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Find a text string in a file and output only the rest of the text that follows it?

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;

4

I am finding a lot of posts on this forum that have to do with finding various values in a text file and outputting text surrounding it. However, I don't seem to find any "stream oriented".

I want to find a particular string in a file, and output only the text that follows it until the end of the file is reached. In other words, I want something that acts like a filter that ignores the text in a file until a specific string value is reached, and then from that point on outputs text to stdout until the end of the file. I want to use stdout so I can pipe output to a file if I so chose.

Is there a Linux text utility that will help me do this and if so, how? Or if I need to write a bash shell script to accomplish that, what are the general steps and command line utilities I would use to do this?

For example, given a sample file below:

one
two
three
four
five

Suppose I wanted to output all the text after the "three" so the result would be:

four
five

NOTE: I did find this seemingly related post but as you can see it's a bit of a mess:

how to find a text and copy the text after?

awk sed grep pipe stdout

share|improve this question

asked 9 hours ago

Robert OschlerRobert Oschler

12855 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Is "three" unique? What if are more than one ocurrences?
  
  – guillermo chamorro
  9 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Related question
  
  – Thor
  9 hours ago
  

  
  
  
  

add a comment | 

4

I am finding a lot of posts on this forum that have to do with finding various values in a text file and outputting text surrounding it. However, I don't seem to find any "stream oriented".

I want to find a particular string in a file, and output only the text that follows it until the end of the file is reached. In other words, I want something that acts like a filter that ignores the text in a file until a specific string value is reached, and then from that point on outputs text to stdout until the end of the file. I want to use stdout so I can pipe output to a file if I so chose.

Is there a Linux text utility that will help me do this and if so, how? Or if I need to write a bash shell script to accomplish that, what are the general steps and command line utilities I would use to do this?

For example, given a sample file below:

one
two
three
four
five

Suppose I wanted to output all the text after the "three" so the result would be:

four
five

NOTE: I did find this seemingly related post but as you can see it's a bit of a mess:

how to find a text and copy the text after?

awk sed grep pipe stdout

share|improve this question

asked 9 hours ago

Robert OschlerRobert Oschler

12855 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Is "three" unique? What if are more than one ocurrences?
  
  – guillermo chamorro
  9 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Related question
  
  – Thor
  9 hours ago
  

  
  
  
  

add a comment | 

I am finding a lot of posts on this forum that have to do with finding various values in a text file and outputting text surrounding it. However, I don't seem to find any "stream oriented".

I want to find a particular string in a file, and output only the text that follows it until the end of the file is reached. In other words, I want something that acts like a filter that ignores the text in a file until a specific string value is reached, and then from that point on outputs text to stdout until the end of the file. I want to use stdout so I can pipe output to a file if I so chose.

Is there a Linux text utility that will help me do this and if so, how? Or if I need to write a bash shell script to accomplish that, what are the general steps and command line utilities I would use to do this?

For example, given a sample file below:

one
two
three
four
five

Suppose I wanted to output all the text after the "three" so the result would be:

four
five

NOTE: I did find this seemingly related post but as you can see it's a bit of a mess:

how to find a text and copy the text after?

awk sed grep pipe stdout

share|improve this question

asked 9 hours ago

Robert OschlerRobert Oschler

12855 bronze badges

one
two
three
four
five

four
five

share|improve this question

asked 9 hours ago

Robert OschlerRobert Oschler

12855 bronze badges

share|improve this question

asked 9 hours ago

Robert OschlerRobert Oschler

12855 bronze badges

asked 9 hours ago

Robert OschlerRobert Oschler

12855 bronze badges

asked 9 hours ago

Robert OschlerRobert Oschler

12855 bronze badges

2 Answers
2

active

oldest

votes

4

Use awk:

awk 's;/^three$/s=1' file

or

awk 's;$0=="three"s=1' file

• 
  s; will print the line if variable s is true, which is the case first time after the pattern/word has been found ...


• 
  /^three$/s=1 will set variable s to true (1) if pattern/word is found.

share|improve this answer

edited 8 hours ago

answered 9 hours ago

pLumopLumo

7,2081414 silver badges3232 bronze badges

add a comment | 

3

With GNU sed:

sed 0,/three/d

Note that Linux is a kernel, it doesn't have utilities. GNU sed is the sed implementation commonly found on GNU/Linux systems like Debian GNU/Linux. GNU sed predates Linux and has been compiled to run on most Unix-like systems including most of those running Linux as their kernel. It is itself a Free, Libre and OpenSource re-implementation (with a few extensions including that 0 address) of the UNIX sed utility from the late 70s.

share|improve this answer

answered 8 hours ago

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

add a comment | 

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4

Use awk:

awk 's;/^three$/s=1' file

or

awk 's;$0=="three"s=1' file

• 
  s; will print the line if variable s is true, which is the case first time after the pattern/word has been found ...


• 
  /^three$/s=1 will set variable s to true (1) if pattern/word is found.

share|improve this answer

edited 8 hours ago

answered 9 hours ago

pLumopLumo

7,2081414 silver badges3232 bronze badges

add a comment | 

4

Use awk:

awk 's;/^three$/s=1' file

or

awk 's;$0=="three"s=1' file

• 
  s; will print the line if variable s is true, which is the case first time after the pattern/word has been found ...


• 
  /^three$/s=1 will set variable s to true (1) if pattern/word is found.

share|improve this answer

edited 8 hours ago

answered 9 hours ago

pLumopLumo

7,2081414 silver badges3232 bronze badges

add a comment | 

Use awk:

awk 's;/^three$/s=1' file

or

awk 's;$0=="three"s=1' file

• 
  s; will print the line if variable s is true, which is the case first time after the pattern/word has been found ...


• 
  /^three$/s=1 will set variable s to true (1) if pattern/word is found.

share|improve this answer

edited 8 hours ago

answered 9 hours ago

pLumopLumo

7,2081414 silver badges3232 bronze badges

awk 's;/^three$/s=1' file

awk 's;$0=="three"s=1' file

share|improve this answer

edited 8 hours ago

answered 9 hours ago

pLumopLumo

7,2081414 silver badges3232 bronze badges

answered 9 hours ago

pLumopLumo

7,2081414 silver badges3232 bronze badges

answered 9 hours ago

pLumopLumo

7,2081414 silver badges3232 bronze badges

3

With GNU sed:

sed 0,/three/d

Note that Linux is a kernel, it doesn't have utilities. GNU sed is the sed implementation commonly found on GNU/Linux systems like Debian GNU/Linux. GNU sed predates Linux and has been compiled to run on most Unix-like systems including most of those running Linux as their kernel. It is itself a Free, Libre and OpenSource re-implementation (with a few extensions including that 0 address) of the UNIX sed utility from the late 70s.

share|improve this answer

answered 8 hours ago

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

add a comment | 

3

With GNU sed:

sed 0,/three/d

Note that Linux is a kernel, it doesn't have utilities. GNU sed is the sed implementation commonly found on GNU/Linux systems like Debian GNU/Linux. GNU sed predates Linux and has been compiled to run on most Unix-like systems including most of those running Linux as their kernel. It is itself a Free, Libre and OpenSource re-implementation (with a few extensions including that 0 address) of the UNIX sed utility from the late 70s.

share|improve this answer

answered 8 hours ago

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

add a comment | 

With GNU sed:

sed 0,/three/d

Note that Linux is a kernel, it doesn't have utilities. GNU sed is the sed implementation commonly found on GNU/Linux systems like Debian GNU/Linux. GNU sed predates Linux and has been compiled to run on most Unix-like systems including most of those running Linux as their kernel. It is itself a Free, Libre and OpenSource re-implementation (with a few extensions including that 0 address) of the UNIX sed utility from the late 70s.

share|improve this answer

answered 8 hours ago

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

sed 0,/three/d

share|improve this answer

answered 8 hours ago

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

answered 8 hours ago

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges

answered 8 hours ago

Stéphane ChazelasStéphane Chazelas

328k5757 gold badges638638 silver badges10061006 bronze badges