Generating random numbers that keep a minimum distanceSimple algorithm to find cycles in edge listHow to Gather a list with some elements considered uniqueFinding Local Minima / Maxima in Noisy DataGarbage collection for memoized functions on subkernelsIssue with very large lists in MathematicaGenerating random symmetric matrixNeed Help Writing code to find Capparelli PartitionsDoes Mathematica have a functional programming idiom to loop over a list till a condition is met?Toroidal metric in a random geometric graphLooking up one additional array element increases runtime by three orders of magnitude

Storming Area 51

US Civil War story: man hanged from a bridge

Is there any word for "disobedience to God"?

Why does the U.S. tolerate foreign influence from Saudi Arabia and Israel on its domestic policies while not tolerating that from China or Russia?

Generating random numbers that keep a minimum distance

Graduate student with abysmal English writing skills, how to help

How can I effectively communicate to recruiters that a phone call is not possible?

Why were Er and Onan punished if they were under 20?

Using Newton's shell theorem to accelerate a spaceship

How would vampires avoid contracting diseases?

How to convert a file with several spaces into a tab-delimited file?

When casting Eldritch Blast with the Agonizing Blast eldritch invocation, what do I add to my damage roll?

Are there any sports for which the world's best player is female?

Cops: The Hidden OEIS Substring

Constructive proof of existence of free algebras for infinitary equational theories

C program to parse source code of another language

Why isn't pressure filtration popular compared to vacuum filtration?

Is "I do not want you to go nowhere" a case of "DOUBLE-NEGATIVES" as claimed by Grammarly?

Are unclear "take-it or leave-it" contracts interpreted in my favor?

How to md5 a list of filepaths contained in a file?

How were Martello towers supposed to work?

Why weren't bootable game disks ever common on the IBM PC?

How to tell someone I'd like to become friends without causing them to them think I'm romantically interested in them?

How can I get a player to accept that they should stop trying to pull stunts without thinking them through first?



Generating random numbers that keep a minimum distance


Simple algorithm to find cycles in edge listHow to Gather a list with some elements considered uniqueFinding Local Minima / Maxima in Noisy DataGarbage collection for memoized functions on subkernelsIssue with very large lists in MathematicaGenerating random symmetric matrixNeed Help Writing code to find Capparelli PartitionsDoes Mathematica have a functional programming idiom to loop over a list till a condition is met?Toroidal metric in a random geometric graphLooking up one additional array element increases runtime by three orders of magnitude






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3












$begingroup$


I want to create a list of n random integers from 1 to m, where all integers have to be at least a certain distance min apart (i.e. 3 integers out of Range[10], keeping a minimum distance of 2)



This is the module I created to fullfill that purpose:



StartGen[MinimalDistance_] := 
Module[nCells, min,test,i,j,r,
min = MinimalDistance;

(*Just create a Random Sample from Range[m] if min=0
is chosen*)
If[min == 0,
nCells = Sort[RandomSample[Range[m], n]];
Return[nCells]
,
nCells = Table[0, n];
nCells[[1]] = RandomInteger[m];
i = 1; j = 1;

(*Only execute if n integers out of m actually can
keep a minimum distance of min*)
If[m/(n (min + 1)) >= 1,

While[i <= n,
(*Generate random integers from Range[m] until one
fits with the already assigned Integers*)
r = RandomInteger[m];
test = True;
Do[If[Abs[nCells[[j]] - r] <= min,
test = False; Break[],
test = True], j, i
];
If[test == True, nCells[[i]] = r; i++, Null];
];

nCells = Sort[nCells];
Return[nCells];
,
Print["Impossible figuration for m n and min"];
];
];
];


Now the performance problem this creates is quite obvious: If the number of possible integers m and the minimum distance min are too big, as the While loop goes on fewer and fewer generated integers will fit the requirements and it gets harder and harder to hit those few integers through generating random numbers out of Range[m]. (For me this module couldn't produce lists for n=100,m=1000,min=8.)



I think the solution to this problem lies in reducing the number of Integers to choose from as the calculation go on, i.e. eliminate integers that dont fit the requirements anymore.



I tried implementing this with some variants of the DeleteCases[] function but I always ended up just creating more iterative calculations that would worsen the performance once again.

Is there an elegant way to do this?










share|improve this question







New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$











  • $begingroup$
    Your problem is that Length[Range[8, 1000, 2 8 - 1]] equals 67 which is less than 100. So that's just not always possible with n=100, m=1000, and min=8.
    $endgroup$
    – Henrik Schumacher
    8 hours ago

















3












$begingroup$


I want to create a list of n random integers from 1 to m, where all integers have to be at least a certain distance min apart (i.e. 3 integers out of Range[10], keeping a minimum distance of 2)



This is the module I created to fullfill that purpose:



StartGen[MinimalDistance_] := 
Module[nCells, min,test,i,j,r,
min = MinimalDistance;

(*Just create a Random Sample from Range[m] if min=0
is chosen*)
If[min == 0,
nCells = Sort[RandomSample[Range[m], n]];
Return[nCells]
,
nCells = Table[0, n];
nCells[[1]] = RandomInteger[m];
i = 1; j = 1;

(*Only execute if n integers out of m actually can
keep a minimum distance of min*)
If[m/(n (min + 1)) >= 1,

While[i <= n,
(*Generate random integers from Range[m] until one
fits with the already assigned Integers*)
r = RandomInteger[m];
test = True;
Do[If[Abs[nCells[[j]] - r] <= min,
test = False; Break[],
test = True], j, i
];
If[test == True, nCells[[i]] = r; i++, Null];
];

nCells = Sort[nCells];
Return[nCells];
,
Print["Impossible figuration for m n and min"];
];
];
];


Now the performance problem this creates is quite obvious: If the number of possible integers m and the minimum distance min are too big, as the While loop goes on fewer and fewer generated integers will fit the requirements and it gets harder and harder to hit those few integers through generating random numbers out of Range[m]. (For me this module couldn't produce lists for n=100,m=1000,min=8.)



I think the solution to this problem lies in reducing the number of Integers to choose from as the calculation go on, i.e. eliminate integers that dont fit the requirements anymore.



I tried implementing this with some variants of the DeleteCases[] function but I always ended up just creating more iterative calculations that would worsen the performance once again.

Is there an elegant way to do this?










share|improve this question







New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$











  • $begingroup$
    Your problem is that Length[Range[8, 1000, 2 8 - 1]] equals 67 which is less than 100. So that's just not always possible with n=100, m=1000, and min=8.
    $endgroup$
    – Henrik Schumacher
    8 hours ago













3












3








3


1



$begingroup$


I want to create a list of n random integers from 1 to m, where all integers have to be at least a certain distance min apart (i.e. 3 integers out of Range[10], keeping a minimum distance of 2)



This is the module I created to fullfill that purpose:



StartGen[MinimalDistance_] := 
Module[nCells, min,test,i,j,r,
min = MinimalDistance;

(*Just create a Random Sample from Range[m] if min=0
is chosen*)
If[min == 0,
nCells = Sort[RandomSample[Range[m], n]];
Return[nCells]
,
nCells = Table[0, n];
nCells[[1]] = RandomInteger[m];
i = 1; j = 1;

(*Only execute if n integers out of m actually can
keep a minimum distance of min*)
If[m/(n (min + 1)) >= 1,

While[i <= n,
(*Generate random integers from Range[m] until one
fits with the already assigned Integers*)
r = RandomInteger[m];
test = True;
Do[If[Abs[nCells[[j]] - r] <= min,
test = False; Break[],
test = True], j, i
];
If[test == True, nCells[[i]] = r; i++, Null];
];

nCells = Sort[nCells];
Return[nCells];
,
Print["Impossible figuration for m n and min"];
];
];
];


Now the performance problem this creates is quite obvious: If the number of possible integers m and the minimum distance min are too big, as the While loop goes on fewer and fewer generated integers will fit the requirements and it gets harder and harder to hit those few integers through generating random numbers out of Range[m]. (For me this module couldn't produce lists for n=100,m=1000,min=8.)



I think the solution to this problem lies in reducing the number of Integers to choose from as the calculation go on, i.e. eliminate integers that dont fit the requirements anymore.



I tried implementing this with some variants of the DeleteCases[] function but I always ended up just creating more iterative calculations that would worsen the performance once again.

Is there an elegant way to do this?










share|improve this question







New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




I want to create a list of n random integers from 1 to m, where all integers have to be at least a certain distance min apart (i.e. 3 integers out of Range[10], keeping a minimum distance of 2)



This is the module I created to fullfill that purpose:



StartGen[MinimalDistance_] := 
Module[nCells, min,test,i,j,r,
min = MinimalDistance;

(*Just create a Random Sample from Range[m] if min=0
is chosen*)
If[min == 0,
nCells = Sort[RandomSample[Range[m], n]];
Return[nCells]
,
nCells = Table[0, n];
nCells[[1]] = RandomInteger[m];
i = 1; j = 1;

(*Only execute if n integers out of m actually can
keep a minimum distance of min*)
If[m/(n (min + 1)) >= 1,

While[i <= n,
(*Generate random integers from Range[m] until one
fits with the already assigned Integers*)
r = RandomInteger[m];
test = True;
Do[If[Abs[nCells[[j]] - r] <= min,
test = False; Break[],
test = True], j, i
];
If[test == True, nCells[[i]] = r; i++, Null];
];

nCells = Sort[nCells];
Return[nCells];
,
Print["Impossible figuration for m n and min"];
];
];
];


Now the performance problem this creates is quite obvious: If the number of possible integers m and the minimum distance min are too big, as the While loop goes on fewer and fewer generated integers will fit the requirements and it gets harder and harder to hit those few integers through generating random numbers out of Range[m]. (For me this module couldn't produce lists for n=100,m=1000,min=8.)



I think the solution to this problem lies in reducing the number of Integers to choose from as the calculation go on, i.e. eliminate integers that dont fit the requirements anymore.



I tried implementing this with some variants of the DeleteCases[] function but I always ended up just creating more iterative calculations that would worsen the performance once again.

Is there an elegant way to do this?







list-manipulation performance-tuning






share|improve this question







New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question







New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question






New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked 9 hours ago









Maxim HanselowskiMaxim Hanselowski

161 bronze badge




161 bronze badge




New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.













  • $begingroup$
    Your problem is that Length[Range[8, 1000, 2 8 - 1]] equals 67 which is less than 100. So that's just not always possible with n=100, m=1000, and min=8.
    $endgroup$
    – Henrik Schumacher
    8 hours ago
















  • $begingroup$
    Your problem is that Length[Range[8, 1000, 2 8 - 1]] equals 67 which is less than 100. So that's just not always possible with n=100, m=1000, and min=8.
    $endgroup$
    – Henrik Schumacher
    8 hours ago















$begingroup$
Your problem is that Length[Range[8, 1000, 2 8 - 1]] equals 67 which is less than 100. So that's just not always possible with n=100, m=1000, and min=8.
$endgroup$
– Henrik Schumacher
8 hours ago




$begingroup$
Your problem is that Length[Range[8, 1000, 2 8 - 1]] equals 67 which is less than 100. So that's just not always possible with n=100, m=1000, and min=8.
$endgroup$
– Henrik Schumacher
8 hours ago










2 Answers
2






active

oldest

votes


















3












$begingroup$

  1. Construct a random sample from Range[m] satisfying the minimum
    distance requirements taking into account the fact that if $x_k$ is
    selected at step $k$, the choices in step $k+1$ are restricted to
    the range from $x_k + d$ to $m - (n-k)d$ to be able to get $n-k$
    additional elements in remaining steps satisfying the minimum distance constraint.

  2. Shuffle the list obtained in the first step



ClearAll[f]
f[m_, n_, d_] /; n d <= m := RandomSample @ Rest @
FoldList[RandomChoice[Range[# + Boole[#2 > 1] d, m - (n - #2) d]] &, 1, Range[n]]


Examples:



Table[f[10, 3, 2], 5]



8, 3, 6, 6, 10, 8, 8, 5, 10, 8, 10, 6, 10, 1, 4




Min[Differences@Sort@#] & /@ %



2, 2, 2, 2, 3




f[10, 4, 3]



f[10, 4, 3] (* impossible *)




f[1000, 100, 8]



848, 808, 189, 776, 680, 824, 472, 728, 352, 976, 736, 544, 504,
936, 904, 408, 720, 400, 816, 448, 856, 560, 279, 336, 312, 512, 888,
928, 424, 944, 584, 480, 238, 552, 920, 568, 528, 600, 952, 304, 536,
688, 632, 712, 992, 592, 616, 221, 896, 456, 864, 344, 792, 744, 392,
624, 320, 984, 576, 206, 648, 960, 368, 840, 872, 376, 328, 752, 832,
24, 288, 640, 416, 1000, 760, 696, 520, 488, 672, 464, 249, 800, 968,
768, 664, 432, 384, 784, 271, 912, 296, 656, 704, 496, 608, 230, 880,
360, 257, 440




Min @ Differences@ Sort @ %



8




res = f[10000000, 10000, 800]; // AbsoluteTiming // First



0.105936




Min @ Differences @ Sort @ res



800




Update: An alternative implementation using NestList:



ClearAll[f2]
f2[m_, n_, d_] /; n d <= m := Module[k = 1, RandomSample @ Rest @
NestList[RandomChoice[Range[# + Boole[k++ > 1] d, m - (n - k) d]] &, 1, n]]





share|improve this answer











$endgroup$




















    2












    $begingroup$

    How about something like this - rather than picking random numbers until one satisfies the minimum distance criteria, pick the random number from a set that excludes disallowed values.



    gen2[m_, n_, min_] := Module[nCells, set,
    set = Range[m];
    nCells = RandomSample[set, 1];
    While[Length[nCells] < n && Length[set] > 0,
    set = Complement[set,
    Range[nCells[[-1]] - min + 1, nCells[[-1]] + min - 1]];
    If[Length[set] < 1, Print["Couldn't pick ", n],
    nCells = Join[nCells, RandomSample[set, 1]]];
    ];
    nCells]


    Table[gen2[10, 3, 2], 10] // Column
    (*
    4,7,10
    8,3,6
    2,6,9
    5,8,3
    7,10,1
    3,10,6
    3,7,10
    3,9,6
    1,10,5
    9,2,6 *)


    As noted by Henrik Schumacher in the comments, n=100, m=1000, min=8 doesn't work most of the time (you get an empty set before you pick 100 numbers):



    gen2[1000, 100, 8]
    (*
    Couldn't pick 100
    599, 14, 526, 475, 52, 448, 791, 576, 196, 711, 941, 35, 211, 483,
    371, 401, 827, 354, 757, 547, 858, 86, 222, 336, 696, 913, 419, 386,
    812, 363, 982, 974, 563, 966, 665, 279, 955, 494, 243, 675, 151, 994,
    742, 5, 298, 438, 901, 316, 24, 627, 636, 873, 411, 684, 261, 516,
    107, 586, 138, 768, 508, 290, 650, 253, 850, 116, 73, 464, 173, 163,
    129, 94, 428, 346, 842, 609, 888, 306, 619, 181, 922, 44, 555, 931,
    231, 539, 327, 731, 776, 456, 799, 64, 722, 271 *)



    But 7 is fine:



    test = gen2[1000, 100, 7]
    (*
    556, 966, 917, 863, 425, 155, 414, 504, 43, 82, 395, 196, 765, 701,
    55, 330, 935, 626, 337, 843, 511, 885, 441, 834, 756, 117, 572, 285,
    519, 17, 189, 658, 563, 817, 266, 727, 28, 854, 805, 747, 775, 210,
    997, 546, 138, 303, 608, 295, 900, 145, 718, 355, 176, 666, 130, 946,
    259, 102, 405, 795, 452, 649, 480, 591, 240, 363, 63, 641, 95, 694,
    493, 221, 536, 978, 633, 784, 739, 387, 871, 827, 675, 465, 10, 954,
    580, 599, 686, 878, 36, 1, 926, 373, 320, 529, 348, 248, 708, 893,
    311, 273 *)


    Test the minimum distance between numbers:



    stest = Sort[test];
    Min[Table[stest[[i]] - stest[[i - 1]], i, 2, Length[test]]]
    (* 7 *)
    ```





    share|improve this answer









    $endgroup$















      Your Answer








      StackExchange.ready(function()
      var channelOptions =
      tags: "".split(" "),
      id: "387"
      ;
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function()
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled)
      StackExchange.using("snippets", function()
      createEditor();
      );

      else
      createEditor();

      );

      function createEditor()
      StackExchange.prepareEditor(
      heartbeatType: 'answer',
      autoActivateHeartbeat: false,
      convertImagesToLinks: false,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: null,
      bindNavPrevention: true,
      postfix: "",
      imageUploader:
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      ,
      onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      );



      );






      Maxim Hanselowski is a new contributor. Be nice, and check out our Code of Conduct.









      draft saved

      draft discarded


















      StackExchange.ready(
      function ()
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f201889%2fgenerating-random-numbers-that-keep-a-minimum-distance%23new-answer', 'question_page');

      );

      Post as a guest















      Required, but never shown

























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3












      $begingroup$

      1. Construct a random sample from Range[m] satisfying the minimum
        distance requirements taking into account the fact that if $x_k$ is
        selected at step $k$, the choices in step $k+1$ are restricted to
        the range from $x_k + d$ to $m - (n-k)d$ to be able to get $n-k$
        additional elements in remaining steps satisfying the minimum distance constraint.

      2. Shuffle the list obtained in the first step



      ClearAll[f]
      f[m_, n_, d_] /; n d <= m := RandomSample @ Rest @
      FoldList[RandomChoice[Range[# + Boole[#2 > 1] d, m - (n - #2) d]] &, 1, Range[n]]


      Examples:



      Table[f[10, 3, 2], 5]



      8, 3, 6, 6, 10, 8, 8, 5, 10, 8, 10, 6, 10, 1, 4




      Min[Differences@Sort@#] & /@ %



      2, 2, 2, 2, 3




      f[10, 4, 3]



      f[10, 4, 3] (* impossible *)




      f[1000, 100, 8]



      848, 808, 189, 776, 680, 824, 472, 728, 352, 976, 736, 544, 504,
      936, 904, 408, 720, 400, 816, 448, 856, 560, 279, 336, 312, 512, 888,
      928, 424, 944, 584, 480, 238, 552, 920, 568, 528, 600, 952, 304, 536,
      688, 632, 712, 992, 592, 616, 221, 896, 456, 864, 344, 792, 744, 392,
      624, 320, 984, 576, 206, 648, 960, 368, 840, 872, 376, 328, 752, 832,
      24, 288, 640, 416, 1000, 760, 696, 520, 488, 672, 464, 249, 800, 968,
      768, 664, 432, 384, 784, 271, 912, 296, 656, 704, 496, 608, 230, 880,
      360, 257, 440




      Min @ Differences@ Sort @ %



      8




      res = f[10000000, 10000, 800]; // AbsoluteTiming // First



      0.105936




      Min @ Differences @ Sort @ res



      800




      Update: An alternative implementation using NestList:



      ClearAll[f2]
      f2[m_, n_, d_] /; n d <= m := Module[k = 1, RandomSample @ Rest @
      NestList[RandomChoice[Range[# + Boole[k++ > 1] d, m - (n - k) d]] &, 1, n]]





      share|improve this answer











      $endgroup$

















        3












        $begingroup$

        1. Construct a random sample from Range[m] satisfying the minimum
          distance requirements taking into account the fact that if $x_k$ is
          selected at step $k$, the choices in step $k+1$ are restricted to
          the range from $x_k + d$ to $m - (n-k)d$ to be able to get $n-k$
          additional elements in remaining steps satisfying the minimum distance constraint.

        2. Shuffle the list obtained in the first step



        ClearAll[f]
        f[m_, n_, d_] /; n d <= m := RandomSample @ Rest @
        FoldList[RandomChoice[Range[# + Boole[#2 > 1] d, m - (n - #2) d]] &, 1, Range[n]]


        Examples:



        Table[f[10, 3, 2], 5]



        8, 3, 6, 6, 10, 8, 8, 5, 10, 8, 10, 6, 10, 1, 4




        Min[Differences@Sort@#] & /@ %



        2, 2, 2, 2, 3




        f[10, 4, 3]



        f[10, 4, 3] (* impossible *)




        f[1000, 100, 8]



        848, 808, 189, 776, 680, 824, 472, 728, 352, 976, 736, 544, 504,
        936, 904, 408, 720, 400, 816, 448, 856, 560, 279, 336, 312, 512, 888,
        928, 424, 944, 584, 480, 238, 552, 920, 568, 528, 600, 952, 304, 536,
        688, 632, 712, 992, 592, 616, 221, 896, 456, 864, 344, 792, 744, 392,
        624, 320, 984, 576, 206, 648, 960, 368, 840, 872, 376, 328, 752, 832,
        24, 288, 640, 416, 1000, 760, 696, 520, 488, 672, 464, 249, 800, 968,
        768, 664, 432, 384, 784, 271, 912, 296, 656, 704, 496, 608, 230, 880,
        360, 257, 440




        Min @ Differences@ Sort @ %



        8




        res = f[10000000, 10000, 800]; // AbsoluteTiming // First



        0.105936




        Min @ Differences @ Sort @ res



        800




        Update: An alternative implementation using NestList:



        ClearAll[f2]
        f2[m_, n_, d_] /; n d <= m := Module[k = 1, RandomSample @ Rest @
        NestList[RandomChoice[Range[# + Boole[k++ > 1] d, m - (n - k) d]] &, 1, n]]





        share|improve this answer











        $endgroup$















          3












          3








          3





          $begingroup$

          1. Construct a random sample from Range[m] satisfying the minimum
            distance requirements taking into account the fact that if $x_k$ is
            selected at step $k$, the choices in step $k+1$ are restricted to
            the range from $x_k + d$ to $m - (n-k)d$ to be able to get $n-k$
            additional elements in remaining steps satisfying the minimum distance constraint.

          2. Shuffle the list obtained in the first step



          ClearAll[f]
          f[m_, n_, d_] /; n d <= m := RandomSample @ Rest @
          FoldList[RandomChoice[Range[# + Boole[#2 > 1] d, m - (n - #2) d]] &, 1, Range[n]]


          Examples:



          Table[f[10, 3, 2], 5]



          8, 3, 6, 6, 10, 8, 8, 5, 10, 8, 10, 6, 10, 1, 4




          Min[Differences@Sort@#] & /@ %



          2, 2, 2, 2, 3




          f[10, 4, 3]



          f[10, 4, 3] (* impossible *)




          f[1000, 100, 8]



          848, 808, 189, 776, 680, 824, 472, 728, 352, 976, 736, 544, 504,
          936, 904, 408, 720, 400, 816, 448, 856, 560, 279, 336, 312, 512, 888,
          928, 424, 944, 584, 480, 238, 552, 920, 568, 528, 600, 952, 304, 536,
          688, 632, 712, 992, 592, 616, 221, 896, 456, 864, 344, 792, 744, 392,
          624, 320, 984, 576, 206, 648, 960, 368, 840, 872, 376, 328, 752, 832,
          24, 288, 640, 416, 1000, 760, 696, 520, 488, 672, 464, 249, 800, 968,
          768, 664, 432, 384, 784, 271, 912, 296, 656, 704, 496, 608, 230, 880,
          360, 257, 440




          Min @ Differences@ Sort @ %



          8




          res = f[10000000, 10000, 800]; // AbsoluteTiming // First



          0.105936




          Min @ Differences @ Sort @ res



          800




          Update: An alternative implementation using NestList:



          ClearAll[f2]
          f2[m_, n_, d_] /; n d <= m := Module[k = 1, RandomSample @ Rest @
          NestList[RandomChoice[Range[# + Boole[k++ > 1] d, m - (n - k) d]] &, 1, n]]





          share|improve this answer











          $endgroup$



          1. Construct a random sample from Range[m] satisfying the minimum
            distance requirements taking into account the fact that if $x_k$ is
            selected at step $k$, the choices in step $k+1$ are restricted to
            the range from $x_k + d$ to $m - (n-k)d$ to be able to get $n-k$
            additional elements in remaining steps satisfying the minimum distance constraint.

          2. Shuffle the list obtained in the first step



          ClearAll[f]
          f[m_, n_, d_] /; n d <= m := RandomSample @ Rest @
          FoldList[RandomChoice[Range[# + Boole[#2 > 1] d, m - (n - #2) d]] &, 1, Range[n]]


          Examples:



          Table[f[10, 3, 2], 5]



          8, 3, 6, 6, 10, 8, 8, 5, 10, 8, 10, 6, 10, 1, 4




          Min[Differences@Sort@#] & /@ %



          2, 2, 2, 2, 3




          f[10, 4, 3]



          f[10, 4, 3] (* impossible *)




          f[1000, 100, 8]



          848, 808, 189, 776, 680, 824, 472, 728, 352, 976, 736, 544, 504,
          936, 904, 408, 720, 400, 816, 448, 856, 560, 279, 336, 312, 512, 888,
          928, 424, 944, 584, 480, 238, 552, 920, 568, 528, 600, 952, 304, 536,
          688, 632, 712, 992, 592, 616, 221, 896, 456, 864, 344, 792, 744, 392,
          624, 320, 984, 576, 206, 648, 960, 368, 840, 872, 376, 328, 752, 832,
          24, 288, 640, 416, 1000, 760, 696, 520, 488, 672, 464, 249, 800, 968,
          768, 664, 432, 384, 784, 271, 912, 296, 656, 704, 496, 608, 230, 880,
          360, 257, 440




          Min @ Differences@ Sort @ %



          8




          res = f[10000000, 10000, 800]; // AbsoluteTiming // First



          0.105936




          Min @ Differences @ Sort @ res



          800




          Update: An alternative implementation using NestList:



          ClearAll[f2]
          f2[m_, n_, d_] /; n d <= m := Module[k = 1, RandomSample @ Rest @
          NestList[RandomChoice[Range[# + Boole[k++ > 1] d, m - (n - k) d]] &, 1, n]]






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 3 hours ago

























          answered 7 hours ago









          kglrkglr

          204k10 gold badges233 silver badges463 bronze badges




          204k10 gold badges233 silver badges463 bronze badges























              2












              $begingroup$

              How about something like this - rather than picking random numbers until one satisfies the minimum distance criteria, pick the random number from a set that excludes disallowed values.



              gen2[m_, n_, min_] := Module[nCells, set,
              set = Range[m];
              nCells = RandomSample[set, 1];
              While[Length[nCells] < n && Length[set] > 0,
              set = Complement[set,
              Range[nCells[[-1]] - min + 1, nCells[[-1]] + min - 1]];
              If[Length[set] < 1, Print["Couldn't pick ", n],
              nCells = Join[nCells, RandomSample[set, 1]]];
              ];
              nCells]


              Table[gen2[10, 3, 2], 10] // Column
              (*
              4,7,10
              8,3,6
              2,6,9
              5,8,3
              7,10,1
              3,10,6
              3,7,10
              3,9,6
              1,10,5
              9,2,6 *)


              As noted by Henrik Schumacher in the comments, n=100, m=1000, min=8 doesn't work most of the time (you get an empty set before you pick 100 numbers):



              gen2[1000, 100, 8]
              (*
              Couldn't pick 100
              599, 14, 526, 475, 52, 448, 791, 576, 196, 711, 941, 35, 211, 483,
              371, 401, 827, 354, 757, 547, 858, 86, 222, 336, 696, 913, 419, 386,
              812, 363, 982, 974, 563, 966, 665, 279, 955, 494, 243, 675, 151, 994,
              742, 5, 298, 438, 901, 316, 24, 627, 636, 873, 411, 684, 261, 516,
              107, 586, 138, 768, 508, 290, 650, 253, 850, 116, 73, 464, 173, 163,
              129, 94, 428, 346, 842, 609, 888, 306, 619, 181, 922, 44, 555, 931,
              231, 539, 327, 731, 776, 456, 799, 64, 722, 271 *)



              But 7 is fine:



              test = gen2[1000, 100, 7]
              (*
              556, 966, 917, 863, 425, 155, 414, 504, 43, 82, 395, 196, 765, 701,
              55, 330, 935, 626, 337, 843, 511, 885, 441, 834, 756, 117, 572, 285,
              519, 17, 189, 658, 563, 817, 266, 727, 28, 854, 805, 747, 775, 210,
              997, 546, 138, 303, 608, 295, 900, 145, 718, 355, 176, 666, 130, 946,
              259, 102, 405, 795, 452, 649, 480, 591, 240, 363, 63, 641, 95, 694,
              493, 221, 536, 978, 633, 784, 739, 387, 871, 827, 675, 465, 10, 954,
              580, 599, 686, 878, 36, 1, 926, 373, 320, 529, 348, 248, 708, 893,
              311, 273 *)


              Test the minimum distance between numbers:



              stest = Sort[test];
              Min[Table[stest[[i]] - stest[[i - 1]], i, 2, Length[test]]]
              (* 7 *)
              ```





              share|improve this answer









              $endgroup$

















                2












                $begingroup$

                How about something like this - rather than picking random numbers until one satisfies the minimum distance criteria, pick the random number from a set that excludes disallowed values.



                gen2[m_, n_, min_] := Module[nCells, set,
                set = Range[m];
                nCells = RandomSample[set, 1];
                While[Length[nCells] < n && Length[set] > 0,
                set = Complement[set,
                Range[nCells[[-1]] - min + 1, nCells[[-1]] + min - 1]];
                If[Length[set] < 1, Print["Couldn't pick ", n],
                nCells = Join[nCells, RandomSample[set, 1]]];
                ];
                nCells]


                Table[gen2[10, 3, 2], 10] // Column
                (*
                4,7,10
                8,3,6
                2,6,9
                5,8,3
                7,10,1
                3,10,6
                3,7,10
                3,9,6
                1,10,5
                9,2,6 *)


                As noted by Henrik Schumacher in the comments, n=100, m=1000, min=8 doesn't work most of the time (you get an empty set before you pick 100 numbers):



                gen2[1000, 100, 8]
                (*
                Couldn't pick 100
                599, 14, 526, 475, 52, 448, 791, 576, 196, 711, 941, 35, 211, 483,
                371, 401, 827, 354, 757, 547, 858, 86, 222, 336, 696, 913, 419, 386,
                812, 363, 982, 974, 563, 966, 665, 279, 955, 494, 243, 675, 151, 994,
                742, 5, 298, 438, 901, 316, 24, 627, 636, 873, 411, 684, 261, 516,
                107, 586, 138, 768, 508, 290, 650, 253, 850, 116, 73, 464, 173, 163,
                129, 94, 428, 346, 842, 609, 888, 306, 619, 181, 922, 44, 555, 931,
                231, 539, 327, 731, 776, 456, 799, 64, 722, 271 *)



                But 7 is fine:



                test = gen2[1000, 100, 7]
                (*
                556, 966, 917, 863, 425, 155, 414, 504, 43, 82, 395, 196, 765, 701,
                55, 330, 935, 626, 337, 843, 511, 885, 441, 834, 756, 117, 572, 285,
                519, 17, 189, 658, 563, 817, 266, 727, 28, 854, 805, 747, 775, 210,
                997, 546, 138, 303, 608, 295, 900, 145, 718, 355, 176, 666, 130, 946,
                259, 102, 405, 795, 452, 649, 480, 591, 240, 363, 63, 641, 95, 694,
                493, 221, 536, 978, 633, 784, 739, 387, 871, 827, 675, 465, 10, 954,
                580, 599, 686, 878, 36, 1, 926, 373, 320, 529, 348, 248, 708, 893,
                311, 273 *)


                Test the minimum distance between numbers:



                stest = Sort[test];
                Min[Table[stest[[i]] - stest[[i - 1]], i, 2, Length[test]]]
                (* 7 *)
                ```





                share|improve this answer









                $endgroup$















                  2












                  2








                  2





                  $begingroup$

                  How about something like this - rather than picking random numbers until one satisfies the minimum distance criteria, pick the random number from a set that excludes disallowed values.



                  gen2[m_, n_, min_] := Module[nCells, set,
                  set = Range[m];
                  nCells = RandomSample[set, 1];
                  While[Length[nCells] < n && Length[set] > 0,
                  set = Complement[set,
                  Range[nCells[[-1]] - min + 1, nCells[[-1]] + min - 1]];
                  If[Length[set] < 1, Print["Couldn't pick ", n],
                  nCells = Join[nCells, RandomSample[set, 1]]];
                  ];
                  nCells]


                  Table[gen2[10, 3, 2], 10] // Column
                  (*
                  4,7,10
                  8,3,6
                  2,6,9
                  5,8,3
                  7,10,1
                  3,10,6
                  3,7,10
                  3,9,6
                  1,10,5
                  9,2,6 *)


                  As noted by Henrik Schumacher in the comments, n=100, m=1000, min=8 doesn't work most of the time (you get an empty set before you pick 100 numbers):



                  gen2[1000, 100, 8]
                  (*
                  Couldn't pick 100
                  599, 14, 526, 475, 52, 448, 791, 576, 196, 711, 941, 35, 211, 483,
                  371, 401, 827, 354, 757, 547, 858, 86, 222, 336, 696, 913, 419, 386,
                  812, 363, 982, 974, 563, 966, 665, 279, 955, 494, 243, 675, 151, 994,
                  742, 5, 298, 438, 901, 316, 24, 627, 636, 873, 411, 684, 261, 516,
                  107, 586, 138, 768, 508, 290, 650, 253, 850, 116, 73, 464, 173, 163,
                  129, 94, 428, 346, 842, 609, 888, 306, 619, 181, 922, 44, 555, 931,
                  231, 539, 327, 731, 776, 456, 799, 64, 722, 271 *)



                  But 7 is fine:



                  test = gen2[1000, 100, 7]
                  (*
                  556, 966, 917, 863, 425, 155, 414, 504, 43, 82, 395, 196, 765, 701,
                  55, 330, 935, 626, 337, 843, 511, 885, 441, 834, 756, 117, 572, 285,
                  519, 17, 189, 658, 563, 817, 266, 727, 28, 854, 805, 747, 775, 210,
                  997, 546, 138, 303, 608, 295, 900, 145, 718, 355, 176, 666, 130, 946,
                  259, 102, 405, 795, 452, 649, 480, 591, 240, 363, 63, 641, 95, 694,
                  493, 221, 536, 978, 633, 784, 739, 387, 871, 827, 675, 465, 10, 954,
                  580, 599, 686, 878, 36, 1, 926, 373, 320, 529, 348, 248, 708, 893,
                  311, 273 *)


                  Test the minimum distance between numbers:



                  stest = Sort[test];
                  Min[Table[stest[[i]] - stest[[i - 1]], i, 2, Length[test]]]
                  (* 7 *)
                  ```





                  share|improve this answer









                  $endgroup$



                  How about something like this - rather than picking random numbers until one satisfies the minimum distance criteria, pick the random number from a set that excludes disallowed values.



                  gen2[m_, n_, min_] := Module[nCells, set,
                  set = Range[m];
                  nCells = RandomSample[set, 1];
                  While[Length[nCells] < n && Length[set] > 0,
                  set = Complement[set,
                  Range[nCells[[-1]] - min + 1, nCells[[-1]] + min - 1]];
                  If[Length[set] < 1, Print["Couldn't pick ", n],
                  nCells = Join[nCells, RandomSample[set, 1]]];
                  ];
                  nCells]


                  Table[gen2[10, 3, 2], 10] // Column
                  (*
                  4,7,10
                  8,3,6
                  2,6,9
                  5,8,3
                  7,10,1
                  3,10,6
                  3,7,10
                  3,9,6
                  1,10,5
                  9,2,6 *)


                  As noted by Henrik Schumacher in the comments, n=100, m=1000, min=8 doesn't work most of the time (you get an empty set before you pick 100 numbers):



                  gen2[1000, 100, 8]
                  (*
                  Couldn't pick 100
                  599, 14, 526, 475, 52, 448, 791, 576, 196, 711, 941, 35, 211, 483,
                  371, 401, 827, 354, 757, 547, 858, 86, 222, 336, 696, 913, 419, 386,
                  812, 363, 982, 974, 563, 966, 665, 279, 955, 494, 243, 675, 151, 994,
                  742, 5, 298, 438, 901, 316, 24, 627, 636, 873, 411, 684, 261, 516,
                  107, 586, 138, 768, 508, 290, 650, 253, 850, 116, 73, 464, 173, 163,
                  129, 94, 428, 346, 842, 609, 888, 306, 619, 181, 922, 44, 555, 931,
                  231, 539, 327, 731, 776, 456, 799, 64, 722, 271 *)



                  But 7 is fine:



                  test = gen2[1000, 100, 7]
                  (*
                  556, 966, 917, 863, 425, 155, 414, 504, 43, 82, 395, 196, 765, 701,
                  55, 330, 935, 626, 337, 843, 511, 885, 441, 834, 756, 117, 572, 285,
                  519, 17, 189, 658, 563, 817, 266, 727, 28, 854, 805, 747, 775, 210,
                  997, 546, 138, 303, 608, 295, 900, 145, 718, 355, 176, 666, 130, 946,
                  259, 102, 405, 795, 452, 649, 480, 591, 240, 363, 63, 641, 95, 694,
                  493, 221, 536, 978, 633, 784, 739, 387, 871, 827, 675, 465, 10, 954,
                  580, 599, 686, 878, 36, 1, 926, 373, 320, 529, 348, 248, 708, 893,
                  311, 273 *)


                  Test the minimum distance between numbers:



                  stest = Sort[test];
                  Min[Table[stest[[i]] - stest[[i - 1]], i, 2, Length[test]]]
                  (* 7 *)
                  ```






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 7 hours ago









                  MelaGoMelaGo

                  2,0361 gold badge1 silver badge7 bronze badges




                  2,0361 gold badge1 silver badge7 bronze badges




















                      Maxim Hanselowski is a new contributor. Be nice, and check out our Code of Conduct.









                      draft saved

                      draft discarded


















                      Maxim Hanselowski is a new contributor. Be nice, and check out our Code of Conduct.












                      Maxim Hanselowski is a new contributor. Be nice, and check out our Code of Conduct.











                      Maxim Hanselowski is a new contributor. Be nice, and check out our Code of Conduct.














                      Thanks for contributing an answer to Mathematica Stack Exchange!


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid


                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.

                      Use MathJax to format equations. MathJax reference.


                      To learn more, see our tips on writing great answers.




                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function ()
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f201889%2fgenerating-random-numbers-that-keep-a-minimum-distance%23new-answer', 'question_page');

                      );

                      Post as a guest















                      Required, but never shown





















































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown

































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown







                      Popular posts from this blog

                      Invision Community Contents History See also References External links Navigation menuProprietaryinvisioncommunity.comIPS Community ForumsIPS Community Forumsthis blog entry"License Changes, IP.Board 3.4, and the Future""Interview -- Matt Mecham of Ibforums""CEO Invision Power Board, Matt Mecham Is a Liar, Thief!"IPB License Explanation 1.3, 1.3.1, 2.0, and 2.1ArchivedSecurity Fixes, Updates And Enhancements For IPB 1.3.1Archived"New Demo Accounts - Invision Power Services"the original"New Default Skin"the original"Invision Power Board 3.0.0 and Applications Released"the original"Archived copy"the original"Perpetual licenses being done away with""Release Notes - Invision Power Services""Introducing: IPS Community Suite 4!"Invision Community Release Notes

                      Canceling a color specificationRandomly assigning color to Graphics3D objects?Default color for Filling in Mathematica 9Coloring specific elements of sets with a prime modified order in an array plotHow to pick a color differing significantly from the colors already in a given color list?Detection of the text colorColor numbers based on their valueCan color schemes for use with ColorData include opacity specification?My dynamic color schemes

                      Ласкавець круглолистий Зміст Опис | Поширення | Галерея | Примітки | Посилання | Навігаційне меню58171138361-22960890446Bupleurum rotundifoliumEuro+Med PlantbasePlants of the World Online — Kew ScienceGermplasm Resources Information Network (GRIN)Ласкавецькн. VI : Літери Ком — Левиправивши або дописавши її