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2

I have a folder x with a number of sufolders ale, bae, galo and inside each subfolder one .pest file.

x/ale/ale.pest 
x/bae/bae.pest 
x/galo/galo.pest

I have a list in folder y containing the order I should cat .pest files

bae
galo
ale

from my x folder I'm trying

for file in ./*/*.pest; do while read line; do cat "$line".pest; done; done <./y/list

but it's not working.

bash shell-script

share|improve this question

asked 8 hours ago

Madza Yasodara Farias VirgensMadza Yasodara Farias Virgens

3044 bronze badges

add a comment | 

2

I have a folder x with a number of sufolders ale, bae, galo and inside each subfolder one .pest file.

x/ale/ale.pest 
x/bae/bae.pest 
x/galo/galo.pest

I have a list in folder y containing the order I should cat .pest files

bae
galo
ale

from my x folder I'm trying

for file in ./*/*.pest; do while read line; do cat "$line".pest; done; done <./y/list

but it's not working.

bash shell-script

share|improve this question

asked 8 hours ago

Madza Yasodara Farias VirgensMadza Yasodara Farias Virgens

3044 bronze badges

add a comment | 

I have a folder x with a number of sufolders ale, bae, galo and inside each subfolder one .pest file.

x/ale/ale.pest 
x/bae/bae.pest 
x/galo/galo.pest

I have a list in folder y containing the order I should cat .pest files

bae
galo
ale

from my x folder I'm trying

for file in ./*/*.pest; do while read line; do cat "$line".pest; done; done <./y/list

but it's not working.

bash shell-script

share|improve this question

asked 8 hours ago

Madza Yasodara Farias VirgensMadza Yasodara Farias Virgens

3044 bronze badges

x/ale/ale.pest 
x/bae/bae.pest 
x/galo/galo.pest

bae
galo
ale

for file in ./*/*.pest; do while read line; do cat "$line".pest; done; done <./y/list

share|improve this question

asked 8 hours ago

Madza Yasodara Farias VirgensMadza Yasodara Farias Virgens

3044 bronze badges

share|improve this question

asked 8 hours ago

Madza Yasodara Farias VirgensMadza Yasodara Farias Virgens

3044 bronze badges

asked 8 hours ago

Madza Yasodara Farias VirgensMadza Yasodara Farias Virgens

3044 bronze badges

asked 8 hours ago

Madza Yasodara Farias VirgensMadza Yasodara Farias Virgens

3044 bronze badges

2 Answers
2

active

oldest

votes

1

To answer the follow-up subtly different question:

I'm still wondering how would be if my subdirectories didnt have same names as in list though....

Let's make some assumptions:

• All the subdirectories of x are fair game.


• All .pest files are fair game.


• If you have two .pest files with the same name (but in different directories), you don't care what order those two files will be cated in.

Then you have:

while read -r name; do
 cat x/*/"$name.pest"
done <y/list >concatenated.pest

Adding sanity checking is a little bit trickier but still doable. (I'm not doing that part as I don't know if my assumptions even match your use case.)

share|improve this answer

answered 7 hours ago

WildcardWildcard

23.8k1010 gold badges6868 silver badges179179 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yup. It did it's thing. Thxs!
  
  – Madza Yasodara Farias Virgens
  7 hours ago
  

  
  
  
  

add a comment | 

3

You have the order in a list, so don't match the filenames with a filename globbing pattern. Instead, construct the names from the strings read from the list:

#!/bin/sh

while read -r name; do
 cat "x/$name/$name.pest"
done <y/list >concatenated.pest

This would concatenate all the relevant .pest files and create a single file called concatenated.pest from these in the current directory, in the order read from y/list.

With a bit of checking included:

#!/bin/sh

while read -r name; do
 pathname="x/$name/$name.pest"

 if [ ! -f "$pathname" ]; then
 printf 'Can not find %sn' "$pathname"
 echo 'Output file will be incomplete'
 exit 1
 fi >&2

 cat "$pathname"
done <y/list >concatenated.pest

share|improve this answer

edited 7 hours ago

answered 8 hours ago

Kusalananda♦Kusalananda

153k1818 gold badges302302 silver badges483483 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Thank you!!! I'm still wondering how would be if my subdirectories didnt have same names as in list though...
  
  – Madza Yasodara Farias Virgens
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @MadzaYasodaraFariasVirgens In this question, the do all have the same names as the actual .pest file. If they don't, then maybe they follow some other pattern that would be easily handled. If not, you may want to ask a separate question about that, but I doubt it would be too difficult.
  
  – Kusalananda♦
  7 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  got it! k I'll post as a different question bc I'm also having to process some files like that. thxs
  
  – Madza Yasodara Farias Virgens
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I posted a modified version of the answer to illustrate the easiest way to handle differently named subdirectories.
  
  – Wildcard
  7 hours ago
  

  
  
  
  

add a comment | 

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1

To answer the follow-up subtly different question:

I'm still wondering how would be if my subdirectories didnt have same names as in list though....

Let's make some assumptions:

• All the subdirectories of x are fair game.


• All .pest files are fair game.


• If you have two .pest files with the same name (but in different directories), you don't care what order those two files will be cated in.

Then you have:

while read -r name; do
 cat x/*/"$name.pest"
done <y/list >concatenated.pest

Adding sanity checking is a little bit trickier but still doable. (I'm not doing that part as I don't know if my assumptions even match your use case.)

share|improve this answer

answered 7 hours ago

WildcardWildcard

23.8k1010 gold badges6868 silver badges179179 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yup. It did it's thing. Thxs!
  
  – Madza Yasodara Farias Virgens
  7 hours ago
  

  
  
  
  

add a comment | 

1

To answer the follow-up subtly different question:

I'm still wondering how would be if my subdirectories didnt have same names as in list though....

Let's make some assumptions:

• All the subdirectories of x are fair game.


• All .pest files are fair game.


• If you have two .pest files with the same name (but in different directories), you don't care what order those two files will be cated in.

Then you have:

while read -r name; do
 cat x/*/"$name.pest"
done <y/list >concatenated.pest

Adding sanity checking is a little bit trickier but still doable. (I'm not doing that part as I don't know if my assumptions even match your use case.)

share|improve this answer

answered 7 hours ago

WildcardWildcard

23.8k1010 gold badges6868 silver badges179179 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yup. It did it's thing. Thxs!
  
  – Madza Yasodara Farias Virgens
  7 hours ago
  

  
  
  
  

add a comment | 

To answer the follow-up subtly different question:

I'm still wondering how would be if my subdirectories didnt have same names as in list though....

Let's make some assumptions:

• All the subdirectories of x are fair game.


• All .pest files are fair game.


• If you have two .pest files with the same name (but in different directories), you don't care what order those two files will be cated in.

Then you have:

while read -r name; do
 cat x/*/"$name.pest"
done <y/list >concatenated.pest

Adding sanity checking is a little bit trickier but still doable. (I'm not doing that part as I don't know if my assumptions even match your use case.)

share|improve this answer

answered 7 hours ago

WildcardWildcard

23.8k1010 gold badges6868 silver badges179179 bronze badges

while read -r name; do
 cat x/*/"$name.pest"
done <y/list >concatenated.pest

share|improve this answer

answered 7 hours ago

WildcardWildcard

23.8k1010 gold badges6868 silver badges179179 bronze badges

answered 7 hours ago

WildcardWildcard

23.8k1010 gold badges6868 silver badges179179 bronze badges

answered 7 hours ago

WildcardWildcard

23.8k1010 gold badges6868 silver badges179179 bronze badges

3

You have the order in a list, so don't match the filenames with a filename globbing pattern. Instead, construct the names from the strings read from the list:

#!/bin/sh

while read -r name; do
 cat "x/$name/$name.pest"
done <y/list >concatenated.pest

This would concatenate all the relevant .pest files and create a single file called concatenated.pest from these in the current directory, in the order read from y/list.

With a bit of checking included:

#!/bin/sh

while read -r name; do
 pathname="x/$name/$name.pest"

 if [ ! -f "$pathname" ]; then
 printf 'Can not find %sn' "$pathname"
 echo 'Output file will be incomplete'
 exit 1
 fi >&2

 cat "$pathname"
done <y/list >concatenated.pest

share|improve this answer

edited 7 hours ago

answered 8 hours ago

Kusalananda♦Kusalananda

153k1818 gold badges302302 silver badges483483 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Thank you!!! I'm still wondering how would be if my subdirectories didnt have same names as in list though...
  
  – Madza Yasodara Farias Virgens
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @MadzaYasodaraFariasVirgens In this question, the do all have the same names as the actual .pest file. If they don't, then maybe they follow some other pattern that would be easily handled. If not, you may want to ask a separate question about that, but I doubt it would be too difficult.
  
  – Kusalananda♦
  7 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  got it! k I'll post as a different question bc I'm also having to process some files like that. thxs
  
  – Madza Yasodara Farias Virgens
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I posted a modified version of the answer to illustrate the easiest way to handle differently named subdirectories.
  
  – Wildcard
  7 hours ago
  

  
  
  
  

add a comment | 

3

You have the order in a list, so don't match the filenames with a filename globbing pattern. Instead, construct the names from the strings read from the list:

#!/bin/sh

while read -r name; do
 cat "x/$name/$name.pest"
done <y/list >concatenated.pest

This would concatenate all the relevant .pest files and create a single file called concatenated.pest from these in the current directory, in the order read from y/list.

With a bit of checking included:

#!/bin/sh

while read -r name; do
 pathname="x/$name/$name.pest"

 if [ ! -f "$pathname" ]; then
 printf 'Can not find %sn' "$pathname"
 echo 'Output file will be incomplete'
 exit 1
 fi >&2

 cat "$pathname"
done <y/list >concatenated.pest

share|improve this answer

edited 7 hours ago

answered 8 hours ago

Kusalananda♦Kusalananda

153k1818 gold badges302302 silver badges483483 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Thank you!!! I'm still wondering how would be if my subdirectories didnt have same names as in list though...
  
  – Madza Yasodara Farias Virgens
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @MadzaYasodaraFariasVirgens In this question, the do all have the same names as the actual .pest file. If they don't, then maybe they follow some other pattern that would be easily handled. If not, you may want to ask a separate question about that, but I doubt it would be too difficult.
  
  – Kusalananda♦
  7 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  got it! k I'll post as a different question bc I'm also having to process some files like that. thxs
  
  – Madza Yasodara Farias Virgens
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I posted a modified version of the answer to illustrate the easiest way to handle differently named subdirectories.
  
  – Wildcard
  7 hours ago
  

  
  
  
  

add a comment | 

You have the order in a list, so don't match the filenames with a filename globbing pattern. Instead, construct the names from the strings read from the list:

#!/bin/sh

while read -r name; do
 cat "x/$name/$name.pest"
done <y/list >concatenated.pest

This would concatenate all the relevant .pest files and create a single file called concatenated.pest from these in the current directory, in the order read from y/list.

With a bit of checking included:

#!/bin/sh

while read -r name; do
 pathname="x/$name/$name.pest"

 if [ ! -f "$pathname" ]; then
 printf 'Can not find %sn' "$pathname"
 echo 'Output file will be incomplete'
 exit 1
 fi >&2

 cat "$pathname"
done <y/list >concatenated.pest

share|improve this answer

edited 7 hours ago

answered 8 hours ago

Kusalananda♦Kusalananda

153k1818 gold badges302302 silver badges483483 bronze badges

#!/bin/sh

while read -r name; do
 cat "x/$name/$name.pest"
done <y/list >concatenated.pest

#!/bin/sh

while read -r name; do
 pathname="x/$name/$name.pest"

 if [ ! -f "$pathname" ]; then
 printf 'Can not find %sn' "$pathname"
 echo 'Output file will be incomplete'
 exit 1
 fi >&2

 cat "$pathname"
done <y/list >concatenated.pest

share|improve this answer

edited 7 hours ago

answered 8 hours ago

Kusalananda♦Kusalananda

153k1818 gold badges302302 silver badges483483 bronze badges

answered 8 hours ago

Kusalananda♦Kusalananda

153k1818 gold badges302302 silver badges483483 bronze badges

answered 8 hours ago

Kusalananda♦Kusalananda

153k1818 gold badges302302 silver badges483483 bronze badges