Mfcttrf

Does a windmilling propeller create more drag than a stopped propeller in an engine out scenario?

How is dynamic resistance of a diode modeled for large voltage variations?

What was the primary motivation for a historical figure like Xenophon to create an extensive collection of written material?

Why did Nick Fury not hesitate in blowing up the plane he thought was carrying a nuke?

How to tease a romance without a cat and mouse chase?

What causes a person to remain in this world as a ghost?

How do you cope with rejection?

Barron states that 4.18×10⁸ joules equal 1 kcal, is this correct?

US F1 Visa grace period attending a conference

Gambler's Fallacy Dice

Eigenvalues of the Laplace-Beltrami operator on a compact Riemannnian manifold

Was Tyrion always a poor strategist?

Does the fact that we can only measure the two-way speed of light undermine the axiom of invariance?

List of lists elementwise greater/smaller than

What should I wear to go and sign an employment contract?

Is presenting a play showing Military characters in a bad light a crime in the US?

Removing Doubles Destroy Topology

Is there a word for pant sleeves?

Do seaplanes need to get clearance for takeoff?

How to draw with Tikz a chord parallel to AC that passes through a point?

3D Histogram / bar chart

Way of refund if scammed?

RAID 5/6 rebuild time calculation

Difference in 1 user doing 1000 iterations and 1000 users doing 1 iteration in Load testing

Reverse Array, Let Elements in New Array Equal Length of Original Array Elements - JavaScript

Length of a JavaScript objectHow do I check if an array includes an object in JavaScript?Which equals operator (== vs ===) should be used in JavaScript comparisons?Deleting an element from an array in PHPHow to insert an item into an array at a specific index (JavaScript)?How do I empty an array in JavaScript?Loop through an array in JavaScriptHow do I remove a particular element from an array in JavaScript?How can I add new array elements at the beginning of an array in Javascript?For-each over an array in JavaScript?

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;

7

I'm ultimately trying to solve this kata on Codewars.

I've been able to reverse the array into a string, but I don't know how to assign this string into individual elements of a specified length. I tried:

function ultimateReverse (array) 

 let newArray = array.join("").split("");
 let reversedArray = newArray.reverse();
 return reversedArray.join("");



console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

//!eiltonnacIdnasttubgibekilI

But the outcome that we want is:

["!", "eilt", "onn", "acIdn", "ast", "t", "ubgibe", "kilI"]

So according to the original array, the length of the first element should be 1, the length of the second element should be 4, the third should be length 3, and so on.

Is there a way to split a string into array of elements, each of a specified length?

I thought of creating an array of the lengths of the items from the original array by doing:

function ultimateReverse (array) 

let elementLengths = [];

let newArray = array.join("").split("");
let reversedArray = newArray.reverse().join("");

for (let i = 0; i < array.length; i++) 
 let element = array[i];
 elementLengths.push(element.length);


return reversedArray + " " + elementLengths;



console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

Now if I can just split the string into elements in an array based on the length of the original elements...

javascript arrays reverse string-length

share|improve this question

asked 3 hours ago

HappyHands31HappyHands31

1,12432138

add a comment | 

7

I'm ultimately trying to solve this kata on Codewars.

I've been able to reverse the array into a string, but I don't know how to assign this string into individual elements of a specified length. I tried:

function ultimateReverse (array) 

 let newArray = array.join("").split("");
 let reversedArray = newArray.reverse();
 return reversedArray.join("");



console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

//!eiltonnacIdnasttubgibekilI

But the outcome that we want is:

["!", "eilt", "onn", "acIdn", "ast", "t", "ubgibe", "kilI"]

So according to the original array, the length of the first element should be 1, the length of the second element should be 4, the third should be length 3, and so on.

Is there a way to split a string into array of elements, each of a specified length?

I thought of creating an array of the lengths of the items from the original array by doing:

function ultimateReverse (array) 

let elementLengths = [];

let newArray = array.join("").split("");
let reversedArray = newArray.reverse().join("");

for (let i = 0; i < array.length; i++) 
 let element = array[i];
 elementLengths.push(element.length);


return reversedArray + " " + elementLengths;



console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

Now if I can just split the string into elements in an array based on the length of the original elements...

javascript arrays reverse string-length

share|improve this question

asked 3 hours ago

HappyHands31HappyHands31

1,12432138

add a comment | 

I'm ultimately trying to solve this kata on Codewars.

I've been able to reverse the array into a string, but I don't know how to assign this string into individual elements of a specified length. I tried:

function ultimateReverse (array) 

 let newArray = array.join("").split("");
 let reversedArray = newArray.reverse();
 return reversedArray.join("");



console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

//!eiltonnacIdnasttubgibekilI

But the outcome that we want is:

["!", "eilt", "onn", "acIdn", "ast", "t", "ubgibe", "kilI"]

So according to the original array, the length of the first element should be 1, the length of the second element should be 4, the third should be length 3, and so on.

Is there a way to split a string into array of elements, each of a specified length?

I thought of creating an array of the lengths of the items from the original array by doing:

function ultimateReverse (array) 

let elementLengths = [];

let newArray = array.join("").split("");
let reversedArray = newArray.reverse().join("");

for (let i = 0; i < array.length; i++) 
 let element = array[i];
 elementLengths.push(element.length);


return reversedArray + " " + elementLengths;



console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

Now if I can just split the string into elements in an array based on the length of the original elements...

javascript arrays reverse string-length

share|improve this question

asked 3 hours ago

HappyHands31HappyHands31

1,12432138

function ultimateReverse (array) 

 let newArray = array.join("").split("");
 let reversedArray = newArray.reverse();
 return reversedArray.join("");



console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

//!eiltonnacIdnasttubgibekilI

function ultimateReverse (array) 

let elementLengths = [];

let newArray = array.join("").split("");
let reversedArray = newArray.reverse().join("");

for (let i = 0; i < array.length; i++) 
 let element = array[i];
 elementLengths.push(element.length);


return reversedArray + " " + elementLengths;



console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

share|improve this question

asked 3 hours ago

HappyHands31HappyHands31

1,12432138

share|improve this question

asked 3 hours ago

HappyHands31HappyHands31

1,12432138

asked 3 hours ago

HappyHands31HappyHands31

1,12432138

asked 3 hours ago

HappyHands31HappyHands31

1,12432138

1 Answer
1

active

oldest

votes

7

First construct the full reversed string, eg

!eiltonnacIdnasttubgibekilI

Then, from an array of the initial lengths (which can be done with a .map in advance), iterate over that array and slice that length from the reversed string, and push to an array:

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 let reversedStr = [...array.join("")].reverse().join('');
 const result = [];
 lengths.forEach((length) => 
 result.push(reversedStr.slice(0, length));
 reversedStr = reversedStr.slice(length);
 );
 return result;


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

Pushing to a new array on every iteration is usually the place to use .map, but I don't see a way to do it that elegantly, since you'd have to reference multiple outer variables, and change one of them:

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 const reversedStr = [...array.join("")].reverse().join('');
 let startIndex = 0;
 let endIndex = 0;
 return lengths.map(length => 
 startIndex = endIndex;
 endIndex = startIndex + length;
 return reversedStr.slice(startIndex, startIndex + length);
 );


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

share|improve this answer

edited 3 hours ago

answered 3 hours ago

CertainPerformanceCertainPerformance

107k166999

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks @CertainPerformance - it certainly works. Can you please explain a little more about length on line 2 - length is an object, in this case?
  
  – HappyHands31
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  That's destructuring. propName inside a parameter list extracts the property named propName from the item at that position in the parameter list, and puts it into a variable named propName. The .length of a string is an integer.
  
  – CertainPerformance
  2 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please explain the reason why the parens wrapping length are needed. Otherwise error: unknown: Unexpected token, expected ","
  
  – sandthorn
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @sandthorn I think it's because the parser sees length without parentheses as an object, and then chokes up when it sees => following the object. Not entirely sure, I'm going to look into it. If I don't see a good answer to it, I'll probably write up a Q+A myself once I figure out what's going on
  
  – CertainPerformance
  2 hours ago
  

  
  
  
  

add a comment | 

Your Answer

StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f56204534%2freverse-array-let-elements-in-new-array-equal-length-of-original-array-elements%23new-answer', 'question_page');

);

Post as a guest

Name

Email

Required, but never shown

7

First construct the full reversed string, eg

!eiltonnacIdnasttubgibekilI

Then, from an array of the initial lengths (which can be done with a .map in advance), iterate over that array and slice that length from the reversed string, and push to an array:

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 let reversedStr = [...array.join("")].reverse().join('');
 const result = [];
 lengths.forEach((length) => 
 result.push(reversedStr.slice(0, length));
 reversedStr = reversedStr.slice(length);
 );
 return result;


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

Pushing to a new array on every iteration is usually the place to use .map, but I don't see a way to do it that elegantly, since you'd have to reference multiple outer variables, and change one of them:

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 const reversedStr = [...array.join("")].reverse().join('');
 let startIndex = 0;
 let endIndex = 0;
 return lengths.map(length => 
 startIndex = endIndex;
 endIndex = startIndex + length;
 return reversedStr.slice(startIndex, startIndex + length);
 );


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

share|improve this answer

edited 3 hours ago

answered 3 hours ago

CertainPerformanceCertainPerformance

107k166999

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks @CertainPerformance - it certainly works. Can you please explain a little more about length on line 2 - length is an object, in this case?
  
  – HappyHands31
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  That's destructuring. propName inside a parameter list extracts the property named propName from the item at that position in the parameter list, and puts it into a variable named propName. The .length of a string is an integer.
  
  – CertainPerformance
  2 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please explain the reason why the parens wrapping length are needed. Otherwise error: unknown: Unexpected token, expected ","
  
  – sandthorn
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @sandthorn I think it's because the parser sees length without parentheses as an object, and then chokes up when it sees => following the object. Not entirely sure, I'm going to look into it. If I don't see a good answer to it, I'll probably write up a Q+A myself once I figure out what's going on
  
  – CertainPerformance
  2 hours ago
  

  
  
  
  

add a comment | 

7

First construct the full reversed string, eg

!eiltonnacIdnasttubgibekilI

Then, from an array of the initial lengths (which can be done with a .map in advance), iterate over that array and slice that length from the reversed string, and push to an array:

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 let reversedStr = [...array.join("")].reverse().join('');
 const result = [];
 lengths.forEach((length) => 
 result.push(reversedStr.slice(0, length));
 reversedStr = reversedStr.slice(length);
 );
 return result;


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

Pushing to a new array on every iteration is usually the place to use .map, but I don't see a way to do it that elegantly, since you'd have to reference multiple outer variables, and change one of them:

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 const reversedStr = [...array.join("")].reverse().join('');
 let startIndex = 0;
 let endIndex = 0;
 return lengths.map(length => 
 startIndex = endIndex;
 endIndex = startIndex + length;
 return reversedStr.slice(startIndex, startIndex + length);
 );


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

share|improve this answer

edited 3 hours ago

answered 3 hours ago

CertainPerformanceCertainPerformance

107k166999

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks @CertainPerformance - it certainly works. Can you please explain a little more about length on line 2 - length is an object, in this case?
  
  – HappyHands31
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  That's destructuring. propName inside a parameter list extracts the property named propName from the item at that position in the parameter list, and puts it into a variable named propName. The .length of a string is an integer.
  
  – CertainPerformance
  2 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please explain the reason why the parens wrapping length are needed. Otherwise error: unknown: Unexpected token, expected ","
  
  – sandthorn
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @sandthorn I think it's because the parser sees length without parentheses as an object, and then chokes up when it sees => following the object. Not entirely sure, I'm going to look into it. If I don't see a good answer to it, I'll probably write up a Q+A myself once I figure out what's going on
  
  – CertainPerformance
  2 hours ago
  

  
  
  
  

add a comment | 

First construct the full reversed string, eg

!eiltonnacIdnasttubgibekilI

Then, from an array of the initial lengths (which can be done with a .map in advance), iterate over that array and slice that length from the reversed string, and push to an array:

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 let reversedStr = [...array.join("")].reverse().join('');
 const result = [];
 lengths.forEach((length) => 
 result.push(reversedStr.slice(0, length));
 reversedStr = reversedStr.slice(length);
 );
 return result;


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

Pushing to a new array on every iteration is usually the place to use .map, but I don't see a way to do it that elegantly, since you'd have to reference multiple outer variables, and change one of them:

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 const reversedStr = [...array.join("")].reverse().join('');
 let startIndex = 0;
 let endIndex = 0;
 return lengths.map(length => 
 startIndex = endIndex;
 endIndex = startIndex + length;
 return reversedStr.slice(startIndex, startIndex + length);
 );


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

share|improve this answer

edited 3 hours ago

answered 3 hours ago

CertainPerformanceCertainPerformance

107k166999

!eiltonnacIdnasttubgibekilI

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 let reversedStr = [...array.join("")].reverse().join('');
 const result = [];
 lengths.forEach((length) => 
 result.push(reversedStr.slice(0, length));
 reversedStr = reversedStr.slice(length);
 );
 return result;


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 const reversedStr = [...array.join("")].reverse().join('');
 let startIndex = 0;
 let endIndex = 0;
 return lengths.map(length => 
 startIndex = endIndex;
 endIndex = startIndex + length;
 return reversedStr.slice(startIndex, startIndex + length);
 );


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 let reversedStr = [...array.join("")].reverse().join('');
 const result = [];
 lengths.forEach((length) => 
 result.push(reversedStr.slice(0, length));
 reversedStr = reversedStr.slice(length);
 );
 return result;


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 let reversedStr = [...array.join("")].reverse().join('');
 const result = [];
 lengths.forEach((length) => 
 result.push(reversedStr.slice(0, length));
 reversedStr = reversedStr.slice(length);
 );
 return result;


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 const reversedStr = [...array.join("")].reverse().join('');
 let startIndex = 0;
 let endIndex = 0;
 return lengths.map(length => 
 startIndex = endIndex;
 endIndex = startIndex + length;
 return reversedStr.slice(startIndex, startIndex + length);
 );


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

function ultimateReverse(array) 
 const lengths = array.map(( length ) => length);
 const reversedStr = [...array.join("")].reverse().join('');
 let startIndex = 0;
 let endIndex = 0;
 return lengths.map(length => 
 startIndex = endIndex;
 endIndex = startIndex + length;
 return reversedStr.slice(startIndex, startIndex + length);
 );


console.log(ultimateReverse(["I", "like", "big", "butts", "and", "I", "cannot", "lie!"]));

share|improve this answer

edited 3 hours ago

answered 3 hours ago

CertainPerformanceCertainPerformance

107k166999

answered 3 hours ago

CertainPerformanceCertainPerformance

107k166999

answered 3 hours ago

CertainPerformanceCertainPerformance

107k166999