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Drawing arrowtips at the end of each segment in a polygonal path


Drawing the Reeb foliationAsymptote: Drawing contours of spline surfaceAsymptote: Planar surface from path - misdrawn streaks at cornersI need help with path times command of asymptote package. How do I find the point of intersection of a line through X=a and a path p?Error drawing curve within slopefieldHow to shift first point in a cyclic path?Drawing schematics or figuresDrawing contour around the modular fundamental domainAsymptote: How do I make a gap in a segment to include a label?Drawing some simple pictures with tikz






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2















I need to draw polygonal paths, with an arrow tip placed at the end of each segment like in the figure below.



enter image description here



The above image was made with Inkscape (I had to literally create the triangles for the arrow tips at A and B and orient them appropriately).



Can I get such arrowheads automatically in Asymptote? From what I can gather from the manual, there are a large variety of arrowtip shapes available but no option to place them at the ends of each segment of a polygonal path.



The code below for instance produces



unitsize(5cm);
settings.outformat = "png";

draw((0,0) -- (1,0.2) -- (0,1)--(2,2), arrow=Arrow);


enter image description here



where the arrow is only at the endpoint (2,2).










share|improve this question






























    2















    I need to draw polygonal paths, with an arrow tip placed at the end of each segment like in the figure below.



    enter image description here



    The above image was made with Inkscape (I had to literally create the triangles for the arrow tips at A and B and orient them appropriately).



    Can I get such arrowheads automatically in Asymptote? From what I can gather from the manual, there are a large variety of arrowtip shapes available but no option to place them at the ends of each segment of a polygonal path.



    The code below for instance produces



    unitsize(5cm);
    settings.outformat = "png";

    draw((0,0) -- (1,0.2) -- (0,1)--(2,2), arrow=Arrow);


    enter image description here



    where the arrow is only at the endpoint (2,2).










    share|improve this question


























      2












      2








      2








      I need to draw polygonal paths, with an arrow tip placed at the end of each segment like in the figure below.



      enter image description here



      The above image was made with Inkscape (I had to literally create the triangles for the arrow tips at A and B and orient them appropriately).



      Can I get such arrowheads automatically in Asymptote? From what I can gather from the manual, there are a large variety of arrowtip shapes available but no option to place them at the ends of each segment of a polygonal path.



      The code below for instance produces



      unitsize(5cm);
      settings.outformat = "png";

      draw((0,0) -- (1,0.2) -- (0,1)--(2,2), arrow=Arrow);


      enter image description here



      where the arrow is only at the endpoint (2,2).










      share|improve this question














      I need to draw polygonal paths, with an arrow tip placed at the end of each segment like in the figure below.



      enter image description here



      The above image was made with Inkscape (I had to literally create the triangles for the arrow tips at A and B and orient them appropriately).



      Can I get such arrowheads automatically in Asymptote? From what I can gather from the manual, there are a large variety of arrowtip shapes available but no option to place them at the ends of each segment of a polygonal path.



      The code below for instance produces



      unitsize(5cm);
      settings.outformat = "png";

      draw((0,0) -- (1,0.2) -- (0,1)--(2,2), arrow=Arrow);


      enter image description here



      where the arrow is only at the endpoint (2,2).







      asymptote draw






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 8 hours ago









      smilingbuddhasmilingbuddha

      9694 gold badges10 silver badges17 bronze badges




      9694 gold badges10 silver badges17 bronze badges























          1 Answer
          1






          active

          oldest

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          6














          I don't know of a built-in way to do it, but here is a short function I wrote to do it. It uses the built-in length() and subpath() functions.



          unitsize(5cm);
          settings.outformat = "png";

          void segmentArrows(path p)
          for (int i = 0; i < length(p); ++i)
          draw(subpath(p, i, i+1), arrow=Arrow);



          segmentArrows((0,0)--(1,0.2)--(0,1)--(2,2));


          enter image description here






          share|improve this answer

























          • Thanks! I didn't know about subpath!

            – smilingbuddha
            8 hours ago













          Your Answer








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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          6














          I don't know of a built-in way to do it, but here is a short function I wrote to do it. It uses the built-in length() and subpath() functions.



          unitsize(5cm);
          settings.outformat = "png";

          void segmentArrows(path p)
          for (int i = 0; i < length(p); ++i)
          draw(subpath(p, i, i+1), arrow=Arrow);



          segmentArrows((0,0)--(1,0.2)--(0,1)--(2,2));


          enter image description here






          share|improve this answer

























          • Thanks! I didn't know about subpath!

            – smilingbuddha
            8 hours ago















          6














          I don't know of a built-in way to do it, but here is a short function I wrote to do it. It uses the built-in length() and subpath() functions.



          unitsize(5cm);
          settings.outformat = "png";

          void segmentArrows(path p)
          for (int i = 0; i < length(p); ++i)
          draw(subpath(p, i, i+1), arrow=Arrow);



          segmentArrows((0,0)--(1,0.2)--(0,1)--(2,2));


          enter image description here






          share|improve this answer

























          • Thanks! I didn't know about subpath!

            – smilingbuddha
            8 hours ago













          6












          6








          6







          I don't know of a built-in way to do it, but here is a short function I wrote to do it. It uses the built-in length() and subpath() functions.



          unitsize(5cm);
          settings.outformat = "png";

          void segmentArrows(path p)
          for (int i = 0; i < length(p); ++i)
          draw(subpath(p, i, i+1), arrow=Arrow);



          segmentArrows((0,0)--(1,0.2)--(0,1)--(2,2));


          enter image description here






          share|improve this answer













          I don't know of a built-in way to do it, but here is a short function I wrote to do it. It uses the built-in length() and subpath() functions.



          unitsize(5cm);
          settings.outformat = "png";

          void segmentArrows(path p)
          for (int i = 0; i < length(p); ++i)
          draw(subpath(p, i, i+1), arrow=Arrow);



          segmentArrows((0,0)--(1,0.2)--(0,1)--(2,2));


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 8 hours ago









          JamesJames

          3,1821 gold badge6 silver badges25 bronze badges




          3,1821 gold badge6 silver badges25 bronze badges















          • Thanks! I didn't know about subpath!

            – smilingbuddha
            8 hours ago

















          • Thanks! I didn't know about subpath!

            – smilingbuddha
            8 hours ago
















          Thanks! I didn't know about subpath!

          – smilingbuddha
          8 hours ago





          Thanks! I didn't know about subpath!

          – smilingbuddha
          8 hours ago

















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