Output the date in the Mel calendarValiDate ISO 8601 by RXResolving the Date Format DisputeRollover CalendarForgotten Realms date calculatorRoman-style date formattingFriday the 13thBeat Pure Regular Expressions at Validating ISO 8601 DatesThe Last MondayWhat's the Date?Date Occurrences

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Output the date in the Mel calendar


ValiDate ISO 8601 by RXResolving the Date Format DisputeRollover CalendarForgotten Realms date calculatorRoman-style date formattingFriday the 13thBeat Pure Regular Expressions at Validating ISO 8601 DatesThe Last MondayWhat's the Date?Date Occurrences













3












$begingroup$


The Mel calendar is used in the fictional world of Kaldia. Your goal is to convert dates into the Mel calendar.



This calendar has 13 months of 28 days each, plus 1 or 2 extra days after the last month. A year that is divisible by 4 but not by 100, or divisible by 400 has 366 days, and other years have 365 (i.e. our leap year rules, but with years in the Mel calendar).



You should use the month and day name abbreviations:



months: dia vio lis gil ful dyu mel ral zan pal mik fav ruj



days: dia vio lis gil ful dyu mel ral zan pal mik fav ruj ser rav tan lin rez jil din ket len lax nen pin mat kun mir



The extra days outside of any month have the month name of myuxet (no abbreviation here), and the day names are axet and teems, respectively.



0 dia dia is 1988/11/30.



You can take the input date as a string or a (year, month, day) tuple; alternatively, for functions, the parameter can be in your standard library's date type. The output should be a space-separated string.



Test cases



1776-07-04 => -213 ral ket
1859-12-15 => -129 dia rav
1917-04-14 => -72 ful nen
1981-02-04 => -8 lis mik
1988-11-30 => 0 dia dia
1988-12-01 => 0 dia vio
1988-12-28 => 0 vio dia
2017-01-01 => 28 vio ful
2019-04-22 => 30 dyu lis
2019-11-30 => 30 myuxet axet
2019-12-01 => 31 dia dia
2021-11-29 => 32 myuxet axet
2021-11-30 => 32 myuxet teems
2089-11-30 => 101 dia dia
2389-11-30 => 400 myuxet teems


Reference implementation in Perl 6



Standard loopholes are forbidden.










share|improve this question











$endgroup$







  • 3




    $begingroup$
    You should probably include in your post that axet and teems are at the end of the year, I was confused until I looked at the link
    $endgroup$
    – Embodiment of Ignorance
    47 mins ago










  • $begingroup$
    It has to be a space-separated string.
    $endgroup$
    – bb94
    14 mins ago










  • $begingroup$
    Can we take input as a three value named tuple or a list of three values each signifying year, month, and day?
    $endgroup$
    – Embodiment of Ignorance
    10 mins ago










  • $begingroup$
    Yes, that's fine.
    $endgroup$
    – bb94
    9 mins ago















3












$begingroup$


The Mel calendar is used in the fictional world of Kaldia. Your goal is to convert dates into the Mel calendar.



This calendar has 13 months of 28 days each, plus 1 or 2 extra days after the last month. A year that is divisible by 4 but not by 100, or divisible by 400 has 366 days, and other years have 365 (i.e. our leap year rules, but with years in the Mel calendar).



You should use the month and day name abbreviations:



months: dia vio lis gil ful dyu mel ral zan pal mik fav ruj



days: dia vio lis gil ful dyu mel ral zan pal mik fav ruj ser rav tan lin rez jil din ket len lax nen pin mat kun mir



The extra days outside of any month have the month name of myuxet (no abbreviation here), and the day names are axet and teems, respectively.



0 dia dia is 1988/11/30.



You can take the input date as a string or a (year, month, day) tuple; alternatively, for functions, the parameter can be in your standard library's date type. The output should be a space-separated string.



Test cases



1776-07-04 => -213 ral ket
1859-12-15 => -129 dia rav
1917-04-14 => -72 ful nen
1981-02-04 => -8 lis mik
1988-11-30 => 0 dia dia
1988-12-01 => 0 dia vio
1988-12-28 => 0 vio dia
2017-01-01 => 28 vio ful
2019-04-22 => 30 dyu lis
2019-11-30 => 30 myuxet axet
2019-12-01 => 31 dia dia
2021-11-29 => 32 myuxet axet
2021-11-30 => 32 myuxet teems
2089-11-30 => 101 dia dia
2389-11-30 => 400 myuxet teems


Reference implementation in Perl 6



Standard loopholes are forbidden.










share|improve this question











$endgroup$







  • 3




    $begingroup$
    You should probably include in your post that axet and teems are at the end of the year, I was confused until I looked at the link
    $endgroup$
    – Embodiment of Ignorance
    47 mins ago










  • $begingroup$
    It has to be a space-separated string.
    $endgroup$
    – bb94
    14 mins ago










  • $begingroup$
    Can we take input as a three value named tuple or a list of three values each signifying year, month, and day?
    $endgroup$
    – Embodiment of Ignorance
    10 mins ago










  • $begingroup$
    Yes, that's fine.
    $endgroup$
    – bb94
    9 mins ago













3












3








3





$begingroup$


The Mel calendar is used in the fictional world of Kaldia. Your goal is to convert dates into the Mel calendar.



This calendar has 13 months of 28 days each, plus 1 or 2 extra days after the last month. A year that is divisible by 4 but not by 100, or divisible by 400 has 366 days, and other years have 365 (i.e. our leap year rules, but with years in the Mel calendar).



You should use the month and day name abbreviations:



months: dia vio lis gil ful dyu mel ral zan pal mik fav ruj



days: dia vio lis gil ful dyu mel ral zan pal mik fav ruj ser rav tan lin rez jil din ket len lax nen pin mat kun mir



The extra days outside of any month have the month name of myuxet (no abbreviation here), and the day names are axet and teems, respectively.



0 dia dia is 1988/11/30.



You can take the input date as a string or a (year, month, day) tuple; alternatively, for functions, the parameter can be in your standard library's date type. The output should be a space-separated string.



Test cases



1776-07-04 => -213 ral ket
1859-12-15 => -129 dia rav
1917-04-14 => -72 ful nen
1981-02-04 => -8 lis mik
1988-11-30 => 0 dia dia
1988-12-01 => 0 dia vio
1988-12-28 => 0 vio dia
2017-01-01 => 28 vio ful
2019-04-22 => 30 dyu lis
2019-11-30 => 30 myuxet axet
2019-12-01 => 31 dia dia
2021-11-29 => 32 myuxet axet
2021-11-30 => 32 myuxet teems
2089-11-30 => 101 dia dia
2389-11-30 => 400 myuxet teems


Reference implementation in Perl 6



Standard loopholes are forbidden.










share|improve this question











$endgroup$




The Mel calendar is used in the fictional world of Kaldia. Your goal is to convert dates into the Mel calendar.



This calendar has 13 months of 28 days each, plus 1 or 2 extra days after the last month. A year that is divisible by 4 but not by 100, or divisible by 400 has 366 days, and other years have 365 (i.e. our leap year rules, but with years in the Mel calendar).



You should use the month and day name abbreviations:



months: dia vio lis gil ful dyu mel ral zan pal mik fav ruj



days: dia vio lis gil ful dyu mel ral zan pal mik fav ruj ser rav tan lin rez jil din ket len lax nen pin mat kun mir



The extra days outside of any month have the month name of myuxet (no abbreviation here), and the day names are axet and teems, respectively.



0 dia dia is 1988/11/30.



You can take the input date as a string or a (year, month, day) tuple; alternatively, for functions, the parameter can be in your standard library's date type. The output should be a space-separated string.



Test cases



1776-07-04 => -213 ral ket
1859-12-15 => -129 dia rav
1917-04-14 => -72 ful nen
1981-02-04 => -8 lis mik
1988-11-30 => 0 dia dia
1988-12-01 => 0 dia vio
1988-12-28 => 0 vio dia
2017-01-01 => 28 vio ful
2019-04-22 => 30 dyu lis
2019-11-30 => 30 myuxet axet
2019-12-01 => 31 dia dia
2021-11-29 => 32 myuxet axet
2021-11-30 => 32 myuxet teems
2089-11-30 => 101 dia dia
2389-11-30 => 400 myuxet teems


Reference implementation in Perl 6



Standard loopholes are forbidden.







code-golf date






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 8 mins ago







bb94

















asked 2 hours ago









bb94bb94

1,307714




1,307714







  • 3




    $begingroup$
    You should probably include in your post that axet and teems are at the end of the year, I was confused until I looked at the link
    $endgroup$
    – Embodiment of Ignorance
    47 mins ago










  • $begingroup$
    It has to be a space-separated string.
    $endgroup$
    – bb94
    14 mins ago










  • $begingroup$
    Can we take input as a three value named tuple or a list of three values each signifying year, month, and day?
    $endgroup$
    – Embodiment of Ignorance
    10 mins ago










  • $begingroup$
    Yes, that's fine.
    $endgroup$
    – bb94
    9 mins ago












  • 3




    $begingroup$
    You should probably include in your post that axet and teems are at the end of the year, I was confused until I looked at the link
    $endgroup$
    – Embodiment of Ignorance
    47 mins ago










  • $begingroup$
    It has to be a space-separated string.
    $endgroup$
    – bb94
    14 mins ago










  • $begingroup$
    Can we take input as a three value named tuple or a list of three values each signifying year, month, and day?
    $endgroup$
    – Embodiment of Ignorance
    10 mins ago










  • $begingroup$
    Yes, that's fine.
    $endgroup$
    – bb94
    9 mins ago







3




3




$begingroup$
You should probably include in your post that axet and teems are at the end of the year, I was confused until I looked at the link
$endgroup$
– Embodiment of Ignorance
47 mins ago




$begingroup$
You should probably include in your post that axet and teems are at the end of the year, I was confused until I looked at the link
$endgroup$
– Embodiment of Ignorance
47 mins ago












$begingroup$
It has to be a space-separated string.
$endgroup$
– bb94
14 mins ago




$begingroup$
It has to be a space-separated string.
$endgroup$
– bb94
14 mins ago












$begingroup$
Can we take input as a three value named tuple or a list of three values each signifying year, month, and day?
$endgroup$
– Embodiment of Ignorance
10 mins ago




$begingroup$
Can we take input as a three value named tuple or a list of three values each signifying year, month, and day?
$endgroup$
– Embodiment of Ignorance
10 mins ago












$begingroup$
Yes, that's fine.
$endgroup$
– bb94
9 mins ago




$begingroup$
Yes, that's fine.
$endgroup$
– bb94
9 mins ago










2 Answers
2






active

oldest

votes


















1












$begingroup$


Ruby, 199 bytes



Oof, only 23 bytes saved over the sample Perl code... I blame the fact that I have to subtract a bigger number due to using a Time class instead of what I assume is a Date class in Perl. (AFAIK importing Ruby's Date class is 2 bytes longer)





->dd-=62764070400;y=d.yday;m=y/28;s="diaviolisgilfuldyumelralzanpalmikfavrujserravtanlinrezjildinketlenlaxnenpinmatkunmir".scan /.../;[d.year,m<13?s[m]:"myuxet",(m<13?s:%w[axet teems])[y%28-1]]*' '


Try it online!






share|improve this answer









$endgroup$




















    1












    $begingroup$


    Perl 6, 174 bytes





    [X]("diaviolisgilfuldyumelralzanpalmikfavrujserravtanlinrezjildinketlenlaxnenpinmatkunmir".comb(3)xx 2)[^364],o*-726436


    Try it online!



    Generate a list of all the valid dates and then indexes the day of the year into that list.






    share|improve this answer











    $endgroup$













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      2 Answers
      2






      active

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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1












      $begingroup$


      Ruby, 199 bytes



      Oof, only 23 bytes saved over the sample Perl code... I blame the fact that I have to subtract a bigger number due to using a Time class instead of what I assume is a Date class in Perl. (AFAIK importing Ruby's Date class is 2 bytes longer)





      ->dd-=62764070400;y=d.yday;m=y/28;s="diaviolisgilfuldyumelralzanpalmikfavrujserravtanlinrezjildinketlenlaxnenpinmatkunmir".scan /.../;[d.year,m<13?s[m]:"myuxet",(m<13?s:%w[axet teems])[y%28-1]]*' '


      Try it online!






      share|improve this answer









      $endgroup$

















        1












        $begingroup$


        Ruby, 199 bytes



        Oof, only 23 bytes saved over the sample Perl code... I blame the fact that I have to subtract a bigger number due to using a Time class instead of what I assume is a Date class in Perl. (AFAIK importing Ruby's Date class is 2 bytes longer)





        ->dd-=62764070400;y=d.yday;m=y/28;s="diaviolisgilfuldyumelralzanpalmikfavrujserravtanlinrezjildinketlenlaxnenpinmatkunmir".scan /.../;[d.year,m<13?s[m]:"myuxet",(m<13?s:%w[axet teems])[y%28-1]]*' '


        Try it online!






        share|improve this answer









        $endgroup$















          1












          1








          1





          $begingroup$


          Ruby, 199 bytes



          Oof, only 23 bytes saved over the sample Perl code... I blame the fact that I have to subtract a bigger number due to using a Time class instead of what I assume is a Date class in Perl. (AFAIK importing Ruby's Date class is 2 bytes longer)





          ->dd-=62764070400;y=d.yday;m=y/28;s="diaviolisgilfuldyumelralzanpalmikfavrujserravtanlinrezjildinketlenlaxnenpinmatkunmir".scan /.../;[d.year,m<13?s[m]:"myuxet",(m<13?s:%w[axet teems])[y%28-1]]*' '


          Try it online!






          share|improve this answer









          $endgroup$




          Ruby, 199 bytes



          Oof, only 23 bytes saved over the sample Perl code... I blame the fact that I have to subtract a bigger number due to using a Time class instead of what I assume is a Date class in Perl. (AFAIK importing Ruby's Date class is 2 bytes longer)





          ->dd-=62764070400;y=d.yday;m=y/28;s="diaviolisgilfuldyumelralzanpalmikfavrujserravtanlinrezjildinketlenlaxnenpinmatkunmir".scan /.../;[d.year,m<13?s[m]:"myuxet",(m<13?s:%w[axet teems])[y%28-1]]*' '


          Try it online!







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 57 mins ago









          Value InkValue Ink

          7,895731




          7,895731





















              1












              $begingroup$


              Perl 6, 174 bytes





              [X]("diaviolisgilfuldyumelralzanpalmikfavrujserravtanlinrezjildinketlenlaxnenpinmatkunmir".comb(3)xx 2)[^364],o*-726436


              Try it online!



              Generate a list of all the valid dates and then indexes the day of the year into that list.






              share|improve this answer











              $endgroup$

















                1












                $begingroup$


                Perl 6, 174 bytes





                [X]("diaviolisgilfuldyumelralzanpalmikfavrujserravtanlinrezjildinketlenlaxnenpinmatkunmir".comb(3)xx 2)[^364],o*-726436


                Try it online!



                Generate a list of all the valid dates and then indexes the day of the year into that list.






                share|improve this answer











                $endgroup$















                  1












                  1








                  1





                  $begingroup$


                  Perl 6, 174 bytes





                  [X]("diaviolisgilfuldyumelralzanpalmikfavrujserravtanlinrezjildinketlenlaxnenpinmatkunmir".comb(3)xx 2)[^364],o*-726436


                  Try it online!



                  Generate a list of all the valid dates and then indexes the day of the year into that list.






                  share|improve this answer











                  $endgroup$




                  Perl 6, 174 bytes





                  [X]("diaviolisgilfuldyumelralzanpalmikfavrujserravtanlinrezjildinketlenlaxnenpinmatkunmir".comb(3)xx 2)[^364],o*-726436


                  Try it online!



                  Generate a list of all the valid dates and then indexes the day of the year into that list.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 13 mins ago

























                  answered 21 mins ago









                  Jo KingJo King

                  28k366134




                  28k366134



























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