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1

1

When I am setting a variable to a command, I am getting the answer along with the error "command not found". Below is the command in the script.

#!/bin/bash

fs=$(ps -C "daemon_name" > /dev/null && echo "Running" || echo "Not Running")

$fs

Output:

./test.sh: Line 5: Running: command not found

bash shell variable

share|improve this question

edited 7 hours ago

ctrl-alt-delor

13k52663

asked 8 hours ago

SLSSLS

83

New contributor

SLS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

1

1

When I am setting a variable to a command, I am getting the answer along with the error "command not found". Below is the command in the script.

#!/bin/bash

fs=$(ps -C "daemon_name" > /dev/null && echo "Running" || echo "Not Running")

$fs

Output:

./test.sh: Line 5: Running: command not found

bash shell variable

share|improve this question

edited 7 hours ago

ctrl-alt-delor

13k52663

asked 8 hours ago

SLSSLS

83

New contributor

SLS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

When I am setting a variable to a command, I am getting the answer along with the error "command not found". Below is the command in the script.

#!/bin/bash

fs=$(ps -C "daemon_name" > /dev/null && echo "Running" || echo "Not Running")

$fs

Output:

./test.sh: Line 5: Running: command not found

bash shell variable

share|improve this question

edited 7 hours ago

ctrl-alt-delor

13k52663

asked 8 hours ago

SLSSLS

83

New contributor

SLS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

#!/bin/bash

fs=$(ps -C "daemon_name" > /dev/null && echo "Running" || echo "Not Running")

$fs

./test.sh: Line 5: Running: command not found

share|improve this question

edited 7 hours ago

ctrl-alt-delor

13k52663

asked 8 hours ago

SLSSLS

83

New contributor

SLS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 7 hours ago

ctrl-alt-delor

13k52663

asked 8 hours ago

SLSSLS

83

New contributor

SLS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

edited 7 hours ago

ctrl-alt-delor

13k52663

edited 7 hours ago

ctrl-alt-delor

13k52663

asked 8 hours ago

SLSSLS

83

New contributor

SLS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 8 hours ago

SLSSLS

83

1 Answer
1

active

oldest

votes

4

ps is finding the process you are looking for which causes your fs variable to be set to Running. When you call $fs you are essentially just trying to run Running. Since there is no command named Running on your system you get command not found. I imagine you want to echo or printf the result?

printf '%sn' "$fs"

share|improve this answer

edited 8 hours ago

ilkkachu

64.2k10107185

answered 8 hours ago

Jesse_bJesse_b

16.1k34078

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Thank you, your suggestion cleared that up for me. I went with echo, but I tried both and they worked. Have a good one!
  
  – SLS
  7 hours ago
  

  
  
  
  

add a comment | 

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4

ps is finding the process you are looking for which causes your fs variable to be set to Running. When you call $fs you are essentially just trying to run Running. Since there is no command named Running on your system you get command not found. I imagine you want to echo or printf the result?

printf '%sn' "$fs"

share|improve this answer

edited 8 hours ago

ilkkachu

64.2k10107185

answered 8 hours ago

Jesse_bJesse_b

16.1k34078

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Thank you, your suggestion cleared that up for me. I went with echo, but I tried both and they worked. Have a good one!
  
  – SLS
  7 hours ago
  

  
  
  
  

add a comment | 

4

ps is finding the process you are looking for which causes your fs variable to be set to Running. When you call $fs you are essentially just trying to run Running. Since there is no command named Running on your system you get command not found. I imagine you want to echo or printf the result?

printf '%sn' "$fs"

share|improve this answer

edited 8 hours ago

ilkkachu

64.2k10107185

answered 8 hours ago

Jesse_bJesse_b

16.1k34078

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Thank you, your suggestion cleared that up for me. I went with echo, but I tried both and they worked. Have a good one!
  
  – SLS
  7 hours ago
  

  
  
  
  

add a comment | 

ps is finding the process you are looking for which causes your fs variable to be set to Running. When you call $fs you are essentially just trying to run Running. Since there is no command named Running on your system you get command not found. I imagine you want to echo or printf the result?

printf '%sn' "$fs"

share|improve this answer

edited 8 hours ago

ilkkachu

64.2k10107185

answered 8 hours ago

Jesse_bJesse_b

16.1k34078

printf '%sn' "$fs"

share|improve this answer

edited 8 hours ago

ilkkachu

64.2k10107185

answered 8 hours ago

Jesse_bJesse_b

16.1k34078

edited 8 hours ago

ilkkachu

64.2k10107185

edited 8 hours ago

ilkkachu

64.2k10107185

answered 8 hours ago

Jesse_bJesse_b

16.1k34078

answered 8 hours ago

Jesse_bJesse_b

16.1k34078