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Why should password hash verification be time consistent?
Why is it always `HASH( salt + password )` that we recommend?What encryption hash function I should use for password securing?Why we use GPG signatures for file verification instead of hash values?Why should I hash passwords?Should email verification be followed by password-based login? Why?Potential collision with hash passwordWhy is hashing a password with multiple hash functions useless?Why should password authentication require sending the password?Send hash password or send password to hash in server?Why should we protect access to password hashes?
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In the asp.net core PasswordHasher type there is is remark on the VerifyHashedPassword method
/// <remarks>Implementations of this method should be time consistent.</remarks>
And then to compare the hashes it uses code that is deliberately not optimised and written not do early exits in the loop.
// Compares two byte arrays for equality. The method is specifically written so that the loop is not optimized.
[MethodImpl(MethodImplOptions.NoInlining | MethodImplOptions.NoOptimization)]
private static bool ByteArraysEqual(byte[] a, byte[] b)
At first I thought that without this timing could be used to determine how close the hash was, if it takes longer then more of the hash is the same.
However this doesn't make sense because the hash has gone through 1000 iterations of SHA256 at this point. So any change in the password would produce a completely different hash, and knowing that your password produces almost the correct hash does not help you find the correct one.
What is the purpose of ensuring a constant time hash verification?
passwords hash
New contributor
add a comment |
In the asp.net core PasswordHasher type there is is remark on the VerifyHashedPassword method
/// <remarks>Implementations of this method should be time consistent.</remarks>
And then to compare the hashes it uses code that is deliberately not optimised and written not do early exits in the loop.
// Compares two byte arrays for equality. The method is specifically written so that the loop is not optimized.
[MethodImpl(MethodImplOptions.NoInlining | MethodImplOptions.NoOptimization)]
private static bool ByteArraysEqual(byte[] a, byte[] b)
At first I thought that without this timing could be used to determine how close the hash was, if it takes longer then more of the hash is the same.
However this doesn't make sense because the hash has gone through 1000 iterations of SHA256 at this point. So any change in the password would produce a completely different hash, and knowing that your password produces almost the correct hash does not help you find the correct one.
What is the purpose of ensuring a constant time hash verification?
passwords hash
New contributor
Is that function used for anything other than comparing hashes?
– forest
3 hours ago
no it is only used for comparing hashes
– trampster
3 hours ago
add a comment |
In the asp.net core PasswordHasher type there is is remark on the VerifyHashedPassword method
/// <remarks>Implementations of this method should be time consistent.</remarks>
And then to compare the hashes it uses code that is deliberately not optimised and written not do early exits in the loop.
// Compares two byte arrays for equality. The method is specifically written so that the loop is not optimized.
[MethodImpl(MethodImplOptions.NoInlining | MethodImplOptions.NoOptimization)]
private static bool ByteArraysEqual(byte[] a, byte[] b)
At first I thought that without this timing could be used to determine how close the hash was, if it takes longer then more of the hash is the same.
However this doesn't make sense because the hash has gone through 1000 iterations of SHA256 at this point. So any change in the password would produce a completely different hash, and knowing that your password produces almost the correct hash does not help you find the correct one.
What is the purpose of ensuring a constant time hash verification?
passwords hash
New contributor
In the asp.net core PasswordHasher type there is is remark on the VerifyHashedPassword method
/// <remarks>Implementations of this method should be time consistent.</remarks>
And then to compare the hashes it uses code that is deliberately not optimised and written not do early exits in the loop.
// Compares two byte arrays for equality. The method is specifically written so that the loop is not optimized.
[MethodImpl(MethodImplOptions.NoInlining | MethodImplOptions.NoOptimization)]
private static bool ByteArraysEqual(byte[] a, byte[] b)
At first I thought that without this timing could be used to determine how close the hash was, if it takes longer then more of the hash is the same.
However this doesn't make sense because the hash has gone through 1000 iterations of SHA256 at this point. So any change in the password would produce a completely different hash, and knowing that your password produces almost the correct hash does not help you find the correct one.
What is the purpose of ensuring a constant time hash verification?
passwords hash
passwords hash
New contributor
New contributor
New contributor
asked 3 hours ago
trampstertrampster
1163
1163
New contributor
New contributor
Is that function used for anything other than comparing hashes?
– forest
3 hours ago
no it is only used for comparing hashes
– trampster
3 hours ago
add a comment |
Is that function used for anything other than comparing hashes?
– forest
3 hours ago
no it is only used for comparing hashes
– trampster
3 hours ago
Is that function used for anything other than comparing hashes?
– forest
3 hours ago
Is that function used for anything other than comparing hashes?
– forest
3 hours ago
no it is only used for comparing hashes
– trampster
3 hours ago
no it is only used for comparing hashes
– trampster
3 hours ago
add a comment |
1 Answer
1
active
oldest
votes
Assuming neither of the hashes are secret and the hashes are secure (which SHA-256 is), there is no reason to check the hash in constant time. In fact, comparing hashes is one of the well-known alternatives to verifying passwords within a constant time routine. I can't say what reason the developers would give for doing this, but it is not technically necessary to make it constant time. Most likely, they were just being cautious. Non-constant time code in a cryptographic library makes auditors anxious.
More information about the theoretical weaknesses is discussed in an answer on the Cryptography site. It explains how, with a significant amount of queries, it can be possible to discover the first several bytes of the hash, which makes it possible to perform an offline computation to discard candidate passwords that obviously wouldn't match (their hash doesn't match the first few discovered bytes of the real hash) and avoid sending them to the password checking service, and why this is unlikely to be a real issue.
add a comment |
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1 Answer
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Assuming neither of the hashes are secret and the hashes are secure (which SHA-256 is), there is no reason to check the hash in constant time. In fact, comparing hashes is one of the well-known alternatives to verifying passwords within a constant time routine. I can't say what reason the developers would give for doing this, but it is not technically necessary to make it constant time. Most likely, they were just being cautious. Non-constant time code in a cryptographic library makes auditors anxious.
More information about the theoretical weaknesses is discussed in an answer on the Cryptography site. It explains how, with a significant amount of queries, it can be possible to discover the first several bytes of the hash, which makes it possible to perform an offline computation to discard candidate passwords that obviously wouldn't match (their hash doesn't match the first few discovered bytes of the real hash) and avoid sending them to the password checking service, and why this is unlikely to be a real issue.
add a comment |
Assuming neither of the hashes are secret and the hashes are secure (which SHA-256 is), there is no reason to check the hash in constant time. In fact, comparing hashes is one of the well-known alternatives to verifying passwords within a constant time routine. I can't say what reason the developers would give for doing this, but it is not technically necessary to make it constant time. Most likely, they were just being cautious. Non-constant time code in a cryptographic library makes auditors anxious.
More information about the theoretical weaknesses is discussed in an answer on the Cryptography site. It explains how, with a significant amount of queries, it can be possible to discover the first several bytes of the hash, which makes it possible to perform an offline computation to discard candidate passwords that obviously wouldn't match (their hash doesn't match the first few discovered bytes of the real hash) and avoid sending them to the password checking service, and why this is unlikely to be a real issue.
add a comment |
Assuming neither of the hashes are secret and the hashes are secure (which SHA-256 is), there is no reason to check the hash in constant time. In fact, comparing hashes is one of the well-known alternatives to verifying passwords within a constant time routine. I can't say what reason the developers would give for doing this, but it is not technically necessary to make it constant time. Most likely, they were just being cautious. Non-constant time code in a cryptographic library makes auditors anxious.
More information about the theoretical weaknesses is discussed in an answer on the Cryptography site. It explains how, with a significant amount of queries, it can be possible to discover the first several bytes of the hash, which makes it possible to perform an offline computation to discard candidate passwords that obviously wouldn't match (their hash doesn't match the first few discovered bytes of the real hash) and avoid sending them to the password checking service, and why this is unlikely to be a real issue.
Assuming neither of the hashes are secret and the hashes are secure (which SHA-256 is), there is no reason to check the hash in constant time. In fact, comparing hashes is one of the well-known alternatives to verifying passwords within a constant time routine. I can't say what reason the developers would give for doing this, but it is not technically necessary to make it constant time. Most likely, they were just being cautious. Non-constant time code in a cryptographic library makes auditors anxious.
More information about the theoretical weaknesses is discussed in an answer on the Cryptography site. It explains how, with a significant amount of queries, it can be possible to discover the first several bytes of the hash, which makes it possible to perform an offline computation to discard candidate passwords that obviously wouldn't match (their hash doesn't match the first few discovered bytes of the real hash) and avoid sending them to the password checking service, and why this is unlikely to be a real issue.
edited 3 hours ago
answered 3 hours ago
forestforest
41.2k18132148
41.2k18132148
add a comment |
add a comment |
trampster is a new contributor. Be nice, and check out our Code of Conduct.
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Is that function used for anything other than comparing hashes?
– forest
3 hours ago
no it is only used for comparing hashes
– trampster
3 hours ago