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Can I reproduce this in Latex


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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;









12

















Is there an easy way to reproduce the following image in latex?
enter image description here










share|improve this question





















  • 5





    Welcome to TeX.SX! On this site, a question should typically revolve around an abstract issue (e.g. "How do I get a double horizontal line in a table?") rather than a concrete application (e.g. "How do I make this table?"). Questions that look like "Please do this complicated thing for me" tend to get closed because they are either "off topic", "too broad", or "unclear". Please try to make your question clear and simple by giving a minimal working example (MWE): you'll stand a greater chance of getting help.

    – Stefan Pinnow
    Oct 13 at 7:23

















12

















Is there an easy way to reproduce the following image in latex?
enter image description here










share|improve this question





















  • 5





    Welcome to TeX.SX! On this site, a question should typically revolve around an abstract issue (e.g. "How do I get a double horizontal line in a table?") rather than a concrete application (e.g. "How do I make this table?"). Questions that look like "Please do this complicated thing for me" tend to get closed because they are either "off topic", "too broad", or "unclear". Please try to make your question clear and simple by giving a minimal working example (MWE): you'll stand a greater chance of getting help.

    – Stefan Pinnow
    Oct 13 at 7:23













12












12








12


7






Is there an easy way to reproduce the following image in latex?
enter image description here










share|improve this question















Is there an easy way to reproduce the following image in latex?
enter image description here







tikz-pgf tikz-graphdrawing






share|improve this question














share|improve this question











share|improve this question




share|improve this question










asked Oct 13 at 7:12









user199255user199255

721 silver badge4 bronze badges




721 silver badge4 bronze badges










  • 5





    Welcome to TeX.SX! On this site, a question should typically revolve around an abstract issue (e.g. "How do I get a double horizontal line in a table?") rather than a concrete application (e.g. "How do I make this table?"). Questions that look like "Please do this complicated thing for me" tend to get closed because they are either "off topic", "too broad", or "unclear". Please try to make your question clear and simple by giving a minimal working example (MWE): you'll stand a greater chance of getting help.

    – Stefan Pinnow
    Oct 13 at 7:23












  • 5





    Welcome to TeX.SX! On this site, a question should typically revolve around an abstract issue (e.g. "How do I get a double horizontal line in a table?") rather than a concrete application (e.g. "How do I make this table?"). Questions that look like "Please do this complicated thing for me" tend to get closed because they are either "off topic", "too broad", or "unclear". Please try to make your question clear and simple by giving a minimal working example (MWE): you'll stand a greater chance of getting help.

    – Stefan Pinnow
    Oct 13 at 7:23







5




5





Welcome to TeX.SX! On this site, a question should typically revolve around an abstract issue (e.g. "How do I get a double horizontal line in a table?") rather than a concrete application (e.g. "How do I make this table?"). Questions that look like "Please do this complicated thing for me" tend to get closed because they are either "off topic", "too broad", or "unclear". Please try to make your question clear and simple by giving a minimal working example (MWE): you'll stand a greater chance of getting help.

– Stefan Pinnow
Oct 13 at 7:23





Welcome to TeX.SX! On this site, a question should typically revolve around an abstract issue (e.g. "How do I get a double horizontal line in a table?") rather than a concrete application (e.g. "How do I make this table?"). Questions that look like "Please do this complicated thing for me" tend to get closed because they are either "off topic", "too broad", or "unclear". Please try to make your question clear and simple by giving a minimal working example (MWE): you'll stand a greater chance of getting help.

– Stefan Pinnow
Oct 13 at 7:23










3 Answers
3






active

oldest

votes


















27


















enter image description here



documentclass[tikz, margin=3mm]standalone
usetikzlibrarychains,
positioning

usepackageamsmath

begindocument
begintikzpicture[
node distance = 1pt and 0pt,
start chain = going right,
block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
on chain,
dot/.style = circle, fill, node contents=
]
foreach i in 0,...,14
node (ni) [block] i;

draw (n0.north west) -- (n14.north east);
draw (n1.south west) -- ++ (0,-0.2) -| (n13.south east)
node[pos=0.25,below] $textRange = 13 - 1 = 12$;
node [dot,above=of n1];
node [dot,above=of n2];
node (d4) [dot,above=of n4];
node [dot,above=of d4];
node [dot,above=of n6];
node (d8) [dot,above=of n8];
node (d8a) [dot,above=of d8];
node [dot, above=of d8a];
node [dot, above=of n9];
node (d11) [dot, above=of n11];
node [dot, above=of d11];
node [dot, above=of n12];
node [dot, above=of n13];
endtikzpicture
enddocument


Addedndum (1):
you can define nodes styles for two and three dots. With them the code for picture is:



documentclass[tikz, margin=3mm]standalone
usetikzlibrarychains,
positioning

usepackageamsmath

begindocument
begintikzpicture[
node distance = 1pt and 0pt,
start chain = going right,
block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
on chain,
dot/.style = circle, fill, node contents=,
ddot/.style = circle, fill,
append after command=node[dot,above=of tikzlastnode],
node contents=,
dddot/.style = circle, fill,
append after command=node (aux) [dot,above=of tikzlastnode]
node [dot,above=of aux],
node contents=
]
foreach i in 0,...,14
node (ni) [block] i;

draw (n0.north west) -- (n14.north east);
draw (n1.south west) -- ++ (0,-0.2) -| (n13.south east)
node[pos=0.25,below] $textRange = 13 - 1 = 12$;
%
node [dot,above=of n1];
node [dot,above=of n2];
node [ddot,above=of n4]; % <---
node [dot,above=of n6];
node [dddot,above=of n8]; % <---
node [dot, above=of n9];
node [ddot, above=of n11];% <---
node [dot, above=of n12];
node [dot, above=of n13];
endtikzpicture
enddocument


Addedndum (2):
version with dots as labels in the loop. A bit shorter code:



documentclass[tikz, margin=3mm]standalone
usetikzlibrarychains,
positioning

usepackageamsmath

begindocument
begintikzpicture[
node distance = 1pt and 0pt,
start chain = going right,
block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
on chain,
dot/.style = circle, fill, node contents=,
ddot/.style = circle, fill,
append after command=node[dot,above=of tikzlastnode],
dddot/.style = circle, fill,
append after command=node (aux) [dot,above=of tikzlastnode]
node [dot,above=of aux],
node contents=
]
foreach i [count=j from 0] in , dot, dot, ,ddot, , dot,
,dddot,dot, ,ddot, dot, dot,
node (nj) [block, label=[yshift=3pt,i]] j;

draw (n0.north west) -- (n14.north east);
draw (n1.south) -- ++ (0,-0.1) -| (n13.south)
node[pos=0.25,below] $textRange = 13 - 1 = 12$;
endtikzpicture
enddocument


Result is the same as before.






share|improve this answer




























  • "Result is the same" except you corrected an error (the too-short bar below). Excellent!

    – user3445853
    Oct 15 at 12:35











  • @user3445853, almost the same ... :-), recently I experiences some difficulties to upload images, so I didn't provide the recent one :-( (which not differ very much from showed)

    – Zarko
    Oct 15 at 12:42


















27


















Use pics. You can define a pic tower list which draws the circles. Getting all the x coordinates and circles is then as simple as saying



 pictower list=0,1,1,0,2,0,1,0,3,1,0,2,1,1,0;


where the integers indicate how many circles should be drawn at 0, 1, 2....



documentclass[tikz,border=3mm]standalone
begindocument
begintikzpicture[font=sffamily,pics/tower/.style=code=
ifnum#1>0
foreach X in 1,...,#1fill (0,X*0.4) circle[radius=0.17cm];
fi,
pics/tower list/.style=code=path foreach Y [count=Z starting from 0] in #1
(Z*0.5,0)node[below](tower-Z)$mathsfZ$ (Z*0.5,0) pictower=Y;]
beginscope
pictower list=0,1,1,0,2,0,1,0,3,1,0,2,1,1,0;
draw (tower-0.west|-0,0) -- (tower-13.east|-0,0);
draw[blue] (tower-1.south) -- ++(0,-0.1)
-| (tower-13.south)
node[pos=0.25,below]Range$=mathsf13-mathsf1=mathsf12$;
endscope
endtikzpicture
enddocument


enter image description here






share|improve this answer




























  • Hello, then with such a technique you can built an Italian abacus with units, tens, hundreds? +1. Can I ask a question on LaTeX with reference to your code?

    – Sebastiano
    Oct 13 at 8:32







  • 1





    @Sebastiano Sure you can define an abacus pic (will be back in a bit...)

    – Schrödinger's cat
    Oct 13 at 8:41


















16


















You don't really need TiKZ for this. Just marvosym, booktabs and stackengine:



documentclassarticle
usepackage[utf8]inputenc
usepackage[T1]fontenc
usepackagemarvosym
usepackage[svgnames, table]xcolor
newcommandMVTenMVOneMVZero
newcommandMVxiMVOneMVOne
newcommandMVxiiMVOneMVTwo
newcommandMVxiiiMVOneMVThree
newcommandMVxivMVOneMVFour
usepackagearray,booktabs
usepackage[usestackEOL]stackengine

begindocument

setstackgapS0pt
begintabular*15c
& CircSteel & CircSteel & & ShortstackCircSteel\ CircSteel & & CircSteel & & ShortstackCircSteel\ CircSteel\ CircSteel & CircSteel & & ShortstackCircSteel\ CircSteel & CircSteel & CircSteel \[-0.6ex]
midrule[1pt]
MVZero & MVOne & MVTwo & MVThree & MVFour & MVFive & MVSix & MVSeven & MVEight & MVNine & MVTen & MVxi & MVxii & MVxiii & MVxiv \[-1ex]
arrayrulecolorLightSlateBlue!60 &colorLightSlateBlue!60 rule1pt1.3ex & multicolumn11c & colorLightSlateBlue!60rule1pt1.3ex \[-1.46ex]
cmidrule[1pt](l0.88emr1.19em)2-14addlinespace[-0.3ex]
& multicolumn13csffamilybfseries Range = 13 – 1 = 12
endtabular

enddocument


enter image description here






share|improve this answer



























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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    27


















    enter image description here



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarychains,
    positioning

    usepackageamsmath

    begindocument
    begintikzpicture[
    node distance = 1pt and 0pt,
    start chain = going right,
    block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
    on chain,
    dot/.style = circle, fill, node contents=
    ]
    foreach i in 0,...,14
    node (ni) [block] i;

    draw (n0.north west) -- (n14.north east);
    draw (n1.south west) -- ++ (0,-0.2) -| (n13.south east)
    node[pos=0.25,below] $textRange = 13 - 1 = 12$;
    node [dot,above=of n1];
    node [dot,above=of n2];
    node (d4) [dot,above=of n4];
    node [dot,above=of d4];
    node [dot,above=of n6];
    node (d8) [dot,above=of n8];
    node (d8a) [dot,above=of d8];
    node [dot, above=of d8a];
    node [dot, above=of n9];
    node (d11) [dot, above=of n11];
    node [dot, above=of d11];
    node [dot, above=of n12];
    node [dot, above=of n13];
    endtikzpicture
    enddocument


    Addedndum (1):
    you can define nodes styles for two and three dots. With them the code for picture is:



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarychains,
    positioning

    usepackageamsmath

    begindocument
    begintikzpicture[
    node distance = 1pt and 0pt,
    start chain = going right,
    block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
    on chain,
    dot/.style = circle, fill, node contents=,
    ddot/.style = circle, fill,
    append after command=node[dot,above=of tikzlastnode],
    node contents=,
    dddot/.style = circle, fill,
    append after command=node (aux) [dot,above=of tikzlastnode]
    node [dot,above=of aux],
    node contents=
    ]
    foreach i in 0,...,14
    node (ni) [block] i;

    draw (n0.north west) -- (n14.north east);
    draw (n1.south west) -- ++ (0,-0.2) -| (n13.south east)
    node[pos=0.25,below] $textRange = 13 - 1 = 12$;
    %
    node [dot,above=of n1];
    node [dot,above=of n2];
    node [ddot,above=of n4]; % <---
    node [dot,above=of n6];
    node [dddot,above=of n8]; % <---
    node [dot, above=of n9];
    node [ddot, above=of n11];% <---
    node [dot, above=of n12];
    node [dot, above=of n13];
    endtikzpicture
    enddocument


    Addedndum (2):
    version with dots as labels in the loop. A bit shorter code:



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarychains,
    positioning

    usepackageamsmath

    begindocument
    begintikzpicture[
    node distance = 1pt and 0pt,
    start chain = going right,
    block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
    on chain,
    dot/.style = circle, fill, node contents=,
    ddot/.style = circle, fill,
    append after command=node[dot,above=of tikzlastnode],
    dddot/.style = circle, fill,
    append after command=node (aux) [dot,above=of tikzlastnode]
    node [dot,above=of aux],
    node contents=
    ]
    foreach i [count=j from 0] in , dot, dot, ,ddot, , dot,
    ,dddot,dot, ,ddot, dot, dot,
    node (nj) [block, label=[yshift=3pt,i]] j;

    draw (n0.north west) -- (n14.north east);
    draw (n1.south) -- ++ (0,-0.1) -| (n13.south)
    node[pos=0.25,below] $textRange = 13 - 1 = 12$;
    endtikzpicture
    enddocument


    Result is the same as before.






    share|improve this answer




























    • "Result is the same" except you corrected an error (the too-short bar below). Excellent!

      – user3445853
      Oct 15 at 12:35











    • @user3445853, almost the same ... :-), recently I experiences some difficulties to upload images, so I didn't provide the recent one :-( (which not differ very much from showed)

      – Zarko
      Oct 15 at 12:42















    27


















    enter image description here



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarychains,
    positioning

    usepackageamsmath

    begindocument
    begintikzpicture[
    node distance = 1pt and 0pt,
    start chain = going right,
    block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
    on chain,
    dot/.style = circle, fill, node contents=
    ]
    foreach i in 0,...,14
    node (ni) [block] i;

    draw (n0.north west) -- (n14.north east);
    draw (n1.south west) -- ++ (0,-0.2) -| (n13.south east)
    node[pos=0.25,below] $textRange = 13 - 1 = 12$;
    node [dot,above=of n1];
    node [dot,above=of n2];
    node (d4) [dot,above=of n4];
    node [dot,above=of d4];
    node [dot,above=of n6];
    node (d8) [dot,above=of n8];
    node (d8a) [dot,above=of d8];
    node [dot, above=of d8a];
    node [dot, above=of n9];
    node (d11) [dot, above=of n11];
    node [dot, above=of d11];
    node [dot, above=of n12];
    node [dot, above=of n13];
    endtikzpicture
    enddocument


    Addedndum (1):
    you can define nodes styles for two and three dots. With them the code for picture is:



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarychains,
    positioning

    usepackageamsmath

    begindocument
    begintikzpicture[
    node distance = 1pt and 0pt,
    start chain = going right,
    block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
    on chain,
    dot/.style = circle, fill, node contents=,
    ddot/.style = circle, fill,
    append after command=node[dot,above=of tikzlastnode],
    node contents=,
    dddot/.style = circle, fill,
    append after command=node (aux) [dot,above=of tikzlastnode]
    node [dot,above=of aux],
    node contents=
    ]
    foreach i in 0,...,14
    node (ni) [block] i;

    draw (n0.north west) -- (n14.north east);
    draw (n1.south west) -- ++ (0,-0.2) -| (n13.south east)
    node[pos=0.25,below] $textRange = 13 - 1 = 12$;
    %
    node [dot,above=of n1];
    node [dot,above=of n2];
    node [ddot,above=of n4]; % <---
    node [dot,above=of n6];
    node [dddot,above=of n8]; % <---
    node [dot, above=of n9];
    node [ddot, above=of n11];% <---
    node [dot, above=of n12];
    node [dot, above=of n13];
    endtikzpicture
    enddocument


    Addedndum (2):
    version with dots as labels in the loop. A bit shorter code:



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarychains,
    positioning

    usepackageamsmath

    begindocument
    begintikzpicture[
    node distance = 1pt and 0pt,
    start chain = going right,
    block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
    on chain,
    dot/.style = circle, fill, node contents=,
    ddot/.style = circle, fill,
    append after command=node[dot,above=of tikzlastnode],
    dddot/.style = circle, fill,
    append after command=node (aux) [dot,above=of tikzlastnode]
    node [dot,above=of aux],
    node contents=
    ]
    foreach i [count=j from 0] in , dot, dot, ,ddot, , dot,
    ,dddot,dot, ,ddot, dot, dot,
    node (nj) [block, label=[yshift=3pt,i]] j;

    draw (n0.north west) -- (n14.north east);
    draw (n1.south) -- ++ (0,-0.1) -| (n13.south)
    node[pos=0.25,below] $textRange = 13 - 1 = 12$;
    endtikzpicture
    enddocument


    Result is the same as before.






    share|improve this answer




























    • "Result is the same" except you corrected an error (the too-short bar below). Excellent!

      – user3445853
      Oct 15 at 12:35











    • @user3445853, almost the same ... :-), recently I experiences some difficulties to upload images, so I didn't provide the recent one :-( (which not differ very much from showed)

      – Zarko
      Oct 15 at 12:42













    27














    27










    27









    enter image description here



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarychains,
    positioning

    usepackageamsmath

    begindocument
    begintikzpicture[
    node distance = 1pt and 0pt,
    start chain = going right,
    block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
    on chain,
    dot/.style = circle, fill, node contents=
    ]
    foreach i in 0,...,14
    node (ni) [block] i;

    draw (n0.north west) -- (n14.north east);
    draw (n1.south west) -- ++ (0,-0.2) -| (n13.south east)
    node[pos=0.25,below] $textRange = 13 - 1 = 12$;
    node [dot,above=of n1];
    node [dot,above=of n2];
    node (d4) [dot,above=of n4];
    node [dot,above=of d4];
    node [dot,above=of n6];
    node (d8) [dot,above=of n8];
    node (d8a) [dot,above=of d8];
    node [dot, above=of d8a];
    node [dot, above=of n9];
    node (d11) [dot, above=of n11];
    node [dot, above=of d11];
    node [dot, above=of n12];
    node [dot, above=of n13];
    endtikzpicture
    enddocument


    Addedndum (1):
    you can define nodes styles for two and three dots. With them the code for picture is:



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarychains,
    positioning

    usepackageamsmath

    begindocument
    begintikzpicture[
    node distance = 1pt and 0pt,
    start chain = going right,
    block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
    on chain,
    dot/.style = circle, fill, node contents=,
    ddot/.style = circle, fill,
    append after command=node[dot,above=of tikzlastnode],
    node contents=,
    dddot/.style = circle, fill,
    append after command=node (aux) [dot,above=of tikzlastnode]
    node [dot,above=of aux],
    node contents=
    ]
    foreach i in 0,...,14
    node (ni) [block] i;

    draw (n0.north west) -- (n14.north east);
    draw (n1.south west) -- ++ (0,-0.2) -| (n13.south east)
    node[pos=0.25,below] $textRange = 13 - 1 = 12$;
    %
    node [dot,above=of n1];
    node [dot,above=of n2];
    node [ddot,above=of n4]; % <---
    node [dot,above=of n6];
    node [dddot,above=of n8]; % <---
    node [dot, above=of n9];
    node [ddot, above=of n11];% <---
    node [dot, above=of n12];
    node [dot, above=of n13];
    endtikzpicture
    enddocument


    Addedndum (2):
    version with dots as labels in the loop. A bit shorter code:



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarychains,
    positioning

    usepackageamsmath

    begindocument
    begintikzpicture[
    node distance = 1pt and 0pt,
    start chain = going right,
    block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
    on chain,
    dot/.style = circle, fill, node contents=,
    ddot/.style = circle, fill,
    append after command=node[dot,above=of tikzlastnode],
    dddot/.style = circle, fill,
    append after command=node (aux) [dot,above=of tikzlastnode]
    node [dot,above=of aux],
    node contents=
    ]
    foreach i [count=j from 0] in , dot, dot, ,ddot, , dot,
    ,dddot,dot, ,ddot, dot, dot,
    node (nj) [block, label=[yshift=3pt,i]] j;

    draw (n0.north west) -- (n14.north east);
    draw (n1.south) -- ++ (0,-0.1) -| (n13.south)
    node[pos=0.25,below] $textRange = 13 - 1 = 12$;
    endtikzpicture
    enddocument


    Result is the same as before.






    share|improve this answer
















    enter image description here



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarychains,
    positioning

    usepackageamsmath

    begindocument
    begintikzpicture[
    node distance = 1pt and 0pt,
    start chain = going right,
    block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
    on chain,
    dot/.style = circle, fill, node contents=
    ]
    foreach i in 0,...,14
    node (ni) [block] i;

    draw (n0.north west) -- (n14.north east);
    draw (n1.south west) -- ++ (0,-0.2) -| (n13.south east)
    node[pos=0.25,below] $textRange = 13 - 1 = 12$;
    node [dot,above=of n1];
    node [dot,above=of n2];
    node (d4) [dot,above=of n4];
    node [dot,above=of d4];
    node [dot,above=of n6];
    node (d8) [dot,above=of n8];
    node (d8a) [dot,above=of d8];
    node [dot, above=of d8a];
    node [dot, above=of n9];
    node (d11) [dot, above=of n11];
    node [dot, above=of d11];
    node [dot, above=of n12];
    node [dot, above=of n13];
    endtikzpicture
    enddocument


    Addedndum (1):
    you can define nodes styles for two and three dots. With them the code for picture is:



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarychains,
    positioning

    usepackageamsmath

    begindocument
    begintikzpicture[
    node distance = 1pt and 0pt,
    start chain = going right,
    block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
    on chain,
    dot/.style = circle, fill, node contents=,
    ddot/.style = circle, fill,
    append after command=node[dot,above=of tikzlastnode],
    node contents=,
    dddot/.style = circle, fill,
    append after command=node (aux) [dot,above=of tikzlastnode]
    node [dot,above=of aux],
    node contents=
    ]
    foreach i in 0,...,14
    node (ni) [block] i;

    draw (n0.north west) -- (n14.north east);
    draw (n1.south west) -- ++ (0,-0.2) -| (n13.south east)
    node[pos=0.25,below] $textRange = 13 - 1 = 12$;
    %
    node [dot,above=of n1];
    node [dot,above=of n2];
    node [ddot,above=of n4]; % <---
    node [dot,above=of n6];
    node [dddot,above=of n8]; % <---
    node [dot, above=of n9];
    node [ddot, above=of n11];% <---
    node [dot, above=of n12];
    node [dot, above=of n13];
    endtikzpicture
    enddocument


    Addedndum (2):
    version with dots as labels in the loop. A bit shorter code:



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarychains,
    positioning

    usepackageamsmath

    begindocument
    begintikzpicture[
    node distance = 1pt and 0pt,
    start chain = going right,
    block/.style = rectangle, minimum width=1.5em, outer sep=0pt,
    on chain,
    dot/.style = circle, fill, node contents=,
    ddot/.style = circle, fill,
    append after command=node[dot,above=of tikzlastnode],
    dddot/.style = circle, fill,
    append after command=node (aux) [dot,above=of tikzlastnode]
    node [dot,above=of aux],
    node contents=
    ]
    foreach i [count=j from 0] in , dot, dot, ,ddot, , dot,
    ,dddot,dot, ,ddot, dot, dot,
    node (nj) [block, label=[yshift=3pt,i]] j;

    draw (n0.north west) -- (n14.north east);
    draw (n1.south) -- ++ (0,-0.1) -| (n13.south)
    node[pos=0.25,below] $textRange = 13 - 1 = 12$;
    endtikzpicture
    enddocument


    Result is the same as before.







    share|improve this answer















    share|improve this answer




    share|improve this answer








    edited Oct 14 at 7:33

























    answered Oct 13 at 8:11









    ZarkoZarko

    150k8 gold badges87 silver badges197 bronze badges




    150k8 gold badges87 silver badges197 bronze badges















    • "Result is the same" except you corrected an error (the too-short bar below). Excellent!

      – user3445853
      Oct 15 at 12:35











    • @user3445853, almost the same ... :-), recently I experiences some difficulties to upload images, so I didn't provide the recent one :-( (which not differ very much from showed)

      – Zarko
      Oct 15 at 12:42

















    • "Result is the same" except you corrected an error (the too-short bar below). Excellent!

      – user3445853
      Oct 15 at 12:35











    • @user3445853, almost the same ... :-), recently I experiences some difficulties to upload images, so I didn't provide the recent one :-( (which not differ very much from showed)

      – Zarko
      Oct 15 at 12:42
















    "Result is the same" except you corrected an error (the too-short bar below). Excellent!

    – user3445853
    Oct 15 at 12:35





    "Result is the same" except you corrected an error (the too-short bar below). Excellent!

    – user3445853
    Oct 15 at 12:35













    @user3445853, almost the same ... :-), recently I experiences some difficulties to upload images, so I didn't provide the recent one :-( (which not differ very much from showed)

    – Zarko
    Oct 15 at 12:42





    @user3445853, almost the same ... :-), recently I experiences some difficulties to upload images, so I didn't provide the recent one :-( (which not differ very much from showed)

    – Zarko
    Oct 15 at 12:42













    27


















    Use pics. You can define a pic tower list which draws the circles. Getting all the x coordinates and circles is then as simple as saying



     pictower list=0,1,1,0,2,0,1,0,3,1,0,2,1,1,0;


    where the integers indicate how many circles should be drawn at 0, 1, 2....



    documentclass[tikz,border=3mm]standalone
    begindocument
    begintikzpicture[font=sffamily,pics/tower/.style=code=
    ifnum#1>0
    foreach X in 1,...,#1fill (0,X*0.4) circle[radius=0.17cm];
    fi,
    pics/tower list/.style=code=path foreach Y [count=Z starting from 0] in #1
    (Z*0.5,0)node[below](tower-Z)$mathsfZ$ (Z*0.5,0) pictower=Y;]
    beginscope
    pictower list=0,1,1,0,2,0,1,0,3,1,0,2,1,1,0;
    draw (tower-0.west|-0,0) -- (tower-13.east|-0,0);
    draw[blue] (tower-1.south) -- ++(0,-0.1)
    -| (tower-13.south)
    node[pos=0.25,below]Range$=mathsf13-mathsf1=mathsf12$;
    endscope
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer




























    • Hello, then with such a technique you can built an Italian abacus with units, tens, hundreds? +1. Can I ask a question on LaTeX with reference to your code?

      – Sebastiano
      Oct 13 at 8:32







    • 1





      @Sebastiano Sure you can define an abacus pic (will be back in a bit...)

      – Schrödinger's cat
      Oct 13 at 8:41















    27


















    Use pics. You can define a pic tower list which draws the circles. Getting all the x coordinates and circles is then as simple as saying



     pictower list=0,1,1,0,2,0,1,0,3,1,0,2,1,1,0;


    where the integers indicate how many circles should be drawn at 0, 1, 2....



    documentclass[tikz,border=3mm]standalone
    begindocument
    begintikzpicture[font=sffamily,pics/tower/.style=code=
    ifnum#1>0
    foreach X in 1,...,#1fill (0,X*0.4) circle[radius=0.17cm];
    fi,
    pics/tower list/.style=code=path foreach Y [count=Z starting from 0] in #1
    (Z*0.5,0)node[below](tower-Z)$mathsfZ$ (Z*0.5,0) pictower=Y;]
    beginscope
    pictower list=0,1,1,0,2,0,1,0,3,1,0,2,1,1,0;
    draw (tower-0.west|-0,0) -- (tower-13.east|-0,0);
    draw[blue] (tower-1.south) -- ++(0,-0.1)
    -| (tower-13.south)
    node[pos=0.25,below]Range$=mathsf13-mathsf1=mathsf12$;
    endscope
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer




























    • Hello, then with such a technique you can built an Italian abacus with units, tens, hundreds? +1. Can I ask a question on LaTeX with reference to your code?

      – Sebastiano
      Oct 13 at 8:32







    • 1





      @Sebastiano Sure you can define an abacus pic (will be back in a bit...)

      – Schrödinger's cat
      Oct 13 at 8:41













    27














    27










    27









    Use pics. You can define a pic tower list which draws the circles. Getting all the x coordinates and circles is then as simple as saying



     pictower list=0,1,1,0,2,0,1,0,3,1,0,2,1,1,0;


    where the integers indicate how many circles should be drawn at 0, 1, 2....



    documentclass[tikz,border=3mm]standalone
    begindocument
    begintikzpicture[font=sffamily,pics/tower/.style=code=
    ifnum#1>0
    foreach X in 1,...,#1fill (0,X*0.4) circle[radius=0.17cm];
    fi,
    pics/tower list/.style=code=path foreach Y [count=Z starting from 0] in #1
    (Z*0.5,0)node[below](tower-Z)$mathsfZ$ (Z*0.5,0) pictower=Y;]
    beginscope
    pictower list=0,1,1,0,2,0,1,0,3,1,0,2,1,1,0;
    draw (tower-0.west|-0,0) -- (tower-13.east|-0,0);
    draw[blue] (tower-1.south) -- ++(0,-0.1)
    -| (tower-13.south)
    node[pos=0.25,below]Range$=mathsf13-mathsf1=mathsf12$;
    endscope
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer
















    Use pics. You can define a pic tower list which draws the circles. Getting all the x coordinates and circles is then as simple as saying



     pictower list=0,1,1,0,2,0,1,0,3,1,0,2,1,1,0;


    where the integers indicate how many circles should be drawn at 0, 1, 2....



    documentclass[tikz,border=3mm]standalone
    begindocument
    begintikzpicture[font=sffamily,pics/tower/.style=code=
    ifnum#1>0
    foreach X in 1,...,#1fill (0,X*0.4) circle[radius=0.17cm];
    fi,
    pics/tower list/.style=code=path foreach Y [count=Z starting from 0] in #1
    (Z*0.5,0)node[below](tower-Z)$mathsfZ$ (Z*0.5,0) pictower=Y;]
    beginscope
    pictower list=0,1,1,0,2,0,1,0,3,1,0,2,1,1,0;
    draw (tower-0.west|-0,0) -- (tower-13.east|-0,0);
    draw[blue] (tower-1.south) -- ++(0,-0.1)
    -| (tower-13.south)
    node[pos=0.25,below]Range$=mathsf13-mathsf1=mathsf12$;
    endscope
    endtikzpicture
    enddocument


    enter image description here







    share|improve this answer















    share|improve this answer




    share|improve this answer








    edited Oct 13 at 14:55

























    answered Oct 13 at 8:26









    Schrödinger's catSchrödinger's cat

    16k21 silver badges39 bronze badges




    16k21 silver badges39 bronze badges















    • Hello, then with such a technique you can built an Italian abacus with units, tens, hundreds? +1. Can I ask a question on LaTeX with reference to your code?

      – Sebastiano
      Oct 13 at 8:32







    • 1





      @Sebastiano Sure you can define an abacus pic (will be back in a bit...)

      – Schrödinger's cat
      Oct 13 at 8:41

















    • Hello, then with such a technique you can built an Italian abacus with units, tens, hundreds? +1. Can I ask a question on LaTeX with reference to your code?

      – Sebastiano
      Oct 13 at 8:32







    • 1





      @Sebastiano Sure you can define an abacus pic (will be back in a bit...)

      – Schrödinger's cat
      Oct 13 at 8:41
















    Hello, then with such a technique you can built an Italian abacus with units, tens, hundreds? +1. Can I ask a question on LaTeX with reference to your code?

    – Sebastiano
    Oct 13 at 8:32






    Hello, then with such a technique you can built an Italian abacus with units, tens, hundreds? +1. Can I ask a question on LaTeX with reference to your code?

    – Sebastiano
    Oct 13 at 8:32





    1




    1





    @Sebastiano Sure you can define an abacus pic (will be back in a bit...)

    – Schrödinger's cat
    Oct 13 at 8:41





    @Sebastiano Sure you can define an abacus pic (will be back in a bit...)

    – Schrödinger's cat
    Oct 13 at 8:41











    16


















    You don't really need TiKZ for this. Just marvosym, booktabs and stackengine:



    documentclassarticle
    usepackage[utf8]inputenc
    usepackage[T1]fontenc
    usepackagemarvosym
    usepackage[svgnames, table]xcolor
    newcommandMVTenMVOneMVZero
    newcommandMVxiMVOneMVOne
    newcommandMVxiiMVOneMVTwo
    newcommandMVxiiiMVOneMVThree
    newcommandMVxivMVOneMVFour
    usepackagearray,booktabs
    usepackage[usestackEOL]stackengine

    begindocument

    setstackgapS0pt
    begintabular*15c
    & CircSteel & CircSteel & & ShortstackCircSteel\ CircSteel & & CircSteel & & ShortstackCircSteel\ CircSteel\ CircSteel & CircSteel & & ShortstackCircSteel\ CircSteel & CircSteel & CircSteel \[-0.6ex]
    midrule[1pt]
    MVZero & MVOne & MVTwo & MVThree & MVFour & MVFive & MVSix & MVSeven & MVEight & MVNine & MVTen & MVxi & MVxii & MVxiii & MVxiv \[-1ex]
    arrayrulecolorLightSlateBlue!60 &colorLightSlateBlue!60 rule1pt1.3ex & multicolumn11c & colorLightSlateBlue!60rule1pt1.3ex \[-1.46ex]
    cmidrule[1pt](l0.88emr1.19em)2-14addlinespace[-0.3ex]
    & multicolumn13csffamilybfseries Range = 13 – 1 = 12
    endtabular

    enddocument


    enter image description here






    share|improve this answer






























      16


















      You don't really need TiKZ for this. Just marvosym, booktabs and stackengine:



      documentclassarticle
      usepackage[utf8]inputenc
      usepackage[T1]fontenc
      usepackagemarvosym
      usepackage[svgnames, table]xcolor
      newcommandMVTenMVOneMVZero
      newcommandMVxiMVOneMVOne
      newcommandMVxiiMVOneMVTwo
      newcommandMVxiiiMVOneMVThree
      newcommandMVxivMVOneMVFour
      usepackagearray,booktabs
      usepackage[usestackEOL]stackengine

      begindocument

      setstackgapS0pt
      begintabular*15c
      & CircSteel & CircSteel & & ShortstackCircSteel\ CircSteel & & CircSteel & & ShortstackCircSteel\ CircSteel\ CircSteel & CircSteel & & ShortstackCircSteel\ CircSteel & CircSteel & CircSteel \[-0.6ex]
      midrule[1pt]
      MVZero & MVOne & MVTwo & MVThree & MVFour & MVFive & MVSix & MVSeven & MVEight & MVNine & MVTen & MVxi & MVxii & MVxiii & MVxiv \[-1ex]
      arrayrulecolorLightSlateBlue!60 &colorLightSlateBlue!60 rule1pt1.3ex & multicolumn11c & colorLightSlateBlue!60rule1pt1.3ex \[-1.46ex]
      cmidrule[1pt](l0.88emr1.19em)2-14addlinespace[-0.3ex]
      & multicolumn13csffamilybfseries Range = 13 – 1 = 12
      endtabular

      enddocument


      enter image description here






      share|improve this answer




























        16














        16










        16









        You don't really need TiKZ for this. Just marvosym, booktabs and stackengine:



        documentclassarticle
        usepackage[utf8]inputenc
        usepackage[T1]fontenc
        usepackagemarvosym
        usepackage[svgnames, table]xcolor
        newcommandMVTenMVOneMVZero
        newcommandMVxiMVOneMVOne
        newcommandMVxiiMVOneMVTwo
        newcommandMVxiiiMVOneMVThree
        newcommandMVxivMVOneMVFour
        usepackagearray,booktabs
        usepackage[usestackEOL]stackengine

        begindocument

        setstackgapS0pt
        begintabular*15c
        & CircSteel & CircSteel & & ShortstackCircSteel\ CircSteel & & CircSteel & & ShortstackCircSteel\ CircSteel\ CircSteel & CircSteel & & ShortstackCircSteel\ CircSteel & CircSteel & CircSteel \[-0.6ex]
        midrule[1pt]
        MVZero & MVOne & MVTwo & MVThree & MVFour & MVFive & MVSix & MVSeven & MVEight & MVNine & MVTen & MVxi & MVxii & MVxiii & MVxiv \[-1ex]
        arrayrulecolorLightSlateBlue!60 &colorLightSlateBlue!60 rule1pt1.3ex & multicolumn11c & colorLightSlateBlue!60rule1pt1.3ex \[-1.46ex]
        cmidrule[1pt](l0.88emr1.19em)2-14addlinespace[-0.3ex]
        & multicolumn13csffamilybfseries Range = 13 – 1 = 12
        endtabular

        enddocument


        enter image description here






        share|improve this answer














        You don't really need TiKZ for this. Just marvosym, booktabs and stackengine:



        documentclassarticle
        usepackage[utf8]inputenc
        usepackage[T1]fontenc
        usepackagemarvosym
        usepackage[svgnames, table]xcolor
        newcommandMVTenMVOneMVZero
        newcommandMVxiMVOneMVOne
        newcommandMVxiiMVOneMVTwo
        newcommandMVxiiiMVOneMVThree
        newcommandMVxivMVOneMVFour
        usepackagearray,booktabs
        usepackage[usestackEOL]stackengine

        begindocument

        setstackgapS0pt
        begintabular*15c
        & CircSteel & CircSteel & & ShortstackCircSteel\ CircSteel & & CircSteel & & ShortstackCircSteel\ CircSteel\ CircSteel & CircSteel & & ShortstackCircSteel\ CircSteel & CircSteel & CircSteel \[-0.6ex]
        midrule[1pt]
        MVZero & MVOne & MVTwo & MVThree & MVFour & MVFive & MVSix & MVSeven & MVEight & MVNine & MVTen & MVxi & MVxii & MVxiii & MVxiv \[-1ex]
        arrayrulecolorLightSlateBlue!60 &colorLightSlateBlue!60 rule1pt1.3ex & multicolumn11c & colorLightSlateBlue!60rule1pt1.3ex \[-1.46ex]
        cmidrule[1pt](l0.88emr1.19em)2-14addlinespace[-0.3ex]
        & multicolumn13csffamilybfseries Range = 13 – 1 = 12
        endtabular

        enddocument


        enter image description here







        share|improve this answer













        share|improve this answer




        share|improve this answer










        answered Oct 13 at 12:03









        BernardBernard

        194k8 gold badges87 silver badges232 bronze badges




        194k8 gold badges87 silver badges232 bronze badges































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