How to avoid voltage drop when using full bridge rectifier as reverse polarity protectionStoring the charge from a MOSFET Bridge RectifierReverse polarity protection using MOSFET - what is the voltage drop after it?How can I prevent reverse voltage in my stop/tail light design?Minimal reverse voltage protectionFull wave bridge rectifierWhat circuit will allow reverse polarity and continue to work?Reverse Polarity & Load Dump Protection (TVS)Diode Array for Full-Wave Rectifier for PoEWhat could have caused bridge rectifiers to fail?Circuit protection component arrangementTrying to come up with a overvoltage overcurrent reverse polarity protection circuit, is option 3 done right?
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How to avoid voltage drop when using full bridge rectifier as reverse polarity protection
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How to avoid voltage drop when using full bridge rectifier as reverse polarity protection
Storing the charge from a MOSFET Bridge RectifierReverse polarity protection using MOSFET - what is the voltage drop after it?How can I prevent reverse voltage in my stop/tail light design?Minimal reverse voltage protectionFull wave bridge rectifierWhat circuit will allow reverse polarity and continue to work?Reverse Polarity & Load Dump Protection (TVS)Diode Array for Full-Wave Rectifier for PoEWhat could have caused bridge rectifiers to fail?Circuit protection component arrangementTrying to come up with a overvoltage overcurrent reverse polarity protection circuit, is option 3 done right?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
I found a couple of old bridge rectifiers. After reading some docs and tutorials about reverse polarity protection decided to give them a try. The problem is nobody offered a solution against the voltage drop (and the power loss) after the rectifier, which is usually mounted at the load side not at the supply side.
What is the way to avoid this drop - using higher voltage as input or additional circuit to overcome this at the load side?
bridge-rectifier reverse-polarity voltage-drop
edited 6 hours ago
laptop2d
32.8k123999
asked 8 hours ago
1000Gbps1000Gbps
1105
$endgroup$
add a comment |
$begingroup$
I found a couple of old bridge rectifiers. After reading some docs and tutorials about reverse polarity protection decided to give them a try. The problem is nobody offered a solution against the voltage drop (and the power loss) after the rectifier, which is usually mounted at the load side not at the supply side.
What is the way to avoid this drop - using higher voltage as input or additional circuit to overcome this at the load side?
bridge-rectifier reverse-polarity voltage-drop
edited 6 hours ago
laptop2d
32.8k123999
asked 8 hours ago
1000Gbps1000Gbps
1105
$endgroup$
add a comment |
$begingroup$
I found a couple of old bridge rectifiers. After reading some docs and tutorials about reverse polarity protection decided to give them a try. The problem is nobody offered a solution against the voltage drop (and the power loss) after the rectifier, which is usually mounted at the load side not at the supply side.
What is the way to avoid this drop - using higher voltage as input or additional circuit to overcome this at the load side?
bridge-rectifier reverse-polarity voltage-drop
edited 6 hours ago
laptop2d
32.8k123999
asked 8 hours ago
1000Gbps1000Gbps
1105
$endgroup$
I found a couple of old bridge rectifiers. After reading some docs and tutorials about reverse polarity protection decided to give them a try. The problem is nobody offered a solution against the voltage drop (and the power loss) after the rectifier, which is usually mounted at the load side not at the supply side.
What is the way to avoid this drop - using higher voltage as input or additional circuit to overcome this at the load side?
bridge-rectifier reverse-polarity voltage-drop
bridge-rectifier reverse-polarity voltage-drop
edited 6 hours ago
laptop2d
32.8k123999
asked 8 hours ago
1000Gbps1000Gbps
1105
edited 6 hours ago
laptop2d
32.8k123999
asked 8 hours ago
1000Gbps1000Gbps
1105
edited 6 hours ago
laptop2d
32.8k123999
edited 6 hours ago
laptop2d
32.8k123999
edited 6 hours ago
laptop2d
32.8k123999
32.8k123999
asked 8 hours ago
1000Gbps1000Gbps
1105
asked 8 hours ago
1000Gbps1000Gbps
1105
asked 8 hours ago
1000Gbps1000Gbps
1105
1105
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
If you want to avoid the drop, you need a different device that doesn't use as diodes for current control. Diodes have a drop, the best you can do is switch to a diode that has a lower voltage drop, usually 0.2 is as good as it gets.
Mosfets have low resistances, you can either deisgn your own active rectifier by matching mosfets, or buy an active rectifier IC.
Source: Storing the charge from a MOSFET Bridge Rectifier
answered 8 hours ago
laptop2dlaptop2d
32.8k123999
$endgroup$
1
$begingroup$
Should we mention what happens if you place a capacitor between +OUT and -OUT to OP? But then again, it appears OP isn't using it as a full bridge rectifier. Just as a "make it work regardless of how I connect my DC power supply"
$endgroup$
– Harry Svensson
7 hours ago
$begingroup$
Can you explain what will happen?
$endgroup$
– 1000Gbps
7 hours ago
$begingroup$
Reverse polarity in most cases wouldn't need a filter cap.
$endgroup$
– laptop2d
6 hours ago
$begingroup$
@1000Gbps It's only a problem if your voltage source contains AC. See here if it's still not obvious. laptop2d's design will only work if your source is like a battery or some other fairly steady output, like a buck converter. If you use his design where the source is a transformer then you can watch as the mosfets burn up, assuming you have a capacitor between +OUT and -OUT.
$endgroup$
– Harry Svensson
6 hours ago
add a comment |
$begingroup$
What about this simple solution from www.ti.com/lit/an/slva139/slva139.pdf
You should put a zener and a large resistor to protect your MOSFET if the load voltage is larger than Vgs max:
answered 7 hours ago
vangelovangelo
4008
$endgroup$
$begingroup$
The idea is to always power-on the device even with reversed polarity
$endgroup$
– 1000Gbps
7 hours ago
add a comment |
$begingroup$
If all you want to do is avoid damage you can use a single Schottkey diode in the power lead (as opposed to ground) and end up with less drop. The board won't work if power is applied in reverse, but it won't go up in smoke.
One place I worked used a fuse, and a diode on the other side of it that would crowbar the supply to one diode drop in reverse. If the board was connected backward the fuse would blow -- so technically it would be "broken", but it would be an easy fix. You need to take care if you do this -- you need to size the diode so that it doesn't get damaged before the fuse blows, and you need to make sure the system isn't going to be damaged by the brief short across the power leads.
answered 8 hours ago
TimWescottTimWescott
9,8271821
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
If you want to avoid the drop, you need a different device that doesn't use as diodes for current control. Diodes have a drop, the best you can do is switch to a diode that has a lower voltage drop, usually 0.2 is as good as it gets.
Mosfets have low resistances, you can either deisgn your own active rectifier by matching mosfets, or buy an active rectifier IC.
Source: Storing the charge from a MOSFET Bridge Rectifier
answered 8 hours ago
laptop2dlaptop2d
32.8k123999
$endgroup$
1
$begingroup$
Should we mention what happens if you place a capacitor between +OUT and -OUT to OP? But then again, it appears OP isn't using it as a full bridge rectifier. Just as a "make it work regardless of how I connect my DC power supply"
$endgroup$
– Harry Svensson
7 hours ago
$begingroup$
Can you explain what will happen?
$endgroup$
– 1000Gbps
7 hours ago
$begingroup$
Reverse polarity in most cases wouldn't need a filter cap.
$endgroup$
– laptop2d
6 hours ago
$begingroup$
@1000Gbps It's only a problem if your voltage source contains AC. See here if it's still not obvious. laptop2d's design will only work if your source is like a battery or some other fairly steady output, like a buck converter. If you use his design where the source is a transformer then you can watch as the mosfets burn up, assuming you have a capacitor between +OUT and -OUT.
$endgroup$
– Harry Svensson
6 hours ago
add a comment |
$begingroup$
If you want to avoid the drop, you need a different device that doesn't use as diodes for current control. Diodes have a drop, the best you can do is switch to a diode that has a lower voltage drop, usually 0.2 is as good as it gets.
Mosfets have low resistances, you can either deisgn your own active rectifier by matching mosfets, or buy an active rectifier IC.
Source: Storing the charge from a MOSFET Bridge Rectifier
answered 8 hours ago
laptop2dlaptop2d
32.8k123999
$endgroup$
1
$begingroup$
Should we mention what happens if you place a capacitor between +OUT and -OUT to OP? But then again, it appears OP isn't using it as a full bridge rectifier. Just as a "make it work regardless of how I connect my DC power supply"
$endgroup$
– Harry Svensson
7 hours ago
$begingroup$
Can you explain what will happen?
$endgroup$
– 1000Gbps
7 hours ago
$begingroup$
Reverse polarity in most cases wouldn't need a filter cap.
$endgroup$
– laptop2d
6 hours ago
$begingroup$
@1000Gbps It's only a problem if your voltage source contains AC. See here if it's still not obvious. laptop2d's design will only work if your source is like a battery or some other fairly steady output, like a buck converter. If you use his design where the source is a transformer then you can watch as the mosfets burn up, assuming you have a capacitor between +OUT and -OUT.
$endgroup$
– Harry Svensson
6 hours ago
add a comment |
$begingroup$
If you want to avoid the drop, you need a different device that doesn't use as diodes for current control. Diodes have a drop, the best you can do is switch to a diode that has a lower voltage drop, usually 0.2 is as good as it gets.
Mosfets have low resistances, you can either deisgn your own active rectifier by matching mosfets, or buy an active rectifier IC.
Source: Storing the charge from a MOSFET Bridge Rectifier
answered 8 hours ago
laptop2dlaptop2d
32.8k123999
$endgroup$
If you want to avoid the drop, you need a different device that doesn't use as diodes for current control. Diodes have a drop, the best you can do is switch to a diode that has a lower voltage drop, usually 0.2 is as good as it gets.
Mosfets have low resistances, you can either deisgn your own active rectifier by matching mosfets, or buy an active rectifier IC.
Source: Storing the charge from a MOSFET Bridge Rectifier
answered 8 hours ago
laptop2dlaptop2d
32.8k123999
answered 8 hours ago
laptop2dlaptop2d
32.8k123999
answered 8 hours ago
laptop2dlaptop2d
32.8k123999
answered 8 hours ago
laptop2dlaptop2d
32.8k123999
32.8k123999
1
$begingroup$
Should we mention what happens if you place a capacitor between +OUT and -OUT to OP? But then again, it appears OP isn't using it as a full bridge rectifier. Just as a "make it work regardless of how I connect my DC power supply"
$endgroup$
– Harry Svensson
7 hours ago
$begingroup$
Can you explain what will happen?
$endgroup$
– 1000Gbps
7 hours ago
$begingroup$
Reverse polarity in most cases wouldn't need a filter cap.
$endgroup$
– laptop2d
6 hours ago
$begingroup$
@1000Gbps It's only a problem if your voltage source contains AC. See here if it's still not obvious. laptop2d's design will only work if your source is like a battery or some other fairly steady output, like a buck converter. If you use his design where the source is a transformer then you can watch as the mosfets burn up, assuming you have a capacitor between +OUT and -OUT.
$endgroup$
– Harry Svensson
6 hours ago
add a comment |
1
$begingroup$
Should we mention what happens if you place a capacitor between +OUT and -OUT to OP? But then again, it appears OP isn't using it as a full bridge rectifier. Just as a "make it work regardless of how I connect my DC power supply"
$endgroup$
– Harry Svensson
7 hours ago
$begingroup$
Can you explain what will happen?
$endgroup$
– 1000Gbps
7 hours ago
$begingroup$
Reverse polarity in most cases wouldn't need a filter cap.
$endgroup$
– laptop2d
6 hours ago
$begingroup$
@1000Gbps It's only a problem if your voltage source contains AC. See here if it's still not obvious. laptop2d's design will only work if your source is like a battery or some other fairly steady output, like a buck converter. If you use his design where the source is a transformer then you can watch as the mosfets burn up, assuming you have a capacitor between +OUT and -OUT.
$endgroup$
– Harry Svensson
6 hours ago
1
1
$begingroup$
Should we mention what happens if you place a capacitor between +OUT and -OUT to OP? But then again, it appears OP isn't using it as a full bridge rectifier. Just as a "make it work regardless of how I connect my DC power supply"
$endgroup$
– Harry Svensson
7 hours ago
$begingroup$
Should we mention what happens if you place a capacitor between +OUT and -OUT to OP? But then again, it appears OP isn't using it as a full bridge rectifier. Just as a "make it work regardless of how I connect my DC power supply"
$endgroup$
– Harry Svensson
7 hours ago
$begingroup$
Can you explain what will happen?
$endgroup$
– 1000Gbps
7 hours ago
$begingroup$
Can you explain what will happen?
$endgroup$
– 1000Gbps
7 hours ago
$begingroup$
Reverse polarity in most cases wouldn't need a filter cap.
$endgroup$
– laptop2d
6 hours ago
$begingroup$
Reverse polarity in most cases wouldn't need a filter cap.
$endgroup$
– laptop2d
6 hours ago
$begingroup$
@1000Gbps It's only a problem if your voltage source contains AC. See here if it's still not obvious. laptop2d's design will only work if your source is like a battery or some other fairly steady output, like a buck converter. If you use his design where the source is a transformer then you can watch as the mosfets burn up, assuming you have a capacitor between +OUT and -OUT.
$endgroup$
– Harry Svensson
6 hours ago
$begingroup$
@1000Gbps It's only a problem if your voltage source contains AC. See here if it's still not obvious. laptop2d's design will only work if your source is like a battery or some other fairly steady output, like a buck converter. If you use his design where the source is a transformer then you can watch as the mosfets burn up, assuming you have a capacitor between +OUT and -OUT.
$endgroup$
– Harry Svensson
6 hours ago
add a comment |
$begingroup$
What about this simple solution from www.ti.com/lit/an/slva139/slva139.pdf
You should put a zener and a large resistor to protect your MOSFET if the load voltage is larger than Vgs max:
answered 7 hours ago
vangelovangelo
4008
$endgroup$
$begingroup$
The idea is to always power-on the device even with reversed polarity
$endgroup$
– 1000Gbps
7 hours ago
add a comment |
$begingroup$
What about this simple solution from www.ti.com/lit/an/slva139/slva139.pdf
You should put a zener and a large resistor to protect your MOSFET if the load voltage is larger than Vgs max:
answered 7 hours ago
vangelovangelo
4008
$endgroup$
$begingroup$
The idea is to always power-on the device even with reversed polarity
$endgroup$
– 1000Gbps
7 hours ago
add a comment |
$begingroup$
What about this simple solution from www.ti.com/lit/an/slva139/slva139.pdf
You should put a zener and a large resistor to protect your MOSFET if the load voltage is larger than Vgs max:
answered 7 hours ago
vangelovangelo
4008
$endgroup$
What about this simple solution from www.ti.com/lit/an/slva139/slva139.pdf
You should put a zener and a large resistor to protect your MOSFET if the load voltage is larger than Vgs max:
answered 7 hours ago
vangelovangelo
4008
edited 7 hours ago
answered 7 hours ago
vangelovangelo
4008
answered 7 hours ago
vangelovangelo
4008
answered 7 hours ago
vangelovangelo
4008
4008
$begingroup$
The idea is to always power-on the device even with reversed polarity
$endgroup$
– 1000Gbps
7 hours ago
add a comment |
$begingroup$
The idea is to always power-on the device even with reversed polarity
$endgroup$
– 1000Gbps
7 hours ago
$begingroup$
The idea is to always power-on the device even with reversed polarity
$endgroup$
– 1000Gbps
7 hours ago
$begingroup$
The idea is to always power-on the device even with reversed polarity
$endgroup$
– 1000Gbps
7 hours ago
add a comment |
$begingroup$
If all you want to do is avoid damage you can use a single Schottkey diode in the power lead (as opposed to ground) and end up with less drop. The board won't work if power is applied in reverse, but it won't go up in smoke.
One place I worked used a fuse, and a diode on the other side of it that would crowbar the supply to one diode drop in reverse. If the board was connected backward the fuse would blow -- so technically it would be "broken", but it would be an easy fix. You need to take care if you do this -- you need to size the diode so that it doesn't get damaged before the fuse blows, and you need to make sure the system isn't going to be damaged by the brief short across the power leads.
answered 8 hours ago
TimWescottTimWescott
9,8271821
$endgroup$
add a comment |
$begingroup$
If all you want to do is avoid damage you can use a single Schottkey diode in the power lead (as opposed to ground) and end up with less drop. The board won't work if power is applied in reverse, but it won't go up in smoke.
One place I worked used a fuse, and a diode on the other side of it that would crowbar the supply to one diode drop in reverse. If the board was connected backward the fuse would blow -- so technically it would be "broken", but it would be an easy fix. You need to take care if you do this -- you need to size the diode so that it doesn't get damaged before the fuse blows, and you need to make sure the system isn't going to be damaged by the brief short across the power leads.
answered 8 hours ago
TimWescottTimWescott
9,8271821
$endgroup$
add a comment |
$begingroup$
If all you want to do is avoid damage you can use a single Schottkey diode in the power lead (as opposed to ground) and end up with less drop. The board won't work if power is applied in reverse, but it won't go up in smoke.
One place I worked used a fuse, and a diode on the other side of it that would crowbar the supply to one diode drop in reverse. If the board was connected backward the fuse would blow -- so technically it would be "broken", but it would be an easy fix. You need to take care if you do this -- you need to size the diode so that it doesn't get damaged before the fuse blows, and you need to make sure the system isn't going to be damaged by the brief short across the power leads.
answered 8 hours ago
TimWescottTimWescott
9,8271821
$endgroup$
If all you want to do is avoid damage you can use a single Schottkey diode in the power lead (as opposed to ground) and end up with less drop. The board won't work if power is applied in reverse, but it won't go up in smoke.
One place I worked used a fuse, and a diode on the other side of it that would crowbar the supply to one diode drop in reverse. If the board was connected backward the fuse would blow -- so technically it would be "broken", but it would be an easy fix. You need to take care if you do this -- you need to size the diode so that it doesn't get damaged before the fuse blows, and you need to make sure the system isn't going to be damaged by the brief short across the power leads.
answered 8 hours ago
TimWescottTimWescott
9,8271821
answered 8 hours ago
TimWescottTimWescott
9,8271821
answered 8 hours ago
TimWescottTimWescott
9,8271821
answered 8 hours ago
TimWescottTimWescott
9,8271821
9,8271821
add a comment |
add a comment |
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