Heat reduction based on compressionHeat Exchanger CalculationUnderstanding heat pump efficiencyHeat diffusion in a houseWhat is the temperature of compress air entering the atmosphere?For air conditioning, why is it 20BTU/hr/sq ft?Why does the refrigerant release heat when it is compressed into a liquid?Why do objects stop cooling down / losing heat?

How do I get toddlers to stop asking for food every hour?

Is it possible to perform a regression where you have an unknown / unknowable feature variable?

Why does The Ancient One think differently about Doctor Strange in Endgame than the film Doctor Strange?

Does travel insurance for short flight delays exist?

Why in most German places is the church the tallest building?

How do I get a decreased-by-one x in a foreach loop?

If all stars rotate, why was there a theory developed that requires non-rotating stars?

How should I face my manager if I make a mistake because a senior coworker explained something incorrectly to me?

Architectural feasibility of a tiered circular stone keep

How many US airports have 4 or more parallel runways?

What is the difference between "Grippe" and "Männergrippe"?

Why isn't "I've" a proper response?

Why is there so little discussion / research on the philosophy of precision?

Pythagorean triple with hypotenuse a power of 2

How to find out the average duration of the peer-review process for a given journal?

Anatomically Correct Whomping Willow

Who was president of the USA?

Are there any elected officials in the U.S. who are not legislators, judges, or constitutional officers?

Justifying the use of directed energy weapons

Read file lines into shell line separated by space

Antonym of "billable"

How much authority do teachers get from *In Loco Parentis*?

Is for(( ... )) ... ; a valid shell syntax? In which shells?

Understanding Parallelize methods



Heat reduction based on compression


Heat Exchanger CalculationUnderstanding heat pump efficiencyHeat diffusion in a houseWhat is the temperature of compress air entering the atmosphere?For air conditioning, why is it 20BTU/hr/sq ft?Why does the refrigerant release heat when it is compressed into a liquid?Why do objects stop cooling down / losing heat?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1












$begingroup$


So I was thinking about air conditioner today and how we run air across compressed freon to cool down air but why do we need freon at all why not store just compressed air. My guess is because its inefficient.



My question given a 1 cubic meter tank of air, if the room temperature at 1 atmosphere is 80 degrees. At what atmosphere would you have to have the tank so that the initial release of the air would be the temperature 70 degrees?










share|cite|improve this question











$endgroup$




















    1












    $begingroup$


    So I was thinking about air conditioner today and how we run air across compressed freon to cool down air but why do we need freon at all why not store just compressed air. My guess is because its inefficient.



    My question given a 1 cubic meter tank of air, if the room temperature at 1 atmosphere is 80 degrees. At what atmosphere would you have to have the tank so that the initial release of the air would be the temperature 70 degrees?










    share|cite|improve this question











    $endgroup$
















      1












      1








      1





      $begingroup$


      So I was thinking about air conditioner today and how we run air across compressed freon to cool down air but why do we need freon at all why not store just compressed air. My guess is because its inefficient.



      My question given a 1 cubic meter tank of air, if the room temperature at 1 atmosphere is 80 degrees. At what atmosphere would you have to have the tank so that the initial release of the air would be the temperature 70 degrees?










      share|cite|improve this question











      $endgroup$




      So I was thinking about air conditioner today and how we run air across compressed freon to cool down air but why do we need freon at all why not store just compressed air. My guess is because its inefficient.



      My question given a 1 cubic meter tank of air, if the room temperature at 1 atmosphere is 80 degrees. At what atmosphere would you have to have the tank so that the initial release of the air would be the temperature 70 degrees?







      thermodynamics pressure air






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited 5 hours ago







      johnny 5

















      asked 8 hours ago









      johnny 5johnny 5

      2341 gold badge2 silver badges7 bronze badges




      2341 gold badge2 silver badges7 bronze badges























          3 Answers
          3






          active

          oldest

          votes


















          3













          $begingroup$

          Let's first walk you through the usual refrigeration cycle:



          1. We compress the freon, which heats it up. That's because we've put energy into in during the compression: It took work to push the piston.


          2. Next we cool the gas back to room temperature. That's the big black coil on the back of the fridge.


          3. Then we let it expand. The expansion cools the gas, because it does work (energy is removed) as it expands. Since it started at room temperature, it's cooler than room temperature after the expansion.


          4. Finally, we let that cool gas absorb heat energy from whatever we want to keep cold. That warms the gas a bit, and gets us ready to start the cycle again.


          If we didn't have step 2, the expansion in step 3 would just be the reverse of step 1 and get the freon back where it started. But since we did some of the cooling in step 2 (which we can do because it's hot from the compression), we end up with colder-than-room-temperature gas after 3.



          Now, why do we do this with freon? The process I described above is for something like air which stays gaseous throughout. If you use freon (or sometimes ammonia or other chemicals) that will switch between gas and liquid during the process, it becomes more efficient. The physics is still basically the same, it's just that the boiling and condensing can transfer more heat energy without having to use really high pressures.



          Back to a gas like air: If you want to calculate how much it chills as it expands, you're talking about "adiabatic expansion". The Wikipedia article is a good starting point. For that operation, there's a relation between the initial and final pressure and temperature:



          $$P_i^1-gammaT_i^gamma = P_f^1-gammaT_f^gamma$$



          Where $gamma = 1.6$ is a constant value for air. If we take the initial temperature to be roughly 80F or 300K, the final temp to be 70F or 295K and the final pressure to be $P_A = 10^5$ for atmospheric, then



          $$ P_i = P_f (T_f/T_i)^gamma/(1-gamma) $$



          $$ P_i = (10^5) (295/300)^1.6/(-0.6) = 106,000$$



          That's a messy calculation, but because of the exponents ends up being that about a 6% increase in the pressure, when let out, will given you a 10F decrease in the temperature. In US units, that's from 14.7 PSIA to 15.6 PSAI; not all that much. Of course, a 10F drop isn't really enough to run a refrigerator that you'd really want...






          share|cite|improve this answer











          $endgroup$






















            2













            $begingroup$


            Compression brings the molecules closer together thus cooling it down.




            This isn't correct. The temperature of a gas isn't related to how close together the molecules are, but their speed.



            By compressing the gas, they are closer together, but the work done in compression has sped them up as well. If you wait a while and let the gas cool, they'll still be closer together, but will be moving at the original speed.




            My question is given air pressure at sea level. 80 degrees at 14.70 psi, how much pressure would you have to add to cool the air to 70 degrees if it was stored in a tank for 1 cubic meter?




            There is no such pressure. Applying pressure will increase the temperature in the short term, not lower it. Any temperature change by doing this is only temporary. The gas will then exchange heat with the environment and move to ambient temperature.






            share|cite|improve this answer









            $endgroup$














            • $begingroup$
              Thank you for clarifying my misunderstanding, I've made a minor edit to clarify the question, If you waited until the tank, cooled back down to room temperature, How much pressure would be needed so that when releasing the gas, it came out 10 degrees cooler?
              $endgroup$
              – johnny 5
              6 hours ago


















            1













            $begingroup$

            I will address the use of air rather than freon (or its current replacement) as a refrigerant. I believe @BowlOfRed has satisfactorily answered your other questions.



            Air is not used as a refrigerant because it would not be practical. This is because a refrigerator requires the use of a working fluid that can undergo phase changes (gas to liquid in condenser, liquid to gas in evaporator) at practical operating pressures and temperatures. Air cannot undergo phase changes except at extremely low temperatures.



            For example, at 1 atmosphere the boiling/condensing point of refrigerant HFC-134a (which has replaced freon for environmental reasons) is about -25 C (-13 F). This is somewhat lower than the setting of a household freezer. In contrast, the boiling/condensing point of liquid air at 1 atmosphere is -194.4 C. In order to increase the boiling/condensing temperature to that required by the refrigerator, extremely impractically high pressure would be required.



            Hope this helps.






            share|cite|improve this answer









            $endgroup$














            • $begingroup$
              Thanks, I'm learning alot about thermodynamics today. I see that it would be impractical to do such a thing. But to cool the air down 10 degrees I don't think you would need to store the air in liquid form. e.g if the air at 1 atmosphere is 80 degrees, and you have air store at 2 atomsphere at 80 degrees, upon expansion what would the temperature of the air be?
              $endgroup$
              – johnny 5
              5 hours ago










            • $begingroup$
              e.g in this example, pass air over cool pipe, you would just release the air back into the environment at a lower temperature
              $endgroup$
              – johnny 5
              5 hours ago













            Your Answer








            StackExchange.ready(function()
            var channelOptions =
            tags: "".split(" "),
            id: "151"
            ;
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function()
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled)
            StackExchange.using("snippets", function()
            createEditor();
            );

            else
            createEditor();

            );

            function createEditor()
            StackExchange.prepareEditor(
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: false,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: null,
            bindNavPrevention: true,
            postfix: "",
            imageUploader:
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            ,
            noCode: true, onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            );



            );













            draft saved

            draft discarded


















            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f498395%2fheat-reduction-based-on-compression%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown

























            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3













            $begingroup$

            Let's first walk you through the usual refrigeration cycle:



            1. We compress the freon, which heats it up. That's because we've put energy into in during the compression: It took work to push the piston.


            2. Next we cool the gas back to room temperature. That's the big black coil on the back of the fridge.


            3. Then we let it expand. The expansion cools the gas, because it does work (energy is removed) as it expands. Since it started at room temperature, it's cooler than room temperature after the expansion.


            4. Finally, we let that cool gas absorb heat energy from whatever we want to keep cold. That warms the gas a bit, and gets us ready to start the cycle again.


            If we didn't have step 2, the expansion in step 3 would just be the reverse of step 1 and get the freon back where it started. But since we did some of the cooling in step 2 (which we can do because it's hot from the compression), we end up with colder-than-room-temperature gas after 3.



            Now, why do we do this with freon? The process I described above is for something like air which stays gaseous throughout. If you use freon (or sometimes ammonia or other chemicals) that will switch between gas and liquid during the process, it becomes more efficient. The physics is still basically the same, it's just that the boiling and condensing can transfer more heat energy without having to use really high pressures.



            Back to a gas like air: If you want to calculate how much it chills as it expands, you're talking about "adiabatic expansion". The Wikipedia article is a good starting point. For that operation, there's a relation between the initial and final pressure and temperature:



            $$P_i^1-gammaT_i^gamma = P_f^1-gammaT_f^gamma$$



            Where $gamma = 1.6$ is a constant value for air. If we take the initial temperature to be roughly 80F or 300K, the final temp to be 70F or 295K and the final pressure to be $P_A = 10^5$ for atmospheric, then



            $$ P_i = P_f (T_f/T_i)^gamma/(1-gamma) $$



            $$ P_i = (10^5) (295/300)^1.6/(-0.6) = 106,000$$



            That's a messy calculation, but because of the exponents ends up being that about a 6% increase in the pressure, when let out, will given you a 10F decrease in the temperature. In US units, that's from 14.7 PSIA to 15.6 PSAI; not all that much. Of course, a 10F drop isn't really enough to run a refrigerator that you'd really want...






            share|cite|improve this answer











            $endgroup$



















              3













              $begingroup$

              Let's first walk you through the usual refrigeration cycle:



              1. We compress the freon, which heats it up. That's because we've put energy into in during the compression: It took work to push the piston.


              2. Next we cool the gas back to room temperature. That's the big black coil on the back of the fridge.


              3. Then we let it expand. The expansion cools the gas, because it does work (energy is removed) as it expands. Since it started at room temperature, it's cooler than room temperature after the expansion.


              4. Finally, we let that cool gas absorb heat energy from whatever we want to keep cold. That warms the gas a bit, and gets us ready to start the cycle again.


              If we didn't have step 2, the expansion in step 3 would just be the reverse of step 1 and get the freon back where it started. But since we did some of the cooling in step 2 (which we can do because it's hot from the compression), we end up with colder-than-room-temperature gas after 3.



              Now, why do we do this with freon? The process I described above is for something like air which stays gaseous throughout. If you use freon (or sometimes ammonia or other chemicals) that will switch between gas and liquid during the process, it becomes more efficient. The physics is still basically the same, it's just that the boiling and condensing can transfer more heat energy without having to use really high pressures.



              Back to a gas like air: If you want to calculate how much it chills as it expands, you're talking about "adiabatic expansion". The Wikipedia article is a good starting point. For that operation, there's a relation between the initial and final pressure and temperature:



              $$P_i^1-gammaT_i^gamma = P_f^1-gammaT_f^gamma$$



              Where $gamma = 1.6$ is a constant value for air. If we take the initial temperature to be roughly 80F or 300K, the final temp to be 70F or 295K and the final pressure to be $P_A = 10^5$ for atmospheric, then



              $$ P_i = P_f (T_f/T_i)^gamma/(1-gamma) $$



              $$ P_i = (10^5) (295/300)^1.6/(-0.6) = 106,000$$



              That's a messy calculation, but because of the exponents ends up being that about a 6% increase in the pressure, when let out, will given you a 10F decrease in the temperature. In US units, that's from 14.7 PSIA to 15.6 PSAI; not all that much. Of course, a 10F drop isn't really enough to run a refrigerator that you'd really want...






              share|cite|improve this answer











              $endgroup$

















                3














                3










                3







                $begingroup$

                Let's first walk you through the usual refrigeration cycle:



                1. We compress the freon, which heats it up. That's because we've put energy into in during the compression: It took work to push the piston.


                2. Next we cool the gas back to room temperature. That's the big black coil on the back of the fridge.


                3. Then we let it expand. The expansion cools the gas, because it does work (energy is removed) as it expands. Since it started at room temperature, it's cooler than room temperature after the expansion.


                4. Finally, we let that cool gas absorb heat energy from whatever we want to keep cold. That warms the gas a bit, and gets us ready to start the cycle again.


                If we didn't have step 2, the expansion in step 3 would just be the reverse of step 1 and get the freon back where it started. But since we did some of the cooling in step 2 (which we can do because it's hot from the compression), we end up with colder-than-room-temperature gas after 3.



                Now, why do we do this with freon? The process I described above is for something like air which stays gaseous throughout. If you use freon (or sometimes ammonia or other chemicals) that will switch between gas and liquid during the process, it becomes more efficient. The physics is still basically the same, it's just that the boiling and condensing can transfer more heat energy without having to use really high pressures.



                Back to a gas like air: If you want to calculate how much it chills as it expands, you're talking about "adiabatic expansion". The Wikipedia article is a good starting point. For that operation, there's a relation between the initial and final pressure and temperature:



                $$P_i^1-gammaT_i^gamma = P_f^1-gammaT_f^gamma$$



                Where $gamma = 1.6$ is a constant value for air. If we take the initial temperature to be roughly 80F or 300K, the final temp to be 70F or 295K and the final pressure to be $P_A = 10^5$ for atmospheric, then



                $$ P_i = P_f (T_f/T_i)^gamma/(1-gamma) $$



                $$ P_i = (10^5) (295/300)^1.6/(-0.6) = 106,000$$



                That's a messy calculation, but because of the exponents ends up being that about a 6% increase in the pressure, when let out, will given you a 10F decrease in the temperature. In US units, that's from 14.7 PSIA to 15.6 PSAI; not all that much. Of course, a 10F drop isn't really enough to run a refrigerator that you'd really want...






                share|cite|improve this answer











                $endgroup$



                Let's first walk you through the usual refrigeration cycle:



                1. We compress the freon, which heats it up. That's because we've put energy into in during the compression: It took work to push the piston.


                2. Next we cool the gas back to room temperature. That's the big black coil on the back of the fridge.


                3. Then we let it expand. The expansion cools the gas, because it does work (energy is removed) as it expands. Since it started at room temperature, it's cooler than room temperature after the expansion.


                4. Finally, we let that cool gas absorb heat energy from whatever we want to keep cold. That warms the gas a bit, and gets us ready to start the cycle again.


                If we didn't have step 2, the expansion in step 3 would just be the reverse of step 1 and get the freon back where it started. But since we did some of the cooling in step 2 (which we can do because it's hot from the compression), we end up with colder-than-room-temperature gas after 3.



                Now, why do we do this with freon? The process I described above is for something like air which stays gaseous throughout. If you use freon (or sometimes ammonia or other chemicals) that will switch between gas and liquid during the process, it becomes more efficient. The physics is still basically the same, it's just that the boiling and condensing can transfer more heat energy without having to use really high pressures.



                Back to a gas like air: If you want to calculate how much it chills as it expands, you're talking about "adiabatic expansion". The Wikipedia article is a good starting point. For that operation, there's a relation between the initial and final pressure and temperature:



                $$P_i^1-gammaT_i^gamma = P_f^1-gammaT_f^gamma$$



                Where $gamma = 1.6$ is a constant value for air. If we take the initial temperature to be roughly 80F or 300K, the final temp to be 70F or 295K and the final pressure to be $P_A = 10^5$ for atmospheric, then



                $$ P_i = P_f (T_f/T_i)^gamma/(1-gamma) $$



                $$ P_i = (10^5) (295/300)^1.6/(-0.6) = 106,000$$



                That's a messy calculation, but because of the exponents ends up being that about a 6% increase in the pressure, when let out, will given you a 10F decrease in the temperature. In US units, that's from 14.7 PSIA to 15.6 PSAI; not all that much. Of course, a 10F drop isn't really enough to run a refrigerator that you'd really want...







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited 5 hours ago

























                answered 8 hours ago









                Bob JacobsenBob Jacobsen

                7,98213 silver badges24 bronze badges




                7,98213 silver badges24 bronze badges


























                    2













                    $begingroup$


                    Compression brings the molecules closer together thus cooling it down.




                    This isn't correct. The temperature of a gas isn't related to how close together the molecules are, but their speed.



                    By compressing the gas, they are closer together, but the work done in compression has sped them up as well. If you wait a while and let the gas cool, they'll still be closer together, but will be moving at the original speed.




                    My question is given air pressure at sea level. 80 degrees at 14.70 psi, how much pressure would you have to add to cool the air to 70 degrees if it was stored in a tank for 1 cubic meter?




                    There is no such pressure. Applying pressure will increase the temperature in the short term, not lower it. Any temperature change by doing this is only temporary. The gas will then exchange heat with the environment and move to ambient temperature.






                    share|cite|improve this answer









                    $endgroup$














                    • $begingroup$
                      Thank you for clarifying my misunderstanding, I've made a minor edit to clarify the question, If you waited until the tank, cooled back down to room temperature, How much pressure would be needed so that when releasing the gas, it came out 10 degrees cooler?
                      $endgroup$
                      – johnny 5
                      6 hours ago















                    2













                    $begingroup$


                    Compression brings the molecules closer together thus cooling it down.




                    This isn't correct. The temperature of a gas isn't related to how close together the molecules are, but their speed.



                    By compressing the gas, they are closer together, but the work done in compression has sped them up as well. If you wait a while and let the gas cool, they'll still be closer together, but will be moving at the original speed.




                    My question is given air pressure at sea level. 80 degrees at 14.70 psi, how much pressure would you have to add to cool the air to 70 degrees if it was stored in a tank for 1 cubic meter?




                    There is no such pressure. Applying pressure will increase the temperature in the short term, not lower it. Any temperature change by doing this is only temporary. The gas will then exchange heat with the environment and move to ambient temperature.






                    share|cite|improve this answer









                    $endgroup$














                    • $begingroup$
                      Thank you for clarifying my misunderstanding, I've made a minor edit to clarify the question, If you waited until the tank, cooled back down to room temperature, How much pressure would be needed so that when releasing the gas, it came out 10 degrees cooler?
                      $endgroup$
                      – johnny 5
                      6 hours ago













                    2














                    2










                    2







                    $begingroup$


                    Compression brings the molecules closer together thus cooling it down.




                    This isn't correct. The temperature of a gas isn't related to how close together the molecules are, but their speed.



                    By compressing the gas, they are closer together, but the work done in compression has sped them up as well. If you wait a while and let the gas cool, they'll still be closer together, but will be moving at the original speed.




                    My question is given air pressure at sea level. 80 degrees at 14.70 psi, how much pressure would you have to add to cool the air to 70 degrees if it was stored in a tank for 1 cubic meter?




                    There is no such pressure. Applying pressure will increase the temperature in the short term, not lower it. Any temperature change by doing this is only temporary. The gas will then exchange heat with the environment and move to ambient temperature.






                    share|cite|improve this answer









                    $endgroup$




                    Compression brings the molecules closer together thus cooling it down.




                    This isn't correct. The temperature of a gas isn't related to how close together the molecules are, but their speed.



                    By compressing the gas, they are closer together, but the work done in compression has sped them up as well. If you wait a while and let the gas cool, they'll still be closer together, but will be moving at the original speed.




                    My question is given air pressure at sea level. 80 degrees at 14.70 psi, how much pressure would you have to add to cool the air to 70 degrees if it was stored in a tank for 1 cubic meter?




                    There is no such pressure. Applying pressure will increase the temperature in the short term, not lower it. Any temperature change by doing this is only temporary. The gas will then exchange heat with the environment and move to ambient temperature.







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered 6 hours ago









                    BowlOfRedBowlOfRed

                    20k2 gold badges35 silver badges54 bronze badges




                    20k2 gold badges35 silver badges54 bronze badges














                    • $begingroup$
                      Thank you for clarifying my misunderstanding, I've made a minor edit to clarify the question, If you waited until the tank, cooled back down to room temperature, How much pressure would be needed so that when releasing the gas, it came out 10 degrees cooler?
                      $endgroup$
                      – johnny 5
                      6 hours ago
















                    • $begingroup$
                      Thank you for clarifying my misunderstanding, I've made a minor edit to clarify the question, If you waited until the tank, cooled back down to room temperature, How much pressure would be needed so that when releasing the gas, it came out 10 degrees cooler?
                      $endgroup$
                      – johnny 5
                      6 hours ago















                    $begingroup$
                    Thank you for clarifying my misunderstanding, I've made a minor edit to clarify the question, If you waited until the tank, cooled back down to room temperature, How much pressure would be needed so that when releasing the gas, it came out 10 degrees cooler?
                    $endgroup$
                    – johnny 5
                    6 hours ago




                    $begingroup$
                    Thank you for clarifying my misunderstanding, I've made a minor edit to clarify the question, If you waited until the tank, cooled back down to room temperature, How much pressure would be needed so that when releasing the gas, it came out 10 degrees cooler?
                    $endgroup$
                    – johnny 5
                    6 hours ago











                    1













                    $begingroup$

                    I will address the use of air rather than freon (or its current replacement) as a refrigerant. I believe @BowlOfRed has satisfactorily answered your other questions.



                    Air is not used as a refrigerant because it would not be practical. This is because a refrigerator requires the use of a working fluid that can undergo phase changes (gas to liquid in condenser, liquid to gas in evaporator) at practical operating pressures and temperatures. Air cannot undergo phase changes except at extremely low temperatures.



                    For example, at 1 atmosphere the boiling/condensing point of refrigerant HFC-134a (which has replaced freon for environmental reasons) is about -25 C (-13 F). This is somewhat lower than the setting of a household freezer. In contrast, the boiling/condensing point of liquid air at 1 atmosphere is -194.4 C. In order to increase the boiling/condensing temperature to that required by the refrigerator, extremely impractically high pressure would be required.



                    Hope this helps.






                    share|cite|improve this answer









                    $endgroup$














                    • $begingroup$
                      Thanks, I'm learning alot about thermodynamics today. I see that it would be impractical to do such a thing. But to cool the air down 10 degrees I don't think you would need to store the air in liquid form. e.g if the air at 1 atmosphere is 80 degrees, and you have air store at 2 atomsphere at 80 degrees, upon expansion what would the temperature of the air be?
                      $endgroup$
                      – johnny 5
                      5 hours ago










                    • $begingroup$
                      e.g in this example, pass air over cool pipe, you would just release the air back into the environment at a lower temperature
                      $endgroup$
                      – johnny 5
                      5 hours ago















                    1













                    $begingroup$

                    I will address the use of air rather than freon (or its current replacement) as a refrigerant. I believe @BowlOfRed has satisfactorily answered your other questions.



                    Air is not used as a refrigerant because it would not be practical. This is because a refrigerator requires the use of a working fluid that can undergo phase changes (gas to liquid in condenser, liquid to gas in evaporator) at practical operating pressures and temperatures. Air cannot undergo phase changes except at extremely low temperatures.



                    For example, at 1 atmosphere the boiling/condensing point of refrigerant HFC-134a (which has replaced freon for environmental reasons) is about -25 C (-13 F). This is somewhat lower than the setting of a household freezer. In contrast, the boiling/condensing point of liquid air at 1 atmosphere is -194.4 C. In order to increase the boiling/condensing temperature to that required by the refrigerator, extremely impractically high pressure would be required.



                    Hope this helps.






                    share|cite|improve this answer









                    $endgroup$














                    • $begingroup$
                      Thanks, I'm learning alot about thermodynamics today. I see that it would be impractical to do such a thing. But to cool the air down 10 degrees I don't think you would need to store the air in liquid form. e.g if the air at 1 atmosphere is 80 degrees, and you have air store at 2 atomsphere at 80 degrees, upon expansion what would the temperature of the air be?
                      $endgroup$
                      – johnny 5
                      5 hours ago










                    • $begingroup$
                      e.g in this example, pass air over cool pipe, you would just release the air back into the environment at a lower temperature
                      $endgroup$
                      – johnny 5
                      5 hours ago













                    1














                    1










                    1







                    $begingroup$

                    I will address the use of air rather than freon (or its current replacement) as a refrigerant. I believe @BowlOfRed has satisfactorily answered your other questions.



                    Air is not used as a refrigerant because it would not be practical. This is because a refrigerator requires the use of a working fluid that can undergo phase changes (gas to liquid in condenser, liquid to gas in evaporator) at practical operating pressures and temperatures. Air cannot undergo phase changes except at extremely low temperatures.



                    For example, at 1 atmosphere the boiling/condensing point of refrigerant HFC-134a (which has replaced freon for environmental reasons) is about -25 C (-13 F). This is somewhat lower than the setting of a household freezer. In contrast, the boiling/condensing point of liquid air at 1 atmosphere is -194.4 C. In order to increase the boiling/condensing temperature to that required by the refrigerator, extremely impractically high pressure would be required.



                    Hope this helps.






                    share|cite|improve this answer









                    $endgroup$



                    I will address the use of air rather than freon (or its current replacement) as a refrigerant. I believe @BowlOfRed has satisfactorily answered your other questions.



                    Air is not used as a refrigerant because it would not be practical. This is because a refrigerator requires the use of a working fluid that can undergo phase changes (gas to liquid in condenser, liquid to gas in evaporator) at practical operating pressures and temperatures. Air cannot undergo phase changes except at extremely low temperatures.



                    For example, at 1 atmosphere the boiling/condensing point of refrigerant HFC-134a (which has replaced freon for environmental reasons) is about -25 C (-13 F). This is somewhat lower than the setting of a household freezer. In contrast, the boiling/condensing point of liquid air at 1 atmosphere is -194.4 C. In order to increase the boiling/condensing temperature to that required by the refrigerator, extremely impractically high pressure would be required.



                    Hope this helps.







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered 5 hours ago









                    Bob DBob D

                    12k3 gold badges10 silver badges36 bronze badges




                    12k3 gold badges10 silver badges36 bronze badges














                    • $begingroup$
                      Thanks, I'm learning alot about thermodynamics today. I see that it would be impractical to do such a thing. But to cool the air down 10 degrees I don't think you would need to store the air in liquid form. e.g if the air at 1 atmosphere is 80 degrees, and you have air store at 2 atomsphere at 80 degrees, upon expansion what would the temperature of the air be?
                      $endgroup$
                      – johnny 5
                      5 hours ago










                    • $begingroup$
                      e.g in this example, pass air over cool pipe, you would just release the air back into the environment at a lower temperature
                      $endgroup$
                      – johnny 5
                      5 hours ago
















                    • $begingroup$
                      Thanks, I'm learning alot about thermodynamics today. I see that it would be impractical to do such a thing. But to cool the air down 10 degrees I don't think you would need to store the air in liquid form. e.g if the air at 1 atmosphere is 80 degrees, and you have air store at 2 atomsphere at 80 degrees, upon expansion what would the temperature of the air be?
                      $endgroup$
                      – johnny 5
                      5 hours ago










                    • $begingroup$
                      e.g in this example, pass air over cool pipe, you would just release the air back into the environment at a lower temperature
                      $endgroup$
                      – johnny 5
                      5 hours ago















                    $begingroup$
                    Thanks, I'm learning alot about thermodynamics today. I see that it would be impractical to do such a thing. But to cool the air down 10 degrees I don't think you would need to store the air in liquid form. e.g if the air at 1 atmosphere is 80 degrees, and you have air store at 2 atomsphere at 80 degrees, upon expansion what would the temperature of the air be?
                    $endgroup$
                    – johnny 5
                    5 hours ago




                    $begingroup$
                    Thanks, I'm learning alot about thermodynamics today. I see that it would be impractical to do such a thing. But to cool the air down 10 degrees I don't think you would need to store the air in liquid form. e.g if the air at 1 atmosphere is 80 degrees, and you have air store at 2 atomsphere at 80 degrees, upon expansion what would the temperature of the air be?
                    $endgroup$
                    – johnny 5
                    5 hours ago












                    $begingroup$
                    e.g in this example, pass air over cool pipe, you would just release the air back into the environment at a lower temperature
                    $endgroup$
                    – johnny 5
                    5 hours ago




                    $begingroup$
                    e.g in this example, pass air over cool pipe, you would just release the air back into the environment at a lower temperature
                    $endgroup$
                    – johnny 5
                    5 hours ago

















                    draft saved

                    draft discarded
















































                    Thanks for contributing an answer to Physics Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid


                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.

                    Use MathJax to format equations. MathJax reference.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function ()
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f498395%2fheat-reduction-based-on-compression%23new-answer', 'question_page');

                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    Invision Community Contents History See also References External links Navigation menuProprietaryinvisioncommunity.comIPS Community ForumsIPS Community Forumsthis blog entry"License Changes, IP.Board 3.4, and the Future""Interview -- Matt Mecham of Ibforums""CEO Invision Power Board, Matt Mecham Is a Liar, Thief!"IPB License Explanation 1.3, 1.3.1, 2.0, and 2.1ArchivedSecurity Fixes, Updates And Enhancements For IPB 1.3.1Archived"New Demo Accounts - Invision Power Services"the original"New Default Skin"the original"Invision Power Board 3.0.0 and Applications Released"the original"Archived copy"the original"Perpetual licenses being done away with""Release Notes - Invision Power Services""Introducing: IPS Community Suite 4!"Invision Community Release Notes

                    Canceling a color specificationRandomly assigning color to Graphics3D objects?Default color for Filling in Mathematica 9Coloring specific elements of sets with a prime modified order in an array plotHow to pick a color differing significantly from the colors already in a given color list?Detection of the text colorColor numbers based on their valueCan color schemes for use with ColorData include opacity specification?My dynamic color schemes

                    Ласкавець круглолистий Зміст Опис | Поширення | Галерея | Примітки | Посилання | Навігаційне меню58171138361-22960890446Bupleurum rotundifoliumEuro+Med PlantbasePlants of the World Online — Kew ScienceGermplasm Resources Information Network (GRIN)Ласкавецькн. VI : Літери Ком — Левиправивши або дописавши її