Markov-chain sentence generator in PythonMarkov Chain generatorShakespeare and dictionariesMarkov chain-based word salad generatorMarkov chain text generation in PythonCumulative transition matrix Markov Chain simulationMarkov Chain in PythonSentence generation using Markov ChainsCalculate probability of word occurenceGiven a string and a word dict, find all possible sentences

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Markov-chain sentence generator in Python


Markov Chain generatorShakespeare and dictionariesMarkov chain-based word salad generatorMarkov chain text generation in PythonCumulative transition matrix Markov Chain simulationMarkov Chain in PythonSentence generation using Markov ChainsCalculate probability of word occurenceGiven a string and a word dict, find all possible sentences






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








5












$begingroup$


I wrote a Markov-chain based sentence generator as my first non-trivial Python program. I mainly used C before, so I probably have ignored a lot of Python conventions and features, so any advice would be appreciated.



text-gen.py



import sys
import random

class MarkovChain:
# Class constant that serves as an initial state for the Markov chain
START = ""

# The Markov chain is modelled as a directed graph,
# with the START state acting as the only source,
# and the tranisition probabilities as the graph weights.
#
# The graph is implemented using an adjacency list,
# which in turn is implemented as a dictionary of dictionaries.
#
# self.adjList is a dictionary keyed by all words of the text
# or START (the states). For each key/state, it contains
# another dictionary indexed by the words of the text
# that succeed the key in the text (the next states in the chain),
# and for each of those words/next states the dictionary contains
# the transition probability from the present state to them.
#
# This implementation was chosen because of it being easy to code,
# and offering an easy way to iterate on both the probabilities and
# the words/next states of each dictionary using items().
def __init__(self, file):
self.adjList =

# The totals dictionary is used in calculating the probabilities,
# for every word in the text/chain state it contains the total
# number of transitions from it to another state.
totals =


# Start by insering the initial state to the structures
self.adjList[MarkovChain.START] =
totals[MarkovChain.START] = 0

# prev: Contains the previously encountered word or the START state,
# initialized to the START state.
prev = MarkovChain.START


for line in file:
for word in line.split():
# If the word ends with a terminating punctuation mark,
# ignore the mark, and treat the word as a terminating state as
# it does not preceed another word in the current sentence.
# So prev is set to START, in order for the text model
# to account for the fact that some words start sentences
# more frequently than others (not all words are next states of START).
endsTerm = word[-1] == "." or word[-1] == "?" or word[-1] == "!"
if (endsTerm):
word = word[0:-1]

# If this is the first time the word is encountered,
# add it to the adjacency list, and initialize its dictionary
# and transition total.
if (word not in self.adjList):
self.adjList[word] =
totals[word] = 0

# If this is the first time the prev->word transition
# was detected, initialize the prev->word transition frequency to 1,
# else increment it.
if (word in self.adjList[prev]):
self.adjList[prev][word] += 1
else:
self.adjList[prev][word] = 1

# There is a prev->word state transition, so increment
# the total transition number of the prev state.
totals[prev] += 1

if (endsTerm):
prev = START

# Using total, convert the transition frequencies
# to transition probabilities.
for word, neighbors in self.adjList.items():
for name in neighbors:
neighbors[name] /= totals[word]


# chooseNextWord: Chooses the next state/word,
# by sampling the non uniform transition probability distribution
# of the current word/state.
def chooseNextWord(self, curWord):
# Convert the dict_keys object to a list
# to use indexing
nextWords = list(self.adjList[curWord].keys())

# Sampling is done through linear search.
for word in nextWords[0:-1]:
prob = self.adjList[curWord][word]
roll = random.random()
if (roll <= prob):
return word

# If none of the first N-1 words were chosen,
# only the last one was left.
return nextWords[-1]


# genSentence: Generates a sentence. If a positive
# limit is not provided by the caller, the sentences grow to
# an arbitrary number of words, until the last word of a sentence/a terminal state
# is reached.
def genSentence(self, limit = 0):
sentence = ""

curWord = self.chooseNextWord(MarkovChain.START)
sentence += curWord + " "

if (limit > 0):
wordsUsed = 1
while (wordsUsed < limit and self.adjList[curWord]):
curWord = self.chooseNextWord(curWord)
sentence += curWord + " "
wordsUsed += 1
else:
while (self.adjList[curWord]):
curWord = self.chooseNextWord(curWord)
sentence += curWord + " "

return sentence



if (__name__ == "__main__"):
if (len(sys.argv) < 3):
print("Not enough arguements, run with python3 text-gen.py <input-filename> <sentence-num>")
sys.exit(1)

try:
with open(sys.argv[1], "r") as f:
markov = MarkovChain(f)

except OSError as error:
print(error.strerror)
sys.exit(1)

# Generate and print as many sentences as asked.
for k in range(0, int(sys.argv[2])):
print(markov.genSentence(20) + "n")
```









share|improve this question









New contributor



Hashew is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




















    5












    $begingroup$


    I wrote a Markov-chain based sentence generator as my first non-trivial Python program. I mainly used C before, so I probably have ignored a lot of Python conventions and features, so any advice would be appreciated.



    text-gen.py



    import sys
    import random

    class MarkovChain:
    # Class constant that serves as an initial state for the Markov chain
    START = ""

    # The Markov chain is modelled as a directed graph,
    # with the START state acting as the only source,
    # and the tranisition probabilities as the graph weights.
    #
    # The graph is implemented using an adjacency list,
    # which in turn is implemented as a dictionary of dictionaries.
    #
    # self.adjList is a dictionary keyed by all words of the text
    # or START (the states). For each key/state, it contains
    # another dictionary indexed by the words of the text
    # that succeed the key in the text (the next states in the chain),
    # and for each of those words/next states the dictionary contains
    # the transition probability from the present state to them.
    #
    # This implementation was chosen because of it being easy to code,
    # and offering an easy way to iterate on both the probabilities and
    # the words/next states of each dictionary using items().
    def __init__(self, file):
    self.adjList =

    # The totals dictionary is used in calculating the probabilities,
    # for every word in the text/chain state it contains the total
    # number of transitions from it to another state.
    totals =


    # Start by insering the initial state to the structures
    self.adjList[MarkovChain.START] =
    totals[MarkovChain.START] = 0

    # prev: Contains the previously encountered word or the START state,
    # initialized to the START state.
    prev = MarkovChain.START


    for line in file:
    for word in line.split():
    # If the word ends with a terminating punctuation mark,
    # ignore the mark, and treat the word as a terminating state as
    # it does not preceed another word in the current sentence.
    # So prev is set to START, in order for the text model
    # to account for the fact that some words start sentences
    # more frequently than others (not all words are next states of START).
    endsTerm = word[-1] == "." or word[-1] == "?" or word[-1] == "!"
    if (endsTerm):
    word = word[0:-1]

    # If this is the first time the word is encountered,
    # add it to the adjacency list, and initialize its dictionary
    # and transition total.
    if (word not in self.adjList):
    self.adjList[word] =
    totals[word] = 0

    # If this is the first time the prev->word transition
    # was detected, initialize the prev->word transition frequency to 1,
    # else increment it.
    if (word in self.adjList[prev]):
    self.adjList[prev][word] += 1
    else:
    self.adjList[prev][word] = 1

    # There is a prev->word state transition, so increment
    # the total transition number of the prev state.
    totals[prev] += 1

    if (endsTerm):
    prev = START

    # Using total, convert the transition frequencies
    # to transition probabilities.
    for word, neighbors in self.adjList.items():
    for name in neighbors:
    neighbors[name] /= totals[word]


    # chooseNextWord: Chooses the next state/word,
    # by sampling the non uniform transition probability distribution
    # of the current word/state.
    def chooseNextWord(self, curWord):
    # Convert the dict_keys object to a list
    # to use indexing
    nextWords = list(self.adjList[curWord].keys())

    # Sampling is done through linear search.
    for word in nextWords[0:-1]:
    prob = self.adjList[curWord][word]
    roll = random.random()
    if (roll <= prob):
    return word

    # If none of the first N-1 words were chosen,
    # only the last one was left.
    return nextWords[-1]


    # genSentence: Generates a sentence. If a positive
    # limit is not provided by the caller, the sentences grow to
    # an arbitrary number of words, until the last word of a sentence/a terminal state
    # is reached.
    def genSentence(self, limit = 0):
    sentence = ""

    curWord = self.chooseNextWord(MarkovChain.START)
    sentence += curWord + " "

    if (limit > 0):
    wordsUsed = 1
    while (wordsUsed < limit and self.adjList[curWord]):
    curWord = self.chooseNextWord(curWord)
    sentence += curWord + " "
    wordsUsed += 1
    else:
    while (self.adjList[curWord]):
    curWord = self.chooseNextWord(curWord)
    sentence += curWord + " "

    return sentence



    if (__name__ == "__main__"):
    if (len(sys.argv) < 3):
    print("Not enough arguements, run with python3 text-gen.py <input-filename> <sentence-num>")
    sys.exit(1)

    try:
    with open(sys.argv[1], "r") as f:
    markov = MarkovChain(f)

    except OSError as error:
    print(error.strerror)
    sys.exit(1)

    # Generate and print as many sentences as asked.
    for k in range(0, int(sys.argv[2])):
    print(markov.genSentence(20) + "n")
    ```









    share|improve this question









    New contributor



    Hashew is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$
















      5












      5








      5





      $begingroup$


      I wrote a Markov-chain based sentence generator as my first non-trivial Python program. I mainly used C before, so I probably have ignored a lot of Python conventions and features, so any advice would be appreciated.



      text-gen.py



      import sys
      import random

      class MarkovChain:
      # Class constant that serves as an initial state for the Markov chain
      START = ""

      # The Markov chain is modelled as a directed graph,
      # with the START state acting as the only source,
      # and the tranisition probabilities as the graph weights.
      #
      # The graph is implemented using an adjacency list,
      # which in turn is implemented as a dictionary of dictionaries.
      #
      # self.adjList is a dictionary keyed by all words of the text
      # or START (the states). For each key/state, it contains
      # another dictionary indexed by the words of the text
      # that succeed the key in the text (the next states in the chain),
      # and for each of those words/next states the dictionary contains
      # the transition probability from the present state to them.
      #
      # This implementation was chosen because of it being easy to code,
      # and offering an easy way to iterate on both the probabilities and
      # the words/next states of each dictionary using items().
      def __init__(self, file):
      self.adjList =

      # The totals dictionary is used in calculating the probabilities,
      # for every word in the text/chain state it contains the total
      # number of transitions from it to another state.
      totals =


      # Start by insering the initial state to the structures
      self.adjList[MarkovChain.START] =
      totals[MarkovChain.START] = 0

      # prev: Contains the previously encountered word or the START state,
      # initialized to the START state.
      prev = MarkovChain.START


      for line in file:
      for word in line.split():
      # If the word ends with a terminating punctuation mark,
      # ignore the mark, and treat the word as a terminating state as
      # it does not preceed another word in the current sentence.
      # So prev is set to START, in order for the text model
      # to account for the fact that some words start sentences
      # more frequently than others (not all words are next states of START).
      endsTerm = word[-1] == "." or word[-1] == "?" or word[-1] == "!"
      if (endsTerm):
      word = word[0:-1]

      # If this is the first time the word is encountered,
      # add it to the adjacency list, and initialize its dictionary
      # and transition total.
      if (word not in self.adjList):
      self.adjList[word] =
      totals[word] = 0

      # If this is the first time the prev->word transition
      # was detected, initialize the prev->word transition frequency to 1,
      # else increment it.
      if (word in self.adjList[prev]):
      self.adjList[prev][word] += 1
      else:
      self.adjList[prev][word] = 1

      # There is a prev->word state transition, so increment
      # the total transition number of the prev state.
      totals[prev] += 1

      if (endsTerm):
      prev = START

      # Using total, convert the transition frequencies
      # to transition probabilities.
      for word, neighbors in self.adjList.items():
      for name in neighbors:
      neighbors[name] /= totals[word]


      # chooseNextWord: Chooses the next state/word,
      # by sampling the non uniform transition probability distribution
      # of the current word/state.
      def chooseNextWord(self, curWord):
      # Convert the dict_keys object to a list
      # to use indexing
      nextWords = list(self.adjList[curWord].keys())

      # Sampling is done through linear search.
      for word in nextWords[0:-1]:
      prob = self.adjList[curWord][word]
      roll = random.random()
      if (roll <= prob):
      return word

      # If none of the first N-1 words were chosen,
      # only the last one was left.
      return nextWords[-1]


      # genSentence: Generates a sentence. If a positive
      # limit is not provided by the caller, the sentences grow to
      # an arbitrary number of words, until the last word of a sentence/a terminal state
      # is reached.
      def genSentence(self, limit = 0):
      sentence = ""

      curWord = self.chooseNextWord(MarkovChain.START)
      sentence += curWord + " "

      if (limit > 0):
      wordsUsed = 1
      while (wordsUsed < limit and self.adjList[curWord]):
      curWord = self.chooseNextWord(curWord)
      sentence += curWord + " "
      wordsUsed += 1
      else:
      while (self.adjList[curWord]):
      curWord = self.chooseNextWord(curWord)
      sentence += curWord + " "

      return sentence



      if (__name__ == "__main__"):
      if (len(sys.argv) < 3):
      print("Not enough arguements, run with python3 text-gen.py <input-filename> <sentence-num>")
      sys.exit(1)

      try:
      with open(sys.argv[1], "r") as f:
      markov = MarkovChain(f)

      except OSError as error:
      print(error.strerror)
      sys.exit(1)

      # Generate and print as many sentences as asked.
      for k in range(0, int(sys.argv[2])):
      print(markov.genSentence(20) + "n")
      ```









      share|improve this question









      New contributor



      Hashew is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      $endgroup$




      I wrote a Markov-chain based sentence generator as my first non-trivial Python program. I mainly used C before, so I probably have ignored a lot of Python conventions and features, so any advice would be appreciated.



      text-gen.py



      import sys
      import random

      class MarkovChain:
      # Class constant that serves as an initial state for the Markov chain
      START = ""

      # The Markov chain is modelled as a directed graph,
      # with the START state acting as the only source,
      # and the tranisition probabilities as the graph weights.
      #
      # The graph is implemented using an adjacency list,
      # which in turn is implemented as a dictionary of dictionaries.
      #
      # self.adjList is a dictionary keyed by all words of the text
      # or START (the states). For each key/state, it contains
      # another dictionary indexed by the words of the text
      # that succeed the key in the text (the next states in the chain),
      # and for each of those words/next states the dictionary contains
      # the transition probability from the present state to them.
      #
      # This implementation was chosen because of it being easy to code,
      # and offering an easy way to iterate on both the probabilities and
      # the words/next states of each dictionary using items().
      def __init__(self, file):
      self.adjList =

      # The totals dictionary is used in calculating the probabilities,
      # for every word in the text/chain state it contains the total
      # number of transitions from it to another state.
      totals =


      # Start by insering the initial state to the structures
      self.adjList[MarkovChain.START] =
      totals[MarkovChain.START] = 0

      # prev: Contains the previously encountered word or the START state,
      # initialized to the START state.
      prev = MarkovChain.START


      for line in file:
      for word in line.split():
      # If the word ends with a terminating punctuation mark,
      # ignore the mark, and treat the word as a terminating state as
      # it does not preceed another word in the current sentence.
      # So prev is set to START, in order for the text model
      # to account for the fact that some words start sentences
      # more frequently than others (not all words are next states of START).
      endsTerm = word[-1] == "." or word[-1] == "?" or word[-1] == "!"
      if (endsTerm):
      word = word[0:-1]

      # If this is the first time the word is encountered,
      # add it to the adjacency list, and initialize its dictionary
      # and transition total.
      if (word not in self.adjList):
      self.adjList[word] =
      totals[word] = 0

      # If this is the first time the prev->word transition
      # was detected, initialize the prev->word transition frequency to 1,
      # else increment it.
      if (word in self.adjList[prev]):
      self.adjList[prev][word] += 1
      else:
      self.adjList[prev][word] = 1

      # There is a prev->word state transition, so increment
      # the total transition number of the prev state.
      totals[prev] += 1

      if (endsTerm):
      prev = START

      # Using total, convert the transition frequencies
      # to transition probabilities.
      for word, neighbors in self.adjList.items():
      for name in neighbors:
      neighbors[name] /= totals[word]


      # chooseNextWord: Chooses the next state/word,
      # by sampling the non uniform transition probability distribution
      # of the current word/state.
      def chooseNextWord(self, curWord):
      # Convert the dict_keys object to a list
      # to use indexing
      nextWords = list(self.adjList[curWord].keys())

      # Sampling is done through linear search.
      for word in nextWords[0:-1]:
      prob = self.adjList[curWord][word]
      roll = random.random()
      if (roll <= prob):
      return word

      # If none of the first N-1 words were chosen,
      # only the last one was left.
      return nextWords[-1]


      # genSentence: Generates a sentence. If a positive
      # limit is not provided by the caller, the sentences grow to
      # an arbitrary number of words, until the last word of a sentence/a terminal state
      # is reached.
      def genSentence(self, limit = 0):
      sentence = ""

      curWord = self.chooseNextWord(MarkovChain.START)
      sentence += curWord + " "

      if (limit > 0):
      wordsUsed = 1
      while (wordsUsed < limit and self.adjList[curWord]):
      curWord = self.chooseNextWord(curWord)
      sentence += curWord + " "
      wordsUsed += 1
      else:
      while (self.adjList[curWord]):
      curWord = self.chooseNextWord(curWord)
      sentence += curWord + " "

      return sentence



      if (__name__ == "__main__"):
      if (len(sys.argv) < 3):
      print("Not enough arguements, run with python3 text-gen.py <input-filename> <sentence-num>")
      sys.exit(1)

      try:
      with open(sys.argv[1], "r") as f:
      markov = MarkovChain(f)

      except OSError as error:
      print(error.strerror)
      sys.exit(1)

      # Generate and print as many sentences as asked.
      for k in range(0, int(sys.argv[2])):
      print(markov.genSentence(20) + "n")
      ```






      python python-3.x statistics markov-chain






      share|improve this question









      New contributor



      Hashew is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share|improve this question









      New contributor



      Hashew is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share|improve this question




      share|improve this question








      edited 7 hours ago









      vnp

      42.7k2 gold badges35 silver badges109 bronze badges




      42.7k2 gold badges35 silver badges109 bronze badges






      New contributor



      Hashew is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      asked 8 hours ago









      HashewHashew

      534 bronze badges




      534 bronze badges




      New contributor



      Hashew is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




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      Check out our Code of Conduct.

























          2 Answers
          2






          active

          oldest

          votes


















          5












          $begingroup$


          • chooseNextWord distorts the probabilities.



            For example, consider a list of 3 words with the inherent probabilities [⅓, ⅓, ⅓]. The first word is selected with the probability ⅓. The second, however is selected with probability ½ (⅓ that word in the second round is selected, divided by ⅔ that the word in the first round isn't selected). Following the same reasoning, selecting the third word is certain (⅓ that word in the third round is selected, divided by ⅓, the probability that both the first and the second word aren't chosen).



            A standard approach is to compute an accumulated sums of probabilities (in the constructor), then to choose a word roll once, and search for a value just above the rolled one.



          • The code may benefit from using defaultdict rather than a plain dictionaries. Lesser ifs is better.


          • Nitpicking. You may want to account for possible typos, such as a space between a word and a terminating punctuation.






          share|improve this answer











          $endgroup$














          • $begingroup$
            I completely forgot about conditional probability, I will implement sampling using the CDF then. I will look into the rest, thank you.
            $endgroup$
            – Hashew
            7 hours ago







          • 2




            $begingroup$
            @Hashew I rolled back your last edit. It is against the CR chapter to edit the code after a review was posted, because it invalidates the review. You are welcome to post a separate follow-up question.
            $endgroup$
            – vnp
            7 hours ago










          • $begingroup$
            I think this approach based on conditional probability is correct: The probability that a word is chosen on the condition that all of the previous ones weren't is P = (probability that the word was chosen and the previous weren't) / (probability that the previous ones weren't chosen) which is equal to (probability that the word was chosen) / (probability that the previous weren't). So if I initialize a variable (say notPrevProb) to 1 and subtract the probability of each word once I am done with it, I should be able to produce the correct probabilities. What do you think?
            $endgroup$
            – Hashew
            7 hours ago



















          0












          $begingroup$

          endTerms



          When a word ends with an endTerm, think you need to include an START or END symbol in adjList. Most words can appear anywhere in a sentence. So it is unlikely that you can end a sentence only when words don't have any follow-on words. Include the START/END symbol in adjList and the Markov process can also end a sentence.



          the standard library



          collections.defaultdict provides a dictionary that when you attempt to access a new key automatically initializes the new key to a default value.



          collections.Counter provides a dictionary that counts things.



          random.choices selects items from a population according to specified weights.



          import collections
          import random

          class MarkovChain:
          START = ""

          def __init__(self, file):
          adjList = collections.defaultdict(collections.Counter)

          # this inserts START into the defaultdict
          adjList[MarkovChain.START]

          prev = MarkovChain.START

          for line in file:
          for word in line.split():
          endsTerm = word[-1] in ('.', '?', '!')

          if (endsTerm):
          word = word[:-1]

          adjList[prev].update([word])

          if endsTerm:
          # mark the end of a sentence
          adjList[word].update([MarkovChain.START])
          prev = MarkovChain.START
          else:
          prev = word

          # convert defaultdict to a regular dict
          # the values are a tuple: ([follow words], [counts])
          # for use in random.choices() in chooseNextWord()
          self.adjList = k:(list(v.keys()), list(v.values()))
          for k,v in adjList.items()

          #print(self.adjList)


          def chooseNextWord(self, word):
          # random.choices returns a list, hence the [0]
          return random.choices(*self.adjList[word])[0]


          def genSentence(self, limit = 0):
          sentence = []
          curWord = MarkovChain.START

          while True:
          curWord = self.chooseNextWord(curWord)
          sentence.append(curWord)

          if 0 < limit < len(sentence) or curWord == MarkovChain.START:
          break

          return ' '.join(sentence).strip()





          share|improve this answer









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            $begingroup$


            • chooseNextWord distorts the probabilities.



              For example, consider a list of 3 words with the inherent probabilities [⅓, ⅓, ⅓]. The first word is selected with the probability ⅓. The second, however is selected with probability ½ (⅓ that word in the second round is selected, divided by ⅔ that the word in the first round isn't selected). Following the same reasoning, selecting the third word is certain (⅓ that word in the third round is selected, divided by ⅓, the probability that both the first and the second word aren't chosen).



              A standard approach is to compute an accumulated sums of probabilities (in the constructor), then to choose a word roll once, and search for a value just above the rolled one.



            • The code may benefit from using defaultdict rather than a plain dictionaries. Lesser ifs is better.


            • Nitpicking. You may want to account for possible typos, such as a space between a word and a terminating punctuation.






            share|improve this answer











            $endgroup$














            • $begingroup$
              I completely forgot about conditional probability, I will implement sampling using the CDF then. I will look into the rest, thank you.
              $endgroup$
              – Hashew
              7 hours ago







            • 2




              $begingroup$
              @Hashew I rolled back your last edit. It is against the CR chapter to edit the code after a review was posted, because it invalidates the review. You are welcome to post a separate follow-up question.
              $endgroup$
              – vnp
              7 hours ago










            • $begingroup$
              I think this approach based on conditional probability is correct: The probability that a word is chosen on the condition that all of the previous ones weren't is P = (probability that the word was chosen and the previous weren't) / (probability that the previous ones weren't chosen) which is equal to (probability that the word was chosen) / (probability that the previous weren't). So if I initialize a variable (say notPrevProb) to 1 and subtract the probability of each word once I am done with it, I should be able to produce the correct probabilities. What do you think?
              $endgroup$
              – Hashew
              7 hours ago
















            5












            $begingroup$


            • chooseNextWord distorts the probabilities.



              For example, consider a list of 3 words with the inherent probabilities [⅓, ⅓, ⅓]. The first word is selected with the probability ⅓. The second, however is selected with probability ½ (⅓ that word in the second round is selected, divided by ⅔ that the word in the first round isn't selected). Following the same reasoning, selecting the third word is certain (⅓ that word in the third round is selected, divided by ⅓, the probability that both the first and the second word aren't chosen).



              A standard approach is to compute an accumulated sums of probabilities (in the constructor), then to choose a word roll once, and search for a value just above the rolled one.



            • The code may benefit from using defaultdict rather than a plain dictionaries. Lesser ifs is better.


            • Nitpicking. You may want to account for possible typos, such as a space between a word and a terminating punctuation.






            share|improve this answer











            $endgroup$














            • $begingroup$
              I completely forgot about conditional probability, I will implement sampling using the CDF then. I will look into the rest, thank you.
              $endgroup$
              – Hashew
              7 hours ago







            • 2




              $begingroup$
              @Hashew I rolled back your last edit. It is against the CR chapter to edit the code after a review was posted, because it invalidates the review. You are welcome to post a separate follow-up question.
              $endgroup$
              – vnp
              7 hours ago










            • $begingroup$
              I think this approach based on conditional probability is correct: The probability that a word is chosen on the condition that all of the previous ones weren't is P = (probability that the word was chosen and the previous weren't) / (probability that the previous ones weren't chosen) which is equal to (probability that the word was chosen) / (probability that the previous weren't). So if I initialize a variable (say notPrevProb) to 1 and subtract the probability of each word once I am done with it, I should be able to produce the correct probabilities. What do you think?
              $endgroup$
              – Hashew
              7 hours ago














            5












            5








            5





            $begingroup$


            • chooseNextWord distorts the probabilities.



              For example, consider a list of 3 words with the inherent probabilities [⅓, ⅓, ⅓]. The first word is selected with the probability ⅓. The second, however is selected with probability ½ (⅓ that word in the second round is selected, divided by ⅔ that the word in the first round isn't selected). Following the same reasoning, selecting the third word is certain (⅓ that word in the third round is selected, divided by ⅓, the probability that both the first and the second word aren't chosen).



              A standard approach is to compute an accumulated sums of probabilities (in the constructor), then to choose a word roll once, and search for a value just above the rolled one.



            • The code may benefit from using defaultdict rather than a plain dictionaries. Lesser ifs is better.


            • Nitpicking. You may want to account for possible typos, such as a space between a word and a terminating punctuation.






            share|improve this answer











            $endgroup$




            • chooseNextWord distorts the probabilities.



              For example, consider a list of 3 words with the inherent probabilities [⅓, ⅓, ⅓]. The first word is selected with the probability ⅓. The second, however is selected with probability ½ (⅓ that word in the second round is selected, divided by ⅔ that the word in the first round isn't selected). Following the same reasoning, selecting the third word is certain (⅓ that word in the third round is selected, divided by ⅓, the probability that both the first and the second word aren't chosen).



              A standard approach is to compute an accumulated sums of probabilities (in the constructor), then to choose a word roll once, and search for a value just above the rolled one.



            • The code may benefit from using defaultdict rather than a plain dictionaries. Lesser ifs is better.


            • Nitpicking. You may want to account for possible typos, such as a space between a word and a terminating punctuation.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 6 hours ago









            Toby Speight

            31.1k7 gold badges45 silver badges135 bronze badges




            31.1k7 gold badges45 silver badges135 bronze badges










            answered 8 hours ago









            vnpvnp

            42.7k2 gold badges35 silver badges109 bronze badges




            42.7k2 gold badges35 silver badges109 bronze badges














            • $begingroup$
              I completely forgot about conditional probability, I will implement sampling using the CDF then. I will look into the rest, thank you.
              $endgroup$
              – Hashew
              7 hours ago







            • 2




              $begingroup$
              @Hashew I rolled back your last edit. It is against the CR chapter to edit the code after a review was posted, because it invalidates the review. You are welcome to post a separate follow-up question.
              $endgroup$
              – vnp
              7 hours ago










            • $begingroup$
              I think this approach based on conditional probability is correct: The probability that a word is chosen on the condition that all of the previous ones weren't is P = (probability that the word was chosen and the previous weren't) / (probability that the previous ones weren't chosen) which is equal to (probability that the word was chosen) / (probability that the previous weren't). So if I initialize a variable (say notPrevProb) to 1 and subtract the probability of each word once I am done with it, I should be able to produce the correct probabilities. What do you think?
              $endgroup$
              – Hashew
              7 hours ago

















            • $begingroup$
              I completely forgot about conditional probability, I will implement sampling using the CDF then. I will look into the rest, thank you.
              $endgroup$
              – Hashew
              7 hours ago







            • 2




              $begingroup$
              @Hashew I rolled back your last edit. It is against the CR chapter to edit the code after a review was posted, because it invalidates the review. You are welcome to post a separate follow-up question.
              $endgroup$
              – vnp
              7 hours ago










            • $begingroup$
              I think this approach based on conditional probability is correct: The probability that a word is chosen on the condition that all of the previous ones weren't is P = (probability that the word was chosen and the previous weren't) / (probability that the previous ones weren't chosen) which is equal to (probability that the word was chosen) / (probability that the previous weren't). So if I initialize a variable (say notPrevProb) to 1 and subtract the probability of each word once I am done with it, I should be able to produce the correct probabilities. What do you think?
              $endgroup$
              – Hashew
              7 hours ago
















            $begingroup$
            I completely forgot about conditional probability, I will implement sampling using the CDF then. I will look into the rest, thank you.
            $endgroup$
            – Hashew
            7 hours ago





            $begingroup$
            I completely forgot about conditional probability, I will implement sampling using the CDF then. I will look into the rest, thank you.
            $endgroup$
            – Hashew
            7 hours ago





            2




            2




            $begingroup$
            @Hashew I rolled back your last edit. It is against the CR chapter to edit the code after a review was posted, because it invalidates the review. You are welcome to post a separate follow-up question.
            $endgroup$
            – vnp
            7 hours ago




            $begingroup$
            @Hashew I rolled back your last edit. It is against the CR chapter to edit the code after a review was posted, because it invalidates the review. You are welcome to post a separate follow-up question.
            $endgroup$
            – vnp
            7 hours ago












            $begingroup$
            I think this approach based on conditional probability is correct: The probability that a word is chosen on the condition that all of the previous ones weren't is P = (probability that the word was chosen and the previous weren't) / (probability that the previous ones weren't chosen) which is equal to (probability that the word was chosen) / (probability that the previous weren't). So if I initialize a variable (say notPrevProb) to 1 and subtract the probability of each word once I am done with it, I should be able to produce the correct probabilities. What do you think?
            $endgroup$
            – Hashew
            7 hours ago





            $begingroup$
            I think this approach based on conditional probability is correct: The probability that a word is chosen on the condition that all of the previous ones weren't is P = (probability that the word was chosen and the previous weren't) / (probability that the previous ones weren't chosen) which is equal to (probability that the word was chosen) / (probability that the previous weren't). So if I initialize a variable (say notPrevProb) to 1 and subtract the probability of each word once I am done with it, I should be able to produce the correct probabilities. What do you think?
            $endgroup$
            – Hashew
            7 hours ago














            0












            $begingroup$

            endTerms



            When a word ends with an endTerm, think you need to include an START or END symbol in adjList. Most words can appear anywhere in a sentence. So it is unlikely that you can end a sentence only when words don't have any follow-on words. Include the START/END symbol in adjList and the Markov process can also end a sentence.



            the standard library



            collections.defaultdict provides a dictionary that when you attempt to access a new key automatically initializes the new key to a default value.



            collections.Counter provides a dictionary that counts things.



            random.choices selects items from a population according to specified weights.



            import collections
            import random

            class MarkovChain:
            START = ""

            def __init__(self, file):
            adjList = collections.defaultdict(collections.Counter)

            # this inserts START into the defaultdict
            adjList[MarkovChain.START]

            prev = MarkovChain.START

            for line in file:
            for word in line.split():
            endsTerm = word[-1] in ('.', '?', '!')

            if (endsTerm):
            word = word[:-1]

            adjList[prev].update([word])

            if endsTerm:
            # mark the end of a sentence
            adjList[word].update([MarkovChain.START])
            prev = MarkovChain.START
            else:
            prev = word

            # convert defaultdict to a regular dict
            # the values are a tuple: ([follow words], [counts])
            # for use in random.choices() in chooseNextWord()
            self.adjList = k:(list(v.keys()), list(v.values()))
            for k,v in adjList.items()

            #print(self.adjList)


            def chooseNextWord(self, word):
            # random.choices returns a list, hence the [0]
            return random.choices(*self.adjList[word])[0]


            def genSentence(self, limit = 0):
            sentence = []
            curWord = MarkovChain.START

            while True:
            curWord = self.chooseNextWord(curWord)
            sentence.append(curWord)

            if 0 < limit < len(sentence) or curWord == MarkovChain.START:
            break

            return ' '.join(sentence).strip()





            share|improve this answer









            $endgroup$



















              0












              $begingroup$

              endTerms



              When a word ends with an endTerm, think you need to include an START or END symbol in adjList. Most words can appear anywhere in a sentence. So it is unlikely that you can end a sentence only when words don't have any follow-on words. Include the START/END symbol in adjList and the Markov process can also end a sentence.



              the standard library



              collections.defaultdict provides a dictionary that when you attempt to access a new key automatically initializes the new key to a default value.



              collections.Counter provides a dictionary that counts things.



              random.choices selects items from a population according to specified weights.



              import collections
              import random

              class MarkovChain:
              START = ""

              def __init__(self, file):
              adjList = collections.defaultdict(collections.Counter)

              # this inserts START into the defaultdict
              adjList[MarkovChain.START]

              prev = MarkovChain.START

              for line in file:
              for word in line.split():
              endsTerm = word[-1] in ('.', '?', '!')

              if (endsTerm):
              word = word[:-1]

              adjList[prev].update([word])

              if endsTerm:
              # mark the end of a sentence
              adjList[word].update([MarkovChain.START])
              prev = MarkovChain.START
              else:
              prev = word

              # convert defaultdict to a regular dict
              # the values are a tuple: ([follow words], [counts])
              # for use in random.choices() in chooseNextWord()
              self.adjList = k:(list(v.keys()), list(v.values()))
              for k,v in adjList.items()

              #print(self.adjList)


              def chooseNextWord(self, word):
              # random.choices returns a list, hence the [0]
              return random.choices(*self.adjList[word])[0]


              def genSentence(self, limit = 0):
              sentence = []
              curWord = MarkovChain.START

              while True:
              curWord = self.chooseNextWord(curWord)
              sentence.append(curWord)

              if 0 < limit < len(sentence) or curWord == MarkovChain.START:
              break

              return ' '.join(sentence).strip()





              share|improve this answer









              $endgroup$

















                0












                0








                0





                $begingroup$

                endTerms



                When a word ends with an endTerm, think you need to include an START or END symbol in adjList. Most words can appear anywhere in a sentence. So it is unlikely that you can end a sentence only when words don't have any follow-on words. Include the START/END symbol in adjList and the Markov process can also end a sentence.



                the standard library



                collections.defaultdict provides a dictionary that when you attempt to access a new key automatically initializes the new key to a default value.



                collections.Counter provides a dictionary that counts things.



                random.choices selects items from a population according to specified weights.



                import collections
                import random

                class MarkovChain:
                START = ""

                def __init__(self, file):
                adjList = collections.defaultdict(collections.Counter)

                # this inserts START into the defaultdict
                adjList[MarkovChain.START]

                prev = MarkovChain.START

                for line in file:
                for word in line.split():
                endsTerm = word[-1] in ('.', '?', '!')

                if (endsTerm):
                word = word[:-1]

                adjList[prev].update([word])

                if endsTerm:
                # mark the end of a sentence
                adjList[word].update([MarkovChain.START])
                prev = MarkovChain.START
                else:
                prev = word

                # convert defaultdict to a regular dict
                # the values are a tuple: ([follow words], [counts])
                # for use in random.choices() in chooseNextWord()
                self.adjList = k:(list(v.keys()), list(v.values()))
                for k,v in adjList.items()

                #print(self.adjList)


                def chooseNextWord(self, word):
                # random.choices returns a list, hence the [0]
                return random.choices(*self.adjList[word])[0]


                def genSentence(self, limit = 0):
                sentence = []
                curWord = MarkovChain.START

                while True:
                curWord = self.chooseNextWord(curWord)
                sentence.append(curWord)

                if 0 < limit < len(sentence) or curWord == MarkovChain.START:
                break

                return ' '.join(sentence).strip()





                share|improve this answer









                $endgroup$



                endTerms



                When a word ends with an endTerm, think you need to include an START or END symbol in adjList. Most words can appear anywhere in a sentence. So it is unlikely that you can end a sentence only when words don't have any follow-on words. Include the START/END symbol in adjList and the Markov process can also end a sentence.



                the standard library



                collections.defaultdict provides a dictionary that when you attempt to access a new key automatically initializes the new key to a default value.



                collections.Counter provides a dictionary that counts things.



                random.choices selects items from a population according to specified weights.



                import collections
                import random

                class MarkovChain:
                START = ""

                def __init__(self, file):
                adjList = collections.defaultdict(collections.Counter)

                # this inserts START into the defaultdict
                adjList[MarkovChain.START]

                prev = MarkovChain.START

                for line in file:
                for word in line.split():
                endsTerm = word[-1] in ('.', '?', '!')

                if (endsTerm):
                word = word[:-1]

                adjList[prev].update([word])

                if endsTerm:
                # mark the end of a sentence
                adjList[word].update([MarkovChain.START])
                prev = MarkovChain.START
                else:
                prev = word

                # convert defaultdict to a regular dict
                # the values are a tuple: ([follow words], [counts])
                # for use in random.choices() in chooseNextWord()
                self.adjList = k:(list(v.keys()), list(v.values()))
                for k,v in adjList.items()

                #print(self.adjList)


                def chooseNextWord(self, word):
                # random.choices returns a list, hence the [0]
                return random.choices(*self.adjList[word])[0]


                def genSentence(self, limit = 0):
                sentence = []
                curWord = MarkovChain.START

                while True:
                curWord = self.chooseNextWord(curWord)
                sentence.append(curWord)

                if 0 < limit < len(sentence) or curWord == MarkovChain.START:
                break

                return ' '.join(sentence).strip()






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 1 hour ago









                RootTwoRootTwo

                1,0593 silver badges6 bronze badges




                1,0593 silver badges6 bronze badges























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