Query nodes and attributes of parent waysOverpass API: Get coordinates of postal boundaryCorrect order of nodes in Overpass queryHow can I get a relation with multiple ways as members in addition to the members with Overpass QL?Is there a Service to get only nodes from OSM?Query for WAY that connects two INTERSECTIONSA way to find all footway and street interesections in openstreetmapOverpass / Overpy: Getting Way IDs from NodesOverpass API - Multiple ways for same roadFetching node(nd) reference data of way in Overpass query resultRetrieving OpenStreetMap data (ways and its child nodes) by coordinates using Overpass API?
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Query nodes and attributes of parent ways
Overpass API: Get coordinates of postal boundaryCorrect order of nodes in Overpass queryHow can I get a relation with multiple ways as members in addition to the members with Overpass QL?Is there a Service to get only nodes from OSM?Query for WAY that connects two INTERSECTIONSA way to find all footway and street interesections in openstreetmapOverpass / Overpy: Getting Way IDs from NodesOverpass API - Multiple ways for same roadFetching node(nd) reference data of way in Overpass query resultRetrieving OpenStreetMap data (ways and its child nodes) by coordinates using Overpass API?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
Does the Overpass API provide a way to query a list of nodes and some attributes of their parent ways, and return the data in CSV format?
For example, the following will give me all motorway junctions:
[out:csv(ref, name, ::lat, ::lon)];
// gather results
(
// query part for: “highway=milestone”
node["highway"="motorway_junction"](bbox);
);
// print results
out body;
>;
out skel qt;
Is there a way to query the ref=* tag of the roads of which the node is a member?
openstreetmap overpass-api
asked 8 hours ago
user149408user149408
18017
add a comment |
Does the Overpass API provide a way to query a list of nodes and some attributes of their parent ways, and return the data in CSV format?
For example, the following will give me all motorway junctions:
[out:csv(ref, name, ::lat, ::lon)];
// gather results
(
// query part for: “highway=milestone”
node["highway"="motorway_junction"](bbox);
);
// print results
out body;
>;
out skel qt;
Is there a way to query the ref=* tag of the roads of which the node is a member?
openstreetmap overpass-api
asked 8 hours ago
user149408user149408
18017
add a comment |
Does the Overpass API provide a way to query a list of nodes and some attributes of their parent ways, and return the data in CSV format?
For example, the following will give me all motorway junctions:
[out:csv(ref, name, ::lat, ::lon)];
// gather results
(
// query part for: “highway=milestone”
node["highway"="motorway_junction"](bbox);
);
// print results
out body;
>;
out skel qt;
Is there a way to query the ref=* tag of the roads of which the node is a member?
openstreetmap overpass-api
asked 8 hours ago
user149408user149408
18017
Does the Overpass API provide a way to query a list of nodes and some attributes of their parent ways, and return the data in CSV format?
For example, the following will give me all motorway junctions:
[out:csv(ref, name, ::lat, ::lon)];
// gather results
(
// query part for: “highway=milestone”
node["highway"="motorway_junction"](bbox);
);
// print results
out body;
>;
out skel qt;
Is there a way to query the ref=* tag of the roads of which the node is a member?
openstreetmap overpass-api
openstreetmap overpass-api
asked 8 hours ago
user149408user149408
18017
asked 8 hours ago
user149408user149408
18017
asked 8 hours ago
user149408user149408
18017
asked 8 hours ago
user149408user149408
18017
asked 8 hours ago
user149408user149408
18017
18017
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Yes, that's possible:
[out:csv(_ref, name, ::lat, ::lon)];
node["highway"="motorway_junction"](bbox);
foreach // iterate over nodes
way(bn)[highway~"^(motorway
edited 6 hours ago
user149408
18017
answered 8 hours ago
mmdmmd
2,3651616
Thanks! I’ve edited the answer to include also trunk roads. There are still issues to be solved where multiple ways with differentreftags are involved: either different spellings (A8vs.A 8), or the road name actually changes at the junction (A2becomingS8). The solution to that probably depends on the use case: I would want two rows, one for each road, so it’s probably better to search for the roads and iterate over its junctions.
– user149408
7 hours ago
1
To have one single entry for each of the ".ways", you'd need to add another foreach loop and iterate over those ways.
– mmd
6 hours ago
So I’ve replaced theifwith anotherforeach, and I get short of 200 results (which looks OK). Problem is, how can I refer to tags of the way from the innerforeach?
– user149408
6 hours ago
1
Try this one: overpass-turbo.eu/s/JY8
– mmd
6 hours ago
That did the trick. Thanks again!
– user149408
5 hours ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Yes, that's possible:
[out:csv(_ref, name, ::lat, ::lon)];
node["highway"="motorway_junction"](bbox);
foreach // iterate over nodes
way(bn)[highway~"^(motorway
edited 6 hours ago
user149408
18017
answered 8 hours ago
mmdmmd
2,3651616
Thanks! I’ve edited the answer to include also trunk roads. There are still issues to be solved where multiple ways with differentreftags are involved: either different spellings (A8vs.A 8), or the road name actually changes at the junction (A2becomingS8). The solution to that probably depends on the use case: I would want two rows, one for each road, so it’s probably better to search for the roads and iterate over its junctions.
– user149408
7 hours ago
1
To have one single entry for each of the ".ways", you'd need to add another foreach loop and iterate over those ways.
– mmd
6 hours ago
So I’ve replaced theifwith anotherforeach, and I get short of 200 results (which looks OK). Problem is, how can I refer to tags of the way from the innerforeach?
– user149408
6 hours ago
1
Try this one: overpass-turbo.eu/s/JY8
– mmd
6 hours ago
That did the trick. Thanks again!
– user149408
5 hours ago
add a comment |
Yes, that's possible:
[out:csv(_ref, name, ::lat, ::lon)];
node["highway"="motorway_junction"](bbox);
foreach // iterate over nodes
way(bn)[highway~"^(motorway
edited 6 hours ago
user149408
18017
answered 8 hours ago
mmdmmd
2,3651616
Thanks! I’ve edited the answer to include also trunk roads. There are still issues to be solved where multiple ways with differentreftags are involved: either different spellings (A8vs.A 8), or the road name actually changes at the junction (A2becomingS8). The solution to that probably depends on the use case: I would want two rows, one for each road, so it’s probably better to search for the roads and iterate over its junctions.
– user149408
7 hours ago
1
To have one single entry for each of the ".ways", you'd need to add another foreach loop and iterate over those ways.
– mmd
6 hours ago
So I’ve replaced theifwith anotherforeach, and I get short of 200 results (which looks OK). Problem is, how can I refer to tags of the way from the innerforeach?
– user149408
6 hours ago
1
Try this one: overpass-turbo.eu/s/JY8
– mmd
6 hours ago
That did the trick. Thanks again!
– user149408
5 hours ago
add a comment |
Yes, that's possible:
[out:csv(_ref, name, ::lat, ::lon)];
node["highway"="motorway_junction"](bbox);
foreach // iterate over nodes
way(bn)[highway~"^(motorway
edited 6 hours ago
user149408
18017
answered 8 hours ago
mmdmmd
2,3651616
Yes, that's possible:
[out:csv(_ref, name, ::lat, ::lon)];
node["highway"="motorway_junction"](bbox);
foreach // iterate over nodes
way(bn)[highway~"^(motorway
edited 6 hours ago
user149408
18017
answered 8 hours ago
mmdmmd
2,3651616
edited 6 hours ago
user149408
18017
edited 6 hours ago
user149408
18017
edited 6 hours ago
user149408
18017
18017
answered 8 hours ago
mmdmmd
2,3651616
answered 8 hours ago
mmdmmd
2,3651616
answered 8 hours ago
mmdmmd
2,3651616
2,3651616
Thanks! I’ve edited the answer to include also trunk roads. There are still issues to be solved where multiple ways with differentreftags are involved: either different spellings (A8vs.A 8), or the road name actually changes at the junction (A2becomingS8). The solution to that probably depends on the use case: I would want two rows, one for each road, so it’s probably better to search for the roads and iterate over its junctions.
– user149408
7 hours ago
1
To have one single entry for each of the ".ways", you'd need to add another foreach loop and iterate over those ways.
– mmd
6 hours ago
So I’ve replaced theifwith anotherforeach, and I get short of 200 results (which looks OK). Problem is, how can I refer to tags of the way from the innerforeach?
– user149408
6 hours ago
1
Try this one: overpass-turbo.eu/s/JY8
– mmd
6 hours ago
That did the trick. Thanks again!
– user149408
5 hours ago
add a comment |
Thanks! I’ve edited the answer to include also trunk roads. There are still issues to be solved where multiple ways with differentreftags are involved: either different spellings (A8vs.A 8), or the road name actually changes at the junction (A2becomingS8). The solution to that probably depends on the use case: I would want two rows, one for each road, so it’s probably better to search for the roads and iterate over its junctions.
– user149408
7 hours ago
1
To have one single entry for each of the ".ways", you'd need to add another foreach loop and iterate over those ways.
– mmd
6 hours ago
So I’ve replaced theifwith anotherforeach, and I get short of 200 results (which looks OK). Problem is, how can I refer to tags of the way from the innerforeach?
– user149408
6 hours ago
1
Try this one: overpass-turbo.eu/s/JY8
– mmd
6 hours ago
That did the trick. Thanks again!
– user149408
5 hours ago
Thanks! I’ve edited the answer to include also trunk roads. There are still issues to be solved where multiple ways with different
ref tags are involved: either different spellings (A8 vs. A 8), or the road name actually changes at the junction (A2 becoming S8). The solution to that probably depends on the use case: I would want two rows, one for each road, so it’s probably better to search for the roads and iterate over its junctions.– user149408
7 hours ago
Thanks! I’ve edited the answer to include also trunk roads. There are still issues to be solved where multiple ways with different
ref tags are involved: either different spellings (A8 vs. A 8), or the road name actually changes at the junction (A2 becoming S8). The solution to that probably depends on the use case: I would want two rows, one for each road, so it’s probably better to search for the roads and iterate over its junctions.– user149408
7 hours ago
1
1
To have one single entry for each of the ".ways", you'd need to add another foreach loop and iterate over those ways.
– mmd
6 hours ago
To have one single entry for each of the ".ways", you'd need to add another foreach loop and iterate over those ways.
– mmd
6 hours ago
So I’ve replaced the
if with another foreach, and I get short of 200 results (which looks OK). Problem is, how can I refer to tags of the way from the inner foreach?– user149408
6 hours ago
So I’ve replaced the
if with another foreach, and I get short of 200 results (which looks OK). Problem is, how can I refer to tags of the way from the inner foreach?– user149408
6 hours ago
1
1
Try this one: overpass-turbo.eu/s/JY8
– mmd
6 hours ago
Try this one: overpass-turbo.eu/s/JY8
– mmd
6 hours ago
That did the trick. Thanks again!
– user149408
5 hours ago
That did the trick. Thanks again!
– user149408
5 hours ago
add a comment |
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