Orbital mechanics: Jump from ISS, where will I meet again?How hard do you have to throw something off the ISS to make it deorbit?What are the choices today for orbital mechanics simulation software?Orbital mechanics: trying to understand counterintuitive behavior (braking to overtake)Is there drag inside a Space craft?If you throw a baseball from the space station, will it return to you in 90 minutes?Satellite altitude as a function of time?Game for teaching basics of orbital mechanicsTwo 1000 kg gold spheres orbit their CM in near-contact, great way to measure G or limited by spaceflight issues?What orbital mechanics toolkits available today are suitable for a real-time simulator?
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Orbital mechanics: Jump from ISS, where will I meet again?
How hard do you have to throw something off the ISS to make it deorbit?What are the choices today for orbital mechanics simulation software?Orbital mechanics: trying to understand counterintuitive behavior (braking to overtake)Is there drag inside a Space craft?If you throw a baseball from the space station, will it return to you in 90 minutes?Satellite altitude as a function of time?Game for teaching basics of orbital mechanicsTwo 1000 kg gold spheres orbit their CM in near-contact, great way to measure G or limited by spaceflight issues?What orbital mechanics toolkits available today are suitable for a real-time simulator?
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This is a hypothetical question, and I hope it is on-topic here.
If an astronaut would stand on the surface of the ISS, and he or she will make a jump directed perfectly towards the earth, what will their orbit be, and when will they meet again with the ISS? After one round (90 Minutes) or half a round (45 Minutes) around the earth.
Note: I read somewhere (do not remember where) that two object, separated at a point, will meet again while in orbit (neglecting any atmospherical drag).
orbital-mechanics spacecraft
asked 10 hours ago
hitchhikerhitchhiker
1212 bronze badges
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add a comment
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$begingroup$
This is a hypothetical question, and I hope it is on-topic here.
If an astronaut would stand on the surface of the ISS, and he or she will make a jump directed perfectly towards the earth, what will their orbit be, and when will they meet again with the ISS? After one round (90 Minutes) or half a round (45 Minutes) around the earth.
Note: I read somewhere (do not remember where) that two object, separated at a point, will meet again while in orbit (neglecting any atmospherical drag).
orbital-mechanics spacecraft
asked 10 hours ago
hitchhikerhitchhiker
1212 bronze badges
$endgroup$
$begingroup$
Related: space.stackexchange.com/questions/28002/…
$endgroup$
– Organic Marble
9 hours ago
$begingroup$
Tristan's answer is generally correct; in practice at JSC, we used/wrote software tools that integrated the equations of motion for whatever object to determine if it would contact or re-contact the ISS. Analyses would consider multiple orbits to guard against something like the drag of the ISS eventually overcoming a larger initial impulse for the object. Two of the tools I remember: ADIOS (Adverse Departure Iterative Orbit Simulation) and Vireo ("It's a bird, not an acronym"). There were probably many more.
$endgroup$
– Erin Anne
2 hours ago
add a comment
|
$begingroup$
This is a hypothetical question, and I hope it is on-topic here.
If an astronaut would stand on the surface of the ISS, and he or she will make a jump directed perfectly towards the earth, what will their orbit be, and when will they meet again with the ISS? After one round (90 Minutes) or half a round (45 Minutes) around the earth.
Note: I read somewhere (do not remember where) that two object, separated at a point, will meet again while in orbit (neglecting any atmospherical drag).
orbital-mechanics spacecraft
asked 10 hours ago
hitchhikerhitchhiker
1212 bronze badges
$endgroup$
This is a hypothetical question, and I hope it is on-topic here.
If an astronaut would stand on the surface of the ISS, and he or she will make a jump directed perfectly towards the earth, what will their orbit be, and when will they meet again with the ISS? After one round (90 Minutes) or half a round (45 Minutes) around the earth.
Note: I read somewhere (do not remember where) that two object, separated at a point, will meet again while in orbit (neglecting any atmospherical drag).
orbital-mechanics spacecraft
orbital-mechanics spacecraft
asked 10 hours ago
hitchhikerhitchhiker
1212 bronze badges
asked 10 hours ago
hitchhikerhitchhiker
1212 bronze badges
asked 10 hours ago
hitchhikerhitchhiker
1212 bronze badges
asked 10 hours ago
hitchhikerhitchhiker
1212 bronze badges
asked 10 hours ago
hitchhikerhitchhiker
1212 bronze badges
1212 bronze badges
$begingroup$
Related: space.stackexchange.com/questions/28002/…
$endgroup$
– Organic Marble
9 hours ago
$begingroup$
Tristan's answer is generally correct; in practice at JSC, we used/wrote software tools that integrated the equations of motion for whatever object to determine if it would contact or re-contact the ISS. Analyses would consider multiple orbits to guard against something like the drag of the ISS eventually overcoming a larger initial impulse for the object. Two of the tools I remember: ADIOS (Adverse Departure Iterative Orbit Simulation) and Vireo ("It's a bird, not an acronym"). There were probably many more.
$endgroup$
– Erin Anne
2 hours ago
add a comment
|
$begingroup$
Related: space.stackexchange.com/questions/28002/…
$endgroup$
– Organic Marble
9 hours ago
$begingroup$
Tristan's answer is generally correct; in practice at JSC, we used/wrote software tools that integrated the equations of motion for whatever object to determine if it would contact or re-contact the ISS. Analyses would consider multiple orbits to guard against something like the drag of the ISS eventually overcoming a larger initial impulse for the object. Two of the tools I remember: ADIOS (Adverse Departure Iterative Orbit Simulation) and Vireo ("It's a bird, not an acronym"). There were probably many more.
$endgroup$
– Erin Anne
2 hours ago
$begingroup$
Related: space.stackexchange.com/questions/28002/…
$endgroup$
– Organic Marble
9 hours ago
$begingroup$
Related: space.stackexchange.com/questions/28002/…
$endgroup$
– Organic Marble
9 hours ago
$begingroup$
Tristan's answer is generally correct; in practice at JSC, we used/wrote software tools that integrated the equations of motion for whatever object to determine if it would contact or re-contact the ISS. Analyses would consider multiple orbits to guard against something like the drag of the ISS eventually overcoming a larger initial impulse for the object. Two of the tools I remember: ADIOS (Adverse Departure Iterative Orbit Simulation) and Vireo ("It's a bird, not an acronym"). There were probably many more.
$endgroup$
– Erin Anne
2 hours ago
$begingroup$
Tristan's answer is generally correct; in practice at JSC, we used/wrote software tools that integrated the equations of motion for whatever object to determine if it would contact or re-contact the ISS. Analyses would consider multiple orbits to guard against something like the drag of the ISS eventually overcoming a larger initial impulse for the object. Two of the tools I remember: ADIOS (Adverse Departure Iterative Orbit Simulation) and Vireo ("It's a bird, not an acronym"). There were probably many more.
$endgroup$
– Erin Anne
2 hours ago
add a comment
|
1 Answer
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If your jump is perfectly nadir pointing, and all perturbing forces are neglected so we can consider both your orbit and the ISS orbit as perfect two-body orbits, you will meet again after one full orbit, as a low-velocity impulse that is perfectly radial does not affect the orbital period.
From your perspective, relative to the ISS, you will move downward initially, then you will drift forward, then come back up, then drift backward, then eventually settle back down where you jumped from.
If I have time later, I can see if I can graph something up.
answered 8 hours ago
TristanTristan
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$begingroup$
If your jump is perfectly nadir pointing, and all perturbing forces are neglected so we can consider both your orbit and the ISS orbit as perfect two-body orbits, you will meet again after one full orbit, as a low-velocity impulse that is perfectly radial does not affect the orbital period.
From your perspective, relative to the ISS, you will move downward initially, then you will drift forward, then come back up, then drift backward, then eventually settle back down where you jumped from.
If I have time later, I can see if I can graph something up.
answered 8 hours ago
TristanTristan
12.7k1 gold badge43 silver badges63 bronze badges
$endgroup$
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$begingroup$
If your jump is perfectly nadir pointing, and all perturbing forces are neglected so we can consider both your orbit and the ISS orbit as perfect two-body orbits, you will meet again after one full orbit, as a low-velocity impulse that is perfectly radial does not affect the orbital period.
From your perspective, relative to the ISS, you will move downward initially, then you will drift forward, then come back up, then drift backward, then eventually settle back down where you jumped from.
If I have time later, I can see if I can graph something up.
answered 8 hours ago
TristanTristan
12.7k1 gold badge43 silver badges63 bronze badges
$endgroup$
add a comment
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$begingroup$
If your jump is perfectly nadir pointing, and all perturbing forces are neglected so we can consider both your orbit and the ISS orbit as perfect two-body orbits, you will meet again after one full orbit, as a low-velocity impulse that is perfectly radial does not affect the orbital period.
From your perspective, relative to the ISS, you will move downward initially, then you will drift forward, then come back up, then drift backward, then eventually settle back down where you jumped from.
If I have time later, I can see if I can graph something up.
answered 8 hours ago
TristanTristan
12.7k1 gold badge43 silver badges63 bronze badges
$endgroup$
If your jump is perfectly nadir pointing, and all perturbing forces are neglected so we can consider both your orbit and the ISS orbit as perfect two-body orbits, you will meet again after one full orbit, as a low-velocity impulse that is perfectly radial does not affect the orbital period.
From your perspective, relative to the ISS, you will move downward initially, then you will drift forward, then come back up, then drift backward, then eventually settle back down where you jumped from.
If I have time later, I can see if I can graph something up.
answered 8 hours ago
TristanTristan
12.7k1 gold badge43 silver badges63 bronze badges
answered 8 hours ago
TristanTristan
12.7k1 gold badge43 silver badges63 bronze badges
answered 8 hours ago
TristanTristan
12.7k1 gold badge43 silver badges63 bronze badges
answered 8 hours ago
TristanTristan
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Related: space.stackexchange.com/questions/28002/…
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– Organic Marble
9 hours ago
$begingroup$
Tristan's answer is generally correct; in practice at JSC, we used/wrote software tools that integrated the equations of motion for whatever object to determine if it would contact or re-contact the ISS. Analyses would consider multiple orbits to guard against something like the drag of the ISS eventually overcoming a larger initial impulse for the object. Two of the tools I remember: ADIOS (Adverse Departure Iterative Orbit Simulation) and Vireo ("It's a bird, not an acronym"). There were probably many more.
$endgroup$
– Erin Anne
2 hours ago