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How does the Moon's gravity affect Earth's oceans despite Earth's stronger gravitational pull?


Does the Moon's magnetic field affect Earth's magnetic field?How much of an effect does the moon have on Earth's liquid mantle?Earth's gravitational pull on ISSUnder Earth's gravitational pull, how dense would an object have to be to reach its Schwarzschild Radius?Meteorites bring waterHow much do the mascons on the moon affect surface gravity?Understanding gravityDoes Uranus have a stronger gravitational pull on its moons than Earth does?When the asteroid hit the earth 65 mya did the earth's gravity pull change? By how much?Can the moon's gravity influence be observed on the space station's orbit?






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Given that Earth has a much stronger gravitational pull than the Moon, how does the Moon have any influence on Earth's oceans?










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    Please search the site first before asking a question
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    Field strengths combine -- it's not binary "win or lose."
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    13 hours ago






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    To the downvoters: Just because a question appears to be naive does not mean that the question is bad and is worthy of a downvote.
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    @Jan Doggen. Yes I should have done that. Sorry. With hindsight gained from the link you provided I still would have asked the question.
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3












$begingroup$


Given that Earth has a much stronger gravitational pull than the Moon, how does the Moon have any influence on Earth's oceans?










share|improve this question









New contributor



Steve is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$









  • 3




    $begingroup$
    Please search the site first before asking a question
    $endgroup$
    – Jan Doggen
    15 hours ago







  • 1




    $begingroup$
    Field strengths combine -- it's not binary "win or lose."
    $endgroup$
    – Carl Witthoft
    13 hours ago






  • 3




    $begingroup$
    To the downvoters: Just because a question appears to be naive does not mean that the question is bad and is worthy of a downvote.
    $endgroup$
    – David Hammen
    12 hours ago










  • $begingroup$
    @Jan Doggen. Yes I should have done that. Sorry. With hindsight gained from the link you provided I still would have asked the question.
    $endgroup$
    – Steve
    6 mins ago













3












3








3





$begingroup$


Given that Earth has a much stronger gravitational pull than the Moon, how does the Moon have any influence on Earth's oceans?










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Steve is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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Given that Earth has a much stronger gravitational pull than the Moon, how does the Moon have any influence on Earth's oceans?







the-moon gravity tides






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edited 1 hour ago









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asked 16 hours ago









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  • 3




    $begingroup$
    Please search the site first before asking a question
    $endgroup$
    – Jan Doggen
    15 hours ago







  • 1




    $begingroup$
    Field strengths combine -- it's not binary "win or lose."
    $endgroup$
    – Carl Witthoft
    13 hours ago






  • 3




    $begingroup$
    To the downvoters: Just because a question appears to be naive does not mean that the question is bad and is worthy of a downvote.
    $endgroup$
    – David Hammen
    12 hours ago










  • $begingroup$
    @Jan Doggen. Yes I should have done that. Sorry. With hindsight gained from the link you provided I still would have asked the question.
    $endgroup$
    – Steve
    6 mins ago












  • 3




    $begingroup$
    Please search the site first before asking a question
    $endgroup$
    – Jan Doggen
    15 hours ago







  • 1




    $begingroup$
    Field strengths combine -- it's not binary "win or lose."
    $endgroup$
    – Carl Witthoft
    13 hours ago






  • 3




    $begingroup$
    To the downvoters: Just because a question appears to be naive does not mean that the question is bad and is worthy of a downvote.
    $endgroup$
    – David Hammen
    12 hours ago










  • $begingroup$
    @Jan Doggen. Yes I should have done that. Sorry. With hindsight gained from the link you provided I still would have asked the question.
    $endgroup$
    – Steve
    6 mins ago







3




3




$begingroup$
Please search the site first before asking a question
$endgroup$
– Jan Doggen
15 hours ago





$begingroup$
Please search the site first before asking a question
$endgroup$
– Jan Doggen
15 hours ago





1




1




$begingroup$
Field strengths combine -- it's not binary "win or lose."
$endgroup$
– Carl Witthoft
13 hours ago




$begingroup$
Field strengths combine -- it's not binary "win or lose."
$endgroup$
– Carl Witthoft
13 hours ago




3




3




$begingroup$
To the downvoters: Just because a question appears to be naive does not mean that the question is bad and is worthy of a downvote.
$endgroup$
– David Hammen
12 hours ago




$begingroup$
To the downvoters: Just because a question appears to be naive does not mean that the question is bad and is worthy of a downvote.
$endgroup$
– David Hammen
12 hours ago












$begingroup$
@Jan Doggen. Yes I should have done that. Sorry. With hindsight gained from the link you provided I still would have asked the question.
$endgroup$
– Steve
6 mins ago




$begingroup$
@Jan Doggen. Yes I should have done that. Sorry. With hindsight gained from the link you provided I still would have asked the question.
$endgroup$
– Steve
6 mins ago










2 Answers
2






active

oldest

votes


















3












$begingroup$

Everything in the universe has a gravitational influence on everything else in the universe. It isn't a question of the strongest gravitational pull winning out and all the others doing nothing.



The Earth is the strongest pull on the oceans, but the Moon and the Sun both have easily measurable effect in addition to the Earth's. Other bodies (Venus, Jupiter, a small asteroid in another galaxy,....) all have much smaller effects which will be hard or impossible to detect amidst the noise due to waves and so on.






share|improve this answer









$endgroup$






















    8












    $begingroup$

    The following diagram from the wikipedia article on the tidal force shows the tidal force that results from a moon.



    Depiction of the tidal forcing from a satellite



    Note that the tidal force is directed away from the center of the planet when the moon (satellite) is directly overhead or underfoot but is directed toward the center of the planet when the moon is on the horizon. You are right that these very small influences. The tiny changes in the vertical component of the tidal force from the Moon on the Earth have very little effect on the oceans.



    What does matter are those places where the angle between the line segment from the center of the planet to the moon and the line segment from the center of the planet to a point on the surface is approximately 45° or 135°. The tidal force is purely horizontal in those places. Minuscule as that tidal forcing is, this horizontal component of the tidal forcing function is unopposed by gravitation the Earth itself. This horizontal forcing makes the waters "want" to flow sideways.



    The direction of this flow changes constantly due to the Earth's rotation. The Coriolis effect comes into play precisely because the Earth is rotating. The shapes of the oceanic basins and continental margins also come into play. The end result is a set of amphidromic systems, each of which involves large scale oceanic waves that rotate about amphidromic points.






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      2 Answers
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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

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      active

      oldest

      votes









      3












      $begingroup$

      Everything in the universe has a gravitational influence on everything else in the universe. It isn't a question of the strongest gravitational pull winning out and all the others doing nothing.



      The Earth is the strongest pull on the oceans, but the Moon and the Sun both have easily measurable effect in addition to the Earth's. Other bodies (Venus, Jupiter, a small asteroid in another galaxy,....) all have much smaller effects which will be hard or impossible to detect amidst the noise due to waves and so on.






      share|improve this answer









      $endgroup$



















        3












        $begingroup$

        Everything in the universe has a gravitational influence on everything else in the universe. It isn't a question of the strongest gravitational pull winning out and all the others doing nothing.



        The Earth is the strongest pull on the oceans, but the Moon and the Sun both have easily measurable effect in addition to the Earth's. Other bodies (Venus, Jupiter, a small asteroid in another galaxy,....) all have much smaller effects which will be hard or impossible to detect amidst the noise due to waves and so on.






        share|improve this answer









        $endgroup$

















          3












          3








          3





          $begingroup$

          Everything in the universe has a gravitational influence on everything else in the universe. It isn't a question of the strongest gravitational pull winning out and all the others doing nothing.



          The Earth is the strongest pull on the oceans, but the Moon and the Sun both have easily measurable effect in addition to the Earth's. Other bodies (Venus, Jupiter, a small asteroid in another galaxy,....) all have much smaller effects which will be hard or impossible to detect amidst the noise due to waves and so on.






          share|improve this answer









          $endgroup$



          Everything in the universe has a gravitational influence on everything else in the universe. It isn't a question of the strongest gravitational pull winning out and all the others doing nothing.



          The Earth is the strongest pull on the oceans, but the Moon and the Sun both have easily measurable effect in addition to the Earth's. Other bodies (Venus, Jupiter, a small asteroid in another galaxy,....) all have much smaller effects which will be hard or impossible to detect amidst the noise due to waves and so on.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 15 hours ago









          Steve LintonSteve Linton

          5,1441 gold badge8 silver badges31 bronze badges




          5,1441 gold badge8 silver badges31 bronze badges


























              8












              $begingroup$

              The following diagram from the wikipedia article on the tidal force shows the tidal force that results from a moon.



              Depiction of the tidal forcing from a satellite



              Note that the tidal force is directed away from the center of the planet when the moon (satellite) is directly overhead or underfoot but is directed toward the center of the planet when the moon is on the horizon. You are right that these very small influences. The tiny changes in the vertical component of the tidal force from the Moon on the Earth have very little effect on the oceans.



              What does matter are those places where the angle between the line segment from the center of the planet to the moon and the line segment from the center of the planet to a point on the surface is approximately 45° or 135°. The tidal force is purely horizontal in those places. Minuscule as that tidal forcing is, this horizontal component of the tidal forcing function is unopposed by gravitation the Earth itself. This horizontal forcing makes the waters "want" to flow sideways.



              The direction of this flow changes constantly due to the Earth's rotation. The Coriolis effect comes into play precisely because the Earth is rotating. The shapes of the oceanic basins and continental margins also come into play. The end result is a set of amphidromic systems, each of which involves large scale oceanic waves that rotate about amphidromic points.






              share|improve this answer









              $endgroup$



















                8












                $begingroup$

                The following diagram from the wikipedia article on the tidal force shows the tidal force that results from a moon.



                Depiction of the tidal forcing from a satellite



                Note that the tidal force is directed away from the center of the planet when the moon (satellite) is directly overhead or underfoot but is directed toward the center of the planet when the moon is on the horizon. You are right that these very small influences. The tiny changes in the vertical component of the tidal force from the Moon on the Earth have very little effect on the oceans.



                What does matter are those places where the angle between the line segment from the center of the planet to the moon and the line segment from the center of the planet to a point on the surface is approximately 45° or 135°. The tidal force is purely horizontal in those places. Minuscule as that tidal forcing is, this horizontal component of the tidal forcing function is unopposed by gravitation the Earth itself. This horizontal forcing makes the waters "want" to flow sideways.



                The direction of this flow changes constantly due to the Earth's rotation. The Coriolis effect comes into play precisely because the Earth is rotating. The shapes of the oceanic basins and continental margins also come into play. The end result is a set of amphidromic systems, each of which involves large scale oceanic waves that rotate about amphidromic points.






                share|improve this answer









                $endgroup$

















                  8












                  8








                  8





                  $begingroup$

                  The following diagram from the wikipedia article on the tidal force shows the tidal force that results from a moon.



                  Depiction of the tidal forcing from a satellite



                  Note that the tidal force is directed away from the center of the planet when the moon (satellite) is directly overhead or underfoot but is directed toward the center of the planet when the moon is on the horizon. You are right that these very small influences. The tiny changes in the vertical component of the tidal force from the Moon on the Earth have very little effect on the oceans.



                  What does matter are those places where the angle between the line segment from the center of the planet to the moon and the line segment from the center of the planet to a point on the surface is approximately 45° or 135°. The tidal force is purely horizontal in those places. Minuscule as that tidal forcing is, this horizontal component of the tidal forcing function is unopposed by gravitation the Earth itself. This horizontal forcing makes the waters "want" to flow sideways.



                  The direction of this flow changes constantly due to the Earth's rotation. The Coriolis effect comes into play precisely because the Earth is rotating. The shapes of the oceanic basins and continental margins also come into play. The end result is a set of amphidromic systems, each of which involves large scale oceanic waves that rotate about amphidromic points.






                  share|improve this answer









                  $endgroup$



                  The following diagram from the wikipedia article on the tidal force shows the tidal force that results from a moon.



                  Depiction of the tidal forcing from a satellite



                  Note that the tidal force is directed away from the center of the planet when the moon (satellite) is directly overhead or underfoot but is directed toward the center of the planet when the moon is on the horizon. You are right that these very small influences. The tiny changes in the vertical component of the tidal force from the Moon on the Earth have very little effect on the oceans.



                  What does matter are those places where the angle between the line segment from the center of the planet to the moon and the line segment from the center of the planet to a point on the surface is approximately 45° or 135°. The tidal force is purely horizontal in those places. Minuscule as that tidal forcing is, this horizontal component of the tidal forcing function is unopposed by gravitation the Earth itself. This horizontal forcing makes the waters "want" to flow sideways.



                  The direction of this flow changes constantly due to the Earth's rotation. The Coriolis effect comes into play precisely because the Earth is rotating. The shapes of the oceanic basins and continental margins also come into play. The end result is a set of amphidromic systems, each of which involves large scale oceanic waves that rotate about amphidromic points.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 12 hours ago









                  David HammenDavid Hammen

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                  12k1 gold badge19 silver badges51 bronze badges























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