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Reverse of diffraction


Does diffraction contribute to the Black Drop effect?Why does a CD work as a diffraction grating even with light from a light bulb?Diffraction Grating in spectrophotometerDiffraction problem - How do I interpretBasic rule for diffractionx-ray diffraction of crystalsTotal number of primary maxima in diffraction gratingDiffraction of monochromatic lightExplanation of single and double slit diffraction, and Frensel diffraction in light of Feynman's method of probability amplitudesDiffraction pattern vs Interference pattern






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4












$begingroup$


Can we arrange a practical in such a way that the dark and bright bands in diffraction grating be allowed to pass through the same slit to get the original light (i.e the incident light before diffraction), just like we reverse the arrows in reflection and refraction






optics visible-light reflection refraction diffraction







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  • 1




    $begingroup$
    You might want to look at a zone plate.
    $endgroup$
    – M. Enns
    8 hours ago

















4












$begingroup$


Can we arrange a practical in such a way that the dark and bright bands in diffraction grating be allowed to pass through the same slit to get the original light (i.e the incident light before diffraction), just like we reverse the arrows in reflection and refraction






optics visible-light reflection refraction diffraction







share|cite|improve this question









New contributor



Syed Hasnain Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$







  • 1




    $begingroup$
    You might want to look at a zone plate.
    $endgroup$
    – M. Enns
    8 hours ago













4












4








4





$begingroup$


Can we arrange a practical in such a way that the dark and bright bands in diffraction grating be allowed to pass through the same slit to get the original light (i.e the incident light before diffraction), just like we reverse the arrows in reflection and refraction






optics visible-light reflection refraction diffraction







share|cite|improve this question









New contributor



Syed Hasnain Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




Can we arrange a practical in such a way that the dark and bright bands in diffraction grating be allowed to pass through the same slit to get the original light (i.e the incident light before diffraction), just like we reverse the arrows in reflection and refraction






optics visible-light reflection refraction diffraction




optics visible-light reflection refraction diffraction






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Syed Hasnain Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|cite|improve this question









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edited 7 hours ago









Qmechanic♦

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asked 8 hours ago









Syed Hasnain AhmedSyed Hasnain Ahmed

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  • 1




    $begingroup$
    You might want to look at a zone plate.
    $endgroup$
    – M. Enns
    8 hours ago












  • 1




    $begingroup$
    You might want to look at a zone plate.
    $endgroup$
    – M. Enns
    8 hours ago







1




1




$begingroup$
You might want to look at a zone plate.
$endgroup$
– M. Enns
8 hours ago




$begingroup$
You might want to look at a zone plate.
$endgroup$
– M. Enns
8 hours ago










3 Answers
3






active

oldest

votes


















2












$begingroup$

Optics is time-reversal invariant, so the short answer is "yes".



As a practical matter it is essentially impossible to set up the exact reversed situation, but we can set up good approximations in some cases (and in particular in electromagnetic bands not including visible light). Once the approximation is good enough it becomes useful.



A "phased array" transmitter is exactly a mechanism for focusing electromagnetic waves by emitting them from many places with carefully arranged phase off-sets. They are difficult to build, tune, and operate effectively; but they are a thing.






share|cite|improve this answer









$endgroup$




















    2












    $begingroup$

    Reversing diffraction is precisely what is done in Fourier Optics!



    There, instead of placing a screen after the slit to see the diffraction pattern, a lens is put there instead. If you arrange the diffraction image to lie at the back focal plane of the lens, you will see the image of the slit itself at the front focal plane of the lens.



    This procedure of reversing diffraction relies on a fundamental Fourier transform property of a thin lens. The idea is that placing an object exactly one focal length $+f$ away from the lens will produce an image of the object one focal length $-f$ on the opposite side that is the Fourier transform of the object.



    This is shown in the image below



    cns-alumni.bu.edu






    share|cite|improve this answer









    $endgroup$




















      1












      $begingroup$

      for light beams, you might also consider something called a corner reflector or retro-reflector. this is a glass prism cut in such a way that any beam of light entering it is reflected back at almost exactly the same angle that it made going into the prism. if you constructed a flat plate containing a large number of small corner reflectors and placed it at the location of the screen in the experiment you describe, then all the light striking the plate across its width would be reflected back to the slit.



      I do not know how that collection of beams coming back into the slit would behave when they all meet!






      share|cite|improve this answer









      $endgroup$












      • $begingroup$
        Glass corner cubes aren't so simple. Rays do not counterpropagate on themselves. And each of the six possible paths of a ray through a corner cube affects the phase of the light differently. Metallic reflecting corner cubes help, but since metals are not perfect conductors, there is still a small phase/polarization effect, but there is energy lost.
        $endgroup$
        – garyp
        4 hours ago














      Your Answer








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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2












      $begingroup$

      Optics is time-reversal invariant, so the short answer is "yes".



      As a practical matter it is essentially impossible to set up the exact reversed situation, but we can set up good approximations in some cases (and in particular in electromagnetic bands not including visible light). Once the approximation is good enough it becomes useful.



      A "phased array" transmitter is exactly a mechanism for focusing electromagnetic waves by emitting them from many places with carefully arranged phase off-sets. They are difficult to build, tune, and operate effectively; but they are a thing.






      share|cite|improve this answer









      $endgroup$

















        2












        $begingroup$

        Optics is time-reversal invariant, so the short answer is "yes".



        As a practical matter it is essentially impossible to set up the exact reversed situation, but we can set up good approximations in some cases (and in particular in electromagnetic bands not including visible light). Once the approximation is good enough it becomes useful.



        A "phased array" transmitter is exactly a mechanism for focusing electromagnetic waves by emitting them from many places with carefully arranged phase off-sets. They are difficult to build, tune, and operate effectively; but they are a thing.






        share|cite|improve this answer









        $endgroup$















          2












          2








          2





          $begingroup$

          Optics is time-reversal invariant, so the short answer is "yes".



          As a practical matter it is essentially impossible to set up the exact reversed situation, but we can set up good approximations in some cases (and in particular in electromagnetic bands not including visible light). Once the approximation is good enough it becomes useful.



          A "phased array" transmitter is exactly a mechanism for focusing electromagnetic waves by emitting them from many places with carefully arranged phase off-sets. They are difficult to build, tune, and operate effectively; but they are a thing.






          share|cite|improve this answer









          $endgroup$



          Optics is time-reversal invariant, so the short answer is "yes".



          As a practical matter it is essentially impossible to set up the exact reversed situation, but we can set up good approximations in some cases (and in particular in electromagnetic bands not including visible light). Once the approximation is good enough it becomes useful.



          A "phased array" transmitter is exactly a mechanism for focusing electromagnetic waves by emitting them from many places with carefully arranged phase off-sets. They are difficult to build, tune, and operate effectively; but they are a thing.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered 8 hours ago









          dmckee♦dmckee

          76k6 gold badges139 silver badges277 bronze badges




          76k6 gold badges139 silver badges277 bronze badges























              2












              $begingroup$

              Reversing diffraction is precisely what is done in Fourier Optics!



              There, instead of placing a screen after the slit to see the diffraction pattern, a lens is put there instead. If you arrange the diffraction image to lie at the back focal plane of the lens, you will see the image of the slit itself at the front focal plane of the lens.



              This procedure of reversing diffraction relies on a fundamental Fourier transform property of a thin lens. The idea is that placing an object exactly one focal length $+f$ away from the lens will produce an image of the object one focal length $-f$ on the opposite side that is the Fourier transform of the object.



              This is shown in the image below



              cns-alumni.bu.edu






              share|cite|improve this answer









              $endgroup$

















                2












                $begingroup$

                Reversing diffraction is precisely what is done in Fourier Optics!



                There, instead of placing a screen after the slit to see the diffraction pattern, a lens is put there instead. If you arrange the diffraction image to lie at the back focal plane of the lens, you will see the image of the slit itself at the front focal plane of the lens.



                This procedure of reversing diffraction relies on a fundamental Fourier transform property of a thin lens. The idea is that placing an object exactly one focal length $+f$ away from the lens will produce an image of the object one focal length $-f$ on the opposite side that is the Fourier transform of the object.



                This is shown in the image below



                cns-alumni.bu.edu






                share|cite|improve this answer









                $endgroup$















                  2












                  2








                  2





                  $begingroup$

                  Reversing diffraction is precisely what is done in Fourier Optics!



                  There, instead of placing a screen after the slit to see the diffraction pattern, a lens is put there instead. If you arrange the diffraction image to lie at the back focal plane of the lens, you will see the image of the slit itself at the front focal plane of the lens.



                  This procedure of reversing diffraction relies on a fundamental Fourier transform property of a thin lens. The idea is that placing an object exactly one focal length $+f$ away from the lens will produce an image of the object one focal length $-f$ on the opposite side that is the Fourier transform of the object.



                  This is shown in the image below



                  cns-alumni.bu.edu






                  share|cite|improve this answer









                  $endgroup$



                  Reversing diffraction is precisely what is done in Fourier Optics!



                  There, instead of placing a screen after the slit to see the diffraction pattern, a lens is put there instead. If you arrange the diffraction image to lie at the back focal plane of the lens, you will see the image of the slit itself at the front focal plane of the lens.



                  This procedure of reversing diffraction relies on a fundamental Fourier transform property of a thin lens. The idea is that placing an object exactly one focal length $+f$ away from the lens will produce an image of the object one focal length $-f$ on the opposite side that is the Fourier transform of the object.



                  This is shown in the image below



                  cns-alumni.bu.edu







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered 4 hours ago









                  KF GaussKF Gauss

                  1,6181 gold badge10 silver badges26 bronze badges




                  1,6181 gold badge10 silver badges26 bronze badges





















                      1












                      $begingroup$

                      for light beams, you might also consider something called a corner reflector or retro-reflector. this is a glass prism cut in such a way that any beam of light entering it is reflected back at almost exactly the same angle that it made going into the prism. if you constructed a flat plate containing a large number of small corner reflectors and placed it at the location of the screen in the experiment you describe, then all the light striking the plate across its width would be reflected back to the slit.



                      I do not know how that collection of beams coming back into the slit would behave when they all meet!






                      share|cite|improve this answer









                      $endgroup$












                      • $begingroup$
                        Glass corner cubes aren't so simple. Rays do not counterpropagate on themselves. And each of the six possible paths of a ray through a corner cube affects the phase of the light differently. Metallic reflecting corner cubes help, but since metals are not perfect conductors, there is still a small phase/polarization effect, but there is energy lost.
                        $endgroup$
                        – garyp
                        4 hours ago
















                      1












                      $begingroup$

                      for light beams, you might also consider something called a corner reflector or retro-reflector. this is a glass prism cut in such a way that any beam of light entering it is reflected back at almost exactly the same angle that it made going into the prism. if you constructed a flat plate containing a large number of small corner reflectors and placed it at the location of the screen in the experiment you describe, then all the light striking the plate across its width would be reflected back to the slit.



                      I do not know how that collection of beams coming back into the slit would behave when they all meet!






                      share|cite|improve this answer









                      $endgroup$












                      • $begingroup$
                        Glass corner cubes aren't so simple. Rays do not counterpropagate on themselves. And each of the six possible paths of a ray through a corner cube affects the phase of the light differently. Metallic reflecting corner cubes help, but since metals are not perfect conductors, there is still a small phase/polarization effect, but there is energy lost.
                        $endgroup$
                        – garyp
                        4 hours ago














                      1












                      1








                      1





                      $begingroup$

                      for light beams, you might also consider something called a corner reflector or retro-reflector. this is a glass prism cut in such a way that any beam of light entering it is reflected back at almost exactly the same angle that it made going into the prism. if you constructed a flat plate containing a large number of small corner reflectors and placed it at the location of the screen in the experiment you describe, then all the light striking the plate across its width would be reflected back to the slit.



                      I do not know how that collection of beams coming back into the slit would behave when they all meet!






                      share|cite|improve this answer









                      $endgroup$



                      for light beams, you might also consider something called a corner reflector or retro-reflector. this is a glass prism cut in such a way that any beam of light entering it is reflected back at almost exactly the same angle that it made going into the prism. if you constructed a flat plate containing a large number of small corner reflectors and placed it at the location of the screen in the experiment you describe, then all the light striking the plate across its width would be reflected back to the slit.



                      I do not know how that collection of beams coming back into the slit would behave when they all meet!







                      share|cite|improve this answer












                      share|cite|improve this answer



                      share|cite|improve this answer










                      answered 5 hours ago









                      niels nielsenniels nielsen

                      23.3k5 gold badges32 silver badges66 bronze badges




                      23.3k5 gold badges32 silver badges66 bronze badges











                      • $begingroup$
                        Glass corner cubes aren't so simple. Rays do not counterpropagate on themselves. And each of the six possible paths of a ray through a corner cube affects the phase of the light differently. Metallic reflecting corner cubes help, but since metals are not perfect conductors, there is still a small phase/polarization effect, but there is energy lost.
                        $endgroup$
                        – garyp
                        4 hours ago

















                      • $begingroup$
                        Glass corner cubes aren't so simple. Rays do not counterpropagate on themselves. And each of the six possible paths of a ray through a corner cube affects the phase of the light differently. Metallic reflecting corner cubes help, but since metals are not perfect conductors, there is still a small phase/polarization effect, but there is energy lost.
                        $endgroup$
                        – garyp
                        4 hours ago
















                      $begingroup$
                      Glass corner cubes aren't so simple. Rays do not counterpropagate on themselves. And each of the six possible paths of a ray through a corner cube affects the phase of the light differently. Metallic reflecting corner cubes help, but since metals are not perfect conductors, there is still a small phase/polarization effect, but there is energy lost.
                      $endgroup$
                      – garyp
                      4 hours ago





                      $begingroup$
                      Glass corner cubes aren't so simple. Rays do not counterpropagate on themselves. And each of the six possible paths of a ray through a corner cube affects the phase of the light differently. Metallic reflecting corner cubes help, but since metals are not perfect conductors, there is still a small phase/polarization effect, but there is energy lost.
                      $endgroup$
                      – garyp
                      4 hours ago











                      Syed Hasnain Ahmed is a new contributor. Be nice, and check out our Code of Conduct.









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