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Drawing arrowtips at the end of each segment in a polygonal path

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2

I need to draw polygonal paths, with an arrow tip placed at the end of each segment like in the figure below.

The above image was made with Inkscape (I had to literally create the triangles for the arrow tips at A and B and orient them appropriately).

Can I get such arrowheads automatically in Asymptote? From what I can gather from the manual, there are a large variety of arrowtip shapes available but no option to place them at the ends of each segment of a polygonal path.

The code below for instance produces

unitsize(5cm);
settings.outformat = "png"; 

draw((0,0) -- (1,0.2) -- (0,1)--(2,2), arrow=Arrow); 

where the arrow is only at the endpoint (2,2).

asymptote draw

share|improve this question

asked 8 hours ago

smilingbuddhasmilingbuddha

96944 gold badges1010 silver badges1717 bronze badges

add a comment | 

2

I need to draw polygonal paths, with an arrow tip placed at the end of each segment like in the figure below.

The above image was made with Inkscape (I had to literally create the triangles for the arrow tips at A and B and orient them appropriately).

Can I get such arrowheads automatically in Asymptote? From what I can gather from the manual, there are a large variety of arrowtip shapes available but no option to place them at the ends of each segment of a polygonal path.

The code below for instance produces

unitsize(5cm);
settings.outformat = "png"; 

draw((0,0) -- (1,0.2) -- (0,1)--(2,2), arrow=Arrow); 

where the arrow is only at the endpoint (2,2).

asymptote draw

share|improve this question

asked 8 hours ago

smilingbuddhasmilingbuddha

96944 gold badges1010 silver badges1717 bronze badges

add a comment | 

I need to draw polygonal paths, with an arrow tip placed at the end of each segment like in the figure below.

The above image was made with Inkscape (I had to literally create the triangles for the arrow tips at A and B and orient them appropriately).

Can I get such arrowheads automatically in Asymptote? From what I can gather from the manual, there are a large variety of arrowtip shapes available but no option to place them at the ends of each segment of a polygonal path.

The code below for instance produces

unitsize(5cm);
settings.outformat = "png"; 

draw((0,0) -- (1,0.2) -- (0,1)--(2,2), arrow=Arrow); 

where the arrow is only at the endpoint (2,2).

asymptote draw

share|improve this question

asked 8 hours ago

smilingbuddhasmilingbuddha

96944 gold badges1010 silver badges1717 bronze badges

unitsize(5cm);
settings.outformat = "png"; 

draw((0,0) -- (1,0.2) -- (0,1)--(2,2), arrow=Arrow); 

share|improve this question

asked 8 hours ago

smilingbuddhasmilingbuddha

96944 gold badges1010 silver badges1717 bronze badges

share|improve this question

asked 8 hours ago

smilingbuddhasmilingbuddha

96944 gold badges1010 silver badges1717 bronze badges

asked 8 hours ago

smilingbuddhasmilingbuddha

96944 gold badges1010 silver badges1717 bronze badges

asked 8 hours ago

smilingbuddhasmilingbuddha

96944 gold badges1010 silver badges1717 bronze badges

1 Answer
1

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6

I don't know of a built-in way to do it, but here is a short function I wrote to do it. It uses the built-in length() and subpath() functions.

unitsize(5cm);
settings.outformat = "png"; 

void segmentArrows(path p) 
 for (int i = 0; i < length(p); ++i) 
 draw(subpath(p, i, i+1), arrow=Arrow);
 


segmentArrows((0,0)--(1,0.2)--(0,1)--(2,2)); 

share|improve this answer

answered 8 hours ago

JamesJames

3,18211 gold badge66 silver badges2525 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! I didn't know about subpath!
  
  – smilingbuddha
  8 hours ago
  

  
  
  
  

add a comment | 

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6

I don't know of a built-in way to do it, but here is a short function I wrote to do it. It uses the built-in length() and subpath() functions.

unitsize(5cm);
settings.outformat = "png"; 

void segmentArrows(path p) 
 for (int i = 0; i < length(p); ++i) 
 draw(subpath(p, i, i+1), arrow=Arrow);
 


segmentArrows((0,0)--(1,0.2)--(0,1)--(2,2)); 

share|improve this answer

answered 8 hours ago

JamesJames

3,18211 gold badge66 silver badges2525 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! I didn't know about subpath!
  
  – smilingbuddha
  8 hours ago
  

  
  
  
  

add a comment | 

6

I don't know of a built-in way to do it, but here is a short function I wrote to do it. It uses the built-in length() and subpath() functions.

unitsize(5cm);
settings.outformat = "png"; 

void segmentArrows(path p) 
 for (int i = 0; i < length(p); ++i) 
 draw(subpath(p, i, i+1), arrow=Arrow);
 


segmentArrows((0,0)--(1,0.2)--(0,1)--(2,2)); 

share|improve this answer

answered 8 hours ago

JamesJames

3,18211 gold badge66 silver badges2525 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! I didn't know about subpath!
  
  – smilingbuddha
  8 hours ago
  

  
  
  
  

add a comment | 

I don't know of a built-in way to do it, but here is a short function I wrote to do it. It uses the built-in length() and subpath() functions.

unitsize(5cm);
settings.outformat = "png"; 

void segmentArrows(path p) 
 for (int i = 0; i < length(p); ++i) 
 draw(subpath(p, i, i+1), arrow=Arrow);
 


segmentArrows((0,0)--(1,0.2)--(0,1)--(2,2)); 

share|improve this answer

answered 8 hours ago

JamesJames

3,18211 gold badge66 silver badges2525 bronze badges

unitsize(5cm);
settings.outformat = "png"; 

void segmentArrows(path p) 
 for (int i = 0; i < length(p); ++i) 
 draw(subpath(p, i, i+1), arrow=Arrow);
 


segmentArrows((0,0)--(1,0.2)--(0,1)--(2,2)); 

share|improve this answer

answered 8 hours ago

JamesJames

3,18211 gold badge66 silver badges2525 bronze badges

answered 8 hours ago

JamesJames

3,18211 gold badge66 silver badges2525 bronze badges

answered 8 hours ago

JamesJames

3,18211 gold badge66 silver badges2525 bronze badges