Can Jimmy hang on his rope?Will Jimmy fall off his platform?How many Jimmys can fit?Jimmy needs your help!Count the bytes of a programCenter The Text!Analyse your ChairSplit a Shakespeare ScriptJimmy these arrays downNo strings attached!Would this string work as string?Will Jimmy fall off his platform?How many Jimmys can fit?Jimmy needs your help!

Need a non-volatile memory IC with near unlimited read/write operations capability

How do ballistic trajectories work in a ring world?

How do I separate enchants from items?

Why do people prefer metropolitan areas, considering monsters and villains?

How can I review my manager, who is fine?

Can "expliquer" be followed by "que" and the subjunctive?

Can one block with a protection from color creature?

Why is a semiprime used as the modulus in RSA?

Why won't the U.S. sign a peace treaty with North Korea?

How to use Adostop Eco stop bath?

Wires do not connect in Circuitikz

Tesco's Burger Relish Best Before End date number

US citizen traveling with Peruvian passport

How do I talk to my wife about unrealistic expectations?

What does "spinning upon the shoals" mean?

How do I explain that I don't want to maintain old projects?

Computer name naming convention for security

Why did Old English lose both thorn and eth?

I'm feeling like my character doesn't fit the campaign

A ring of generalized power series

What exactly is a "murder hobo"?

Moving millions of files to a different directory with specfic name patterns

How many Jimmys can fit?

Publishing papers seem natural to many, while I find it really hard to think novel stuff to pursue till publication. How to cope up with this?



Can Jimmy hang on his rope?


Will Jimmy fall off his platform?How many Jimmys can fit?Jimmy needs your help!Count the bytes of a programCenter The Text!Analyse your ChairSplit a Shakespeare ScriptJimmy these arrays downNo strings attached!Would this string work as string?Will Jimmy fall off his platform?How many Jimmys can fit?Jimmy needs your help!






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








6












$begingroup$


Yet another Jimmy challenge by his original father. See these other lovely challenges.




As you all know, recently we've been seeing challenges related to Jimmy on platforms. Now, Jimmy is an acrobat as I mentioned before, and he's got other tricks up his sleeve.



One of these tricks is hanging by ropes. Here's an example of a rope Jimmy could hang from:



 ||
||
||
||
||
||


When Jimmy hangs on a rope, it looks like this:



 ||
||
/o
||
||
||


He can hang on the left or the right of the rope, so this:



 ||
||
||
/o
||
||


is also valid. But he cannot hang by just one body part, so anything like this:



 ||
||
||
/o|
||
||


is invalid. Note that when he is hanging by one body part the other half of the rope is visible because Jimmy does not cover it up.



Also, Jimmy does not like hanging on the bottom of the rope - it scares him - so this:



 ||
||
||
||
||
/o


is invalid.



The challenge



Take input of a Jimmy situation like the ones above, and output whether Jimmy will hang on to the rope or not through a truthy or falsy value.



The specifics




  • Write a program that takes input. This can be through a function or any other appropriate input method.



    1. The input should be a scene of one Jimmy and a rope as exemplified above.


  • The program should output a truthy or falsy value to the console based on whether Jimmy can hang on to the rope or if he would fall off the rope, respectively.



  • The criteria for Jimmy being able to hang on the rope:



    1. Two of his body parts are on the rope.


    2. He is not on the bottom of the rope.


    3. He is not floating in mid-air.



  • You can assume the rope will be straight, made up of || segments, and will be longer than one character in height.


  • You can assume one whole rope and one singular Jimmy will be present in your scene, no more and no less.


  • You can assume there will be no trailing newlines at the bottom of the rope.


  • You must cover any amount of leading or trailing spaces before and after the rope.


Test cases



 ||
||
|| TRUTHY
/o
||
||


||
||
/o| FALSY
||
||


||
/o TRUTHY
||


||
/o FALSY


/o
|| TRUTHY


||
||
/o || FALSY
||
||


Scoring



This is code-golf, so lowest score in bytes wins after about a week.



Leaderboard



You can view the leaderboard for this post by expanding the widget/snippet below. In order for your post to be included in the rankings, you need a header (# header text) with the following info:



  • The name of the language (end it with a comma , or dash -), followed by...


  • The byte count, as the last number to appear in your header.


For example, JavaScript (ES6), 72 bytes is valid, but Fortran, 143 bytes (8-bit) is invalid because the byte count is not the last number in the header (your answer will be recognized as 8 bytes - don't take advantage of this).






<!-- Run the snippet to see the leaderboard. Report any bugs to @xMikee1 on Github. --> <iframe src="https://xmikee1.github.io/ppcg-leaderboard/?id=187759" width="100%" height="100%" style="border:none;">Oops, your browser is too old to view this content! Please upgrade to a newer version of your browser that supports HTML5.</iframe><style>html,bodymargin:0;padding:0;height:100%;overflow:hidden</style>












share|improve this question











$endgroup$











  • $begingroup$
    Is the rope always going to have the same number of spaces before it, or can that vary?
    $endgroup$
    – Maxwell
    8 hours ago










  • $begingroup$
    @Maxwell That can vary.
    $endgroup$
    – connectyourcharger
    8 hours ago










  • $begingroup$
    Can we take the input as something like a list, where each line is a separate string, or does it have to be one single string?
    $endgroup$
    – Maxwell
    8 hours ago






  • 6




    $begingroup$
    Jimmy should really take a holiday
    $endgroup$
    – Luis Mendo
    7 hours ago






  • 1




    $begingroup$
    @LuisMendo Jimmy is dedicated to what he does!
    $endgroup$
    – connectyourcharger
    7 hours ago

















6












$begingroup$


Yet another Jimmy challenge by his original father. See these other lovely challenges.




As you all know, recently we've been seeing challenges related to Jimmy on platforms. Now, Jimmy is an acrobat as I mentioned before, and he's got other tricks up his sleeve.



One of these tricks is hanging by ropes. Here's an example of a rope Jimmy could hang from:



 ||
||
||
||
||
||


When Jimmy hangs on a rope, it looks like this:



 ||
||
/o
||
||
||


He can hang on the left or the right of the rope, so this:



 ||
||
||
/o
||
||


is also valid. But he cannot hang by just one body part, so anything like this:



 ||
||
||
/o|
||
||


is invalid. Note that when he is hanging by one body part the other half of the rope is visible because Jimmy does not cover it up.



Also, Jimmy does not like hanging on the bottom of the rope - it scares him - so this:



 ||
||
||
||
||
/o


is invalid.



The challenge



Take input of a Jimmy situation like the ones above, and output whether Jimmy will hang on to the rope or not through a truthy or falsy value.



The specifics




  • Write a program that takes input. This can be through a function or any other appropriate input method.



    1. The input should be a scene of one Jimmy and a rope as exemplified above.


  • The program should output a truthy or falsy value to the console based on whether Jimmy can hang on to the rope or if he would fall off the rope, respectively.



  • The criteria for Jimmy being able to hang on the rope:



    1. Two of his body parts are on the rope.


    2. He is not on the bottom of the rope.


    3. He is not floating in mid-air.



  • You can assume the rope will be straight, made up of || segments, and will be longer than one character in height.


  • You can assume one whole rope and one singular Jimmy will be present in your scene, no more and no less.


  • You can assume there will be no trailing newlines at the bottom of the rope.


  • You must cover any amount of leading or trailing spaces before and after the rope.


Test cases



 ||
||
|| TRUTHY
/o
||
||


||
||
/o| FALSY
||
||


||
/o TRUTHY
||


||
/o FALSY


/o
|| TRUTHY


||
||
/o || FALSY
||
||


Scoring



This is code-golf, so lowest score in bytes wins after about a week.



Leaderboard



You can view the leaderboard for this post by expanding the widget/snippet below. In order for your post to be included in the rankings, you need a header (# header text) with the following info:



  • The name of the language (end it with a comma , or dash -), followed by...


  • The byte count, as the last number to appear in your header.


For example, JavaScript (ES6), 72 bytes is valid, but Fortran, 143 bytes (8-bit) is invalid because the byte count is not the last number in the header (your answer will be recognized as 8 bytes - don't take advantage of this).






<!-- Run the snippet to see the leaderboard. Report any bugs to @xMikee1 on Github. --> <iframe src="https://xmikee1.github.io/ppcg-leaderboard/?id=187759" width="100%" height="100%" style="border:none;">Oops, your browser is too old to view this content! Please upgrade to a newer version of your browser that supports HTML5.</iframe><style>html,bodymargin:0;padding:0;height:100%;overflow:hidden</style>












share|improve this question











$endgroup$











  • $begingroup$
    Is the rope always going to have the same number of spaces before it, or can that vary?
    $endgroup$
    – Maxwell
    8 hours ago










  • $begingroup$
    @Maxwell That can vary.
    $endgroup$
    – connectyourcharger
    8 hours ago










  • $begingroup$
    Can we take the input as something like a list, where each line is a separate string, or does it have to be one single string?
    $endgroup$
    – Maxwell
    8 hours ago






  • 6




    $begingroup$
    Jimmy should really take a holiday
    $endgroup$
    – Luis Mendo
    7 hours ago






  • 1




    $begingroup$
    @LuisMendo Jimmy is dedicated to what he does!
    $endgroup$
    – connectyourcharger
    7 hours ago













6












6








6





$begingroup$


Yet another Jimmy challenge by his original father. See these other lovely challenges.




As you all know, recently we've been seeing challenges related to Jimmy on platforms. Now, Jimmy is an acrobat as I mentioned before, and he's got other tricks up his sleeve.



One of these tricks is hanging by ropes. Here's an example of a rope Jimmy could hang from:



 ||
||
||
||
||
||


When Jimmy hangs on a rope, it looks like this:



 ||
||
/o
||
||
||


He can hang on the left or the right of the rope, so this:



 ||
||
||
/o
||
||


is also valid. But he cannot hang by just one body part, so anything like this:



 ||
||
||
/o|
||
||


is invalid. Note that when he is hanging by one body part the other half of the rope is visible because Jimmy does not cover it up.



Also, Jimmy does not like hanging on the bottom of the rope - it scares him - so this:



 ||
||
||
||
||
/o


is invalid.



The challenge



Take input of a Jimmy situation like the ones above, and output whether Jimmy will hang on to the rope or not through a truthy or falsy value.



The specifics




  • Write a program that takes input. This can be through a function or any other appropriate input method.



    1. The input should be a scene of one Jimmy and a rope as exemplified above.


  • The program should output a truthy or falsy value to the console based on whether Jimmy can hang on to the rope or if he would fall off the rope, respectively.



  • The criteria for Jimmy being able to hang on the rope:



    1. Two of his body parts are on the rope.


    2. He is not on the bottom of the rope.


    3. He is not floating in mid-air.



  • You can assume the rope will be straight, made up of || segments, and will be longer than one character in height.


  • You can assume one whole rope and one singular Jimmy will be present in your scene, no more and no less.


  • You can assume there will be no trailing newlines at the bottom of the rope.


  • You must cover any amount of leading or trailing spaces before and after the rope.


Test cases



 ||
||
|| TRUTHY
/o
||
||


||
||
/o| FALSY
||
||


||
/o TRUTHY
||


||
/o FALSY


/o
|| TRUTHY


||
||
/o || FALSY
||
||


Scoring



This is code-golf, so lowest score in bytes wins after about a week.



Leaderboard



You can view the leaderboard for this post by expanding the widget/snippet below. In order for your post to be included in the rankings, you need a header (# header text) with the following info:



  • The name of the language (end it with a comma , or dash -), followed by...


  • The byte count, as the last number to appear in your header.


For example, JavaScript (ES6), 72 bytes is valid, but Fortran, 143 bytes (8-bit) is invalid because the byte count is not the last number in the header (your answer will be recognized as 8 bytes - don't take advantage of this).






<!-- Run the snippet to see the leaderboard. Report any bugs to @xMikee1 on Github. --> <iframe src="https://xmikee1.github.io/ppcg-leaderboard/?id=187759" width="100%" height="100%" style="border:none;">Oops, your browser is too old to view this content! Please upgrade to a newer version of your browser that supports HTML5.</iframe><style>html,bodymargin:0;padding:0;height:100%;overflow:hidden</style>












share|improve this question











$endgroup$




Yet another Jimmy challenge by his original father. See these other lovely challenges.




As you all know, recently we've been seeing challenges related to Jimmy on platforms. Now, Jimmy is an acrobat as I mentioned before, and he's got other tricks up his sleeve.



One of these tricks is hanging by ropes. Here's an example of a rope Jimmy could hang from:



 ||
||
||
||
||
||


When Jimmy hangs on a rope, it looks like this:



 ||
||
/o
||
||
||


He can hang on the left or the right of the rope, so this:



 ||
||
||
/o
||
||


is also valid. But he cannot hang by just one body part, so anything like this:



 ||
||
||
/o|
||
||


is invalid. Note that when he is hanging by one body part the other half of the rope is visible because Jimmy does not cover it up.



Also, Jimmy does not like hanging on the bottom of the rope - it scares him - so this:



 ||
||
||
||
||
/o


is invalid.



The challenge



Take input of a Jimmy situation like the ones above, and output whether Jimmy will hang on to the rope or not through a truthy or falsy value.



The specifics




  • Write a program that takes input. This can be through a function or any other appropriate input method.



    1. The input should be a scene of one Jimmy and a rope as exemplified above.


  • The program should output a truthy or falsy value to the console based on whether Jimmy can hang on to the rope or if he would fall off the rope, respectively.



  • The criteria for Jimmy being able to hang on the rope:



    1. Two of his body parts are on the rope.


    2. He is not on the bottom of the rope.


    3. He is not floating in mid-air.



  • You can assume the rope will be straight, made up of || segments, and will be longer than one character in height.


  • You can assume one whole rope and one singular Jimmy will be present in your scene, no more and no less.


  • You can assume there will be no trailing newlines at the bottom of the rope.


  • You must cover any amount of leading or trailing spaces before and after the rope.


Test cases



 ||
||
|| TRUTHY
/o
||
||


||
||
/o| FALSY
||
||


||
/o TRUTHY
||


||
/o FALSY


/o
|| TRUTHY


||
||
/o || FALSY
||
||


Scoring



This is code-golf, so lowest score in bytes wins after about a week.



Leaderboard



You can view the leaderboard for this post by expanding the widget/snippet below. In order for your post to be included in the rankings, you need a header (# header text) with the following info:



  • The name of the language (end it with a comma , or dash -), followed by...


  • The byte count, as the last number to appear in your header.


For example, JavaScript (ES6), 72 bytes is valid, but Fortran, 143 bytes (8-bit) is invalid because the byte count is not the last number in the header (your answer will be recognized as 8 bytes - don't take advantage of this).






<!-- Run the snippet to see the leaderboard. Report any bugs to @xMikee1 on Github. --> <iframe src="https://xmikee1.github.io/ppcg-leaderboard/?id=187759" width="100%" height="100%" style="border:none;">Oops, your browser is too old to view this content! Please upgrade to a newer version of your browser that supports HTML5.</iframe><style>html,bodymargin:0;padding:0;height:100%;overflow:hidden</style>








<!-- Run the snippet to see the leaderboard. Report any bugs to @xMikee1 on Github. --> <iframe src="https://xmikee1.github.io/ppcg-leaderboard/?id=187759" width="100%" height="100%" style="border:none;">Oops, your browser is too old to view this content! Please upgrade to a newer version of your browser that supports HTML5.</iframe><style>html,bodymargin:0;padding:0;height:100%;overflow:hidden</style>





<!-- Run the snippet to see the leaderboard. Report any bugs to @xMikee1 on Github. --> <iframe src="https://xmikee1.github.io/ppcg-leaderboard/?id=187759" width="100%" height="100%" style="border:none;">Oops, your browser is too old to view this content! Please upgrade to a newer version of your browser that supports HTML5.</iframe><style>html,bodymargin:0;padding:0;height:100%;overflow:hidden</style>






code-golf string ascii-art parsing






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 7 hours ago









Glorfindel

2331 gold badge3 silver badges9 bronze badges




2331 gold badge3 silver badges9 bronze badges










asked 8 hours ago









connectyourchargerconnectyourcharger

6241 gold badge3 silver badges17 bronze badges




6241 gold badge3 silver badges17 bronze badges











  • $begingroup$
    Is the rope always going to have the same number of spaces before it, or can that vary?
    $endgroup$
    – Maxwell
    8 hours ago










  • $begingroup$
    @Maxwell That can vary.
    $endgroup$
    – connectyourcharger
    8 hours ago










  • $begingroup$
    Can we take the input as something like a list, where each line is a separate string, or does it have to be one single string?
    $endgroup$
    – Maxwell
    8 hours ago






  • 6




    $begingroup$
    Jimmy should really take a holiday
    $endgroup$
    – Luis Mendo
    7 hours ago






  • 1




    $begingroup$
    @LuisMendo Jimmy is dedicated to what he does!
    $endgroup$
    – connectyourcharger
    7 hours ago
















  • $begingroup$
    Is the rope always going to have the same number of spaces before it, or can that vary?
    $endgroup$
    – Maxwell
    8 hours ago










  • $begingroup$
    @Maxwell That can vary.
    $endgroup$
    – connectyourcharger
    8 hours ago










  • $begingroup$
    Can we take the input as something like a list, where each line is a separate string, or does it have to be one single string?
    $endgroup$
    – Maxwell
    8 hours ago






  • 6




    $begingroup$
    Jimmy should really take a holiday
    $endgroup$
    – Luis Mendo
    7 hours ago






  • 1




    $begingroup$
    @LuisMendo Jimmy is dedicated to what he does!
    $endgroup$
    – connectyourcharger
    7 hours ago















$begingroup$
Is the rope always going to have the same number of spaces before it, or can that vary?
$endgroup$
– Maxwell
8 hours ago




$begingroup$
Is the rope always going to have the same number of spaces before it, or can that vary?
$endgroup$
– Maxwell
8 hours ago












$begingroup$
@Maxwell That can vary.
$endgroup$
– connectyourcharger
8 hours ago




$begingroup$
@Maxwell That can vary.
$endgroup$
– connectyourcharger
8 hours ago












$begingroup$
Can we take the input as something like a list, where each line is a separate string, or does it have to be one single string?
$endgroup$
– Maxwell
8 hours ago




$begingroup$
Can we take the input as something like a list, where each line is a separate string, or does it have to be one single string?
$endgroup$
– Maxwell
8 hours ago




6




6




$begingroup$
Jimmy should really take a holiday
$endgroup$
– Luis Mendo
7 hours ago




$begingroup$
Jimmy should really take a holiday
$endgroup$
– Luis Mendo
7 hours ago




1




1




$begingroup$
@LuisMendo Jimmy is dedicated to what he does!
$endgroup$
– connectyourcharger
7 hours ago




$begingroup$
@LuisMendo Jimmy is dedicated to what he does!
$endgroup$
– connectyourcharger
7 hours ago










10 Answers
10






active

oldest

votes


















8












$begingroup$

Python 3, 41 bytes



lambda x:any("|"not in i for i in x[:-1])


A function that takes input as a list of strings, each string being a different line.



-11 bytes thanks to xnor!



Try it online! (If you want to try more test cases, just put a "." after each set of lines in the input box.)



Takes advantage of the fact that if Jimmy is fully on the rope, no parts of the rope (no "|") will be showing. It checks if there are any lines that do not have "|", which means that Jimmy is fully on the rope.






share|improve this answer










New contributor



Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





$endgroup$












  • $begingroup$
    Can you do it without the check that the line has a "/"?
    $endgroup$
    – xnor
    7 hours ago










  • $begingroup$
    @xnor Yup! -11 bytes
    $endgroup$
    – Maxwell
    7 hours ago










  • $begingroup$
    Save a couple like so: lambda x:1-all("|"in i for i in x[:-1])
    $endgroup$
    – Jonathan Allan
    7 hours ago






  • 1




    $begingroup$
    Ouch, you was faster :)
    $endgroup$
    – Daniil Tutubalin
    6 hours ago


















6












$begingroup$


Python 2 or 3, 33 bytes





lambda l:min(map(max,l[:-1]))<'|'


An unnamed function accepting a list of lines



Try it online!



How?



There needs to be a section of rope obscured by Jimmy that is not the bottom one.



lambda l:min(map(max,l[:-1]))<'|'
lambda l: - a function taking l (the lines as strings)
l[:-1] - strip off the last line
map(max, ) - maximum of each line (where '|'>'o'>''>'/'>' ')
min( ) - minimum
<'|' - is less than '|' (hence not rope since '|' is maximal)





share|improve this answer











$endgroup$




















    5












    $begingroup$


    Jelly,  9 7  6 bytes



    Ṗ<”|ṀẠ


    A monadic Link accepting a list of lines



    Try it online!



    How?



    There needs to be a section of rope obscured by Jimmy that is not the bottom one.



    Ṗ<”|ṀẠ - Main Link: list of lines of characters
    Ṗ - remove last line
    ”| - pipe character
    < - less than? (vectorises) - Note that all other characters are
    Ṁ - maximum
    Ạ - all?





    share|improve this answer











    $endgroup$








    • 1




      $begingroup$
      I feel so weird writing these challenges about Jimmies. It starts to make you feel weird once you imagine multiple Jimmies hanging off of the same rope.
      $endgroup$
      – connectyourcharger
      8 hours ago






    • 1




      $begingroup$
      @connectyourcharger Foreshadowing?
      $endgroup$
      – negative seven
      8 hours ago










    • $begingroup$
      @negativeseven Possibly. I have already considered a meta community wiki to index all of the Jimmy posts.
      $endgroup$
      – connectyourcharger
      8 hours ago






    • 1




      $begingroup$
      Nine bytes, and once again, we still find out how someone can die.
      $endgroup$
      – IMustBeSomeone
      7 hours ago










    • $begingroup$
      "Note that all other characters are [less than '|']"?
      $endgroup$
      – Erik the Outgolfer
      5 hours ago


















    2












    $begingroup$

    JavaScript, 39 33 bytes



    Thanks @Daniil Tutubalin for golfing off 2 bytes





    x=>!!x.match(/^( *)/[^|]*n/m)


    This matches any line which is not the line where his left arm shows up and none of the rope shows.



    Try it online!






    share|improve this answer











    $endgroup$












    • $begingroup$
      It appears to fail if he is at the bottom of the rope
      $endgroup$
      – fəˈnɛtɪk
      7 hours ago










    • $begingroup$
      It should fail if he is at the bottom, right? Because Jimmy falls if he is at the bottom fo the rope
      $endgroup$
      – Maxwell
      7 hours ago










    • $begingroup$
      I mean that when I put him at the bottom of the rope your function for some reason returned 1
      $endgroup$
      – fəˈnɛtɪk
      6 hours ago










    • $begingroup$
      Hm, nevermind then.
      $endgroup$
      – Maxwell
      6 hours ago










    • $begingroup$
      Minus 2 bytes: x=>!!x.match(/^( *)/o\ *n1 ?|/m) But basically !! is not required because valid object is truthy value and null is falsy value, so you can make even minus 4.
      $endgroup$
      – Daniil Tutubalin
      3 hours ago



















    1












    $begingroup$

    JavaScript, 38 37 bytes





    r=>r.some(x=>!~x.search`\|`,r.pop())


    Try it online!






    share|improve this answer











    $endgroup$




















      1












      $begingroup$


      Befunge-98 (PyFunge), 26 bytes



      >#@~:a-!#v_' `+
      ^ 0_-3q#$<


      Try it online!



      Exits with return code 3 if n is encountered and the last line contained 3 non-space characters, otherwise exits with return code 0 on EOF. Thus, this relies on the last line not containing a trailing newline.



      Dissected



      >#@~ :a-!#v_ ' `+
      Read character, Branch downwards if Increment counter on
      return with code 0 equal to 10 ('n') the stack if greater
      if end of stream than 32 (' ') and
      implicitly loop

      ^ 0_-3q#$ <
      Return with code 3
      if counter is equal to 3,
      otherwise reset counter
      and return to beginning





      share|improve this answer









      $endgroup$




















        0












        $begingroup$


        Pyth, 9 bytes



        sPm!sqR|


        Test suite!






        share|improve this answer









        $endgroup$




















          0












          $begingroup$


          Retina, 9 bytes



          m`^[^|]+^


          Try it online!



          Now, I've never programmed in Retina before, but as far as I can tell this works. It is a regular expression that finds a string containing (1) the beginning of the input, (2) no "|" characters, and (3) a newline.



          People more familiar with either regular expressions or Retina are encouraged to offer suggestions. -2 bytes thanks to Neil!






          share|improve this answer










          New contributor



          Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.





          $endgroup$












          • $begingroup$
            Two alternatives: 1) Remove the n because a new line is not a | and so that will match anyway, and the final ^ suffices to ensure that you actually matched a newline. 2) Use a pilcrow instead of n and remove the trailing ^ (because that's always true after a newline in multiline mode).
            $endgroup$
            – Neil
            6 hours ago


















          0












          $begingroup$

          Dyalog APL Extended, 14 13 11 bytes





          3∊+/<¯1↓⍵


          Try it online!






          share|improve this answer











          $endgroup$




















            0












            $begingroup$


            Stax, 6 bytes



            é¿┤4╠q


            Run and debug it



            Transposes the input, then searches for "o|".






            share|improve this answer









            $endgroup$















              Your Answer






              StackExchange.ifUsing("editor", function ()
              StackExchange.using("externalEditor", function ()
              StackExchange.using("snippets", function ()
              StackExchange.snippets.init();
              );
              );
              , "code-snippets");

              StackExchange.ready(function()
              var channelOptions =
              tags: "".split(" "),
              id: "200"
              ;
              initTagRenderer("".split(" "), "".split(" "), channelOptions);

              StackExchange.using("externalEditor", function()
              // Have to fire editor after snippets, if snippets enabled
              if (StackExchange.settings.snippets.snippetsEnabled)
              StackExchange.using("snippets", function()
              createEditor();
              );

              else
              createEditor();

              );

              function createEditor()
              StackExchange.prepareEditor(
              heartbeatType: 'answer',
              autoActivateHeartbeat: false,
              convertImagesToLinks: false,
              noModals: true,
              showLowRepImageUploadWarning: true,
              reputationToPostImages: null,
              bindNavPrevention: true,
              postfix: "",
              imageUploader:
              brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
              contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
              allowUrls: true
              ,
              onDemand: true,
              discardSelector: ".discard-answer"
              ,immediatelyShowMarkdownHelp:true
              );



              );













              draft saved

              draft discarded


















              StackExchange.ready(
              function ()
              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodegolf.stackexchange.com%2fquestions%2f187759%2fcan-jimmy-hang-on-his-rope%23new-answer', 'question_page');

              );

              Post as a guest















              Required, but never shown

























              10 Answers
              10






              active

              oldest

              votes








              10 Answers
              10






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              8












              $begingroup$

              Python 3, 41 bytes



              lambda x:any("|"not in i for i in x[:-1])


              A function that takes input as a list of strings, each string being a different line.



              -11 bytes thanks to xnor!



              Try it online! (If you want to try more test cases, just put a "." after each set of lines in the input box.)



              Takes advantage of the fact that if Jimmy is fully on the rope, no parts of the rope (no "|") will be showing. It checks if there are any lines that do not have "|", which means that Jimmy is fully on the rope.






              share|improve this answer










              New contributor



              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.





              $endgroup$












              • $begingroup$
                Can you do it without the check that the line has a "/"?
                $endgroup$
                – xnor
                7 hours ago










              • $begingroup$
                @xnor Yup! -11 bytes
                $endgroup$
                – Maxwell
                7 hours ago










              • $begingroup$
                Save a couple like so: lambda x:1-all("|"in i for i in x[:-1])
                $endgroup$
                – Jonathan Allan
                7 hours ago






              • 1




                $begingroup$
                Ouch, you was faster :)
                $endgroup$
                – Daniil Tutubalin
                6 hours ago















              8












              $begingroup$

              Python 3, 41 bytes



              lambda x:any("|"not in i for i in x[:-1])


              A function that takes input as a list of strings, each string being a different line.



              -11 bytes thanks to xnor!



              Try it online! (If you want to try more test cases, just put a "." after each set of lines in the input box.)



              Takes advantage of the fact that if Jimmy is fully on the rope, no parts of the rope (no "|") will be showing. It checks if there are any lines that do not have "|", which means that Jimmy is fully on the rope.






              share|improve this answer










              New contributor



              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.





              $endgroup$












              • $begingroup$
                Can you do it without the check that the line has a "/"?
                $endgroup$
                – xnor
                7 hours ago










              • $begingroup$
                @xnor Yup! -11 bytes
                $endgroup$
                – Maxwell
                7 hours ago










              • $begingroup$
                Save a couple like so: lambda x:1-all("|"in i for i in x[:-1])
                $endgroup$
                – Jonathan Allan
                7 hours ago






              • 1




                $begingroup$
                Ouch, you was faster :)
                $endgroup$
                – Daniil Tutubalin
                6 hours ago













              8












              8








              8





              $begingroup$

              Python 3, 41 bytes



              lambda x:any("|"not in i for i in x[:-1])


              A function that takes input as a list of strings, each string being a different line.



              -11 bytes thanks to xnor!



              Try it online! (If you want to try more test cases, just put a "." after each set of lines in the input box.)



              Takes advantage of the fact that if Jimmy is fully on the rope, no parts of the rope (no "|") will be showing. It checks if there are any lines that do not have "|", which means that Jimmy is fully on the rope.






              share|improve this answer










              New contributor



              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.





              $endgroup$



              Python 3, 41 bytes



              lambda x:any("|"not in i for i in x[:-1])


              A function that takes input as a list of strings, each string being a different line.



              -11 bytes thanks to xnor!



              Try it online! (If you want to try more test cases, just put a "." after each set of lines in the input box.)



              Takes advantage of the fact that if Jimmy is fully on the rope, no parts of the rope (no "|") will be showing. It checks if there are any lines that do not have "|", which means that Jimmy is fully on the rope.







              share|improve this answer










              New contributor



              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.








              share|improve this answer



              share|improve this answer








              edited 7 hours ago





















              New contributor



              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.








              answered 7 hours ago









              MaxwellMaxwell

              2714 bronze badges




              2714 bronze badges




              New contributor



              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.




              New contributor




              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.













              • $begingroup$
                Can you do it without the check that the line has a "/"?
                $endgroup$
                – xnor
                7 hours ago










              • $begingroup$
                @xnor Yup! -11 bytes
                $endgroup$
                – Maxwell
                7 hours ago










              • $begingroup$
                Save a couple like so: lambda x:1-all("|"in i for i in x[:-1])
                $endgroup$
                – Jonathan Allan
                7 hours ago






              • 1




                $begingroup$
                Ouch, you was faster :)
                $endgroup$
                – Daniil Tutubalin
                6 hours ago
















              • $begingroup$
                Can you do it without the check that the line has a "/"?
                $endgroup$
                – xnor
                7 hours ago










              • $begingroup$
                @xnor Yup! -11 bytes
                $endgroup$
                – Maxwell
                7 hours ago










              • $begingroup$
                Save a couple like so: lambda x:1-all("|"in i for i in x[:-1])
                $endgroup$
                – Jonathan Allan
                7 hours ago






              • 1




                $begingroup$
                Ouch, you was faster :)
                $endgroup$
                – Daniil Tutubalin
                6 hours ago















              $begingroup$
              Can you do it without the check that the line has a "/"?
              $endgroup$
              – xnor
              7 hours ago




              $begingroup$
              Can you do it without the check that the line has a "/"?
              $endgroup$
              – xnor
              7 hours ago












              $begingroup$
              @xnor Yup! -11 bytes
              $endgroup$
              – Maxwell
              7 hours ago




              $begingroup$
              @xnor Yup! -11 bytes
              $endgroup$
              – Maxwell
              7 hours ago












              $begingroup$
              Save a couple like so: lambda x:1-all("|"in i for i in x[:-1])
              $endgroup$
              – Jonathan Allan
              7 hours ago




              $begingroup$
              Save a couple like so: lambda x:1-all("|"in i for i in x[:-1])
              $endgroup$
              – Jonathan Allan
              7 hours ago




              1




              1




              $begingroup$
              Ouch, you was faster :)
              $endgroup$
              – Daniil Tutubalin
              6 hours ago




              $begingroup$
              Ouch, you was faster :)
              $endgroup$
              – Daniil Tutubalin
              6 hours ago













              6












              $begingroup$


              Python 2 or 3, 33 bytes





              lambda l:min(map(max,l[:-1]))<'|'


              An unnamed function accepting a list of lines



              Try it online!



              How?



              There needs to be a section of rope obscured by Jimmy that is not the bottom one.



              lambda l:min(map(max,l[:-1]))<'|'
              lambda l: - a function taking l (the lines as strings)
              l[:-1] - strip off the last line
              map(max, ) - maximum of each line (where '|'>'o'>''>'/'>' ')
              min( ) - minimum
              <'|' - is less than '|' (hence not rope since '|' is maximal)





              share|improve this answer











              $endgroup$

















                6












                $begingroup$


                Python 2 or 3, 33 bytes





                lambda l:min(map(max,l[:-1]))<'|'


                An unnamed function accepting a list of lines



                Try it online!



                How?



                There needs to be a section of rope obscured by Jimmy that is not the bottom one.



                lambda l:min(map(max,l[:-1]))<'|'
                lambda l: - a function taking l (the lines as strings)
                l[:-1] - strip off the last line
                map(max, ) - maximum of each line (where '|'>'o'>''>'/'>' ')
                min( ) - minimum
                <'|' - is less than '|' (hence not rope since '|' is maximal)





                share|improve this answer











                $endgroup$















                  6












                  6








                  6





                  $begingroup$


                  Python 2 or 3, 33 bytes





                  lambda l:min(map(max,l[:-1]))<'|'


                  An unnamed function accepting a list of lines



                  Try it online!



                  How?



                  There needs to be a section of rope obscured by Jimmy that is not the bottom one.



                  lambda l:min(map(max,l[:-1]))<'|'
                  lambda l: - a function taking l (the lines as strings)
                  l[:-1] - strip off the last line
                  map(max, ) - maximum of each line (where '|'>'o'>''>'/'>' ')
                  min( ) - minimum
                  <'|' - is less than '|' (hence not rope since '|' is maximal)





                  share|improve this answer











                  $endgroup$




                  Python 2 or 3, 33 bytes





                  lambda l:min(map(max,l[:-1]))<'|'


                  An unnamed function accepting a list of lines



                  Try it online!



                  How?



                  There needs to be a section of rope obscured by Jimmy that is not the bottom one.



                  lambda l:min(map(max,l[:-1]))<'|'
                  lambda l: - a function taking l (the lines as strings)
                  l[:-1] - strip off the last line
                  map(max, ) - maximum of each line (where '|'>'o'>''>'/'>' ')
                  min( ) - minimum
                  <'|' - is less than '|' (hence not rope since '|' is maximal)






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 6 hours ago

























                  answered 6 hours ago









                  Jonathan AllanJonathan Allan

                  56.7k5 gold badges41 silver badges178 bronze badges




                  56.7k5 gold badges41 silver badges178 bronze badges





















                      5












                      $begingroup$


                      Jelly,  9 7  6 bytes



                      Ṗ<”|ṀẠ


                      A monadic Link accepting a list of lines



                      Try it online!



                      How?



                      There needs to be a section of rope obscured by Jimmy that is not the bottom one.



                      Ṗ<”|ṀẠ - Main Link: list of lines of characters
                      Ṗ - remove last line
                      ”| - pipe character
                      < - less than? (vectorises) - Note that all other characters are
                      Ṁ - maximum
                      Ạ - all?





                      share|improve this answer











                      $endgroup$








                      • 1




                        $begingroup$
                        I feel so weird writing these challenges about Jimmies. It starts to make you feel weird once you imagine multiple Jimmies hanging off of the same rope.
                        $endgroup$
                        – connectyourcharger
                        8 hours ago






                      • 1




                        $begingroup$
                        @connectyourcharger Foreshadowing?
                        $endgroup$
                        – negative seven
                        8 hours ago










                      • $begingroup$
                        @negativeseven Possibly. I have already considered a meta community wiki to index all of the Jimmy posts.
                        $endgroup$
                        – connectyourcharger
                        8 hours ago






                      • 1




                        $begingroup$
                        Nine bytes, and once again, we still find out how someone can die.
                        $endgroup$
                        – IMustBeSomeone
                        7 hours ago










                      • $begingroup$
                        "Note that all other characters are [less than '|']"?
                        $endgroup$
                        – Erik the Outgolfer
                        5 hours ago















                      5












                      $begingroup$


                      Jelly,  9 7  6 bytes



                      Ṗ<”|ṀẠ


                      A monadic Link accepting a list of lines



                      Try it online!



                      How?



                      There needs to be a section of rope obscured by Jimmy that is not the bottom one.



                      Ṗ<”|ṀẠ - Main Link: list of lines of characters
                      Ṗ - remove last line
                      ”| - pipe character
                      < - less than? (vectorises) - Note that all other characters are
                      Ṁ - maximum
                      Ạ - all?





                      share|improve this answer











                      $endgroup$








                      • 1




                        $begingroup$
                        I feel so weird writing these challenges about Jimmies. It starts to make you feel weird once you imagine multiple Jimmies hanging off of the same rope.
                        $endgroup$
                        – connectyourcharger
                        8 hours ago






                      • 1




                        $begingroup$
                        @connectyourcharger Foreshadowing?
                        $endgroup$
                        – negative seven
                        8 hours ago










                      • $begingroup$
                        @negativeseven Possibly. I have already considered a meta community wiki to index all of the Jimmy posts.
                        $endgroup$
                        – connectyourcharger
                        8 hours ago






                      • 1




                        $begingroup$
                        Nine bytes, and once again, we still find out how someone can die.
                        $endgroup$
                        – IMustBeSomeone
                        7 hours ago










                      • $begingroup$
                        "Note that all other characters are [less than '|']"?
                        $endgroup$
                        – Erik the Outgolfer
                        5 hours ago













                      5












                      5








                      5





                      $begingroup$


                      Jelly,  9 7  6 bytes



                      Ṗ<”|ṀẠ


                      A monadic Link accepting a list of lines



                      Try it online!



                      How?



                      There needs to be a section of rope obscured by Jimmy that is not the bottom one.



                      Ṗ<”|ṀẠ - Main Link: list of lines of characters
                      Ṗ - remove last line
                      ”| - pipe character
                      < - less than? (vectorises) - Note that all other characters are
                      Ṁ - maximum
                      Ạ - all?





                      share|improve this answer











                      $endgroup$




                      Jelly,  9 7  6 bytes



                      Ṗ<”|ṀẠ


                      A monadic Link accepting a list of lines



                      Try it online!



                      How?



                      There needs to be a section of rope obscured by Jimmy that is not the bottom one.



                      Ṗ<”|ṀẠ - Main Link: list of lines of characters
                      Ṗ - remove last line
                      ”| - pipe character
                      < - less than? (vectorises) - Note that all other characters are
                      Ṁ - maximum
                      Ạ - all?






                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited 6 hours ago

























                      answered 8 hours ago









                      Jonathan AllanJonathan Allan

                      56.7k5 gold badges41 silver badges178 bronze badges




                      56.7k5 gold badges41 silver badges178 bronze badges







                      • 1




                        $begingroup$
                        I feel so weird writing these challenges about Jimmies. It starts to make you feel weird once you imagine multiple Jimmies hanging off of the same rope.
                        $endgroup$
                        – connectyourcharger
                        8 hours ago






                      • 1




                        $begingroup$
                        @connectyourcharger Foreshadowing?
                        $endgroup$
                        – negative seven
                        8 hours ago










                      • $begingroup$
                        @negativeseven Possibly. I have already considered a meta community wiki to index all of the Jimmy posts.
                        $endgroup$
                        – connectyourcharger
                        8 hours ago






                      • 1




                        $begingroup$
                        Nine bytes, and once again, we still find out how someone can die.
                        $endgroup$
                        – IMustBeSomeone
                        7 hours ago










                      • $begingroup$
                        "Note that all other characters are [less than '|']"?
                        $endgroup$
                        – Erik the Outgolfer
                        5 hours ago












                      • 1




                        $begingroup$
                        I feel so weird writing these challenges about Jimmies. It starts to make you feel weird once you imagine multiple Jimmies hanging off of the same rope.
                        $endgroup$
                        – connectyourcharger
                        8 hours ago






                      • 1




                        $begingroup$
                        @connectyourcharger Foreshadowing?
                        $endgroup$
                        – negative seven
                        8 hours ago










                      • $begingroup$
                        @negativeseven Possibly. I have already considered a meta community wiki to index all of the Jimmy posts.
                        $endgroup$
                        – connectyourcharger
                        8 hours ago






                      • 1




                        $begingroup$
                        Nine bytes, and once again, we still find out how someone can die.
                        $endgroup$
                        – IMustBeSomeone
                        7 hours ago










                      • $begingroup$
                        "Note that all other characters are [less than '|']"?
                        $endgroup$
                        – Erik the Outgolfer
                        5 hours ago







                      1




                      1




                      $begingroup$
                      I feel so weird writing these challenges about Jimmies. It starts to make you feel weird once you imagine multiple Jimmies hanging off of the same rope.
                      $endgroup$
                      – connectyourcharger
                      8 hours ago




                      $begingroup$
                      I feel so weird writing these challenges about Jimmies. It starts to make you feel weird once you imagine multiple Jimmies hanging off of the same rope.
                      $endgroup$
                      – connectyourcharger
                      8 hours ago




                      1




                      1




                      $begingroup$
                      @connectyourcharger Foreshadowing?
                      $endgroup$
                      – negative seven
                      8 hours ago




                      $begingroup$
                      @connectyourcharger Foreshadowing?
                      $endgroup$
                      – negative seven
                      8 hours ago












                      $begingroup$
                      @negativeseven Possibly. I have already considered a meta community wiki to index all of the Jimmy posts.
                      $endgroup$
                      – connectyourcharger
                      8 hours ago




                      $begingroup$
                      @negativeseven Possibly. I have already considered a meta community wiki to index all of the Jimmy posts.
                      $endgroup$
                      – connectyourcharger
                      8 hours ago




                      1




                      1




                      $begingroup$
                      Nine bytes, and once again, we still find out how someone can die.
                      $endgroup$
                      – IMustBeSomeone
                      7 hours ago




                      $begingroup$
                      Nine bytes, and once again, we still find out how someone can die.
                      $endgroup$
                      – IMustBeSomeone
                      7 hours ago












                      $begingroup$
                      "Note that all other characters are [less than '|']"?
                      $endgroup$
                      – Erik the Outgolfer
                      5 hours ago




                      $begingroup$
                      "Note that all other characters are [less than '|']"?
                      $endgroup$
                      – Erik the Outgolfer
                      5 hours ago











                      2












                      $begingroup$

                      JavaScript, 39 33 bytes



                      Thanks @Daniil Tutubalin for golfing off 2 bytes





                      x=>!!x.match(/^( *)/[^|]*n/m)


                      This matches any line which is not the line where his left arm shows up and none of the rope shows.



                      Try it online!






                      share|improve this answer











                      $endgroup$












                      • $begingroup$
                        It appears to fail if he is at the bottom of the rope
                        $endgroup$
                        – fəˈnɛtɪk
                        7 hours ago










                      • $begingroup$
                        It should fail if he is at the bottom, right? Because Jimmy falls if he is at the bottom fo the rope
                        $endgroup$
                        – Maxwell
                        7 hours ago










                      • $begingroup$
                        I mean that when I put him at the bottom of the rope your function for some reason returned 1
                        $endgroup$
                        – fəˈnɛtɪk
                        6 hours ago










                      • $begingroup$
                        Hm, nevermind then.
                        $endgroup$
                        – Maxwell
                        6 hours ago










                      • $begingroup$
                        Minus 2 bytes: x=>!!x.match(/^( *)/o\ *n1 ?|/m) But basically !! is not required because valid object is truthy value and null is falsy value, so you can make even minus 4.
                        $endgroup$
                        – Daniil Tutubalin
                        3 hours ago
















                      2












                      $begingroup$

                      JavaScript, 39 33 bytes



                      Thanks @Daniil Tutubalin for golfing off 2 bytes





                      x=>!!x.match(/^( *)/[^|]*n/m)


                      This matches any line which is not the line where his left arm shows up and none of the rope shows.



                      Try it online!






                      share|improve this answer











                      $endgroup$












                      • $begingroup$
                        It appears to fail if he is at the bottom of the rope
                        $endgroup$
                        – fəˈnɛtɪk
                        7 hours ago










                      • $begingroup$
                        It should fail if he is at the bottom, right? Because Jimmy falls if he is at the bottom fo the rope
                        $endgroup$
                        – Maxwell
                        7 hours ago










                      • $begingroup$
                        I mean that when I put him at the bottom of the rope your function for some reason returned 1
                        $endgroup$
                        – fəˈnɛtɪk
                        6 hours ago










                      • $begingroup$
                        Hm, nevermind then.
                        $endgroup$
                        – Maxwell
                        6 hours ago










                      • $begingroup$
                        Minus 2 bytes: x=>!!x.match(/^( *)/o\ *n1 ?|/m) But basically !! is not required because valid object is truthy value and null is falsy value, so you can make even minus 4.
                        $endgroup$
                        – Daniil Tutubalin
                        3 hours ago














                      2












                      2








                      2





                      $begingroup$

                      JavaScript, 39 33 bytes



                      Thanks @Daniil Tutubalin for golfing off 2 bytes





                      x=>!!x.match(/^( *)/[^|]*n/m)


                      This matches any line which is not the line where his left arm shows up and none of the rope shows.



                      Try it online!






                      share|improve this answer











                      $endgroup$



                      JavaScript, 39 33 bytes



                      Thanks @Daniil Tutubalin for golfing off 2 bytes





                      x=>!!x.match(/^( *)/[^|]*n/m)


                      This matches any line which is not the line where his left arm shows up and none of the rope shows.



                      Try it online!







                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited 1 hour ago

























                      answered 7 hours ago









                      fəˈnɛtɪkfəˈnɛtɪk

                      3,7062 gold badges6 silver badges37 bronze badges




                      3,7062 gold badges6 silver badges37 bronze badges











                      • $begingroup$
                        It appears to fail if he is at the bottom of the rope
                        $endgroup$
                        – fəˈnɛtɪk
                        7 hours ago










                      • $begingroup$
                        It should fail if he is at the bottom, right? Because Jimmy falls if he is at the bottom fo the rope
                        $endgroup$
                        – Maxwell
                        7 hours ago










                      • $begingroup$
                        I mean that when I put him at the bottom of the rope your function for some reason returned 1
                        $endgroup$
                        – fəˈnɛtɪk
                        6 hours ago










                      • $begingroup$
                        Hm, nevermind then.
                        $endgroup$
                        – Maxwell
                        6 hours ago










                      • $begingroup$
                        Minus 2 bytes: x=>!!x.match(/^( *)/o\ *n1 ?|/m) But basically !! is not required because valid object is truthy value and null is falsy value, so you can make even minus 4.
                        $endgroup$
                        – Daniil Tutubalin
                        3 hours ago

















                      • $begingroup$
                        It appears to fail if he is at the bottom of the rope
                        $endgroup$
                        – fəˈnɛtɪk
                        7 hours ago










                      • $begingroup$
                        It should fail if he is at the bottom, right? Because Jimmy falls if he is at the bottom fo the rope
                        $endgroup$
                        – Maxwell
                        7 hours ago










                      • $begingroup$
                        I mean that when I put him at the bottom of the rope your function for some reason returned 1
                        $endgroup$
                        – fəˈnɛtɪk
                        6 hours ago










                      • $begingroup$
                        Hm, nevermind then.
                        $endgroup$
                        – Maxwell
                        6 hours ago










                      • $begingroup$
                        Minus 2 bytes: x=>!!x.match(/^( *)/o\ *n1 ?|/m) But basically !! is not required because valid object is truthy value and null is falsy value, so you can make even minus 4.
                        $endgroup$
                        – Daniil Tutubalin
                        3 hours ago
















                      $begingroup$
                      It appears to fail if he is at the bottom of the rope
                      $endgroup$
                      – fəˈnɛtɪk
                      7 hours ago




                      $begingroup$
                      It appears to fail if he is at the bottom of the rope
                      $endgroup$
                      – fəˈnɛtɪk
                      7 hours ago












                      $begingroup$
                      It should fail if he is at the bottom, right? Because Jimmy falls if he is at the bottom fo the rope
                      $endgroup$
                      – Maxwell
                      7 hours ago




                      $begingroup$
                      It should fail if he is at the bottom, right? Because Jimmy falls if he is at the bottom fo the rope
                      $endgroup$
                      – Maxwell
                      7 hours ago












                      $begingroup$
                      I mean that when I put him at the bottom of the rope your function for some reason returned 1
                      $endgroup$
                      – fəˈnɛtɪk
                      6 hours ago




                      $begingroup$
                      I mean that when I put him at the bottom of the rope your function for some reason returned 1
                      $endgroup$
                      – fəˈnɛtɪk
                      6 hours ago












                      $begingroup$
                      Hm, nevermind then.
                      $endgroup$
                      – Maxwell
                      6 hours ago




                      $begingroup$
                      Hm, nevermind then.
                      $endgroup$
                      – Maxwell
                      6 hours ago












                      $begingroup$
                      Minus 2 bytes: x=>!!x.match(/^( *)/o\ *n1 ?|/m) But basically !! is not required because valid object is truthy value and null is falsy value, so you can make even minus 4.
                      $endgroup$
                      – Daniil Tutubalin
                      3 hours ago





                      $begingroup$
                      Minus 2 bytes: x=>!!x.match(/^( *)/o\ *n1 ?|/m) But basically !! is not required because valid object is truthy value and null is falsy value, so you can make even minus 4.
                      $endgroup$
                      – Daniil Tutubalin
                      3 hours ago












                      1












                      $begingroup$

                      JavaScript, 38 37 bytes





                      r=>r.some(x=>!~x.search`\|`,r.pop())


                      Try it online!






                      share|improve this answer











                      $endgroup$

















                        1












                        $begingroup$

                        JavaScript, 38 37 bytes





                        r=>r.some(x=>!~x.search`\|`,r.pop())


                        Try it online!






                        share|improve this answer











                        $endgroup$















                          1












                          1








                          1





                          $begingroup$

                          JavaScript, 38 37 bytes





                          r=>r.some(x=>!~x.search`\|`,r.pop())


                          Try it online!






                          share|improve this answer











                          $endgroup$



                          JavaScript, 38 37 bytes





                          r=>r.some(x=>!~x.search`\|`,r.pop())


                          Try it online!







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited 6 hours ago

























                          answered 6 hours ago









                          Daniil TutubalinDaniil Tutubalin

                          1827 bronze badges




                          1827 bronze badges





















                              1












                              $begingroup$


                              Befunge-98 (PyFunge), 26 bytes



                              >#@~:a-!#v_' `+
                              ^ 0_-3q#$<


                              Try it online!



                              Exits with return code 3 if n is encountered and the last line contained 3 non-space characters, otherwise exits with return code 0 on EOF. Thus, this relies on the last line not containing a trailing newline.



                              Dissected



                              >#@~ :a-!#v_ ' `+
                              Read character, Branch downwards if Increment counter on
                              return with code 0 equal to 10 ('n') the stack if greater
                              if end of stream than 32 (' ') and
                              implicitly loop

                              ^ 0_-3q#$ <
                              Return with code 3
                              if counter is equal to 3,
                              otherwise reset counter
                              and return to beginning





                              share|improve this answer









                              $endgroup$

















                                1












                                $begingroup$


                                Befunge-98 (PyFunge), 26 bytes



                                >#@~:a-!#v_' `+
                                ^ 0_-3q#$<


                                Try it online!



                                Exits with return code 3 if n is encountered and the last line contained 3 non-space characters, otherwise exits with return code 0 on EOF. Thus, this relies on the last line not containing a trailing newline.



                                Dissected



                                >#@~ :a-!#v_ ' `+
                                Read character, Branch downwards if Increment counter on
                                return with code 0 equal to 10 ('n') the stack if greater
                                if end of stream than 32 (' ') and
                                implicitly loop

                                ^ 0_-3q#$ <
                                Return with code 3
                                if counter is equal to 3,
                                otherwise reset counter
                                and return to beginning





                                share|improve this answer









                                $endgroup$















                                  1












                                  1








                                  1





                                  $begingroup$


                                  Befunge-98 (PyFunge), 26 bytes



                                  >#@~:a-!#v_' `+
                                  ^ 0_-3q#$<


                                  Try it online!



                                  Exits with return code 3 if n is encountered and the last line contained 3 non-space characters, otherwise exits with return code 0 on EOF. Thus, this relies on the last line not containing a trailing newline.



                                  Dissected



                                  >#@~ :a-!#v_ ' `+
                                  Read character, Branch downwards if Increment counter on
                                  return with code 0 equal to 10 ('n') the stack if greater
                                  if end of stream than 32 (' ') and
                                  implicitly loop

                                  ^ 0_-3q#$ <
                                  Return with code 3
                                  if counter is equal to 3,
                                  otherwise reset counter
                                  and return to beginning





                                  share|improve this answer









                                  $endgroup$




                                  Befunge-98 (PyFunge), 26 bytes



                                  >#@~:a-!#v_' `+
                                  ^ 0_-3q#$<


                                  Try it online!



                                  Exits with return code 3 if n is encountered and the last line contained 3 non-space characters, otherwise exits with return code 0 on EOF. Thus, this relies on the last line not containing a trailing newline.



                                  Dissected



                                  >#@~ :a-!#v_ ' `+
                                  Read character, Branch downwards if Increment counter on
                                  return with code 0 equal to 10 ('n') the stack if greater
                                  if end of stream than 32 (' ') and
                                  implicitly loop

                                  ^ 0_-3q#$ <
                                  Return with code 3
                                  if counter is equal to 3,
                                  otherwise reset counter
                                  and return to beginning






                                  share|improve this answer












                                  share|improve this answer



                                  share|improve this answer










                                  answered 6 hours ago









                                  negative sevennegative seven

                                  5812 silver badges8 bronze badges




                                  5812 silver badges8 bronze badges





















                                      0












                                      $begingroup$


                                      Pyth, 9 bytes



                                      sPm!sqR|


                                      Test suite!






                                      share|improve this answer









                                      $endgroup$

















                                        0












                                        $begingroup$


                                        Pyth, 9 bytes



                                        sPm!sqR|


                                        Test suite!






                                        share|improve this answer









                                        $endgroup$















                                          0












                                          0








                                          0





                                          $begingroup$


                                          Pyth, 9 bytes



                                          sPm!sqR|


                                          Test suite!






                                          share|improve this answer









                                          $endgroup$




                                          Pyth, 9 bytes



                                          sPm!sqR|


                                          Test suite!







                                          share|improve this answer












                                          share|improve this answer



                                          share|improve this answer










                                          answered 6 hours ago









                                          Mr. XcoderMr. Xcoder

                                          32.6k7 gold badges61 silver badges202 bronze badges




                                          32.6k7 gold badges61 silver badges202 bronze badges





















                                              0












                                              $begingroup$


                                              Retina, 9 bytes



                                              m`^[^|]+^


                                              Try it online!



                                              Now, I've never programmed in Retina before, but as far as I can tell this works. It is a regular expression that finds a string containing (1) the beginning of the input, (2) no "|" characters, and (3) a newline.



                                              People more familiar with either regular expressions or Retina are encouraged to offer suggestions. -2 bytes thanks to Neil!






                                              share|improve this answer










                                              New contributor



                                              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                              Check out our Code of Conduct.





                                              $endgroup$












                                              • $begingroup$
                                                Two alternatives: 1) Remove the n because a new line is not a | and so that will match anyway, and the final ^ suffices to ensure that you actually matched a newline. 2) Use a pilcrow instead of n and remove the trailing ^ (because that's always true after a newline in multiline mode).
                                                $endgroup$
                                                – Neil
                                                6 hours ago















                                              0












                                              $begingroup$


                                              Retina, 9 bytes



                                              m`^[^|]+^


                                              Try it online!



                                              Now, I've never programmed in Retina before, but as far as I can tell this works. It is a regular expression that finds a string containing (1) the beginning of the input, (2) no "|" characters, and (3) a newline.



                                              People more familiar with either regular expressions or Retina are encouraged to offer suggestions. -2 bytes thanks to Neil!






                                              share|improve this answer










                                              New contributor



                                              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                              Check out our Code of Conduct.





                                              $endgroup$












                                              • $begingroup$
                                                Two alternatives: 1) Remove the n because a new line is not a | and so that will match anyway, and the final ^ suffices to ensure that you actually matched a newline. 2) Use a pilcrow instead of n and remove the trailing ^ (because that's always true after a newline in multiline mode).
                                                $endgroup$
                                                – Neil
                                                6 hours ago













                                              0












                                              0








                                              0





                                              $begingroup$


                                              Retina, 9 bytes



                                              m`^[^|]+^


                                              Try it online!



                                              Now, I've never programmed in Retina before, but as far as I can tell this works. It is a regular expression that finds a string containing (1) the beginning of the input, (2) no "|" characters, and (3) a newline.



                                              People more familiar with either regular expressions or Retina are encouraged to offer suggestions. -2 bytes thanks to Neil!






                                              share|improve this answer










                                              New contributor



                                              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                              Check out our Code of Conduct.





                                              $endgroup$




                                              Retina, 9 bytes



                                              m`^[^|]+^


                                              Try it online!



                                              Now, I've never programmed in Retina before, but as far as I can tell this works. It is a regular expression that finds a string containing (1) the beginning of the input, (2) no "|" characters, and (3) a newline.



                                              People more familiar with either regular expressions or Retina are encouraged to offer suggestions. -2 bytes thanks to Neil!







                                              share|improve this answer










                                              New contributor



                                              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                              Check out our Code of Conduct.








                                              share|improve this answer



                                              share|improve this answer








                                              edited 6 hours ago





















                                              New contributor



                                              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                              Check out our Code of Conduct.








                                              answered 6 hours ago









                                              MaxwellMaxwell

                                              2714 bronze badges




                                              2714 bronze badges




                                              New contributor



                                              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                              Check out our Code of Conduct.




                                              New contributor




                                              Maxwell is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                              Check out our Code of Conduct.













                                              • $begingroup$
                                                Two alternatives: 1) Remove the n because a new line is not a | and so that will match anyway, and the final ^ suffices to ensure that you actually matched a newline. 2) Use a pilcrow instead of n and remove the trailing ^ (because that's always true after a newline in multiline mode).
                                                $endgroup$
                                                – Neil
                                                6 hours ago
















                                              • $begingroup$
                                                Two alternatives: 1) Remove the n because a new line is not a | and so that will match anyway, and the final ^ suffices to ensure that you actually matched a newline. 2) Use a pilcrow instead of n and remove the trailing ^ (because that's always true after a newline in multiline mode).
                                                $endgroup$
                                                – Neil
                                                6 hours ago















                                              $begingroup$
                                              Two alternatives: 1) Remove the n because a new line is not a | and so that will match anyway, and the final ^ suffices to ensure that you actually matched a newline. 2) Use a pilcrow instead of n and remove the trailing ^ (because that's always true after a newline in multiline mode).
                                              $endgroup$
                                              – Neil
                                              6 hours ago




                                              $begingroup$
                                              Two alternatives: 1) Remove the n because a new line is not a | and so that will match anyway, and the final ^ suffices to ensure that you actually matched a newline. 2) Use a pilcrow instead of n and remove the trailing ^ (because that's always true after a newline in multiline mode).
                                              $endgroup$
                                              – Neil
                                              6 hours ago











                                              0












                                              $begingroup$

                                              Dyalog APL Extended, 14 13 11 bytes





                                              3∊+/<¯1↓⍵


                                              Try it online!






                                              share|improve this answer











                                              $endgroup$

















                                                0












                                                $begingroup$

                                                Dyalog APL Extended, 14 13 11 bytes





                                                3∊+/<¯1↓⍵


                                                Try it online!






                                                share|improve this answer











                                                $endgroup$















                                                  0












                                                  0








                                                  0





                                                  $begingroup$

                                                  Dyalog APL Extended, 14 13 11 bytes





                                                  3∊+/<¯1↓⍵


                                                  Try it online!






                                                  share|improve this answer











                                                  $endgroup$



                                                  Dyalog APL Extended, 14 13 11 bytes





                                                  3∊+/<¯1↓⍵


                                                  Try it online!







                                                  share|improve this answer














                                                  share|improve this answer



                                                  share|improve this answer








                                                  edited 4 hours ago

























                                                  answered 4 hours ago









                                                  dzaimadzaima

                                                  16.9k2 gold badges26 silver badges64 bronze badges




                                                  16.9k2 gold badges26 silver badges64 bronze badges





















                                                      0












                                                      $begingroup$


                                                      Stax, 6 bytes



                                                      é¿┤4╠q


                                                      Run and debug it



                                                      Transposes the input, then searches for "o|".






                                                      share|improve this answer









                                                      $endgroup$

















                                                        0












                                                        $begingroup$


                                                        Stax, 6 bytes



                                                        é¿┤4╠q


                                                        Run and debug it



                                                        Transposes the input, then searches for "o|".






                                                        share|improve this answer









                                                        $endgroup$















                                                          0












                                                          0








                                                          0





                                                          $begingroup$


                                                          Stax, 6 bytes



                                                          é¿┤4╠q


                                                          Run and debug it



                                                          Transposes the input, then searches for "o|".






                                                          share|improve this answer









                                                          $endgroup$




                                                          Stax, 6 bytes



                                                          é¿┤4╠q


                                                          Run and debug it



                                                          Transposes the input, then searches for "o|".







                                                          share|improve this answer












                                                          share|improve this answer



                                                          share|improve this answer










                                                          answered 2 hours ago









                                                          recursiverecursive

                                                          6,93914 silver badges27 bronze badges




                                                          6,93914 silver badges27 bronze badges



























                                                              draft saved

                                                              draft discarded
















































                                                              If this is an answer to a challenge…



                                                              • …Be sure to follow the challenge specification. However, please refrain from exploiting obvious loopholes. Answers abusing any of the standard loopholes are considered invalid. If you think a specification is unclear or underspecified, comment on the question instead.


                                                              • …Try to optimize your score. For instance, answers to code-golf challenges should attempt to be as short as possible. You can always include a readable version of the code in addition to the competitive one.
                                                                Explanations of your answer make it more interesting to read and are very much encouraged.


                                                              • …Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.


                                                              More generally…



                                                              • …Please make sure to answer the question and provide sufficient detail.


                                                              • …Avoid asking for help, clarification or responding to other answers (use comments instead).




                                                              draft saved


                                                              draft discarded














                                                              StackExchange.ready(
                                                              function ()
                                                              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodegolf.stackexchange.com%2fquestions%2f187759%2fcan-jimmy-hang-on-his-rope%23new-answer', 'question_page');

                                                              );

                                                              Post as a guest















                                                              Required, but never shown





















































                                                              Required, but never shown














                                                              Required, but never shown












                                                              Required, but never shown







                                                              Required, but never shown

































                                                              Required, but never shown














                                                              Required, but never shown












                                                              Required, but never shown







                                                              Required, but never shown







                                                              Popular posts from this blog

                                                              Invision Community Contents History See also References External links Navigation menuProprietaryinvisioncommunity.comIPS Community ForumsIPS Community Forumsthis blog entry"License Changes, IP.Board 3.4, and the Future""Interview -- Matt Mecham of Ibforums""CEO Invision Power Board, Matt Mecham Is a Liar, Thief!"IPB License Explanation 1.3, 1.3.1, 2.0, and 2.1ArchivedSecurity Fixes, Updates And Enhancements For IPB 1.3.1Archived"New Demo Accounts - Invision Power Services"the original"New Default Skin"the original"Invision Power Board 3.0.0 and Applications Released"the original"Archived copy"the original"Perpetual licenses being done away with""Release Notes - Invision Power Services""Introducing: IPS Community Suite 4!"Invision Community Release Notes

                                                              Canceling a color specificationRandomly assigning color to Graphics3D objects?Default color for Filling in Mathematica 9Coloring specific elements of sets with a prime modified order in an array plotHow to pick a color differing significantly from the colors already in a given color list?Detection of the text colorColor numbers based on their valueCan color schemes for use with ColorData include opacity specification?My dynamic color schemes

                                                              Ласкавець круглолистий Зміст Опис | Поширення | Галерея | Примітки | Посилання | Навігаційне меню58171138361-22960890446Bupleurum rotundifoliumEuro+Med PlantbasePlants of the World Online — Kew ScienceGermplasm Resources Information Network (GRIN)Ласкавецькн. VI : Літери Ком — Левиправивши або дописавши її