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Why is this int array not passed as an object vararg array?

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6

I used this code. I am confused why this int array is not converted to an object vararg argument:

class MyClass 
 static void print(Object... obj) 
 System.out.println("Object…: " + obj[0]);
 

 public static void main(String[] args) 
 int[] array = new int[] 9, 1, 1;
 print(array);
 System.out.println(array instanceof Object);
 

I expected the output:

Object…: 9
true

but it gives:

Object…: [I@140e19d
true

java

share|improve this question

edited 4 mins ago

Boann

37.8k1291123

asked 3 hours ago

JoeCrayonJoeCrayon

442

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  The issue is that Object... means Object[] and int[] can not be converted to Object[] (int is a primitive, not an Object). However, the int[] array itself can be interpreted as Object. So you end up passing an object array Object[] with exactly one element in it, an int[]. So you have an array of arrays.
  
  – Zabuza
  2 hours ago
  
  

  
  
  
  

add a comment | 

6

I used this code. I am confused why this int array is not converted to an object vararg argument:

class MyClass 
 static void print(Object... obj) 
 System.out.println("Object…: " + obj[0]);
 

 public static void main(String[] args) 
 int[] array = new int[] 9, 1, 1;
 print(array);
 System.out.println(array instanceof Object);
 

I expected the output:

Object…: 9
true

but it gives:

Object…: [I@140e19d
true

java

share|improve this question

edited 4 mins ago

Boann

37.8k1291123

asked 3 hours ago

JoeCrayonJoeCrayon

442

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  The issue is that Object... means Object[] and int[] can not be converted to Object[] (int is a primitive, not an Object). However, the int[] array itself can be interpreted as Object. So you end up passing an object array Object[] with exactly one element in it, an int[]. So you have an array of arrays.
  
  – Zabuza
  2 hours ago
  
  

  
  
  
  

add a comment | 

I used this code. I am confused why this int array is not converted to an object vararg argument:

class MyClass 
 static void print(Object... obj) 
 System.out.println("Object…: " + obj[0]);
 

 public static void main(String[] args) 
 int[] array = new int[] 9, 1, 1;
 print(array);
 System.out.println(array instanceof Object);
 

I expected the output:

Object…: 9
true

but it gives:

Object…: [I@140e19d
true

java

share|improve this question

edited 4 mins ago

Boann

37.8k1291123

asked 3 hours ago

JoeCrayonJoeCrayon

442

class MyClass 
 static void print(Object... obj) 
 System.out.println("Object…: " + obj[0]);
 

 public static void main(String[] args) 
 int[] array = new int[] 9, 1, 1;
 print(array);
 System.out.println(array instanceof Object);
 

Object…: 9
true

Object…: [I@140e19d
true

share|improve this question

edited 4 mins ago

Boann

37.8k1291123

asked 3 hours ago

JoeCrayonJoeCrayon

442

share|improve this question

edited 4 mins ago

Boann

37.8k1291123

asked 3 hours ago

JoeCrayonJoeCrayon

442

edited 4 mins ago

Boann

37.8k1291123

edited 4 mins ago

Boann

37.8k1291123

asked 3 hours ago

JoeCrayonJoeCrayon

442

asked 3 hours ago

JoeCrayonJoeCrayon

442

2 Answers
2

active

oldest

votes

8

You're running into an edge case where objects and primitives don't work as expected.
The problem is that the actual code ends up expecting static void print(Object[]), but int[] cannot be cast to Object[]. However it can be cast to Object, resulting in the following executed code: print(new int[][]array).

You get the behavior you expect by using an object-based array like Integer[] instead of int[].

share|improve this answer

answered 3 hours ago

KiskaeKiskae

14.1k13242

add a comment | 

4

The reason for this is that an int array cannot be casted to an Object array implicitly. So you actually end up passing the int array as the first element of the Object array.

You could get the expected output without changing your main method and without changing the parameters if you do it like this:

static void print(Object... obj) 
 System.out.println("Object…: " + ((int[]) obj[0])[0]);

Output:

Object…: 9
true

share|improve this answer

edited 2 hours ago

answered 3 hours ago

ruoholaruohola

3,1802634

add a comment | 

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8

You're running into an edge case where objects and primitives don't work as expected.
The problem is that the actual code ends up expecting static void print(Object[]), but int[] cannot be cast to Object[]. However it can be cast to Object, resulting in the following executed code: print(new int[][]array).

You get the behavior you expect by using an object-based array like Integer[] instead of int[].

share|improve this answer

answered 3 hours ago

KiskaeKiskae

14.1k13242

add a comment | 

8

You're running into an edge case where objects and primitives don't work as expected.
The problem is that the actual code ends up expecting static void print(Object[]), but int[] cannot be cast to Object[]. However it can be cast to Object, resulting in the following executed code: print(new int[][]array).

You get the behavior you expect by using an object-based array like Integer[] instead of int[].

share|improve this answer

answered 3 hours ago

KiskaeKiskae

14.1k13242

add a comment | 

You're running into an edge case where objects and primitives don't work as expected.
The problem is that the actual code ends up expecting static void print(Object[]), but int[] cannot be cast to Object[]. However it can be cast to Object, resulting in the following executed code: print(new int[][]array).

You get the behavior you expect by using an object-based array like Integer[] instead of int[].

share|improve this answer

answered 3 hours ago

KiskaeKiskae

14.1k13242

share|improve this answer

answered 3 hours ago

KiskaeKiskae

14.1k13242

answered 3 hours ago

KiskaeKiskae

14.1k13242

answered 3 hours ago

KiskaeKiskae

14.1k13242

4

The reason for this is that an int array cannot be casted to an Object array implicitly. So you actually end up passing the int array as the first element of the Object array.

You could get the expected output without changing your main method and without changing the parameters if you do it like this:

static void print(Object... obj) 
 System.out.println("Object…: " + ((int[]) obj[0])[0]);

Output:

Object…: 9
true

share|improve this answer

edited 2 hours ago

answered 3 hours ago

ruoholaruohola

3,1802634

add a comment | 

4

The reason for this is that an int array cannot be casted to an Object array implicitly. So you actually end up passing the int array as the first element of the Object array.

You could get the expected output without changing your main method and without changing the parameters if you do it like this:

static void print(Object... obj) 
 System.out.println("Object…: " + ((int[]) obj[0])[0]);

Output:

Object…: 9
true

share|improve this answer

edited 2 hours ago

answered 3 hours ago

ruoholaruohola

3,1802634

add a comment | 

The reason for this is that an int array cannot be casted to an Object array implicitly. So you actually end up passing the int array as the first element of the Object array.

You could get the expected output without changing your main method and without changing the parameters if you do it like this:

static void print(Object... obj) 
 System.out.println("Object…: " + ((int[]) obj[0])[0]);

Output:

Object…: 9
true

share|improve this answer

edited 2 hours ago

answered 3 hours ago

ruoholaruohola

3,1802634

static void print(Object... obj) 
 System.out.println("Object…: " + ((int[]) obj[0])[0]);

share|improve this answer

edited 2 hours ago

answered 3 hours ago

ruoholaruohola

3,1802634

answered 3 hours ago

ruoholaruohola

3,1802634

answered 3 hours ago

ruoholaruohola

3,1802634