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How do I make a function that generates nth natural number that isn't a perfect square?


Convergent subsequencesHow to find a “better description” (e.g. recurrence relation) for this sequence?Determine the value for which a sequence is an arithmetic progression.Convergence of a sequence in a Hilbert space2-cycles and limitsFind a recursive definition for the sequencesMonotonicity of $fracnsqrt[n](n!)$$2021^textst$ term of a SequenceGetting a specific element of a non-recursive sequenceHow to calculate the general formula for nth term of this recursion?













1












$begingroup$


So I want to make a function such that for every n that you input it generates nth natural number that isn't a perfect square, like 2, 3, 5,...? I tried recurrance relation and I can't seem to find the proper relation between the members of sequence. Then I tried making a function but I don't know what to use actually... Any help?










share|cite|improve this question









$endgroup$
















    1












    $begingroup$


    So I want to make a function such that for every n that you input it generates nth natural number that isn't a perfect square, like 2, 3, 5,...? I tried recurrance relation and I can't seem to find the proper relation between the members of sequence. Then I tried making a function but I don't know what to use actually... Any help?










    share|cite|improve this question









    $endgroup$














      1












      1








      1


      1



      $begingroup$


      So I want to make a function such that for every n that you input it generates nth natural number that isn't a perfect square, like 2, 3, 5,...? I tried recurrance relation and I can't seem to find the proper relation between the members of sequence. Then I tried making a function but I don't know what to use actually... Any help?










      share|cite|improve this question









      $endgroup$




      So I want to make a function such that for every n that you input it generates nth natural number that isn't a perfect square, like 2, 3, 5,...? I tried recurrance relation and I can't seem to find the proper relation between the members of sequence. Then I tried making a function but I don't know what to use actually... Any help?







      sequences-and-series roots






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked 3 hours ago









      Adnan CAdnan C

      335




      335




















          2 Answers
          2






          active

          oldest

          votes


















          6












          $begingroup$

          OEIS to the rescue.



          It gives the formula
          $$
          n+leftlfloorfrac12+sqrt nrightrfloor.
          $$

          where $lfloorcdotrfloor$ is the floor function.






          share|cite|improve this answer









          $endgroup$




















            0












            $begingroup$

            Let $Bbb N = 1,2,3,dots$.



            Let $pi_1$ and $pi_2$ be the two coordinate projection mappings on $Bbb N times Bbb N$.



            We will define a function $f$ using recursion.



            Define $f(1) = (2,2)$.



            For $n ge 1$ define



            $$
            f(n+1) = leftbeginarraylr
            left ( , pi_1(f(n)) + 1 ,pi_2(f(n)), right ) & textwhen pi_1(f(n)) + 1 lt [pi_2(f(n))]^2 \
            left ( , pi_1(f(n)) + 2 ,pi_2(f(n))+1 , right ) & textelse
            endarrayright
            $$



            The function $pi_1 circ f$ has the desired properties.






            share|cite|improve this answer











            $endgroup$













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              2 Answers
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              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              6












              $begingroup$

              OEIS to the rescue.



              It gives the formula
              $$
              n+leftlfloorfrac12+sqrt nrightrfloor.
              $$

              where $lfloorcdotrfloor$ is the floor function.






              share|cite|improve this answer









              $endgroup$

















                6












                $begingroup$

                OEIS to the rescue.



                It gives the formula
                $$
                n+leftlfloorfrac12+sqrt nrightrfloor.
                $$

                where $lfloorcdotrfloor$ is the floor function.






                share|cite|improve this answer









                $endgroup$















                  6












                  6








                  6





                  $begingroup$

                  OEIS to the rescue.



                  It gives the formula
                  $$
                  n+leftlfloorfrac12+sqrt nrightrfloor.
                  $$

                  where $lfloorcdotrfloor$ is the floor function.






                  share|cite|improve this answer









                  $endgroup$



                  OEIS to the rescue.



                  It gives the formula
                  $$
                  n+leftlfloorfrac12+sqrt nrightrfloor.
                  $$

                  where $lfloorcdotrfloor$ is the floor function.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered 3 hours ago









                  ArthurArthur

                  124k7122211




                  124k7122211





















                      0












                      $begingroup$

                      Let $Bbb N = 1,2,3,dots$.



                      Let $pi_1$ and $pi_2$ be the two coordinate projection mappings on $Bbb N times Bbb N$.



                      We will define a function $f$ using recursion.



                      Define $f(1) = (2,2)$.



                      For $n ge 1$ define



                      $$
                      f(n+1) = leftbeginarraylr
                      left ( , pi_1(f(n)) + 1 ,pi_2(f(n)), right ) & textwhen pi_1(f(n)) + 1 lt [pi_2(f(n))]^2 \
                      left ( , pi_1(f(n)) + 2 ,pi_2(f(n))+1 , right ) & textelse
                      endarrayright
                      $$



                      The function $pi_1 circ f$ has the desired properties.






                      share|cite|improve this answer











                      $endgroup$

















                        0












                        $begingroup$

                        Let $Bbb N = 1,2,3,dots$.



                        Let $pi_1$ and $pi_2$ be the two coordinate projection mappings on $Bbb N times Bbb N$.



                        We will define a function $f$ using recursion.



                        Define $f(1) = (2,2)$.



                        For $n ge 1$ define



                        $$
                        f(n+1) = leftbeginarraylr
                        left ( , pi_1(f(n)) + 1 ,pi_2(f(n)), right ) & textwhen pi_1(f(n)) + 1 lt [pi_2(f(n))]^2 \
                        left ( , pi_1(f(n)) + 2 ,pi_2(f(n))+1 , right ) & textelse
                        endarrayright
                        $$



                        The function $pi_1 circ f$ has the desired properties.






                        share|cite|improve this answer











                        $endgroup$















                          0












                          0








                          0





                          $begingroup$

                          Let $Bbb N = 1,2,3,dots$.



                          Let $pi_1$ and $pi_2$ be the two coordinate projection mappings on $Bbb N times Bbb N$.



                          We will define a function $f$ using recursion.



                          Define $f(1) = (2,2)$.



                          For $n ge 1$ define



                          $$
                          f(n+1) = leftbeginarraylr
                          left ( , pi_1(f(n)) + 1 ,pi_2(f(n)), right ) & textwhen pi_1(f(n)) + 1 lt [pi_2(f(n))]^2 \
                          left ( , pi_1(f(n)) + 2 ,pi_2(f(n))+1 , right ) & textelse
                          endarrayright
                          $$



                          The function $pi_1 circ f$ has the desired properties.






                          share|cite|improve this answer











                          $endgroup$



                          Let $Bbb N = 1,2,3,dots$.



                          Let $pi_1$ and $pi_2$ be the two coordinate projection mappings on $Bbb N times Bbb N$.



                          We will define a function $f$ using recursion.



                          Define $f(1) = (2,2)$.



                          For $n ge 1$ define



                          $$
                          f(n+1) = leftbeginarraylr
                          left ( , pi_1(f(n)) + 1 ,pi_2(f(n)), right ) & textwhen pi_1(f(n)) + 1 lt [pi_2(f(n))]^2 \
                          left ( , pi_1(f(n)) + 2 ,pi_2(f(n))+1 , right ) & textelse
                          endarrayright
                          $$



                          The function $pi_1 circ f$ has the desired properties.







                          share|cite|improve this answer














                          share|cite|improve this answer



                          share|cite|improve this answer








                          edited 1 hour ago

























                          answered 1 hour ago









                          CopyPasteItCopyPasteIt

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                          4,4471828



























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