try it online!
$endgroup$
– Mr. Xcoder
9 hours ago
$begingroup$
@Mr.Xcoder So it does! Thanks
$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
Your solution has the same problem as my 05AB1E answer had: it fails ifoneis12(i.e.one=12; two=1; range=3should result in truthy).
$endgroup$
– Kevin Cruijssen
8 hours ago
1
$begingroup$
@KevinCruijssen I believe that is fixed, but I'm on mobile so haven't fully tested it
$endgroup$
– caird coinheringaahing
8 hours ago
$begingroup$
ŒR+%12Ɠe (ŒR is (inclusive) range from $-|z|$ to $|z|$) saves 2 bytes. Takes one from STDIN, range as the first argument and two as the second argument. Try it online!$endgroup$
– Mr. Xcoder
9 hours ago
$begingroup$
ŒR+%12Ɠe (ŒR is (inclusive) range from $-|z|$ to $|z|$) saves 2 bytes. Takes one from STDIN, range as the first argument and two as the second argument. Try it online!$endgroup$
– Mr. Xcoder
9 hours ago
$begingroup$
@Mr.Xcoder So it does! Thanks
$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
@Mr.Xcoder So it does! Thanks
$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
Your solution has the same problem as my 05AB1E answer had: it fails if
one is 12 (i.e. one=12; two=1; range=3 should result in truthy).$endgroup$
– Kevin Cruijssen
8 hours ago
$begingroup$
Your solution has the same problem as my 05AB1E answer had: it fails if
one is 12 (i.e. one=12; two=1; range=3 should result in truthy).$endgroup$
– Kevin Cruijssen
8 hours ago
1
1
$begingroup$
@KevinCruijssen I believe that is fixed, but I'm on mobile so haven't fully tested it
$endgroup$
– caird coinheringaahing
8 hours ago
$begingroup$
@KevinCruijssen I believe that is fixed, but I'm on mobile so haven't fully tested it
$endgroup$
– caird coinheringaahing
8 hours ago
add a comment |
$begingroup$
Java 10, 70 38 bytes
(o,t,r)->((o=o<t?t-o:o-t)>6?12-o:o)<=r
-32 bytes by porting @Arnauld's JavaScript answer.
Try it online.
Explanation:
(o,t,r)-> // Method with three integer parameters and boolean return-type
((o=o<t?t-o:o-t) // Replace `o` with abs(t-o)
>6? // And if it's smaller than 6:
12-o // Use 12-o
: // Else (it's larger than or equal to 6):
o // Use o itself
)<=r // And check if that is smaller than or equal to r
answered 8 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
$endgroup$
add a comment |
$begingroup$
Java 10, 70 38 bytes
(o,t,r)->((o=o<t?t-o:o-t)>6?12-o:o)<=r
-32 bytes by porting @Arnauld's JavaScript answer.
Try it online.
Explanation:
(o,t,r)-> // Method with three integer parameters and boolean return-type
((o=o<t?t-o:o-t) // Replace `o` with abs(t-o)
>6? // And if it's smaller than 6:
12-o // Use 12-o
: // Else (it's larger than or equal to 6):
o // Use o itself
)<=r // And check if that is smaller than or equal to r
answered 8 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
$endgroup$
add a comment |
$begingroup$
Java 10, 70 38 bytes
(o,t,r)->((o=o<t?t-o:o-t)>6?12-o:o)<=r
-32 bytes by porting @Arnauld's JavaScript answer.
Try it online.
Explanation:
(o,t,r)-> // Method with three integer parameters and boolean return-type
((o=o<t?t-o:o-t) // Replace `o` with abs(t-o)
>6? // And if it's smaller than 6:
12-o // Use 12-o
: // Else (it's larger than or equal to 6):
o // Use o itself
)<=r // And check if that is smaller than or equal to r
answered 8 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
$endgroup$
Java 10, 70 38 bytes
(o,t,r)->((o=o<t?t-o:o-t)>6?12-o:o)<=r
-32 bytes by porting @Arnauld's JavaScript answer.
Try it online.
Explanation:
(o,t,r)-> // Method with three integer parameters and boolean return-type
((o=o<t?t-o:o-t) // Replace `o` with abs(t-o)
>6? // And if it's smaller than 6:
12-o // Use 12-o
: // Else (it's larger than or equal to 6):
o // Use o itself
)<=r // And check if that is smaller than or equal to r
answered 8 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
edited 8 hours ago
answered 8 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
answered 8 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
answered 8 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
49.8k7 gold badges83 silver badges246 bronze badges
add a comment |
add a comment |
$begingroup$
05AB1E, 11 8 bytes
αD12α‚ß@
-3 bytes by porting @Arnauld's JavaScript answer, so make sure to upvote him!
Inputs in the same order as the challenge description: one; two; range.
Try it online or verify all test cases.
Explanation:
$temp=lvert two-onervert$
$result=rangegeq min(temp,lvert12-temprvert)$
α # Take the absolute difference between the first two (implicit) inputs one & two
D # Duplicate it
12α # And take the absolute difference with 12
‚ß # Pair, pop, and push the minimum of the two values on the stack
@ # And check if the (implicit) input range is larger than or equal to this value
# (after which the result is output implicitly)
answered 9 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
$endgroup$
add a comment |
$begingroup$
05AB1E, 11 8 bytes
αD12α‚ß@
-3 bytes by porting @Arnauld's JavaScript answer, so make sure to upvote him!
Inputs in the same order as the challenge description: one; two; range.
Try it online or verify all test cases.
Explanation:
$temp=lvert two-onervert$
$result=rangegeq min(temp,lvert12-temprvert)$
α # Take the absolute difference between the first two (implicit) inputs one & two
D # Duplicate it
12α # And take the absolute difference with 12
‚ß # Pair, pop, and push the minimum of the two values on the stack
@ # And check if the (implicit) input range is larger than or equal to this value
# (after which the result is output implicitly)
answered 9 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
$endgroup$
add a comment |
$begingroup$
05AB1E, 11 8 bytes
αD12α‚ß@
-3 bytes by porting @Arnauld's JavaScript answer, so make sure to upvote him!
Inputs in the same order as the challenge description: one; two; range.
Try it online or verify all test cases.
Explanation:
$temp=lvert two-onervert$
$result=rangegeq min(temp,lvert12-temprvert)$
α # Take the absolute difference between the first two (implicit) inputs one & two
D # Duplicate it
12α # And take the absolute difference with 12
‚ß # Pair, pop, and push the minimum of the two values on the stack
@ # And check if the (implicit) input range is larger than or equal to this value
# (after which the result is output implicitly)
answered 9 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
$endgroup$
05AB1E, 11 8 bytes
αD12α‚ß@
-3 bytes by porting @Arnauld's JavaScript answer, so make sure to upvote him!
Inputs in the same order as the challenge description: one; two; range.
Try it online or verify all test cases.
Explanation:
$temp=lvert two-onervert$
$result=rangegeq min(temp,lvert12-temprvert)$
α # Take the absolute difference between the first two (implicit) inputs one & two
D # Duplicate it
12α # And take the absolute difference with 12
‚ß # Pair, pop, and push the minimum of the two values on the stack
@ # And check if the (implicit) input range is larger than or equal to this value
# (after which the result is output implicitly)
answered 9 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
edited 8 hours ago
answered 9 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
answered 9 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
answered 9 hours ago
Kevin CruijssenKevin Cruijssen
49.8k7 gold badges83 silver badges246 bronze badges
49.8k7 gold badges83 silver badges246 bronze badges
add a comment |
add a comment |
$begingroup$
Wolfram Language (Mathematica), 24 bytes
Abs@Mod[#-#2,12,-6]<=#3&
Try it online!
answered 8 hours ago
RomanRoman
6251 silver badge6 bronze badges
$endgroup$
add a comment |
$begingroup$
Wolfram Language (Mathematica), 24 bytes
Abs@Mod[#-#2,12,-6]<=#3&
Try it online!
answered 8 hours ago
RomanRoman
6251 silver badge6 bronze badges
$endgroup$
add a comment |
$begingroup$
Wolfram Language (Mathematica), 24 bytes
Abs@Mod[#-#2,12,-6]<=#3&
Try it online!
answered 8 hours ago
RomanRoman
6251 silver badge6 bronze badges
$endgroup$
Wolfram Language (Mathematica), 24 bytes
Abs@Mod[#-#2,12,-6]<=#3&
Try it online!
answered 8 hours ago
RomanRoman
6251 silver badge6 bronze badges
answered 8 hours ago
RomanRoman
6251 silver badge6 bronze badges
answered 8 hours ago
RomanRoman
6251 silver badge6 bronze badges
answered 8 hours ago
RomanRoman
6251 silver badge6 bronze badges
6251 silver badge6 bronze badges
add a comment |
add a comment |
$begingroup$
Perl 5, 63 bytes
sub fgrep$_[0]==$_%12,(1..36)[11+$_[1]-$_[2]..11+$_[1]+$_[2]]
Try it online!
Ungolfed:
sub f
my($one, $two, $range) = @_;
my @n = (1..36);
return 0 + grep $one==$_%12, @n[ 11+$two-$range ..
11+$two+$range ];
answered 8 hours ago
Kjetil S.Kjetil S.
7072 silver badges5 bronze badges
$endgroup$
add a comment |
$begingroup$
Perl 5, 63 bytes
sub fgrep$_[0]==$_%12,(1..36)[11+$_[1]-$_[2]..11+$_[1]+$_[2]]
Try it online!
Ungolfed:
sub f
my($one, $two, $range) = @_;
my @n = (1..36);
return 0 + grep $one==$_%12, @n[ 11+$two-$range ..
11+$two+$range ];
answered 8 hours ago
Kjetil S.Kjetil S.
7072 silver badges5 bronze badges
$endgroup$
add a comment |
$begingroup$
Perl 5, 63 bytes
sub fgrep$_[0]==$_%12,(1..36)[11+$_[1]-$_[2]..11+$_[1]+$_[2]]
Try it online!
Ungolfed:
sub f
my($one, $two, $range) = @_;
my @n = (1..36);
return 0 + grep $one==$_%12, @n[ 11+$two-$range ..
11+$two+$range ];
answered 8 hours ago
Kjetil S.Kjetil S.
7072 silver badges5 bronze badges
$endgroup$
Perl 5, 63 bytes
sub fgrep$_[0]==$_%12,(1..36)[11+$_[1]-$_[2]..11+$_[1]+$_[2]]
Try it online!
Ungolfed:
sub f
my($one, $two, $range) = @_;
my @n = (1..36);
return 0 + grep $one==$_%12, @n[ 11+$two-$range ..
11+$two+$range ];
answered 8 hours ago
Kjetil S.Kjetil S.
7072 silver badges5 bronze badges
edited 8 hours ago
answered 8 hours ago
Kjetil S.Kjetil S.
7072 silver badges5 bronze badges
answered 8 hours ago
Kjetil S.Kjetil S.
7072 silver badges5 bronze badges
answered 8 hours ago
Kjetil S.Kjetil S.
7072 silver badges5 bronze badges
7072 silver badges5 bronze badges
add a comment |
add a comment |
$begingroup$
Haskell, 42 bytes
t#r=(`elem`[1+(n-1)`mod`12|n<-[t-r..t+r]])
two # range returns a function which when applied to one returns a Bool.
Try it online!
answered 8 hours ago
Leo TenenbaumLeo Tenenbaum
1,5782 gold badges7 silver badges16 bronze badges
$endgroup$
add a comment |
$begingroup$
Haskell, 42 bytes
t#r=(`elem`[1+(n-1)`mod`12|n<-[t-r..t+r]])
two # range returns a function which when applied to one returns a Bool.
Try it online!
answered 8 hours ago
Leo TenenbaumLeo Tenenbaum
1,5782 gold badges7 silver badges16 bronze badges
$endgroup$
add a comment |
$begingroup$
Haskell, 42 bytes
t#r=(`elem`[1+(n-1)`mod`12|n<-[t-r..t+r]])
two # range returns a function which when applied to one returns a Bool.
Try it online!
answered 8 hours ago
Leo TenenbaumLeo Tenenbaum
1,5782 gold badges7 silver badges16 bronze badges
$endgroup$
Haskell, 42 bytes
t#r=(`elem`[1+(n-1)`mod`12|n<-[t-r..t+r]])
two # range returns a function which when applied to one returns a Bool.
Try it online!
answered 8 hours ago
Leo TenenbaumLeo Tenenbaum
1,5782 gold badges7 silver badges16 bronze badges
answered 8 hours ago
Leo TenenbaumLeo Tenenbaum
1,5782 gold badges7 silver badges16 bronze badges
answered 8 hours ago
Leo TenenbaumLeo Tenenbaum
1,5782 gold badges7 silver badges16 bronze badges
answered 8 hours ago
Leo TenenbaumLeo Tenenbaum
1,5782 gold badges7 silver badges16 bronze badges
1,5782 gold badges7 silver badges16 bronze badges
add a comment |
add a comment |
$begingroup$
Japt, 11 bytes
aV
aC mU §W
Try it
answered 8 hours ago
Embodiment of IgnoranceEmbodiment of Ignorance
4,9861 silver badge30 bronze badges
$endgroup$
add a comment |
$begingroup$
Japt, 11 bytes
aV
aC mU §W
Try it
answered 8 hours ago
Embodiment of IgnoranceEmbodiment of Ignorance
4,9861 silver badge30 bronze badges
$endgroup$
add a comment |
$begingroup$
Japt, 11 bytes
aV
aC mU §W
Try it
answered 8 hours ago
Embodiment of IgnoranceEmbodiment of Ignorance
4,9861 silver badge30 bronze badges
$endgroup$
Japt, 11 bytes
aV
aC mU §W
Try it
answered 8 hours ago
Embodiment of IgnoranceEmbodiment of Ignorance
4,9861 silver badge30 bronze badges
edited 8 hours ago
answered 8 hours ago
Embodiment of IgnoranceEmbodiment of Ignorance
4,9861 silver badge30 bronze badges
answered 8 hours ago
Embodiment of IgnoranceEmbodiment of Ignorance
4,9861 silver badge30 bronze badges
answered 8 hours ago
Embodiment of IgnoranceEmbodiment of Ignorance
4,9861 silver badge30 bronze badges
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$begingroup$
Ruby, 45 characters
->o,t,r[*1..12].rotate(t-r-1)[0..r*2].any?o
Nothing fancy, just a chance to use Array#rotate.
Sample run:
irb(main):001:0> ->o,t,r[*1..12].rotate(t-r-1)[0..r*2].any?o[2, 11, 3]
=> true
Try it online!
answered 7 hours ago
manatworkmanatwork
16.7k4 gold badges38 silver badges72 bronze badges
$endgroup$
add a comment |
$begingroup$
Ruby, 45 characters
->o,t,r[*1..12].rotate(t-r-1)[0..r*2].any?o
Nothing fancy, just a chance to use Array#rotate.
Sample run:
irb(main):001:0> ->o,t,r[*1..12].rotate(t-r-1)[0..r*2].any?o[2, 11, 3]
=> true
Try it online!
answered 7 hours ago
manatworkmanatwork
16.7k4 gold badges38 silver badges72 bronze badges
$endgroup$
add a comment |
$begingroup$
Ruby, 45 characters
->o,t,r[*1..12].rotate(t-r-1)[0..r*2].any?o
Nothing fancy, just a chance to use Array#rotate.
Sample run:
irb(main):001:0> ->o,t,r[*1..12].rotate(t-r-1)[0..r*2].any?o[2, 11, 3]
=> true
Try it online!
answered 7 hours ago
manatworkmanatwork
16.7k4 gold badges38 silver badges72 bronze badges
$endgroup$
Ruby, 45 characters
->o,t,r[*1..12].rotate(t-r-1)[0..r*2].any?o
Nothing fancy, just a chance to use Array#rotate.
Sample run:
irb(main):001:0> ->o,t,r[*1..12].rotate(t-r-1)[0..r*2].any?o[2, 11, 3]
=> true
Try it online!
answered 7 hours ago
manatworkmanatwork
16.7k4 gold badges38 silver badges72 bronze badges
answered 7 hours ago
manatworkmanatwork
16.7k4 gold badges38 silver badges72 bronze badges
answered 7 hours ago
manatworkmanatwork
16.7k4 gold badges38 silver badges72 bronze badges
answered 7 hours ago
manatworkmanatwork
16.7k4 gold badges38 silver badges72 bronze badges
16.7k4 gold badges38 silver badges72 bronze badges
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$begingroup$
Python 2, 31 bytes
lambda o,t,r:5-r<(o-t+6)%12<7+r
Try it online!
Python 2, 33 bytes
lambda o,t,r:abs((o-t+6)%12-6)<=r
Try it online!
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
$endgroup$
add a comment |
$begingroup$
Python 2, 31 bytes
lambda o,t,r:5-r<(o-t+6)%12<7+r
Try it online!
Python 2, 33 bytes
lambda o,t,r:abs((o-t+6)%12-6)<=r
Try it online!
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
$endgroup$
add a comment |
$begingroup$
Python 2, 31 bytes
lambda o,t,r:5-r<(o-t+6)%12<7+r
Try it online!
Python 2, 33 bytes
lambda o,t,r:abs((o-t+6)%12-6)<=r
Try it online!
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
$endgroup$
Python 2, 31 bytes
lambda o,t,r:5-r<(o-t+6)%12<7+r
Try it online!
Python 2, 33 bytes
lambda o,t,r:abs((o-t+6)%12-6)<=r
Try it online!
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
edited 7 hours ago
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
97.8k19 gold badges201 silver badges461 bronze badges
add a comment |
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$begingroup$
Haskell, 27 bytes
o%t=(abs(mod(o-t+6)12-6)<=)
Try it online!
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
$endgroup$
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$begingroup$
Haskell, 27 bytes
o%t=(abs(mod(o-t+6)12-6)<=)
Try it online!
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
$endgroup$
add a comment |
$begingroup$
Haskell, 27 bytes
o%t=(abs(mod(o-t+6)12-6)<=)
Try it online!
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
$endgroup$
Haskell, 27 bytes
o%t=(abs(mod(o-t+6)12-6)<=)
Try it online!
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
answered 7 hours ago
xnorxnor
97.8k19 gold badges201 silver badges461 bronze badges
97.8k19 gold badges201 silver badges461 bronze badges
add a comment |
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$begingroup$
Charcoal, 11 bytes
‹⁵⁺Ｎ↔⁻⁶↔⁻ＮＮ
Try it online! Link is to verbose version of code. Takes the size of the range as the first input. Output uses Charcoal's default Boolean format of - for true, nothing for false. Explanation:
ＮＮ Two inputs
↔⁻ Absolute difference
⁶ Literal 6
↔⁻ Absolute difference
⁺Ｎ Plus range
‹⁵ Is greater than 5
answered 3 hours ago
NeilNeil
87.3k8 gold badges46 silver badges183 bronze badges
$endgroup$
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$begingroup$
Charcoal, 11 bytes
‹⁵⁺Ｎ↔⁻⁶↔⁻ＮＮ
Try it online! Link is to verbose version of code. Takes the size of the range as the first input. Output uses Charcoal's default Boolean format of - for true, nothing for false. Explanation:
ＮＮ Two inputs
↔⁻ Absolute difference
⁶ Literal 6
↔⁻ Absolute difference
⁺Ｎ Plus range
‹⁵ Is greater than 5
answered 3 hours ago
NeilNeil
87.3k8 gold badges46 silver badges183 bronze badges
$endgroup$
add a comment |
$begingroup$
Charcoal, 11 bytes
‹⁵⁺Ｎ↔⁻⁶↔⁻ＮＮ
Try it online! Link is to verbose version of code. Takes the size of the range as the first input. Output uses Charcoal's default Boolean format of - for true, nothing for false. Explanation:
ＮＮ Two inputs
↔⁻ Absolute difference
⁶ Literal 6
↔⁻ Absolute difference
⁺Ｎ Plus range
‹⁵ Is greater than 5
answered 3 hours ago
NeilNeil
87.3k8 gold badges46 silver badges183 bronze badges
$endgroup$
Charcoal, 11 bytes
‹⁵⁺Ｎ↔⁻⁶↔⁻ＮＮ
Try it online! Link is to verbose version of code. Takes the size of the range as the first input. Output uses Charcoal's default Boolean format of - for true, nothing for false. Explanation:
ＮＮ Two inputs
↔⁻ Absolute difference
⁶ Literal 6
↔⁻ Absolute difference
⁺Ｎ Plus range
‹⁵ Is greater than 5
answered 3 hours ago
NeilNeil
87.3k8 gold badges46 silver badges183 bronze badges
answered 3 hours ago
NeilNeil
87.3k8 gold badges46 silver badges183 bronze badges
answered 3 hours ago
NeilNeil
87.3k8 gold badges46 silver badges183 bronze badges
answered 3 hours ago
NeilNeil
87.3k8 gold badges46 silver badges183 bronze badges
87.3k8 gold badges46 silver badges183 bronze badges
add a comment |
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$begingroup$
R, 48 bytes
function(a,b,r)a%in%c(9:12,1:12,1:4)[-r:r+b+4]
Try it online!
Pretty straightforward, I struggled for a while to find the best way to test if a was in the given range. There is likely a method I haven't seen or tried yet.
answered 3 hours ago
Sumner18Sumner18
7202 silver badges8 bronze badges
$endgroup$
add a comment |
$begingroup$
R, 48 bytes
function(a,b,r)a%in%c(9:12,1:12,1:4)[-r:r+b+4]
Try it online!
Pretty straightforward, I struggled for a while to find the best way to test if a was in the given range. There is likely a method I haven't seen or tried yet.
answered 3 hours ago
Sumner18Sumner18
7202 silver badges8 bronze badges
$endgroup$
add a comment |
$begingroup$
R, 48 bytes
function(a,b,r)a%in%c(9:12,1:12,1:4)[-r:r+b+4]
Try it online!
Pretty straightforward, I struggled for a while to find the best way to test if a was in the given range. There is likely a method I haven't seen or tried yet.
answered 3 hours ago
Sumner18Sumner18
7202 silver badges8 bronze badges
$endgroup$
R, 48 bytes
function(a,b,r)a%in%c(9:12,1:12,1:4)[-r:r+b+4]
Try it online!
Pretty straightforward, I struggled for a while to find the best way to test if a was in the given range. There is likely a method I haven't seen or tried yet.
answered 3 hours ago
Sumner18Sumner18
7202 silver badges8 bronze badges
answered 3 hours ago
Sumner18Sumner18
7202 silver badges8 bronze badges
answered 3 hours ago
Sumner18Sumner18
7202 silver badges8 bronze badges
answered 3 hours ago
Sumner18Sumner18
7202 silver badges8 bronze badges
7202 silver badges8 bronze badges
add a comment |
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$begingroup$
Julia 1.0, 35 bytes
f(o,t,r)=o in@.mod(t-1+(-r:r),12)+1
Try it online!
answered 2 hours ago
user3263164user3263164
1313 bronze badges
$endgroup$
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$begingroup$
Julia 1.0, 35 bytes
f(o,t,r)=o in@.mod(t-1+(-r:r),12)+1
Try it online!
answered 2 hours ago
user3263164user3263164
1313 bronze badges
$endgroup$
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$begingroup$
Julia 1.0, 35 bytes
f(o,t,r)=o in@.mod(t-1+(-r:r),12)+1
Try it online!
answered 2 hours ago
user3263164user3263164
1313 bronze badges
$endgroup$
Julia 1.0, 35 bytes
f(o,t,r)=o in@.mod(t-1+(-r:r),12)+1
Try it online!
answered 2 hours ago
user3263164user3263164
1313 bronze badges
answered 2 hours ago
user3263164user3263164
1313 bronze badges
answered 2 hours ago
user3263164user3263164
1313 bronze badges
answered 2 hours ago
user3263164user3263164
1313 bronze badges
1313 bronze badges
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$begingroup$
Stax, 7 bytes
₧╝g╙╖²╞
Run and debug it
It takes input as space separated [range] [one] [two] and outputs 0 for false, 1 for true.
In pseudo-code:
d = abs(one - two)
return min(d, 12 - d) <= range
Hm, that's probably almost a python submission.
answered 1 hour ago
recursiverecursive
7,85115 silver badges31 bronze badges
$endgroup$
add a comment |
$begingroup$
Stax, 7 bytes
₧╝g╙╖²╞
Run and debug it
It takes input as space separated [range] [one] [two] and outputs 0 for false, 1 for true.
In pseudo-code:
d = abs(one - two)
return min(d, 12 - d) <= range
Hm, that's probably almost a python submission.
answered 1 hour ago
recursiverecursive
7,85115 silver badges31 bronze badges
$endgroup$
add a comment |
$begingroup$
Stax, 7 bytes
₧╝g╙╖²╞
Run and debug it
It takes input as space separated [range] [one] [two] and outputs 0 for false, 1 for true.
In pseudo-code:
d = abs(one - two)
return min(d, 12 - d) <= range
Hm, that's probably almost a python submission.
answered 1 hour ago
recursiverecursive
7,85115 silver badges31 bronze badges
$endgroup$
Stax, 7 bytes
₧╝g╙╖²╞
Run and debug it
It takes input as space separated [range] [one] [two] and outputs 0 for false, 1 for true.
In pseudo-code:
d = abs(one - two)
return min(d, 12 - d) <= range
Hm, that's probably almost a python submission.
answered 1 hour ago
recursiverecursive
7,85115 silver badges31 bronze badges
answered 1 hour ago
recursiverecursive
7,85115 silver badges31 bronze badges
answered 1 hour ago
recursiverecursive
7,85115 silver badges31 bronze badges
answered 1 hour ago
recursiverecursive
7,85115 silver badges31 bronze badges
7,85115 silver badges31 bronze badges
add a comment |
add a comment |
Tom Unger is a new contributor. Be nice, and check out our Code of Conduct.
Tom Unger is a new contributor. Be nice, and check out our Code of Conduct.
Tom Unger is a new contributor. Be nice, and check out our Code of Conduct.
Tom Unger is a new contributor. Be nice, and check out our Code of Conduct.
If this is an answer to a challenge…
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$begingroup$
Welcome to the site! While this challenge is understandable, there are still a few issues. For example, why between 1 and 12, and 0 and 4 particularly? Also, please keep in mind that homework questions are not on-topic here, so if this is homework (or similar), I'd recommend loosening the requirements of the challenge (allowing the integers/range to be any number, etc.). Finally, what do you mean by "Restarting with 1 after 12 and vise versa."?
$endgroup$
– caird coinheringaahing
10 hours ago
$begingroup$
@cairdcoinheringaahing Hey thank you, I picked those numbers randomly, but two has to be bigger than one. How big the range is does not really matter. With restarting I mean that your range overlaps over
twoso ifoneis 2 andtwois 11 and therangeis 3,oneis still inside the range because it restarts attwowithone$endgroup$
– Tom Unger
10 hours ago
$begingroup$
So if
oneis 2,twois 11, andrangeis 3, is the task basically to check ifoneis in the list[8, 9, 10, 11, 12, 1, 2]? That the range cycles round if it goes out of bounds?$endgroup$
– caird coinheringaahing
9 hours ago
$begingroup$
Exactly, sorry If my description was irritating
$endgroup$
– Tom Unger
9 hours ago
1
$begingroup$
oneandtworeally should be calledAandBfor the sake of clarity. Also, it's still unclear IMO what is given as input and what is a constant. Are $1$ and $12$ the input values, or are the input values guaranteed to be in $[1..12]$?$endgroup$
– Arnauld
9 hours ago