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How does the Moon's gravity affect Earth's oceans despite Earth's stronger gravitational pull?
Does the Moon's magnetic field affect Earth's magnetic field?How much of an effect does the moon have on Earth's liquid mantle?Earth's gravitational pull on ISSUnder Earth's gravitational pull, how dense would an object have to be to reach its Schwarzschild Radius?Meteorites bring waterHow much do the mascons on the moon affect surface gravity?Understanding gravityDoes Uranus have a stronger gravitational pull on its moons than Earth does?When the asteroid hit the earth 65 mya did the earth's gravity pull change? By how much?Can the moon's gravity influence be observed on the space station's orbit?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
Given that Earth has a much stronger gravitational pull than the Moon, how does the Moon have any influence on Earth's oceans?
the-moon gravity tides
New contributor
$endgroup$
add a comment |
$begingroup$
Given that Earth has a much stronger gravitational pull than the Moon, how does the Moon have any influence on Earth's oceans?
the-moon gravity tides
New contributor
$endgroup$
3
$begingroup$
Please search the site first before asking a question
$endgroup$
– Jan Doggen
15 hours ago
1
$begingroup$
Field strengths combine -- it's not binary "win or lose."
$endgroup$
– Carl Witthoft
13 hours ago
3
$begingroup$
To the downvoters: Just because a question appears to be naive does not mean that the question is bad and is worthy of a downvote.
$endgroup$
– David Hammen
12 hours ago
$begingroup$
@Jan Doggen. Yes I should have done that. Sorry. With hindsight gained from the link you provided I still would have asked the question.
$endgroup$
– Steve
6 mins ago
add a comment |
$begingroup$
Given that Earth has a much stronger gravitational pull than the Moon, how does the Moon have any influence on Earth's oceans?
the-moon gravity tides
New contributor
$endgroup$
Given that Earth has a much stronger gravitational pull than the Moon, how does the Moon have any influence on Earth's oceans?
the-moon gravity tides
the-moon gravity tides
New contributor
New contributor
edited 1 hour ago
Nat
2531 gold badge3 silver badges9 bronze badges
2531 gold badge3 silver badges9 bronze badges
New contributor
asked 16 hours ago
SteveSteve
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233 bronze badges
New contributor
New contributor
3
$begingroup$
Please search the site first before asking a question
$endgroup$
– Jan Doggen
15 hours ago
1
$begingroup$
Field strengths combine -- it's not binary "win or lose."
$endgroup$
– Carl Witthoft
13 hours ago
3
$begingroup$
To the downvoters: Just because a question appears to be naive does not mean that the question is bad and is worthy of a downvote.
$endgroup$
– David Hammen
12 hours ago
$begingroup$
@Jan Doggen. Yes I should have done that. Sorry. With hindsight gained from the link you provided I still would have asked the question.
$endgroup$
– Steve
6 mins ago
add a comment |
3
$begingroup$
Please search the site first before asking a question
$endgroup$
– Jan Doggen
15 hours ago
1
$begingroup$
Field strengths combine -- it's not binary "win or lose."
$endgroup$
– Carl Witthoft
13 hours ago
3
$begingroup$
To the downvoters: Just because a question appears to be naive does not mean that the question is bad and is worthy of a downvote.
$endgroup$
– David Hammen
12 hours ago
$begingroup$
@Jan Doggen. Yes I should have done that. Sorry. With hindsight gained from the link you provided I still would have asked the question.
$endgroup$
– Steve
6 mins ago
3
3
$begingroup$
Please search the site first before asking a question
$endgroup$
– Jan Doggen
15 hours ago
$begingroup$
Please search the site first before asking a question
$endgroup$
– Jan Doggen
15 hours ago
1
1
$begingroup$
Field strengths combine -- it's not binary "win or lose."
$endgroup$
– Carl Witthoft
13 hours ago
$begingroup$
Field strengths combine -- it's not binary "win or lose."
$endgroup$
– Carl Witthoft
13 hours ago
3
3
$begingroup$
To the downvoters: Just because a question appears to be naive does not mean that the question is bad and is worthy of a downvote.
$endgroup$
– David Hammen
12 hours ago
$begingroup$
To the downvoters: Just because a question appears to be naive does not mean that the question is bad and is worthy of a downvote.
$endgroup$
– David Hammen
12 hours ago
$begingroup$
@Jan Doggen. Yes I should have done that. Sorry. With hindsight gained from the link you provided I still would have asked the question.
$endgroup$
– Steve
6 mins ago
$begingroup$
@Jan Doggen. Yes I should have done that. Sorry. With hindsight gained from the link you provided I still would have asked the question.
$endgroup$
– Steve
6 mins ago
add a comment |
2 Answers
2
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$begingroup$
Everything in the universe has a gravitational influence on everything else in the universe. It isn't a question of the strongest gravitational pull winning out and all the others doing nothing.
The Earth is the strongest pull on the oceans, but the Moon and the Sun both have easily measurable effect in addition to the Earth's. Other bodies (Venus, Jupiter, a small asteroid in another galaxy,....) all have much smaller effects which will be hard or impossible to detect amidst the noise due to waves and so on.
$endgroup$
add a comment |
$begingroup$
The following diagram from the wikipedia article on the tidal force shows the tidal force that results from a moon.
Note that the tidal force is directed away from the center of the planet when the moon (satellite) is directly overhead or underfoot but is directed toward the center of the planet when the moon is on the horizon. You are right that these very small influences. The tiny changes in the vertical component of the tidal force from the Moon on the Earth have very little effect on the oceans.
What does matter are those places where the angle between the line segment from the center of the planet to the moon and the line segment from the center of the planet to a point on the surface is approximately 45° or 135°. The tidal force is purely horizontal in those places. Minuscule as that tidal forcing is, this horizontal component of the tidal forcing function is unopposed by gravitation the Earth itself. This horizontal forcing makes the waters "want" to flow sideways.
The direction of this flow changes constantly due to the Earth's rotation. The Coriolis effect comes into play precisely because the Earth is rotating. The shapes of the oceanic basins and continental margins also come into play. The end result is a set of amphidromic systems, each of which involves large scale oceanic waves that rotate about amphidromic points.
$endgroup$
add a comment |
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2 Answers
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$begingroup$
Everything in the universe has a gravitational influence on everything else in the universe. It isn't a question of the strongest gravitational pull winning out and all the others doing nothing.
The Earth is the strongest pull on the oceans, but the Moon and the Sun both have easily measurable effect in addition to the Earth's. Other bodies (Venus, Jupiter, a small asteroid in another galaxy,....) all have much smaller effects which will be hard or impossible to detect amidst the noise due to waves and so on.
$endgroup$
add a comment |
$begingroup$
Everything in the universe has a gravitational influence on everything else in the universe. It isn't a question of the strongest gravitational pull winning out and all the others doing nothing.
The Earth is the strongest pull on the oceans, but the Moon and the Sun both have easily measurable effect in addition to the Earth's. Other bodies (Venus, Jupiter, a small asteroid in another galaxy,....) all have much smaller effects which will be hard or impossible to detect amidst the noise due to waves and so on.
$endgroup$
add a comment |
$begingroup$
Everything in the universe has a gravitational influence on everything else in the universe. It isn't a question of the strongest gravitational pull winning out and all the others doing nothing.
The Earth is the strongest pull on the oceans, but the Moon and the Sun both have easily measurable effect in addition to the Earth's. Other bodies (Venus, Jupiter, a small asteroid in another galaxy,....) all have much smaller effects which will be hard or impossible to detect amidst the noise due to waves and so on.
$endgroup$
Everything in the universe has a gravitational influence on everything else in the universe. It isn't a question of the strongest gravitational pull winning out and all the others doing nothing.
The Earth is the strongest pull on the oceans, but the Moon and the Sun both have easily measurable effect in addition to the Earth's. Other bodies (Venus, Jupiter, a small asteroid in another galaxy,....) all have much smaller effects which will be hard or impossible to detect amidst the noise due to waves and so on.
answered 15 hours ago
Steve LintonSteve Linton
5,1441 gold badge8 silver badges31 bronze badges
5,1441 gold badge8 silver badges31 bronze badges
add a comment |
add a comment |
$begingroup$
The following diagram from the wikipedia article on the tidal force shows the tidal force that results from a moon.
Note that the tidal force is directed away from the center of the planet when the moon (satellite) is directly overhead or underfoot but is directed toward the center of the planet when the moon is on the horizon. You are right that these very small influences. The tiny changes in the vertical component of the tidal force from the Moon on the Earth have very little effect on the oceans.
What does matter are those places where the angle between the line segment from the center of the planet to the moon and the line segment from the center of the planet to a point on the surface is approximately 45° or 135°. The tidal force is purely horizontal in those places. Minuscule as that tidal forcing is, this horizontal component of the tidal forcing function is unopposed by gravitation the Earth itself. This horizontal forcing makes the waters "want" to flow sideways.
The direction of this flow changes constantly due to the Earth's rotation. The Coriolis effect comes into play precisely because the Earth is rotating. The shapes of the oceanic basins and continental margins also come into play. The end result is a set of amphidromic systems, each of which involves large scale oceanic waves that rotate about amphidromic points.
$endgroup$
add a comment |
$begingroup$
The following diagram from the wikipedia article on the tidal force shows the tidal force that results from a moon.
Note that the tidal force is directed away from the center of the planet when the moon (satellite) is directly overhead or underfoot but is directed toward the center of the planet when the moon is on the horizon. You are right that these very small influences. The tiny changes in the vertical component of the tidal force from the Moon on the Earth have very little effect on the oceans.
What does matter are those places where the angle between the line segment from the center of the planet to the moon and the line segment from the center of the planet to a point on the surface is approximately 45° or 135°. The tidal force is purely horizontal in those places. Minuscule as that tidal forcing is, this horizontal component of the tidal forcing function is unopposed by gravitation the Earth itself. This horizontal forcing makes the waters "want" to flow sideways.
The direction of this flow changes constantly due to the Earth's rotation. The Coriolis effect comes into play precisely because the Earth is rotating. The shapes of the oceanic basins and continental margins also come into play. The end result is a set of amphidromic systems, each of which involves large scale oceanic waves that rotate about amphidromic points.
$endgroup$
add a comment |
$begingroup$
The following diagram from the wikipedia article on the tidal force shows the tidal force that results from a moon.
Note that the tidal force is directed away from the center of the planet when the moon (satellite) is directly overhead or underfoot but is directed toward the center of the planet when the moon is on the horizon. You are right that these very small influences. The tiny changes in the vertical component of the tidal force from the Moon on the Earth have very little effect on the oceans.
What does matter are those places where the angle between the line segment from the center of the planet to the moon and the line segment from the center of the planet to a point on the surface is approximately 45° or 135°. The tidal force is purely horizontal in those places. Minuscule as that tidal forcing is, this horizontal component of the tidal forcing function is unopposed by gravitation the Earth itself. This horizontal forcing makes the waters "want" to flow sideways.
The direction of this flow changes constantly due to the Earth's rotation. The Coriolis effect comes into play precisely because the Earth is rotating. The shapes of the oceanic basins and continental margins also come into play. The end result is a set of amphidromic systems, each of which involves large scale oceanic waves that rotate about amphidromic points.
$endgroup$
The following diagram from the wikipedia article on the tidal force shows the tidal force that results from a moon.
Note that the tidal force is directed away from the center of the planet when the moon (satellite) is directly overhead or underfoot but is directed toward the center of the planet when the moon is on the horizon. You are right that these very small influences. The tiny changes in the vertical component of the tidal force from the Moon on the Earth have very little effect on the oceans.
What does matter are those places where the angle between the line segment from the center of the planet to the moon and the line segment from the center of the planet to a point on the surface is approximately 45° or 135°. The tidal force is purely horizontal in those places. Minuscule as that tidal forcing is, this horizontal component of the tidal forcing function is unopposed by gravitation the Earth itself. This horizontal forcing makes the waters "want" to flow sideways.
The direction of this flow changes constantly due to the Earth's rotation. The Coriolis effect comes into play precisely because the Earth is rotating. The shapes of the oceanic basins and continental margins also come into play. The end result is a set of amphidromic systems, each of which involves large scale oceanic waves that rotate about amphidromic points.
answered 12 hours ago
David HammenDavid Hammen
12k1 gold badge19 silver badges51 bronze badges
12k1 gold badge19 silver badges51 bronze badges
add a comment |
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Steve is a new contributor. Be nice, and check out our Code of Conduct.
Steve is a new contributor. Be nice, and check out our Code of Conduct.
Steve is a new contributor. Be nice, and check out our Code of Conduct.
Steve is a new contributor. Be nice, and check out our Code of Conduct.
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3
$begingroup$
Please search the site first before asking a question
$endgroup$
– Jan Doggen
15 hours ago
1
$begingroup$
Field strengths combine -- it's not binary "win or lose."
$endgroup$
– Carl Witthoft
13 hours ago
3
$begingroup$
To the downvoters: Just because a question appears to be naive does not mean that the question is bad and is worthy of a downvote.
$endgroup$
– David Hammen
12 hours ago
$begingroup$
@Jan Doggen. Yes I should have done that. Sorry. With hindsight gained from the link you provided I still would have asked the question.
$endgroup$
– Steve
6 mins ago