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Convert a string containing integers to list of integers


Convert a string of binary characters to the ASCII equivalentsConvert Chevrons to SolidusesRemove all occurrences of the first letter of a string from the entire stringConvert to and from the backwards-factorial number baseConvert string to numberRank a list of integersConvert CMYK values to RGBMost common elements of a list in PythonMake a list continuous!The max() is not enough






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3












$begingroup$


What is the shortest way to convert a string containing integers separated by spaces to a list of integers?



  • input : "-3 1 5 8 10"

  • output : [-3, 1, 5, 8, 10]

I regularly face this situation and I wanted to know if there is a better way than (24 bytes):



list(map(int,s.split()))









share|improve this question









New contributor



Nelson G. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$







  • 3




    $begingroup$
    Assuming you don't want to make this an challenge open to any language, and are instead looking for some python golfing advice I would add the "tips" tag to this, and I could also recommend the Code Golf Chatroom, The Nineteenth Byte for quick questions like this.
    $endgroup$
    – Giuseppe
    8 hours ago







  • 4




    $begingroup$
    Why the downvotes? This is a legit tips question
    $endgroup$
    – Rod
    7 hours ago






  • 1




    $begingroup$
    I have added tips to the tags to help clarify this.
    $endgroup$
    – Giuseppe
    7 hours ago

















3












$begingroup$


What is the shortest way to convert a string containing integers separated by spaces to a list of integers?



  • input : "-3 1 5 8 10"

  • output : [-3, 1, 5, 8, 10]

I regularly face this situation and I wanted to know if there is a better way than (24 bytes):



list(map(int,s.split()))









share|improve this question









New contributor



Nelson G. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$







  • 3




    $begingroup$
    Assuming you don't want to make this an challenge open to any language, and are instead looking for some python golfing advice I would add the "tips" tag to this, and I could also recommend the Code Golf Chatroom, The Nineteenth Byte for quick questions like this.
    $endgroup$
    – Giuseppe
    8 hours ago







  • 4




    $begingroup$
    Why the downvotes? This is a legit tips question
    $endgroup$
    – Rod
    7 hours ago






  • 1




    $begingroup$
    I have added tips to the tags to help clarify this.
    $endgroup$
    – Giuseppe
    7 hours ago













3












3








3





$begingroup$


What is the shortest way to convert a string containing integers separated by spaces to a list of integers?



  • input : "-3 1 5 8 10"

  • output : [-3, 1, 5, 8, 10]

I regularly face this situation and I wanted to know if there is a better way than (24 bytes):



list(map(int,s.split()))









share|improve this question









New contributor



Nelson G. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




What is the shortest way to convert a string containing integers separated by spaces to a list of integers?



  • input : "-3 1 5 8 10"

  • output : [-3, 1, 5, 8, 10]

I regularly face this situation and I wanted to know if there is a better way than (24 bytes):



list(map(int,s.split()))






code-golf tips python






share|improve this question









New contributor



Nelson G. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question









New contributor



Nelson G. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question








edited 7 hours ago









Giuseppe

18.7k31461




18.7k31461






New contributor



Nelson G. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked 8 hours ago









Nelson G.Nelson G.

1726




1726




New contributor



Nelson G. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Nelson G. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









  • 3




    $begingroup$
    Assuming you don't want to make this an challenge open to any language, and are instead looking for some python golfing advice I would add the "tips" tag to this, and I could also recommend the Code Golf Chatroom, The Nineteenth Byte for quick questions like this.
    $endgroup$
    – Giuseppe
    8 hours ago







  • 4




    $begingroup$
    Why the downvotes? This is a legit tips question
    $endgroup$
    – Rod
    7 hours ago






  • 1




    $begingroup$
    I have added tips to the tags to help clarify this.
    $endgroup$
    – Giuseppe
    7 hours ago












  • 3




    $begingroup$
    Assuming you don't want to make this an challenge open to any language, and are instead looking for some python golfing advice I would add the "tips" tag to this, and I could also recommend the Code Golf Chatroom, The Nineteenth Byte for quick questions like this.
    $endgroup$
    – Giuseppe
    8 hours ago







  • 4




    $begingroup$
    Why the downvotes? This is a legit tips question
    $endgroup$
    – Rod
    7 hours ago






  • 1




    $begingroup$
    I have added tips to the tags to help clarify this.
    $endgroup$
    – Giuseppe
    7 hours ago







3




3




$begingroup$
Assuming you don't want to make this an challenge open to any language, and are instead looking for some python golfing advice I would add the "tips" tag to this, and I could also recommend the Code Golf Chatroom, The Nineteenth Byte for quick questions like this.
$endgroup$
– Giuseppe
8 hours ago





$begingroup$
Assuming you don't want to make this an challenge open to any language, and are instead looking for some python golfing advice I would add the "tips" tag to this, and I could also recommend the Code Golf Chatroom, The Nineteenth Byte for quick questions like this.
$endgroup$
– Giuseppe
8 hours ago





4




4




$begingroup$
Why the downvotes? This is a legit tips question
$endgroup$
– Rod
7 hours ago




$begingroup$
Why the downvotes? This is a legit tips question
$endgroup$
– Rod
7 hours ago




1




1




$begingroup$
I have added tips to the tags to help clarify this.
$endgroup$
– Giuseppe
7 hours ago




$begingroup$
I have added tips to the tags to help clarify this.
$endgroup$
– Giuseppe
7 hours ago










1 Answer
1






active

oldest

votes


















6












$begingroup$

Using map is way shorter than any of the ways I mentioned. You should do that.



Instead of calling list(...), you should use [*...] (21 bytes):



[*map(int,s.split())]


Or even better, if you switch to python 2, map will always return a list. (18 bytes):



map(int,s.split())


Try it online!



Original Post:




The straightforward way is going to be 26 bytes





[int(n)for n in s.split()]


Try it online!



However, if a tuple is acceptable instead of a list, we could use a trick to shave one byte off leaving us with 25 bytes





eval(",".join(s.split()))


Try it online!



This can be shortened even more with the replace function (24):





eval(s.replace(' ',','))


Try it online!



and even more with iterable unpacking (22):





eval(s.replace(*" ,"))


Try it online!



If you truly need a list, you can wrap it in [*...]. This is still shorter than the straightforward way by 1 byte:



[*eval(s.replace(*" ,"))]





share|improve this answer











$endgroup$















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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    6












    $begingroup$

    Using map is way shorter than any of the ways I mentioned. You should do that.



    Instead of calling list(...), you should use [*...] (21 bytes):



    [*map(int,s.split())]


    Or even better, if you switch to python 2, map will always return a list. (18 bytes):



    map(int,s.split())


    Try it online!



    Original Post:




    The straightforward way is going to be 26 bytes





    [int(n)for n in s.split()]


    Try it online!



    However, if a tuple is acceptable instead of a list, we could use a trick to shave one byte off leaving us with 25 bytes





    eval(",".join(s.split()))


    Try it online!



    This can be shortened even more with the replace function (24):





    eval(s.replace(' ',','))


    Try it online!



    and even more with iterable unpacking (22):





    eval(s.replace(*" ,"))


    Try it online!



    If you truly need a list, you can wrap it in [*...]. This is still shorter than the straightforward way by 1 byte:



    [*eval(s.replace(*" ,"))]





    share|improve this answer











    $endgroup$

















      6












      $begingroup$

      Using map is way shorter than any of the ways I mentioned. You should do that.



      Instead of calling list(...), you should use [*...] (21 bytes):



      [*map(int,s.split())]


      Or even better, if you switch to python 2, map will always return a list. (18 bytes):



      map(int,s.split())


      Try it online!



      Original Post:




      The straightforward way is going to be 26 bytes





      [int(n)for n in s.split()]


      Try it online!



      However, if a tuple is acceptable instead of a list, we could use a trick to shave one byte off leaving us with 25 bytes





      eval(",".join(s.split()))


      Try it online!



      This can be shortened even more with the replace function (24):





      eval(s.replace(' ',','))


      Try it online!



      and even more with iterable unpacking (22):





      eval(s.replace(*" ,"))


      Try it online!



      If you truly need a list, you can wrap it in [*...]. This is still shorter than the straightforward way by 1 byte:



      [*eval(s.replace(*" ,"))]





      share|improve this answer











      $endgroup$















        6












        6








        6





        $begingroup$

        Using map is way shorter than any of the ways I mentioned. You should do that.



        Instead of calling list(...), you should use [*...] (21 bytes):



        [*map(int,s.split())]


        Or even better, if you switch to python 2, map will always return a list. (18 bytes):



        map(int,s.split())


        Try it online!



        Original Post:




        The straightforward way is going to be 26 bytes





        [int(n)for n in s.split()]


        Try it online!



        However, if a tuple is acceptable instead of a list, we could use a trick to shave one byte off leaving us with 25 bytes





        eval(",".join(s.split()))


        Try it online!



        This can be shortened even more with the replace function (24):





        eval(s.replace(' ',','))


        Try it online!



        and even more with iterable unpacking (22):





        eval(s.replace(*" ,"))


        Try it online!



        If you truly need a list, you can wrap it in [*...]. This is still shorter than the straightforward way by 1 byte:



        [*eval(s.replace(*" ,"))]





        share|improve this answer











        $endgroup$



        Using map is way shorter than any of the ways I mentioned. You should do that.



        Instead of calling list(...), you should use [*...] (21 bytes):



        [*map(int,s.split())]


        Or even better, if you switch to python 2, map will always return a list. (18 bytes):



        map(int,s.split())


        Try it online!



        Original Post:




        The straightforward way is going to be 26 bytes





        [int(n)for n in s.split()]


        Try it online!



        However, if a tuple is acceptable instead of a list, we could use a trick to shave one byte off leaving us with 25 bytes





        eval(",".join(s.split()))


        Try it online!



        This can be shortened even more with the replace function (24):





        eval(s.replace(' ',','))


        Try it online!



        and even more with iterable unpacking (22):





        eval(s.replace(*" ,"))


        Try it online!



        If you truly need a list, you can wrap it in [*...]. This is still shorter than the straightforward way by 1 byte:



        [*eval(s.replace(*" ,"))]






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 8 hours ago

























        answered 8 hours ago









        DJMcMayhemDJMcMayhem

        41.1k12152319




        41.1k12152319




















            Nelson G. is a new contributor. Be nice, and check out our Code of Conduct.









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            Nelson G. is a new contributor. Be nice, and check out our Code of Conduct.












            Nelson G. is a new contributor. Be nice, and check out our Code of Conduct.











            Nelson G. is a new contributor. Be nice, and check out our Code of Conduct.














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