Alignment problem with a mathematical equation in a presentation in beamerProblem with alignment in listingsbeamer presentation with enumerated list problemBeamer equation problem settingBeamer presentationBeamer presentation: Problem with captionsAlignment problem with textbfUsing printeranswers environment, how to print solutions in the box without the title “Solutions”Problem with display of presentationAlignment problem in BeamerAlignment Problem in Beamer for Maths code
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Alignment problem with a mathematical equation in a presentation in beamer
Problem with alignment in listingsbeamer presentation with enumerated list problemBeamer equation problem settingBeamer presentationBeamer presentation: Problem with captionsAlignment problem with textbfUsing printeranswers environment, how to print solutions in the box without the title “Solutions”Problem with display of presentationAlignment problem in BeamerAlignment Problem in Beamer for Maths code
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
documentclassbeamer
newcommandFontvifontsize24selectfont
usepackage[utf8]inputenc
usepackage[compat=1.1.0]tikz-feynman
usepackageamsmath, amsthm, amssymb,amsfonts
usepackagegraphicx
usepackagetikz
usepackagetcolorbox
usepackageamsmath
usepackageamsthm
usepackageamssymb
usepackagetikz-feynman
setcounterMaxMatrixCols20
%usepackagebreqn
usepackagetikz-feynman
usepackageamsmath
newtheoremrulesRule
usethemeAntibes
usecolortheme
titleNegative Dimensional Integral and Modified Method of Brackets
author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
instituteIndian Institute of Science\Bangalore- 560012
date
begin document
begin frame
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + cdots + A_J)^alpha
\
&quad=
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,
<z_1 + cdots + z_J - alpha>
,
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J),.
endsplit
endequation
endrules
end frame
end document
beamer math-mode horizontal-alignment
add a comment |
documentclassbeamer
newcommandFontvifontsize24selectfont
usepackage[utf8]inputenc
usepackage[compat=1.1.0]tikz-feynman
usepackageamsmath, amsthm, amssymb,amsfonts
usepackagegraphicx
usepackagetikz
usepackagetcolorbox
usepackageamsmath
usepackageamsthm
usepackageamssymb
usepackagetikz-feynman
setcounterMaxMatrixCols20
%usepackagebreqn
usepackagetikz-feynman
usepackageamsmath
newtheoremrulesRule
usethemeAntibes
usecolortheme
titleNegative Dimensional Integral and Modified Method of Brackets
author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
instituteIndian Institute of Science\Bangalore- 560012
date
begin document
begin frame
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + cdots + A_J)^alpha
\
&quad=
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,
<z_1 + cdots + z_J - alpha>
,
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J),.
endsplit
endequation
endrules
end frame
end document
beamer math-mode horizontal-alignment
add a comment |
documentclassbeamer
newcommandFontvifontsize24selectfont
usepackage[utf8]inputenc
usepackage[compat=1.1.0]tikz-feynman
usepackageamsmath, amsthm, amssymb,amsfonts
usepackagegraphicx
usepackagetikz
usepackagetcolorbox
usepackageamsmath
usepackageamsthm
usepackageamssymb
usepackagetikz-feynman
setcounterMaxMatrixCols20
%usepackagebreqn
usepackagetikz-feynman
usepackageamsmath
newtheoremrulesRule
usethemeAntibes
usecolortheme
titleNegative Dimensional Integral and Modified Method of Brackets
author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
instituteIndian Institute of Science\Bangalore- 560012
date
begin document
begin frame
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + cdots + A_J)^alpha
\
&quad=
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,
<z_1 + cdots + z_J - alpha>
,
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J),.
endsplit
endequation
endrules
end frame
end document
beamer math-mode horizontal-alignment
documentclassbeamer
newcommandFontvifontsize24selectfont
usepackage[utf8]inputenc
usepackage[compat=1.1.0]tikz-feynman
usepackageamsmath, amsthm, amssymb,amsfonts
usepackagegraphicx
usepackagetikz
usepackagetcolorbox
usepackageamsmath
usepackageamsthm
usepackageamssymb
usepackagetikz-feynman
setcounterMaxMatrixCols20
%usepackagebreqn
usepackagetikz-feynman
usepackageamsmath
newtheoremrulesRule
usethemeAntibes
usecolortheme
titleNegative Dimensional Integral and Modified Method of Brackets
author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
instituteIndian Institute of Science\Bangalore- 560012
date
begin document
begin frame
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + cdots + A_J)^alpha
\
&quad=
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,
<z_1 + cdots + z_J - alpha>
,
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J),.
endsplit
endequation
endrules
end frame
end document
beamer math-mode horizontal-alignment
beamer math-mode horizontal-alignment
edited 8 hours ago
CarLaTeX
37.1k5 gold badges60 silver badges164 bronze badges
37.1k5 gold badges60 silver badges164 bronze badges
asked 8 hours ago
Sumit BanikSumit Banik
466 bronze badges
466 bronze badges
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
I would go for a multline
environment. Unrelated: don't load packages twice, and also, if you load amssymb
, needless to load amsfonts
.
documentclassbeamer
newcommandFontvifontsize24selectfont
usepackage[utf8]inputenc
usepackage[compat=1.1.0]tikz-feynman
usepackagemathtools, amsthm, amssymb
usepackagegraphicx
usepackagetikz
usepackagetcolorbox
usepackagetikz-feynman
setcounterMaxMatrixCols20
usepackagetikz-feynman
newtheoremrulesRule
usethemeAntibes
usecolortheme
titleNegative Dimensional Integral and Modified Method of Brackets
author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
instituteIndian Institute of Science\Bangalore- 560012
date
begin document
begin frame
beginrules labelRule2
beginmultlinelabeleq:rule-B
(A_1 + cdots + A_J)^alpha =
\
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,
langle z_1 + cdots + z_J - alpharangle times \
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J)phantomtimes
endmultline
endrules
end frame
end document
I was wondering whether the<...>...
stuff contained a mistake. I see you've re-imagined it aslangle ... rangle ...
. Neat!
– Mico
7 hours ago
add a comment |
I think the equation could benefit from a couple of additional line breaks.
documentclassbeamer
usethemeAntibes
usepackageamsmath, amsthm, amssymb%,amsfonts}
newtheoremrulesRule
usepackagegraphicx
usepackage[utf8]inputenc
%% I've commented out all instructions that are repetitive or
%% do not affect the body of the sample document.
%newcommandFontvifontsize24selectfont
%usepackage[compat=1.1.0]tikz-feynman
%usepackagetikz
%usepackagetcolorbox
%usepackageamsmath
%usepackageamsthm
%usepackageamssymb
%usepackagetikz-feynman
%setcounterMaxMatrixCols20
%usepackagebreqn
%usepackagetikz-feynman
%usepackageamsmath
%usecolortheme
%titleNegative Dimensional Integral and Modified Method of Brackets
%author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
%instituteIndian Institute of Science\Bangalore- 560012
%date
begindocument
beginframe
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + dots + A_J)^alpha \
&quad= frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
dotsm
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
\
&quad< z_1 + dots + z_J - alpha\
&quad> A_1^z_1dotsm A_J^z_J
,Gamma(-z_1)dotsmGamma(-z_J),.
endsplit
endequation
endrules
endframe
enddocument
Addendum, inspired by a detail in @Bernard's parallel answer: If <
and >
do not denote "less than" and "greater than" and, instead, are supposed to be interpreted as angle brackets (langle
and rangle
, respectively, in TeX parlance), it would be better to combine rows three and four of the answer shown above into a single line:
documentclassbeamer
usethemeAntibes
usepackageamsmath, amsthm, amssymb
newtheoremrulesRule
usepackagegraphicx
usepackage[utf8]inputenc
begindocument
beginframe
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + dots + A_J)^alpha \
&quad= frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
dotsm
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i \
&qquadtimes
langle z_1 + dots + z_J - alpharangle
,A_1^z_1dotsm A_J^z_J
,Gamma(-z_1)dotsmGamma(-z_J),.
endsplit
endequation
endrules
endframe
enddocument
add a comment |
You should split your equation. Please Consider the following code:
documentclassbeamer
usepackage[compat=1.1.0]tikz-feynman
usepackageamsmath, amsthm, amssymb,amsfonts
usepackagetikz
newtheoremrulesRule
usethemeAntibes
begin document
begin frame
beginrules labelRule2
beginalign labeleq:rule-B
&(A_1 + cdots + A_J)^alpha
nonumber\
quad=&
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,nonumber\
&<z_1 + cdots + z_J - alpha>
,
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J),.
endalign
endrules
end frame
end document
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
I would go for a multline
environment. Unrelated: don't load packages twice, and also, if you load amssymb
, needless to load amsfonts
.
documentclassbeamer
newcommandFontvifontsize24selectfont
usepackage[utf8]inputenc
usepackage[compat=1.1.0]tikz-feynman
usepackagemathtools, amsthm, amssymb
usepackagegraphicx
usepackagetikz
usepackagetcolorbox
usepackagetikz-feynman
setcounterMaxMatrixCols20
usepackagetikz-feynman
newtheoremrulesRule
usethemeAntibes
usecolortheme
titleNegative Dimensional Integral and Modified Method of Brackets
author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
instituteIndian Institute of Science\Bangalore- 560012
date
begin document
begin frame
beginrules labelRule2
beginmultlinelabeleq:rule-B
(A_1 + cdots + A_J)^alpha =
\
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,
langle z_1 + cdots + z_J - alpharangle times \
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J)phantomtimes
endmultline
endrules
end frame
end document
I was wondering whether the<...>...
stuff contained a mistake. I see you've re-imagined it aslangle ... rangle ...
. Neat!
– Mico
7 hours ago
add a comment |
I would go for a multline
environment. Unrelated: don't load packages twice, and also, if you load amssymb
, needless to load amsfonts
.
documentclassbeamer
newcommandFontvifontsize24selectfont
usepackage[utf8]inputenc
usepackage[compat=1.1.0]tikz-feynman
usepackagemathtools, amsthm, amssymb
usepackagegraphicx
usepackagetikz
usepackagetcolorbox
usepackagetikz-feynman
setcounterMaxMatrixCols20
usepackagetikz-feynman
newtheoremrulesRule
usethemeAntibes
usecolortheme
titleNegative Dimensional Integral and Modified Method of Brackets
author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
instituteIndian Institute of Science\Bangalore- 560012
date
begin document
begin frame
beginrules labelRule2
beginmultlinelabeleq:rule-B
(A_1 + cdots + A_J)^alpha =
\
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,
langle z_1 + cdots + z_J - alpharangle times \
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J)phantomtimes
endmultline
endrules
end frame
end document
I was wondering whether the<...>...
stuff contained a mistake. I see you've re-imagined it aslangle ... rangle ...
. Neat!
– Mico
7 hours ago
add a comment |
I would go for a multline
environment. Unrelated: don't load packages twice, and also, if you load amssymb
, needless to load amsfonts
.
documentclassbeamer
newcommandFontvifontsize24selectfont
usepackage[utf8]inputenc
usepackage[compat=1.1.0]tikz-feynman
usepackagemathtools, amsthm, amssymb
usepackagegraphicx
usepackagetikz
usepackagetcolorbox
usepackagetikz-feynman
setcounterMaxMatrixCols20
usepackagetikz-feynman
newtheoremrulesRule
usethemeAntibes
usecolortheme
titleNegative Dimensional Integral and Modified Method of Brackets
author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
instituteIndian Institute of Science\Bangalore- 560012
date
begin document
begin frame
beginrules labelRule2
beginmultlinelabeleq:rule-B
(A_1 + cdots + A_J)^alpha =
\
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,
langle z_1 + cdots + z_J - alpharangle times \
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J)phantomtimes
endmultline
endrules
end frame
end document
I would go for a multline
environment. Unrelated: don't load packages twice, and also, if you load amssymb
, needless to load amsfonts
.
documentclassbeamer
newcommandFontvifontsize24selectfont
usepackage[utf8]inputenc
usepackage[compat=1.1.0]tikz-feynman
usepackagemathtools, amsthm, amssymb
usepackagegraphicx
usepackagetikz
usepackagetcolorbox
usepackagetikz-feynman
setcounterMaxMatrixCols20
usepackagetikz-feynman
newtheoremrulesRule
usethemeAntibes
usecolortheme
titleNegative Dimensional Integral and Modified Method of Brackets
author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
instituteIndian Institute of Science\Bangalore- 560012
date
begin document
begin frame
beginrules labelRule2
beginmultlinelabeleq:rule-B
(A_1 + cdots + A_J)^alpha =
\
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,
langle z_1 + cdots + z_J - alpharangle times \
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J)phantomtimes
endmultline
endrules
end frame
end document
answered 7 hours ago
BernardBernard
185k7 gold badges84 silver badges219 bronze badges
185k7 gold badges84 silver badges219 bronze badges
I was wondering whether the<...>...
stuff contained a mistake. I see you've re-imagined it aslangle ... rangle ...
. Neat!
– Mico
7 hours ago
add a comment |
I was wondering whether the<...>...
stuff contained a mistake. I see you've re-imagined it aslangle ... rangle ...
. Neat!
– Mico
7 hours ago
I was wondering whether the
<...>...
stuff contained a mistake. I see you've re-imagined it as langle ... rangle ...
. Neat!– Mico
7 hours ago
I was wondering whether the
<...>...
stuff contained a mistake. I see you've re-imagined it as langle ... rangle ...
. Neat!– Mico
7 hours ago
add a comment |
I think the equation could benefit from a couple of additional line breaks.
documentclassbeamer
usethemeAntibes
usepackageamsmath, amsthm, amssymb%,amsfonts}
newtheoremrulesRule
usepackagegraphicx
usepackage[utf8]inputenc
%% I've commented out all instructions that are repetitive or
%% do not affect the body of the sample document.
%newcommandFontvifontsize24selectfont
%usepackage[compat=1.1.0]tikz-feynman
%usepackagetikz
%usepackagetcolorbox
%usepackageamsmath
%usepackageamsthm
%usepackageamssymb
%usepackagetikz-feynman
%setcounterMaxMatrixCols20
%usepackagebreqn
%usepackagetikz-feynman
%usepackageamsmath
%usecolortheme
%titleNegative Dimensional Integral and Modified Method of Brackets
%author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
%instituteIndian Institute of Science\Bangalore- 560012
%date
begindocument
beginframe
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + dots + A_J)^alpha \
&quad= frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
dotsm
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
\
&quad< z_1 + dots + z_J - alpha\
&quad> A_1^z_1dotsm A_J^z_J
,Gamma(-z_1)dotsmGamma(-z_J),.
endsplit
endequation
endrules
endframe
enddocument
Addendum, inspired by a detail in @Bernard's parallel answer: If <
and >
do not denote "less than" and "greater than" and, instead, are supposed to be interpreted as angle brackets (langle
and rangle
, respectively, in TeX parlance), it would be better to combine rows three and four of the answer shown above into a single line:
documentclassbeamer
usethemeAntibes
usepackageamsmath, amsthm, amssymb
newtheoremrulesRule
usepackagegraphicx
usepackage[utf8]inputenc
begindocument
beginframe
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + dots + A_J)^alpha \
&quad= frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
dotsm
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i \
&qquadtimes
langle z_1 + dots + z_J - alpharangle
,A_1^z_1dotsm A_J^z_J
,Gamma(-z_1)dotsmGamma(-z_J),.
endsplit
endequation
endrules
endframe
enddocument
add a comment |
I think the equation could benefit from a couple of additional line breaks.
documentclassbeamer
usethemeAntibes
usepackageamsmath, amsthm, amssymb%,amsfonts}
newtheoremrulesRule
usepackagegraphicx
usepackage[utf8]inputenc
%% I've commented out all instructions that are repetitive or
%% do not affect the body of the sample document.
%newcommandFontvifontsize24selectfont
%usepackage[compat=1.1.0]tikz-feynman
%usepackagetikz
%usepackagetcolorbox
%usepackageamsmath
%usepackageamsthm
%usepackageamssymb
%usepackagetikz-feynman
%setcounterMaxMatrixCols20
%usepackagebreqn
%usepackagetikz-feynman
%usepackageamsmath
%usecolortheme
%titleNegative Dimensional Integral and Modified Method of Brackets
%author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
%instituteIndian Institute of Science\Bangalore- 560012
%date
begindocument
beginframe
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + dots + A_J)^alpha \
&quad= frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
dotsm
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
\
&quad< z_1 + dots + z_J - alpha\
&quad> A_1^z_1dotsm A_J^z_J
,Gamma(-z_1)dotsmGamma(-z_J),.
endsplit
endequation
endrules
endframe
enddocument
Addendum, inspired by a detail in @Bernard's parallel answer: If <
and >
do not denote "less than" and "greater than" and, instead, are supposed to be interpreted as angle brackets (langle
and rangle
, respectively, in TeX parlance), it would be better to combine rows three and four of the answer shown above into a single line:
documentclassbeamer
usethemeAntibes
usepackageamsmath, amsthm, amssymb
newtheoremrulesRule
usepackagegraphicx
usepackage[utf8]inputenc
begindocument
beginframe
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + dots + A_J)^alpha \
&quad= frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
dotsm
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i \
&qquadtimes
langle z_1 + dots + z_J - alpharangle
,A_1^z_1dotsm A_J^z_J
,Gamma(-z_1)dotsmGamma(-z_J),.
endsplit
endequation
endrules
endframe
enddocument
add a comment |
I think the equation could benefit from a couple of additional line breaks.
documentclassbeamer
usethemeAntibes
usepackageamsmath, amsthm, amssymb%,amsfonts}
newtheoremrulesRule
usepackagegraphicx
usepackage[utf8]inputenc
%% I've commented out all instructions that are repetitive or
%% do not affect the body of the sample document.
%newcommandFontvifontsize24selectfont
%usepackage[compat=1.1.0]tikz-feynman
%usepackagetikz
%usepackagetcolorbox
%usepackageamsmath
%usepackageamsthm
%usepackageamssymb
%usepackagetikz-feynman
%setcounterMaxMatrixCols20
%usepackagebreqn
%usepackagetikz-feynman
%usepackageamsmath
%usecolortheme
%titleNegative Dimensional Integral and Modified Method of Brackets
%author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
%instituteIndian Institute of Science\Bangalore- 560012
%date
begindocument
beginframe
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + dots + A_J)^alpha \
&quad= frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
dotsm
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
\
&quad< z_1 + dots + z_J - alpha\
&quad> A_1^z_1dotsm A_J^z_J
,Gamma(-z_1)dotsmGamma(-z_J),.
endsplit
endequation
endrules
endframe
enddocument
Addendum, inspired by a detail in @Bernard's parallel answer: If <
and >
do not denote "less than" and "greater than" and, instead, are supposed to be interpreted as angle brackets (langle
and rangle
, respectively, in TeX parlance), it would be better to combine rows three and four of the answer shown above into a single line:
documentclassbeamer
usethemeAntibes
usepackageamsmath, amsthm, amssymb
newtheoremrulesRule
usepackagegraphicx
usepackage[utf8]inputenc
begindocument
beginframe
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + dots + A_J)^alpha \
&quad= frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
dotsm
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i \
&qquadtimes
langle z_1 + dots + z_J - alpharangle
,A_1^z_1dotsm A_J^z_J
,Gamma(-z_1)dotsmGamma(-z_J),.
endsplit
endequation
endrules
endframe
enddocument
I think the equation could benefit from a couple of additional line breaks.
documentclassbeamer
usethemeAntibes
usepackageamsmath, amsthm, amssymb%,amsfonts}
newtheoremrulesRule
usepackagegraphicx
usepackage[utf8]inputenc
%% I've commented out all instructions that are repetitive or
%% do not affect the body of the sample document.
%newcommandFontvifontsize24selectfont
%usepackage[compat=1.1.0]tikz-feynman
%usepackagetikz
%usepackagetcolorbox
%usepackageamsmath
%usepackageamsthm
%usepackageamssymb
%usepackagetikz-feynman
%setcounterMaxMatrixCols20
%usepackagebreqn
%usepackagetikz-feynman
%usepackageamsmath
%usecolortheme
%titleNegative Dimensional Integral and Modified Method of Brackets
%author[Sumit Banik]textbf Work By-Sumit Banik\ footnotesize Supervised by: B Ananthanarayan
%instituteIndian Institute of Science\Bangalore- 560012
%date
begindocument
beginframe
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + dots + A_J)^alpha \
&quad= frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
dotsm
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
\
&quad< z_1 + dots + z_J - alpha\
&quad> A_1^z_1dotsm A_J^z_J
,Gamma(-z_1)dotsmGamma(-z_J),.
endsplit
endequation
endrules
endframe
enddocument
Addendum, inspired by a detail in @Bernard's parallel answer: If <
and >
do not denote "less than" and "greater than" and, instead, are supposed to be interpreted as angle brackets (langle
and rangle
, respectively, in TeX parlance), it would be better to combine rows three and four of the answer shown above into a single line:
documentclassbeamer
usethemeAntibes
usepackageamsmath, amsthm, amssymb
newtheoremrulesRule
usepackagegraphicx
usepackage[utf8]inputenc
begindocument
beginframe
beginrules labelRule2
beginequation labeleq:rule-B
beginsplit
&(A_1 + dots + A_J)^alpha \
&quad= frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
dotsm
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i \
&qquadtimes
langle z_1 + dots + z_J - alpharangle
,A_1^z_1dotsm A_J^z_J
,Gamma(-z_1)dotsmGamma(-z_J),.
endsplit
endequation
endrules
endframe
enddocument
edited 7 hours ago
answered 8 hours ago
MicoMico
298k32 gold badges410 silver badges810 bronze badges
298k32 gold badges410 silver badges810 bronze badges
add a comment |
add a comment |
You should split your equation. Please Consider the following code:
documentclassbeamer
usepackage[compat=1.1.0]tikz-feynman
usepackageamsmath, amsthm, amssymb,amsfonts
usepackagetikz
newtheoremrulesRule
usethemeAntibes
begin document
begin frame
beginrules labelRule2
beginalign labeleq:rule-B
&(A_1 + cdots + A_J)^alpha
nonumber\
quad=&
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,nonumber\
&<z_1 + cdots + z_J - alpha>
,
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J),.
endalign
endrules
end frame
end document
add a comment |
You should split your equation. Please Consider the following code:
documentclassbeamer
usepackage[compat=1.1.0]tikz-feynman
usepackageamsmath, amsthm, amssymb,amsfonts
usepackagetikz
newtheoremrulesRule
usethemeAntibes
begin document
begin frame
beginrules labelRule2
beginalign labeleq:rule-B
&(A_1 + cdots + A_J)^alpha
nonumber\
quad=&
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,nonumber\
&<z_1 + cdots + z_J - alpha>
,
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J),.
endalign
endrules
end frame
end document
add a comment |
You should split your equation. Please Consider the following code:
documentclassbeamer
usepackage[compat=1.1.0]tikz-feynman
usepackageamsmath, amsthm, amssymb,amsfonts
usepackagetikz
newtheoremrulesRule
usethemeAntibes
begin document
begin frame
beginrules labelRule2
beginalign labeleq:rule-B
&(A_1 + cdots + A_J)^alpha
nonumber\
quad=&
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,nonumber\
&<z_1 + cdots + z_J - alpha>
,
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J),.
endalign
endrules
end frame
end document
You should split your equation. Please Consider the following code:
documentclassbeamer
usepackage[compat=1.1.0]tikz-feynman
usepackageamsmath, amsthm, amssymb,amsfonts
usepackagetikz
newtheoremrulesRule
usethemeAntibes
begin document
begin frame
beginrules labelRule2
beginalign labeleq:rule-B
&(A_1 + cdots + A_J)^alpha
nonumber\
quad=&
frac1Gamma(-alpha)
int_c_1-iinfty^c_1+iinftyfracdz_12pi i
cdots
int_c_J-iinfty^c_J+iinftyfracdz_J2pi i
,nonumber\
&<z_1 + cdots + z_J - alpha>
,
A_1^z_1
cdots
A_J^z_J
,
Gamma(-z_1)
cdots
Gamma(-z_J),.
endalign
endrules
end frame
end document
answered 8 hours ago
A DiyanatA Diyanat
404 bronze badges
404 bronze badges
add a comment |
add a comment |
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