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linearization of objective function


How to linearize the product of a binary and a non-negative continuous variable?Simplest way to eliminate redundant constraints due to a new cutVariable bounds in column generationHow to formulate maximum function in a constraint?Is my approach to my internship project good? Optimal allocation of product across stores, constrained optimizationQA techniques for optimization problem codingFormulation of a constraint in a MIP for an element in different SetsHow to formulate this scheduling problem efficiently?How to reformulate (linearize/convexify) a budgeted assignment problem?Linearize or approximate a square root constraintFinding minimum time for vehicle to reach to its destination













4












$begingroup$


$src_h,s$, $dst_h,s$, $ch_h,s$ are constants.



$a_h,s$, $x_i,j,s$ are binary variables.



$wt_h,s$ are continuous variables.



$mini.$
$$
sum_h in H sum_s in S (src_h,s + ch_h,s + dst_h,s + wt_h,s) times a_h,s
$$



$s.t.$



$$
forall i in H hspace0.3cm forall j in H hspace0.3cm forall s in S hspace0.3cm
$$

$$
wt_j,s geq ((src_i,s + ch_i,s+wt_i,s) - src_j,s) times x_i,j,s
$$



$$
forall i in H hspace0.3cm forall j in H hspace0.3cm
x_ij + x_ji leq 1
$$



$$
forall i in H hspace0.3cm forall j in H hspace0.3cm forall s in S hspace0.3cm
$$

$$
x_ij + x_ji geq a_i,s + a_j,s + 1
$$



$$
forall h in H sum_s in S b_h,s leq 1
$$



I want to use a LP solver on this problem but there are continuous variable $wt_h,s$ and Boolean variable $a_h,s$ together in objective function, how to separate them.



I have found a link for linearization in constraints, (https://www.leandro-coelho.com/linearization-product-variables/) but how to linearize in objective function.



Also in first constraint there are two continuous variable $wt_j,s$ and $wt_i,s$, is it possible to linearize it.










share|improve this question











$endgroup$









  • 1




    $begingroup$
    Linearize the objective function the same way you would a constraint. Having two continuous variables in the first constraint doesn't add any complications because one of these variable appears "by itself", i.e., not multiplied by another variable, and therefore that variable already appears linearly.
    $endgroup$
    – Mark L. Stone
    8 hours ago






  • 1




    $begingroup$
    Maybe take a look at this question: How to linearize the product of a binary and a non-negative continuous variable?
    $endgroup$
    – EhsanK
    6 hours ago










  • $begingroup$
    Is this $$ sum_h in H sum_s in S (src_h,s + ch_h,s + dst_h,s ) times a_h,s + ( wt_h,s - (1 - a_h,s) times infty ) $$ correct linearization of objective function, but what about the bounds.
    $endgroup$
    – anoop yadav
    6 hours ago
















4












$begingroup$


$src_h,s$, $dst_h,s$, $ch_h,s$ are constants.



$a_h,s$, $x_i,j,s$ are binary variables.



$wt_h,s$ are continuous variables.



$mini.$
$$
sum_h in H sum_s in S (src_h,s + ch_h,s + dst_h,s + wt_h,s) times a_h,s
$$



$s.t.$



$$
forall i in H hspace0.3cm forall j in H hspace0.3cm forall s in S hspace0.3cm
$$

$$
wt_j,s geq ((src_i,s + ch_i,s+wt_i,s) - src_j,s) times x_i,j,s
$$



$$
forall i in H hspace0.3cm forall j in H hspace0.3cm
x_ij + x_ji leq 1
$$



$$
forall i in H hspace0.3cm forall j in H hspace0.3cm forall s in S hspace0.3cm
$$

$$
x_ij + x_ji geq a_i,s + a_j,s + 1
$$



$$
forall h in H sum_s in S b_h,s leq 1
$$



I want to use a LP solver on this problem but there are continuous variable $wt_h,s$ and Boolean variable $a_h,s$ together in objective function, how to separate them.



I have found a link for linearization in constraints, (https://www.leandro-coelho.com/linearization-product-variables/) but how to linearize in objective function.



Also in first constraint there are two continuous variable $wt_j,s$ and $wt_i,s$, is it possible to linearize it.










share|improve this question











$endgroup$









  • 1




    $begingroup$
    Linearize the objective function the same way you would a constraint. Having two continuous variables in the first constraint doesn't add any complications because one of these variable appears "by itself", i.e., not multiplied by another variable, and therefore that variable already appears linearly.
    $endgroup$
    – Mark L. Stone
    8 hours ago






  • 1




    $begingroup$
    Maybe take a look at this question: How to linearize the product of a binary and a non-negative continuous variable?
    $endgroup$
    – EhsanK
    6 hours ago










  • $begingroup$
    Is this $$ sum_h in H sum_s in S (src_h,s + ch_h,s + dst_h,s ) times a_h,s + ( wt_h,s - (1 - a_h,s) times infty ) $$ correct linearization of objective function, but what about the bounds.
    $endgroup$
    – anoop yadav
    6 hours ago














4












4








4





$begingroup$


$src_h,s$, $dst_h,s$, $ch_h,s$ are constants.



$a_h,s$, $x_i,j,s$ are binary variables.



$wt_h,s$ are continuous variables.



$mini.$
$$
sum_h in H sum_s in S (src_h,s + ch_h,s + dst_h,s + wt_h,s) times a_h,s
$$



$s.t.$



$$
forall i in H hspace0.3cm forall j in H hspace0.3cm forall s in S hspace0.3cm
$$

$$
wt_j,s geq ((src_i,s + ch_i,s+wt_i,s) - src_j,s) times x_i,j,s
$$



$$
forall i in H hspace0.3cm forall j in H hspace0.3cm
x_ij + x_ji leq 1
$$



$$
forall i in H hspace0.3cm forall j in H hspace0.3cm forall s in S hspace0.3cm
$$

$$
x_ij + x_ji geq a_i,s + a_j,s + 1
$$



$$
forall h in H sum_s in S b_h,s leq 1
$$



I want to use a LP solver on this problem but there are continuous variable $wt_h,s$ and Boolean variable $a_h,s$ together in objective function, how to separate them.



I have found a link for linearization in constraints, (https://www.leandro-coelho.com/linearization-product-variables/) but how to linearize in objective function.



Also in first constraint there are two continuous variable $wt_j,s$ and $wt_i,s$, is it possible to linearize it.










share|improve this question











$endgroup$




$src_h,s$, $dst_h,s$, $ch_h,s$ are constants.



$a_h,s$, $x_i,j,s$ are binary variables.



$wt_h,s$ are continuous variables.



$mini.$
$$
sum_h in H sum_s in S (src_h,s + ch_h,s + dst_h,s + wt_h,s) times a_h,s
$$



$s.t.$



$$
forall i in H hspace0.3cm forall j in H hspace0.3cm forall s in S hspace0.3cm
$$

$$
wt_j,s geq ((src_i,s + ch_i,s+wt_i,s) - src_j,s) times x_i,j,s
$$



$$
forall i in H hspace0.3cm forall j in H hspace0.3cm
x_ij + x_ji leq 1
$$



$$
forall i in H hspace0.3cm forall j in H hspace0.3cm forall s in S hspace0.3cm
$$

$$
x_ij + x_ji geq a_i,s + a_j,s + 1
$$



$$
forall h in H sum_s in S b_h,s leq 1
$$



I want to use a LP solver on this problem but there are continuous variable $wt_h,s$ and Boolean variable $a_h,s$ together in objective function, how to separate them.



I have found a link for linearization in constraints, (https://www.leandro-coelho.com/linearization-product-variables/) but how to linearize in objective function.



Also in first constraint there are two continuous variable $wt_j,s$ and $wt_i,s$, is it possible to linearize it.







linear-programming optimization linearization






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 6 hours ago









Simon

4471 silver badge12 bronze badges




4471 silver badge12 bronze badges










asked 8 hours ago









anoop yadavanoop yadav

1084 bronze badges




1084 bronze badges










  • 1




    $begingroup$
    Linearize the objective function the same way you would a constraint. Having two continuous variables in the first constraint doesn't add any complications because one of these variable appears "by itself", i.e., not multiplied by another variable, and therefore that variable already appears linearly.
    $endgroup$
    – Mark L. Stone
    8 hours ago






  • 1




    $begingroup$
    Maybe take a look at this question: How to linearize the product of a binary and a non-negative continuous variable?
    $endgroup$
    – EhsanK
    6 hours ago










  • $begingroup$
    Is this $$ sum_h in H sum_s in S (src_h,s + ch_h,s + dst_h,s ) times a_h,s + ( wt_h,s - (1 - a_h,s) times infty ) $$ correct linearization of objective function, but what about the bounds.
    $endgroup$
    – anoop yadav
    6 hours ago













  • 1




    $begingroup$
    Linearize the objective function the same way you would a constraint. Having two continuous variables in the first constraint doesn't add any complications because one of these variable appears "by itself", i.e., not multiplied by another variable, and therefore that variable already appears linearly.
    $endgroup$
    – Mark L. Stone
    8 hours ago






  • 1




    $begingroup$
    Maybe take a look at this question: How to linearize the product of a binary and a non-negative continuous variable?
    $endgroup$
    – EhsanK
    6 hours ago










  • $begingroup$
    Is this $$ sum_h in H sum_s in S (src_h,s + ch_h,s + dst_h,s ) times a_h,s + ( wt_h,s - (1 - a_h,s) times infty ) $$ correct linearization of objective function, but what about the bounds.
    $endgroup$
    – anoop yadav
    6 hours ago








1




1




$begingroup$
Linearize the objective function the same way you would a constraint. Having two continuous variables in the first constraint doesn't add any complications because one of these variable appears "by itself", i.e., not multiplied by another variable, and therefore that variable already appears linearly.
$endgroup$
– Mark L. Stone
8 hours ago




$begingroup$
Linearize the objective function the same way you would a constraint. Having two continuous variables in the first constraint doesn't add any complications because one of these variable appears "by itself", i.e., not multiplied by another variable, and therefore that variable already appears linearly.
$endgroup$
– Mark L. Stone
8 hours ago




1




1




$begingroup$
Maybe take a look at this question: How to linearize the product of a binary and a non-negative continuous variable?
$endgroup$
– EhsanK
6 hours ago




$begingroup$
Maybe take a look at this question: How to linearize the product of a binary and a non-negative continuous variable?
$endgroup$
– EhsanK
6 hours ago












$begingroup$
Is this $$ sum_h in H sum_s in S (src_h,s + ch_h,s + dst_h,s ) times a_h,s + ( wt_h,s - (1 - a_h,s) times infty ) $$ correct linearization of objective function, but what about the bounds.
$endgroup$
– anoop yadav
6 hours ago





$begingroup$
Is this $$ sum_h in H sum_s in S (src_h,s + ch_h,s + dst_h,s ) times a_h,s + ( wt_h,s - (1 - a_h,s) times infty ) $$ correct linearization of objective function, but what about the bounds.
$endgroup$
– anoop yadav
6 hours ago











2 Answers
2






active

oldest

votes


















5












$begingroup$

Piecewise linearization methods have been widely applied to convert a nonlinear programming problem into a linear programming problem or a mixed-integer convex programming problem for obtaining an approximated global optimal solution. In the transformation process, extra binary variables, continuous variables, and constraints are introduced to reformulate the original problem. These extra variables and constraints mainly determine the solution efficiency of the converted problem.[source]






share|improve this answer









$endgroup$






















    2












    $begingroup$

    1. Add some additional continuous variables $s_h,s$ to your model and use those variables in the objective, instead of the products.



    2. Add the following constraints for each $s_h,s$:




      • This constraint ensures that $s_h,s$ is at most equal to the sum:



        $s_h,s leq src_h,s+ch_h,s+dst_h,s+wt_h,s$




      • This constraint ensures that $s_h,s$ will be at least the sum when $a_h,s=1$:



        $s_h,s geq src_h,s+ch_h,s+dst_h,s+wt_h,s - M times (1 - a_h,s) $




      • This constraints ensures that $s_h,s=0$ when $a_h,s=0$:



        $s_h,s leq M times a_h,s $




    Some notes about this:



    • I assumed that your constants and variables are all nonnegative.

    • You should pick small values for the constant $M$ to make it all work (e.g. $src_h,s+ch_h,s+dst_h,s+UB(wt_h,s)$). Picking much larger values leads to lower performance and might even introduce numerical problems.

    • If your solver of choice supports indicator constraints, you could also formulate it using those.





    share|improve this answer









    $endgroup$

















      Your Answer








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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      5












      $begingroup$

      Piecewise linearization methods have been widely applied to convert a nonlinear programming problem into a linear programming problem or a mixed-integer convex programming problem for obtaining an approximated global optimal solution. In the transformation process, extra binary variables, continuous variables, and constraints are introduced to reformulate the original problem. These extra variables and constraints mainly determine the solution efficiency of the converted problem.[source]






      share|improve this answer









      $endgroup$



















        5












        $begingroup$

        Piecewise linearization methods have been widely applied to convert a nonlinear programming problem into a linear programming problem or a mixed-integer convex programming problem for obtaining an approximated global optimal solution. In the transformation process, extra binary variables, continuous variables, and constraints are introduced to reformulate the original problem. These extra variables and constraints mainly determine the solution efficiency of the converted problem.[source]






        share|improve this answer









        $endgroup$

















          5












          5








          5





          $begingroup$

          Piecewise linearization methods have been widely applied to convert a nonlinear programming problem into a linear programming problem or a mixed-integer convex programming problem for obtaining an approximated global optimal solution. In the transformation process, extra binary variables, continuous variables, and constraints are introduced to reformulate the original problem. These extra variables and constraints mainly determine the solution efficiency of the converted problem.[source]






          share|improve this answer









          $endgroup$



          Piecewise linearization methods have been widely applied to convert a nonlinear programming problem into a linear programming problem or a mixed-integer convex programming problem for obtaining an approximated global optimal solution. In the transformation process, extra binary variables, continuous variables, and constraints are introduced to reformulate the original problem. These extra variables and constraints mainly determine the solution efficiency of the converted problem.[source]







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 7 hours ago









          Oguz ToragayOguz Toragay

          1,5691 silver badge20 bronze badges




          1,5691 silver badge20 bronze badges
























              2












              $begingroup$

              1. Add some additional continuous variables $s_h,s$ to your model and use those variables in the objective, instead of the products.



              2. Add the following constraints for each $s_h,s$:




                • This constraint ensures that $s_h,s$ is at most equal to the sum:



                  $s_h,s leq src_h,s+ch_h,s+dst_h,s+wt_h,s$




                • This constraint ensures that $s_h,s$ will be at least the sum when $a_h,s=1$:



                  $s_h,s geq src_h,s+ch_h,s+dst_h,s+wt_h,s - M times (1 - a_h,s) $




                • This constraints ensures that $s_h,s=0$ when $a_h,s=0$:



                  $s_h,s leq M times a_h,s $




              Some notes about this:



              • I assumed that your constants and variables are all nonnegative.

              • You should pick small values for the constant $M$ to make it all work (e.g. $src_h,s+ch_h,s+dst_h,s+UB(wt_h,s)$). Picking much larger values leads to lower performance and might even introduce numerical problems.

              • If your solver of choice supports indicator constraints, you could also formulate it using those.





              share|improve this answer









              $endgroup$



















                2












                $begingroup$

                1. Add some additional continuous variables $s_h,s$ to your model and use those variables in the objective, instead of the products.



                2. Add the following constraints for each $s_h,s$:




                  • This constraint ensures that $s_h,s$ is at most equal to the sum:



                    $s_h,s leq src_h,s+ch_h,s+dst_h,s+wt_h,s$




                  • This constraint ensures that $s_h,s$ will be at least the sum when $a_h,s=1$:



                    $s_h,s geq src_h,s+ch_h,s+dst_h,s+wt_h,s - M times (1 - a_h,s) $




                  • This constraints ensures that $s_h,s=0$ when $a_h,s=0$:



                    $s_h,s leq M times a_h,s $




                Some notes about this:



                • I assumed that your constants and variables are all nonnegative.

                • You should pick small values for the constant $M$ to make it all work (e.g. $src_h,s+ch_h,s+dst_h,s+UB(wt_h,s)$). Picking much larger values leads to lower performance and might even introduce numerical problems.

                • If your solver of choice supports indicator constraints, you could also formulate it using those.





                share|improve this answer









                $endgroup$

















                  2












                  2








                  2





                  $begingroup$

                  1. Add some additional continuous variables $s_h,s$ to your model and use those variables in the objective, instead of the products.



                  2. Add the following constraints for each $s_h,s$:




                    • This constraint ensures that $s_h,s$ is at most equal to the sum:



                      $s_h,s leq src_h,s+ch_h,s+dst_h,s+wt_h,s$




                    • This constraint ensures that $s_h,s$ will be at least the sum when $a_h,s=1$:



                      $s_h,s geq src_h,s+ch_h,s+dst_h,s+wt_h,s - M times (1 - a_h,s) $




                    • This constraints ensures that $s_h,s=0$ when $a_h,s=0$:



                      $s_h,s leq M times a_h,s $




                  Some notes about this:



                  • I assumed that your constants and variables are all nonnegative.

                  • You should pick small values for the constant $M$ to make it all work (e.g. $src_h,s+ch_h,s+dst_h,s+UB(wt_h,s)$). Picking much larger values leads to lower performance and might even introduce numerical problems.

                  • If your solver of choice supports indicator constraints, you could also formulate it using those.





                  share|improve this answer









                  $endgroup$



                  1. Add some additional continuous variables $s_h,s$ to your model and use those variables in the objective, instead of the products.



                  2. Add the following constraints for each $s_h,s$:




                    • This constraint ensures that $s_h,s$ is at most equal to the sum:



                      $s_h,s leq src_h,s+ch_h,s+dst_h,s+wt_h,s$




                    • This constraint ensures that $s_h,s$ will be at least the sum when $a_h,s=1$:



                      $s_h,s geq src_h,s+ch_h,s+dst_h,s+wt_h,s - M times (1 - a_h,s) $




                    • This constraints ensures that $s_h,s=0$ when $a_h,s=0$:



                      $s_h,s leq M times a_h,s $




                  Some notes about this:



                  • I assumed that your constants and variables are all nonnegative.

                  • You should pick small values for the constant $M$ to make it all work (e.g. $src_h,s+ch_h,s+dst_h,s+UB(wt_h,s)$). Picking much larger values leads to lower performance and might even introduce numerical problems.

                  • If your solver of choice supports indicator constraints, you could also formulate it using those.






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 4 hours ago









                  SimonSimon

                  4471 silver badge12 bronze badges




                  4471 silver badge12 bronze badges






























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                      Tom Holland Mục lục Đầu đời và giáo dục | Sự nghiệp | Cuộc sống cá nhân | Phim tham gia | Giải thưởng và đề cử | Chú thích | Liên kết ngoài | Trình đơn chuyển hướngProfile“Person Details for Thomas Stanley Holland, "England and Wales Birth Registration Index, 1837-2008" — FamilySearch.org”"Meet Tom Holland... the 16-year-old star of The Impossible""Schoolboy actor Tom Holland finds himself in Oscar contention for role in tsunami drama"“Naomi Watts on the Prince William and Harry's reaction to her film about the late Princess Diana”lưu trữ"Holland and Pflueger Are West End's Two New 'Billy Elliots'""I'm so envious of my son, the movie star! British writer Dominic Holland's spent 20 years trying to crack Hollywood - but he's been beaten to it by a very unlikely rival"“Richard and Margaret Povey of Jersey, Channel Islands, UK: Information about Thomas Stanley Holland”"Tom Holland to play Billy Elliot""New Billy Elliot leaving the garage"Billy Elliot the Musical - Tom Holland - Billy"A Tale of four Billys: Tom Holland""The Feel Good Factor""Thames Christian College schoolboys join Myleene Klass for The Feelgood Factor""Government launches £600,000 arts bursaries pilot""BILLY's Chapman, Holland, Gardner & Jackson-Keen Visit Prime Minister""Elton John 'blown away' by Billy Elliot fifth birthday" (video with John's interview and fragments of Holland's performance)"First News interviews Arrietty's Tom Holland"“33rd Critics' Circle Film Awards winners”“National Board of Review Current Awards”Bản gốc"Ron Howard Whaling Tale 'In The Heart Of The Sea' Casts Tom Holland"“'Spider-Man' Finds Tom Holland to Star as New Web-Slinger”lưu trữ“Captain America: Civil War (2016)”“Film Review: ‘Captain America: Civil War’”lưu trữ“‘Captain America: Civil War’ review: Choose your own avenger”lưu trữ“The Lost City of Z reviews”“Sony Pictures and Marvel Studios Find Their 'Spider-Man' Star and Director”“‘Mary Magdalene’, ‘Current War’ & ‘Wind River’ Get 2017 Release Dates From Weinstein”“Lionsgate Unleashing Daisy Ridley & Tom Holland Starrer ‘Chaos Walking’ In Cannes”“PTA's 'Master' Leads Chicago Film Critics Nominations, UPDATED: Houston and Indiana Critics Nominations”“Nominaciones Goya 2013 Telecinco Cinema – ENG”“Jameson Empire Film Awards: Martin Freeman wins best actor for performance in The Hobbit”“34th Annual Young Artist Awards”Bản gốc“Teen Choice Awards 2016—Captain America: Civil War Leads Second Wave of Nominations”“BAFTA Film Award Nominations: ‘La La Land’ Leads Race”“Saturn Awards Nominations 2017: 'Rogue One,' 'Walking Dead' Lead”Tom HollandTom HollandTom HollandTom Hollandmedia.gettyimages.comWorldCat Identities300279794no20130442900000 0004 0355 42791085670554170004732cb16706349t(data)XX5557367