Number of optically active compounds among the products of ozonolysisOptical isomerism in Co-ordination CompoundsPredicting reaction among compoundsCan a system of 2 consecutive Biphenyl systems be optically active , even if any adjacent biphenyl systems arent optically active?Can the following compound having a centre of symmetry be called both optically inactive and meso?Is the product of Lindlar hydrogenation of (2Z,4S)-4-methylhept-2-en-5-yne optically active?Why are optically active compounds abundant in nature?Are compounds containing active methylene groups positive for the haloform test?Is trans-1,2-dimethylcyclopropane optically active or not?How to find the number of optically active and optically inactive isomers for a spiropentane derivative?How many stereoisomers can exist for 4,5-bis(3-hydroxyoct-1-en-1-yl)cyclopentane-1,3-diol?
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Number of optically active compounds among the products of ozonolysis
Optical isomerism in Co-ordination CompoundsPredicting reaction among compoundsCan a system of 2 consecutive Biphenyl systems be optically active , even if any adjacent biphenyl systems arent optically active?Can the following compound having a centre of symmetry be called both optically inactive and meso?Is the product of Lindlar hydrogenation of (2Z,4S)-4-methylhept-2-en-5-yne optically active?Why are optically active compounds abundant in nature?Are compounds containing active methylene groups positive for the haloform test?Is trans-1,2-dimethylcyclopropane optically active or not?How to find the number of optically active and optically inactive isomers for a spiropentane derivative?How many stereoisomers can exist for 4,5-bis(3-hydroxyoct-1-en-1-yl)cyclopentane-1,3-diol?
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$begingroup$
The number of optically active compound(s) obtained upon complete ozonolysis of
the following optically active compound is
In the question, I broke all the double bonds and added a $ce-CHO$ group according to the question (ozonolysis).
Checking for the optically active compounds I found two of them:
But the solution has given only one compound! Can you please help me with this?
organic-chemistry stereochemistry ozone
$endgroup$
add a comment |
$begingroup$
The number of optically active compound(s) obtained upon complete ozonolysis of
the following optically active compound is
In the question, I broke all the double bonds and added a $ce-CHO$ group according to the question (ozonolysis).
Checking for the optically active compounds I found two of them:
But the solution has given only one compound! Can you please help me with this?
organic-chemistry stereochemistry ozone
$endgroup$
add a comment |
$begingroup$
The number of optically active compound(s) obtained upon complete ozonolysis of
the following optically active compound is
In the question, I broke all the double bonds and added a $ce-CHO$ group according to the question (ozonolysis).
Checking for the optically active compounds I found two of them:
But the solution has given only one compound! Can you please help me with this?
organic-chemistry stereochemistry ozone
$endgroup$
The number of optically active compound(s) obtained upon complete ozonolysis of
the following optically active compound is
In the question, I broke all the double bonds and added a $ce-CHO$ group according to the question (ozonolysis).
Checking for the optically active compounds I found two of them:
But the solution has given only one compound! Can you please help me with this?
organic-chemistry stereochemistry ozone
organic-chemistry stereochemistry ozone
edited 5 hours ago
andselisk♦
21.6k7 gold badges75 silver badges144 bronze badges
21.6k7 gold badges75 silver badges144 bronze badges
asked 14 hours ago
Asad AhmadAsad Ahmad
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163 bronze badges
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2 Answers
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$begingroup$
The given answer is correct. The product scheme you drew is correct as well. However, as I marked in your scheme (see below), products A and B are essentially the same enanthiomer (both have (2S)-configuration). The compounds you have drown in right-hand side are also an identical compound, which is not optically active. Therefore, ozonolysis has given only one optically active compound.
$endgroup$
add a comment |
$begingroup$
Ozonolysis of the given compound gives $ceI$ , $ceII$ , $ceIII$ and $ceIV$.
$ceI$ and $ceII$ are Homomers and have same configuration "S" and therefore identical (as shown in the figure).
$ceIII$ and $ceIV$ are achiral . Therefore , the total number of optically
active compounds formed after ozonolysis is $ce= 1$.
$endgroup$
add a comment |
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2 Answers
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2 Answers
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$begingroup$
The given answer is correct. The product scheme you drew is correct as well. However, as I marked in your scheme (see below), products A and B are essentially the same enanthiomer (both have (2S)-configuration). The compounds you have drown in right-hand side are also an identical compound, which is not optically active. Therefore, ozonolysis has given only one optically active compound.
$endgroup$
add a comment |
$begingroup$
The given answer is correct. The product scheme you drew is correct as well. However, as I marked in your scheme (see below), products A and B are essentially the same enanthiomer (both have (2S)-configuration). The compounds you have drown in right-hand side are also an identical compound, which is not optically active. Therefore, ozonolysis has given only one optically active compound.
$endgroup$
add a comment |
$begingroup$
The given answer is correct. The product scheme you drew is correct as well. However, as I marked in your scheme (see below), products A and B are essentially the same enanthiomer (both have (2S)-configuration). The compounds you have drown in right-hand side are also an identical compound, which is not optically active. Therefore, ozonolysis has given only one optically active compound.
$endgroup$
The given answer is correct. The product scheme you drew is correct as well. However, as I marked in your scheme (see below), products A and B are essentially the same enanthiomer (both have (2S)-configuration). The compounds you have drown in right-hand side are also an identical compound, which is not optically active. Therefore, ozonolysis has given only one optically active compound.
edited 11 hours ago
answered 11 hours ago
Mathew MahindaratneMathew Mahindaratne
10.3k1 gold badge12 silver badges37 bronze badges
10.3k1 gold badge12 silver badges37 bronze badges
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$begingroup$
Ozonolysis of the given compound gives $ceI$ , $ceII$ , $ceIII$ and $ceIV$.
$ceI$ and $ceII$ are Homomers and have same configuration "S" and therefore identical (as shown in the figure).
$ceIII$ and $ceIV$ are achiral . Therefore , the total number of optically
active compounds formed after ozonolysis is $ce= 1$.
$endgroup$
add a comment |
$begingroup$
Ozonolysis of the given compound gives $ceI$ , $ceII$ , $ceIII$ and $ceIV$.
$ceI$ and $ceII$ are Homomers and have same configuration "S" and therefore identical (as shown in the figure).
$ceIII$ and $ceIV$ are achiral . Therefore , the total number of optically
active compounds formed after ozonolysis is $ce= 1$.
$endgroup$
add a comment |
$begingroup$
Ozonolysis of the given compound gives $ceI$ , $ceII$ , $ceIII$ and $ceIV$.
$ceI$ and $ceII$ are Homomers and have same configuration "S" and therefore identical (as shown in the figure).
$ceIII$ and $ceIV$ are achiral . Therefore , the total number of optically
active compounds formed after ozonolysis is $ce= 1$.
$endgroup$
Ozonolysis of the given compound gives $ceI$ , $ceII$ , $ceIII$ and $ceIV$.
$ceI$ and $ceII$ are Homomers and have same configuration "S" and therefore identical (as shown in the figure).
$ceIII$ and $ceIV$ are achiral . Therefore , the total number of optically
active compounds formed after ozonolysis is $ce= 1$.
edited 3 hours ago
answered 3 hours ago
Chakravarthy KalyanChakravarthy Kalyan
2,6745 silver badges23 bronze badges
2,6745 silver badges23 bronze badges
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