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How to define command with 2 optional params such that it calls another command (accepting 1 optional param) to which it passes one of those 2 params?


Conditionals in newcommandPass key option inside a macro to a TikZ drawing commandWrite a command that dynamically calls the argument of another commandHow do you define one macro with arguments inside anothercustom hatching pattern : arbitrary direction of hatchingHow to define such a command with an optional argument in my class?How to define a command that defines another command?How to define a newcommand that expands into another newcommandDefine latex command in which argument is part of another commandHow to define a command with two optional arguments?













1















documentclassstandalone

usepackagetikz

newcountermyC

newcommandmyN % I need optional parameter here which is set to zero by default and which will replace zero below
thenumexpr(valuemyC-0)

% command below should accept 2 optional parameters (one of which is already defined as "north" but can contain other values, like "south")
newcommandmyL[1][north]
% I need to be able to call myN here either without parameter (like below), which will make it default to predefined value (of zero) or to call it with a value supplied by the user)
path[draw=red](myN.#1 west)--(myN.#1 east);


begindocument
begintikzpicture
path node[draw,/utils/exec=stepcountermyC](1)one;
myL
path node[draw,/utils/exec=stepcountermyC](2)two;
myL
endtikzpicture
enddocument



EDIT (for @Red-Cloud):



I can do



newcommandmyN[1]thenumexpr(valuemyC-#1)
NewDocumentCommandmyTO0Onorthpath[draw=red](myN0.west)--(1,0);


but as soon as myN is rewritten to allow for an optional argument, it doesn't work



newcommandmyN[1][0]thenumexpr(valuemyC-#1)
% square brackets now instead of curly braces
NewDocumentCommandmyTO0Onorthpath[draw=red](myN[0].west)--(1,0);


Why is that? I need myN to accept an optional arg.










share|improve this question
























  • I'm not quite understanding. I see how myL has one optional parameter, and can be called by myL or myL[south]. How does the other optional parameter fit in? How do you intend to call myL?

    – Teepeemm
    2 hours ago











  • path[draw=red](myN.#1 west)--(myN.#1 east); makes no sense here because it doesn't use the second optional parameter #2 (default north)

    – Red-Cloud
    1 hour ago















1















documentclassstandalone

usepackagetikz

newcountermyC

newcommandmyN % I need optional parameter here which is set to zero by default and which will replace zero below
thenumexpr(valuemyC-0)

% command below should accept 2 optional parameters (one of which is already defined as "north" but can contain other values, like "south")
newcommandmyL[1][north]
% I need to be able to call myN here either without parameter (like below), which will make it default to predefined value (of zero) or to call it with a value supplied by the user)
path[draw=red](myN.#1 west)--(myN.#1 east);


begindocument
begintikzpicture
path node[draw,/utils/exec=stepcountermyC](1)one;
myL
path node[draw,/utils/exec=stepcountermyC](2)two;
myL
endtikzpicture
enddocument



EDIT (for @Red-Cloud):



I can do



newcommandmyN[1]thenumexpr(valuemyC-#1)
NewDocumentCommandmyTO0Onorthpath[draw=red](myN0.west)--(1,0);


but as soon as myN is rewritten to allow for an optional argument, it doesn't work



newcommandmyN[1][0]thenumexpr(valuemyC-#1)
% square brackets now instead of curly braces
NewDocumentCommandmyTO0Onorthpath[draw=red](myN[0].west)--(1,0);


Why is that? I need myN to accept an optional arg.










share|improve this question
























  • I'm not quite understanding. I see how myL has one optional parameter, and can be called by myL or myL[south]. How does the other optional parameter fit in? How do you intend to call myL?

    – Teepeemm
    2 hours ago











  • path[draw=red](myN.#1 west)--(myN.#1 east); makes no sense here because it doesn't use the second optional parameter #2 (default north)

    – Red-Cloud
    1 hour ago













1












1








1








documentclassstandalone

usepackagetikz

newcountermyC

newcommandmyN % I need optional parameter here which is set to zero by default and which will replace zero below
thenumexpr(valuemyC-0)

% command below should accept 2 optional parameters (one of which is already defined as "north" but can contain other values, like "south")
newcommandmyL[1][north]
% I need to be able to call myN here either without parameter (like below), which will make it default to predefined value (of zero) or to call it with a value supplied by the user)
path[draw=red](myN.#1 west)--(myN.#1 east);


begindocument
begintikzpicture
path node[draw,/utils/exec=stepcountermyC](1)one;
myL
path node[draw,/utils/exec=stepcountermyC](2)two;
myL
endtikzpicture
enddocument



EDIT (for @Red-Cloud):



I can do



newcommandmyN[1]thenumexpr(valuemyC-#1)
NewDocumentCommandmyTO0Onorthpath[draw=red](myN0.west)--(1,0);


but as soon as myN is rewritten to allow for an optional argument, it doesn't work



newcommandmyN[1][0]thenumexpr(valuemyC-#1)
% square brackets now instead of curly braces
NewDocumentCommandmyTO0Onorthpath[draw=red](myN[0].west)--(1,0);


Why is that? I need myN to accept an optional arg.










share|improve this question
















documentclassstandalone

usepackagetikz

newcountermyC

newcommandmyN % I need optional parameter here which is set to zero by default and which will replace zero below
thenumexpr(valuemyC-0)

% command below should accept 2 optional parameters (one of which is already defined as "north" but can contain other values, like "south")
newcommandmyL[1][north]
% I need to be able to call myN here either without parameter (like below), which will make it default to predefined value (of zero) or to call it with a value supplied by the user)
path[draw=red](myN.#1 west)--(myN.#1 east);


begindocument
begintikzpicture
path node[draw,/utils/exec=stepcountermyC](1)one;
myL
path node[draw,/utils/exec=stepcountermyC](2)two;
myL
endtikzpicture
enddocument



EDIT (for @Red-Cloud):



I can do



newcommandmyN[1]thenumexpr(valuemyC-#1)
NewDocumentCommandmyTO0Onorthpath[draw=red](myN0.west)--(1,0);


but as soon as myN is rewritten to allow for an optional argument, it doesn't work



newcommandmyN[1][0]thenumexpr(valuemyC-#1)
% square brackets now instead of curly braces
NewDocumentCommandmyTO0Onorthpath[draw=red](myN[0].west)--(1,0);


Why is that? I need myN to accept an optional arg.







macros






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 18 mins ago







bp2017

















asked 4 hours ago









bp2017bp2017

879114




879114












  • I'm not quite understanding. I see how myL has one optional parameter, and can be called by myL or myL[south]. How does the other optional parameter fit in? How do you intend to call myL?

    – Teepeemm
    2 hours ago











  • path[draw=red](myN.#1 west)--(myN.#1 east); makes no sense here because it doesn't use the second optional parameter #2 (default north)

    – Red-Cloud
    1 hour ago

















  • I'm not quite understanding. I see how myL has one optional parameter, and can be called by myL or myL[south]. How does the other optional parameter fit in? How do you intend to call myL?

    – Teepeemm
    2 hours ago











  • path[draw=red](myN.#1 west)--(myN.#1 east); makes no sense here because it doesn't use the second optional parameter #2 (default north)

    – Red-Cloud
    1 hour ago
















I'm not quite understanding. I see how myL has one optional parameter, and can be called by myL or myL[south]. How does the other optional parameter fit in? How do you intend to call myL?

– Teepeemm
2 hours ago





I'm not quite understanding. I see how myL has one optional parameter, and can be called by myL or myL[south]. How does the other optional parameter fit in? How do you intend to call myL?

– Teepeemm
2 hours ago













path[draw=red](myN.#1 west)--(myN.#1 east); makes no sense here because it doesn't use the second optional parameter #2 (default north)

– Red-Cloud
1 hour ago





path[draw=red](myN.#1 west)--(myN.#1 east); makes no sense here because it doesn't use the second optional parameter #2 (default north)

– Red-Cloud
1 hour ago










2 Answers
2






active

oldest

votes


















1














newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax

usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
path[draw=red](myN.#1 west)--(myN.#1 east);%



But makes no real sense in your example






share|improve this answer























  • Please check EDIT part (on the bottom) in my question.

    – bp2017
    17 mins ago


















1














It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:



 documentclass[tikz, border=5mm]standalone
usepackagexparse

newcountermyC
NewDocumentCommandmyLOnorth O0%
defmyCthenumexpr(themyC-#2)
path[draw=red](myC.#1 west)--(myC.#1 east);


begindocument
begintikzpicture[mystep/.code=stepcountermyC]
path node[draw,mystep](1)at (themyC,0)one;
myL
path node[draw,mystep](2)at (themyC,0)two;
myL
endtikzpicture
enddocument


Here is the output:



enter image description here



Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.






share|improve this answer























  • I need newcommand which you removed. I also use it for other means.

    – bp2017
    11 mins ago











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax

usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
path[draw=red](myN.#1 west)--(myN.#1 east);%



But makes no real sense in your example






share|improve this answer























  • Please check EDIT part (on the bottom) in my question.

    – bp2017
    17 mins ago















1














newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax

usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
path[draw=red](myN.#1 west)--(myN.#1 east);%



But makes no real sense in your example






share|improve this answer























  • Please check EDIT part (on the bottom) in my question.

    – bp2017
    17 mins ago













1












1








1







newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax

usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
path[draw=red](myN.#1 west)--(myN.#1 east);%



But makes no real sense in your example






share|improve this answer













newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax

usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
path[draw=red](myN.#1 west)--(myN.#1 east);%



But makes no real sense in your example







share|improve this answer












share|improve this answer



share|improve this answer










answered 1 hour ago









Red-CloudRed-Cloud

1,61911




1,61911












  • Please check EDIT part (on the bottom) in my question.

    – bp2017
    17 mins ago

















  • Please check EDIT part (on the bottom) in my question.

    – bp2017
    17 mins ago
















Please check EDIT part (on the bottom) in my question.

– bp2017
17 mins ago





Please check EDIT part (on the bottom) in my question.

– bp2017
17 mins ago











1














It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:



 documentclass[tikz, border=5mm]standalone
usepackagexparse

newcountermyC
NewDocumentCommandmyLOnorth O0%
defmyCthenumexpr(themyC-#2)
path[draw=red](myC.#1 west)--(myC.#1 east);


begindocument
begintikzpicture[mystep/.code=stepcountermyC]
path node[draw,mystep](1)at (themyC,0)one;
myL
path node[draw,mystep](2)at (themyC,0)two;
myL
endtikzpicture
enddocument


Here is the output:



enter image description here



Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.






share|improve this answer























  • I need newcommand which you removed. I also use it for other means.

    – bp2017
    11 mins ago















1














It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:



 documentclass[tikz, border=5mm]standalone
usepackagexparse

newcountermyC
NewDocumentCommandmyLOnorth O0%
defmyCthenumexpr(themyC-#2)
path[draw=red](myC.#1 west)--(myC.#1 east);


begindocument
begintikzpicture[mystep/.code=stepcountermyC]
path node[draw,mystep](1)at (themyC,0)one;
myL
path node[draw,mystep](2)at (themyC,0)two;
myL
endtikzpicture
enddocument


Here is the output:



enter image description here



Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.






share|improve this answer























  • I need newcommand which you removed. I also use it for other means.

    – bp2017
    11 mins ago













1












1








1







It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:



 documentclass[tikz, border=5mm]standalone
usepackagexparse

newcountermyC
NewDocumentCommandmyLOnorth O0%
defmyCthenumexpr(themyC-#2)
path[draw=red](myC.#1 west)--(myC.#1 east);


begindocument
begintikzpicture[mystep/.code=stepcountermyC]
path node[draw,mystep](1)at (themyC,0)one;
myL
path node[draw,mystep](2)at (themyC,0)two;
myL
endtikzpicture
enddocument


Here is the output:



enter image description here



Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.






share|improve this answer













It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:



 documentclass[tikz, border=5mm]standalone
usepackagexparse

newcountermyC
NewDocumentCommandmyLOnorth O0%
defmyCthenumexpr(themyC-#2)
path[draw=red](myC.#1 west)--(myC.#1 east);


begindocument
begintikzpicture[mystep/.code=stepcountermyC]
path node[draw,mystep](1)at (themyC,0)one;
myL
path node[draw,mystep](2)at (themyC,0)two;
myL
endtikzpicture
enddocument


Here is the output:



enter image description here



Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.







share|improve this answer












share|improve this answer



share|improve this answer










answered 1 hour ago









AndrewAndrew

32.5k34684




32.5k34684












  • I need newcommand which you removed. I also use it for other means.

    – bp2017
    11 mins ago

















  • I need newcommand which you removed. I also use it for other means.

    – bp2017
    11 mins ago
















I need newcommand which you removed. I also use it for other means.

– bp2017
11 mins ago





I need newcommand which you removed. I also use it for other means.

– bp2017
11 mins ago

















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