Gain of Non-Inverting Amplifier Does Not vary with Resistor ValuesMy simple audio amplifier circuit does not workNon-inverting amp GainHi-Fi Stereo Amplifier gain regulation with potentiometerNon-inverting and inverting gain of differential amplifierWhy not vary the opamp feedback resistor to change output levels?Output resistance of non-inverting amplifierProblems with setting op-amp amplifier gainPhotodiode non-inverting amplifier circuitNoisy non-inverting op amp with gain selectionactual formula for open loop gain in a non-inverting op-amp?

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Gain of Non-Inverting Amplifier Does Not vary with Resistor Values


My simple audio amplifier circuit does not workNon-inverting amp GainHi-Fi Stereo Amplifier gain regulation with potentiometerNon-inverting and inverting gain of differential amplifierWhy not vary the opamp feedback resistor to change output levels?Output resistance of non-inverting amplifierProblems with setting op-amp amplifier gainPhotodiode non-inverting amplifier circuitNoisy non-inverting op amp with gain selectionactual formula for open loop gain in a non-inverting op-amp?






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$begingroup$


I am trying to build a non-inverting amplifier using a LM7171 op amp, and I am implementing it with potentiometers as Rf and R2 so that I can smoothly control the gain of the amplifier (and easily check if its working correctly). I am applying +/- 15 V to the op amp. When I adjust the potentiometer's resistance the gain does not change as expected, or noticeably at all. Setup is shown below with traces when the resistances are Rf=Ri=540 Ohm and Rf=1.8 kOhm, Ri=540 Ohm, and as can be seen the gain/amplitude is the same for the different resistances used. The yellow output on the oscilloscope is the output of the amplifier, and the green is directly from a t-connector to the function generator's output.



I have used two different op amps and got the same behavior, so it is not broken, and all connections seem good. I measure the values of the potentiometer so am confident they are as described. Any ideas what might cause this? Thank you in advance for your help.



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share|improve this question









$endgroup$











  • $begingroup$
    You also have a large phase shift. Something odd going on. You have no DC path on the non-inverting input. That's going to cause the input capacitor to charge up or down until it hits one of the supply rails.
    $endgroup$
    – Transistor
    5 hours ago











  • $begingroup$
    The LM7171 has a very, very fast slew rate and 200 MHz at unity gain. I think your output is showing a gain of about 1.5 in the setup. This looks more to me about the breadboard's pF, which is getting well into the 1k zone with that frequency. Use dead-bug construction and see what happens.
    $endgroup$
    – jonk
    5 hours ago


















2












$begingroup$


I am trying to build a non-inverting amplifier using a LM7171 op amp, and I am implementing it with potentiometers as Rf and R2 so that I can smoothly control the gain of the amplifier (and easily check if its working correctly). I am applying +/- 15 V to the op amp. When I adjust the potentiometer's resistance the gain does not change as expected, or noticeably at all. Setup is shown below with traces when the resistances are Rf=Ri=540 Ohm and Rf=1.8 kOhm, Ri=540 Ohm, and as can be seen the gain/amplitude is the same for the different resistances used. The yellow output on the oscilloscope is the output of the amplifier, and the green is directly from a t-connector to the function generator's output.



I have used two different op amps and got the same behavior, so it is not broken, and all connections seem good. I measure the values of the potentiometer so am confident they are as described. Any ideas what might cause this? Thank you in advance for your help.



enter image description here



enter image description here



enter image description here



enter image description here



enter image description here










share|improve this question









$endgroup$











  • $begingroup$
    You also have a large phase shift. Something odd going on. You have no DC path on the non-inverting input. That's going to cause the input capacitor to charge up or down until it hits one of the supply rails.
    $endgroup$
    – Transistor
    5 hours ago











  • $begingroup$
    The LM7171 has a very, very fast slew rate and 200 MHz at unity gain. I think your output is showing a gain of about 1.5 in the setup. This looks more to me about the breadboard's pF, which is getting well into the 1k zone with that frequency. Use dead-bug construction and see what happens.
    $endgroup$
    – jonk
    5 hours ago














2












2








2





$begingroup$


I am trying to build a non-inverting amplifier using a LM7171 op amp, and I am implementing it with potentiometers as Rf and R2 so that I can smoothly control the gain of the amplifier (and easily check if its working correctly). I am applying +/- 15 V to the op amp. When I adjust the potentiometer's resistance the gain does not change as expected, or noticeably at all. Setup is shown below with traces when the resistances are Rf=Ri=540 Ohm and Rf=1.8 kOhm, Ri=540 Ohm, and as can be seen the gain/amplitude is the same for the different resistances used. The yellow output on the oscilloscope is the output of the amplifier, and the green is directly from a t-connector to the function generator's output.



I have used two different op amps and got the same behavior, so it is not broken, and all connections seem good. I measure the values of the potentiometer so am confident they are as described. Any ideas what might cause this? Thank you in advance for your help.



enter image description here



enter image description here



enter image description here



enter image description here



enter image description here










share|improve this question









$endgroup$




I am trying to build a non-inverting amplifier using a LM7171 op amp, and I am implementing it with potentiometers as Rf and R2 so that I can smoothly control the gain of the amplifier (and easily check if its working correctly). I am applying +/- 15 V to the op amp. When I adjust the potentiometer's resistance the gain does not change as expected, or noticeably at all. Setup is shown below with traces when the resistances are Rf=Ri=540 Ohm and Rf=1.8 kOhm, Ri=540 Ohm, and as can be seen the gain/amplitude is the same for the different resistances used. The yellow output on the oscilloscope is the output of the amplifier, and the green is directly from a t-connector to the function generator's output.



I have used two different op amps and got the same behavior, so it is not broken, and all connections seem good. I measure the values of the potentiometer so am confident they are as described. Any ideas what might cause this? Thank you in advance for your help.



enter image description here



enter image description here



enter image description here



enter image description here



enter image description here







operational-amplifier amplifier potentiometer gain non-inverting






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 5 hours ago









wondersmwondersm

113




113











  • $begingroup$
    You also have a large phase shift. Something odd going on. You have no DC path on the non-inverting input. That's going to cause the input capacitor to charge up or down until it hits one of the supply rails.
    $endgroup$
    – Transistor
    5 hours ago











  • $begingroup$
    The LM7171 has a very, very fast slew rate and 200 MHz at unity gain. I think your output is showing a gain of about 1.5 in the setup. This looks more to me about the breadboard's pF, which is getting well into the 1k zone with that frequency. Use dead-bug construction and see what happens.
    $endgroup$
    – jonk
    5 hours ago

















  • $begingroup$
    You also have a large phase shift. Something odd going on. You have no DC path on the non-inverting input. That's going to cause the input capacitor to charge up or down until it hits one of the supply rails.
    $endgroup$
    – Transistor
    5 hours ago











  • $begingroup$
    The LM7171 has a very, very fast slew rate and 200 MHz at unity gain. I think your output is showing a gain of about 1.5 in the setup. This looks more to me about the breadboard's pF, which is getting well into the 1k zone with that frequency. Use dead-bug construction and see what happens.
    $endgroup$
    – jonk
    5 hours ago
















$begingroup$
You also have a large phase shift. Something odd going on. You have no DC path on the non-inverting input. That's going to cause the input capacitor to charge up or down until it hits one of the supply rails.
$endgroup$
– Transistor
5 hours ago





$begingroup$
You also have a large phase shift. Something odd going on. You have no DC path on the non-inverting input. That's going to cause the input capacitor to charge up or down until it hits one of the supply rails.
$endgroup$
– Transistor
5 hours ago













$begingroup$
The LM7171 has a very, very fast slew rate and 200 MHz at unity gain. I think your output is showing a gain of about 1.5 in the setup. This looks more to me about the breadboard's pF, which is getting well into the 1k zone with that frequency. Use dead-bug construction and see what happens.
$endgroup$
– jonk
5 hours ago





$begingroup$
The LM7171 has a very, very fast slew rate and 200 MHz at unity gain. I think your output is showing a gain of about 1.5 in the setup. This looks more to me about the breadboard's pF, which is getting well into the 1k zone with that frequency. Use dead-bug construction and see what happens.
$endgroup$
– jonk
5 hours ago











2 Answers
2






active

oldest

votes


















3












$begingroup$

The phase shift is the give-away. You are bandwidth limited. You need a faster op-amp, or a lower frequency.






share|improve this answer









$endgroup$












  • $begingroup$
    Yup, 18.88 MHz. I hadn't spotted that.
    $endgroup$
    – Transistor
    5 hours ago


















0












$begingroup$

I cannot add as a comment, my reputation is too low, but Transistor makes a good point, the +input of the opamp will drift up close to negative rail due to input bias current - connect a large ohm resistor from this pin to 0V.



Constructing high frequency circuits on breadboard is likely to be problematic, with multiple stray capacitances. If you have a signal generator, test again at a low frequency.



Also add some decoupling capacitors, see 8.1 of the TI datasheet.






share|improve this answer










New contributor



Innovodesign is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





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    2 Answers
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    2 Answers
    2






    active

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    active

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    active

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    3












    $begingroup$

    The phase shift is the give-away. You are bandwidth limited. You need a faster op-amp, or a lower frequency.






    share|improve this answer









    $endgroup$












    • $begingroup$
      Yup, 18.88 MHz. I hadn't spotted that.
      $endgroup$
      – Transistor
      5 hours ago















    3












    $begingroup$

    The phase shift is the give-away. You are bandwidth limited. You need a faster op-amp, or a lower frequency.






    share|improve this answer









    $endgroup$












    • $begingroup$
      Yup, 18.88 MHz. I hadn't spotted that.
      $endgroup$
      – Transistor
      5 hours ago













    3












    3








    3





    $begingroup$

    The phase shift is the give-away. You are bandwidth limited. You need a faster op-amp, or a lower frequency.






    share|improve this answer









    $endgroup$



    The phase shift is the give-away. You are bandwidth limited. You need a faster op-amp, or a lower frequency.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 5 hours ago









    Mattman944Mattman944

    55317




    55317











    • $begingroup$
      Yup, 18.88 MHz. I hadn't spotted that.
      $endgroup$
      – Transistor
      5 hours ago
















    • $begingroup$
      Yup, 18.88 MHz. I hadn't spotted that.
      $endgroup$
      – Transistor
      5 hours ago















    $begingroup$
    Yup, 18.88 MHz. I hadn't spotted that.
    $endgroup$
    – Transistor
    5 hours ago




    $begingroup$
    Yup, 18.88 MHz. I hadn't spotted that.
    $endgroup$
    – Transistor
    5 hours ago













    0












    $begingroup$

    I cannot add as a comment, my reputation is too low, but Transistor makes a good point, the +input of the opamp will drift up close to negative rail due to input bias current - connect a large ohm resistor from this pin to 0V.



    Constructing high frequency circuits on breadboard is likely to be problematic, with multiple stray capacitances. If you have a signal generator, test again at a low frequency.



    Also add some decoupling capacitors, see 8.1 of the TI datasheet.






    share|improve this answer










    New contributor



    Innovodesign is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





    $endgroup$

















      0












      $begingroup$

      I cannot add as a comment, my reputation is too low, but Transistor makes a good point, the +input of the opamp will drift up close to negative rail due to input bias current - connect a large ohm resistor from this pin to 0V.



      Constructing high frequency circuits on breadboard is likely to be problematic, with multiple stray capacitances. If you have a signal generator, test again at a low frequency.



      Also add some decoupling capacitors, see 8.1 of the TI datasheet.






      share|improve this answer










      New contributor



      Innovodesign is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      $endgroup$















        0












        0








        0





        $begingroup$

        I cannot add as a comment, my reputation is too low, but Transistor makes a good point, the +input of the opamp will drift up close to negative rail due to input bias current - connect a large ohm resistor from this pin to 0V.



        Constructing high frequency circuits on breadboard is likely to be problematic, with multiple stray capacitances. If you have a signal generator, test again at a low frequency.



        Also add some decoupling capacitors, see 8.1 of the TI datasheet.






        share|improve this answer










        New contributor



        Innovodesign is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





        $endgroup$



        I cannot add as a comment, my reputation is too low, but Transistor makes a good point, the +input of the opamp will drift up close to negative rail due to input bias current - connect a large ohm resistor from this pin to 0V.



        Constructing high frequency circuits on breadboard is likely to be problematic, with multiple stray capacitances. If you have a signal generator, test again at a low frequency.



        Also add some decoupling capacitors, see 8.1 of the TI datasheet.







        share|improve this answer










        New contributor



        Innovodesign is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.








        share|improve this answer



        share|improve this answer








        edited 3 hours ago





















        New contributor



        Innovodesign is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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        answered 4 hours ago









        InnovodesignInnovodesign

        464




        464




        New contributor



        Innovodesign is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.




        New contributor




        Innovodesign is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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