Defining a Function programmaticallyExamine function parameters programmaticallyReplace function call with expression resulting from the symbolic evaluation of the function when defining a second function?using a Mathematica function to define a new functionHow to programmatically covert a function-like rule to a pure function?Add semicolon at the end of code line programmaticallyTable with programmatically specified number of iterators in CompileMeta information about function parametersFull memory from defining a single functionMathematica function which formats Physics calculationEfficiently defining a SparseArray function

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Defining a Function programmatically


Examine function parameters programmaticallyReplace function call with expression resulting from the symbolic evaluation of the function when defining a second function?using a Mathematica function to define a new functionHow to programmatically covert a function-like rule to a pure function?Add semicolon at the end of code line programmaticallyTable with programmatically specified number of iterators in CompileMeta information about function parametersFull memory from defining a single functionMathematica function which formats Physics calculationEfficiently defining a SparseArray function






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3












$begingroup$


I need to create a function programmatically. For example, suppose I've got:



  1. mon - a Symbol

  2. mons - a List of Symbols

  3. vars - another List of Symbols (same Length)

and want to make a function as:



Function[«mon»,
Function[«mons»,
Internal`InheritedBlock[«vars»,
«vars[[1]]» =.;
«vars[[2]]» =.;
...
«vars[[-1]]» =.;
«vars[[1]]» = «mons[[1]]»;
«vars[[2]]»[t] = «mons[[2]]»;
...
«vars[[-1]]»[t] = «mons[[-1]]»;
«mon»
]]]


where «» denotes injecting from the given mon, mons, and vars.



So the input



mon = Unique[NDSolve`Monitor];
mons = Table[Unique[mon], 3];
vars = t, x, y;


would result in the desired output:



Function[NDSolve`Monitor$3080, 
Function[NDSolve`Monitor$3080$3081, NDSolve`Monitor$3080$3082, NDSolve`Monitor$3080$3083,
Internal`InheritedBlock[t, x, y,
t =.;
x =.;
y =.;
t = NDSolve`Monitor$3080$3081;
x[t] = NDSolve`Monitor$3080$3082;
y[t] = NDSolve`Monitor$3080$3083;
NDSolve`Monitor$3080
]]]


One possible solution involves building up a String, then using ToExpression:



str = "Function[" <> ToString[mon] <> ",
Function[" <> ToString[mons] <> ",
Internal`InheritedBlock[" <> ToString[vars] <> ",
";
Do[
str = str <> ToString[var] <> "=.;n"
, var, vars];
str = str <> "t=" <> ToString[mons[[1]]] <> ";n";
Do[
str = str <> ToString[vars[[i]]] <> "[t]=" <> ToString[mons[[i]]] <> ";n"
, i, 2, Length[vars]];
str = str <> ToString[mon] <> "]]]n";


but this is kind of inelegant and can be slow for large lists.



Are there any nicer and/or faster alternatives?










share|improve this question











$endgroup$











  • $begingroup$
    Sorry, it is not at all clear to me what you try to achieve. Would you please give a concrete example?
    $endgroup$
    – Henrik Schumacher
    9 hours ago










  • $begingroup$
    @HenrikSchumacher I want to make the third code block based on the info given in the second code block. The code following “One possible solution...” does what I want, but it’s slow.
    $endgroup$
    – Chris K
    9 hours ago






  • 1




    $begingroup$
    Uuuh... Do you really want to have such a side effect in a pure function? Yes, Mathematica allows you to do that by I would not consider it programming practice.
    $endgroup$
    – Henrik Schumacher
    9 hours ago






  • 2




    $begingroup$
    It might be worth mentioning that you need this for a specific purpose (working with the StateData internals) such that it must be a pure function like this.
    $endgroup$
    – b3m2a1
    8 hours ago






  • 1




    $begingroup$
    As @b3m2a1 alludes to, I do have a specific reason to achieve what I asked for. Maybe there's an easier way, but I thought it would be better to ask this question on its own rather than mixed in with that complicated project. Anyhow, I'll link to the Q&A that motivates this question as soon as I write it up.
    $endgroup$
    – Chris K
    8 hours ago

















3












$begingroup$


I need to create a function programmatically. For example, suppose I've got:



  1. mon - a Symbol

  2. mons - a List of Symbols

  3. vars - another List of Symbols (same Length)

and want to make a function as:



Function[«mon»,
Function[«mons»,
Internal`InheritedBlock[«vars»,
«vars[[1]]» =.;
«vars[[2]]» =.;
...
«vars[[-1]]» =.;
«vars[[1]]» = «mons[[1]]»;
«vars[[2]]»[t] = «mons[[2]]»;
...
«vars[[-1]]»[t] = «mons[[-1]]»;
«mon»
]]]


where «» denotes injecting from the given mon, mons, and vars.



So the input



mon = Unique[NDSolve`Monitor];
mons = Table[Unique[mon], 3];
vars = t, x, y;


would result in the desired output:



Function[NDSolve`Monitor$3080, 
Function[NDSolve`Monitor$3080$3081, NDSolve`Monitor$3080$3082, NDSolve`Monitor$3080$3083,
Internal`InheritedBlock[t, x, y,
t =.;
x =.;
y =.;
t = NDSolve`Monitor$3080$3081;
x[t] = NDSolve`Monitor$3080$3082;
y[t] = NDSolve`Monitor$3080$3083;
NDSolve`Monitor$3080
]]]


One possible solution involves building up a String, then using ToExpression:



str = "Function[" <> ToString[mon] <> ",
Function[" <> ToString[mons] <> ",
Internal`InheritedBlock[" <> ToString[vars] <> ",
";
Do[
str = str <> ToString[var] <> "=.;n"
, var, vars];
str = str <> "t=" <> ToString[mons[[1]]] <> ";n";
Do[
str = str <> ToString[vars[[i]]] <> "[t]=" <> ToString[mons[[i]]] <> ";n"
, i, 2, Length[vars]];
str = str <> ToString[mon] <> "]]]n";


but this is kind of inelegant and can be slow for large lists.



Are there any nicer and/or faster alternatives?










share|improve this question











$endgroup$











  • $begingroup$
    Sorry, it is not at all clear to me what you try to achieve. Would you please give a concrete example?
    $endgroup$
    – Henrik Schumacher
    9 hours ago










  • $begingroup$
    @HenrikSchumacher I want to make the third code block based on the info given in the second code block. The code following “One possible solution...” does what I want, but it’s slow.
    $endgroup$
    – Chris K
    9 hours ago






  • 1




    $begingroup$
    Uuuh... Do you really want to have such a side effect in a pure function? Yes, Mathematica allows you to do that by I would not consider it programming practice.
    $endgroup$
    – Henrik Schumacher
    9 hours ago






  • 2




    $begingroup$
    It might be worth mentioning that you need this for a specific purpose (working with the StateData internals) such that it must be a pure function like this.
    $endgroup$
    – b3m2a1
    8 hours ago






  • 1




    $begingroup$
    As @b3m2a1 alludes to, I do have a specific reason to achieve what I asked for. Maybe there's an easier way, but I thought it would be better to ask this question on its own rather than mixed in with that complicated project. Anyhow, I'll link to the Q&A that motivates this question as soon as I write it up.
    $endgroup$
    – Chris K
    8 hours ago













3












3








3


1



$begingroup$


I need to create a function programmatically. For example, suppose I've got:



  1. mon - a Symbol

  2. mons - a List of Symbols

  3. vars - another List of Symbols (same Length)

and want to make a function as:



Function[«mon»,
Function[«mons»,
Internal`InheritedBlock[«vars»,
«vars[[1]]» =.;
«vars[[2]]» =.;
...
«vars[[-1]]» =.;
«vars[[1]]» = «mons[[1]]»;
«vars[[2]]»[t] = «mons[[2]]»;
...
«vars[[-1]]»[t] = «mons[[-1]]»;
«mon»
]]]


where «» denotes injecting from the given mon, mons, and vars.



So the input



mon = Unique[NDSolve`Monitor];
mons = Table[Unique[mon], 3];
vars = t, x, y;


would result in the desired output:



Function[NDSolve`Monitor$3080, 
Function[NDSolve`Monitor$3080$3081, NDSolve`Monitor$3080$3082, NDSolve`Monitor$3080$3083,
Internal`InheritedBlock[t, x, y,
t =.;
x =.;
y =.;
t = NDSolve`Monitor$3080$3081;
x[t] = NDSolve`Monitor$3080$3082;
y[t] = NDSolve`Monitor$3080$3083;
NDSolve`Monitor$3080
]]]


One possible solution involves building up a String, then using ToExpression:



str = "Function[" <> ToString[mon] <> ",
Function[" <> ToString[mons] <> ",
Internal`InheritedBlock[" <> ToString[vars] <> ",
";
Do[
str = str <> ToString[var] <> "=.;n"
, var, vars];
str = str <> "t=" <> ToString[mons[[1]]] <> ";n";
Do[
str = str <> ToString[vars[[i]]] <> "[t]=" <> ToString[mons[[i]]] <> ";n"
, i, 2, Length[vars]];
str = str <> ToString[mon] <> "]]]n";


but this is kind of inelegant and can be slow for large lists.



Are there any nicer and/or faster alternatives?










share|improve this question











$endgroup$




I need to create a function programmatically. For example, suppose I've got:



  1. mon - a Symbol

  2. mons - a List of Symbols

  3. vars - another List of Symbols (same Length)

and want to make a function as:



Function[«mon»,
Function[«mons»,
Internal`InheritedBlock[«vars»,
«vars[[1]]» =.;
«vars[[2]]» =.;
...
«vars[[-1]]» =.;
«vars[[1]]» = «mons[[1]]»;
«vars[[2]]»[t] = «mons[[2]]»;
...
«vars[[-1]]»[t] = «mons[[-1]]»;
«mon»
]]]


where «» denotes injecting from the given mon, mons, and vars.



So the input



mon = Unique[NDSolve`Monitor];
mons = Table[Unique[mon], 3];
vars = t, x, y;


would result in the desired output:



Function[NDSolve`Monitor$3080, 
Function[NDSolve`Monitor$3080$3081, NDSolve`Monitor$3080$3082, NDSolve`Monitor$3080$3083,
Internal`InheritedBlock[t, x, y,
t =.;
x =.;
y =.;
t = NDSolve`Monitor$3080$3081;
x[t] = NDSolve`Monitor$3080$3082;
y[t] = NDSolve`Monitor$3080$3083;
NDSolve`Monitor$3080
]]]


One possible solution involves building up a String, then using ToExpression:



str = "Function[" <> ToString[mon] <> ",
Function[" <> ToString[mons] <> ",
Internal`InheritedBlock[" <> ToString[vars] <> ",
";
Do[
str = str <> ToString[var] <> "=.;n"
, var, vars];
str = str <> "t=" <> ToString[mons[[1]]] <> ";n";
Do[
str = str <> ToString[vars[[i]]] <> "[t]=" <> ToString[mons[[i]]] <> ";n"
, i, 2, Length[vars]];
str = str <> ToString[mon] <> "]]]n";


but this is kind of inelegant and can be slow for large lists.



Are there any nicer and/or faster alternatives?







performance-tuning meta-programming






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 9 hours ago







Chris K

















asked 10 hours ago









Chris KChris K

9,2202 gold badges23 silver badges50 bronze badges




9,2202 gold badges23 silver badges50 bronze badges











  • $begingroup$
    Sorry, it is not at all clear to me what you try to achieve. Would you please give a concrete example?
    $endgroup$
    – Henrik Schumacher
    9 hours ago










  • $begingroup$
    @HenrikSchumacher I want to make the third code block based on the info given in the second code block. The code following “One possible solution...” does what I want, but it’s slow.
    $endgroup$
    – Chris K
    9 hours ago






  • 1




    $begingroup$
    Uuuh... Do you really want to have such a side effect in a pure function? Yes, Mathematica allows you to do that by I would not consider it programming practice.
    $endgroup$
    – Henrik Schumacher
    9 hours ago






  • 2




    $begingroup$
    It might be worth mentioning that you need this for a specific purpose (working with the StateData internals) such that it must be a pure function like this.
    $endgroup$
    – b3m2a1
    8 hours ago






  • 1




    $begingroup$
    As @b3m2a1 alludes to, I do have a specific reason to achieve what I asked for. Maybe there's an easier way, but I thought it would be better to ask this question on its own rather than mixed in with that complicated project. Anyhow, I'll link to the Q&A that motivates this question as soon as I write it up.
    $endgroup$
    – Chris K
    8 hours ago
















  • $begingroup$
    Sorry, it is not at all clear to me what you try to achieve. Would you please give a concrete example?
    $endgroup$
    – Henrik Schumacher
    9 hours ago










  • $begingroup$
    @HenrikSchumacher I want to make the third code block based on the info given in the second code block. The code following “One possible solution...” does what I want, but it’s slow.
    $endgroup$
    – Chris K
    9 hours ago






  • 1




    $begingroup$
    Uuuh... Do you really want to have such a side effect in a pure function? Yes, Mathematica allows you to do that by I would not consider it programming practice.
    $endgroup$
    – Henrik Schumacher
    9 hours ago






  • 2




    $begingroup$
    It might be worth mentioning that you need this for a specific purpose (working with the StateData internals) such that it must be a pure function like this.
    $endgroup$
    – b3m2a1
    8 hours ago






  • 1




    $begingroup$
    As @b3m2a1 alludes to, I do have a specific reason to achieve what I asked for. Maybe there's an easier way, but I thought it would be better to ask this question on its own rather than mixed in with that complicated project. Anyhow, I'll link to the Q&A that motivates this question as soon as I write it up.
    $endgroup$
    – Chris K
    8 hours ago















$begingroup$
Sorry, it is not at all clear to me what you try to achieve. Would you please give a concrete example?
$endgroup$
– Henrik Schumacher
9 hours ago




$begingroup$
Sorry, it is not at all clear to me what you try to achieve. Would you please give a concrete example?
$endgroup$
– Henrik Schumacher
9 hours ago












$begingroup$
@HenrikSchumacher I want to make the third code block based on the info given in the second code block. The code following “One possible solution...” does what I want, but it’s slow.
$endgroup$
– Chris K
9 hours ago




$begingroup$
@HenrikSchumacher I want to make the third code block based on the info given in the second code block. The code following “One possible solution...” does what I want, but it’s slow.
$endgroup$
– Chris K
9 hours ago




1




1




$begingroup$
Uuuh... Do you really want to have such a side effect in a pure function? Yes, Mathematica allows you to do that by I would not consider it programming practice.
$endgroup$
– Henrik Schumacher
9 hours ago




$begingroup$
Uuuh... Do you really want to have such a side effect in a pure function? Yes, Mathematica allows you to do that by I would not consider it programming practice.
$endgroup$
– Henrik Schumacher
9 hours ago




2




2




$begingroup$
It might be worth mentioning that you need this for a specific purpose (working with the StateData internals) such that it must be a pure function like this.
$endgroup$
– b3m2a1
8 hours ago




$begingroup$
It might be worth mentioning that you need this for a specific purpose (working with the StateData internals) such that it must be a pure function like this.
$endgroup$
– b3m2a1
8 hours ago




1




1




$begingroup$
As @b3m2a1 alludes to, I do have a specific reason to achieve what I asked for. Maybe there's an easier way, but I thought it would be better to ask this question on its own rather than mixed in with that complicated project. Anyhow, I'll link to the Q&A that motivates this question as soon as I write it up.
$endgroup$
– Chris K
8 hours ago




$begingroup$
As @b3m2a1 alludes to, I do have a specific reason to achieve what I asked for. Maybe there's an easier way, but I thought it would be better to ask this question on its own rather than mixed in with that complicated project. Anyhow, I'll link to the Q&A that motivates this question as soon as I write it up.
$endgroup$
– Chris K
8 hours ago










4 Answers
4






active

oldest

votes


















2












$begingroup$

Possibly this:



mon = Unique[NDSolve`Monitor];
mons = Table[Unique[mon], 3];
vars = t, x, y;

Block[Set, Unset, CompoundExpression,
With[code = CompoundExpression @@ Join[
Unset /@ #3,
MapThread[
Set,
Prepend[Through[Rest[#3][First[#3]]], First[#3]], #2],
#1
],
Function @@ #1,
Function @@ Hold[#2, Internal`InheritedBlock[#3, code]]
]] &[mon, mons, vars]

(*
Function[NDSolve`Monitor$234166,
Function[NDSolve`Monitor$234166$234167,
NDSolve`Monitor$234166$234168, NDSolve`Monitor$234166$234169,
Internal`InheritedBlock[t, x, y,
t =.;
x =.;
y =.;
t = NDSolve`Monitor$234166$234167;
x[t] = NDSolve`Monitor$234166$234168;
y[t] = NDSolve`Monitor$234166$234169;
NDSolve`Monitor$234166
]]]
*)


Update:
This avoids blocking system functions. It shouldn't be a problem above because of the limited scope of the Block[] and the fact that the arguments mon, mons, vars are all evaluated before injected; but maybe it seems safer the following way.



With[code = Join[
Hold[#1, #2, #3], (* first args of Function and InheritedBlock *)
Unset /@ Hold @@ #3, (* beginning of body *)
Set @@@ Hold @@ Transpose@
Prepend[Through[Rest[#3][First[#3]]], First[#3]], #2,
Hold[#1]
],
Replace[code, Hold[m1_, m2_, v_, body__] :>
Function[m1, Function[m2,
Internal`InheritedBlock[v, CompoundExpression[body]]]]]
] &[mon, mons, vars]

(* same output as above *)





share|improve this answer











$endgroup$








  • 1




    $begingroup$
    @kglr Tee-hee, how funny....Touché, as they say. Thanks! I've got several versions. I guess copied the wrong one.
    $endgroup$
    – Michael E2
    4 hours ago










  • $begingroup$
    Also Block[Set, Unset, CompoundExpression, Function[#1, Function[#2, Internal`InheritedBlock[#3, #4]]] &[ mon, mons, vars, CompoundExpression @@ Join[ Unset /@ vars, MapThread[Set, Prepend[Through[Rest[vars]@First[vars]], First[vars]], mons], mon] ] ]
    $endgroup$
    – Michael E2
    3 hours ago


















1












$begingroup$

ClearAll[makeArgs, makeFunc]
makeArgs[m_, ms_, v_] := m, ms, Inactive[Internal`InheritedBlock][v,
Inactive[CompoundExpression] @@ Flatten[
Inactive[Unset] /@ v, Inactive[Set][ v[[1]], ms[[1]]],
Inactivate[Thread[Through[Rest[v] @ First[v]] = Rest[ms]], Set], m]];

makeFunc = Function[#, Evaluate @ Activate @ Function[#2, #3]] & @@ makeArgs[##] &;

makeFunc[mon, mons, vars]



Function[NDSolve`Monitor$30945,
Function[NDSolve`Monitor$30945$30952, NDSolve`Monitor$30945$30953,
NDSolve`Monitor$30945$30954,
Internal`InheritedBlock[t, x, y,
t =.; x =.; y =.;
t = NDSolve`Monitor$30945$30952;
x[t] = NDSolve`Monitor$30945$30953;
y[t] = NDSolve`Monitor$30945$30954;
NDSolve`Monitor$30945]]]







share|improve this answer











$endgroup$




















    0












    $begingroup$

    Rather than try to figure out what your detailed intentions are, let me just give a simple example. This kind of thing is easy with Function because it holds its arguments until it is applied. You may thus reach into a Function and perform arbitrary replacements. There is no need to clumsily edit text. Here, I define powerN as a prototype, and do replacements:



    powerN = Function[x, x^n];
    power2 = powerN /. n -> 2
    (* Function[x, x^2] *)


    Another way is to define a constructor:



    power[n_] := Function[x, x^n]
    power[2]
    (* Function[x$, x$^2] *)





    share|improve this answer









    $endgroup$












    • $begingroup$
      I think injecting the variable bits into the Internal`InheritedBlock is more my problem, but thanks.
      $endgroup$
      – Chris K
      8 hours ago


















    0












    $begingroup$

    Is there any reason why this won't work?



    doopDoopDoop~SetAttributes~HoldAll;
    doopDoopDoop[
    mon_Symbol, mons : __Symbol, vars : __Symbol, t_Symbol,
    body1_,
    body2_
    ] :=
    Function[mon,
    Function[mons,
    Internal`InheritedBlock[vars,
    vars[[1]] =.;
    vars[[2]] =.;
    body1;
    vars[[-1]] =.;
    vars[[1]] vars = mons[[1]] mons;
    vars[[2]][t] = mons[[2]];
    body2;
    vars[[-1]][t] = mons[[-1]];
    mon
    ]
    ]
    ]


    Then:



    doopDoopDoop[
    a, b, c, d, e, t,
    1,
    2
    ]

    Function[a,
    Function[b, c,
    Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
    1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
    t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]


    The annoying thing will be the parameter injection if you have mons stored as a list. In this case I'm going to assume you have each variable wrapped in Hold, because that makes it a bit more subtle. The way we'll prep the parameter list is then:



    depVar = Hold@a;
    mons = Thread@Hold@b, c;
    vars = Thread@Hold@d, e;
    timeVar = Hold@t;

    paramList =
    Thread[depVar, Thread[mons, Hold], Thread[vars, Hold], timeVar, Hold]

    Hold[a, b, c, d, e, t]


    Then we inject it like:



    Replace[
    paramList,
    Hold[pars_] :>
    doopDoopDoop[
    pars,
    1,
    2
    ]
    ]

    Function[a,
    Function[b, c,
    Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
    1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
    t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]


    In general, the final thing you'll want to do with an injection is wrap it in a Replace to inject the contents of the Hold or provide a function with DownValues that does the injection, e.g.:



    doopDoopDoopHold~SetAttributes~HoldRest;
    doopDoopDoopHold[
    Hold[pars : mon_Symbol, mons : __Symbol, vars : __Symbol, t_Symbol],
    body1_,
    body2_
    ] :=
    doopDoopDoop[pars, body1, body2];

    doopDoopDoopHold[paramList, 1, 2]

    Function[a,
    Function[b, c,
    Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
    1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
    t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]





    share|improve this answer









    $endgroup$















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      4 Answers
      4






      active

      oldest

      votes








      4 Answers
      4






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2












      $begingroup$

      Possibly this:



      mon = Unique[NDSolve`Monitor];
      mons = Table[Unique[mon], 3];
      vars = t, x, y;

      Block[Set, Unset, CompoundExpression,
      With[code = CompoundExpression @@ Join[
      Unset /@ #3,
      MapThread[
      Set,
      Prepend[Through[Rest[#3][First[#3]]], First[#3]], #2],
      #1
      ],
      Function @@ #1,
      Function @@ Hold[#2, Internal`InheritedBlock[#3, code]]
      ]] &[mon, mons, vars]

      (*
      Function[NDSolve`Monitor$234166,
      Function[NDSolve`Monitor$234166$234167,
      NDSolve`Monitor$234166$234168, NDSolve`Monitor$234166$234169,
      Internal`InheritedBlock[t, x, y,
      t =.;
      x =.;
      y =.;
      t = NDSolve`Monitor$234166$234167;
      x[t] = NDSolve`Monitor$234166$234168;
      y[t] = NDSolve`Monitor$234166$234169;
      NDSolve`Monitor$234166
      ]]]
      *)


      Update:
      This avoids blocking system functions. It shouldn't be a problem above because of the limited scope of the Block[] and the fact that the arguments mon, mons, vars are all evaluated before injected; but maybe it seems safer the following way.



      With[code = Join[
      Hold[#1, #2, #3], (* first args of Function and InheritedBlock *)
      Unset /@ Hold @@ #3, (* beginning of body *)
      Set @@@ Hold @@ Transpose@
      Prepend[Through[Rest[#3][First[#3]]], First[#3]], #2,
      Hold[#1]
      ],
      Replace[code, Hold[m1_, m2_, v_, body__] :>
      Function[m1, Function[m2,
      Internal`InheritedBlock[v, CompoundExpression[body]]]]]
      ] &[mon, mons, vars]

      (* same output as above *)





      share|improve this answer











      $endgroup$








      • 1




        $begingroup$
        @kglr Tee-hee, how funny....Touché, as they say. Thanks! I've got several versions. I guess copied the wrong one.
        $endgroup$
        – Michael E2
        4 hours ago










      • $begingroup$
        Also Block[Set, Unset, CompoundExpression, Function[#1, Function[#2, Internal`InheritedBlock[#3, #4]]] &[ mon, mons, vars, CompoundExpression @@ Join[ Unset /@ vars, MapThread[Set, Prepend[Through[Rest[vars]@First[vars]], First[vars]], mons], mon] ] ]
        $endgroup$
        – Michael E2
        3 hours ago















      2












      $begingroup$

      Possibly this:



      mon = Unique[NDSolve`Monitor];
      mons = Table[Unique[mon], 3];
      vars = t, x, y;

      Block[Set, Unset, CompoundExpression,
      With[code = CompoundExpression @@ Join[
      Unset /@ #3,
      MapThread[
      Set,
      Prepend[Through[Rest[#3][First[#3]]], First[#3]], #2],
      #1
      ],
      Function @@ #1,
      Function @@ Hold[#2, Internal`InheritedBlock[#3, code]]
      ]] &[mon, mons, vars]

      (*
      Function[NDSolve`Monitor$234166,
      Function[NDSolve`Monitor$234166$234167,
      NDSolve`Monitor$234166$234168, NDSolve`Monitor$234166$234169,
      Internal`InheritedBlock[t, x, y,
      t =.;
      x =.;
      y =.;
      t = NDSolve`Monitor$234166$234167;
      x[t] = NDSolve`Monitor$234166$234168;
      y[t] = NDSolve`Monitor$234166$234169;
      NDSolve`Monitor$234166
      ]]]
      *)


      Update:
      This avoids blocking system functions. It shouldn't be a problem above because of the limited scope of the Block[] and the fact that the arguments mon, mons, vars are all evaluated before injected; but maybe it seems safer the following way.



      With[code = Join[
      Hold[#1, #2, #3], (* first args of Function and InheritedBlock *)
      Unset /@ Hold @@ #3, (* beginning of body *)
      Set @@@ Hold @@ Transpose@
      Prepend[Through[Rest[#3][First[#3]]], First[#3]], #2,
      Hold[#1]
      ],
      Replace[code, Hold[m1_, m2_, v_, body__] :>
      Function[m1, Function[m2,
      Internal`InheritedBlock[v, CompoundExpression[body]]]]]
      ] &[mon, mons, vars]

      (* same output as above *)





      share|improve this answer











      $endgroup$








      • 1




        $begingroup$
        @kglr Tee-hee, how funny....Touché, as they say. Thanks! I've got several versions. I guess copied the wrong one.
        $endgroup$
        – Michael E2
        4 hours ago










      • $begingroup$
        Also Block[Set, Unset, CompoundExpression, Function[#1, Function[#2, Internal`InheritedBlock[#3, #4]]] &[ mon, mons, vars, CompoundExpression @@ Join[ Unset /@ vars, MapThread[Set, Prepend[Through[Rest[vars]@First[vars]], First[vars]], mons], mon] ] ]
        $endgroup$
        – Michael E2
        3 hours ago













      2












      2








      2





      $begingroup$

      Possibly this:



      mon = Unique[NDSolve`Monitor];
      mons = Table[Unique[mon], 3];
      vars = t, x, y;

      Block[Set, Unset, CompoundExpression,
      With[code = CompoundExpression @@ Join[
      Unset /@ #3,
      MapThread[
      Set,
      Prepend[Through[Rest[#3][First[#3]]], First[#3]], #2],
      #1
      ],
      Function @@ #1,
      Function @@ Hold[#2, Internal`InheritedBlock[#3, code]]
      ]] &[mon, mons, vars]

      (*
      Function[NDSolve`Monitor$234166,
      Function[NDSolve`Monitor$234166$234167,
      NDSolve`Monitor$234166$234168, NDSolve`Monitor$234166$234169,
      Internal`InheritedBlock[t, x, y,
      t =.;
      x =.;
      y =.;
      t = NDSolve`Monitor$234166$234167;
      x[t] = NDSolve`Monitor$234166$234168;
      y[t] = NDSolve`Monitor$234166$234169;
      NDSolve`Monitor$234166
      ]]]
      *)


      Update:
      This avoids blocking system functions. It shouldn't be a problem above because of the limited scope of the Block[] and the fact that the arguments mon, mons, vars are all evaluated before injected; but maybe it seems safer the following way.



      With[code = Join[
      Hold[#1, #2, #3], (* first args of Function and InheritedBlock *)
      Unset /@ Hold @@ #3, (* beginning of body *)
      Set @@@ Hold @@ Transpose@
      Prepend[Through[Rest[#3][First[#3]]], First[#3]], #2,
      Hold[#1]
      ],
      Replace[code, Hold[m1_, m2_, v_, body__] :>
      Function[m1, Function[m2,
      Internal`InheritedBlock[v, CompoundExpression[body]]]]]
      ] &[mon, mons, vars]

      (* same output as above *)





      share|improve this answer











      $endgroup$



      Possibly this:



      mon = Unique[NDSolve`Monitor];
      mons = Table[Unique[mon], 3];
      vars = t, x, y;

      Block[Set, Unset, CompoundExpression,
      With[code = CompoundExpression @@ Join[
      Unset /@ #3,
      MapThread[
      Set,
      Prepend[Through[Rest[#3][First[#3]]], First[#3]], #2],
      #1
      ],
      Function @@ #1,
      Function @@ Hold[#2, Internal`InheritedBlock[#3, code]]
      ]] &[mon, mons, vars]

      (*
      Function[NDSolve`Monitor$234166,
      Function[NDSolve`Monitor$234166$234167,
      NDSolve`Monitor$234166$234168, NDSolve`Monitor$234166$234169,
      Internal`InheritedBlock[t, x, y,
      t =.;
      x =.;
      y =.;
      t = NDSolve`Monitor$234166$234167;
      x[t] = NDSolve`Monitor$234166$234168;
      y[t] = NDSolve`Monitor$234166$234169;
      NDSolve`Monitor$234166
      ]]]
      *)


      Update:
      This avoids blocking system functions. It shouldn't be a problem above because of the limited scope of the Block[] and the fact that the arguments mon, mons, vars are all evaluated before injected; but maybe it seems safer the following way.



      With[code = Join[
      Hold[#1, #2, #3], (* first args of Function and InheritedBlock *)
      Unset /@ Hold @@ #3, (* beginning of body *)
      Set @@@ Hold @@ Transpose@
      Prepend[Through[Rest[#3][First[#3]]], First[#3]], #2,
      Hold[#1]
      ],
      Replace[code, Hold[m1_, m2_, v_, body__] :>
      Function[m1, Function[m2,
      Internal`InheritedBlock[v, CompoundExpression[body]]]]]
      ] &[mon, mons, vars]

      (* same output as above *)






      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited 4 hours ago

























      answered 8 hours ago









      Michael E2Michael E2

      156k13 gold badges215 silver badges509 bronze badges




      156k13 gold badges215 silver badges509 bronze badges







      • 1




        $begingroup$
        @kglr Tee-hee, how funny....Touché, as they say. Thanks! I've got several versions. I guess copied the wrong one.
        $endgroup$
        – Michael E2
        4 hours ago










      • $begingroup$
        Also Block[Set, Unset, CompoundExpression, Function[#1, Function[#2, Internal`InheritedBlock[#3, #4]]] &[ mon, mons, vars, CompoundExpression @@ Join[ Unset /@ vars, MapThread[Set, Prepend[Through[Rest[vars]@First[vars]], First[vars]], mons], mon] ] ]
        $endgroup$
        – Michael E2
        3 hours ago












      • 1




        $begingroup$
        @kglr Tee-hee, how funny....Touché, as they say. Thanks! I've got several versions. I guess copied the wrong one.
        $endgroup$
        – Michael E2
        4 hours ago










      • $begingroup$
        Also Block[Set, Unset, CompoundExpression, Function[#1, Function[#2, Internal`InheritedBlock[#3, #4]]] &[ mon, mons, vars, CompoundExpression @@ Join[ Unset /@ vars, MapThread[Set, Prepend[Through[Rest[vars]@First[vars]], First[vars]], mons], mon] ] ]
        $endgroup$
        – Michael E2
        3 hours ago







      1




      1




      $begingroup$
      @kglr Tee-hee, how funny....Touché, as they say. Thanks! I've got several versions. I guess copied the wrong one.
      $endgroup$
      – Michael E2
      4 hours ago




      $begingroup$
      @kglr Tee-hee, how funny....Touché, as they say. Thanks! I've got several versions. I guess copied the wrong one.
      $endgroup$
      – Michael E2
      4 hours ago












      $begingroup$
      Also Block[Set, Unset, CompoundExpression, Function[#1, Function[#2, Internal`InheritedBlock[#3, #4]]] &[ mon, mons, vars, CompoundExpression @@ Join[ Unset /@ vars, MapThread[Set, Prepend[Through[Rest[vars]@First[vars]], First[vars]], mons], mon] ] ]
      $endgroup$
      – Michael E2
      3 hours ago




      $begingroup$
      Also Block[Set, Unset, CompoundExpression, Function[#1, Function[#2, Internal`InheritedBlock[#3, #4]]] &[ mon, mons, vars, CompoundExpression @@ Join[ Unset /@ vars, MapThread[Set, Prepend[Through[Rest[vars]@First[vars]], First[vars]], mons], mon] ] ]
      $endgroup$
      – Michael E2
      3 hours ago













      1












      $begingroup$

      ClearAll[makeArgs, makeFunc]
      makeArgs[m_, ms_, v_] := m, ms, Inactive[Internal`InheritedBlock][v,
      Inactive[CompoundExpression] @@ Flatten[
      Inactive[Unset] /@ v, Inactive[Set][ v[[1]], ms[[1]]],
      Inactivate[Thread[Through[Rest[v] @ First[v]] = Rest[ms]], Set], m]];

      makeFunc = Function[#, Evaluate @ Activate @ Function[#2, #3]] & @@ makeArgs[##] &;

      makeFunc[mon, mons, vars]



      Function[NDSolve`Monitor$30945,
      Function[NDSolve`Monitor$30945$30952, NDSolve`Monitor$30945$30953,
      NDSolve`Monitor$30945$30954,
      Internal`InheritedBlock[t, x, y,
      t =.; x =.; y =.;
      t = NDSolve`Monitor$30945$30952;
      x[t] = NDSolve`Monitor$30945$30953;
      y[t] = NDSolve`Monitor$30945$30954;
      NDSolve`Monitor$30945]]]







      share|improve this answer











      $endgroup$

















        1












        $begingroup$

        ClearAll[makeArgs, makeFunc]
        makeArgs[m_, ms_, v_] := m, ms, Inactive[Internal`InheritedBlock][v,
        Inactive[CompoundExpression] @@ Flatten[
        Inactive[Unset] /@ v, Inactive[Set][ v[[1]], ms[[1]]],
        Inactivate[Thread[Through[Rest[v] @ First[v]] = Rest[ms]], Set], m]];

        makeFunc = Function[#, Evaluate @ Activate @ Function[#2, #3]] & @@ makeArgs[##] &;

        makeFunc[mon, mons, vars]



        Function[NDSolve`Monitor$30945,
        Function[NDSolve`Monitor$30945$30952, NDSolve`Monitor$30945$30953,
        NDSolve`Monitor$30945$30954,
        Internal`InheritedBlock[t, x, y,
        t =.; x =.; y =.;
        t = NDSolve`Monitor$30945$30952;
        x[t] = NDSolve`Monitor$30945$30953;
        y[t] = NDSolve`Monitor$30945$30954;
        NDSolve`Monitor$30945]]]







        share|improve this answer











        $endgroup$















          1












          1








          1





          $begingroup$

          ClearAll[makeArgs, makeFunc]
          makeArgs[m_, ms_, v_] := m, ms, Inactive[Internal`InheritedBlock][v,
          Inactive[CompoundExpression] @@ Flatten[
          Inactive[Unset] /@ v, Inactive[Set][ v[[1]], ms[[1]]],
          Inactivate[Thread[Through[Rest[v] @ First[v]] = Rest[ms]], Set], m]];

          makeFunc = Function[#, Evaluate @ Activate @ Function[#2, #3]] & @@ makeArgs[##] &;

          makeFunc[mon, mons, vars]



          Function[NDSolve`Monitor$30945,
          Function[NDSolve`Monitor$30945$30952, NDSolve`Monitor$30945$30953,
          NDSolve`Monitor$30945$30954,
          Internal`InheritedBlock[t, x, y,
          t =.; x =.; y =.;
          t = NDSolve`Monitor$30945$30952;
          x[t] = NDSolve`Monitor$30945$30953;
          y[t] = NDSolve`Monitor$30945$30954;
          NDSolve`Monitor$30945]]]







          share|improve this answer











          $endgroup$



          ClearAll[makeArgs, makeFunc]
          makeArgs[m_, ms_, v_] := m, ms, Inactive[Internal`InheritedBlock][v,
          Inactive[CompoundExpression] @@ Flatten[
          Inactive[Unset] /@ v, Inactive[Set][ v[[1]], ms[[1]]],
          Inactivate[Thread[Through[Rest[v] @ First[v]] = Rest[ms]], Set], m]];

          makeFunc = Function[#, Evaluate @ Activate @ Function[#2, #3]] & @@ makeArgs[##] &;

          makeFunc[mon, mons, vars]



          Function[NDSolve`Monitor$30945,
          Function[NDSolve`Monitor$30945$30952, NDSolve`Monitor$30945$30953,
          NDSolve`Monitor$30945$30954,
          Internal`InheritedBlock[t, x, y,
          t =.; x =.; y =.;
          t = NDSolve`Monitor$30945$30952;
          x[t] = NDSolve`Monitor$30945$30953;
          y[t] = NDSolve`Monitor$30945$30954;
          NDSolve`Monitor$30945]]]








          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 7 hours ago

























          answered 7 hours ago









          kglrkglr

          207k10 gold badges237 silver badges470 bronze badges




          207k10 gold badges237 silver badges470 bronze badges





















              0












              $begingroup$

              Rather than try to figure out what your detailed intentions are, let me just give a simple example. This kind of thing is easy with Function because it holds its arguments until it is applied. You may thus reach into a Function and perform arbitrary replacements. There is no need to clumsily edit text. Here, I define powerN as a prototype, and do replacements:



              powerN = Function[x, x^n];
              power2 = powerN /. n -> 2
              (* Function[x, x^2] *)


              Another way is to define a constructor:



              power[n_] := Function[x, x^n]
              power[2]
              (* Function[x$, x$^2] *)





              share|improve this answer









              $endgroup$












              • $begingroup$
                I think injecting the variable bits into the Internal`InheritedBlock is more my problem, but thanks.
                $endgroup$
                – Chris K
                8 hours ago















              0












              $begingroup$

              Rather than try to figure out what your detailed intentions are, let me just give a simple example. This kind of thing is easy with Function because it holds its arguments until it is applied. You may thus reach into a Function and perform arbitrary replacements. There is no need to clumsily edit text. Here, I define powerN as a prototype, and do replacements:



              powerN = Function[x, x^n];
              power2 = powerN /. n -> 2
              (* Function[x, x^2] *)


              Another way is to define a constructor:



              power[n_] := Function[x, x^n]
              power[2]
              (* Function[x$, x$^2] *)





              share|improve this answer









              $endgroup$












              • $begingroup$
                I think injecting the variable bits into the Internal`InheritedBlock is more my problem, but thanks.
                $endgroup$
                – Chris K
                8 hours ago













              0












              0








              0





              $begingroup$

              Rather than try to figure out what your detailed intentions are, let me just give a simple example. This kind of thing is easy with Function because it holds its arguments until it is applied. You may thus reach into a Function and perform arbitrary replacements. There is no need to clumsily edit text. Here, I define powerN as a prototype, and do replacements:



              powerN = Function[x, x^n];
              power2 = powerN /. n -> 2
              (* Function[x, x^2] *)


              Another way is to define a constructor:



              power[n_] := Function[x, x^n]
              power[2]
              (* Function[x$, x$^2] *)





              share|improve this answer









              $endgroup$



              Rather than try to figure out what your detailed intentions are, let me just give a simple example. This kind of thing is easy with Function because it holds its arguments until it is applied. You may thus reach into a Function and perform arbitrary replacements. There is no need to clumsily edit text. Here, I define powerN as a prototype, and do replacements:



              powerN = Function[x, x^n];
              power2 = powerN /. n -> 2
              (* Function[x, x^2] *)


              Another way is to define a constructor:



              power[n_] := Function[x, x^n]
              power[2]
              (* Function[x$, x$^2] *)






              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered 8 hours ago









              John DotyJohn Doty

              8,4331 gold badge13 silver badges25 bronze badges




              8,4331 gold badge13 silver badges25 bronze badges











              • $begingroup$
                I think injecting the variable bits into the Internal`InheritedBlock is more my problem, but thanks.
                $endgroup$
                – Chris K
                8 hours ago
















              • $begingroup$
                I think injecting the variable bits into the Internal`InheritedBlock is more my problem, but thanks.
                $endgroup$
                – Chris K
                8 hours ago















              $begingroup$
              I think injecting the variable bits into the Internal`InheritedBlock is more my problem, but thanks.
              $endgroup$
              – Chris K
              8 hours ago




              $begingroup$
              I think injecting the variable bits into the Internal`InheritedBlock is more my problem, but thanks.
              $endgroup$
              – Chris K
              8 hours ago











              0












              $begingroup$

              Is there any reason why this won't work?



              doopDoopDoop~SetAttributes~HoldAll;
              doopDoopDoop[
              mon_Symbol, mons : __Symbol, vars : __Symbol, t_Symbol,
              body1_,
              body2_
              ] :=
              Function[mon,
              Function[mons,
              Internal`InheritedBlock[vars,
              vars[[1]] =.;
              vars[[2]] =.;
              body1;
              vars[[-1]] =.;
              vars[[1]] vars = mons[[1]] mons;
              vars[[2]][t] = mons[[2]];
              body2;
              vars[[-1]][t] = mons[[-1]];
              mon
              ]
              ]
              ]


              Then:



              doopDoopDoop[
              a, b, c, d, e, t,
              1,
              2
              ]

              Function[a,
              Function[b, c,
              Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
              1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
              t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]


              The annoying thing will be the parameter injection if you have mons stored as a list. In this case I'm going to assume you have each variable wrapped in Hold, because that makes it a bit more subtle. The way we'll prep the parameter list is then:



              depVar = Hold@a;
              mons = Thread@Hold@b, c;
              vars = Thread@Hold@d, e;
              timeVar = Hold@t;

              paramList =
              Thread[depVar, Thread[mons, Hold], Thread[vars, Hold], timeVar, Hold]

              Hold[a, b, c, d, e, t]


              Then we inject it like:



              Replace[
              paramList,
              Hold[pars_] :>
              doopDoopDoop[
              pars,
              1,
              2
              ]
              ]

              Function[a,
              Function[b, c,
              Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
              1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
              t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]


              In general, the final thing you'll want to do with an injection is wrap it in a Replace to inject the contents of the Hold or provide a function with DownValues that does the injection, e.g.:



              doopDoopDoopHold~SetAttributes~HoldRest;
              doopDoopDoopHold[
              Hold[pars : mon_Symbol, mons : __Symbol, vars : __Symbol, t_Symbol],
              body1_,
              body2_
              ] :=
              doopDoopDoop[pars, body1, body2];

              doopDoopDoopHold[paramList, 1, 2]

              Function[a,
              Function[b, c,
              Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
              1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
              t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]





              share|improve this answer









              $endgroup$

















                0












                $begingroup$

                Is there any reason why this won't work?



                doopDoopDoop~SetAttributes~HoldAll;
                doopDoopDoop[
                mon_Symbol, mons : __Symbol, vars : __Symbol, t_Symbol,
                body1_,
                body2_
                ] :=
                Function[mon,
                Function[mons,
                Internal`InheritedBlock[vars,
                vars[[1]] =.;
                vars[[2]] =.;
                body1;
                vars[[-1]] =.;
                vars[[1]] vars = mons[[1]] mons;
                vars[[2]][t] = mons[[2]];
                body2;
                vars[[-1]][t] = mons[[-1]];
                mon
                ]
                ]
                ]


                Then:



                doopDoopDoop[
                a, b, c, d, e, t,
                1,
                2
                ]

                Function[a,
                Function[b, c,
                Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
                1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
                t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]


                The annoying thing will be the parameter injection if you have mons stored as a list. In this case I'm going to assume you have each variable wrapped in Hold, because that makes it a bit more subtle. The way we'll prep the parameter list is then:



                depVar = Hold@a;
                mons = Thread@Hold@b, c;
                vars = Thread@Hold@d, e;
                timeVar = Hold@t;

                paramList =
                Thread[depVar, Thread[mons, Hold], Thread[vars, Hold], timeVar, Hold]

                Hold[a, b, c, d, e, t]


                Then we inject it like:



                Replace[
                paramList,
                Hold[pars_] :>
                doopDoopDoop[
                pars,
                1,
                2
                ]
                ]

                Function[a,
                Function[b, c,
                Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
                1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
                t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]


                In general, the final thing you'll want to do with an injection is wrap it in a Replace to inject the contents of the Hold or provide a function with DownValues that does the injection, e.g.:



                doopDoopDoopHold~SetAttributes~HoldRest;
                doopDoopDoopHold[
                Hold[pars : mon_Symbol, mons : __Symbol, vars : __Symbol, t_Symbol],
                body1_,
                body2_
                ] :=
                doopDoopDoop[pars, body1, body2];

                doopDoopDoopHold[paramList, 1, 2]

                Function[a,
                Function[b, c,
                Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
                1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
                t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]





                share|improve this answer









                $endgroup$















                  0












                  0








                  0





                  $begingroup$

                  Is there any reason why this won't work?



                  doopDoopDoop~SetAttributes~HoldAll;
                  doopDoopDoop[
                  mon_Symbol, mons : __Symbol, vars : __Symbol, t_Symbol,
                  body1_,
                  body2_
                  ] :=
                  Function[mon,
                  Function[mons,
                  Internal`InheritedBlock[vars,
                  vars[[1]] =.;
                  vars[[2]] =.;
                  body1;
                  vars[[-1]] =.;
                  vars[[1]] vars = mons[[1]] mons;
                  vars[[2]][t] = mons[[2]];
                  body2;
                  vars[[-1]][t] = mons[[-1]];
                  mon
                  ]
                  ]
                  ]


                  Then:



                  doopDoopDoop[
                  a, b, c, d, e, t,
                  1,
                  2
                  ]

                  Function[a,
                  Function[b, c,
                  Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
                  1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
                  t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]


                  The annoying thing will be the parameter injection if you have mons stored as a list. In this case I'm going to assume you have each variable wrapped in Hold, because that makes it a bit more subtle. The way we'll prep the parameter list is then:



                  depVar = Hold@a;
                  mons = Thread@Hold@b, c;
                  vars = Thread@Hold@d, e;
                  timeVar = Hold@t;

                  paramList =
                  Thread[depVar, Thread[mons, Hold], Thread[vars, Hold], timeVar, Hold]

                  Hold[a, b, c, d, e, t]


                  Then we inject it like:



                  Replace[
                  paramList,
                  Hold[pars_] :>
                  doopDoopDoop[
                  pars,
                  1,
                  2
                  ]
                  ]

                  Function[a,
                  Function[b, c,
                  Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
                  1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
                  t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]


                  In general, the final thing you'll want to do with an injection is wrap it in a Replace to inject the contents of the Hold or provide a function with DownValues that does the injection, e.g.:



                  doopDoopDoopHold~SetAttributes~HoldRest;
                  doopDoopDoopHold[
                  Hold[pars : mon_Symbol, mons : __Symbol, vars : __Symbol, t_Symbol],
                  body1_,
                  body2_
                  ] :=
                  doopDoopDoop[pars, body1, body2];

                  doopDoopDoopHold[paramList, 1, 2]

                  Function[a,
                  Function[b, c,
                  Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
                  1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
                  t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]





                  share|improve this answer









                  $endgroup$



                  Is there any reason why this won't work?



                  doopDoopDoop~SetAttributes~HoldAll;
                  doopDoopDoop[
                  mon_Symbol, mons : __Symbol, vars : __Symbol, t_Symbol,
                  body1_,
                  body2_
                  ] :=
                  Function[mon,
                  Function[mons,
                  Internal`InheritedBlock[vars,
                  vars[[1]] =.;
                  vars[[2]] =.;
                  body1;
                  vars[[-1]] =.;
                  vars[[1]] vars = mons[[1]] mons;
                  vars[[2]][t] = mons[[2]];
                  body2;
                  vars[[-1]][t] = mons[[-1]];
                  mon
                  ]
                  ]
                  ]


                  Then:



                  doopDoopDoop[
                  a, b, c, d, e, t,
                  1,
                  2
                  ]

                  Function[a,
                  Function[b, c,
                  Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
                  1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
                  t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]


                  The annoying thing will be the parameter injection if you have mons stored as a list. In this case I'm going to assume you have each variable wrapped in Hold, because that makes it a bit more subtle. The way we'll prep the parameter list is then:



                  depVar = Hold@a;
                  mons = Thread@Hold@b, c;
                  vars = Thread@Hold@d, e;
                  timeVar = Hold@t;

                  paramList =
                  Thread[depVar, Thread[mons, Hold], Thread[vars, Hold], timeVar, Hold]

                  Hold[a, b, c, d, e, t]


                  Then we inject it like:



                  Replace[
                  paramList,
                  Hold[pars_] :>
                  doopDoopDoop[
                  pars,
                  1,
                  2
                  ]
                  ]

                  Function[a,
                  Function[b, c,
                  Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
                  1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
                  t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]


                  In general, the final thing you'll want to do with an injection is wrap it in a Replace to inject the contents of the Hold or provide a function with DownValues that does the injection, e.g.:



                  doopDoopDoopHold~SetAttributes~HoldRest;
                  doopDoopDoopHold[
                  Hold[pars : mon_Symbol, mons : __Symbol, vars : __Symbol, t_Symbol],
                  body1_,
                  body2_
                  ] :=
                  doopDoopDoop[pars, body1, body2];

                  doopDoopDoopHold[paramList, 1, 2]

                  Function[a,
                  Function[b, c,
                  Internal`InheritedBlock[d, e, (d, e[[1]]) =.; (d, e[[2]]) =.;
                  1; (d, e[[-1]]) =.; d, e[[1]] d, e = b, c[[1]] b, c; d, e[[2]][
                  t] = b, c[[2]]; 2; d, e[[-1]][t] = b, c[[-1]]; a]]]






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 8 hours ago









                  b3m2a1b3m2a1

                  31.2k3 gold badges62 silver badges183 bronze badges




                  31.2k3 gold badges62 silver badges183 bronze badges



























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