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Get consecutive integer number ranges from list of int


Converting from binary to unaryFinding the indices of the two items whose price adds up to to a valueHackerEarth - SimpleFunctionFollow-up 1: Compare 2 unordered, rooted trees for shape-isomorphismHackerrank: Max ScoreFilter data with optional parametersFour sum algorithm mock interview practiceAt least 2 paths down the binary tree have the same sumLeetcode 54: Spiral MatrixRecursive function challenge






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3












$begingroup$


This is an algorithm to return a list of consecutive integer ranges from a list of integers.



The practical use of such an algorithm is to filter lists more efficiently, i.e. rather than check e.g. 1000 items (1..1000; x==1 || x==2 || ... || x==1000), it might be possible to check only 2 items (x >= 1 && x <= 1000).



Does this algorithm have any mistakes, can it be optimized, or are there any other improvements you can suggest?



(As a side note: I know this code does not follow the standard C# naming conventions. I do not like to follow that particular convention; I prefer "snake_case" as it is easier on my eyes.)



Sample output:



(x >= 0 && x <= 1690)
(x >= 13642 && x <= 15331)
(x >= 27283 && x <= 27296)
(x >= 27769 && x <= 27776)
(x >= 28249 && x <= 28256)
(x >= 28729 && x <= 28736)
(x >= 29209 && x <= 29222)


The algorithm (built Visual Studio 2017, C# 7.3, .NET 4.7.2):



public static List<(int from, int to)> get_consecutive_ranges(List<int> fids)



Example use:



// slow:
body = body.Where(a => fids.Contains(a.fid)).ToList();

// fast:
body = body.Where(a => fids_fast.Any(x => a.fid >= x.from && a.fid <= x.to)).ToList();









share|improve this question









New contributor




Aalawlx is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 1




    $begingroup$
    @t3chb0t no I just dislike camel case as I personally find it to be quite difficult to read and thus more likely to cause eye strain. Thanks for your suggestion, I will add it to my question.
    $endgroup$
    – Aalawlx
    6 hours ago










  • $begingroup$
    One more suggestion... if you have any running demo console/unit-test code (which I strongly believe) then you should add it too. It'll make it easier to review your algorithm as people will be able to actually execute it.
    $endgroup$
    – t3chb0t
    5 hours ago






  • 1




    $begingroup$
    What does fids stand for? Would help me understand what your algorithm is doing better ( at least I would hope ).
    $endgroup$
    – Shelby115
    5 hours ago










  • $begingroup$
    @Shelby115 actually, your naming makes it more generic, which is good. However, to answer the question, fids means 'features ids'. The reason I am writing this method is to filter criteria-specific feature id numbers from millions of id numbers (integers). The actual use case is machine learning, classification specifically, where millions of features are available, but only a small subset can be used or tested together.
    $endgroup$
    – Aalawlx
    4 hours ago

















3












$begingroup$


This is an algorithm to return a list of consecutive integer ranges from a list of integers.



The practical use of such an algorithm is to filter lists more efficiently, i.e. rather than check e.g. 1000 items (1..1000; x==1 || x==2 || ... || x==1000), it might be possible to check only 2 items (x >= 1 && x <= 1000).



Does this algorithm have any mistakes, can it be optimized, or are there any other improvements you can suggest?



(As a side note: I know this code does not follow the standard C# naming conventions. I do not like to follow that particular convention; I prefer "snake_case" as it is easier on my eyes.)



Sample output:



(x >= 0 && x <= 1690)
(x >= 13642 && x <= 15331)
(x >= 27283 && x <= 27296)
(x >= 27769 && x <= 27776)
(x >= 28249 && x <= 28256)
(x >= 28729 && x <= 28736)
(x >= 29209 && x <= 29222)


The algorithm (built Visual Studio 2017, C# 7.3, .NET 4.7.2):



public static List<(int from, int to)> get_consecutive_ranges(List<int> fids)



Example use:



// slow:
body = body.Where(a => fids.Contains(a.fid)).ToList();

// fast:
body = body.Where(a => fids_fast.Any(x => a.fid >= x.from && a.fid <= x.to)).ToList();









share|improve this question









New contributor




Aalawlx is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 1




    $begingroup$
    @t3chb0t no I just dislike camel case as I personally find it to be quite difficult to read and thus more likely to cause eye strain. Thanks for your suggestion, I will add it to my question.
    $endgroup$
    – Aalawlx
    6 hours ago










  • $begingroup$
    One more suggestion... if you have any running demo console/unit-test code (which I strongly believe) then you should add it too. It'll make it easier to review your algorithm as people will be able to actually execute it.
    $endgroup$
    – t3chb0t
    5 hours ago






  • 1




    $begingroup$
    What does fids stand for? Would help me understand what your algorithm is doing better ( at least I would hope ).
    $endgroup$
    – Shelby115
    5 hours ago










  • $begingroup$
    @Shelby115 actually, your naming makes it more generic, which is good. However, to answer the question, fids means 'features ids'. The reason I am writing this method is to filter criteria-specific feature id numbers from millions of id numbers (integers). The actual use case is machine learning, classification specifically, where millions of features are available, but only a small subset can be used or tested together.
    $endgroup$
    – Aalawlx
    4 hours ago













3












3








3





$begingroup$


This is an algorithm to return a list of consecutive integer ranges from a list of integers.



The practical use of such an algorithm is to filter lists more efficiently, i.e. rather than check e.g. 1000 items (1..1000; x==1 || x==2 || ... || x==1000), it might be possible to check only 2 items (x >= 1 && x <= 1000).



Does this algorithm have any mistakes, can it be optimized, or are there any other improvements you can suggest?



(As a side note: I know this code does not follow the standard C# naming conventions. I do not like to follow that particular convention; I prefer "snake_case" as it is easier on my eyes.)



Sample output:



(x >= 0 && x <= 1690)
(x >= 13642 && x <= 15331)
(x >= 27283 && x <= 27296)
(x >= 27769 && x <= 27776)
(x >= 28249 && x <= 28256)
(x >= 28729 && x <= 28736)
(x >= 29209 && x <= 29222)


The algorithm (built Visual Studio 2017, C# 7.3, .NET 4.7.2):



public static List<(int from, int to)> get_consecutive_ranges(List<int> fids)



Example use:



// slow:
body = body.Where(a => fids.Contains(a.fid)).ToList();

// fast:
body = body.Where(a => fids_fast.Any(x => a.fid >= x.from && a.fid <= x.to)).ToList();









share|improve this question









New contributor




Aalawlx is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




This is an algorithm to return a list of consecutive integer ranges from a list of integers.



The practical use of such an algorithm is to filter lists more efficiently, i.e. rather than check e.g. 1000 items (1..1000; x==1 || x==2 || ... || x==1000), it might be possible to check only 2 items (x >= 1 && x <= 1000).



Does this algorithm have any mistakes, can it be optimized, or are there any other improvements you can suggest?



(As a side note: I know this code does not follow the standard C# naming conventions. I do not like to follow that particular convention; I prefer "snake_case" as it is easier on my eyes.)



Sample output:



(x >= 0 && x <= 1690)
(x >= 13642 && x <= 15331)
(x >= 27283 && x <= 27296)
(x >= 27769 && x <= 27776)
(x >= 28249 && x <= 28256)
(x >= 28729 && x <= 28736)
(x >= 29209 && x <= 29222)


The algorithm (built Visual Studio 2017, C# 7.3, .NET 4.7.2):



public static List<(int from, int to)> get_consecutive_ranges(List<int> fids)



Example use:



// slow:
body = body.Where(a => fids.Contains(a.fid)).ToList();

// fast:
body = body.Where(a => fids_fast.Any(x => a.fid >= x.from && a.fid <= x.to)).ToList();






c# algorithm interval






share|improve this question









New contributor




Aalawlx is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




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Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 37 mins ago









200_success

132k20158423




132k20158423






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Check out our Code of Conduct.









asked 6 hours ago









AalawlxAalawlx

1214




1214




New contributor




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Check out our Code of Conduct.





New contributor





Aalawlx is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Aalawlx is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







  • 1




    $begingroup$
    @t3chb0t no I just dislike camel case as I personally find it to be quite difficult to read and thus more likely to cause eye strain. Thanks for your suggestion, I will add it to my question.
    $endgroup$
    – Aalawlx
    6 hours ago










  • $begingroup$
    One more suggestion... if you have any running demo console/unit-test code (which I strongly believe) then you should add it too. It'll make it easier to review your algorithm as people will be able to actually execute it.
    $endgroup$
    – t3chb0t
    5 hours ago






  • 1




    $begingroup$
    What does fids stand for? Would help me understand what your algorithm is doing better ( at least I would hope ).
    $endgroup$
    – Shelby115
    5 hours ago










  • $begingroup$
    @Shelby115 actually, your naming makes it more generic, which is good. However, to answer the question, fids means 'features ids'. The reason I am writing this method is to filter criteria-specific feature id numbers from millions of id numbers (integers). The actual use case is machine learning, classification specifically, where millions of features are available, but only a small subset can be used or tested together.
    $endgroup$
    – Aalawlx
    4 hours ago












  • 1




    $begingroup$
    @t3chb0t no I just dislike camel case as I personally find it to be quite difficult to read and thus more likely to cause eye strain. Thanks for your suggestion, I will add it to my question.
    $endgroup$
    – Aalawlx
    6 hours ago










  • $begingroup$
    One more suggestion... if you have any running demo console/unit-test code (which I strongly believe) then you should add it too. It'll make it easier to review your algorithm as people will be able to actually execute it.
    $endgroup$
    – t3chb0t
    5 hours ago






  • 1




    $begingroup$
    What does fids stand for? Would help me understand what your algorithm is doing better ( at least I would hope ).
    $endgroup$
    – Shelby115
    5 hours ago










  • $begingroup$
    @Shelby115 actually, your naming makes it more generic, which is good. However, to answer the question, fids means 'features ids'. The reason I am writing this method is to filter criteria-specific feature id numbers from millions of id numbers (integers). The actual use case is machine learning, classification specifically, where millions of features are available, but only a small subset can be used or tested together.
    $endgroup$
    – Aalawlx
    4 hours ago







1




1




$begingroup$
@t3chb0t no I just dislike camel case as I personally find it to be quite difficult to read and thus more likely to cause eye strain. Thanks for your suggestion, I will add it to my question.
$endgroup$
– Aalawlx
6 hours ago




$begingroup$
@t3chb0t no I just dislike camel case as I personally find it to be quite difficult to read and thus more likely to cause eye strain. Thanks for your suggestion, I will add it to my question.
$endgroup$
– Aalawlx
6 hours ago












$begingroup$
One more suggestion... if you have any running demo console/unit-test code (which I strongly believe) then you should add it too. It'll make it easier to review your algorithm as people will be able to actually execute it.
$endgroup$
– t3chb0t
5 hours ago




$begingroup$
One more suggestion... if you have any running demo console/unit-test code (which I strongly believe) then you should add it too. It'll make it easier to review your algorithm as people will be able to actually execute it.
$endgroup$
– t3chb0t
5 hours ago




1




1




$begingroup$
What does fids stand for? Would help me understand what your algorithm is doing better ( at least I would hope ).
$endgroup$
– Shelby115
5 hours ago




$begingroup$
What does fids stand for? Would help me understand what your algorithm is doing better ( at least I would hope ).
$endgroup$
– Shelby115
5 hours ago












$begingroup$
@Shelby115 actually, your naming makes it more generic, which is good. However, to answer the question, fids means 'features ids'. The reason I am writing this method is to filter criteria-specific feature id numbers from millions of id numbers (integers). The actual use case is machine learning, classification specifically, where millions of features are available, but only a small subset can be used or tested together.
$endgroup$
– Aalawlx
4 hours ago




$begingroup$
@Shelby115 actually, your naming makes it more generic, which is good. However, to answer the question, fids means 'features ids'. The reason I am writing this method is to filter criteria-specific feature id numbers from millions of id numbers (integers). The actual use case is machine learning, classification specifically, where millions of features are available, but only a small subset can be used or tested together.
$endgroup$
– Aalawlx
4 hours ago










2 Answers
2






active

oldest

votes


















3












$begingroup$

As a pre-note, I had to translate everything to camelCase and PascalCase because I was having a very difficult time reading your code. No judgments, just understand I was running short on time and didn't translate it back on the conclusion.



Readability



Use meaningful names.




  • fids I changed to integers as from your description I gather it's the list of integers used to create the ranges.


  • fids_index seems very noisy. Standard convention is i, j, etc. When you reduce the iterator variable down to a single character it's much easier to focus on what actually matters.

  • Booleans should be prefixed with Is or Has or Was etc. So in this case IsFirst and IsLast instead of first and last makes it easier to read as english. You could even consider using var isNotFirst = i != 0; as you only use !first in the algorithm.

  • Last vs Previous. is_conseq_with_last is refering to previous, so I switched it to previous to avoid confusion with last.


  • start_index and end_index sound like they would be 0 and integers.Count. They're the start and end of the range you're tracking, let's name them accordingly: rangeStart and rangeEnd.

If-Statement Ordering & Flow



We've all been there, written an algorithm, tested it, and it works, all done right? Well, sometimes that algorithm can be restructured to express what we're actually doing much clearer.



 if (!first && fids[fids_index - 1] == fids[fids_index] - 1)

is_conseq_with_last = true;

else if (!first)

is_conseq_with_last = false;



There's a common denominator here, !first let's work with that, clearly neither of these happen if it's true.



if (!first)

if (fids[fids_index - 1] == fids[fids_index] - 1)

is_conseq_with_last = true;

else

is_conseq_with_last = false;




Well, now it's obvious that inner if-statement can be reduced.



if (!first)

is_conseq_with_last = fids[fids_index - 1] == fids[fids_index] - 1;



And if you wanted, a ternary operator.



is_conseq_with_last = !first && fids[fids_index - 1] == fids[fids_index] - 1;


And it's now also obvious that you're setting the variable with each iteration, so there's no need to declare it outside the loop.



Similar can be done with the bottom if-statement. Here's what I ended up with altogether.



My Version



I am running short on time so there might be a mistake or two and it's still in my coding style so don't take it for face value and try to apply the concepts I'm showing above yourself.



public static List<(int from, int to)> GetConsecutiveRanges(List<int> integers)
integers.Count == 0) return null;

integers = integers.OrderBy(a => a).Distinct().ToList();
var ranges = new List<(int from, int to)>();

var rangeStart = 0;
var rangeEnd = 0;

for (var i = 0; i < integers.Count; i++)

var isFirst = i == 0;
var isLast = i == integers.Count - 1;
var isConsecutiveFromPrevious = isFirst == false && integers[i-1] == integers[i] - 1;

if (last)

if (isConsecutiveFromPrevious == false)

rangeEnd = isFirst == false ? i - 1 : rangeEnd;
ranges.Add((integers[rangeStart], integers[rangeEnd]));
rangeStart = i;


rangeEnd = i;
ranges.Add((integers[rangeStart], integers[rangeEnd]));

else if (isConsecutiveFromPrevious == false && isFirst == false)

rangeEnd = isFirst == false && isLast == false ? i - 1 : i;
ranges.Add((integers[rangeStart], integers[rangeEnd]));
rangeStart = i;




ranges.ForEach(a => Console.WriteLine($"(x >= a.@from && x <= a.to)"));

return ranges;






share|improve this answer









$endgroup$












  • $begingroup$
    I wonder whether it would be more efficient to swap these two calls .OrderBy(a => a).Distinct().- just thinking aloud...
    $endgroup$
    – t3chb0t
    4 hours ago










  • $begingroup$
    @t3chb0t I had exactly the same thought, but in the end, both methods must track values, so performance must surely be similar either way around?
    $endgroup$
    – Aalawlx
    4 hours ago










  • $begingroup$
    @Shelby115 There are some very interesting points in your answer - thanks a lot.
    $endgroup$
    – Aalawlx
    4 hours ago



















1












$begingroup$

Your code is really complicated. First, your code should be abstracted a little more. It is not specific to feature IDs, therefore the terminology should not use these words. The same algorithm can be used to select which pages to print from a document, therefore the variables should be just nums and ranges. To test your current code, I wrote:



[Test]
public void TestRanges()

Assert.AreEqual("", Str(Ranges(new List<int>())));
Assert.AreEqual("1", Str(Ranges(new List<int> 1 )));
Assert.AreEqual("1-5", Str(Ranges(new List<int> 1, 2, 3, 4, 5 )));
Assert.AreEqual("1-3, 5", Str(Ranges(new List<int> 1, 2, 3, 5 )));
Assert.AreEqual("1, 3, 5-6", Str(Ranges(new List<int> 1, 3, 5, 6 )));



I wrote a helper function Str so that I don't have to construct a list of ranges for each test case:



public static string Str(List<(int from, int to)> ranges)

var parts = new List<string>();

foreach (var range in ranges)
if (range.from == range.to)
parts.Add(range.from.ToString());
else
parts.Add(range.@from + "-" + range.to);



return string.Join(", ", parts);



After renaming your function to Ranges, these tests ran successfully. So I was ready to refactor your code. I did not really do this since your code looked too complicated to start with. Instead, I remembered that I had successfully used the following pattern quite often:



var start = ...;
while (start < nums.Count)
var end = ...;
while (end < nums.Count)




With this knowledge I wrote the following code:



public static List<(int from, int to)> Ranges(List<int> nums)

nums = nums.OrderBy(a => a).Distinct().ToList();

var ranges = new List<(int from, int to)>();

var start = 0;
while (start < nums.Count)
var end = start + 1; // the range is from [start, end).

while (end < nums.Count && nums[end - 1] + 1 == nums[end])
end++;


ranges.Add((nums[start], nums[end - 1]));
start = end; // continue after the current range


return ranges;



This code doesn't need any special cases for the last range, or anything else. A range either stops when the end of the numbers is reached, or when the following number is not consecutive. This sounds sensible, and this is exactly what the code is doing.



I removed the check for nums == null since it is not necessary. Collections should never be null, and if they are, the code immediately throws an exception, which is fine.



I also removed the special case for nums.Count == 0 since returning an empty list is much better than returning null. Again, expressions that have collection type should never be null. The test cases cover this case, so there's nothing to worry about.






share|improve this answer











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    2 Answers
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    2 Answers
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    3












    $begingroup$

    As a pre-note, I had to translate everything to camelCase and PascalCase because I was having a very difficult time reading your code. No judgments, just understand I was running short on time and didn't translate it back on the conclusion.



    Readability



    Use meaningful names.




    • fids I changed to integers as from your description I gather it's the list of integers used to create the ranges.


    • fids_index seems very noisy. Standard convention is i, j, etc. When you reduce the iterator variable down to a single character it's much easier to focus on what actually matters.

    • Booleans should be prefixed with Is or Has or Was etc. So in this case IsFirst and IsLast instead of first and last makes it easier to read as english. You could even consider using var isNotFirst = i != 0; as you only use !first in the algorithm.

    • Last vs Previous. is_conseq_with_last is refering to previous, so I switched it to previous to avoid confusion with last.


    • start_index and end_index sound like they would be 0 and integers.Count. They're the start and end of the range you're tracking, let's name them accordingly: rangeStart and rangeEnd.

    If-Statement Ordering & Flow



    We've all been there, written an algorithm, tested it, and it works, all done right? Well, sometimes that algorithm can be restructured to express what we're actually doing much clearer.



     if (!first && fids[fids_index - 1] == fids[fids_index] - 1)

    is_conseq_with_last = true;

    else if (!first)

    is_conseq_with_last = false;



    There's a common denominator here, !first let's work with that, clearly neither of these happen if it's true.



    if (!first)

    if (fids[fids_index - 1] == fids[fids_index] - 1)

    is_conseq_with_last = true;

    else

    is_conseq_with_last = false;




    Well, now it's obvious that inner if-statement can be reduced.



    if (!first)

    is_conseq_with_last = fids[fids_index - 1] == fids[fids_index] - 1;



    And if you wanted, a ternary operator.



    is_conseq_with_last = !first && fids[fids_index - 1] == fids[fids_index] - 1;


    And it's now also obvious that you're setting the variable with each iteration, so there's no need to declare it outside the loop.



    Similar can be done with the bottom if-statement. Here's what I ended up with altogether.



    My Version



    I am running short on time so there might be a mistake or two and it's still in my coding style so don't take it for face value and try to apply the concepts I'm showing above yourself.



    public static List<(int from, int to)> GetConsecutiveRanges(List<int> integers)
    integers.Count == 0) return null;

    integers = integers.OrderBy(a => a).Distinct().ToList();
    var ranges = new List<(int from, int to)>();

    var rangeStart = 0;
    var rangeEnd = 0;

    for (var i = 0; i < integers.Count; i++)

    var isFirst = i == 0;
    var isLast = i == integers.Count - 1;
    var isConsecutiveFromPrevious = isFirst == false && integers[i-1] == integers[i] - 1;

    if (last)

    if (isConsecutiveFromPrevious == false)

    rangeEnd = isFirst == false ? i - 1 : rangeEnd;
    ranges.Add((integers[rangeStart], integers[rangeEnd]));
    rangeStart = i;


    rangeEnd = i;
    ranges.Add((integers[rangeStart], integers[rangeEnd]));

    else if (isConsecutiveFromPrevious == false && isFirst == false)

    rangeEnd = isFirst == false && isLast == false ? i - 1 : i;
    ranges.Add((integers[rangeStart], integers[rangeEnd]));
    rangeStart = i;




    ranges.ForEach(a => Console.WriteLine($"(x >= a.@from && x <= a.to)"));

    return ranges;






    share|improve this answer









    $endgroup$












    • $begingroup$
      I wonder whether it would be more efficient to swap these two calls .OrderBy(a => a).Distinct().- just thinking aloud...
      $endgroup$
      – t3chb0t
      4 hours ago










    • $begingroup$
      @t3chb0t I had exactly the same thought, but in the end, both methods must track values, so performance must surely be similar either way around?
      $endgroup$
      – Aalawlx
      4 hours ago










    • $begingroup$
      @Shelby115 There are some very interesting points in your answer - thanks a lot.
      $endgroup$
      – Aalawlx
      4 hours ago
















    3












    $begingroup$

    As a pre-note, I had to translate everything to camelCase and PascalCase because I was having a very difficult time reading your code. No judgments, just understand I was running short on time and didn't translate it back on the conclusion.



    Readability



    Use meaningful names.




    • fids I changed to integers as from your description I gather it's the list of integers used to create the ranges.


    • fids_index seems very noisy. Standard convention is i, j, etc. When you reduce the iterator variable down to a single character it's much easier to focus on what actually matters.

    • Booleans should be prefixed with Is or Has or Was etc. So in this case IsFirst and IsLast instead of first and last makes it easier to read as english. You could even consider using var isNotFirst = i != 0; as you only use !first in the algorithm.

    • Last vs Previous. is_conseq_with_last is refering to previous, so I switched it to previous to avoid confusion with last.


    • start_index and end_index sound like they would be 0 and integers.Count. They're the start and end of the range you're tracking, let's name them accordingly: rangeStart and rangeEnd.

    If-Statement Ordering & Flow



    We've all been there, written an algorithm, tested it, and it works, all done right? Well, sometimes that algorithm can be restructured to express what we're actually doing much clearer.



     if (!first && fids[fids_index - 1] == fids[fids_index] - 1)

    is_conseq_with_last = true;

    else if (!first)

    is_conseq_with_last = false;



    There's a common denominator here, !first let's work with that, clearly neither of these happen if it's true.



    if (!first)

    if (fids[fids_index - 1] == fids[fids_index] - 1)

    is_conseq_with_last = true;

    else

    is_conseq_with_last = false;




    Well, now it's obvious that inner if-statement can be reduced.



    if (!first)

    is_conseq_with_last = fids[fids_index - 1] == fids[fids_index] - 1;



    And if you wanted, a ternary operator.



    is_conseq_with_last = !first && fids[fids_index - 1] == fids[fids_index] - 1;


    And it's now also obvious that you're setting the variable with each iteration, so there's no need to declare it outside the loop.



    Similar can be done with the bottom if-statement. Here's what I ended up with altogether.



    My Version



    I am running short on time so there might be a mistake or two and it's still in my coding style so don't take it for face value and try to apply the concepts I'm showing above yourself.



    public static List<(int from, int to)> GetConsecutiveRanges(List<int> integers)
    integers.Count == 0) return null;

    integers = integers.OrderBy(a => a).Distinct().ToList();
    var ranges = new List<(int from, int to)>();

    var rangeStart = 0;
    var rangeEnd = 0;

    for (var i = 0; i < integers.Count; i++)

    var isFirst = i == 0;
    var isLast = i == integers.Count - 1;
    var isConsecutiveFromPrevious = isFirst == false && integers[i-1] == integers[i] - 1;

    if (last)

    if (isConsecutiveFromPrevious == false)

    rangeEnd = isFirst == false ? i - 1 : rangeEnd;
    ranges.Add((integers[rangeStart], integers[rangeEnd]));
    rangeStart = i;


    rangeEnd = i;
    ranges.Add((integers[rangeStart], integers[rangeEnd]));

    else if (isConsecutiveFromPrevious == false && isFirst == false)

    rangeEnd = isFirst == false && isLast == false ? i - 1 : i;
    ranges.Add((integers[rangeStart], integers[rangeEnd]));
    rangeStart = i;




    ranges.ForEach(a => Console.WriteLine($"(x >= a.@from && x <= a.to)"));

    return ranges;






    share|improve this answer









    $endgroup$












    • $begingroup$
      I wonder whether it would be more efficient to swap these two calls .OrderBy(a => a).Distinct().- just thinking aloud...
      $endgroup$
      – t3chb0t
      4 hours ago










    • $begingroup$
      @t3chb0t I had exactly the same thought, but in the end, both methods must track values, so performance must surely be similar either way around?
      $endgroup$
      – Aalawlx
      4 hours ago










    • $begingroup$
      @Shelby115 There are some very interesting points in your answer - thanks a lot.
      $endgroup$
      – Aalawlx
      4 hours ago














    3












    3








    3





    $begingroup$

    As a pre-note, I had to translate everything to camelCase and PascalCase because I was having a very difficult time reading your code. No judgments, just understand I was running short on time and didn't translate it back on the conclusion.



    Readability



    Use meaningful names.




    • fids I changed to integers as from your description I gather it's the list of integers used to create the ranges.


    • fids_index seems very noisy. Standard convention is i, j, etc. When you reduce the iterator variable down to a single character it's much easier to focus on what actually matters.

    • Booleans should be prefixed with Is or Has or Was etc. So in this case IsFirst and IsLast instead of first and last makes it easier to read as english. You could even consider using var isNotFirst = i != 0; as you only use !first in the algorithm.

    • Last vs Previous. is_conseq_with_last is refering to previous, so I switched it to previous to avoid confusion with last.


    • start_index and end_index sound like they would be 0 and integers.Count. They're the start and end of the range you're tracking, let's name them accordingly: rangeStart and rangeEnd.

    If-Statement Ordering & Flow



    We've all been there, written an algorithm, tested it, and it works, all done right? Well, sometimes that algorithm can be restructured to express what we're actually doing much clearer.



     if (!first && fids[fids_index - 1] == fids[fids_index] - 1)

    is_conseq_with_last = true;

    else if (!first)

    is_conseq_with_last = false;



    There's a common denominator here, !first let's work with that, clearly neither of these happen if it's true.



    if (!first)

    if (fids[fids_index - 1] == fids[fids_index] - 1)

    is_conseq_with_last = true;

    else

    is_conseq_with_last = false;




    Well, now it's obvious that inner if-statement can be reduced.



    if (!first)

    is_conseq_with_last = fids[fids_index - 1] == fids[fids_index] - 1;



    And if you wanted, a ternary operator.



    is_conseq_with_last = !first && fids[fids_index - 1] == fids[fids_index] - 1;


    And it's now also obvious that you're setting the variable with each iteration, so there's no need to declare it outside the loop.



    Similar can be done with the bottom if-statement. Here's what I ended up with altogether.



    My Version



    I am running short on time so there might be a mistake or two and it's still in my coding style so don't take it for face value and try to apply the concepts I'm showing above yourself.



    public static List<(int from, int to)> GetConsecutiveRanges(List<int> integers)
    integers.Count == 0) return null;

    integers = integers.OrderBy(a => a).Distinct().ToList();
    var ranges = new List<(int from, int to)>();

    var rangeStart = 0;
    var rangeEnd = 0;

    for (var i = 0; i < integers.Count; i++)

    var isFirst = i == 0;
    var isLast = i == integers.Count - 1;
    var isConsecutiveFromPrevious = isFirst == false && integers[i-1] == integers[i] - 1;

    if (last)

    if (isConsecutiveFromPrevious == false)

    rangeEnd = isFirst == false ? i - 1 : rangeEnd;
    ranges.Add((integers[rangeStart], integers[rangeEnd]));
    rangeStart = i;


    rangeEnd = i;
    ranges.Add((integers[rangeStart], integers[rangeEnd]));

    else if (isConsecutiveFromPrevious == false && isFirst == false)

    rangeEnd = isFirst == false && isLast == false ? i - 1 : i;
    ranges.Add((integers[rangeStart], integers[rangeEnd]));
    rangeStart = i;




    ranges.ForEach(a => Console.WriteLine($"(x >= a.@from && x <= a.to)"));

    return ranges;






    share|improve this answer









    $endgroup$



    As a pre-note, I had to translate everything to camelCase and PascalCase because I was having a very difficult time reading your code. No judgments, just understand I was running short on time and didn't translate it back on the conclusion.



    Readability



    Use meaningful names.




    • fids I changed to integers as from your description I gather it's the list of integers used to create the ranges.


    • fids_index seems very noisy. Standard convention is i, j, etc. When you reduce the iterator variable down to a single character it's much easier to focus on what actually matters.

    • Booleans should be prefixed with Is or Has or Was etc. So in this case IsFirst and IsLast instead of first and last makes it easier to read as english. You could even consider using var isNotFirst = i != 0; as you only use !first in the algorithm.

    • Last vs Previous. is_conseq_with_last is refering to previous, so I switched it to previous to avoid confusion with last.


    • start_index and end_index sound like they would be 0 and integers.Count. They're the start and end of the range you're tracking, let's name them accordingly: rangeStart and rangeEnd.

    If-Statement Ordering & Flow



    We've all been there, written an algorithm, tested it, and it works, all done right? Well, sometimes that algorithm can be restructured to express what we're actually doing much clearer.



     if (!first && fids[fids_index - 1] == fids[fids_index] - 1)

    is_conseq_with_last = true;

    else if (!first)

    is_conseq_with_last = false;



    There's a common denominator here, !first let's work with that, clearly neither of these happen if it's true.



    if (!first)

    if (fids[fids_index - 1] == fids[fids_index] - 1)

    is_conseq_with_last = true;

    else

    is_conseq_with_last = false;




    Well, now it's obvious that inner if-statement can be reduced.



    if (!first)

    is_conseq_with_last = fids[fids_index - 1] == fids[fids_index] - 1;



    And if you wanted, a ternary operator.



    is_conseq_with_last = !first && fids[fids_index - 1] == fids[fids_index] - 1;


    And it's now also obvious that you're setting the variable with each iteration, so there's no need to declare it outside the loop.



    Similar can be done with the bottom if-statement. Here's what I ended up with altogether.



    My Version



    I am running short on time so there might be a mistake or two and it's still in my coding style so don't take it for face value and try to apply the concepts I'm showing above yourself.



    public static List<(int from, int to)> GetConsecutiveRanges(List<int> integers)
    integers.Count == 0) return null;

    integers = integers.OrderBy(a => a).Distinct().ToList();
    var ranges = new List<(int from, int to)>();

    var rangeStart = 0;
    var rangeEnd = 0;

    for (var i = 0; i < integers.Count; i++)

    var isFirst = i == 0;
    var isLast = i == integers.Count - 1;
    var isConsecutiveFromPrevious = isFirst == false && integers[i-1] == integers[i] - 1;

    if (last)

    if (isConsecutiveFromPrevious == false)

    rangeEnd = isFirst == false ? i - 1 : rangeEnd;
    ranges.Add((integers[rangeStart], integers[rangeEnd]));
    rangeStart = i;


    rangeEnd = i;
    ranges.Add((integers[rangeStart], integers[rangeEnd]));

    else if (isConsecutiveFromPrevious == false && isFirst == false)

    rangeEnd = isFirst == false && isLast == false ? i - 1 : i;
    ranges.Add((integers[rangeStart], integers[rangeEnd]));
    rangeStart = i;




    ranges.ForEach(a => Console.WriteLine($"(x >= a.@from && x <= a.to)"));

    return ranges;







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 4 hours ago









    Shelby115Shelby115

    1,646517




    1,646517











    • $begingroup$
      I wonder whether it would be more efficient to swap these two calls .OrderBy(a => a).Distinct().- just thinking aloud...
      $endgroup$
      – t3chb0t
      4 hours ago










    • $begingroup$
      @t3chb0t I had exactly the same thought, but in the end, both methods must track values, so performance must surely be similar either way around?
      $endgroup$
      – Aalawlx
      4 hours ago










    • $begingroup$
      @Shelby115 There are some very interesting points in your answer - thanks a lot.
      $endgroup$
      – Aalawlx
      4 hours ago

















    • $begingroup$
      I wonder whether it would be more efficient to swap these two calls .OrderBy(a => a).Distinct().- just thinking aloud...
      $endgroup$
      – t3chb0t
      4 hours ago










    • $begingroup$
      @t3chb0t I had exactly the same thought, but in the end, both methods must track values, so performance must surely be similar either way around?
      $endgroup$
      – Aalawlx
      4 hours ago










    • $begingroup$
      @Shelby115 There are some very interesting points in your answer - thanks a lot.
      $endgroup$
      – Aalawlx
      4 hours ago
















    $begingroup$
    I wonder whether it would be more efficient to swap these two calls .OrderBy(a => a).Distinct().- just thinking aloud...
    $endgroup$
    – t3chb0t
    4 hours ago




    $begingroup$
    I wonder whether it would be more efficient to swap these two calls .OrderBy(a => a).Distinct().- just thinking aloud...
    $endgroup$
    – t3chb0t
    4 hours ago












    $begingroup$
    @t3chb0t I had exactly the same thought, but in the end, both methods must track values, so performance must surely be similar either way around?
    $endgroup$
    – Aalawlx
    4 hours ago




    $begingroup$
    @t3chb0t I had exactly the same thought, but in the end, both methods must track values, so performance must surely be similar either way around?
    $endgroup$
    – Aalawlx
    4 hours ago












    $begingroup$
    @Shelby115 There are some very interesting points in your answer - thanks a lot.
    $endgroup$
    – Aalawlx
    4 hours ago





    $begingroup$
    @Shelby115 There are some very interesting points in your answer - thanks a lot.
    $endgroup$
    – Aalawlx
    4 hours ago














    1












    $begingroup$

    Your code is really complicated. First, your code should be abstracted a little more. It is not specific to feature IDs, therefore the terminology should not use these words. The same algorithm can be used to select which pages to print from a document, therefore the variables should be just nums and ranges. To test your current code, I wrote:



    [Test]
    public void TestRanges()

    Assert.AreEqual("", Str(Ranges(new List<int>())));
    Assert.AreEqual("1", Str(Ranges(new List<int> 1 )));
    Assert.AreEqual("1-5", Str(Ranges(new List<int> 1, 2, 3, 4, 5 )));
    Assert.AreEqual("1-3, 5", Str(Ranges(new List<int> 1, 2, 3, 5 )));
    Assert.AreEqual("1, 3, 5-6", Str(Ranges(new List<int> 1, 3, 5, 6 )));



    I wrote a helper function Str so that I don't have to construct a list of ranges for each test case:



    public static string Str(List<(int from, int to)> ranges)

    var parts = new List<string>();

    foreach (var range in ranges)
    if (range.from == range.to)
    parts.Add(range.from.ToString());
    else
    parts.Add(range.@from + "-" + range.to);



    return string.Join(", ", parts);



    After renaming your function to Ranges, these tests ran successfully. So I was ready to refactor your code. I did not really do this since your code looked too complicated to start with. Instead, I remembered that I had successfully used the following pattern quite often:



    var start = ...;
    while (start < nums.Count)
    var end = ...;
    while (end < nums.Count)




    With this knowledge I wrote the following code:



    public static List<(int from, int to)> Ranges(List<int> nums)

    nums = nums.OrderBy(a => a).Distinct().ToList();

    var ranges = new List<(int from, int to)>();

    var start = 0;
    while (start < nums.Count)
    var end = start + 1; // the range is from [start, end).

    while (end < nums.Count && nums[end - 1] + 1 == nums[end])
    end++;


    ranges.Add((nums[start], nums[end - 1]));
    start = end; // continue after the current range


    return ranges;



    This code doesn't need any special cases for the last range, or anything else. A range either stops when the end of the numbers is reached, or when the following number is not consecutive. This sounds sensible, and this is exactly what the code is doing.



    I removed the check for nums == null since it is not necessary. Collections should never be null, and if they are, the code immediately throws an exception, which is fine.



    I also removed the special case for nums.Count == 0 since returning an empty list is much better than returning null. Again, expressions that have collection type should never be null. The test cases cover this case, so there's nothing to worry about.






    share|improve this answer











    $endgroup$

















      1












      $begingroup$

      Your code is really complicated. First, your code should be abstracted a little more. It is not specific to feature IDs, therefore the terminology should not use these words. The same algorithm can be used to select which pages to print from a document, therefore the variables should be just nums and ranges. To test your current code, I wrote:



      [Test]
      public void TestRanges()

      Assert.AreEqual("", Str(Ranges(new List<int>())));
      Assert.AreEqual("1", Str(Ranges(new List<int> 1 )));
      Assert.AreEqual("1-5", Str(Ranges(new List<int> 1, 2, 3, 4, 5 )));
      Assert.AreEqual("1-3, 5", Str(Ranges(new List<int> 1, 2, 3, 5 )));
      Assert.AreEqual("1, 3, 5-6", Str(Ranges(new List<int> 1, 3, 5, 6 )));



      I wrote a helper function Str so that I don't have to construct a list of ranges for each test case:



      public static string Str(List<(int from, int to)> ranges)

      var parts = new List<string>();

      foreach (var range in ranges)
      if (range.from == range.to)
      parts.Add(range.from.ToString());
      else
      parts.Add(range.@from + "-" + range.to);



      return string.Join(", ", parts);



      After renaming your function to Ranges, these tests ran successfully. So I was ready to refactor your code. I did not really do this since your code looked too complicated to start with. Instead, I remembered that I had successfully used the following pattern quite often:



      var start = ...;
      while (start < nums.Count)
      var end = ...;
      while (end < nums.Count)




      With this knowledge I wrote the following code:



      public static List<(int from, int to)> Ranges(List<int> nums)

      nums = nums.OrderBy(a => a).Distinct().ToList();

      var ranges = new List<(int from, int to)>();

      var start = 0;
      while (start < nums.Count)
      var end = start + 1; // the range is from [start, end).

      while (end < nums.Count && nums[end - 1] + 1 == nums[end])
      end++;


      ranges.Add((nums[start], nums[end - 1]));
      start = end; // continue after the current range


      return ranges;



      This code doesn't need any special cases for the last range, or anything else. A range either stops when the end of the numbers is reached, or when the following number is not consecutive. This sounds sensible, and this is exactly what the code is doing.



      I removed the check for nums == null since it is not necessary. Collections should never be null, and if they are, the code immediately throws an exception, which is fine.



      I also removed the special case for nums.Count == 0 since returning an empty list is much better than returning null. Again, expressions that have collection type should never be null. The test cases cover this case, so there's nothing to worry about.






      share|improve this answer











      $endgroup$















        1












        1








        1





        $begingroup$

        Your code is really complicated. First, your code should be abstracted a little more. It is not specific to feature IDs, therefore the terminology should not use these words. The same algorithm can be used to select which pages to print from a document, therefore the variables should be just nums and ranges. To test your current code, I wrote:



        [Test]
        public void TestRanges()

        Assert.AreEqual("", Str(Ranges(new List<int>())));
        Assert.AreEqual("1", Str(Ranges(new List<int> 1 )));
        Assert.AreEqual("1-5", Str(Ranges(new List<int> 1, 2, 3, 4, 5 )));
        Assert.AreEqual("1-3, 5", Str(Ranges(new List<int> 1, 2, 3, 5 )));
        Assert.AreEqual("1, 3, 5-6", Str(Ranges(new List<int> 1, 3, 5, 6 )));



        I wrote a helper function Str so that I don't have to construct a list of ranges for each test case:



        public static string Str(List<(int from, int to)> ranges)

        var parts = new List<string>();

        foreach (var range in ranges)
        if (range.from == range.to)
        parts.Add(range.from.ToString());
        else
        parts.Add(range.@from + "-" + range.to);



        return string.Join(", ", parts);



        After renaming your function to Ranges, these tests ran successfully. So I was ready to refactor your code. I did not really do this since your code looked too complicated to start with. Instead, I remembered that I had successfully used the following pattern quite often:



        var start = ...;
        while (start < nums.Count)
        var end = ...;
        while (end < nums.Count)




        With this knowledge I wrote the following code:



        public static List<(int from, int to)> Ranges(List<int> nums)

        nums = nums.OrderBy(a => a).Distinct().ToList();

        var ranges = new List<(int from, int to)>();

        var start = 0;
        while (start < nums.Count)
        var end = start + 1; // the range is from [start, end).

        while (end < nums.Count && nums[end - 1] + 1 == nums[end])
        end++;


        ranges.Add((nums[start], nums[end - 1]));
        start = end; // continue after the current range


        return ranges;



        This code doesn't need any special cases for the last range, or anything else. A range either stops when the end of the numbers is reached, or when the following number is not consecutive. This sounds sensible, and this is exactly what the code is doing.



        I removed the check for nums == null since it is not necessary. Collections should never be null, and if they are, the code immediately throws an exception, which is fine.



        I also removed the special case for nums.Count == 0 since returning an empty list is much better than returning null. Again, expressions that have collection type should never be null. The test cases cover this case, so there's nothing to worry about.






        share|improve this answer











        $endgroup$



        Your code is really complicated. First, your code should be abstracted a little more. It is not specific to feature IDs, therefore the terminology should not use these words. The same algorithm can be used to select which pages to print from a document, therefore the variables should be just nums and ranges. To test your current code, I wrote:



        [Test]
        public void TestRanges()

        Assert.AreEqual("", Str(Ranges(new List<int>())));
        Assert.AreEqual("1", Str(Ranges(new List<int> 1 )));
        Assert.AreEqual("1-5", Str(Ranges(new List<int> 1, 2, 3, 4, 5 )));
        Assert.AreEqual("1-3, 5", Str(Ranges(new List<int> 1, 2, 3, 5 )));
        Assert.AreEqual("1, 3, 5-6", Str(Ranges(new List<int> 1, 3, 5, 6 )));



        I wrote a helper function Str so that I don't have to construct a list of ranges for each test case:



        public static string Str(List<(int from, int to)> ranges)

        var parts = new List<string>();

        foreach (var range in ranges)
        if (range.from == range.to)
        parts.Add(range.from.ToString());
        else
        parts.Add(range.@from + "-" + range.to);



        return string.Join(", ", parts);



        After renaming your function to Ranges, these tests ran successfully. So I was ready to refactor your code. I did not really do this since your code looked too complicated to start with. Instead, I remembered that I had successfully used the following pattern quite often:



        var start = ...;
        while (start < nums.Count)
        var end = ...;
        while (end < nums.Count)




        With this knowledge I wrote the following code:



        public static List<(int from, int to)> Ranges(List<int> nums)

        nums = nums.OrderBy(a => a).Distinct().ToList();

        var ranges = new List<(int from, int to)>();

        var start = 0;
        while (start < nums.Count)
        var end = start + 1; // the range is from [start, end).

        while (end < nums.Count && nums[end - 1] + 1 == nums[end])
        end++;


        ranges.Add((nums[start], nums[end - 1]));
        start = end; // continue after the current range


        return ranges;



        This code doesn't need any special cases for the last range, or anything else. A range either stops when the end of the numbers is reached, or when the following number is not consecutive. This sounds sensible, and this is exactly what the code is doing.



        I removed the check for nums == null since it is not necessary. Collections should never be null, and if they are, the code immediately throws an exception, which is fine.



        I also removed the special case for nums.Count == 0 since returning an empty list is much better than returning null. Again, expressions that have collection type should never be null. The test cases cover this case, so there's nothing to worry about.







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        edited 37 mins ago

























        answered 45 mins ago









        Roland IlligRoland Illig

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