How much mains leakage does an Ethernet connection to a PC induce, and what is the operating leakage path?Does an ATX power supply have any isolated outputs?What does the Arduino ethernet shield connect to?Ethernet phy connection: grounding between chassis, connector and IONon-isolated mains circuit and EthernetAdding a resistive path between live conductors and earth - safety issuesDoes the 802.3 Ethernet standard provide a recommended circuit design?Isolation transformer and AC potential between groundsHow to stop leakage of mains adaptorWhat is GMAC/EMAC and does it define a physical connection to an ethernet chip?How does Ethernet magnetics work?What are the NAND Trees that Ethernet datasheets refer to?

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How much mains leakage does an Ethernet connection to a PC induce, and what is the operating leakage path?


Does an ATX power supply have any isolated outputs?What does the Arduino ethernet shield connect to?Ethernet phy connection: grounding between chassis, connector and IONon-isolated mains circuit and EthernetAdding a resistive path between live conductors and earth - safety issuesDoes the 802.3 Ethernet standard provide a recommended circuit design?Isolation transformer and AC potential between groundsHow to stop leakage of mains adaptorWhat is GMAC/EMAC and does it define a physical connection to an ethernet chip?How does Ethernet magnetics work?What are the NAND Trees that Ethernet datasheets refer to?













5












$begingroup$


It seems that some users on another Stack have reported GFCI nuisance trips caused by mains leakage through twisted-pair Ethernet cables connected between computers on different branch circuits, or more specifically, between a computer with a Class I, chassis-mounted, supply conforming to IEC 60950 connected to a grounded receptacle with UL 943 Class A GFCI protection, and a switch that is a Class III appliance with a Class II power supply, connected to a grounded, but unprotected, receptacle on a different branch circuit.



While, conceptually speaking, the idea that there could be a leakage path through the data cable makes some sense, and I have seen Ethernet reference circuits that have termination RC networks from the port-side center-tap terminals in the magnetics to chassis ground as well as a 1nF capacitor between chassis and signal grounds, it seems to me that it would be very poor engineering for this leakage path to allow the mains leakage current to rise to a magnitude exceeding the IEC 60950 standards.



What is the magnitude of this Ethernet-connection-induced leakage current rise, what factors in the design of the equipment involved control this rise, and can someone describe to me the precise leakage loop involved?










share|improve this question









$endgroup$







  • 1




    $begingroup$
    I think the user on DIY is full of it. if the power supply in the PC is isolated, there shouldn't be any leakage that will trip a GFCI. Maybe he routes his ethernet cables by coiling them around the power cables?
    $endgroup$
    – The Photon
    3 hours ago






  • 1




    $begingroup$
    @ThePhoton -- unfortunately, I'm not in a situation to test it (don't have the network setup or the sensitive leakage clampmeter needed for that) or else I would put this theory to the test! If anyone wishes to experiment with this, though, I'd love to hear about it!
    $endgroup$
    – ThreePhaseEel
    3 hours ago











  • $begingroup$
    I've got a router, computer and laser printer networked together on a GFCI receptacle. Networked back to FIOS box and to another computer both not on this GFCI, and the GFCI hasn't tripped ever (~ 13 years). On the other hand, all the GFCI stuff is also going through a UPS (laser is on the surge-protection-only part) so that may mask any potential problem, though until ~ 6 years ago it wasn't on a UPS. But (as noted in DIY), I've never seen this problem anywhere and I have quite a few customers - I would think I'd come across the problem occasionally if was at all common.
    $endgroup$
    – manassehkatz
    3 hours ago







  • 2




    $begingroup$
    One caveat to my above comment: It's entirely possible (in fact, it's certain) there are some shitty power supplies out there being used in PCs.
    $endgroup$
    – The Photon
    3 hours ago










  • $begingroup$
    Related: Does an ATX power supply have any isolated outputs?.
    $endgroup$
    – The Photon
    2 hours ago















5












$begingroup$


It seems that some users on another Stack have reported GFCI nuisance trips caused by mains leakage through twisted-pair Ethernet cables connected between computers on different branch circuits, or more specifically, between a computer with a Class I, chassis-mounted, supply conforming to IEC 60950 connected to a grounded receptacle with UL 943 Class A GFCI protection, and a switch that is a Class III appliance with a Class II power supply, connected to a grounded, but unprotected, receptacle on a different branch circuit.



While, conceptually speaking, the idea that there could be a leakage path through the data cable makes some sense, and I have seen Ethernet reference circuits that have termination RC networks from the port-side center-tap terminals in the magnetics to chassis ground as well as a 1nF capacitor between chassis and signal grounds, it seems to me that it would be very poor engineering for this leakage path to allow the mains leakage current to rise to a magnitude exceeding the IEC 60950 standards.



What is the magnitude of this Ethernet-connection-induced leakage current rise, what factors in the design of the equipment involved control this rise, and can someone describe to me the precise leakage loop involved?










share|improve this question









$endgroup$







  • 1




    $begingroup$
    I think the user on DIY is full of it. if the power supply in the PC is isolated, there shouldn't be any leakage that will trip a GFCI. Maybe he routes his ethernet cables by coiling them around the power cables?
    $endgroup$
    – The Photon
    3 hours ago






  • 1




    $begingroup$
    @ThePhoton -- unfortunately, I'm not in a situation to test it (don't have the network setup or the sensitive leakage clampmeter needed for that) or else I would put this theory to the test! If anyone wishes to experiment with this, though, I'd love to hear about it!
    $endgroup$
    – ThreePhaseEel
    3 hours ago











  • $begingroup$
    I've got a router, computer and laser printer networked together on a GFCI receptacle. Networked back to FIOS box and to another computer both not on this GFCI, and the GFCI hasn't tripped ever (~ 13 years). On the other hand, all the GFCI stuff is also going through a UPS (laser is on the surge-protection-only part) so that may mask any potential problem, though until ~ 6 years ago it wasn't on a UPS. But (as noted in DIY), I've never seen this problem anywhere and I have quite a few customers - I would think I'd come across the problem occasionally if was at all common.
    $endgroup$
    – manassehkatz
    3 hours ago







  • 2




    $begingroup$
    One caveat to my above comment: It's entirely possible (in fact, it's certain) there are some shitty power supplies out there being used in PCs.
    $endgroup$
    – The Photon
    3 hours ago










  • $begingroup$
    Related: Does an ATX power supply have any isolated outputs?.
    $endgroup$
    – The Photon
    2 hours ago













5












5








5





$begingroup$


It seems that some users on another Stack have reported GFCI nuisance trips caused by mains leakage through twisted-pair Ethernet cables connected between computers on different branch circuits, or more specifically, between a computer with a Class I, chassis-mounted, supply conforming to IEC 60950 connected to a grounded receptacle with UL 943 Class A GFCI protection, and a switch that is a Class III appliance with a Class II power supply, connected to a grounded, but unprotected, receptacle on a different branch circuit.



While, conceptually speaking, the idea that there could be a leakage path through the data cable makes some sense, and I have seen Ethernet reference circuits that have termination RC networks from the port-side center-tap terminals in the magnetics to chassis ground as well as a 1nF capacitor between chassis and signal grounds, it seems to me that it would be very poor engineering for this leakage path to allow the mains leakage current to rise to a magnitude exceeding the IEC 60950 standards.



What is the magnitude of this Ethernet-connection-induced leakage current rise, what factors in the design of the equipment involved control this rise, and can someone describe to me the precise leakage loop involved?










share|improve this question









$endgroup$




It seems that some users on another Stack have reported GFCI nuisance trips caused by mains leakage through twisted-pair Ethernet cables connected between computers on different branch circuits, or more specifically, between a computer with a Class I, chassis-mounted, supply conforming to IEC 60950 connected to a grounded receptacle with UL 943 Class A GFCI protection, and a switch that is a Class III appliance with a Class II power supply, connected to a grounded, but unprotected, receptacle on a different branch circuit.



While, conceptually speaking, the idea that there could be a leakage path through the data cable makes some sense, and I have seen Ethernet reference circuits that have termination RC networks from the port-side center-tap terminals in the magnetics to chassis ground as well as a 1nF capacitor between chassis and signal grounds, it seems to me that it would be very poor engineering for this leakage path to allow the mains leakage current to rise to a magnitude exceeding the IEC 60950 standards.



What is the magnitude of this Ethernet-connection-induced leakage current rise, what factors in the design of the equipment involved control this rise, and can someone describe to me the precise leakage loop involved?







ethernet leakage-current






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 3 hours ago









ThreePhaseEelThreePhaseEel

6,70141534




6,70141534







  • 1




    $begingroup$
    I think the user on DIY is full of it. if the power supply in the PC is isolated, there shouldn't be any leakage that will trip a GFCI. Maybe he routes his ethernet cables by coiling them around the power cables?
    $endgroup$
    – The Photon
    3 hours ago






  • 1




    $begingroup$
    @ThePhoton -- unfortunately, I'm not in a situation to test it (don't have the network setup or the sensitive leakage clampmeter needed for that) or else I would put this theory to the test! If anyone wishes to experiment with this, though, I'd love to hear about it!
    $endgroup$
    – ThreePhaseEel
    3 hours ago











  • $begingroup$
    I've got a router, computer and laser printer networked together on a GFCI receptacle. Networked back to FIOS box and to another computer both not on this GFCI, and the GFCI hasn't tripped ever (~ 13 years). On the other hand, all the GFCI stuff is also going through a UPS (laser is on the surge-protection-only part) so that may mask any potential problem, though until ~ 6 years ago it wasn't on a UPS. But (as noted in DIY), I've never seen this problem anywhere and I have quite a few customers - I would think I'd come across the problem occasionally if was at all common.
    $endgroup$
    – manassehkatz
    3 hours ago







  • 2




    $begingroup$
    One caveat to my above comment: It's entirely possible (in fact, it's certain) there are some shitty power supplies out there being used in PCs.
    $endgroup$
    – The Photon
    3 hours ago










  • $begingroup$
    Related: Does an ATX power supply have any isolated outputs?.
    $endgroup$
    – The Photon
    2 hours ago












  • 1




    $begingroup$
    I think the user on DIY is full of it. if the power supply in the PC is isolated, there shouldn't be any leakage that will trip a GFCI. Maybe he routes his ethernet cables by coiling them around the power cables?
    $endgroup$
    – The Photon
    3 hours ago






  • 1




    $begingroup$
    @ThePhoton -- unfortunately, I'm not in a situation to test it (don't have the network setup or the sensitive leakage clampmeter needed for that) or else I would put this theory to the test! If anyone wishes to experiment with this, though, I'd love to hear about it!
    $endgroup$
    – ThreePhaseEel
    3 hours ago











  • $begingroup$
    I've got a router, computer and laser printer networked together on a GFCI receptacle. Networked back to FIOS box and to another computer both not on this GFCI, and the GFCI hasn't tripped ever (~ 13 years). On the other hand, all the GFCI stuff is also going through a UPS (laser is on the surge-protection-only part) so that may mask any potential problem, though until ~ 6 years ago it wasn't on a UPS. But (as noted in DIY), I've never seen this problem anywhere and I have quite a few customers - I would think I'd come across the problem occasionally if was at all common.
    $endgroup$
    – manassehkatz
    3 hours ago







  • 2




    $begingroup$
    One caveat to my above comment: It's entirely possible (in fact, it's certain) there are some shitty power supplies out there being used in PCs.
    $endgroup$
    – The Photon
    3 hours ago










  • $begingroup$
    Related: Does an ATX power supply have any isolated outputs?.
    $endgroup$
    – The Photon
    2 hours ago







1




1




$begingroup$
I think the user on DIY is full of it. if the power supply in the PC is isolated, there shouldn't be any leakage that will trip a GFCI. Maybe he routes his ethernet cables by coiling them around the power cables?
$endgroup$
– The Photon
3 hours ago




$begingroup$
I think the user on DIY is full of it. if the power supply in the PC is isolated, there shouldn't be any leakage that will trip a GFCI. Maybe he routes his ethernet cables by coiling them around the power cables?
$endgroup$
– The Photon
3 hours ago




1




1




$begingroup$
@ThePhoton -- unfortunately, I'm not in a situation to test it (don't have the network setup or the sensitive leakage clampmeter needed for that) or else I would put this theory to the test! If anyone wishes to experiment with this, though, I'd love to hear about it!
$endgroup$
– ThreePhaseEel
3 hours ago





$begingroup$
@ThePhoton -- unfortunately, I'm not in a situation to test it (don't have the network setup or the sensitive leakage clampmeter needed for that) or else I would put this theory to the test! If anyone wishes to experiment with this, though, I'd love to hear about it!
$endgroup$
– ThreePhaseEel
3 hours ago













$begingroup$
I've got a router, computer and laser printer networked together on a GFCI receptacle. Networked back to FIOS box and to another computer both not on this GFCI, and the GFCI hasn't tripped ever (~ 13 years). On the other hand, all the GFCI stuff is also going through a UPS (laser is on the surge-protection-only part) so that may mask any potential problem, though until ~ 6 years ago it wasn't on a UPS. But (as noted in DIY), I've never seen this problem anywhere and I have quite a few customers - I would think I'd come across the problem occasionally if was at all common.
$endgroup$
– manassehkatz
3 hours ago





$begingroup$
I've got a router, computer and laser printer networked together on a GFCI receptacle. Networked back to FIOS box and to another computer both not on this GFCI, and the GFCI hasn't tripped ever (~ 13 years). On the other hand, all the GFCI stuff is also going through a UPS (laser is on the surge-protection-only part) so that may mask any potential problem, though until ~ 6 years ago it wasn't on a UPS. But (as noted in DIY), I've never seen this problem anywhere and I have quite a few customers - I would think I'd come across the problem occasionally if was at all common.
$endgroup$
– manassehkatz
3 hours ago





2




2




$begingroup$
One caveat to my above comment: It's entirely possible (in fact, it's certain) there are some shitty power supplies out there being used in PCs.
$endgroup$
– The Photon
3 hours ago




$begingroup$
One caveat to my above comment: It's entirely possible (in fact, it's certain) there are some shitty power supplies out there being used in PCs.
$endgroup$
– The Photon
3 hours ago












$begingroup$
Related: Does an ATX power supply have any isolated outputs?.
$endgroup$
– The Photon
2 hours ago




$begingroup$
Related: Does an ATX power supply have any isolated outputs?.
$endgroup$
– The Photon
2 hours ago










3 Answers
3






active

oldest

votes


















2












$begingroup$

The ethernet connection leakage current should be negligable, with UTP.
Every port has a array of transformers for high frequency, the leakage at 50 Hz common mode will be very low.
enter image description here



However, if shielded cable is used, S-UTP or CAT7 cables, there will also be made a chassis connection between the two devices.

Then the power supply leakage enters the equation, and those may leak several milliamperes.



The simple act of reversing the plug might remove the nuisance tripping of the GFCI/RCD.



*(image source)






share|improve this answer











$endgroup$












  • $begingroup$
    Yep, shielded cable was my concern too.
    $endgroup$
    – Ale..chenski
    40 mins ago


















0












$begingroup$



So I'm the user on DIY.



I had some original experience at work where we coudn't get the new portable generator to power more than one computer even though the old one did. We eventually bisected it to the GFCI outlet in the new generator.



Later on, I had to track down why my AFCI breaker kept tripping. The electrician I called tested the AFCI breaker by bridging a resistor between power and ground. That tripped it. He said that AFCI breakers work by detecting ground faults. I originally said he was nuts, but it turns out it was true.



I got a copy of a circuit for RJ45 magnetics. The critical point is RXN and TXN are tied together by a pair of identical resistors R6 and R7 and capacitor C15 which is 10nF ties that bridge line to ground. In steady state, C15 would indeed conduct no current; however when sending a packet, the impedance of C15 1 / jωC = 1 / j(2·10⁹)(10·10⁻⁹) = 1/j20. This gives the resulting current flow of I = V/R = 3.3/2/49.9² + 1/20²)¹ᐟ² = .033 amps.



And that's just that one capacitor. I haven't been able to locate the indicator LEDs yet. I've noticed that the connection indicator LED on quite a few computers will light even when the board is unpowered but not when unplugged. Conclusion: that LED is tied between the Ethernet cable on one side and the ground on the other, and that ground is often the neutral wire rather than the house ground (two wire devices ...).



Now the electrician was in fact telling the truth. Old series AFCI breakers would trip at something like .1 amps of ground loop by specification. The gigabit switch I was using at the time was a two wire device (no dedicated ground) so all of that current had to go into the neutral wire. New AFCI breakers have since been fixed to work by other means than ground fault detection and replacing the AFCI breaker was the solution.



GFCI outlets are documented to trip at .004 amps. Guess what happens when you run Ethernet cables between devices on different circuits where one of them doesn't have a ground wire. And I'm pretty sure from the bisection that most of these cheaper power supplies were tying the motherboard ground to the neutral wire not the ground wire despite the ground wire being available.






share|improve this answer











$endgroup$












  • $begingroup$
    So HIGH SLEW RATE Ethernet signals are, lacking OTHER return paths, using the PowerLine as RETURN?
    $endgroup$
    – analogsystemsrf
    2 hours ago










  • $begingroup$
    @analogsystemsrf: Yup! Was expecting it as soon as I learned how carrier sense worked. Come to think of it, that's probably why that line is tied to neutral rather than ground in the PCs. If it were tied to ground it would have a hard time returning to a two-wire device.
    $endgroup$
    – Joshua
    2 hours ago










  • $begingroup$
    When you say "that ground is often the neutral wire", if that's true then your PC vendor hasn't provided a properly isolated power supply and is violating safety regulations in any first-world country.
    $endgroup$
    – The Photon
    2 hours ago






  • 1




    $begingroup$
    The ground on this schematic would be the negative power rail for the entire circuit. Every part of the computer will send current to the same ground that's on this schematic. In electronics, ground usually just means zero volts, not "real ground".
    $endgroup$
    – immibis
    2 hours ago







  • 1




    $begingroup$
    @Joshua One goes down to 0V at the same time the other goes up to 3.3V and vice versa - that's how differential signals work. The capacitor voltage will be around 1.65V at any time.
    $endgroup$
    – immibis
    2 hours ago



















0












$begingroup$

Tripping a GFCI usually occurs when there is a missmatch between the current going in and the current going out. While there could exist mutual inductance between cables, I don't think it would generate enough current because properly designed Ethernet ports have mega ohms of impedance at DC. I'll find some impedance graphs for the Chokes tomorrow, but if I remember right there is high attention for lower frequencies through chokes, and highly unlikely to pass much current 60Hz through DC.



If the cable was improperly built there could be a pathway there






share|improve this answer









$endgroup$













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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2












    $begingroup$

    The ethernet connection leakage current should be negligable, with UTP.
    Every port has a array of transformers for high frequency, the leakage at 50 Hz common mode will be very low.
    enter image description here



    However, if shielded cable is used, S-UTP or CAT7 cables, there will also be made a chassis connection between the two devices.

    Then the power supply leakage enters the equation, and those may leak several milliamperes.



    The simple act of reversing the plug might remove the nuisance tripping of the GFCI/RCD.



    *(image source)






    share|improve this answer











    $endgroup$












    • $begingroup$
      Yep, shielded cable was my concern too.
      $endgroup$
      – Ale..chenski
      40 mins ago















    2












    $begingroup$

    The ethernet connection leakage current should be negligable, with UTP.
    Every port has a array of transformers for high frequency, the leakage at 50 Hz common mode will be very low.
    enter image description here



    However, if shielded cable is used, S-UTP or CAT7 cables, there will also be made a chassis connection between the two devices.

    Then the power supply leakage enters the equation, and those may leak several milliamperes.



    The simple act of reversing the plug might remove the nuisance tripping of the GFCI/RCD.



    *(image source)






    share|improve this answer











    $endgroup$












    • $begingroup$
      Yep, shielded cable was my concern too.
      $endgroup$
      – Ale..chenski
      40 mins ago













    2












    2








    2





    $begingroup$

    The ethernet connection leakage current should be negligable, with UTP.
    Every port has a array of transformers for high frequency, the leakage at 50 Hz common mode will be very low.
    enter image description here



    However, if shielded cable is used, S-UTP or CAT7 cables, there will also be made a chassis connection between the two devices.

    Then the power supply leakage enters the equation, and those may leak several milliamperes.



    The simple act of reversing the plug might remove the nuisance tripping of the GFCI/RCD.



    *(image source)






    share|improve this answer











    $endgroup$



    The ethernet connection leakage current should be negligable, with UTP.
    Every port has a array of transformers for high frequency, the leakage at 50 Hz common mode will be very low.
    enter image description here



    However, if shielded cable is used, S-UTP or CAT7 cables, there will also be made a chassis connection between the two devices.

    Then the power supply leakage enters the equation, and those may leak several milliamperes.



    The simple act of reversing the plug might remove the nuisance tripping of the GFCI/RCD.



    *(image source)







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 12 mins ago

























    answered 44 mins ago









    Jeroen3Jeroen3

    11.6k1748




    11.6k1748











    • $begingroup$
      Yep, shielded cable was my concern too.
      $endgroup$
      – Ale..chenski
      40 mins ago
















    • $begingroup$
      Yep, shielded cable was my concern too.
      $endgroup$
      – Ale..chenski
      40 mins ago















    $begingroup$
    Yep, shielded cable was my concern too.
    $endgroup$
    – Ale..chenski
    40 mins ago




    $begingroup$
    Yep, shielded cable was my concern too.
    $endgroup$
    – Ale..chenski
    40 mins ago













    0












    $begingroup$



    So I'm the user on DIY.



    I had some original experience at work where we coudn't get the new portable generator to power more than one computer even though the old one did. We eventually bisected it to the GFCI outlet in the new generator.



    Later on, I had to track down why my AFCI breaker kept tripping. The electrician I called tested the AFCI breaker by bridging a resistor between power and ground. That tripped it. He said that AFCI breakers work by detecting ground faults. I originally said he was nuts, but it turns out it was true.



    I got a copy of a circuit for RJ45 magnetics. The critical point is RXN and TXN are tied together by a pair of identical resistors R6 and R7 and capacitor C15 which is 10nF ties that bridge line to ground. In steady state, C15 would indeed conduct no current; however when sending a packet, the impedance of C15 1 / jωC = 1 / j(2·10⁹)(10·10⁻⁹) = 1/j20. This gives the resulting current flow of I = V/R = 3.3/2/49.9² + 1/20²)¹ᐟ² = .033 amps.



    And that's just that one capacitor. I haven't been able to locate the indicator LEDs yet. I've noticed that the connection indicator LED on quite a few computers will light even when the board is unpowered but not when unplugged. Conclusion: that LED is tied between the Ethernet cable on one side and the ground on the other, and that ground is often the neutral wire rather than the house ground (two wire devices ...).



    Now the electrician was in fact telling the truth. Old series AFCI breakers would trip at something like .1 amps of ground loop by specification. The gigabit switch I was using at the time was a two wire device (no dedicated ground) so all of that current had to go into the neutral wire. New AFCI breakers have since been fixed to work by other means than ground fault detection and replacing the AFCI breaker was the solution.



    GFCI outlets are documented to trip at .004 amps. Guess what happens when you run Ethernet cables between devices on different circuits where one of them doesn't have a ground wire. And I'm pretty sure from the bisection that most of these cheaper power supplies were tying the motherboard ground to the neutral wire not the ground wire despite the ground wire being available.






    share|improve this answer











    $endgroup$












    • $begingroup$
      So HIGH SLEW RATE Ethernet signals are, lacking OTHER return paths, using the PowerLine as RETURN?
      $endgroup$
      – analogsystemsrf
      2 hours ago










    • $begingroup$
      @analogsystemsrf: Yup! Was expecting it as soon as I learned how carrier sense worked. Come to think of it, that's probably why that line is tied to neutral rather than ground in the PCs. If it were tied to ground it would have a hard time returning to a two-wire device.
      $endgroup$
      – Joshua
      2 hours ago










    • $begingroup$
      When you say "that ground is often the neutral wire", if that's true then your PC vendor hasn't provided a properly isolated power supply and is violating safety regulations in any first-world country.
      $endgroup$
      – The Photon
      2 hours ago






    • 1




      $begingroup$
      The ground on this schematic would be the negative power rail for the entire circuit. Every part of the computer will send current to the same ground that's on this schematic. In electronics, ground usually just means zero volts, not "real ground".
      $endgroup$
      – immibis
      2 hours ago







    • 1




      $begingroup$
      @Joshua One goes down to 0V at the same time the other goes up to 3.3V and vice versa - that's how differential signals work. The capacitor voltage will be around 1.65V at any time.
      $endgroup$
      – immibis
      2 hours ago
















    0












    $begingroup$



    So I'm the user on DIY.



    I had some original experience at work where we coudn't get the new portable generator to power more than one computer even though the old one did. We eventually bisected it to the GFCI outlet in the new generator.



    Later on, I had to track down why my AFCI breaker kept tripping. The electrician I called tested the AFCI breaker by bridging a resistor between power and ground. That tripped it. He said that AFCI breakers work by detecting ground faults. I originally said he was nuts, but it turns out it was true.



    I got a copy of a circuit for RJ45 magnetics. The critical point is RXN and TXN are tied together by a pair of identical resistors R6 and R7 and capacitor C15 which is 10nF ties that bridge line to ground. In steady state, C15 would indeed conduct no current; however when sending a packet, the impedance of C15 1 / jωC = 1 / j(2·10⁹)(10·10⁻⁹) = 1/j20. This gives the resulting current flow of I = V/R = 3.3/2/49.9² + 1/20²)¹ᐟ² = .033 amps.



    And that's just that one capacitor. I haven't been able to locate the indicator LEDs yet. I've noticed that the connection indicator LED on quite a few computers will light even when the board is unpowered but not when unplugged. Conclusion: that LED is tied between the Ethernet cable on one side and the ground on the other, and that ground is often the neutral wire rather than the house ground (two wire devices ...).



    Now the electrician was in fact telling the truth. Old series AFCI breakers would trip at something like .1 amps of ground loop by specification. The gigabit switch I was using at the time was a two wire device (no dedicated ground) so all of that current had to go into the neutral wire. New AFCI breakers have since been fixed to work by other means than ground fault detection and replacing the AFCI breaker was the solution.



    GFCI outlets are documented to trip at .004 amps. Guess what happens when you run Ethernet cables between devices on different circuits where one of them doesn't have a ground wire. And I'm pretty sure from the bisection that most of these cheaper power supplies were tying the motherboard ground to the neutral wire not the ground wire despite the ground wire being available.






    share|improve this answer











    $endgroup$












    • $begingroup$
      So HIGH SLEW RATE Ethernet signals are, lacking OTHER return paths, using the PowerLine as RETURN?
      $endgroup$
      – analogsystemsrf
      2 hours ago










    • $begingroup$
      @analogsystemsrf: Yup! Was expecting it as soon as I learned how carrier sense worked. Come to think of it, that's probably why that line is tied to neutral rather than ground in the PCs. If it were tied to ground it would have a hard time returning to a two-wire device.
      $endgroup$
      – Joshua
      2 hours ago










    • $begingroup$
      When you say "that ground is often the neutral wire", if that's true then your PC vendor hasn't provided a properly isolated power supply and is violating safety regulations in any first-world country.
      $endgroup$
      – The Photon
      2 hours ago






    • 1




      $begingroup$
      The ground on this schematic would be the negative power rail for the entire circuit. Every part of the computer will send current to the same ground that's on this schematic. In electronics, ground usually just means zero volts, not "real ground".
      $endgroup$
      – immibis
      2 hours ago







    • 1




      $begingroup$
      @Joshua One goes down to 0V at the same time the other goes up to 3.3V and vice versa - that's how differential signals work. The capacitor voltage will be around 1.65V at any time.
      $endgroup$
      – immibis
      2 hours ago














    0












    0








    0





    $begingroup$



    So I'm the user on DIY.



    I had some original experience at work where we coudn't get the new portable generator to power more than one computer even though the old one did. We eventually bisected it to the GFCI outlet in the new generator.



    Later on, I had to track down why my AFCI breaker kept tripping. The electrician I called tested the AFCI breaker by bridging a resistor between power and ground. That tripped it. He said that AFCI breakers work by detecting ground faults. I originally said he was nuts, but it turns out it was true.



    I got a copy of a circuit for RJ45 magnetics. The critical point is RXN and TXN are tied together by a pair of identical resistors R6 and R7 and capacitor C15 which is 10nF ties that bridge line to ground. In steady state, C15 would indeed conduct no current; however when sending a packet, the impedance of C15 1 / jωC = 1 / j(2·10⁹)(10·10⁻⁹) = 1/j20. This gives the resulting current flow of I = V/R = 3.3/2/49.9² + 1/20²)¹ᐟ² = .033 amps.



    And that's just that one capacitor. I haven't been able to locate the indicator LEDs yet. I've noticed that the connection indicator LED on quite a few computers will light even when the board is unpowered but not when unplugged. Conclusion: that LED is tied between the Ethernet cable on one side and the ground on the other, and that ground is often the neutral wire rather than the house ground (two wire devices ...).



    Now the electrician was in fact telling the truth. Old series AFCI breakers would trip at something like .1 amps of ground loop by specification. The gigabit switch I was using at the time was a two wire device (no dedicated ground) so all of that current had to go into the neutral wire. New AFCI breakers have since been fixed to work by other means than ground fault detection and replacing the AFCI breaker was the solution.



    GFCI outlets are documented to trip at .004 amps. Guess what happens when you run Ethernet cables between devices on different circuits where one of them doesn't have a ground wire. And I'm pretty sure from the bisection that most of these cheaper power supplies were tying the motherboard ground to the neutral wire not the ground wire despite the ground wire being available.






    share|improve this answer











    $endgroup$





    So I'm the user on DIY.



    I had some original experience at work where we coudn't get the new portable generator to power more than one computer even though the old one did. We eventually bisected it to the GFCI outlet in the new generator.



    Later on, I had to track down why my AFCI breaker kept tripping. The electrician I called tested the AFCI breaker by bridging a resistor between power and ground. That tripped it. He said that AFCI breakers work by detecting ground faults. I originally said he was nuts, but it turns out it was true.



    I got a copy of a circuit for RJ45 magnetics. The critical point is RXN and TXN are tied together by a pair of identical resistors R6 and R7 and capacitor C15 which is 10nF ties that bridge line to ground. In steady state, C15 would indeed conduct no current; however when sending a packet, the impedance of C15 1 / jωC = 1 / j(2·10⁹)(10·10⁻⁹) = 1/j20. This gives the resulting current flow of I = V/R = 3.3/2/49.9² + 1/20²)¹ᐟ² = .033 amps.



    And that's just that one capacitor. I haven't been able to locate the indicator LEDs yet. I've noticed that the connection indicator LED on quite a few computers will light even when the board is unpowered but not when unplugged. Conclusion: that LED is tied between the Ethernet cable on one side and the ground on the other, and that ground is often the neutral wire rather than the house ground (two wire devices ...).



    Now the electrician was in fact telling the truth. Old series AFCI breakers would trip at something like .1 amps of ground loop by specification. The gigabit switch I was using at the time was a two wire device (no dedicated ground) so all of that current had to go into the neutral wire. New AFCI breakers have since been fixed to work by other means than ground fault detection and replacing the AFCI breaker was the solution.



    GFCI outlets are documented to trip at .004 amps. Guess what happens when you run Ethernet cables between devices on different circuits where one of them doesn't have a ground wire. And I'm pretty sure from the bisection that most of these cheaper power supplies were tying the motherboard ground to the neutral wire not the ground wire despite the ground wire being available.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 2 hours ago

























    answered 2 hours ago









    JoshuaJoshua

    21515




    21515











    • $begingroup$
      So HIGH SLEW RATE Ethernet signals are, lacking OTHER return paths, using the PowerLine as RETURN?
      $endgroup$
      – analogsystemsrf
      2 hours ago










    • $begingroup$
      @analogsystemsrf: Yup! Was expecting it as soon as I learned how carrier sense worked. Come to think of it, that's probably why that line is tied to neutral rather than ground in the PCs. If it were tied to ground it would have a hard time returning to a two-wire device.
      $endgroup$
      – Joshua
      2 hours ago










    • $begingroup$
      When you say "that ground is often the neutral wire", if that's true then your PC vendor hasn't provided a properly isolated power supply and is violating safety regulations in any first-world country.
      $endgroup$
      – The Photon
      2 hours ago






    • 1




      $begingroup$
      The ground on this schematic would be the negative power rail for the entire circuit. Every part of the computer will send current to the same ground that's on this schematic. In electronics, ground usually just means zero volts, not "real ground".
      $endgroup$
      – immibis
      2 hours ago







    • 1




      $begingroup$
      @Joshua One goes down to 0V at the same time the other goes up to 3.3V and vice versa - that's how differential signals work. The capacitor voltage will be around 1.65V at any time.
      $endgroup$
      – immibis
      2 hours ago

















    • $begingroup$
      So HIGH SLEW RATE Ethernet signals are, lacking OTHER return paths, using the PowerLine as RETURN?
      $endgroup$
      – analogsystemsrf
      2 hours ago










    • $begingroup$
      @analogsystemsrf: Yup! Was expecting it as soon as I learned how carrier sense worked. Come to think of it, that's probably why that line is tied to neutral rather than ground in the PCs. If it were tied to ground it would have a hard time returning to a two-wire device.
      $endgroup$
      – Joshua
      2 hours ago










    • $begingroup$
      When you say "that ground is often the neutral wire", if that's true then your PC vendor hasn't provided a properly isolated power supply and is violating safety regulations in any first-world country.
      $endgroup$
      – The Photon
      2 hours ago






    • 1




      $begingroup$
      The ground on this schematic would be the negative power rail for the entire circuit. Every part of the computer will send current to the same ground that's on this schematic. In electronics, ground usually just means zero volts, not "real ground".
      $endgroup$
      – immibis
      2 hours ago







    • 1




      $begingroup$
      @Joshua One goes down to 0V at the same time the other goes up to 3.3V and vice versa - that's how differential signals work. The capacitor voltage will be around 1.65V at any time.
      $endgroup$
      – immibis
      2 hours ago
















    $begingroup$
    So HIGH SLEW RATE Ethernet signals are, lacking OTHER return paths, using the PowerLine as RETURN?
    $endgroup$
    – analogsystemsrf
    2 hours ago




    $begingroup$
    So HIGH SLEW RATE Ethernet signals are, lacking OTHER return paths, using the PowerLine as RETURN?
    $endgroup$
    – analogsystemsrf
    2 hours ago












    $begingroup$
    @analogsystemsrf: Yup! Was expecting it as soon as I learned how carrier sense worked. Come to think of it, that's probably why that line is tied to neutral rather than ground in the PCs. If it were tied to ground it would have a hard time returning to a two-wire device.
    $endgroup$
    – Joshua
    2 hours ago




    $begingroup$
    @analogsystemsrf: Yup! Was expecting it as soon as I learned how carrier sense worked. Come to think of it, that's probably why that line is tied to neutral rather than ground in the PCs. If it were tied to ground it would have a hard time returning to a two-wire device.
    $endgroup$
    – Joshua
    2 hours ago












    $begingroup$
    When you say "that ground is often the neutral wire", if that's true then your PC vendor hasn't provided a properly isolated power supply and is violating safety regulations in any first-world country.
    $endgroup$
    – The Photon
    2 hours ago




    $begingroup$
    When you say "that ground is often the neutral wire", if that's true then your PC vendor hasn't provided a properly isolated power supply and is violating safety regulations in any first-world country.
    $endgroup$
    – The Photon
    2 hours ago




    1




    1




    $begingroup$
    The ground on this schematic would be the negative power rail for the entire circuit. Every part of the computer will send current to the same ground that's on this schematic. In electronics, ground usually just means zero volts, not "real ground".
    $endgroup$
    – immibis
    2 hours ago





    $begingroup$
    The ground on this schematic would be the negative power rail for the entire circuit. Every part of the computer will send current to the same ground that's on this schematic. In electronics, ground usually just means zero volts, not "real ground".
    $endgroup$
    – immibis
    2 hours ago





    1




    1




    $begingroup$
    @Joshua One goes down to 0V at the same time the other goes up to 3.3V and vice versa - that's how differential signals work. The capacitor voltage will be around 1.65V at any time.
    $endgroup$
    – immibis
    2 hours ago





    $begingroup$
    @Joshua One goes down to 0V at the same time the other goes up to 3.3V and vice versa - that's how differential signals work. The capacitor voltage will be around 1.65V at any time.
    $endgroup$
    – immibis
    2 hours ago












    0












    $begingroup$

    Tripping a GFCI usually occurs when there is a missmatch between the current going in and the current going out. While there could exist mutual inductance between cables, I don't think it would generate enough current because properly designed Ethernet ports have mega ohms of impedance at DC. I'll find some impedance graphs for the Chokes tomorrow, but if I remember right there is high attention for lower frequencies through chokes, and highly unlikely to pass much current 60Hz through DC.



    If the cable was improperly built there could be a pathway there






    share|improve this answer









    $endgroup$

















      0












      $begingroup$

      Tripping a GFCI usually occurs when there is a missmatch between the current going in and the current going out. While there could exist mutual inductance between cables, I don't think it would generate enough current because properly designed Ethernet ports have mega ohms of impedance at DC. I'll find some impedance graphs for the Chokes tomorrow, but if I remember right there is high attention for lower frequencies through chokes, and highly unlikely to pass much current 60Hz through DC.



      If the cable was improperly built there could be a pathway there






      share|improve this answer









      $endgroup$















        0












        0








        0





        $begingroup$

        Tripping a GFCI usually occurs when there is a missmatch between the current going in and the current going out. While there could exist mutual inductance between cables, I don't think it would generate enough current because properly designed Ethernet ports have mega ohms of impedance at DC. I'll find some impedance graphs for the Chokes tomorrow, but if I remember right there is high attention for lower frequencies through chokes, and highly unlikely to pass much current 60Hz through DC.



        If the cable was improperly built there could be a pathway there






        share|improve this answer









        $endgroup$



        Tripping a GFCI usually occurs when there is a missmatch between the current going in and the current going out. While there could exist mutual inductance between cables, I don't think it would generate enough current because properly designed Ethernet ports have mega ohms of impedance at DC. I'll find some impedance graphs for the Chokes tomorrow, but if I remember right there is high attention for lower frequencies through chokes, and highly unlikely to pass much current 60Hz through DC.



        If the cable was improperly built there could be a pathway there







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 49 mins ago









        laptop2dlaptop2d

        27.1k123584




        27.1k123584



























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