Create Array from list of indices/valuesIs there a faster way to create a matrix of indices from ragged data?Efficient submatrix swaps for large sparse matrixHow to create automatically some matrices for symbolic manipulation?How to partition a 2-D array properly?How to convert an output of a matrix into a PNG image?Plotting points using adjacency matrixFind the indices of elements which are larger than 10 in a listExtract a matrix from a ListInterpolationReplace elements of a matrix with zeros using another matrixConverting from “matrix” data into “coordinate” data
Use chown -R while excluding one or two files
Operation Unz̖̬̜̺̬a͇͖̯͔͉l̟̭g͕̝̼͇͓̪͍o̬̝͍̹̻
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Does this sentence I constructed with my junior high school latin work? I write online advertising and want to come off as snobby as possible
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Create Array from list of indices/values
Is there a faster way to create a matrix of indices from ragged data?Efficient submatrix swaps for large sparse matrixHow to create automatically some matrices for symbolic manipulation?How to partition a 2-D array properly?How to convert an output of a matrix into a PNG image?Plotting points using adjacency matrixFind the indices of elements which are larger than 10 in a listExtract a matrix from a ListInterpolationReplace elements of a matrix with zeros using another matrixConverting from “matrix” data into “coordinate” data
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
Is there is a performat way to convert something like
0,0,a,0,1,c,1,0,d,1,1,e
into
a,b,c,d
The indices are not always orderes and the only solution I can think of is searching for the maximum indices, create a matrix filled with 0 and use map afterwards to modify the matrix.
Is there is a better way?
Thank you,
Martin
list-manipulation matrix conversion
edited 11 hours ago
Kuba♦
110k12 gold badges217 silver badges554 bronze badges
asked 11 hours ago
MartinMartin
411 bronze badge
New contributor
Martin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Is there is a performat way to convert something like
0,0,a,0,1,c,1,0,d,1,1,e
into
a,b,c,d
The indices are not always orderes and the only solution I can think of is searching for the maximum indices, create a matrix filled with 0 and use map afterwards to modify the matrix.
Is there is a better way?
Thank you,
Martin
list-manipulation matrix conversion
edited 11 hours ago
Kuba♦
110k12 gold badges217 silver badges554 bronze badges
asked 11 hours ago
MartinMartin
411 bronze badge
New contributor
Martin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
2
$begingroup$
I assume that when you write0,0,a,0,1,c,1,0,d,1,1,eyou actually mean0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d, Please check that the input is correct.
$endgroup$
– rhermans
11 hours ago
add a comment |
$begingroup$
Is there is a performat way to convert something like
0,0,a,0,1,c,1,0,d,1,1,e
into
a,b,c,d
The indices are not always orderes and the only solution I can think of is searching for the maximum indices, create a matrix filled with 0 and use map afterwards to modify the matrix.
Is there is a better way?
Thank you,
Martin
list-manipulation matrix conversion
edited 11 hours ago
Kuba♦
110k12 gold badges217 silver badges554 bronze badges
asked 11 hours ago
MartinMartin
411 bronze badge
New contributor
Martin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Is there is a performat way to convert something like
0,0,a,0,1,c,1,0,d,1,1,e
into
a,b,c,d
The indices are not always orderes and the only solution I can think of is searching for the maximum indices, create a matrix filled with 0 and use map afterwards to modify the matrix.
Is there is a better way?
Thank you,
Martin
list-manipulation matrix conversion
list-manipulation matrix conversion
edited 11 hours ago
Kuba♦
110k12 gold badges217 silver badges554 bronze badges
asked 11 hours ago
MartinMartin
411 bronze badge
New contributor
Martin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 11 hours ago
Kuba♦
110k12 gold badges217 silver badges554 bronze badges
asked 11 hours ago
MartinMartin
411 bronze badge
New contributor
Martin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 11 hours ago
Kuba♦
110k12 gold badges217 silver badges554 bronze badges
edited 11 hours ago
Kuba♦
110k12 gold badges217 silver badges554 bronze badges
edited 11 hours ago
Kuba♦
110k12 gold badges217 silver badges554 bronze badges
110k12 gold badges217 silver badges554 bronze badges
asked 11 hours ago
MartinMartin
411 bronze badge
New contributor
Martin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 11 hours ago
MartinMartin
411 bronze badge
asked 11 hours ago
MartinMartin
411 bronze badge
411 bronze badge
New contributor
Martin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Martin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
$begingroup$
I assume that when you write0,0,a,0,1,c,1,0,d,1,1,eyou actually mean0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d, Please check that the input is correct.
$endgroup$
– rhermans
11 hours ago
add a comment |
2
$begingroup$
I assume that when you write0,0,a,0,1,c,1,0,d,1,1,eyou actually mean0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d, Please check that the input is correct.
$endgroup$
– rhermans
11 hours ago
2
2
$begingroup$
I assume that when you write
0,0,a,0,1,c,1,0,d,1,1,e you actually mean 0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d, Please check that the input is correct.$endgroup$
– rhermans
11 hours ago
$begingroup$
I assume that when you write
0,0,a,0,1,c,1,0,d,1,1,e you actually mean 0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d, Please check that the input is correct.$endgroup$
– rhermans
11 hours ago
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
spec = 0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d;
Normal @ SparseArray[# + 1 -> #2 & @@@ spec]
a, b, c, d
answered 11 hours ago
Kuba♦Kuba
110k12 gold badges217 silver badges554 bronze badges
$endgroup$
add a comment |
$begingroup$
Also possible:
r = 0, 0, a, 0, 1, c, 1, 0, d, 1, 1, e;
SparseArray[r[[All, 1]] + 1 -> r[[All, 2]]]
answered 11 hours ago
Henrik SchumacherHenrik Schumacher
65.3k5 gold badges94 silver badges180 bronze badges
$endgroup$
add a comment |
$begingroup$
(Array[#1, #2 &, 2, 2]-1)/.Rule@@@list
a, b, c, d
where
list=0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d;
answered 8 hours ago
user1066user1066
6,4482 gold badges20 silver badges33 bronze badges
$endgroup$
$begingroup$
I think you misinterpret the question. The index may not be limited by 2.
$endgroup$
– rhermans
8 hours ago
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
spec = 0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d;
Normal @ SparseArray[# + 1 -> #2 & @@@ spec]
a, b, c, d
answered 11 hours ago
Kuba♦Kuba
110k12 gold badges217 silver badges554 bronze badges
$endgroup$
add a comment |
$begingroup$
spec = 0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d;
Normal @ SparseArray[# + 1 -> #2 & @@@ spec]
a, b, c, d
answered 11 hours ago
Kuba♦Kuba
110k12 gold badges217 silver badges554 bronze badges
$endgroup$
add a comment |
$begingroup$
spec = 0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d;
Normal @ SparseArray[# + 1 -> #2 & @@@ spec]
a, b, c, d
answered 11 hours ago
Kuba♦Kuba
110k12 gold badges217 silver badges554 bronze badges
$endgroup$
spec = 0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d;
Normal @ SparseArray[# + 1 -> #2 & @@@ spec]
a, b, c, d
answered 11 hours ago
Kuba♦Kuba
110k12 gold badges217 silver badges554 bronze badges
answered 11 hours ago
Kuba♦Kuba
110k12 gold badges217 silver badges554 bronze badges
answered 11 hours ago
Kuba♦Kuba
110k12 gold badges217 silver badges554 bronze badges
answered 11 hours ago
Kuba♦Kuba
110k12 gold badges217 silver badges554 bronze badges
110k12 gold badges217 silver badges554 bronze badges
add a comment |
add a comment |
$begingroup$
Also possible:
r = 0, 0, a, 0, 1, c, 1, 0, d, 1, 1, e;
SparseArray[r[[All, 1]] + 1 -> r[[All, 2]]]
answered 11 hours ago
Henrik SchumacherHenrik Schumacher
65.3k5 gold badges94 silver badges180 bronze badges
$endgroup$
add a comment |
$begingroup$
Also possible:
r = 0, 0, a, 0, 1, c, 1, 0, d, 1, 1, e;
SparseArray[r[[All, 1]] + 1 -> r[[All, 2]]]
answered 11 hours ago
Henrik SchumacherHenrik Schumacher
65.3k5 gold badges94 silver badges180 bronze badges
$endgroup$
add a comment |
$begingroup$
Also possible:
r = 0, 0, a, 0, 1, c, 1, 0, d, 1, 1, e;
SparseArray[r[[All, 1]] + 1 -> r[[All, 2]]]
answered 11 hours ago
Henrik SchumacherHenrik Schumacher
65.3k5 gold badges94 silver badges180 bronze badges
$endgroup$
Also possible:
r = 0, 0, a, 0, 1, c, 1, 0, d, 1, 1, e;
SparseArray[r[[All, 1]] + 1 -> r[[All, 2]]]
answered 11 hours ago
Henrik SchumacherHenrik Schumacher
65.3k5 gold badges94 silver badges180 bronze badges
answered 11 hours ago
Henrik SchumacherHenrik Schumacher
65.3k5 gold badges94 silver badges180 bronze badges
answered 11 hours ago
Henrik SchumacherHenrik Schumacher
65.3k5 gold badges94 silver badges180 bronze badges
answered 11 hours ago
Henrik SchumacherHenrik Schumacher
65.3k5 gold badges94 silver badges180 bronze badges
65.3k5 gold badges94 silver badges180 bronze badges
add a comment |
add a comment |
$begingroup$
(Array[#1, #2 &, 2, 2]-1)/.Rule@@@list
a, b, c, d
where
list=0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d;
answered 8 hours ago
user1066user1066
6,4482 gold badges20 silver badges33 bronze badges
$endgroup$
$begingroup$
I think you misinterpret the question. The index may not be limited by 2.
$endgroup$
– rhermans
8 hours ago
add a comment |
$begingroup$
(Array[#1, #2 &, 2, 2]-1)/.Rule@@@list
a, b, c, d
where
list=0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d;
answered 8 hours ago
user1066user1066
6,4482 gold badges20 silver badges33 bronze badges
$endgroup$
$begingroup$
I think you misinterpret the question. The index may not be limited by 2.
$endgroup$
– rhermans
8 hours ago
add a comment |
$begingroup$
(Array[#1, #2 &, 2, 2]-1)/.Rule@@@list
a, b, c, d
where
list=0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d;
answered 8 hours ago
user1066user1066
6,4482 gold badges20 silver badges33 bronze badges
$endgroup$
(Array[#1, #2 &, 2, 2]-1)/.Rule@@@list
a, b, c, d
where
list=0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d;
answered 8 hours ago
user1066user1066
6,4482 gold badges20 silver badges33 bronze badges
answered 8 hours ago
user1066user1066
6,4482 gold badges20 silver badges33 bronze badges
answered 8 hours ago
user1066user1066
6,4482 gold badges20 silver badges33 bronze badges
answered 8 hours ago
user1066user1066
6,4482 gold badges20 silver badges33 bronze badges
6,4482 gold badges20 silver badges33 bronze badges
$begingroup$
I think you misinterpret the question. The index may not be limited by 2.
$endgroup$
– rhermans
8 hours ago
add a comment |
$begingroup$
I think you misinterpret the question. The index may not be limited by 2.
$endgroup$
– rhermans
8 hours ago
$begingroup$
I think you misinterpret the question. The index may not be limited by 2.
$endgroup$
– rhermans
8 hours ago
$begingroup$
I think you misinterpret the question. The index may not be limited by 2.
$endgroup$
– rhermans
8 hours ago
add a comment |
Martin is a new contributor. Be nice, and check out our Code of Conduct.
Martin is a new contributor. Be nice, and check out our Code of Conduct.
Martin is a new contributor. Be nice, and check out our Code of Conduct.
Martin is a new contributor. Be nice, and check out our Code of Conduct.
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2
$begingroup$
I assume that when you write
0,0,a,0,1,c,1,0,d,1,1,eyou actually mean0, 0, a, 0, 1, b, 1, 0, c, 1, 1, d, Please check that the input is correct.$endgroup$
– rhermans
11 hours ago