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Strange title I know, but you'll understand why quickly.

I wanted to use a black hole to create absurd amounts of power for hopefully obvious reasons (kind of useful). The problem with natural large black holes is that they tend to be heavy and produce less energy per second than small black holes (or that is what I understand, I would expect the larger surface area to mean it generates more energy but have less surface area to volume to release that energy but that doesnt seem to be the case).

The problem with small black holes is that they dissappear on you quickly due to evaporation while you get the energy. So you need to feed them. A very small black hole evaporates almost instantly in a nuclear explosion and they are tiny with swartz radius's measured at then planc scale.

In my story they use a chamber that suspends the black hole, can absorb all the energy of the black hole and convert it into power to run things and the chamber has another function, it can activate and at no energy cost can stop the black hole from evaporating in its entirety. There is no grey area here, it can only stop evaporation completely or normal evaporation occurs. This is all important for the story as part of it takes place inside the room of the black hole and the plot requires at least these things!

The question I have: what is the reasonable maximum power output I can get while feeding the black hole using this system while turning the black hole as little as possible (so you can limit the amount of black holes you need to bring along which can affect the story).

The answer has to explain the following:

• how do you feed the black hole despite it expelling large amounts of energy? (Or why cant you feed it while it is active and need to turn it off to feed it)




• if the black hole needs to be deactivated to be fed, how long does it need to be offline to properly feed it?




• what energy output is this black hole going to give, and based on that how much material needs to be thrown in per second to keep the black hole at that size?




• how do you feed the black hole based on its size?




• what material would be best suited to feed the black hole? (I assume it'll be heavy elements in cases where the black hole is mere hundreds of kilo's in weight)

The best answer will have the most energy output with the least time offline (not amount of times offline, amount of total time offline). In case it is important, the method that offers the highest energy output on average over one cycle of activation, deactivation and feeding is the best answer. For clarity: highest means the most energy per second, rather than the most energy across the entire cycle.

In practice, you may not need to feed it at all - as long as you can deal with a sufficiently hefty mini black-hole. According to wiki a black hole with mass $M$ measured in kg will have:

Power output $P = 3.56times 10^32 M^2$ Watts.

Evaporation time $T = 2.67times 10^-24 M^3$ years.

So a tidy little black hole of mass $10^11$ kg will provide you with a continuous 3.6 GigaWatts. Its evaporation time is 2700 years and it will eventually ramp up its power output, but for the first 2000 years or so the power output won't change significantly. This means that the simplest option is to just use it continuously (and leave it for your great-great-$great^120$ grand children to find a safe way to safely dispose of the remnant.

Of course you could feed it approximately 40 micrograms of matter for every second you leave it 'switched on', in which case it will effectively last forever. But the problem is that your black-hole has a diameter of approximately $1.5times 10^-16$ m, which is about 10 times smaller than a proton, so the absorption cross-section for any kind of matter will be very small. So it is not obvious that you could actually 'feed' it in any practical way - even if your chamber could hand-wavingly stop it from evaporating during the feeding process.

As well as size of the Schwartzchild radius being problematical, the radiation pressure at its surface (about $5 times10^63$ W/m^2) would definitely be a hinderance to poking matter into it, if you didn't stop it from evaporating during feeding.