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Is there formal test of non-linearity in linear regression?
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Is there formal test of non-linearity in linear regression?
Statistic for the curvature or non-linearity of a datasetFormal errors from non-negative least-squares?Multiple regression - how to deal with mixed linear and non-linear variablesNon linearity in data using regressionHow to specify logistic regression as transformed linear regression?Interpreting linearity in regression when there are outliersHow can I use residual plots to determine whether or not a linear classifier is suitable?Which regression methods are adequate in proving the following relationship?How to test the proportional odds assumption for ordinal regression?Formal definition of a Regression Tree
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$begingroup$
In logistic regression there is box-tidwel but I know of nothing like that in linear regression. I use partial residual plots to look for this, a graphical feature, but would love to find a formal test (in honesty I doubt you can do a formal test of this, but I could be wrong).
regression
$endgroup$
add a comment |
$begingroup$
In logistic regression there is box-tidwel but I know of nothing like that in linear regression. I use partial residual plots to look for this, a graphical feature, but would love to find a formal test (in honesty I doubt you can do a formal test of this, but I could be wrong).
regression
$endgroup$
add a comment |
$begingroup$
In logistic regression there is box-tidwel but I know of nothing like that in linear regression. I use partial residual plots to look for this, a graphical feature, but would love to find a formal test (in honesty I doubt you can do a formal test of this, but I could be wrong).
regression
$endgroup$
In logistic regression there is box-tidwel but I know of nothing like that in linear regression. I use partial residual plots to look for this, a graphical feature, but would love to find a formal test (in honesty I doubt you can do a formal test of this, but I could be wrong).
regression
regression
asked 5 hours ago
user54285user54285
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$begingroup$
Box-Tidwell was developed for models fitted by least squared (i.e. including ordinary regression).
So if you were inclined to use Box-Tidwell for this, that's actually what it's designed for.
It's not the only possible approach, but it sounds like an approach you're already familiar with.
I'm not convinced that (most times it's used) a formal test is appropriate - I believe it usually answers the wrong question, while the diagnostic plots you've been looking at come closer to answering a useful question.
$endgroup$
add a comment |
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1 Answer
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$begingroup$
Box-Tidwell was developed for models fitted by least squared (i.e. including ordinary regression).
So if you were inclined to use Box-Tidwell for this, that's actually what it's designed for.
It's not the only possible approach, but it sounds like an approach you're already familiar with.
I'm not convinced that (most times it's used) a formal test is appropriate - I believe it usually answers the wrong question, while the diagnostic plots you've been looking at come closer to answering a useful question.
$endgroup$
add a comment |
$begingroup$
Box-Tidwell was developed for models fitted by least squared (i.e. including ordinary regression).
So if you were inclined to use Box-Tidwell for this, that's actually what it's designed for.
It's not the only possible approach, but it sounds like an approach you're already familiar with.
I'm not convinced that (most times it's used) a formal test is appropriate - I believe it usually answers the wrong question, while the diagnostic plots you've been looking at come closer to answering a useful question.
$endgroup$
add a comment |
$begingroup$
Box-Tidwell was developed for models fitted by least squared (i.e. including ordinary regression).
So if you were inclined to use Box-Tidwell for this, that's actually what it's designed for.
It's not the only possible approach, but it sounds like an approach you're already familiar with.
I'm not convinced that (most times it's used) a formal test is appropriate - I believe it usually answers the wrong question, while the diagnostic plots you've been looking at come closer to answering a useful question.
$endgroup$
Box-Tidwell was developed for models fitted by least squared (i.e. including ordinary regression).
So if you were inclined to use Box-Tidwell for this, that's actually what it's designed for.
It's not the only possible approach, but it sounds like an approach you're already familiar with.
I'm not convinced that (most times it's used) a formal test is appropriate - I believe it usually answers the wrong question, while the diagnostic plots you've been looking at come closer to answering a useful question.
answered 1 hour ago
Glen_b♦Glen_b
216k23422775
216k23422775
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