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Lualatex function producing trailing characters
Ploting a function using mplib in lualatexIs LuaLaTeX producing faulty pdfs?Check for missing font characters in LuaLaTeXaccess all characters in an OpenType font with LuaLaTeXLuaLaTeX pass characters without “ ” to luaProblems with LuaLaTeX and Combining CharactersLuaLaTeX Error: Missing characters which are in the fonts usedmissing accented characters lualatex in texlive2016Print Latex Code with LuaLatex in functionNon-english characters in biblatex fail compilation with xelatex/lualatex
This function was working in the production system and I'm not aware of changing anything (MikTeX did some package updates which may have had an effect).
A very much stripped down MWE is
documentclassarticle
directlua
function underscore(s)
s = tostring(s+2080)
tex.print(s)
end
DeclareRobustCommandBinl[1]directluaunderscore([[#1]])%
begindocument
Use MBinl1 or MBinl2
enddocument
I used to get M_1 and M_2 with proper subscripts, but now the correct unicode characters U+2081 and U+2082 are being generated but have acquired a trailing ".0" as can be seen in the output. N.B. I've omitted prepending "char"" to s before passing the string back.
Output :
Use M2081.0 or M2082.0
luatex
asked 8 hours ago
DLyonsDLyons
1956
add a comment |
This function was working in the production system and I'm not aware of changing anything (MikTeX did some package updates which may have had an effect).
A very much stripped down MWE is
documentclassarticle
directlua
function underscore(s)
s = tostring(s+2080)
tex.print(s)
end
DeclareRobustCommandBinl[1]directluaunderscore([[#1]])%
begindocument
Use MBinl1 or MBinl2
enddocument
I used to get M_1 and M_2 with proper subscripts, but now the correct unicode characters U+2081 and U+2082 are being generated but have acquired a trailing ".0" as can be seen in the output. N.B. I've omitted prepending "char"" to s before passing the string back.
Output :
Use M2081.0 or M2082.0
luatex
asked 8 hours ago
DLyonsDLyons
1956
add a comment |
This function was working in the production system and I'm not aware of changing anything (MikTeX did some package updates which may have had an effect).
A very much stripped down MWE is
documentclassarticle
directlua
function underscore(s)
s = tostring(s+2080)
tex.print(s)
end
DeclareRobustCommandBinl[1]directluaunderscore([[#1]])%
begindocument
Use MBinl1 or MBinl2
enddocument
I used to get M_1 and M_2 with proper subscripts, but now the correct unicode characters U+2081 and U+2082 are being generated but have acquired a trailing ".0" as can be seen in the output. N.B. I've omitted prepending "char"" to s before passing the string back.
Output :
Use M2081.0 or M2082.0
luatex
asked 8 hours ago
DLyonsDLyons
1956
This function was working in the production system and I'm not aware of changing anything (MikTeX did some package updates which may have had an effect).
A very much stripped down MWE is
documentclassarticle
directlua
function underscore(s)
s = tostring(s+2080)
tex.print(s)
end
DeclareRobustCommandBinl[1]directluaunderscore([[#1]])%
begindocument
Use MBinl1 or MBinl2
enddocument
I used to get M_1 and M_2 with proper subscripts, but now the correct unicode characters U+2081 and U+2082 are being generated but have acquired a trailing ".0" as can be seen in the output. N.B. I've omitted prepending "char"" to s before passing the string back.
Output :
Use M2081.0 or M2082.0
luatex
luatex
asked 8 hours ago
DLyonsDLyons
1956
asked 8 hours ago
DLyonsDLyons
1956
edited 8 hours ago
DLyons
asked 8 hours ago
DLyonsDLyons
1956
asked 8 hours ago
DLyonsDLyons
1956
asked 8 hours ago
DLyonsDLyons
1956
1956
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
That's due to the change from lua 5.2 to lua 5.3.
You can force the number to be an integer e.g. with math.floor:
documentclassarticle
directlua
function underscore(s)
s = tostring(math.floor(s+2080))
tex.print(s)
end
DeclareRobustCommandBinl[1]directluaunderscore([[#1]])%
begindocument
Use MBinl1 or MBinl2
enddocument
answered 8 hours ago
Ulrike FischerUlrike Fischer
205k9313705
Thanks @Ulrike Fischer. That fixed it.
– DLyons
8 hours ago
add a comment |
s = tostring(math.floor(s+2080))
answered 8 hours ago
Red-CloudRed-Cloud
3,803215
Thanks Red-Cloud. Millisecs behind Ulrike.
– DLyons
8 hours ago
add a comment |
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2 Answers
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2 Answers
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active
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active
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active
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votes
That's due to the change from lua 5.2 to lua 5.3.
You can force the number to be an integer e.g. with math.floor:
documentclassarticle
directlua
function underscore(s)
s = tostring(math.floor(s+2080))
tex.print(s)
end
DeclareRobustCommandBinl[1]directluaunderscore([[#1]])%
begindocument
Use MBinl1 or MBinl2
enddocument
answered 8 hours ago
Ulrike FischerUlrike Fischer
205k9313705
Thanks @Ulrike Fischer. That fixed it.
– DLyons
8 hours ago
add a comment |
That's due to the change from lua 5.2 to lua 5.3.
You can force the number to be an integer e.g. with math.floor:
documentclassarticle
directlua
function underscore(s)
s = tostring(math.floor(s+2080))
tex.print(s)
end
DeclareRobustCommandBinl[1]directluaunderscore([[#1]])%
begindocument
Use MBinl1 or MBinl2
enddocument
answered 8 hours ago
Ulrike FischerUlrike Fischer
205k9313705
Thanks @Ulrike Fischer. That fixed it.
– DLyons
8 hours ago
add a comment |
That's due to the change from lua 5.2 to lua 5.3.
You can force the number to be an integer e.g. with math.floor:
documentclassarticle
directlua
function underscore(s)
s = tostring(math.floor(s+2080))
tex.print(s)
end
DeclareRobustCommandBinl[1]directluaunderscore([[#1]])%
begindocument
Use MBinl1 or MBinl2
enddocument
answered 8 hours ago
Ulrike FischerUlrike Fischer
205k9313705
That's due to the change from lua 5.2 to lua 5.3.
You can force the number to be an integer e.g. with math.floor:
documentclassarticle
directlua
function underscore(s)
s = tostring(math.floor(s+2080))
tex.print(s)
end
DeclareRobustCommandBinl[1]directluaunderscore([[#1]])%
begindocument
Use MBinl1 or MBinl2
enddocument
answered 8 hours ago
Ulrike FischerUlrike Fischer
205k9313705
answered 8 hours ago
Ulrike FischerUlrike Fischer
205k9313705
answered 8 hours ago
Ulrike FischerUlrike Fischer
205k9313705
answered 8 hours ago
Ulrike FischerUlrike Fischer
205k9313705
205k9313705
Thanks @Ulrike Fischer. That fixed it.
– DLyons
8 hours ago
add a comment |
Thanks @Ulrike Fischer. That fixed it.
– DLyons
8 hours ago
Thanks @Ulrike Fischer. That fixed it.
– DLyons
8 hours ago
Thanks @Ulrike Fischer. That fixed it.
– DLyons
8 hours ago
add a comment |
s = tostring(math.floor(s+2080))
answered 8 hours ago
Red-CloudRed-Cloud
3,803215
Thanks Red-Cloud. Millisecs behind Ulrike.
– DLyons
8 hours ago
add a comment |
s = tostring(math.floor(s+2080))
answered 8 hours ago
Red-CloudRed-Cloud
3,803215
Thanks Red-Cloud. Millisecs behind Ulrike.
– DLyons
8 hours ago
add a comment |
s = tostring(math.floor(s+2080))
answered 8 hours ago
Red-CloudRed-Cloud
3,803215
s = tostring(math.floor(s+2080))
answered 8 hours ago
Red-CloudRed-Cloud
3,803215
answered 8 hours ago
Red-CloudRed-Cloud
3,803215
answered 8 hours ago
Red-CloudRed-Cloud
3,803215
answered 8 hours ago
Red-CloudRed-Cloud
3,803215
3,803215
Thanks Red-Cloud. Millisecs behind Ulrike.
– DLyons
8 hours ago
add a comment |
Thanks Red-Cloud. Millisecs behind Ulrike.
– DLyons
8 hours ago
Thanks Red-Cloud. Millisecs behind Ulrike.
– DLyons
8 hours ago
Thanks Red-Cloud. Millisecs behind Ulrike.
– DLyons
8 hours ago
add a comment |
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