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what does “$@” mean inside a find command

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1

I recently saw a script in which below find command was used:

find "$@" -type f -name "*.iso"

What does "$@" mean here?

find

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1

I recently saw a script in which below find command was used:

find "$@" -type f -name "*.iso"

What does "$@" mean here?

find

share|improve this question

edited 11 hours ago

Prvt_Yadv

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I recently saw a script in which below find command was used:

find "$@" -type f -name "*.iso"

What does "$@" mean here?

find

share|improve this question

edited 11 hours ago

Prvt_Yadv

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asked 11 hours ago

A.KA.K

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edited 11 hours ago

Prvt_Yadv

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edited 11 hours ago

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4

"$@" expands to all arguments passed to the shell. It has nothing to do with find specifically.

https://linux.die.net/man/1/bash

@

Expands to the positional parameters, starting from one. When the
expansion occurs within double quotes, each parameter expands to a
separate word. That is, "$@" is equivalent to "$1" "$2" ... If the
double-quoted expansion occurs within a word, the expansion of the
first parameter is joined with the beginning part of the original
word, and the expansion of the last parameter is joined with the last
part of the original word. When there are no positional parameters,
"$@" and $@ expand to nothing (i.e., they are removed).

A more succinct practical+relevant example below.

$ cat a.sh
#!/bin/bash -x
find "$@" -ls
$ ./a.sh foo bar blah
+ find foo bar blah -ls
15481123719088698 4 -rw-rw-rw- 1 steve steve 4 Jun 30 19:29 foo
17451448556173323 0 -rw-rw-rw- 1 steve steve 0 Jun 30 19:29 bar
find: ‘blah’: No such file or directory
$

share|improve this answer

edited 10 hours ago

ilkkachu

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answered 11 hours ago

stevesteve

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4

"$@" expands to all arguments passed to the shell. It has nothing to do with find specifically.

https://linux.die.net/man/1/bash

@

Expands to the positional parameters, starting from one. When the
expansion occurs within double quotes, each parameter expands to a
separate word. That is, "$@" is equivalent to "$1" "$2" ... If the
double-quoted expansion occurs within a word, the expansion of the
first parameter is joined with the beginning part of the original
word, and the expansion of the last parameter is joined with the last
part of the original word. When there are no positional parameters,
"$@" and $@ expand to nothing (i.e., they are removed).

A more succinct practical+relevant example below.

$ cat a.sh
#!/bin/bash -x
find "$@" -ls
$ ./a.sh foo bar blah
+ find foo bar blah -ls
15481123719088698 4 -rw-rw-rw- 1 steve steve 4 Jun 30 19:29 foo
17451448556173323 0 -rw-rw-rw- 1 steve steve 0 Jun 30 19:29 bar
find: ‘blah’: No such file or directory
$

share|improve this answer

edited 10 hours ago

ilkkachu

64.7k1010 gold badges108108 silver badges188188 bronze badges

answered 11 hours ago

stevesteve

14.7k22 gold badges2929 silver badges5656 bronze badges

add a comment | 

4

"$@" expands to all arguments passed to the shell. It has nothing to do with find specifically.

https://linux.die.net/man/1/bash

@

Expands to the positional parameters, starting from one. When the
expansion occurs within double quotes, each parameter expands to a
separate word. That is, "$@" is equivalent to "$1" "$2" ... If the
double-quoted expansion occurs within a word, the expansion of the
first parameter is joined with the beginning part of the original
word, and the expansion of the last parameter is joined with the last
part of the original word. When there are no positional parameters,
"$@" and $@ expand to nothing (i.e., they are removed).

A more succinct practical+relevant example below.

$ cat a.sh
#!/bin/bash -x
find "$@" -ls
$ ./a.sh foo bar blah
+ find foo bar blah -ls
15481123719088698 4 -rw-rw-rw- 1 steve steve 4 Jun 30 19:29 foo
17451448556173323 0 -rw-rw-rw- 1 steve steve 0 Jun 30 19:29 bar
find: ‘blah’: No such file or directory
$

share|improve this answer

edited 10 hours ago

ilkkachu

64.7k1010 gold badges108108 silver badges188188 bronze badges

answered 11 hours ago

stevesteve

14.7k22 gold badges2929 silver badges5656 bronze badges

add a comment | 

"$@" expands to all arguments passed to the shell. It has nothing to do with find specifically.

https://linux.die.net/man/1/bash

@

Expands to the positional parameters, starting from one. When the
expansion occurs within double quotes, each parameter expands to a
separate word. That is, "$@" is equivalent to "$1" "$2" ... If the
double-quoted expansion occurs within a word, the expansion of the
first parameter is joined with the beginning part of the original
word, and the expansion of the last parameter is joined with the last
part of the original word. When there are no positional parameters,
"$@" and $@ expand to nothing (i.e., they are removed).

A more succinct practical+relevant example below.

$ cat a.sh
#!/bin/bash -x
find "$@" -ls
$ ./a.sh foo bar blah
+ find foo bar blah -ls
15481123719088698 4 -rw-rw-rw- 1 steve steve 4 Jun 30 19:29 foo
17451448556173323 0 -rw-rw-rw- 1 steve steve 0 Jun 30 19:29 bar
find: ‘blah’: No such file or directory
$

share|improve this answer

edited 10 hours ago

ilkkachu

64.7k1010 gold badges108108 silver badges188188 bronze badges

answered 11 hours ago

stevesteve

14.7k22 gold badges2929 silver badges5656 bronze badges

$ cat a.sh
#!/bin/bash -x
find "$@" -ls
$ ./a.sh foo bar blah
+ find foo bar blah -ls
15481123719088698 4 -rw-rw-rw- 1 steve steve 4 Jun 30 19:29 foo
17451448556173323 0 -rw-rw-rw- 1 steve steve 0 Jun 30 19:29 bar
find: ‘blah’: No such file or directory
$

share|improve this answer

edited 10 hours ago

ilkkachu

64.7k1010 gold badges108108 silver badges188188 bronze badges

answered 11 hours ago

stevesteve

14.7k22 gold badges2929 silver badges5656 bronze badges

edited 10 hours ago

ilkkachu

64.7k1010 gold badges108108 silver badges188188 bronze badges

edited 10 hours ago

ilkkachu

64.7k1010 gold badges108108 silver badges188188 bronze badges

answered 11 hours ago

stevesteve

14.7k22 gold badges2929 silver badges5656 bronze badges

answered 11 hours ago

stevesteve

14.7k22 gold badges2929 silver badges5656 bronze badges