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Geometric inspiration behind Hal(irutan)'s Wolf(ram Language Logo)


Distribution of random points in 3D space to simulate the Crab Nebula













3












$begingroup$


Our good friend hal made a logo for WL as part of a Community Ad:



wl



The logo itself is much nicer than the bland Wolfram wolf, of course, but one has to wonder: what's the geometrical inspiration behind it and how could I make it in Mathematica?










share|improve this question











$endgroup$
















    3












    $begingroup$


    Our good friend hal made a logo for WL as part of a Community Ad:



    wl



    The logo itself is much nicer than the bland Wolfram wolf, of course, but one has to wonder: what's the geometrical inspiration behind it and how could I make it in Mathematica?










    share|improve this question











    $endgroup$














      3












      3








      3





      $begingroup$


      Our good friend hal made a logo for WL as part of a Community Ad:



      wl



      The logo itself is much nicer than the bland Wolfram wolf, of course, but one has to wonder: what's the geometrical inspiration behind it and how could I make it in Mathematica?










      share|improve this question











      $endgroup$




      Our good friend hal made a logo for WL as part of a Community Ad:



      wl



      The logo itself is much nicer than the bland Wolfram wolf, of course, but one has to wonder: what's the geometrical inspiration behind it and how could I make it in Mathematica?







      generative-art






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 1 hour ago







      b3m2a1

















      asked 7 hours ago









      b3m2a1b3m2a1

      29.5k360173




      29.5k360173




















          1 Answer
          1






          active

          oldest

          votes


















          7












          $begingroup$

          The logo is indeed constructed geometrically from simple rules, but let me go a bit into detail. It took quite some time with pen and paper to figure out exactly what I wanted. I traced some pictures of real wolves and looking at these pictures, it became quite clear that their ears, cheekbones and nose are prominent features. Eyes are important too, but I want to use the logo for file-icons and therefore, it needs to be rather simple to make it look good in a 16x16 resolution.



          After realizing that a detailed wolf won't work, I concentrated on the basics and after some hours, I had an idea to base everything on a circle with equally distributed points. My idea was to construct everything with lines going through these points. After many sketches, I came up with this (of course on paper):



          Mathematica graphics



          Each of the corner points is either a point on the circle or an intersecting point of lines going through points on the circle. In grey, you see the underlying helping lines. The good thing is, that we need only 3 basic ingredients:



          • the points on the circle

          • a way to form a line equation

          • functions for calculating the intersection between two lines

          This can be given in Mathematica code as



          dphi = 2 Pi/24;
          p = Table[Cos[phi], Sin[phi], phi, -Pi/2, Pi/2, dphi];

          reflectY[x_, y_] := -x, y;
          line[x1_, y1_, x2_, y2_] := (y2 - [FormalY])*(x2 - x1) - (y2 - y1)*(x2 - [FormalX]);
          point[l1_, l2_] := [FormalX], [FormalY] /.
          First@Solve[l1 == 0, l2 == 0, [FormalX], [FormalY]];


          After this, I only translated what I had on paper



          poly1 = 
          p[[9]],
          point[line[p[[4]], p[[9]]], line[p[[-1]], reflectY[p[[10]]]]],
          p[[-1]],
          point[line[p[[-1]], p[[5]]], line[reflectY[p[[5]]], p[[9]]]]
          ;
          poly2 =
          point[line[p[[1]], p[[9]]], line[reflectY[p[[2]]], p[[7]]]],
          point[line[reflectY[p[[2]]], p[[7]]], line[p[[10]], p[[9]]]],
          p[[9]]
          ;
          poly3 =
          p[[2]], 0, 0, reflectY[p[[2]]], point[line[p[[2]], p[[4]]],
          line[reflectY@p[[2]], reflectY@p[[4]]]]
          ;


          These are the 3 polygons you see above and to get the full logo, we need to reflect top two polygons. However, this is basically all we need



          Graphics[

          RGBColor[0.780392, 0.329412, 0.313725],
          Polygon /@ poly1, poly2, reflectY /@ poly1, reflectY /@ poly2,
          poly3
          ,
          AspectRatio -> Automatic
          ]


          Mathematica graphics



          And that's about it. Put a nice circle around it and start up Blender and you can easily create this



          enter image description here






          share|improve this answer









          $endgroup$













            Your Answer








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            1 Answer
            1






            active

            oldest

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            active

            oldest

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            active

            oldest

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            7












            $begingroup$

            The logo is indeed constructed geometrically from simple rules, but let me go a bit into detail. It took quite some time with pen and paper to figure out exactly what I wanted. I traced some pictures of real wolves and looking at these pictures, it became quite clear that their ears, cheekbones and nose are prominent features. Eyes are important too, but I want to use the logo for file-icons and therefore, it needs to be rather simple to make it look good in a 16x16 resolution.



            After realizing that a detailed wolf won't work, I concentrated on the basics and after some hours, I had an idea to base everything on a circle with equally distributed points. My idea was to construct everything with lines going through these points. After many sketches, I came up with this (of course on paper):



            Mathematica graphics



            Each of the corner points is either a point on the circle or an intersecting point of lines going through points on the circle. In grey, you see the underlying helping lines. The good thing is, that we need only 3 basic ingredients:



            • the points on the circle

            • a way to form a line equation

            • functions for calculating the intersection between two lines

            This can be given in Mathematica code as



            dphi = 2 Pi/24;
            p = Table[Cos[phi], Sin[phi], phi, -Pi/2, Pi/2, dphi];

            reflectY[x_, y_] := -x, y;
            line[x1_, y1_, x2_, y2_] := (y2 - [FormalY])*(x2 - x1) - (y2 - y1)*(x2 - [FormalX]);
            point[l1_, l2_] := [FormalX], [FormalY] /.
            First@Solve[l1 == 0, l2 == 0, [FormalX], [FormalY]];


            After this, I only translated what I had on paper



            poly1 = 
            p[[9]],
            point[line[p[[4]], p[[9]]], line[p[[-1]], reflectY[p[[10]]]]],
            p[[-1]],
            point[line[p[[-1]], p[[5]]], line[reflectY[p[[5]]], p[[9]]]]
            ;
            poly2 =
            point[line[p[[1]], p[[9]]], line[reflectY[p[[2]]], p[[7]]]],
            point[line[reflectY[p[[2]]], p[[7]]], line[p[[10]], p[[9]]]],
            p[[9]]
            ;
            poly3 =
            p[[2]], 0, 0, reflectY[p[[2]]], point[line[p[[2]], p[[4]]],
            line[reflectY@p[[2]], reflectY@p[[4]]]]
            ;


            These are the 3 polygons you see above and to get the full logo, we need to reflect top two polygons. However, this is basically all we need



            Graphics[

            RGBColor[0.780392, 0.329412, 0.313725],
            Polygon /@ poly1, poly2, reflectY /@ poly1, reflectY /@ poly2,
            poly3
            ,
            AspectRatio -> Automatic
            ]


            Mathematica graphics



            And that's about it. Put a nice circle around it and start up Blender and you can easily create this



            enter image description here






            share|improve this answer









            $endgroup$

















              7












              $begingroup$

              The logo is indeed constructed geometrically from simple rules, but let me go a bit into detail. It took quite some time with pen and paper to figure out exactly what I wanted. I traced some pictures of real wolves and looking at these pictures, it became quite clear that their ears, cheekbones and nose are prominent features. Eyes are important too, but I want to use the logo for file-icons and therefore, it needs to be rather simple to make it look good in a 16x16 resolution.



              After realizing that a detailed wolf won't work, I concentrated on the basics and after some hours, I had an idea to base everything on a circle with equally distributed points. My idea was to construct everything with lines going through these points. After many sketches, I came up with this (of course on paper):



              Mathematica graphics



              Each of the corner points is either a point on the circle or an intersecting point of lines going through points on the circle. In grey, you see the underlying helping lines. The good thing is, that we need only 3 basic ingredients:



              • the points on the circle

              • a way to form a line equation

              • functions for calculating the intersection between two lines

              This can be given in Mathematica code as



              dphi = 2 Pi/24;
              p = Table[Cos[phi], Sin[phi], phi, -Pi/2, Pi/2, dphi];

              reflectY[x_, y_] := -x, y;
              line[x1_, y1_, x2_, y2_] := (y2 - [FormalY])*(x2 - x1) - (y2 - y1)*(x2 - [FormalX]);
              point[l1_, l2_] := [FormalX], [FormalY] /.
              First@Solve[l1 == 0, l2 == 0, [FormalX], [FormalY]];


              After this, I only translated what I had on paper



              poly1 = 
              p[[9]],
              point[line[p[[4]], p[[9]]], line[p[[-1]], reflectY[p[[10]]]]],
              p[[-1]],
              point[line[p[[-1]], p[[5]]], line[reflectY[p[[5]]], p[[9]]]]
              ;
              poly2 =
              point[line[p[[1]], p[[9]]], line[reflectY[p[[2]]], p[[7]]]],
              point[line[reflectY[p[[2]]], p[[7]]], line[p[[10]], p[[9]]]],
              p[[9]]
              ;
              poly3 =
              p[[2]], 0, 0, reflectY[p[[2]]], point[line[p[[2]], p[[4]]],
              line[reflectY@p[[2]], reflectY@p[[4]]]]
              ;


              These are the 3 polygons you see above and to get the full logo, we need to reflect top two polygons. However, this is basically all we need



              Graphics[

              RGBColor[0.780392, 0.329412, 0.313725],
              Polygon /@ poly1, poly2, reflectY /@ poly1, reflectY /@ poly2,
              poly3
              ,
              AspectRatio -> Automatic
              ]


              Mathematica graphics



              And that's about it. Put a nice circle around it and start up Blender and you can easily create this



              enter image description here






              share|improve this answer









              $endgroup$















                7












                7








                7





                $begingroup$

                The logo is indeed constructed geometrically from simple rules, but let me go a bit into detail. It took quite some time with pen and paper to figure out exactly what I wanted. I traced some pictures of real wolves and looking at these pictures, it became quite clear that their ears, cheekbones and nose are prominent features. Eyes are important too, but I want to use the logo for file-icons and therefore, it needs to be rather simple to make it look good in a 16x16 resolution.



                After realizing that a detailed wolf won't work, I concentrated on the basics and after some hours, I had an idea to base everything on a circle with equally distributed points. My idea was to construct everything with lines going through these points. After many sketches, I came up with this (of course on paper):



                Mathematica graphics



                Each of the corner points is either a point on the circle or an intersecting point of lines going through points on the circle. In grey, you see the underlying helping lines. The good thing is, that we need only 3 basic ingredients:



                • the points on the circle

                • a way to form a line equation

                • functions for calculating the intersection between two lines

                This can be given in Mathematica code as



                dphi = 2 Pi/24;
                p = Table[Cos[phi], Sin[phi], phi, -Pi/2, Pi/2, dphi];

                reflectY[x_, y_] := -x, y;
                line[x1_, y1_, x2_, y2_] := (y2 - [FormalY])*(x2 - x1) - (y2 - y1)*(x2 - [FormalX]);
                point[l1_, l2_] := [FormalX], [FormalY] /.
                First@Solve[l1 == 0, l2 == 0, [FormalX], [FormalY]];


                After this, I only translated what I had on paper



                poly1 = 
                p[[9]],
                point[line[p[[4]], p[[9]]], line[p[[-1]], reflectY[p[[10]]]]],
                p[[-1]],
                point[line[p[[-1]], p[[5]]], line[reflectY[p[[5]]], p[[9]]]]
                ;
                poly2 =
                point[line[p[[1]], p[[9]]], line[reflectY[p[[2]]], p[[7]]]],
                point[line[reflectY[p[[2]]], p[[7]]], line[p[[10]], p[[9]]]],
                p[[9]]
                ;
                poly3 =
                p[[2]], 0, 0, reflectY[p[[2]]], point[line[p[[2]], p[[4]]],
                line[reflectY@p[[2]], reflectY@p[[4]]]]
                ;


                These are the 3 polygons you see above and to get the full logo, we need to reflect top two polygons. However, this is basically all we need



                Graphics[

                RGBColor[0.780392, 0.329412, 0.313725],
                Polygon /@ poly1, poly2, reflectY /@ poly1, reflectY /@ poly2,
                poly3
                ,
                AspectRatio -> Automatic
                ]


                Mathematica graphics



                And that's about it. Put a nice circle around it and start up Blender and you can easily create this



                enter image description here






                share|improve this answer









                $endgroup$



                The logo is indeed constructed geometrically from simple rules, but let me go a bit into detail. It took quite some time with pen and paper to figure out exactly what I wanted. I traced some pictures of real wolves and looking at these pictures, it became quite clear that their ears, cheekbones and nose are prominent features. Eyes are important too, but I want to use the logo for file-icons and therefore, it needs to be rather simple to make it look good in a 16x16 resolution.



                After realizing that a detailed wolf won't work, I concentrated on the basics and after some hours, I had an idea to base everything on a circle with equally distributed points. My idea was to construct everything with lines going through these points. After many sketches, I came up with this (of course on paper):



                Mathematica graphics



                Each of the corner points is either a point on the circle or an intersecting point of lines going through points on the circle. In grey, you see the underlying helping lines. The good thing is, that we need only 3 basic ingredients:



                • the points on the circle

                • a way to form a line equation

                • functions for calculating the intersection between two lines

                This can be given in Mathematica code as



                dphi = 2 Pi/24;
                p = Table[Cos[phi], Sin[phi], phi, -Pi/2, Pi/2, dphi];

                reflectY[x_, y_] := -x, y;
                line[x1_, y1_, x2_, y2_] := (y2 - [FormalY])*(x2 - x1) - (y2 - y1)*(x2 - [FormalX]);
                point[l1_, l2_] := [FormalX], [FormalY] /.
                First@Solve[l1 == 0, l2 == 0, [FormalX], [FormalY]];


                After this, I only translated what I had on paper



                poly1 = 
                p[[9]],
                point[line[p[[4]], p[[9]]], line[p[[-1]], reflectY[p[[10]]]]],
                p[[-1]],
                point[line[p[[-1]], p[[5]]], line[reflectY[p[[5]]], p[[9]]]]
                ;
                poly2 =
                point[line[p[[1]], p[[9]]], line[reflectY[p[[2]]], p[[7]]]],
                point[line[reflectY[p[[2]]], p[[7]]], line[p[[10]], p[[9]]]],
                p[[9]]
                ;
                poly3 =
                p[[2]], 0, 0, reflectY[p[[2]]], point[line[p[[2]], p[[4]]],
                line[reflectY@p[[2]], reflectY@p[[4]]]]
                ;


                These are the 3 polygons you see above and to get the full logo, we need to reflect top two polygons. However, this is basically all we need



                Graphics[

                RGBColor[0.780392, 0.329412, 0.313725],
                Polygon /@ poly1, poly2, reflectY /@ poly1, reflectY /@ poly2,
                poly3
                ,
                AspectRatio -> Automatic
                ]


                Mathematica graphics



                And that's about it. Put a nice circle around it and start up Blender and you can easily create this



                enter image description here







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 6 hours ago









                halirutanhalirutan

                96.1k5222416




                96.1k5222416



























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