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Cutting numbers into a specific decimals


How do I fetch only numbers in grep?How to calculate Pi decimals from a given offset?Is there a command to round decimal numbers in txt files?How to set default scale for bc calculator?How to grep two numbers from the same line at different places using bash?Separating even and odd numbersSED copy specific section to different filesCutting a string using sed






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2















I want to cut all numbers in a file to the fifth decimal only. For example, I have this file:



1.0
12.2348604202 0.0000000000 0.0000000000
0.0000000000 3.0320000648 0.0000000000
-1.3752052829 0.0000000000 5.6183021388
Ga O
8 12
Direct
0.590021042 0.500000000 0.794251030
0.409978979 0.500000000 0.205748985
0.909978943 0.000000000 0.205749006
0.090021023 -0.000000000 0.794251030
0.658887031 0.000000000 0.314083014


So, I want to have the same file but with numbers with 5 decimal places only.










share|improve this question
































    2















    I want to cut all numbers in a file to the fifth decimal only. For example, I have this file:



    1.0
    12.2348604202 0.0000000000 0.0000000000
    0.0000000000 3.0320000648 0.0000000000
    -1.3752052829 0.0000000000 5.6183021388
    Ga O
    8 12
    Direct
    0.590021042 0.500000000 0.794251030
    0.409978979 0.500000000 0.205748985
    0.909978943 0.000000000 0.205749006
    0.090021023 -0.000000000 0.794251030
    0.658887031 0.000000000 0.314083014


    So, I want to have the same file but with numbers with 5 decimal places only.










    share|improve this question




























      2












      2








      2








      I want to cut all numbers in a file to the fifth decimal only. For example, I have this file:



      1.0
      12.2348604202 0.0000000000 0.0000000000
      0.0000000000 3.0320000648 0.0000000000
      -1.3752052829 0.0000000000 5.6183021388
      Ga O
      8 12
      Direct
      0.590021042 0.500000000 0.794251030
      0.409978979 0.500000000 0.205748985
      0.909978943 0.000000000 0.205749006
      0.090021023 -0.000000000 0.794251030
      0.658887031 0.000000000 0.314083014


      So, I want to have the same file but with numbers with 5 decimal places only.










      share|improve this question
















      I want to cut all numbers in a file to the fifth decimal only. For example, I have this file:



      1.0
      12.2348604202 0.0000000000 0.0000000000
      0.0000000000 3.0320000648 0.0000000000
      -1.3752052829 0.0000000000 5.6183021388
      Ga O
      8 12
      Direct
      0.590021042 0.500000000 0.794251030
      0.409978979 0.500000000 0.205748985
      0.909978943 0.000000000 0.205749006
      0.090021023 -0.000000000 0.794251030
      0.658887031 0.000000000 0.314083014


      So, I want to have the same file but with numbers with 5 decimal places only.







      command-line






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 3 hours ago









      dessert

      28.8k7 gold badges86 silver badges119 bronze badges




      28.8k7 gold badges86 silver badges119 bronze badges










      asked 9 hours ago









      Eslam SaadEslam Saad

      183 bronze badges




      183 bronze badges























          4 Answers
          4






          active

          oldest

          votes


















          3















          You can use sed:



          sed -E 's/([0-9]+.[0-9]5)[0-9]*/1/g' file


          Add -i option to add file in place.






          share|improve this answer


































            2















            With GNU awk:



            awk 'print gensub(/([0-9]+.[0-9]5)[0-9]*/, "\1", "g")' input_file > output_file


            This uses the awk function gensub to select a decimal number (/([0-9]+.[0-9]5)[0-9]*/) from a given file (input_file) and split it into two parts. The first part has 5 decimal places (([0-9]+.[0-9]5)) and the second part is the rest of the decimal number (([0-9]*)). gensub then replaces the selected number with its first part ("\1") and does that for all the decimal numbers it can find ("g") in input_file.



            The command then saves the result to an output file (> output_file).






            share|improve this answer


































              2















              With GNU sed:



              sed -E 's/.([0-9]5)[0-9]*/.1/g' file


              Output:



              1.0
              12.23486 0.00000 0.00000
              0.00000 3.03200 0.00000
              -1.37520 0.00000 5.61830
              Ga O
              8 12
              Direct
              0.59002 0.50000 0.79425
              0.40997 0.50000 0.20574
              0.90997 0.00000 0.20574
              0.09002 -0.00000 0.79425
              0.65888 0.00000 0.31408



              Use extended regular expressions with -E:



              sed -E




              Match the pattern .<five digits><n digits> with .([0-9]5)[0-9]*. Capture the 5 digits following the dot . with ([0-9]5)



              s/.([0-9]5)[0-9]*/



              Replace the match with the dot . and the captured pattern:



              /.1/






              share|improve this answer



























              • Could you add an explanation and maybe an example output please?

                – dessert
                3 hours ago











              • @dessert done it.

                – guillermo chamorro
                2 hours ago


















              0















              If you don't mind the integers also being converted to floating point, you could use numfmt:



              $ numfmt --field=1- --format=%.5f --invalid=ignore < file
              1.00000
              12.23487 0.00000 0.00000
              0.00000 3.03201 0.00000
              -1.37521 0.00000 5.61831
              Ga O
              8.00000 12.00000
              Direct
              0.59003 0.50000 0.79426
              0.40998 0.50000 0.20575
              0.90998 0.00000 0.20575
              0.09003 0.00000 0.79426
              0.65889 0.00000 0.31409





              share|improve this answer



























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                4 Answers
                4






                active

                oldest

                votes








                4 Answers
                4






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                3















                You can use sed:



                sed -E 's/([0-9]+.[0-9]5)[0-9]*/1/g' file


                Add -i option to add file in place.






                share|improve this answer































                  3















                  You can use sed:



                  sed -E 's/([0-9]+.[0-9]5)[0-9]*/1/g' file


                  Add -i option to add file in place.






                  share|improve this answer





























                    3














                    3










                    3









                    You can use sed:



                    sed -E 's/([0-9]+.[0-9]5)[0-9]*/1/g' file


                    Add -i option to add file in place.






                    share|improve this answer















                    You can use sed:



                    sed -E 's/([0-9]+.[0-9]5)[0-9]*/1/g' file


                    Add -i option to add file in place.







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 8 hours ago

























                    answered 9 hours ago









                    pLumopLumo

                    10.8k23 silver badges51 bronze badges




                    10.8k23 silver badges51 bronze badges


























                        2















                        With GNU awk:



                        awk 'print gensub(/([0-9]+.[0-9]5)[0-9]*/, "\1", "g")' input_file > output_file


                        This uses the awk function gensub to select a decimal number (/([0-9]+.[0-9]5)[0-9]*/) from a given file (input_file) and split it into two parts. The first part has 5 decimal places (([0-9]+.[0-9]5)) and the second part is the rest of the decimal number (([0-9]*)). gensub then replaces the selected number with its first part ("\1") and does that for all the decimal numbers it can find ("g") in input_file.



                        The command then saves the result to an output file (> output_file).






                        share|improve this answer































                          2















                          With GNU awk:



                          awk 'print gensub(/([0-9]+.[0-9]5)[0-9]*/, "\1", "g")' input_file > output_file


                          This uses the awk function gensub to select a decimal number (/([0-9]+.[0-9]5)[0-9]*/) from a given file (input_file) and split it into two parts. The first part has 5 decimal places (([0-9]+.[0-9]5)) and the second part is the rest of the decimal number (([0-9]*)). gensub then replaces the selected number with its first part ("\1") and does that for all the decimal numbers it can find ("g") in input_file.



                          The command then saves the result to an output file (> output_file).






                          share|improve this answer





























                            2














                            2










                            2









                            With GNU awk:



                            awk 'print gensub(/([0-9]+.[0-9]5)[0-9]*/, "\1", "g")' input_file > output_file


                            This uses the awk function gensub to select a decimal number (/([0-9]+.[0-9]5)[0-9]*/) from a given file (input_file) and split it into two parts. The first part has 5 decimal places (([0-9]+.[0-9]5)) and the second part is the rest of the decimal number (([0-9]*)). gensub then replaces the selected number with its first part ("\1") and does that for all the decimal numbers it can find ("g") in input_file.



                            The command then saves the result to an output file (> output_file).






                            share|improve this answer















                            With GNU awk:



                            awk 'print gensub(/([0-9]+.[0-9]5)[0-9]*/, "\1", "g")' input_file > output_file


                            This uses the awk function gensub to select a decimal number (/([0-9]+.[0-9]5)[0-9]*/) from a given file (input_file) and split it into two parts. The first part has 5 decimal places (([0-9]+.[0-9]5)) and the second part is the rest of the decimal number (([0-9]*)). gensub then replaces the selected number with its first part ("\1") and does that for all the decimal numbers it can find ("g") in input_file.



                            The command then saves the result to an output file (> output_file).







                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited 3 hours ago

























                            answered 7 hours ago









                            user3140225user3140225

                            1,2867 silver badges19 bronze badges




                            1,2867 silver badges19 bronze badges
























                                2















                                With GNU sed:



                                sed -E 's/.([0-9]5)[0-9]*/.1/g' file


                                Output:



                                1.0
                                12.23486 0.00000 0.00000
                                0.00000 3.03200 0.00000
                                -1.37520 0.00000 5.61830
                                Ga O
                                8 12
                                Direct
                                0.59002 0.50000 0.79425
                                0.40997 0.50000 0.20574
                                0.90997 0.00000 0.20574
                                0.09002 -0.00000 0.79425
                                0.65888 0.00000 0.31408



                                Use extended regular expressions with -E:



                                sed -E




                                Match the pattern .<five digits><n digits> with .([0-9]5)[0-9]*. Capture the 5 digits following the dot . with ([0-9]5)



                                s/.([0-9]5)[0-9]*/



                                Replace the match with the dot . and the captured pattern:



                                /.1/






                                share|improve this answer



























                                • Could you add an explanation and maybe an example output please?

                                  – dessert
                                  3 hours ago











                                • @dessert done it.

                                  – guillermo chamorro
                                  2 hours ago















                                2















                                With GNU sed:



                                sed -E 's/.([0-9]5)[0-9]*/.1/g' file


                                Output:



                                1.0
                                12.23486 0.00000 0.00000
                                0.00000 3.03200 0.00000
                                -1.37520 0.00000 5.61830
                                Ga O
                                8 12
                                Direct
                                0.59002 0.50000 0.79425
                                0.40997 0.50000 0.20574
                                0.90997 0.00000 0.20574
                                0.09002 -0.00000 0.79425
                                0.65888 0.00000 0.31408



                                Use extended regular expressions with -E:



                                sed -E




                                Match the pattern .<five digits><n digits> with .([0-9]5)[0-9]*. Capture the 5 digits following the dot . with ([0-9]5)



                                s/.([0-9]5)[0-9]*/



                                Replace the match with the dot . and the captured pattern:



                                /.1/






                                share|improve this answer



























                                • Could you add an explanation and maybe an example output please?

                                  – dessert
                                  3 hours ago











                                • @dessert done it.

                                  – guillermo chamorro
                                  2 hours ago













                                2














                                2










                                2









                                With GNU sed:



                                sed -E 's/.([0-9]5)[0-9]*/.1/g' file


                                Output:



                                1.0
                                12.23486 0.00000 0.00000
                                0.00000 3.03200 0.00000
                                -1.37520 0.00000 5.61830
                                Ga O
                                8 12
                                Direct
                                0.59002 0.50000 0.79425
                                0.40997 0.50000 0.20574
                                0.90997 0.00000 0.20574
                                0.09002 -0.00000 0.79425
                                0.65888 0.00000 0.31408



                                Use extended regular expressions with -E:



                                sed -E




                                Match the pattern .<five digits><n digits> with .([0-9]5)[0-9]*. Capture the 5 digits following the dot . with ([0-9]5)



                                s/.([0-9]5)[0-9]*/



                                Replace the match with the dot . and the captured pattern:



                                /.1/






                                share|improve this answer















                                With GNU sed:



                                sed -E 's/.([0-9]5)[0-9]*/.1/g' file


                                Output:



                                1.0
                                12.23486 0.00000 0.00000
                                0.00000 3.03200 0.00000
                                -1.37520 0.00000 5.61830
                                Ga O
                                8 12
                                Direct
                                0.59002 0.50000 0.79425
                                0.40997 0.50000 0.20574
                                0.90997 0.00000 0.20574
                                0.09002 -0.00000 0.79425
                                0.65888 0.00000 0.31408



                                Use extended regular expressions with -E:



                                sed -E




                                Match the pattern .<five digits><n digits> with .([0-9]5)[0-9]*. Capture the 5 digits following the dot . with ([0-9]5)



                                s/.([0-9]5)[0-9]*/



                                Replace the match with the dot . and the captured pattern:



                                /.1/







                                share|improve this answer














                                share|improve this answer



                                share|improve this answer








                                edited 2 hours ago

























                                answered 9 hours ago









                                guillermo chamorroguillermo chamorro

                                5821 silver badge12 bronze badges




                                5821 silver badge12 bronze badges















                                • Could you add an explanation and maybe an example output please?

                                  – dessert
                                  3 hours ago











                                • @dessert done it.

                                  – guillermo chamorro
                                  2 hours ago

















                                • Could you add an explanation and maybe an example output please?

                                  – dessert
                                  3 hours ago











                                • @dessert done it.

                                  – guillermo chamorro
                                  2 hours ago
















                                Could you add an explanation and maybe an example output please?

                                – dessert
                                3 hours ago





                                Could you add an explanation and maybe an example output please?

                                – dessert
                                3 hours ago













                                @dessert done it.

                                – guillermo chamorro
                                2 hours ago





                                @dessert done it.

                                – guillermo chamorro
                                2 hours ago











                                0















                                If you don't mind the integers also being converted to floating point, you could use numfmt:



                                $ numfmt --field=1- --format=%.5f --invalid=ignore < file
                                1.00000
                                12.23487 0.00000 0.00000
                                0.00000 3.03201 0.00000
                                -1.37521 0.00000 5.61831
                                Ga O
                                8.00000 12.00000
                                Direct
                                0.59003 0.50000 0.79426
                                0.40998 0.50000 0.20575
                                0.90998 0.00000 0.20575
                                0.09003 0.00000 0.79426
                                0.65889 0.00000 0.31409





                                share|improve this answer





























                                  0















                                  If you don't mind the integers also being converted to floating point, you could use numfmt:



                                  $ numfmt --field=1- --format=%.5f --invalid=ignore < file
                                  1.00000
                                  12.23487 0.00000 0.00000
                                  0.00000 3.03201 0.00000
                                  -1.37521 0.00000 5.61831
                                  Ga O
                                  8.00000 12.00000
                                  Direct
                                  0.59003 0.50000 0.79426
                                  0.40998 0.50000 0.20575
                                  0.90998 0.00000 0.20575
                                  0.09003 0.00000 0.79426
                                  0.65889 0.00000 0.31409





                                  share|improve this answer



























                                    0














                                    0










                                    0









                                    If you don't mind the integers also being converted to floating point, you could use numfmt:



                                    $ numfmt --field=1- --format=%.5f --invalid=ignore < file
                                    1.00000
                                    12.23487 0.00000 0.00000
                                    0.00000 3.03201 0.00000
                                    -1.37521 0.00000 5.61831
                                    Ga O
                                    8.00000 12.00000
                                    Direct
                                    0.59003 0.50000 0.79426
                                    0.40998 0.50000 0.20575
                                    0.90998 0.00000 0.20575
                                    0.09003 0.00000 0.79426
                                    0.65889 0.00000 0.31409





                                    share|improve this answer













                                    If you don't mind the integers also being converted to floating point, you could use numfmt:



                                    $ numfmt --field=1- --format=%.5f --invalid=ignore < file
                                    1.00000
                                    12.23487 0.00000 0.00000
                                    0.00000 3.03201 0.00000
                                    -1.37521 0.00000 5.61831
                                    Ga O
                                    8.00000 12.00000
                                    Direct
                                    0.59003 0.50000 0.79426
                                    0.40998 0.50000 0.20575
                                    0.90998 0.00000 0.20575
                                    0.09003 0.00000 0.79426
                                    0.65889 0.00000 0.31409






                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered 19 mins ago









                                    steeldriversteeldriver

                                    78.2k12 gold badges129 silver badges210 bronze badges




                                    78.2k12 gold badges129 silver badges210 bronze badges






























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                                        Tom Holland Mục lục Đầu đời và giáo dục | Sự nghiệp | Cuộc sống cá nhân | Phim tham gia | Giải thưởng và đề cử | Chú thích | Liên kết ngoài | Trình đơn chuyển hướngProfile“Person Details for Thomas Stanley Holland, "England and Wales Birth Registration Index, 1837-2008" — FamilySearch.org”"Meet Tom Holland... the 16-year-old star of The Impossible""Schoolboy actor Tom Holland finds himself in Oscar contention for role in tsunami drama"“Naomi Watts on the Prince William and Harry's reaction to her film about the late Princess Diana”lưu trữ"Holland and Pflueger Are West End's Two New 'Billy Elliots'""I'm so envious of my son, the movie star! British writer Dominic Holland's spent 20 years trying to crack Hollywood - but he's been beaten to it by a very unlikely rival"“Richard and Margaret Povey of Jersey, Channel Islands, UK: Information about Thomas Stanley Holland”"Tom Holland to play Billy Elliot""New Billy Elliot leaving the garage"Billy Elliot the Musical - Tom Holland - Billy"A Tale of four Billys: Tom Holland""The Feel Good Factor""Thames Christian College schoolboys join Myleene Klass for The Feelgood Factor""Government launches £600,000 arts bursaries pilot""BILLY's Chapman, Holland, Gardner & Jackson-Keen Visit Prime Minister""Elton John 'blown away' by Billy Elliot fifth birthday" (video with John's interview and fragments of Holland's performance)"First News interviews Arrietty's Tom Holland"“33rd Critics' Circle Film Awards winners”“National Board of Review Current Awards”Bản gốc"Ron Howard Whaling Tale 'In The Heart Of The Sea' Casts Tom Holland"“'Spider-Man' Finds Tom Holland to Star as New Web-Slinger”lưu trữ“Captain America: Civil War (2016)”“Film Review: ‘Captain America: Civil War’”lưu trữ“‘Captain America: Civil War’ review: Choose your own avenger”lưu trữ“The Lost City of Z reviews”“Sony Pictures and Marvel Studios Find Their 'Spider-Man' Star and Director”“‘Mary Magdalene’, ‘Current War’ & ‘Wind River’ Get 2017 Release Dates From Weinstein”“Lionsgate Unleashing Daisy Ridley & Tom Holland Starrer ‘Chaos Walking’ In Cannes”“PTA's 'Master' Leads Chicago Film Critics Nominations, UPDATED: Houston and Indiana Critics Nominations”“Nominaciones Goya 2013 Telecinco Cinema – ENG”“Jameson Empire Film Awards: Martin Freeman wins best actor for performance in The Hobbit”“34th Annual Young Artist Awards”Bản gốc“Teen Choice Awards 2016—Captain America: Civil War Leads Second Wave of Nominations”“BAFTA Film Award Nominations: ‘La La Land’ Leads Race”“Saturn Awards Nominations 2017: 'Rogue One,' 'Walking Dead' Lead”Tom HollandTom HollandTom HollandTom Hollandmedia.gettyimages.comWorldCat Identities300279794no20130442900000 0004 0355 42791085670554170004732cb16706349t(data)XX5557367