How to create a 2D table with varying step?How to create a Table of Tables with indexed variablesHow can I create a new tables out of a table and plot itCreate a table with inline conditionsA problem involving classification of dataCreate tree association using tableTable from grouping an association by valueHow to create a table of tables with different table lengths?Table with the logarithmic stepLinearly change the step size in a tableTable with varying step
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How to create a 2D table with varying step?
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How to create a 2D table with varying step?
How to create a Table of Tables with indexed variablesHow can I create a new tables out of a table and plot itCreate a table with inline conditionsA problem involving classification of dataCreate tree association using tableTable from grouping an association by valueHow to create a table of tables with different table lengths?Table with the logarithmic stepLinearly change the step size in a tableTable with varying step
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
I would like to produce a table with 2 coordinates, where a step for one coordinate depends on the value of another one. I tried to do this in the following way:
Step[j_] := Association[0.01 -> 5, 0.03 -> 10]
Table1 = Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 100, Step[j]]
but I failed. Could you please show me how to do this?
table syntax
asked 8 hours ago
John TaylorJohn Taylor
8964 silver badges11 bronze badges
$endgroup$
add a comment |
$begingroup$
I would like to produce a table with 2 coordinates, where a step for one coordinate depends on the value of another one. I tried to do this in the following way:
Step[j_] := Association[0.01 -> 5, 0.03 -> 10]
Table1 = Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 100, Step[j]]
but I failed. Could you please show me how to do this?
table syntax
asked 8 hours ago
John TaylorJohn Taylor
8964 silver badges11 bronze badges
$endgroup$
2
$begingroup$
Also:Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 50, If[j == 0.01, 5, 10]]
$endgroup$
– Michael E2
7 hours ago
add a comment |
$begingroup$
I would like to produce a table with 2 coordinates, where a step for one coordinate depends on the value of another one. I tried to do this in the following way:
Step[j_] := Association[0.01 -> 5, 0.03 -> 10]
Table1 = Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 100, Step[j]]
but I failed. Could you please show me how to do this?
table syntax
asked 8 hours ago
John TaylorJohn Taylor
8964 silver badges11 bronze badges
$endgroup$
I would like to produce a table with 2 coordinates, where a step for one coordinate depends on the value of another one. I tried to do this in the following way:
Step[j_] := Association[0.01 -> 5, 0.03 -> 10]
Table1 = Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 100, Step[j]]
but I failed. Could you please show me how to do this?
table syntax
table syntax
asked 8 hours ago
John TaylorJohn Taylor
8964 silver badges11 bronze badges
asked 8 hours ago
John TaylorJohn Taylor
8964 silver badges11 bronze badges
asked 8 hours ago
John TaylorJohn Taylor
8964 silver badges11 bronze badges
asked 8 hours ago
John TaylorJohn Taylor
8964 silver badges11 bronze badges
asked 8 hours ago
John TaylorJohn Taylor
8964 silver badges11 bronze badges
8964 silver badges11 bronze badges
2
$begingroup$
Also:Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 50, If[j == 0.01, 5, 10]]
$endgroup$
– Michael E2
7 hours ago
add a comment |
2
$begingroup$
Also:Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 50, If[j == 0.01, 5, 10]]
$endgroup$
– Michael E2
7 hours ago
2
2
$begingroup$
Also:
Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 50, If[j == 0.01, 5, 10]]$endgroup$
– Michael E2
7 hours ago
$begingroup$
Also:
Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 50, If[j == 0.01, 5, 10]]$endgroup$
– Michael E2
7 hours ago
add a comment |
1 Answer
1
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oldest
votes
$begingroup$
step = Association[0.01 -> 5, 0.03 -> 10];
Table1 = Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 50, step[j]];
TableForm[Table1,
TableDirections -> Row, Row,
TableHeadings -> None, None, "j", "k"]
answered 8 hours ago
kglrkglr
202k10 gold badges230 silver badges461 bronze badges
$endgroup$
$begingroup$
Thank you @MichaelE2. Removed it.
$endgroup$
– kglr
7 hours ago
add a comment |
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1 Answer
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1 Answer
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oldest
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votes
$begingroup$
step = Association[0.01 -> 5, 0.03 -> 10];
Table1 = Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 50, step[j]];
TableForm[Table1,
TableDirections -> Row, Row,
TableHeadings -> None, None, "j", "k"]
answered 8 hours ago
kglrkglr
202k10 gold badges230 silver badges461 bronze badges
$endgroup$
$begingroup$
Thank you @MichaelE2. Removed it.
$endgroup$
– kglr
7 hours ago
add a comment |
$begingroup$
step = Association[0.01 -> 5, 0.03 -> 10];
Table1 = Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 50, step[j]];
TableForm[Table1,
TableDirections -> Row, Row,
TableHeadings -> None, None, "j", "k"]
answered 8 hours ago
kglrkglr
202k10 gold badges230 silver badges461 bronze badges
$endgroup$
$begingroup$
Thank you @MichaelE2. Removed it.
$endgroup$
– kglr
7 hours ago
add a comment |
$begingroup$
step = Association[0.01 -> 5, 0.03 -> 10];
Table1 = Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 50, step[j]];
TableForm[Table1,
TableDirections -> Row, Row,
TableHeadings -> None, None, "j", "k"]
answered 8 hours ago
kglrkglr
202k10 gold badges230 silver badges461 bronze badges
$endgroup$
step = Association[0.01 -> 5, 0.03 -> 10];
Table1 = Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 50, step[j]];
TableForm[Table1,
TableDirections -> Row, Row,
TableHeadings -> None, None, "j", "k"]
answered 8 hours ago
kglrkglr
202k10 gold badges230 silver badges461 bronze badges
edited 7 hours ago
answered 8 hours ago
kglrkglr
202k10 gold badges230 silver badges461 bronze badges
answered 8 hours ago
kglrkglr
202k10 gold badges230 silver badges461 bronze badges
answered 8 hours ago
kglrkglr
202k10 gold badges230 silver badges461 bronze badges
202k10 gold badges230 silver badges461 bronze badges
$begingroup$
Thank you @MichaelE2. Removed it.
$endgroup$
– kglr
7 hours ago
add a comment |
$begingroup$
Thank you @MichaelE2. Removed it.
$endgroup$
– kglr
7 hours ago
$begingroup$
Thank you @MichaelE2. Removed it.
$endgroup$
– kglr
7 hours ago
$begingroup$
Thank you @MichaelE2. Removed it.
$endgroup$
– kglr
7 hours ago
add a comment |
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$begingroup$
Also:
Table[j, k, j, 0.01, 0.03, 0.02, k, 1, 50, If[j == 0.01, 5, 10]]$endgroup$
– Michael E2
7 hours ago