draw a pulley system Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)TikZ: placing a line (transformed into a sinusoidal shape) parallel to an edge connecting nodesAbsolutely position arrow headHow to define the default vertical distance between nodes?Computing the rectangle encompassing a node and a pointUse of overlay command in a graphTikZ: Drawing an arc from an intersection to an intersectionGetting the proper shading within a circle - a bit of litographyAdjusting edge alignment and positioning of fitted nodeRelative transparency in TikZ?Line up nested tikz enviroments or how to get rid of them

Keep at all times, the minus sign above aligned with minus sign below

.bashrc alias for a command with fixed second parameter

How does the body cool itself in a stillsuit?

Pointing to problems without suggesting solutions

Proving that any solution to the differential equation of an oscillator can be written as a sum of sinusoids.

How do Java 8 default methods hеlp with lambdas?

calculator's angle answer for trig ratios that can work in more than 1 quadrant on the unit circle

How to ask rejected full-time candidates to apply to teach individual courses?

Vertical ranges of Column Plots in 12

One-one communication

Understanding piped commands in GNU/Linux

My mentor says to set image to Fine instead of RAW — how is this different from JPG?

Improvising over quartal voicings

Why is there so little support for joining EFTA in the British parliament?

Statistical analysis applied to methods coming out of Machine Learning

Weaponising the Grasp-at-a-Distance spell

"Destructive power" carried by a B-52?

draw a pulley system

Shimano 105 brifters (5800) and Avid BB5 compatibility

Which types of prepositional phrase is "toward its employees" in Philosophy guiding the organization's policies towards its employees is not bad?

Where and when has Thucydides been studied?

Any stored/leased 737s that could substitute for grounded MAXs?

Fit odd number of triplets in a measure?

The test team as an enemy of development? And how can this be avoided?



draw a pulley system



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)TikZ: placing a line (transformed into a sinusoidal shape) parallel to an edge connecting nodesAbsolutely position arrow headHow to define the default vertical distance between nodes?Computing the rectangle encompassing a node and a pointUse of overlay command in a graphTikZ: Drawing an arc from an intersection to an intersectionGetting the proper shading within a circle - a bit of litographyAdjusting edge alignment and positioning of fitted nodeRelative transparency in TikZ?Line up nested tikz enviroments or how to get rid of them










1















enter image description here
I need to draw a pulley system as in the figure. Can you help?



 begintikzpicture
fill[pattern=north east lines] (-3,0) rectangle (3,.3);
draw(-3,0)--(3,0);
draw(-2.5,0)--(-2.5,-2.4);
draw(2.5,0)--(2.5,-1);

draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);
draw[fill=white] (0,-3) circle (.153);

draw
(2.5,-1) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (0,-2.75) coordinate (c) node[above right]
pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
angle=a--b--c;

draw
(0,-2.75) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (-2.5,-2.4) coordinate (c) node[above right]
pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
angle=a--b--c;
draw[dashed] (0,-3)--(0,-1);
draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);

draw[fill=white] (0,-3) circle (.153);


endtikzpicture









share|improve this question




























    1















    enter image description here
    I need to draw a pulley system as in the figure. Can you help?



     begintikzpicture
    fill[pattern=north east lines] (-3,0) rectangle (3,.3);
    draw(-3,0)--(3,0);
    draw(-2.5,0)--(-2.5,-2.4);
    draw(2.5,0)--(2.5,-1);

    draw[fill=white] (-2.5,-2.4) circle (.3);
    draw[fill=white] (2.5,-1) circle (.3);
    draw[fill=white] (0,-3) circle (.153);

    draw
    (2.5,-1) coordinate (a) node[right]
    -- (0,-3) coordinate (b) node[left]
    -- (0,-2.75) coordinate (c) node[above right]
    pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
    angle=a--b--c;

    draw
    (0,-2.75) coordinate (a) node[right]
    -- (0,-3) coordinate (b) node[left]
    -- (-2.5,-2.4) coordinate (c) node[above right]
    pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
    angle=a--b--c;
    draw[dashed] (0,-3)--(0,-1);
    draw[fill=white] (-2.5,-2.4) circle (.3);
    draw[fill=white] (2.5,-1) circle (.3);

    draw[fill=white] (0,-3) circle (.153);


    endtikzpicture









    share|improve this question


























      1












      1








      1


      0






      enter image description here
      I need to draw a pulley system as in the figure. Can you help?



       begintikzpicture
      fill[pattern=north east lines] (-3,0) rectangle (3,.3);
      draw(-3,0)--(3,0);
      draw(-2.5,0)--(-2.5,-2.4);
      draw(2.5,0)--(2.5,-1);

      draw[fill=white] (-2.5,-2.4) circle (.3);
      draw[fill=white] (2.5,-1) circle (.3);
      draw[fill=white] (0,-3) circle (.153);

      draw
      (2.5,-1) coordinate (a) node[right]
      -- (0,-3) coordinate (b) node[left]
      -- (0,-2.75) coordinate (c) node[above right]
      pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
      angle=a--b--c;

      draw
      (0,-2.75) coordinate (a) node[right]
      -- (0,-3) coordinate (b) node[left]
      -- (-2.5,-2.4) coordinate (c) node[above right]
      pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
      angle=a--b--c;
      draw[dashed] (0,-3)--(0,-1);
      draw[fill=white] (-2.5,-2.4) circle (.3);
      draw[fill=white] (2.5,-1) circle (.3);

      draw[fill=white] (0,-3) circle (.153);


      endtikzpicture









      share|improve this question
















      enter image description here
      I need to draw a pulley system as in the figure. Can you help?



       begintikzpicture
      fill[pattern=north east lines] (-3,0) rectangle (3,.3);
      draw(-3,0)--(3,0);
      draw(-2.5,0)--(-2.5,-2.4);
      draw(2.5,0)--(2.5,-1);

      draw[fill=white] (-2.5,-2.4) circle (.3);
      draw[fill=white] (2.5,-1) circle (.3);
      draw[fill=white] (0,-3) circle (.153);

      draw
      (2.5,-1) coordinate (a) node[right]
      -- (0,-3) coordinate (b) node[left]
      -- (0,-2.75) coordinate (c) node[above right]
      pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
      angle=a--b--c;

      draw
      (0,-2.75) coordinate (a) node[right]
      -- (0,-3) coordinate (b) node[left]
      -- (-2.5,-2.4) coordinate (c) node[above right]
      pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
      angle=a--b--c;
      draw[dashed] (0,-3)--(0,-1);
      draw[fill=white] (-2.5,-2.4) circle (.3);
      draw[fill=white] (2.5,-1) circle (.3);

      draw[fill=white] (0,-3) circle (.153);


      endtikzpicture






      tikz-pgf






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 2 hours ago







      Thumbolt

















      asked 3 hours ago









      ThumboltThumbolt

      1,516822




      1,516822




















          1 Answer
          1






          active

          oldest

          votes


















          3














          In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



          documentclass[tikz,border=3.14mm]standalone
          usetikzlibrarypatterns,calc,angles,quotes
          begindocument
          begintikzpicture
          fill[pattern=north east lines] (-3,0) rectangle (3,.3);
          beginscope[thick]
          draw(-3,0)--(3,0);

          path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
          (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
          (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
          draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
          draw[dashed] (M) -- (0,-1)coordinate (M1);
          draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
          let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
          arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
          draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
          let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
          arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
          endscope
          path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
          pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
          endtikzpicture
          enddocument


          enter image description here






          share|improve this answer

























            Your Answer








            StackExchange.ready(function()
            var channelOptions =
            tags: "".split(" "),
            id: "85"
            ;
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function()
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled)
            StackExchange.using("snippets", function()
            createEditor();
            );

            else
            createEditor();

            );

            function createEditor()
            StackExchange.prepareEditor(
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: false,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: null,
            bindNavPrevention: true,
            postfix: "",
            imageUploader:
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            ,
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            );



            );













            draft saved

            draft discarded


















            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f485982%2fdraw-a-pulley-system%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown

























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3














            In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



            documentclass[tikz,border=3.14mm]standalone
            usetikzlibrarypatterns,calc,angles,quotes
            begindocument
            begintikzpicture
            fill[pattern=north east lines] (-3,0) rectangle (3,.3);
            beginscope[thick]
            draw(-3,0)--(3,0);

            path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
            (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
            (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
            draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
            draw[dashed] (M) -- (0,-1)coordinate (M1);
            draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
            let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
            arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
            draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
            let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
            arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
            endscope
            path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
            pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
            endtikzpicture
            enddocument


            enter image description here






            share|improve this answer





























              3














              In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



              documentclass[tikz,border=3.14mm]standalone
              usetikzlibrarypatterns,calc,angles,quotes
              begindocument
              begintikzpicture
              fill[pattern=north east lines] (-3,0) rectangle (3,.3);
              beginscope[thick]
              draw(-3,0)--(3,0);

              path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
              (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
              (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
              draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
              draw[dashed] (M) -- (0,-1)coordinate (M1);
              draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
              let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
              arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
              draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
              let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
              arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
              endscope
              path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
              pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
              endtikzpicture
              enddocument


              enter image description here






              share|improve this answer



























                3












                3








                3







                In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



                documentclass[tikz,border=3.14mm]standalone
                usetikzlibrarypatterns,calc,angles,quotes
                begindocument
                begintikzpicture
                fill[pattern=north east lines] (-3,0) rectangle (3,.3);
                beginscope[thick]
                draw(-3,0)--(3,0);

                path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
                (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
                (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
                draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
                draw[dashed] (M) -- (0,-1)coordinate (M1);
                draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
                let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
                arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
                draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
                let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
                arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
                endscope
                path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
                pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
                endtikzpicture
                enddocument


                enter image description here






                share|improve this answer















                In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



                documentclass[tikz,border=3.14mm]standalone
                usetikzlibrarypatterns,calc,angles,quotes
                begindocument
                begintikzpicture
                fill[pattern=north east lines] (-3,0) rectangle (3,.3);
                beginscope[thick]
                draw(-3,0)--(3,0);

                path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
                (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
                (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
                draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
                draw[dashed] (M) -- (0,-1)coordinate (M1);
                draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
                let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
                arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
                draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
                let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
                arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
                endscope
                path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
                pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
                endtikzpicture
                enddocument


                enter image description here







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 2 hours ago

























                answered 2 hours ago









                marmotmarmot

                120k6156292




                120k6156292



























                    draft saved

                    draft discarded
















































                    Thanks for contributing an answer to TeX - LaTeX Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid


                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.

                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function ()
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f485982%2fdraw-a-pulley-system%23new-answer', 'question_page');

                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    Invision Community Contents History See also References External links Navigation menuProprietaryinvisioncommunity.comIPS Community ForumsIPS Community Forumsthis blog entry"License Changes, IP.Board 3.4, and the Future""Interview -- Matt Mecham of Ibforums""CEO Invision Power Board, Matt Mecham Is a Liar, Thief!"IPB License Explanation 1.3, 1.3.1, 2.0, and 2.1ArchivedSecurity Fixes, Updates And Enhancements For IPB 1.3.1Archived"New Demo Accounts - Invision Power Services"the original"New Default Skin"the original"Invision Power Board 3.0.0 and Applications Released"the original"Archived copy"the original"Perpetual licenses being done away with""Release Notes - Invision Power Services""Introducing: IPS Community Suite 4!"Invision Community Release Notes

                    Canceling a color specificationRandomly assigning color to Graphics3D objects?Default color for Filling in Mathematica 9Coloring specific elements of sets with a prime modified order in an array plotHow to pick a color differing significantly from the colors already in a given color list?Detection of the text colorColor numbers based on their valueCan color schemes for use with ColorData include opacity specification?My dynamic color schemes

                    Ласкавець круглолистий Зміст Опис | Поширення | Галерея | Примітки | Посилання | Навігаційне меню58171138361-22960890446Bupleurum rotundifoliumEuro+Med PlantbasePlants of the World Online — Kew ScienceGermplasm Resources Information Network (GRIN)Ласкавецькн. VI : Літери Ком — Левиправивши або дописавши її