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Is it a missed optimization, when a compile-time known reference takes space in a struct?
POD struct (members of same type): are members in contiguous memory locations?Is it a missed optimization, when a compile-time known reference takes space in a non-aggregate struct?Storing C++ template function definitions in a .CPP fileWhy isn't pass struct by reference a common optimization?Convenient C++ struct initialisationImage Processing: Algorithm Improvement for 'Coca-Cola Can' RecognitionCompilation fails when passing array with missing initializers as argumentWhy does GCC generate 15-20% faster code if I optimize for size instead of speed?Why is f(i = -1, i = -1) undefined behavior?Is the compiler allowed to optimize out dynamic_cast of a volatile pointer when the compiler doesn't see a possible type which can fulfill the cast?Does the C++ standard allow for an uninitialized bool to crash a program?
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See this example:
struct Foo
int a;
int &b = a;
;
Is it a missed optimization, if sizeof(Foo)!=sizeof(int)?
I mean, can the compiler remove b from the struct, as it always refers to a?
Is there anything which stops the compiler to make this transformation?
(Note, struct Foo looks as it is. No constructors, etc. But you can add anything around Foo, which shows that this optimization would violate the standard)
c++ struct reference initialization language-lawyer
edited 8 hours ago
ShadowRanger
72.5k6 gold badges76 silver badges117 bronze badges
asked 8 hours ago
gezageza
16.2k3 gold badges39 silver badges95 bronze badges
add a comment |
See this example:
struct Foo
int a;
int &b = a;
;
Is it a missed optimization, if sizeof(Foo)!=sizeof(int)?
I mean, can the compiler remove b from the struct, as it always refers to a?
Is there anything which stops the compiler to make this transformation?
(Note, struct Foo looks as it is. No constructors, etc. But you can add anything around Foo, which shows that this optimization would violate the standard)
c++ struct reference initialization language-lawyer
edited 8 hours ago
ShadowRanger
72.5k6 gold badges76 silver badges117 bronze badges
asked 8 hours ago
gezageza
16.2k3 gold badges39 silver badges95 bronze badges
Follow-up question: stackoverflow.com/questions/57811424/…
– geza
8 hours ago
add a comment |
See this example:
struct Foo
int a;
int &b = a;
;
Is it a missed optimization, if sizeof(Foo)!=sizeof(int)?
I mean, can the compiler remove b from the struct, as it always refers to a?
Is there anything which stops the compiler to make this transformation?
(Note, struct Foo looks as it is. No constructors, etc. But you can add anything around Foo, which shows that this optimization would violate the standard)
c++ struct reference initialization language-lawyer
edited 8 hours ago
ShadowRanger
72.5k6 gold badges76 silver badges117 bronze badges
asked 8 hours ago
gezageza
16.2k3 gold badges39 silver badges95 bronze badges
See this example:
struct Foo
int a;
int &b = a;
;
Is it a missed optimization, if sizeof(Foo)!=sizeof(int)?
I mean, can the compiler remove b from the struct, as it always refers to a?
Is there anything which stops the compiler to make this transformation?
(Note, struct Foo looks as it is. No constructors, etc. But you can add anything around Foo, which shows that this optimization would violate the standard)
c++ struct reference initialization language-lawyer
c++ struct reference initialization language-lawyer
edited 8 hours ago
ShadowRanger
72.5k6 gold badges76 silver badges117 bronze badges
asked 8 hours ago
gezageza
16.2k3 gold badges39 silver badges95 bronze badges
edited 8 hours ago
ShadowRanger
72.5k6 gold badges76 silver badges117 bronze badges
asked 8 hours ago
gezageza
16.2k3 gold badges39 silver badges95 bronze badges
edited 8 hours ago
ShadowRanger
72.5k6 gold badges76 silver badges117 bronze badges
edited 8 hours ago
ShadowRanger
72.5k6 gold badges76 silver badges117 bronze badges
edited 8 hours ago
ShadowRanger
72.5k6 gold badges76 silver badges117 bronze badges
72.5k6 gold badges76 silver badges117 bronze badges
asked 8 hours ago
gezageza
16.2k3 gold badges39 silver badges95 bronze badges
asked 8 hours ago
gezageza
16.2k3 gold badges39 silver badges95 bronze badges
asked 8 hours ago
gezageza
16.2k3 gold badges39 silver badges95 bronze badges
16.2k3 gold badges39 silver badges95 bronze badges
Follow-up question: stackoverflow.com/questions/57811424/…
– geza
8 hours ago
add a comment |
Follow-up question: stackoverflow.com/questions/57811424/…
– geza
8 hours ago
Follow-up question: stackoverflow.com/questions/57811424/…
– geza
8 hours ago
Follow-up question: stackoverflow.com/questions/57811424/…
– geza
8 hours ago
add a comment |
1 Answer
1
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oldest
votes
No, because you can use aggregate initialization of a variable to have it refer to something else.
struct Foo
int a;
int &b = a;
;
int c;
Foo f7, c;
answered 8 hours ago
1201ProgramAlarm1201ProgramAlarm
21.7k7 gold badges30 silver badges43 bronze badges
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1 Answer
1
active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
No, because you can use aggregate initialization of a variable to have it refer to something else.
struct Foo
int a;
int &b = a;
;
int c;
Foo f7, c;
answered 8 hours ago
1201ProgramAlarm1201ProgramAlarm
21.7k7 gold badges30 silver badges43 bronze badges
add a comment |
No, because you can use aggregate initialization of a variable to have it refer to something else.
struct Foo
int a;
int &b = a;
;
int c;
Foo f7, c;
answered 8 hours ago
1201ProgramAlarm1201ProgramAlarm
21.7k7 gold badges30 silver badges43 bronze badges
add a comment |
No, because you can use aggregate initialization of a variable to have it refer to something else.
struct Foo
int a;
int &b = a;
;
int c;
Foo f7, c;
answered 8 hours ago
1201ProgramAlarm1201ProgramAlarm
21.7k7 gold badges30 silver badges43 bronze badges
No, because you can use aggregate initialization of a variable to have it refer to something else.
struct Foo
int a;
int &b = a;
;
int c;
Foo f7, c;
answered 8 hours ago
1201ProgramAlarm1201ProgramAlarm
21.7k7 gold badges30 silver badges43 bronze badges
answered 8 hours ago
1201ProgramAlarm1201ProgramAlarm
21.7k7 gold badges30 silver badges43 bronze badges
answered 8 hours ago
1201ProgramAlarm1201ProgramAlarm
21.7k7 gold badges30 silver badges43 bronze badges
answered 8 hours ago
1201ProgramAlarm1201ProgramAlarm
21.7k7 gold badges30 silver badges43 bronze badges
21.7k7 gold badges30 silver badges43 bronze badges
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Follow-up question: stackoverflow.com/questions/57811424/…
– geza
8 hours ago