How dangerous are set-size assumptions?Contemporary Philosophy of MathematicsDefining the standard model of PA so that a space alien could understandWhat “forces” us to accept large cardinal axioms?Does the consistency strength hierarchy coincide with the “arithmetic consequence” hierarchy at ZF + Reinhardt?On statements provably independent of ZF + V=LInconsistency and workaday independence.Consistency and inaccessible cardinalsAxiom to exclude nonstandard natural numbersWhen does $ZFC vdash ' ZFC vdash varphi '$ imply $ZFC vdash varphi$?Where is the end of universe?Does the consistency strength hierarchy coincide with the “arithmetic consequence” hierarchy at ZF + Reinhardt?Why are model theorists free to use GCH and other semi-axioms?Is ZFC+(negation of a large cardinal axiom) arithmetically sound?Taking a proper class as a model for Set Theory

How dangerous are set-size assumptions?


Contemporary Philosophy of MathematicsDefining the standard model of PA so that a space alien could understandWhat “forces” us to accept large cardinal axioms?Does the consistency strength hierarchy coincide with the “arithmetic consequence” hierarchy at ZF + Reinhardt?On statements provably independent of ZF + V=LInconsistency and workaday independence.Consistency and inaccessible cardinalsAxiom to exclude nonstandard natural numbersWhen does $ZFC vdash ' ZFC vdash varphi '$ imply $ZFC vdash varphi$?Where is the end of universe?Does the consistency strength hierarchy coincide with the “arithmetic consequence” hierarchy at ZF + Reinhardt?Why are model theorists free to use GCH and other semi-axioms?Is ZFC+(negation of a large cardinal axiom) arithmetically sound?Taking a proper class as a model for Set Theory













8












$begingroup$


Many students' first introduction to the difference between classes and sets is in category theory, where we learn that some categories (such as the category of all sets) are class-sized but not set-sized. After working with such structures, we discover that it is still worthwhile to sometimes treat them as if they were set-sized. But we can't always do so, without running into contradictions. A natural solution to this problem is the "Axiom of Grothendieck Universes". We then work not with the category of all sets, but the category of sets inside some given universe. This type of framework has been used by many notable mathematicians and seems very ubiquitous. For instance, it was an assumption in my universal algebra textbook. I would venture to say that most modern set theorists look at such an axiom as a very tame assumption.



My first question concerns the possible dangers of such an assumption, which are not often raised when first learning about this axiom. One obvious danger is that this axiom might lead to an inconsistency. In other words, ZFC might be consistent but ZFC+Universes might be inconsistent. I don't personally subscribe to this belief, but it is certainly a possibility (without further, even stronger, assumptions).



What really concerns me is the possibility of another danger: Could such a system proves false things about the natural numbers? In other words, even if we assume that ZFC+Universes is consistent, could it be the case that it proves false arithmetic statements?



The motivation for this question came from reading some of the work of Nik Weaver at this link, which argues for a conceptualist stance on mathematics. In particular, if we reject the axiom of power set, we are led to situations where all power sets of infinite sets are class-sized. Nik puts forth the idea that ZFC might prove false things about the natural numbers. Is this a real possibility? I suppose so, since it is possible that ZFC is inconsistent but the natural numbers aren't. But is it still possible even if ZFC is consistent? More generally:




Could treating the power set of the natural numbers as a set-sized object, rather than a class, force us to conclude false arithmetic statements (even if such a system is consistent)?




Even if the answer to this question is yes, I'm having a hard time seeing how we could recognize this fact, since according to the answers to this linked question it is difficult to state precisely what we mean by the natural numbers.



A second motivation for this question comes from what I've read about the multiverse view of set-theory. When creating a (transitive) model $M$ of ZFC, the set $P(mathbbN)$ can often be thought of as some "bigger" power set of the natural numbers intersected with the model. Moreover, via forcing, it seems that one can (always?) enlarge the power set of $mathbbN$. This does seem to suggest that $P(mathbbN)$ is not completely captured in any model. Thus, in its entirety, perhaps $P(mathbbN)$ should be treated as a class-sized object.




Added: I believe that the current proof we have of Fermat's Last Theorem uses the existence of a(t least one) Grothendieck universe. However, my understanding is that this dependence can be completely removed due to the fact that Fermat's Last Theorem has small quantifier complexity. I imagine that proofs of statements with higher quantifier complexity that use Grothendieck universes, do not necessarily have a way of removing their dependence on said universes. How would we tell if such arithmetic statements are true of the natural numbers?




2nd addition: There are some theories that we believe prove false arithmetic statements. Assuming the natural numbers can consistently exist (which we do!), then both PA+Con(PA) and PA+$neg$Con(PA) are consistent, but the second theory proves the false arithmetic sentence $neg$Con(PA).



My question then might be rephrased as:




What principles lead us to believe that "Universes" is a safe assumption, whereas "$neg$Con(PA)" is not safe, regarding what we believe is "true" arithmetic? (Next, repeat this question regarding the axiom of power set.) Is any theory that interprets PA "safe", as long as it is consistent with PA, and PA+Con(PA), and any such natural extension of these ideas?




Another way of putting this might be as follows:




Is the assumption Con(PA) a philosophical one, and not a mathematical one?




This ties into my previous question that I linked to, about describing the "real" natural numbers.










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    @jon The "category of all categories" runs into similar paradoxes as the "set of all sets", whereas the "category of all $U$-small categories" doesn't. We'd like to freely work with the standard categories (of groups, sets, monoids, etc...) as if they (together) can form a new collection which forms the object set of a category, and morphisms between them are functors. The standard way this is done is by working with the $U$-small categories instead. For this and other examples, look where textbooks make use of the axiom of universes.
    $endgroup$
    – Pace Nielsen
    10 hours ago






  • 1




    $begingroup$
    I don't understand the question in the box -- in most of mathematics, $P(mathbb N)$ is treated as a set and not a class. So it sounds like you're simply asking whether ordinary mathematics can prove false arithmetic statements. But I get the impression from the surrounding discussion that you're trying to ask something specific about Grothendieck universes... I don't know what you're asking though.
    $endgroup$
    – Tim Campion
    9 hours ago







  • 1




    $begingroup$
    @TimCampion In most of mathematics $P(mathbbN)$ is treated as a set, but not in conceptualist mathematics. In (at least) one of the linked paper's by Nik Weaver, it is claimed that ZFC might prove false things about the natural numbers. I'm trying to get an idea of what that would mean---apart from the obvious point that if ZFC is inconsistent then it proves all things. You can think of the boxed question as a refinement of the question about Grothendieck universes, to the context of conceptualist mathematics vs. "ordinary mathematics" (as you put it).
    $endgroup$
    – Pace Nielsen
    9 hours ago






  • 2




    $begingroup$
    Ok. So there are two things going on in your question: 1.) You're asking whether "conceptualist mathematics" might prove different arithmetical statements then ZFC, say -- a mathematical question. 2.) You're asking whether there are reasons to think that the arithmetical consequences of one theory are more "true" than another--a philosophical question. To answer either question would require a much more precise specification of which theories, exactly we're discussing. FWIW I've never heard of "conceptualist mathematics" but generally restricting the powerset axiom is called "predicativism".
    $endgroup$
    – Tim Campion
    9 hours ago







  • 2




    $begingroup$
    Just some remarks. 1) By using second-order ZFC, the internal power set operation coincides with the external one (this is essentially why models second-order ZFC and Grothendieck universes are the same thing). 2) Consistency of PA is certainly a philosophical question. It boils down to whether the standard model is really a model. Now, universes are $V_kappa$'s (for $kappa$ strongly inaccessible) and these models are usually considered the intended models of ZFC when you think about a cumulative hierarchy. They have nice properties such as a "true" power set operation.
    $endgroup$
    – user40276
    8 hours ago















8












$begingroup$


Many students' first introduction to the difference between classes and sets is in category theory, where we learn that some categories (such as the category of all sets) are class-sized but not set-sized. After working with such structures, we discover that it is still worthwhile to sometimes treat them as if they were set-sized. But we can't always do so, without running into contradictions. A natural solution to this problem is the "Axiom of Grothendieck Universes". We then work not with the category of all sets, but the category of sets inside some given universe. This type of framework has been used by many notable mathematicians and seems very ubiquitous. For instance, it was an assumption in my universal algebra textbook. I would venture to say that most modern set theorists look at such an axiom as a very tame assumption.



My first question concerns the possible dangers of such an assumption, which are not often raised when first learning about this axiom. One obvious danger is that this axiom might lead to an inconsistency. In other words, ZFC might be consistent but ZFC+Universes might be inconsistent. I don't personally subscribe to this belief, but it is certainly a possibility (without further, even stronger, assumptions).



What really concerns me is the possibility of another danger: Could such a system proves false things about the natural numbers? In other words, even if we assume that ZFC+Universes is consistent, could it be the case that it proves false arithmetic statements?



The motivation for this question came from reading some of the work of Nik Weaver at this link, which argues for a conceptualist stance on mathematics. In particular, if we reject the axiom of power set, we are led to situations where all power sets of infinite sets are class-sized. Nik puts forth the idea that ZFC might prove false things about the natural numbers. Is this a real possibility? I suppose so, since it is possible that ZFC is inconsistent but the natural numbers aren't. But is it still possible even if ZFC is consistent? More generally:




Could treating the power set of the natural numbers as a set-sized object, rather than a class, force us to conclude false arithmetic statements (even if such a system is consistent)?




Even if the answer to this question is yes, I'm having a hard time seeing how we could recognize this fact, since according to the answers to this linked question it is difficult to state precisely what we mean by the natural numbers.



A second motivation for this question comes from what I've read about the multiverse view of set-theory. When creating a (transitive) model $M$ of ZFC, the set $P(mathbbN)$ can often be thought of as some "bigger" power set of the natural numbers intersected with the model. Moreover, via forcing, it seems that one can (always?) enlarge the power set of $mathbbN$. This does seem to suggest that $P(mathbbN)$ is not completely captured in any model. Thus, in its entirety, perhaps $P(mathbbN)$ should be treated as a class-sized object.




Added: I believe that the current proof we have of Fermat's Last Theorem uses the existence of a(t least one) Grothendieck universe. However, my understanding is that this dependence can be completely removed due to the fact that Fermat's Last Theorem has small quantifier complexity. I imagine that proofs of statements with higher quantifier complexity that use Grothendieck universes, do not necessarily have a way of removing their dependence on said universes. How would we tell if such arithmetic statements are true of the natural numbers?




2nd addition: There are some theories that we believe prove false arithmetic statements. Assuming the natural numbers can consistently exist (which we do!), then both PA+Con(PA) and PA+$neg$Con(PA) are consistent, but the second theory proves the false arithmetic sentence $neg$Con(PA).



My question then might be rephrased as:




What principles lead us to believe that "Universes" is a safe assumption, whereas "$neg$Con(PA)" is not safe, regarding what we believe is "true" arithmetic? (Next, repeat this question regarding the axiom of power set.) Is any theory that interprets PA "safe", as long as it is consistent with PA, and PA+Con(PA), and any such natural extension of these ideas?




Another way of putting this might be as follows:




Is the assumption Con(PA) a philosophical one, and not a mathematical one?




This ties into my previous question that I linked to, about describing the "real" natural numbers.










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    @jon The "category of all categories" runs into similar paradoxes as the "set of all sets", whereas the "category of all $U$-small categories" doesn't. We'd like to freely work with the standard categories (of groups, sets, monoids, etc...) as if they (together) can form a new collection which forms the object set of a category, and morphisms between them are functors. The standard way this is done is by working with the $U$-small categories instead. For this and other examples, look where textbooks make use of the axiom of universes.
    $endgroup$
    – Pace Nielsen
    10 hours ago






  • 1




    $begingroup$
    I don't understand the question in the box -- in most of mathematics, $P(mathbb N)$ is treated as a set and not a class. So it sounds like you're simply asking whether ordinary mathematics can prove false arithmetic statements. But I get the impression from the surrounding discussion that you're trying to ask something specific about Grothendieck universes... I don't know what you're asking though.
    $endgroup$
    – Tim Campion
    9 hours ago







  • 1




    $begingroup$
    @TimCampion In most of mathematics $P(mathbbN)$ is treated as a set, but not in conceptualist mathematics. In (at least) one of the linked paper's by Nik Weaver, it is claimed that ZFC might prove false things about the natural numbers. I'm trying to get an idea of what that would mean---apart from the obvious point that if ZFC is inconsistent then it proves all things. You can think of the boxed question as a refinement of the question about Grothendieck universes, to the context of conceptualist mathematics vs. "ordinary mathematics" (as you put it).
    $endgroup$
    – Pace Nielsen
    9 hours ago






  • 2




    $begingroup$
    Ok. So there are two things going on in your question: 1.) You're asking whether "conceptualist mathematics" might prove different arithmetical statements then ZFC, say -- a mathematical question. 2.) You're asking whether there are reasons to think that the arithmetical consequences of one theory are more "true" than another--a philosophical question. To answer either question would require a much more precise specification of which theories, exactly we're discussing. FWIW I've never heard of "conceptualist mathematics" but generally restricting the powerset axiom is called "predicativism".
    $endgroup$
    – Tim Campion
    9 hours ago







  • 2




    $begingroup$
    Just some remarks. 1) By using second-order ZFC, the internal power set operation coincides with the external one (this is essentially why models second-order ZFC and Grothendieck universes are the same thing). 2) Consistency of PA is certainly a philosophical question. It boils down to whether the standard model is really a model. Now, universes are $V_kappa$'s (for $kappa$ strongly inaccessible) and these models are usually considered the intended models of ZFC when you think about a cumulative hierarchy. They have nice properties such as a "true" power set operation.
    $endgroup$
    – user40276
    8 hours ago













8












8








8


1



$begingroup$


Many students' first introduction to the difference between classes and sets is in category theory, where we learn that some categories (such as the category of all sets) are class-sized but not set-sized. After working with such structures, we discover that it is still worthwhile to sometimes treat them as if they were set-sized. But we can't always do so, without running into contradictions. A natural solution to this problem is the "Axiom of Grothendieck Universes". We then work not with the category of all sets, but the category of sets inside some given universe. This type of framework has been used by many notable mathematicians and seems very ubiquitous. For instance, it was an assumption in my universal algebra textbook. I would venture to say that most modern set theorists look at such an axiom as a very tame assumption.



My first question concerns the possible dangers of such an assumption, which are not often raised when first learning about this axiom. One obvious danger is that this axiom might lead to an inconsistency. In other words, ZFC might be consistent but ZFC+Universes might be inconsistent. I don't personally subscribe to this belief, but it is certainly a possibility (without further, even stronger, assumptions).



What really concerns me is the possibility of another danger: Could such a system proves false things about the natural numbers? In other words, even if we assume that ZFC+Universes is consistent, could it be the case that it proves false arithmetic statements?



The motivation for this question came from reading some of the work of Nik Weaver at this link, which argues for a conceptualist stance on mathematics. In particular, if we reject the axiom of power set, we are led to situations where all power sets of infinite sets are class-sized. Nik puts forth the idea that ZFC might prove false things about the natural numbers. Is this a real possibility? I suppose so, since it is possible that ZFC is inconsistent but the natural numbers aren't. But is it still possible even if ZFC is consistent? More generally:




Could treating the power set of the natural numbers as a set-sized object, rather than a class, force us to conclude false arithmetic statements (even if such a system is consistent)?




Even if the answer to this question is yes, I'm having a hard time seeing how we could recognize this fact, since according to the answers to this linked question it is difficult to state precisely what we mean by the natural numbers.



A second motivation for this question comes from what I've read about the multiverse view of set-theory. When creating a (transitive) model $M$ of ZFC, the set $P(mathbbN)$ can often be thought of as some "bigger" power set of the natural numbers intersected with the model. Moreover, via forcing, it seems that one can (always?) enlarge the power set of $mathbbN$. This does seem to suggest that $P(mathbbN)$ is not completely captured in any model. Thus, in its entirety, perhaps $P(mathbbN)$ should be treated as a class-sized object.




Added: I believe that the current proof we have of Fermat's Last Theorem uses the existence of a(t least one) Grothendieck universe. However, my understanding is that this dependence can be completely removed due to the fact that Fermat's Last Theorem has small quantifier complexity. I imagine that proofs of statements with higher quantifier complexity that use Grothendieck universes, do not necessarily have a way of removing their dependence on said universes. How would we tell if such arithmetic statements are true of the natural numbers?




2nd addition: There are some theories that we believe prove false arithmetic statements. Assuming the natural numbers can consistently exist (which we do!), then both PA+Con(PA) and PA+$neg$Con(PA) are consistent, but the second theory proves the false arithmetic sentence $neg$Con(PA).



My question then might be rephrased as:




What principles lead us to believe that "Universes" is a safe assumption, whereas "$neg$Con(PA)" is not safe, regarding what we believe is "true" arithmetic? (Next, repeat this question regarding the axiom of power set.) Is any theory that interprets PA "safe", as long as it is consistent with PA, and PA+Con(PA), and any such natural extension of these ideas?




Another way of putting this might be as follows:




Is the assumption Con(PA) a philosophical one, and not a mathematical one?




This ties into my previous question that I linked to, about describing the "real" natural numbers.










share|cite|improve this question











$endgroup$




Many students' first introduction to the difference between classes and sets is in category theory, where we learn that some categories (such as the category of all sets) are class-sized but not set-sized. After working with such structures, we discover that it is still worthwhile to sometimes treat them as if they were set-sized. But we can't always do so, without running into contradictions. A natural solution to this problem is the "Axiom of Grothendieck Universes". We then work not with the category of all sets, but the category of sets inside some given universe. This type of framework has been used by many notable mathematicians and seems very ubiquitous. For instance, it was an assumption in my universal algebra textbook. I would venture to say that most modern set theorists look at such an axiom as a very tame assumption.



My first question concerns the possible dangers of such an assumption, which are not often raised when first learning about this axiom. One obvious danger is that this axiom might lead to an inconsistency. In other words, ZFC might be consistent but ZFC+Universes might be inconsistent. I don't personally subscribe to this belief, but it is certainly a possibility (without further, even stronger, assumptions).



What really concerns me is the possibility of another danger: Could such a system proves false things about the natural numbers? In other words, even if we assume that ZFC+Universes is consistent, could it be the case that it proves false arithmetic statements?



The motivation for this question came from reading some of the work of Nik Weaver at this link, which argues for a conceptualist stance on mathematics. In particular, if we reject the axiom of power set, we are led to situations where all power sets of infinite sets are class-sized. Nik puts forth the idea that ZFC might prove false things about the natural numbers. Is this a real possibility? I suppose so, since it is possible that ZFC is inconsistent but the natural numbers aren't. But is it still possible even if ZFC is consistent? More generally:




Could treating the power set of the natural numbers as a set-sized object, rather than a class, force us to conclude false arithmetic statements (even if such a system is consistent)?




Even if the answer to this question is yes, I'm having a hard time seeing how we could recognize this fact, since according to the answers to this linked question it is difficult to state precisely what we mean by the natural numbers.



A second motivation for this question comes from what I've read about the multiverse view of set-theory. When creating a (transitive) model $M$ of ZFC, the set $P(mathbbN)$ can often be thought of as some "bigger" power set of the natural numbers intersected with the model. Moreover, via forcing, it seems that one can (always?) enlarge the power set of $mathbbN$. This does seem to suggest that $P(mathbbN)$ is not completely captured in any model. Thus, in its entirety, perhaps $P(mathbbN)$ should be treated as a class-sized object.




Added: I believe that the current proof we have of Fermat's Last Theorem uses the existence of a(t least one) Grothendieck universe. However, my understanding is that this dependence can be completely removed due to the fact that Fermat's Last Theorem has small quantifier complexity. I imagine that proofs of statements with higher quantifier complexity that use Grothendieck universes, do not necessarily have a way of removing their dependence on said universes. How would we tell if such arithmetic statements are true of the natural numbers?




2nd addition: There are some theories that we believe prove false arithmetic statements. Assuming the natural numbers can consistently exist (which we do!), then both PA+Con(PA) and PA+$neg$Con(PA) are consistent, but the second theory proves the false arithmetic sentence $neg$Con(PA).



My question then might be rephrased as:




What principles lead us to believe that "Universes" is a safe assumption, whereas "$neg$Con(PA)" is not safe, regarding what we believe is "true" arithmetic? (Next, repeat this question regarding the axiom of power set.) Is any theory that interprets PA "safe", as long as it is consistent with PA, and PA+Con(PA), and any such natural extension of these ideas?




Another way of putting this might be as follows:




Is the assumption Con(PA) a philosophical one, and not a mathematical one?




This ties into my previous question that I linked to, about describing the "real" natural numbers.







ct.category-theory set-theory lo.logic model-theory universal-algebra






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 7 hours ago









YCor

29.9k488144




29.9k488144










asked 10 hours ago









Pace NielsenPace Nielsen

7,45923280




7,45923280







  • 1




    $begingroup$
    @jon The "category of all categories" runs into similar paradoxes as the "set of all sets", whereas the "category of all $U$-small categories" doesn't. We'd like to freely work with the standard categories (of groups, sets, monoids, etc...) as if they (together) can form a new collection which forms the object set of a category, and morphisms between them are functors. The standard way this is done is by working with the $U$-small categories instead. For this and other examples, look where textbooks make use of the axiom of universes.
    $endgroup$
    – Pace Nielsen
    10 hours ago






  • 1




    $begingroup$
    I don't understand the question in the box -- in most of mathematics, $P(mathbb N)$ is treated as a set and not a class. So it sounds like you're simply asking whether ordinary mathematics can prove false arithmetic statements. But I get the impression from the surrounding discussion that you're trying to ask something specific about Grothendieck universes... I don't know what you're asking though.
    $endgroup$
    – Tim Campion
    9 hours ago







  • 1




    $begingroup$
    @TimCampion In most of mathematics $P(mathbbN)$ is treated as a set, but not in conceptualist mathematics. In (at least) one of the linked paper's by Nik Weaver, it is claimed that ZFC might prove false things about the natural numbers. I'm trying to get an idea of what that would mean---apart from the obvious point that if ZFC is inconsistent then it proves all things. You can think of the boxed question as a refinement of the question about Grothendieck universes, to the context of conceptualist mathematics vs. "ordinary mathematics" (as you put it).
    $endgroup$
    – Pace Nielsen
    9 hours ago






  • 2




    $begingroup$
    Ok. So there are two things going on in your question: 1.) You're asking whether "conceptualist mathematics" might prove different arithmetical statements then ZFC, say -- a mathematical question. 2.) You're asking whether there are reasons to think that the arithmetical consequences of one theory are more "true" than another--a philosophical question. To answer either question would require a much more precise specification of which theories, exactly we're discussing. FWIW I've never heard of "conceptualist mathematics" but generally restricting the powerset axiom is called "predicativism".
    $endgroup$
    – Tim Campion
    9 hours ago







  • 2




    $begingroup$
    Just some remarks. 1) By using second-order ZFC, the internal power set operation coincides with the external one (this is essentially why models second-order ZFC and Grothendieck universes are the same thing). 2) Consistency of PA is certainly a philosophical question. It boils down to whether the standard model is really a model. Now, universes are $V_kappa$'s (for $kappa$ strongly inaccessible) and these models are usually considered the intended models of ZFC when you think about a cumulative hierarchy. They have nice properties such as a "true" power set operation.
    $endgroup$
    – user40276
    8 hours ago












  • 1




    $begingroup$
    @jon The "category of all categories" runs into similar paradoxes as the "set of all sets", whereas the "category of all $U$-small categories" doesn't. We'd like to freely work with the standard categories (of groups, sets, monoids, etc...) as if they (together) can form a new collection which forms the object set of a category, and morphisms between them are functors. The standard way this is done is by working with the $U$-small categories instead. For this and other examples, look where textbooks make use of the axiom of universes.
    $endgroup$
    – Pace Nielsen
    10 hours ago






  • 1




    $begingroup$
    I don't understand the question in the box -- in most of mathematics, $P(mathbb N)$ is treated as a set and not a class. So it sounds like you're simply asking whether ordinary mathematics can prove false arithmetic statements. But I get the impression from the surrounding discussion that you're trying to ask something specific about Grothendieck universes... I don't know what you're asking though.
    $endgroup$
    – Tim Campion
    9 hours ago







  • 1




    $begingroup$
    @TimCampion In most of mathematics $P(mathbbN)$ is treated as a set, but not in conceptualist mathematics. In (at least) one of the linked paper's by Nik Weaver, it is claimed that ZFC might prove false things about the natural numbers. I'm trying to get an idea of what that would mean---apart from the obvious point that if ZFC is inconsistent then it proves all things. You can think of the boxed question as a refinement of the question about Grothendieck universes, to the context of conceptualist mathematics vs. "ordinary mathematics" (as you put it).
    $endgroup$
    – Pace Nielsen
    9 hours ago






  • 2




    $begingroup$
    Ok. So there are two things going on in your question: 1.) You're asking whether "conceptualist mathematics" might prove different arithmetical statements then ZFC, say -- a mathematical question. 2.) You're asking whether there are reasons to think that the arithmetical consequences of one theory are more "true" than another--a philosophical question. To answer either question would require a much more precise specification of which theories, exactly we're discussing. FWIW I've never heard of "conceptualist mathematics" but generally restricting the powerset axiom is called "predicativism".
    $endgroup$
    – Tim Campion
    9 hours ago







  • 2




    $begingroup$
    Just some remarks. 1) By using second-order ZFC, the internal power set operation coincides with the external one (this is essentially why models second-order ZFC and Grothendieck universes are the same thing). 2) Consistency of PA is certainly a philosophical question. It boils down to whether the standard model is really a model. Now, universes are $V_kappa$'s (for $kappa$ strongly inaccessible) and these models are usually considered the intended models of ZFC when you think about a cumulative hierarchy. They have nice properties such as a "true" power set operation.
    $endgroup$
    – user40276
    8 hours ago







1




1




$begingroup$
@jon The "category of all categories" runs into similar paradoxes as the "set of all sets", whereas the "category of all $U$-small categories" doesn't. We'd like to freely work with the standard categories (of groups, sets, monoids, etc...) as if they (together) can form a new collection which forms the object set of a category, and morphisms between them are functors. The standard way this is done is by working with the $U$-small categories instead. For this and other examples, look where textbooks make use of the axiom of universes.
$endgroup$
– Pace Nielsen
10 hours ago




$begingroup$
@jon The "category of all categories" runs into similar paradoxes as the "set of all sets", whereas the "category of all $U$-small categories" doesn't. We'd like to freely work with the standard categories (of groups, sets, monoids, etc...) as if they (together) can form a new collection which forms the object set of a category, and morphisms between them are functors. The standard way this is done is by working with the $U$-small categories instead. For this and other examples, look where textbooks make use of the axiom of universes.
$endgroup$
– Pace Nielsen
10 hours ago




1




1




$begingroup$
I don't understand the question in the box -- in most of mathematics, $P(mathbb N)$ is treated as a set and not a class. So it sounds like you're simply asking whether ordinary mathematics can prove false arithmetic statements. But I get the impression from the surrounding discussion that you're trying to ask something specific about Grothendieck universes... I don't know what you're asking though.
$endgroup$
– Tim Campion
9 hours ago





$begingroup$
I don't understand the question in the box -- in most of mathematics, $P(mathbb N)$ is treated as a set and not a class. So it sounds like you're simply asking whether ordinary mathematics can prove false arithmetic statements. But I get the impression from the surrounding discussion that you're trying to ask something specific about Grothendieck universes... I don't know what you're asking though.
$endgroup$
– Tim Campion
9 hours ago





1




1




$begingroup$
@TimCampion In most of mathematics $P(mathbbN)$ is treated as a set, but not in conceptualist mathematics. In (at least) one of the linked paper's by Nik Weaver, it is claimed that ZFC might prove false things about the natural numbers. I'm trying to get an idea of what that would mean---apart from the obvious point that if ZFC is inconsistent then it proves all things. You can think of the boxed question as a refinement of the question about Grothendieck universes, to the context of conceptualist mathematics vs. "ordinary mathematics" (as you put it).
$endgroup$
– Pace Nielsen
9 hours ago




$begingroup$
@TimCampion In most of mathematics $P(mathbbN)$ is treated as a set, but not in conceptualist mathematics. In (at least) one of the linked paper's by Nik Weaver, it is claimed that ZFC might prove false things about the natural numbers. I'm trying to get an idea of what that would mean---apart from the obvious point that if ZFC is inconsistent then it proves all things. You can think of the boxed question as a refinement of the question about Grothendieck universes, to the context of conceptualist mathematics vs. "ordinary mathematics" (as you put it).
$endgroup$
– Pace Nielsen
9 hours ago




2




2




$begingroup$
Ok. So there are two things going on in your question: 1.) You're asking whether "conceptualist mathematics" might prove different arithmetical statements then ZFC, say -- a mathematical question. 2.) You're asking whether there are reasons to think that the arithmetical consequences of one theory are more "true" than another--a philosophical question. To answer either question would require a much more precise specification of which theories, exactly we're discussing. FWIW I've never heard of "conceptualist mathematics" but generally restricting the powerset axiom is called "predicativism".
$endgroup$
– Tim Campion
9 hours ago





$begingroup$
Ok. So there are two things going on in your question: 1.) You're asking whether "conceptualist mathematics" might prove different arithmetical statements then ZFC, say -- a mathematical question. 2.) You're asking whether there are reasons to think that the arithmetical consequences of one theory are more "true" than another--a philosophical question. To answer either question would require a much more precise specification of which theories, exactly we're discussing. FWIW I've never heard of "conceptualist mathematics" but generally restricting the powerset axiom is called "predicativism".
$endgroup$
– Tim Campion
9 hours ago





2




2




$begingroup$
Just some remarks. 1) By using second-order ZFC, the internal power set operation coincides with the external one (this is essentially why models second-order ZFC and Grothendieck universes are the same thing). 2) Consistency of PA is certainly a philosophical question. It boils down to whether the standard model is really a model. Now, universes are $V_kappa$'s (for $kappa$ strongly inaccessible) and these models are usually considered the intended models of ZFC when you think about a cumulative hierarchy. They have nice properties such as a "true" power set operation.
$endgroup$
– user40276
8 hours ago




$begingroup$
Just some remarks. 1) By using second-order ZFC, the internal power set operation coincides with the external one (this is essentially why models second-order ZFC and Grothendieck universes are the same thing). 2) Consistency of PA is certainly a philosophical question. It boils down to whether the standard model is really a model. Now, universes are $V_kappa$'s (for $kappa$ strongly inaccessible) and these models are usually considered the intended models of ZFC when you think about a cumulative hierarchy. They have nice properties such as a "true" power set operation.
$endgroup$
– user40276
8 hours ago










3 Answers
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$begingroup$

For what it's worth, the reason I made that comment was because when I gave talks expressing skepticism about the philosophical basis of ZFC, I would often get the reaction "but as long as it's consistent, what's the problem?" Some version of this attitude is also quite prevalent in the philosophical literature on the subject. I wanted to make the point that just being consistent isn't good enough: ZFC might well be consistent yet still prove, for example, that some Turing machine halts when in fact it does not. If you're a skeptic about sets but not about numbers, this could be a concern.



As for the "safety" of assuming ZFC is arithmetically sound, it is clear that as long as ZFC is consistent, no weaker system could prove that it is unsound. So for predicativists like me, who generally work in much weaker systems than ZFC, it seems unlikely that we could ever establish unsoundness. In that sense I'd say it's pretty "safe" to assume it is sound.



However ... I regard the Peano axioms as expressing intuitively evident truths about the natural numbers, so I have no problem affirming Con(PA). Whereas I regard ZFC as what you get when you realize that full comprehension leads to inconsistencies, so you replace it with a hodgepodge of instances of comprehension which appear to be weak enough to block any paradoxes. It seems to me quite ad hoc and unmotivated, so although we might (or might not) be confident that ZFC is consistent, there is little reason to expect it to be (or not to be) arithmetically sound.



(I should add that I regard the "iterative conception" which is supposed to justify ZFC as utterly unconvincing. Sets are said to be built up in stages, and then it is parenthetically added that they are, of course, timeless abstract objects so they aren't really "built", nor do they really "appear" in "stages" --- it's all just a "metaphor". Thus "any conviction that the iterative conception may carry is made to depend on metaphorical details that are dismissed as inessential to it." (I. Jane))






share|cite|improve this answer









$endgroup$












  • $begingroup$
    +1 Thanks for the background!
    $endgroup$
    – Pace Nielsen
    4 hours ago










  • $begingroup$
    You're very welcome. Thank you for the interest!
    $endgroup$
    – Nik Weaver
    3 hours ago


















3












$begingroup$

Here is why Universes is a "safe" assumption. Suppose it actually is consistent. Then it cannot possibly prove any arithmetical statement that contradicts an arithmetical theorem of PA or ZFC. This is because it proves that PA and ZFC have "internally standard" interpretations, and so everything that they prove about the naturals is true of the "standard" model (i.e. within the theory ZFC+Universes), and thus agrees with everything "true" (true according to ZFC+Universes).



If we further assume that ZFC+Universes has an actually standard model, then this means that all its arithmetical theorems are actually true. But this kind of begs the question, I think. We would like to know about some kind of coherency between various theories at a syntactical level, that they don't prove contradictory arithmetical statements.



The idea, I believe, is that if we can organize them linearly in a "standard interpretation hierarchy," then we are fine as long as we believe in the consistency of the strongest theory under consideration. To be more precise, we look at theories $T$ which have a "natural numbers object" $mathbb N^T$, which should at least satisfy PA, and should probably be proven by $T$ to satisfy second-order PA. If $S$ is another such theory, and $T$ proves that $S$ has a model $frak A$ such that $mathbb N^frak A = mathbb N^T$, then $T$ and $S$ cannot disagree about what their respective natural numbers object satisfies.



This situation applies to large cardinal axioms more generally.






share|cite|improve this answer









$endgroup$












  • $begingroup$
    I think by "safe" I mean not just consistent with PA, but consistent with all arithmetic true we would naturally accept. This would include Con(PA) as well as Con(PA+Con(PA)), etc... It might also include deeper things like Goodstein's theorem.
    $endgroup$
    – Pace Nielsen
    4 hours ago


















2












$begingroup$

There's a lot going on in this question; let's break it down:




Is the assumption Con(PA) a philosophical one, and not a mathematical one?




I suppose it depends on what you mean by "the assumption Con(PA)":



  • If you're writing a mathematical proof, then either the foundations you're assuming prove Con(PA) or they don't, and it's a mathematical question which is the case. You'll be mathematically justified in assuming Con(PA) in the former case. In the latter case, there are contexts where "assuming Con(PA)" is mathematically justified -- for example, if you're trying to prove a statement of the form $Con(PA) Rightarrow P$ for some $P$, then you're allowed to argue by assuming Con(PA) and proving $P$. But probably that's not what you mean.


  • If you're just asserting "PA is consistent" in a non-mathematical context, then your statement requires some philosophical unpacking to make precise, and moreover to determine to what extent it is justified. In this sense, it's a philosophical statement.



What principles lead us to believe that "Universes" is a safe assumption, whereas "¬Con(PA)" is not safe, regarding what we believe is "true" arithmetic?




There is an extensive philosophical literature discussing justifications for large cardinal axioms. You might start here. I'm not an expert, but I'm not aware of arguments which specifically argue that one should accept the arithmetic consequences of large cardinal axioms without arguing that one should accept the axioms outright. I would be interested to see such an argument. I once asked this question with related motivations.




(Next, repeat this question regarding the axiom of power set.)




Restrictions on powersets are studied in predicative mathematics. For some discussion of predicativism, one might start here or here. For some arguments for impredicativism, one might start here.




Is any theory that interprets PA "safe", as long as it is consistent with PA, and PA+Con(PA), and any such natural extension of these ideas?




By "safe", I take it that you continue to mean that the theory's arithmetic consequences are "true". There is a large body of literature discussing truth in mathematics. You seem to be particularly interested in the hierarchy obtained by passing from $T$ to $T + Con(T)$ iteratively. This hierarchy appears to be discussed from a philosophical perspective here. I think most logicians would probably agree that ascending this hierarchy adds relatively little consistency strength. And I'm not aware of serious attacks on the common-sense idea that if one believes $T$ is true, then one should also believe that $T + Con(T)$ is true.




Again, I'm not an expert, but it seems to me that most of the time when trying to justify stronger axioms from weaker assumptions, one appeals to some sort of reflection principle. This concept seems to be relevant to several of the questions you're asking.






share|cite|improve this answer











$endgroup$












  • $begingroup$
    Regarding your second-to-last paragraph, on "truth" in mathematics, how would you interpret the wikipedia article on Goodstein's Theorem, as it asserts that this is "a true statement that is unprovable in Peano arithmetic". What do they mean by "true" in this context? I think my comment about "safe" means "consistent with anything that we naturally would take to be true"---but I'm also a little confused at what things we take to be true!
    $endgroup$
    – Pace Nielsen
    4 hours ago










  • $begingroup$
    That statement makes sense if you don't read too much into it: if a statement is provable in ZFC, then it's standard mathematical practice to regard it as true. So the statement isn't that different from saying "Goodstein's theorem is a theorem of ZFC but not of PA". (Of course, Goodstein's theorem can presumably be proven using less than the full strength of ZFC, but that's beside the point.)
    $endgroup$
    – Tim Campion
    1 hour ago














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3 Answers
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$begingroup$

For what it's worth, the reason I made that comment was because when I gave talks expressing skepticism about the philosophical basis of ZFC, I would often get the reaction "but as long as it's consistent, what's the problem?" Some version of this attitude is also quite prevalent in the philosophical literature on the subject. I wanted to make the point that just being consistent isn't good enough: ZFC might well be consistent yet still prove, for example, that some Turing machine halts when in fact it does not. If you're a skeptic about sets but not about numbers, this could be a concern.



As for the "safety" of assuming ZFC is arithmetically sound, it is clear that as long as ZFC is consistent, no weaker system could prove that it is unsound. So for predicativists like me, who generally work in much weaker systems than ZFC, it seems unlikely that we could ever establish unsoundness. In that sense I'd say it's pretty "safe" to assume it is sound.



However ... I regard the Peano axioms as expressing intuitively evident truths about the natural numbers, so I have no problem affirming Con(PA). Whereas I regard ZFC as what you get when you realize that full comprehension leads to inconsistencies, so you replace it with a hodgepodge of instances of comprehension which appear to be weak enough to block any paradoxes. It seems to me quite ad hoc and unmotivated, so although we might (or might not) be confident that ZFC is consistent, there is little reason to expect it to be (or not to be) arithmetically sound.



(I should add that I regard the "iterative conception" which is supposed to justify ZFC as utterly unconvincing. Sets are said to be built up in stages, and then it is parenthetically added that they are, of course, timeless abstract objects so they aren't really "built", nor do they really "appear" in "stages" --- it's all just a "metaphor". Thus "any conviction that the iterative conception may carry is made to depend on metaphorical details that are dismissed as inessential to it." (I. Jane))






share|cite|improve this answer









$endgroup$












  • $begingroup$
    +1 Thanks for the background!
    $endgroup$
    – Pace Nielsen
    4 hours ago










  • $begingroup$
    You're very welcome. Thank you for the interest!
    $endgroup$
    – Nik Weaver
    3 hours ago















5












$begingroup$

For what it's worth, the reason I made that comment was because when I gave talks expressing skepticism about the philosophical basis of ZFC, I would often get the reaction "but as long as it's consistent, what's the problem?" Some version of this attitude is also quite prevalent in the philosophical literature on the subject. I wanted to make the point that just being consistent isn't good enough: ZFC might well be consistent yet still prove, for example, that some Turing machine halts when in fact it does not. If you're a skeptic about sets but not about numbers, this could be a concern.



As for the "safety" of assuming ZFC is arithmetically sound, it is clear that as long as ZFC is consistent, no weaker system could prove that it is unsound. So for predicativists like me, who generally work in much weaker systems than ZFC, it seems unlikely that we could ever establish unsoundness. In that sense I'd say it's pretty "safe" to assume it is sound.



However ... I regard the Peano axioms as expressing intuitively evident truths about the natural numbers, so I have no problem affirming Con(PA). Whereas I regard ZFC as what you get when you realize that full comprehension leads to inconsistencies, so you replace it with a hodgepodge of instances of comprehension which appear to be weak enough to block any paradoxes. It seems to me quite ad hoc and unmotivated, so although we might (or might not) be confident that ZFC is consistent, there is little reason to expect it to be (or not to be) arithmetically sound.



(I should add that I regard the "iterative conception" which is supposed to justify ZFC as utterly unconvincing. Sets are said to be built up in stages, and then it is parenthetically added that they are, of course, timeless abstract objects so they aren't really "built", nor do they really "appear" in "stages" --- it's all just a "metaphor". Thus "any conviction that the iterative conception may carry is made to depend on metaphorical details that are dismissed as inessential to it." (I. Jane))






share|cite|improve this answer









$endgroup$












  • $begingroup$
    +1 Thanks for the background!
    $endgroup$
    – Pace Nielsen
    4 hours ago










  • $begingroup$
    You're very welcome. Thank you for the interest!
    $endgroup$
    – Nik Weaver
    3 hours ago













5












5








5





$begingroup$

For what it's worth, the reason I made that comment was because when I gave talks expressing skepticism about the philosophical basis of ZFC, I would often get the reaction "but as long as it's consistent, what's the problem?" Some version of this attitude is also quite prevalent in the philosophical literature on the subject. I wanted to make the point that just being consistent isn't good enough: ZFC might well be consistent yet still prove, for example, that some Turing machine halts when in fact it does not. If you're a skeptic about sets but not about numbers, this could be a concern.



As for the "safety" of assuming ZFC is arithmetically sound, it is clear that as long as ZFC is consistent, no weaker system could prove that it is unsound. So for predicativists like me, who generally work in much weaker systems than ZFC, it seems unlikely that we could ever establish unsoundness. In that sense I'd say it's pretty "safe" to assume it is sound.



However ... I regard the Peano axioms as expressing intuitively evident truths about the natural numbers, so I have no problem affirming Con(PA). Whereas I regard ZFC as what you get when you realize that full comprehension leads to inconsistencies, so you replace it with a hodgepodge of instances of comprehension which appear to be weak enough to block any paradoxes. It seems to me quite ad hoc and unmotivated, so although we might (or might not) be confident that ZFC is consistent, there is little reason to expect it to be (or not to be) arithmetically sound.



(I should add that I regard the "iterative conception" which is supposed to justify ZFC as utterly unconvincing. Sets are said to be built up in stages, and then it is parenthetically added that they are, of course, timeless abstract objects so they aren't really "built", nor do they really "appear" in "stages" --- it's all just a "metaphor". Thus "any conviction that the iterative conception may carry is made to depend on metaphorical details that are dismissed as inessential to it." (I. Jane))






share|cite|improve this answer









$endgroup$



For what it's worth, the reason I made that comment was because when I gave talks expressing skepticism about the philosophical basis of ZFC, I would often get the reaction "but as long as it's consistent, what's the problem?" Some version of this attitude is also quite prevalent in the philosophical literature on the subject. I wanted to make the point that just being consistent isn't good enough: ZFC might well be consistent yet still prove, for example, that some Turing machine halts when in fact it does not. If you're a skeptic about sets but not about numbers, this could be a concern.



As for the "safety" of assuming ZFC is arithmetically sound, it is clear that as long as ZFC is consistent, no weaker system could prove that it is unsound. So for predicativists like me, who generally work in much weaker systems than ZFC, it seems unlikely that we could ever establish unsoundness. In that sense I'd say it's pretty "safe" to assume it is sound.



However ... I regard the Peano axioms as expressing intuitively evident truths about the natural numbers, so I have no problem affirming Con(PA). Whereas I regard ZFC as what you get when you realize that full comprehension leads to inconsistencies, so you replace it with a hodgepodge of instances of comprehension which appear to be weak enough to block any paradoxes. It seems to me quite ad hoc and unmotivated, so although we might (or might not) be confident that ZFC is consistent, there is little reason to expect it to be (or not to be) arithmetically sound.



(I should add that I regard the "iterative conception" which is supposed to justify ZFC as utterly unconvincing. Sets are said to be built up in stages, and then it is parenthetically added that they are, of course, timeless abstract objects so they aren't really "built", nor do they really "appear" in "stages" --- it's all just a "metaphor". Thus "any conviction that the iterative conception may carry is made to depend on metaphorical details that are dismissed as inessential to it." (I. Jane))







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered 6 hours ago









Nik WeaverNik Weaver

23.1k152136




23.1k152136











  • $begingroup$
    +1 Thanks for the background!
    $endgroup$
    – Pace Nielsen
    4 hours ago










  • $begingroup$
    You're very welcome. Thank you for the interest!
    $endgroup$
    – Nik Weaver
    3 hours ago
















  • $begingroup$
    +1 Thanks for the background!
    $endgroup$
    – Pace Nielsen
    4 hours ago










  • $begingroup$
    You're very welcome. Thank you for the interest!
    $endgroup$
    – Nik Weaver
    3 hours ago















$begingroup$
+1 Thanks for the background!
$endgroup$
– Pace Nielsen
4 hours ago




$begingroup$
+1 Thanks for the background!
$endgroup$
– Pace Nielsen
4 hours ago












$begingroup$
You're very welcome. Thank you for the interest!
$endgroup$
– Nik Weaver
3 hours ago




$begingroup$
You're very welcome. Thank you for the interest!
$endgroup$
– Nik Weaver
3 hours ago











3












$begingroup$

Here is why Universes is a "safe" assumption. Suppose it actually is consistent. Then it cannot possibly prove any arithmetical statement that contradicts an arithmetical theorem of PA or ZFC. This is because it proves that PA and ZFC have "internally standard" interpretations, and so everything that they prove about the naturals is true of the "standard" model (i.e. within the theory ZFC+Universes), and thus agrees with everything "true" (true according to ZFC+Universes).



If we further assume that ZFC+Universes has an actually standard model, then this means that all its arithmetical theorems are actually true. But this kind of begs the question, I think. We would like to know about some kind of coherency between various theories at a syntactical level, that they don't prove contradictory arithmetical statements.



The idea, I believe, is that if we can organize them linearly in a "standard interpretation hierarchy," then we are fine as long as we believe in the consistency of the strongest theory under consideration. To be more precise, we look at theories $T$ which have a "natural numbers object" $mathbb N^T$, which should at least satisfy PA, and should probably be proven by $T$ to satisfy second-order PA. If $S$ is another such theory, and $T$ proves that $S$ has a model $frak A$ such that $mathbb N^frak A = mathbb N^T$, then $T$ and $S$ cannot disagree about what their respective natural numbers object satisfies.



This situation applies to large cardinal axioms more generally.






share|cite|improve this answer









$endgroup$












  • $begingroup$
    I think by "safe" I mean not just consistent with PA, but consistent with all arithmetic true we would naturally accept. This would include Con(PA) as well as Con(PA+Con(PA)), etc... It might also include deeper things like Goodstein's theorem.
    $endgroup$
    – Pace Nielsen
    4 hours ago















3












$begingroup$

Here is why Universes is a "safe" assumption. Suppose it actually is consistent. Then it cannot possibly prove any arithmetical statement that contradicts an arithmetical theorem of PA or ZFC. This is because it proves that PA and ZFC have "internally standard" interpretations, and so everything that they prove about the naturals is true of the "standard" model (i.e. within the theory ZFC+Universes), and thus agrees with everything "true" (true according to ZFC+Universes).



If we further assume that ZFC+Universes has an actually standard model, then this means that all its arithmetical theorems are actually true. But this kind of begs the question, I think. We would like to know about some kind of coherency between various theories at a syntactical level, that they don't prove contradictory arithmetical statements.



The idea, I believe, is that if we can organize them linearly in a "standard interpretation hierarchy," then we are fine as long as we believe in the consistency of the strongest theory under consideration. To be more precise, we look at theories $T$ which have a "natural numbers object" $mathbb N^T$, which should at least satisfy PA, and should probably be proven by $T$ to satisfy second-order PA. If $S$ is another such theory, and $T$ proves that $S$ has a model $frak A$ such that $mathbb N^frak A = mathbb N^T$, then $T$ and $S$ cannot disagree about what their respective natural numbers object satisfies.



This situation applies to large cardinal axioms more generally.






share|cite|improve this answer









$endgroup$












  • $begingroup$
    I think by "safe" I mean not just consistent with PA, but consistent with all arithmetic true we would naturally accept. This would include Con(PA) as well as Con(PA+Con(PA)), etc... It might also include deeper things like Goodstein's theorem.
    $endgroup$
    – Pace Nielsen
    4 hours ago













3












3








3





$begingroup$

Here is why Universes is a "safe" assumption. Suppose it actually is consistent. Then it cannot possibly prove any arithmetical statement that contradicts an arithmetical theorem of PA or ZFC. This is because it proves that PA and ZFC have "internally standard" interpretations, and so everything that they prove about the naturals is true of the "standard" model (i.e. within the theory ZFC+Universes), and thus agrees with everything "true" (true according to ZFC+Universes).



If we further assume that ZFC+Universes has an actually standard model, then this means that all its arithmetical theorems are actually true. But this kind of begs the question, I think. We would like to know about some kind of coherency between various theories at a syntactical level, that they don't prove contradictory arithmetical statements.



The idea, I believe, is that if we can organize them linearly in a "standard interpretation hierarchy," then we are fine as long as we believe in the consistency of the strongest theory under consideration. To be more precise, we look at theories $T$ which have a "natural numbers object" $mathbb N^T$, which should at least satisfy PA, and should probably be proven by $T$ to satisfy second-order PA. If $S$ is another such theory, and $T$ proves that $S$ has a model $frak A$ such that $mathbb N^frak A = mathbb N^T$, then $T$ and $S$ cannot disagree about what their respective natural numbers object satisfies.



This situation applies to large cardinal axioms more generally.






share|cite|improve this answer









$endgroup$



Here is why Universes is a "safe" assumption. Suppose it actually is consistent. Then it cannot possibly prove any arithmetical statement that contradicts an arithmetical theorem of PA or ZFC. This is because it proves that PA and ZFC have "internally standard" interpretations, and so everything that they prove about the naturals is true of the "standard" model (i.e. within the theory ZFC+Universes), and thus agrees with everything "true" (true according to ZFC+Universes).



If we further assume that ZFC+Universes has an actually standard model, then this means that all its arithmetical theorems are actually true. But this kind of begs the question, I think. We would like to know about some kind of coherency between various theories at a syntactical level, that they don't prove contradictory arithmetical statements.



The idea, I believe, is that if we can organize them linearly in a "standard interpretation hierarchy," then we are fine as long as we believe in the consistency of the strongest theory under consideration. To be more precise, we look at theories $T$ which have a "natural numbers object" $mathbb N^T$, which should at least satisfy PA, and should probably be proven by $T$ to satisfy second-order PA. If $S$ is another such theory, and $T$ proves that $S$ has a model $frak A$ such that $mathbb N^frak A = mathbb N^T$, then $T$ and $S$ cannot disagree about what their respective natural numbers object satisfies.



This situation applies to large cardinal axioms more generally.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered 6 hours ago









Monroe EskewMonroe Eskew

8,23132768




8,23132768











  • $begingroup$
    I think by "safe" I mean not just consistent with PA, but consistent with all arithmetic true we would naturally accept. This would include Con(PA) as well as Con(PA+Con(PA)), etc... It might also include deeper things like Goodstein's theorem.
    $endgroup$
    – Pace Nielsen
    4 hours ago
















  • $begingroup$
    I think by "safe" I mean not just consistent with PA, but consistent with all arithmetic true we would naturally accept. This would include Con(PA) as well as Con(PA+Con(PA)), etc... It might also include deeper things like Goodstein's theorem.
    $endgroup$
    – Pace Nielsen
    4 hours ago















$begingroup$
I think by "safe" I mean not just consistent with PA, but consistent with all arithmetic true we would naturally accept. This would include Con(PA) as well as Con(PA+Con(PA)), etc... It might also include deeper things like Goodstein's theorem.
$endgroup$
– Pace Nielsen
4 hours ago




$begingroup$
I think by "safe" I mean not just consistent with PA, but consistent with all arithmetic true we would naturally accept. This would include Con(PA) as well as Con(PA+Con(PA)), etc... It might also include deeper things like Goodstein's theorem.
$endgroup$
– Pace Nielsen
4 hours ago











2












$begingroup$

There's a lot going on in this question; let's break it down:




Is the assumption Con(PA) a philosophical one, and not a mathematical one?




I suppose it depends on what you mean by "the assumption Con(PA)":



  • If you're writing a mathematical proof, then either the foundations you're assuming prove Con(PA) or they don't, and it's a mathematical question which is the case. You'll be mathematically justified in assuming Con(PA) in the former case. In the latter case, there are contexts where "assuming Con(PA)" is mathematically justified -- for example, if you're trying to prove a statement of the form $Con(PA) Rightarrow P$ for some $P$, then you're allowed to argue by assuming Con(PA) and proving $P$. But probably that's not what you mean.


  • If you're just asserting "PA is consistent" in a non-mathematical context, then your statement requires some philosophical unpacking to make precise, and moreover to determine to what extent it is justified. In this sense, it's a philosophical statement.



What principles lead us to believe that "Universes" is a safe assumption, whereas "¬Con(PA)" is not safe, regarding what we believe is "true" arithmetic?




There is an extensive philosophical literature discussing justifications for large cardinal axioms. You might start here. I'm not an expert, but I'm not aware of arguments which specifically argue that one should accept the arithmetic consequences of large cardinal axioms without arguing that one should accept the axioms outright. I would be interested to see such an argument. I once asked this question with related motivations.




(Next, repeat this question regarding the axiom of power set.)




Restrictions on powersets are studied in predicative mathematics. For some discussion of predicativism, one might start here or here. For some arguments for impredicativism, one might start here.




Is any theory that interprets PA "safe", as long as it is consistent with PA, and PA+Con(PA), and any such natural extension of these ideas?




By "safe", I take it that you continue to mean that the theory's arithmetic consequences are "true". There is a large body of literature discussing truth in mathematics. You seem to be particularly interested in the hierarchy obtained by passing from $T$ to $T + Con(T)$ iteratively. This hierarchy appears to be discussed from a philosophical perspective here. I think most logicians would probably agree that ascending this hierarchy adds relatively little consistency strength. And I'm not aware of serious attacks on the common-sense idea that if one believes $T$ is true, then one should also believe that $T + Con(T)$ is true.




Again, I'm not an expert, but it seems to me that most of the time when trying to justify stronger axioms from weaker assumptions, one appeals to some sort of reflection principle. This concept seems to be relevant to several of the questions you're asking.






share|cite|improve this answer











$endgroup$












  • $begingroup$
    Regarding your second-to-last paragraph, on "truth" in mathematics, how would you interpret the wikipedia article on Goodstein's Theorem, as it asserts that this is "a true statement that is unprovable in Peano arithmetic". What do they mean by "true" in this context? I think my comment about "safe" means "consistent with anything that we naturally would take to be true"---but I'm also a little confused at what things we take to be true!
    $endgroup$
    – Pace Nielsen
    4 hours ago










  • $begingroup$
    That statement makes sense if you don't read too much into it: if a statement is provable in ZFC, then it's standard mathematical practice to regard it as true. So the statement isn't that different from saying "Goodstein's theorem is a theorem of ZFC but not of PA". (Of course, Goodstein's theorem can presumably be proven using less than the full strength of ZFC, but that's beside the point.)
    $endgroup$
    – Tim Campion
    1 hour ago
















2












$begingroup$

There's a lot going on in this question; let's break it down:




Is the assumption Con(PA) a philosophical one, and not a mathematical one?




I suppose it depends on what you mean by "the assumption Con(PA)":



  • If you're writing a mathematical proof, then either the foundations you're assuming prove Con(PA) or they don't, and it's a mathematical question which is the case. You'll be mathematically justified in assuming Con(PA) in the former case. In the latter case, there are contexts where "assuming Con(PA)" is mathematically justified -- for example, if you're trying to prove a statement of the form $Con(PA) Rightarrow P$ for some $P$, then you're allowed to argue by assuming Con(PA) and proving $P$. But probably that's not what you mean.


  • If you're just asserting "PA is consistent" in a non-mathematical context, then your statement requires some philosophical unpacking to make precise, and moreover to determine to what extent it is justified. In this sense, it's a philosophical statement.



What principles lead us to believe that "Universes" is a safe assumption, whereas "¬Con(PA)" is not safe, regarding what we believe is "true" arithmetic?




There is an extensive philosophical literature discussing justifications for large cardinal axioms. You might start here. I'm not an expert, but I'm not aware of arguments which specifically argue that one should accept the arithmetic consequences of large cardinal axioms without arguing that one should accept the axioms outright. I would be interested to see such an argument. I once asked this question with related motivations.




(Next, repeat this question regarding the axiom of power set.)




Restrictions on powersets are studied in predicative mathematics. For some discussion of predicativism, one might start here or here. For some arguments for impredicativism, one might start here.




Is any theory that interprets PA "safe", as long as it is consistent with PA, and PA+Con(PA), and any such natural extension of these ideas?




By "safe", I take it that you continue to mean that the theory's arithmetic consequences are "true". There is a large body of literature discussing truth in mathematics. You seem to be particularly interested in the hierarchy obtained by passing from $T$ to $T + Con(T)$ iteratively. This hierarchy appears to be discussed from a philosophical perspective here. I think most logicians would probably agree that ascending this hierarchy adds relatively little consistency strength. And I'm not aware of serious attacks on the common-sense idea that if one believes $T$ is true, then one should also believe that $T + Con(T)$ is true.




Again, I'm not an expert, but it seems to me that most of the time when trying to justify stronger axioms from weaker assumptions, one appeals to some sort of reflection principle. This concept seems to be relevant to several of the questions you're asking.






share|cite|improve this answer











$endgroup$












  • $begingroup$
    Regarding your second-to-last paragraph, on "truth" in mathematics, how would you interpret the wikipedia article on Goodstein's Theorem, as it asserts that this is "a true statement that is unprovable in Peano arithmetic". What do they mean by "true" in this context? I think my comment about "safe" means "consistent with anything that we naturally would take to be true"---but I'm also a little confused at what things we take to be true!
    $endgroup$
    – Pace Nielsen
    4 hours ago










  • $begingroup$
    That statement makes sense if you don't read too much into it: if a statement is provable in ZFC, then it's standard mathematical practice to regard it as true. So the statement isn't that different from saying "Goodstein's theorem is a theorem of ZFC but not of PA". (Of course, Goodstein's theorem can presumably be proven using less than the full strength of ZFC, but that's beside the point.)
    $endgroup$
    – Tim Campion
    1 hour ago














2












2








2





$begingroup$

There's a lot going on in this question; let's break it down:




Is the assumption Con(PA) a philosophical one, and not a mathematical one?




I suppose it depends on what you mean by "the assumption Con(PA)":



  • If you're writing a mathematical proof, then either the foundations you're assuming prove Con(PA) or they don't, and it's a mathematical question which is the case. You'll be mathematically justified in assuming Con(PA) in the former case. In the latter case, there are contexts where "assuming Con(PA)" is mathematically justified -- for example, if you're trying to prove a statement of the form $Con(PA) Rightarrow P$ for some $P$, then you're allowed to argue by assuming Con(PA) and proving $P$. But probably that's not what you mean.


  • If you're just asserting "PA is consistent" in a non-mathematical context, then your statement requires some philosophical unpacking to make precise, and moreover to determine to what extent it is justified. In this sense, it's a philosophical statement.



What principles lead us to believe that "Universes" is a safe assumption, whereas "¬Con(PA)" is not safe, regarding what we believe is "true" arithmetic?




There is an extensive philosophical literature discussing justifications for large cardinal axioms. You might start here. I'm not an expert, but I'm not aware of arguments which specifically argue that one should accept the arithmetic consequences of large cardinal axioms without arguing that one should accept the axioms outright. I would be interested to see such an argument. I once asked this question with related motivations.




(Next, repeat this question regarding the axiom of power set.)




Restrictions on powersets are studied in predicative mathematics. For some discussion of predicativism, one might start here or here. For some arguments for impredicativism, one might start here.




Is any theory that interprets PA "safe", as long as it is consistent with PA, and PA+Con(PA), and any such natural extension of these ideas?




By "safe", I take it that you continue to mean that the theory's arithmetic consequences are "true". There is a large body of literature discussing truth in mathematics. You seem to be particularly interested in the hierarchy obtained by passing from $T$ to $T + Con(T)$ iteratively. This hierarchy appears to be discussed from a philosophical perspective here. I think most logicians would probably agree that ascending this hierarchy adds relatively little consistency strength. And I'm not aware of serious attacks on the common-sense idea that if one believes $T$ is true, then one should also believe that $T + Con(T)$ is true.




Again, I'm not an expert, but it seems to me that most of the time when trying to justify stronger axioms from weaker assumptions, one appeals to some sort of reflection principle. This concept seems to be relevant to several of the questions you're asking.






share|cite|improve this answer











$endgroup$



There's a lot going on in this question; let's break it down:




Is the assumption Con(PA) a philosophical one, and not a mathematical one?




I suppose it depends on what you mean by "the assumption Con(PA)":



  • If you're writing a mathematical proof, then either the foundations you're assuming prove Con(PA) or they don't, and it's a mathematical question which is the case. You'll be mathematically justified in assuming Con(PA) in the former case. In the latter case, there are contexts where "assuming Con(PA)" is mathematically justified -- for example, if you're trying to prove a statement of the form $Con(PA) Rightarrow P$ for some $P$, then you're allowed to argue by assuming Con(PA) and proving $P$. But probably that's not what you mean.


  • If you're just asserting "PA is consistent" in a non-mathematical context, then your statement requires some philosophical unpacking to make precise, and moreover to determine to what extent it is justified. In this sense, it's a philosophical statement.



What principles lead us to believe that "Universes" is a safe assumption, whereas "¬Con(PA)" is not safe, regarding what we believe is "true" arithmetic?




There is an extensive philosophical literature discussing justifications for large cardinal axioms. You might start here. I'm not an expert, but I'm not aware of arguments which specifically argue that one should accept the arithmetic consequences of large cardinal axioms without arguing that one should accept the axioms outright. I would be interested to see such an argument. I once asked this question with related motivations.




(Next, repeat this question regarding the axiom of power set.)




Restrictions on powersets are studied in predicative mathematics. For some discussion of predicativism, one might start here or here. For some arguments for impredicativism, one might start here.




Is any theory that interprets PA "safe", as long as it is consistent with PA, and PA+Con(PA), and any such natural extension of these ideas?




By "safe", I take it that you continue to mean that the theory's arithmetic consequences are "true". There is a large body of literature discussing truth in mathematics. You seem to be particularly interested in the hierarchy obtained by passing from $T$ to $T + Con(T)$ iteratively. This hierarchy appears to be discussed from a philosophical perspective here. I think most logicians would probably agree that ascending this hierarchy adds relatively little consistency strength. And I'm not aware of serious attacks on the common-sense idea that if one believes $T$ is true, then one should also believe that $T + Con(T)$ is true.




Again, I'm not an expert, but it seems to me that most of the time when trying to justify stronger axioms from weaker assumptions, one appeals to some sort of reflection principle. This concept seems to be relevant to several of the questions you're asking.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited 6 hours ago

























answered 6 hours ago









Tim CampionTim Campion

16.1k457137




16.1k457137











  • $begingroup$
    Regarding your second-to-last paragraph, on "truth" in mathematics, how would you interpret the wikipedia article on Goodstein's Theorem, as it asserts that this is "a true statement that is unprovable in Peano arithmetic". What do they mean by "true" in this context? I think my comment about "safe" means "consistent with anything that we naturally would take to be true"---but I'm also a little confused at what things we take to be true!
    $endgroup$
    – Pace Nielsen
    4 hours ago










  • $begingroup$
    That statement makes sense if you don't read too much into it: if a statement is provable in ZFC, then it's standard mathematical practice to regard it as true. So the statement isn't that different from saying "Goodstein's theorem is a theorem of ZFC but not of PA". (Of course, Goodstein's theorem can presumably be proven using less than the full strength of ZFC, but that's beside the point.)
    $endgroup$
    – Tim Campion
    1 hour ago

















  • $begingroup$
    Regarding your second-to-last paragraph, on "truth" in mathematics, how would you interpret the wikipedia article on Goodstein's Theorem, as it asserts that this is "a true statement that is unprovable in Peano arithmetic". What do they mean by "true" in this context? I think my comment about "safe" means "consistent with anything that we naturally would take to be true"---but I'm also a little confused at what things we take to be true!
    $endgroup$
    – Pace Nielsen
    4 hours ago










  • $begingroup$
    That statement makes sense if you don't read too much into it: if a statement is provable in ZFC, then it's standard mathematical practice to regard it as true. So the statement isn't that different from saying "Goodstein's theorem is a theorem of ZFC but not of PA". (Of course, Goodstein's theorem can presumably be proven using less than the full strength of ZFC, but that's beside the point.)
    $endgroup$
    – Tim Campion
    1 hour ago
















$begingroup$
Regarding your second-to-last paragraph, on "truth" in mathematics, how would you interpret the wikipedia article on Goodstein's Theorem, as it asserts that this is "a true statement that is unprovable in Peano arithmetic". What do they mean by "true" in this context? I think my comment about "safe" means "consistent with anything that we naturally would take to be true"---but I'm also a little confused at what things we take to be true!
$endgroup$
– Pace Nielsen
4 hours ago




$begingroup$
Regarding your second-to-last paragraph, on "truth" in mathematics, how would you interpret the wikipedia article on Goodstein's Theorem, as it asserts that this is "a true statement that is unprovable in Peano arithmetic". What do they mean by "true" in this context? I think my comment about "safe" means "consistent with anything that we naturally would take to be true"---but I'm also a little confused at what things we take to be true!
$endgroup$
– Pace Nielsen
4 hours ago












$begingroup$
That statement makes sense if you don't read too much into it: if a statement is provable in ZFC, then it's standard mathematical practice to regard it as true. So the statement isn't that different from saying "Goodstein's theorem is a theorem of ZFC but not of PA". (Of course, Goodstein's theorem can presumably be proven using less than the full strength of ZFC, but that's beside the point.)
$endgroup$
– Tim Campion
1 hour ago





$begingroup$
That statement makes sense if you don't read too much into it: if a statement is provable in ZFC, then it's standard mathematical practice to regard it as true. So the statement isn't that different from saying "Goodstein's theorem is a theorem of ZFC but not of PA". (Of course, Goodstein's theorem can presumably be proven using less than the full strength of ZFC, but that's beside the point.)
$endgroup$
– Tim Campion
1 hour ago


















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