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How to construct BezierFunction for BezierCurve with npts>4 and SplineDegree -> 3?
How can I create a ColorFunction using Blend?How to maintain a smooth surface in CDFs while playing?How to draw symmetrical parts of a circleHow to put single points inside the plot?How can I add an arbritrary label to a detail in a Plot or Plot3D?ListPlot with different color optionsProblem in coloring network links with linear gradients through VertexColorsPlanetary motion of a curve within a regionHow can I get high precision circle drawing in Graphics, across ten orders of magnitudeWhy does BezierFunction not follow BezierCurve at npts>4?
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$begingroup$
I would like to use BezierCurve with npts=7 and SplineDegree -> 3 and access its BezierFunction. This code helps:
pts = 0, 0, 1, 1, 2, -1, 3, 0, 5, 2, 6, -1, 7, 3;
f1 = BezierFunction[pts[[1;;4]]]
f2 = BezierFunction[pts[[4;;7]]]
Show[Graphics[Red, Point[pts], Green, Line[pts], Axes -> True],
ParametricPlot[f1[t],f2[t], t, 0, 1],Graphics[Blue, Dashed,
BezierCurve[pts, SplineDegree -> 3]]]
Can it be done better, defining f as a single function, whose plot is BezierCurve?
graphics splines
edited 7 hours ago
Alexey Popkov
39.2k4 gold badges111 silver badges271 bronze badges
asked 8 hours ago
IgorIgor
511 bronze badge
New contributor
Igor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I would like to use BezierCurve with npts=7 and SplineDegree -> 3 and access its BezierFunction. This code helps:
pts = 0, 0, 1, 1, 2, -1, 3, 0, 5, 2, 6, -1, 7, 3;
f1 = BezierFunction[pts[[1;;4]]]
f2 = BezierFunction[pts[[4;;7]]]
Show[Graphics[Red, Point[pts], Green, Line[pts], Axes -> True],
ParametricPlot[f1[t],f2[t], t, 0, 1],Graphics[Blue, Dashed,
BezierCurve[pts, SplineDegree -> 3]]]
Can it be done better, defining f as a single function, whose plot is BezierCurve?
graphics splines
edited 7 hours ago
Alexey Popkov
39.2k4 gold badges111 silver badges271 bronze badges
asked 8 hours ago
IgorIgor
511 bronze badge
New contributor
Igor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I would like to use BezierCurve with npts=7 and SplineDegree -> 3 and access its BezierFunction. This code helps:
pts = 0, 0, 1, 1, 2, -1, 3, 0, 5, 2, 6, -1, 7, 3;
f1 = BezierFunction[pts[[1;;4]]]
f2 = BezierFunction[pts[[4;;7]]]
Show[Graphics[Red, Point[pts], Green, Line[pts], Axes -> True],
ParametricPlot[f1[t],f2[t], t, 0, 1],Graphics[Blue, Dashed,
BezierCurve[pts, SplineDegree -> 3]]]
Can it be done better, defining f as a single function, whose plot is BezierCurve?
graphics splines
edited 7 hours ago
Alexey Popkov
39.2k4 gold badges111 silver badges271 bronze badges
asked 8 hours ago
IgorIgor
511 bronze badge
New contributor
Igor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I would like to use BezierCurve with npts=7 and SplineDegree -> 3 and access its BezierFunction. This code helps:
pts = 0, 0, 1, 1, 2, -1, 3, 0, 5, 2, 6, -1, 7, 3;
f1 = BezierFunction[pts[[1;;4]]]
f2 = BezierFunction[pts[[4;;7]]]
Show[Graphics[Red, Point[pts], Green, Line[pts], Axes -> True],
ParametricPlot[f1[t],f2[t], t, 0, 1],Graphics[Blue, Dashed,
BezierCurve[pts, SplineDegree -> 3]]]
Can it be done better, defining f as a single function, whose plot is BezierCurve?
graphics splines
graphics splines
edited 7 hours ago
Alexey Popkov
39.2k4 gold badges111 silver badges271 bronze badges
asked 8 hours ago
IgorIgor
511 bronze badge
New contributor
Igor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 7 hours ago
Alexey Popkov
39.2k4 gold badges111 silver badges271 bronze badges
asked 8 hours ago
IgorIgor
511 bronze badge
New contributor
Igor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 7 hours ago
Alexey Popkov
39.2k4 gold badges111 silver badges271 bronze badges
edited 7 hours ago
Alexey Popkov
39.2k4 gold badges111 silver badges271 bronze badges
edited 7 hours ago
Alexey Popkov
39.2k4 gold badges111 silver badges271 bronze badges
39.2k4 gold badges111 silver badges271 bronze badges
asked 8 hours ago
IgorIgor
511 bronze badge
New contributor
Igor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
IgorIgor
511 bronze badge
asked 8 hours ago
IgorIgor
511 bronze badge
511 bronze badge
New contributor
Igor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Igor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
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$begingroup$
(1) Partition pts into blocks of 4 with offset 3,
(2) Use BezierFunction on each block and
(3) To get a single function, compose Through with the list of Bezier functions.
pts = 0, 0, 1, 1, 2, -1, 3, 0, 5, 2, 6, -1, 7, 3;
f0 = Through @* (BezierFunction /@ Partition[pts, 4, 3]);
Show[Graphics[Red, Point[pts], Green, Line[pts], Axes -> True],
ParametricPlot[f0[t], t, 0, 1, PlotStyle -> Directive[Opacity[.7, Red], Thickness[.01]]],
Graphics[Blue, Dashed, BezierCurve[pts, SplineDegree -> 3]]]
answered 8 hours ago
kglrkglr
209k10 gold badges241 silver badges478 bronze badges
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
(1) Partition pts into blocks of 4 with offset 3,
(2) Use BezierFunction on each block and
(3) To get a single function, compose Through with the list of Bezier functions.
pts = 0, 0, 1, 1, 2, -1, 3, 0, 5, 2, 6, -1, 7, 3;
f0 = Through @* (BezierFunction /@ Partition[pts, 4, 3]);
Show[Graphics[Red, Point[pts], Green, Line[pts], Axes -> True],
ParametricPlot[f0[t], t, 0, 1, PlotStyle -> Directive[Opacity[.7, Red], Thickness[.01]]],
Graphics[Blue, Dashed, BezierCurve[pts, SplineDegree -> 3]]]
answered 8 hours ago
kglrkglr
209k10 gold badges241 silver badges478 bronze badges
$endgroup$
add a comment |
$begingroup$
(1) Partition pts into blocks of 4 with offset 3,
(2) Use BezierFunction on each block and
(3) To get a single function, compose Through with the list of Bezier functions.
pts = 0, 0, 1, 1, 2, -1, 3, 0, 5, 2, 6, -1, 7, 3;
f0 = Through @* (BezierFunction /@ Partition[pts, 4, 3]);
Show[Graphics[Red, Point[pts], Green, Line[pts], Axes -> True],
ParametricPlot[f0[t], t, 0, 1, PlotStyle -> Directive[Opacity[.7, Red], Thickness[.01]]],
Graphics[Blue, Dashed, BezierCurve[pts, SplineDegree -> 3]]]
answered 8 hours ago
kglrkglr
209k10 gold badges241 silver badges478 bronze badges
$endgroup$
add a comment |
$begingroup$
(1) Partition pts into blocks of 4 with offset 3,
(2) Use BezierFunction on each block and
(3) To get a single function, compose Through with the list of Bezier functions.
pts = 0, 0, 1, 1, 2, -1, 3, 0, 5, 2, 6, -1, 7, 3;
f0 = Through @* (BezierFunction /@ Partition[pts, 4, 3]);
Show[Graphics[Red, Point[pts], Green, Line[pts], Axes -> True],
ParametricPlot[f0[t], t, 0, 1, PlotStyle -> Directive[Opacity[.7, Red], Thickness[.01]]],
Graphics[Blue, Dashed, BezierCurve[pts, SplineDegree -> 3]]]
answered 8 hours ago
kglrkglr
209k10 gold badges241 silver badges478 bronze badges
$endgroup$
(1) Partition pts into blocks of 4 with offset 3,
(2) Use BezierFunction on each block and
(3) To get a single function, compose Through with the list of Bezier functions.
pts = 0, 0, 1, 1, 2, -1, 3, 0, 5, 2, 6, -1, 7, 3;
f0 = Through @* (BezierFunction /@ Partition[pts, 4, 3]);
Show[Graphics[Red, Point[pts], Green, Line[pts], Axes -> True],
ParametricPlot[f0[t], t, 0, 1, PlotStyle -> Directive[Opacity[.7, Red], Thickness[.01]]],
Graphics[Blue, Dashed, BezierCurve[pts, SplineDegree -> 3]]]
answered 8 hours ago
kglrkglr
209k10 gold badges241 silver badges478 bronze badges
edited 2 hours ago
answered 8 hours ago
kglrkglr
209k10 gold badges241 silver badges478 bronze badges
answered 8 hours ago
kglrkglr
209k10 gold badges241 silver badges478 bronze badges
answered 8 hours ago
kglrkglr
209k10 gold badges241 silver badges478 bronze badges
209k10 gold badges241 silver badges478 bronze badges
add a comment |
add a comment |
Igor is a new contributor. Be nice, and check out our Code of Conduct.
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