Why aren't rainbows blurred-out into nothing after they are produced?Why are so many different types of objects white, yet appear gray when they are wet?Why do propellers look like they are moving really slow when they are moving really fast?Frames of reference and why are they differentWhy do convex lenses not disperse light like prisms, given that entry and exit points aren't parallel?Why aren't rainbows more common?Why are my interference patterns completely out of phase?Why are UV Filters Directional? (or are they?)

What ability do tools use?

Why is the result of ('b'+'a'+ + 'a' + 'a').toLowerCase() 'banana'?

Is God unknowable?

What does the phrase "pull off sick wheelies and flips" mean here?

Why isn’t SHA-3 in wider use?

Annotating a table with arrows

Why does the standard fingering / strumming for a D maj chord leave out the 5th string?

Are employers legally allowed to pay employees in goods and services equal to or greater than the minimum wage?

Generate Brainfuck for the numbers 1–255

Not going forward with internship interview process

How to create events observer that only call when REST api dispatch events?

Is there any way to stop a user from creating executables and running them?

Heating Margarine in Pan = loss of calories?

What is this "Table of astronomy" about?

is this F 6'9 chord a figured bass or a chord extension?

Simplification of numbers

Are differences between uniformly distributed numbers uniformly distributed?

Lengthened voiced stops and the airstream through the nose

Why are Tucker and Malcolm not dead?

How does proof assistant organize knowledge?

how do companies get money from being listed publicly

Submitting a new paper just after another was accepted by the same journal

Loading military units into ships optimally, using backtracking

What should I call bands of armed men in the Middle Ages?



Why aren't rainbows blurred-out into nothing after they are produced?


Why are so many different types of objects white, yet appear gray when they are wet?Why do propellers look like they are moving really slow when they are moving really fast?Frames of reference and why are they differentWhy do convex lenses not disperse light like prisms, given that entry and exit points aren't parallel?Why aren't rainbows more common?Why are my interference patterns completely out of phase?Why are UV Filters Directional? (or are they?)






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2












$begingroup$


I understand how a prism works and how a single raindrop can scatter white light into a rainbow, but it seems to me that in normal atmospheric conditions, we should not be able to see rainbows.



enter image description here



When multiple raindrops are side-by-side, their emitted spectra will overlap. An observer at X will see light re-mixed from various originating raindrops. The volume of rain producing a rainbow typically has an angular diameter at least as wide as the rainbow itself, does it not?



So why can we still see separate colours?










share|cite|improve this question









$endgroup$













  • $begingroup$
    While crude your drawing show the principle of why you see red in one direction and blue in another. That is no different from seeing green tree leaves next to a red "Stop" sign. You see different colors in different directions.
    $endgroup$
    – dmckee
    6 hours ago

















2












$begingroup$


I understand how a prism works and how a single raindrop can scatter white light into a rainbow, but it seems to me that in normal atmospheric conditions, we should not be able to see rainbows.



enter image description here



When multiple raindrops are side-by-side, their emitted spectra will overlap. An observer at X will see light re-mixed from various originating raindrops. The volume of rain producing a rainbow typically has an angular diameter at least as wide as the rainbow itself, does it not?



So why can we still see separate colours?










share|cite|improve this question









$endgroup$













  • $begingroup$
    While crude your drawing show the principle of why you see red in one direction and blue in another. That is no different from seeing green tree leaves next to a red "Stop" sign. You see different colors in different directions.
    $endgroup$
    – dmckee
    6 hours ago













2












2








2


1



$begingroup$


I understand how a prism works and how a single raindrop can scatter white light into a rainbow, but it seems to me that in normal atmospheric conditions, we should not be able to see rainbows.



enter image description here



When multiple raindrops are side-by-side, their emitted spectra will overlap. An observer at X will see light re-mixed from various originating raindrops. The volume of rain producing a rainbow typically has an angular diameter at least as wide as the rainbow itself, does it not?



So why can we still see separate colours?










share|cite|improve this question









$endgroup$




I understand how a prism works and how a single raindrop can scatter white light into a rainbow, but it seems to me that in normal atmospheric conditions, we should not be able to see rainbows.



enter image description here



When multiple raindrops are side-by-side, their emitted spectra will overlap. An observer at X will see light re-mixed from various originating raindrops. The volume of rain producing a rainbow typically has an angular diameter at least as wide as the rainbow itself, does it not?



So why can we still see separate colours?







optics visible-light scattering weather






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 9 hours ago









spraffspraff

1,81615 silver badges37 bronze badges




1,81615 silver badges37 bronze badges














  • $begingroup$
    While crude your drawing show the principle of why you see red in one direction and blue in another. That is no different from seeing green tree leaves next to a red "Stop" sign. You see different colors in different directions.
    $endgroup$
    – dmckee
    6 hours ago
















  • $begingroup$
    While crude your drawing show the principle of why you see red in one direction and blue in another. That is no different from seeing green tree leaves next to a red "Stop" sign. You see different colors in different directions.
    $endgroup$
    – dmckee
    6 hours ago















$begingroup$
While crude your drawing show the principle of why you see red in one direction and blue in another. That is no different from seeing green tree leaves next to a red "Stop" sign. You see different colors in different directions.
$endgroup$
– dmckee
6 hours ago




$begingroup$
While crude your drawing show the principle of why you see red in one direction and blue in another. That is no different from seeing green tree leaves next to a red "Stop" sign. You see different colors in different directions.
$endgroup$
– dmckee
6 hours ago










2 Answers
2






active

oldest

votes


















6












$begingroup$

Your picture shows that an observer at X will see both the red and the blue scattered light, but he will see it coming from different directions.



That's the same way you usually see things: different amounts or colors of light reaching your eyes from different directions, and thereby creating an image on your retina.






share|cite|improve this answer











$endgroup$






















    4












    $begingroup$

    This isn't quite how rainbows work. The standard explanation is that light bounces around inside each droplet, and getting reflected once, and exiting at an angle:






    Image source




    However, the real picture is a little bit more complicated. When sunlight hits a water droplet, the rays will



    1. refract when they come in,

    2. (partially) reflect back when they hit the back of the droplet, and then

    3. (partially) refract on their way out.

    For each droplet, though, there are a bunch of rays hitting the droplet at different locations, and each of them will bounce around differently and exit at a different angle, so that the end result looks like this:







    Because there is a reflection inside the droplet, the light is mostly sent backwards, and because there are two steps where refraction happens, the angles are a bit wonky. But here's the important thing: the angle at which the light exits increases, has a maximum, and then decreases again, a fact which is clearly visible by following the dots as they go down from the negative-$x$ axis, stop, and then go back up again.



    This means that if the relative angle between the Sun, the droplet, and your head is smaller than a certain maximal angle $theta_mathrmmax$, usually equal to about $theta_mathrmmaxapprox 42°$, then the droplet will appear bright to you (and, since this isn't an individual droplet but a misty conglomerate, the mist will have a diffuse glow), and if the angle is larger than that, then there will be no extra light going towards your eyes from those droplets.



    In other words, then, this process will produce a disk that's bright, centered at the anti-solar point (i.e. where your eyes receive the on-axis reflections in the diagram above) and with diameter $theta_mathrmmaxapprox 42°$, and this is precisely what's observed, particularly when the rainbow happens against a darker background:





    Image source



    Notice, in particular, that the inside of the (primary) rainbow is much brighter than the outside.



    Moreover, notice that the brightness of this disk increases as you go from the center to the edge: this is caused because the rays cluster at the turning point at $theta_mathrmmax$ (notice in the ray diagram that there's many more dots in that region than there are near the axis). This clustering means that, for each color, the disk of light has a particularly bright edge, called a caustic.



    So what's with the colors?



    Although your diagram's geometry is off, as you correctly note, the standard diagram (the first figure in this answer) is kind of misleading, because for it kind of implies that for every red ray that hits your eyes, there will be another droplet at another angle sending a yellow ray (or green, blue, orange, indigo, and so on) on the same path ─ and that is indeed correct! This is what happens inside this disk of light.



    The thing with this process, though, is that the maximal angle of aperture of the cone of light that's reflected by each droplet depends very sensitively on the refractive index of the water that makes up the droplet, and this refractive index also depends on the wavelength of the light, so that the size of the disk increases with the wavelength, with the red disk being the largest, then the orange, yellow, green, blue, indigo and violet being successively smaller.



    This means that, at the edge of the disk produced by the red light, where it is the brightest, there is no light of other colours to compete with it, so the light looks red there.



    A bit closer in, at the edge of the orange disk, there is no light of yellow, green, or blue colors, since those disks are smaller ─ and, also, the light from the red disk is fainter, because it's not at the maximal-brightness edge and the orange disk does have its maximum shine there. Thus, at that location, the orange light wins out, and the light looks overall orange.



    And so on down the line: for each color in the spectrum, the edge of the disk is brighter than the larger disks, and the smaller disks don't contribute at all, so the edge of each disk shines with its respective color.






    share|cite|improve this answer









    $endgroup$














    • $begingroup$
      That's a fascinating explanation! But probably not quite what was confusing the OP.
      $endgroup$
      – Henning Makholm
      7 hours ago













    Your Answer








    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "151"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f496441%2fwhy-arent-rainbows-blurred-out-into-nothing-after-they-are-produced%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    6












    $begingroup$

    Your picture shows that an observer at X will see both the red and the blue scattered light, but he will see it coming from different directions.



    That's the same way you usually see things: different amounts or colors of light reaching your eyes from different directions, and thereby creating an image on your retina.






    share|cite|improve this answer











    $endgroup$



















      6












      $begingroup$

      Your picture shows that an observer at X will see both the red and the blue scattered light, but he will see it coming from different directions.



      That's the same way you usually see things: different amounts or colors of light reaching your eyes from different directions, and thereby creating an image on your retina.






      share|cite|improve this answer











      $endgroup$

















        6












        6








        6





        $begingroup$

        Your picture shows that an observer at X will see both the red and the blue scattered light, but he will see it coming from different directions.



        That's the same way you usually see things: different amounts or colors of light reaching your eyes from different directions, and thereby creating an image on your retina.






        share|cite|improve this answer











        $endgroup$



        Your picture shows that an observer at X will see both the red and the blue scattered light, but he will see it coming from different directions.



        That's the same way you usually see things: different amounts or colors of light reaching your eyes from different directions, and thereby creating an image on your retina.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited 8 hours ago

























        answered 8 hours ago









        Henning MakholmHenning Makholm

        4,34720 silver badges32 bronze badges




        4,34720 silver badges32 bronze badges


























            4












            $begingroup$

            This isn't quite how rainbows work. The standard explanation is that light bounces around inside each droplet, and getting reflected once, and exiting at an angle:






            Image source




            However, the real picture is a little bit more complicated. When sunlight hits a water droplet, the rays will



            1. refract when they come in,

            2. (partially) reflect back when they hit the back of the droplet, and then

            3. (partially) refract on their way out.

            For each droplet, though, there are a bunch of rays hitting the droplet at different locations, and each of them will bounce around differently and exit at a different angle, so that the end result looks like this:







            Because there is a reflection inside the droplet, the light is mostly sent backwards, and because there are two steps where refraction happens, the angles are a bit wonky. But here's the important thing: the angle at which the light exits increases, has a maximum, and then decreases again, a fact which is clearly visible by following the dots as they go down from the negative-$x$ axis, stop, and then go back up again.



            This means that if the relative angle between the Sun, the droplet, and your head is smaller than a certain maximal angle $theta_mathrmmax$, usually equal to about $theta_mathrmmaxapprox 42°$, then the droplet will appear bright to you (and, since this isn't an individual droplet but a misty conglomerate, the mist will have a diffuse glow), and if the angle is larger than that, then there will be no extra light going towards your eyes from those droplets.



            In other words, then, this process will produce a disk that's bright, centered at the anti-solar point (i.e. where your eyes receive the on-axis reflections in the diagram above) and with diameter $theta_mathrmmaxapprox 42°$, and this is precisely what's observed, particularly when the rainbow happens against a darker background:





            Image source



            Notice, in particular, that the inside of the (primary) rainbow is much brighter than the outside.



            Moreover, notice that the brightness of this disk increases as you go from the center to the edge: this is caused because the rays cluster at the turning point at $theta_mathrmmax$ (notice in the ray diagram that there's many more dots in that region than there are near the axis). This clustering means that, for each color, the disk of light has a particularly bright edge, called a caustic.



            So what's with the colors?



            Although your diagram's geometry is off, as you correctly note, the standard diagram (the first figure in this answer) is kind of misleading, because for it kind of implies that for every red ray that hits your eyes, there will be another droplet at another angle sending a yellow ray (or green, blue, orange, indigo, and so on) on the same path ─ and that is indeed correct! This is what happens inside this disk of light.



            The thing with this process, though, is that the maximal angle of aperture of the cone of light that's reflected by each droplet depends very sensitively on the refractive index of the water that makes up the droplet, and this refractive index also depends on the wavelength of the light, so that the size of the disk increases with the wavelength, with the red disk being the largest, then the orange, yellow, green, blue, indigo and violet being successively smaller.



            This means that, at the edge of the disk produced by the red light, where it is the brightest, there is no light of other colours to compete with it, so the light looks red there.



            A bit closer in, at the edge of the orange disk, there is no light of yellow, green, or blue colors, since those disks are smaller ─ and, also, the light from the red disk is fainter, because it's not at the maximal-brightness edge and the orange disk does have its maximum shine there. Thus, at that location, the orange light wins out, and the light looks overall orange.



            And so on down the line: for each color in the spectrum, the edge of the disk is brighter than the larger disks, and the smaller disks don't contribute at all, so the edge of each disk shines with its respective color.






            share|cite|improve this answer









            $endgroup$














            • $begingroup$
              That's a fascinating explanation! But probably not quite what was confusing the OP.
              $endgroup$
              – Henning Makholm
              7 hours ago















            4












            $begingroup$

            This isn't quite how rainbows work. The standard explanation is that light bounces around inside each droplet, and getting reflected once, and exiting at an angle:






            Image source




            However, the real picture is a little bit more complicated. When sunlight hits a water droplet, the rays will



            1. refract when they come in,

            2. (partially) reflect back when they hit the back of the droplet, and then

            3. (partially) refract on their way out.

            For each droplet, though, there are a bunch of rays hitting the droplet at different locations, and each of them will bounce around differently and exit at a different angle, so that the end result looks like this:







            Because there is a reflection inside the droplet, the light is mostly sent backwards, and because there are two steps where refraction happens, the angles are a bit wonky. But here's the important thing: the angle at which the light exits increases, has a maximum, and then decreases again, a fact which is clearly visible by following the dots as they go down from the negative-$x$ axis, stop, and then go back up again.



            This means that if the relative angle between the Sun, the droplet, and your head is smaller than a certain maximal angle $theta_mathrmmax$, usually equal to about $theta_mathrmmaxapprox 42°$, then the droplet will appear bright to you (and, since this isn't an individual droplet but a misty conglomerate, the mist will have a diffuse glow), and if the angle is larger than that, then there will be no extra light going towards your eyes from those droplets.



            In other words, then, this process will produce a disk that's bright, centered at the anti-solar point (i.e. where your eyes receive the on-axis reflections in the diagram above) and with diameter $theta_mathrmmaxapprox 42°$, and this is precisely what's observed, particularly when the rainbow happens against a darker background:





            Image source



            Notice, in particular, that the inside of the (primary) rainbow is much brighter than the outside.



            Moreover, notice that the brightness of this disk increases as you go from the center to the edge: this is caused because the rays cluster at the turning point at $theta_mathrmmax$ (notice in the ray diagram that there's many more dots in that region than there are near the axis). This clustering means that, for each color, the disk of light has a particularly bright edge, called a caustic.



            So what's with the colors?



            Although your diagram's geometry is off, as you correctly note, the standard diagram (the first figure in this answer) is kind of misleading, because for it kind of implies that for every red ray that hits your eyes, there will be another droplet at another angle sending a yellow ray (or green, blue, orange, indigo, and so on) on the same path ─ and that is indeed correct! This is what happens inside this disk of light.



            The thing with this process, though, is that the maximal angle of aperture of the cone of light that's reflected by each droplet depends very sensitively on the refractive index of the water that makes up the droplet, and this refractive index also depends on the wavelength of the light, so that the size of the disk increases with the wavelength, with the red disk being the largest, then the orange, yellow, green, blue, indigo and violet being successively smaller.



            This means that, at the edge of the disk produced by the red light, where it is the brightest, there is no light of other colours to compete with it, so the light looks red there.



            A bit closer in, at the edge of the orange disk, there is no light of yellow, green, or blue colors, since those disks are smaller ─ and, also, the light from the red disk is fainter, because it's not at the maximal-brightness edge and the orange disk does have its maximum shine there. Thus, at that location, the orange light wins out, and the light looks overall orange.



            And so on down the line: for each color in the spectrum, the edge of the disk is brighter than the larger disks, and the smaller disks don't contribute at all, so the edge of each disk shines with its respective color.






            share|cite|improve this answer









            $endgroup$














            • $begingroup$
              That's a fascinating explanation! But probably not quite what was confusing the OP.
              $endgroup$
              – Henning Makholm
              7 hours ago













            4












            4








            4





            $begingroup$

            This isn't quite how rainbows work. The standard explanation is that light bounces around inside each droplet, and getting reflected once, and exiting at an angle:






            Image source




            However, the real picture is a little bit more complicated. When sunlight hits a water droplet, the rays will



            1. refract when they come in,

            2. (partially) reflect back when they hit the back of the droplet, and then

            3. (partially) refract on their way out.

            For each droplet, though, there are a bunch of rays hitting the droplet at different locations, and each of them will bounce around differently and exit at a different angle, so that the end result looks like this:







            Because there is a reflection inside the droplet, the light is mostly sent backwards, and because there are two steps where refraction happens, the angles are a bit wonky. But here's the important thing: the angle at which the light exits increases, has a maximum, and then decreases again, a fact which is clearly visible by following the dots as they go down from the negative-$x$ axis, stop, and then go back up again.



            This means that if the relative angle between the Sun, the droplet, and your head is smaller than a certain maximal angle $theta_mathrmmax$, usually equal to about $theta_mathrmmaxapprox 42°$, then the droplet will appear bright to you (and, since this isn't an individual droplet but a misty conglomerate, the mist will have a diffuse glow), and if the angle is larger than that, then there will be no extra light going towards your eyes from those droplets.



            In other words, then, this process will produce a disk that's bright, centered at the anti-solar point (i.e. where your eyes receive the on-axis reflections in the diagram above) and with diameter $theta_mathrmmaxapprox 42°$, and this is precisely what's observed, particularly when the rainbow happens against a darker background:





            Image source



            Notice, in particular, that the inside of the (primary) rainbow is much brighter than the outside.



            Moreover, notice that the brightness of this disk increases as you go from the center to the edge: this is caused because the rays cluster at the turning point at $theta_mathrmmax$ (notice in the ray diagram that there's many more dots in that region than there are near the axis). This clustering means that, for each color, the disk of light has a particularly bright edge, called a caustic.



            So what's with the colors?



            Although your diagram's geometry is off, as you correctly note, the standard diagram (the first figure in this answer) is kind of misleading, because for it kind of implies that for every red ray that hits your eyes, there will be another droplet at another angle sending a yellow ray (or green, blue, orange, indigo, and so on) on the same path ─ and that is indeed correct! This is what happens inside this disk of light.



            The thing with this process, though, is that the maximal angle of aperture of the cone of light that's reflected by each droplet depends very sensitively on the refractive index of the water that makes up the droplet, and this refractive index also depends on the wavelength of the light, so that the size of the disk increases with the wavelength, with the red disk being the largest, then the orange, yellow, green, blue, indigo and violet being successively smaller.



            This means that, at the edge of the disk produced by the red light, where it is the brightest, there is no light of other colours to compete with it, so the light looks red there.



            A bit closer in, at the edge of the orange disk, there is no light of yellow, green, or blue colors, since those disks are smaller ─ and, also, the light from the red disk is fainter, because it's not at the maximal-brightness edge and the orange disk does have its maximum shine there. Thus, at that location, the orange light wins out, and the light looks overall orange.



            And so on down the line: for each color in the spectrum, the edge of the disk is brighter than the larger disks, and the smaller disks don't contribute at all, so the edge of each disk shines with its respective color.






            share|cite|improve this answer









            $endgroup$



            This isn't quite how rainbows work. The standard explanation is that light bounces around inside each droplet, and getting reflected once, and exiting at an angle:






            Image source




            However, the real picture is a little bit more complicated. When sunlight hits a water droplet, the rays will



            1. refract when they come in,

            2. (partially) reflect back when they hit the back of the droplet, and then

            3. (partially) refract on their way out.

            For each droplet, though, there are a bunch of rays hitting the droplet at different locations, and each of them will bounce around differently and exit at a different angle, so that the end result looks like this:







            Because there is a reflection inside the droplet, the light is mostly sent backwards, and because there are two steps where refraction happens, the angles are a bit wonky. But here's the important thing: the angle at which the light exits increases, has a maximum, and then decreases again, a fact which is clearly visible by following the dots as they go down from the negative-$x$ axis, stop, and then go back up again.



            This means that if the relative angle between the Sun, the droplet, and your head is smaller than a certain maximal angle $theta_mathrmmax$, usually equal to about $theta_mathrmmaxapprox 42°$, then the droplet will appear bright to you (and, since this isn't an individual droplet but a misty conglomerate, the mist will have a diffuse glow), and if the angle is larger than that, then there will be no extra light going towards your eyes from those droplets.



            In other words, then, this process will produce a disk that's bright, centered at the anti-solar point (i.e. where your eyes receive the on-axis reflections in the diagram above) and with diameter $theta_mathrmmaxapprox 42°$, and this is precisely what's observed, particularly when the rainbow happens against a darker background:





            Image source



            Notice, in particular, that the inside of the (primary) rainbow is much brighter than the outside.



            Moreover, notice that the brightness of this disk increases as you go from the center to the edge: this is caused because the rays cluster at the turning point at $theta_mathrmmax$ (notice in the ray diagram that there's many more dots in that region than there are near the axis). This clustering means that, for each color, the disk of light has a particularly bright edge, called a caustic.



            So what's with the colors?



            Although your diagram's geometry is off, as you correctly note, the standard diagram (the first figure in this answer) is kind of misleading, because for it kind of implies that for every red ray that hits your eyes, there will be another droplet at another angle sending a yellow ray (or green, blue, orange, indigo, and so on) on the same path ─ and that is indeed correct! This is what happens inside this disk of light.



            The thing with this process, though, is that the maximal angle of aperture of the cone of light that's reflected by each droplet depends very sensitively on the refractive index of the water that makes up the droplet, and this refractive index also depends on the wavelength of the light, so that the size of the disk increases with the wavelength, with the red disk being the largest, then the orange, yellow, green, blue, indigo and violet being successively smaller.



            This means that, at the edge of the disk produced by the red light, where it is the brightest, there is no light of other colours to compete with it, so the light looks red there.



            A bit closer in, at the edge of the orange disk, there is no light of yellow, green, or blue colors, since those disks are smaller ─ and, also, the light from the red disk is fainter, because it's not at the maximal-brightness edge and the orange disk does have its maximum shine there. Thus, at that location, the orange light wins out, and the light looks overall orange.



            And so on down the line: for each color in the spectrum, the edge of the disk is brighter than the larger disks, and the smaller disks don't contribute at all, so the edge of each disk shines with its respective color.







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered 7 hours ago









            Emilio PisantyEmilio Pisanty

            89.9k23 gold badges227 silver badges465 bronze badges




            89.9k23 gold badges227 silver badges465 bronze badges














            • $begingroup$
              That's a fascinating explanation! But probably not quite what was confusing the OP.
              $endgroup$
              – Henning Makholm
              7 hours ago
















            • $begingroup$
              That's a fascinating explanation! But probably not quite what was confusing the OP.
              $endgroup$
              – Henning Makholm
              7 hours ago















            $begingroup$
            That's a fascinating explanation! But probably not quite what was confusing the OP.
            $endgroup$
            – Henning Makholm
            7 hours ago




            $begingroup$
            That's a fascinating explanation! But probably not quite what was confusing the OP.
            $endgroup$
            – Henning Makholm
            7 hours ago

















            draft saved

            draft discarded
















































            Thanks for contributing an answer to Physics Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f496441%2fwhy-arent-rainbows-blurred-out-into-nothing-after-they-are-produced%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Invision Community Contents History See also References External links Navigation menuProprietaryinvisioncommunity.comIPS Community ForumsIPS Community Forumsthis blog entry"License Changes, IP.Board 3.4, and the Future""Interview -- Matt Mecham of Ibforums""CEO Invision Power Board, Matt Mecham Is a Liar, Thief!"IPB License Explanation 1.3, 1.3.1, 2.0, and 2.1ArchivedSecurity Fixes, Updates And Enhancements For IPB 1.3.1Archived"New Demo Accounts - Invision Power Services"the original"New Default Skin"the original"Invision Power Board 3.0.0 and Applications Released"the original"Archived copy"the original"Perpetual licenses being done away with""Release Notes - Invision Power Services""Introducing: IPS Community Suite 4!"Invision Community Release Notes

            Canceling a color specificationRandomly assigning color to Graphics3D objects?Default color for Filling in Mathematica 9Coloring specific elements of sets with a prime modified order in an array plotHow to pick a color differing significantly from the colors already in a given color list?Detection of the text colorColor numbers based on their valueCan color schemes for use with ColorData include opacity specification?My dynamic color schemes

            Tom Holland Mục lục Đầu đời và giáo dục | Sự nghiệp | Cuộc sống cá nhân | Phim tham gia | Giải thưởng và đề cử | Chú thích | Liên kết ngoài | Trình đơn chuyển hướngProfile“Person Details for Thomas Stanley Holland, "England and Wales Birth Registration Index, 1837-2008" — FamilySearch.org”"Meet Tom Holland... the 16-year-old star of The Impossible""Schoolboy actor Tom Holland finds himself in Oscar contention for role in tsunami drama"“Naomi Watts on the Prince William and Harry's reaction to her film about the late Princess Diana”lưu trữ"Holland and Pflueger Are West End's Two New 'Billy Elliots'""I'm so envious of my son, the movie star! British writer Dominic Holland's spent 20 years trying to crack Hollywood - but he's been beaten to it by a very unlikely rival"“Richard and Margaret Povey of Jersey, Channel Islands, UK: Information about Thomas Stanley Holland”"Tom Holland to play Billy Elliot""New Billy Elliot leaving the garage"Billy Elliot the Musical - Tom Holland - Billy"A Tale of four Billys: Tom Holland""The Feel Good Factor""Thames Christian College schoolboys join Myleene Klass for The Feelgood Factor""Government launches £600,000 arts bursaries pilot""BILLY's Chapman, Holland, Gardner & Jackson-Keen Visit Prime Minister""Elton John 'blown away' by Billy Elliot fifth birthday" (video with John's interview and fragments of Holland's performance)"First News interviews Arrietty's Tom Holland"“33rd Critics' Circle Film Awards winners”“National Board of Review Current Awards”Bản gốc"Ron Howard Whaling Tale 'In The Heart Of The Sea' Casts Tom Holland"“'Spider-Man' Finds Tom Holland to Star as New Web-Slinger”lưu trữ“Captain America: Civil War (2016)”“Film Review: ‘Captain America: Civil War’”lưu trữ“‘Captain America: Civil War’ review: Choose your own avenger”lưu trữ“The Lost City of Z reviews”“Sony Pictures and Marvel Studios Find Their 'Spider-Man' Star and Director”“‘Mary Magdalene’, ‘Current War’ & ‘Wind River’ Get 2017 Release Dates From Weinstein”“Lionsgate Unleashing Daisy Ridley & Tom Holland Starrer ‘Chaos Walking’ In Cannes”“PTA's 'Master' Leads Chicago Film Critics Nominations, UPDATED: Houston and Indiana Critics Nominations”“Nominaciones Goya 2013 Telecinco Cinema – ENG”“Jameson Empire Film Awards: Martin Freeman wins best actor for performance in The Hobbit”“34th Annual Young Artist Awards”Bản gốc“Teen Choice Awards 2016—Captain America: Civil War Leads Second Wave of Nominations”“BAFTA Film Award Nominations: ‘La La Land’ Leads Race”“Saturn Awards Nominations 2017: 'Rogue One,' 'Walking Dead' Lead”Tom HollandTom HollandTom HollandTom Hollandmedia.gettyimages.comWorldCat Identities300279794no20130442900000 0004 0355 42791085670554170004732cb16706349t(data)XX5557367