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What is the resistivity of copper at 3 kelvin?
Do the copper connectors we used in measuring the resistance of a wire contribute to the said measurement?Graph of Electrical Resistivity of Air vs Air PressureWhy is the resistivity of a copper cable much higher than copper?Why resistivity of copper wire is not zero even at zero kelvin?Determining the resistivity of gold and copper alloyCan four probe method be used to find resistivity of metals?A question about resistivity ( high school physics )Resistivity of electrolytesElectrical resistivity calculation of a cylindrical materialvolume resistivity
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I couldn't find the value of resistivity of copper at 2.73K on google
electrical-resistance
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I couldn't find the value of resistivity of copper at 2.73K on google
electrical-resistance
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add a comment |
$begingroup$
I couldn't find the value of resistivity of copper at 2.73K on google
electrical-resistance
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I couldn't find the value of resistivity of copper at 2.73K on google
electrical-resistance
electrical-resistance
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asked 8 hours ago
AJKAJK
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1 Answer
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There is a problem with answering your question in that at such a low temperature the resistivity of copper is very much determined by the impurities and crystallographic defects eg dislocations, voids etc, which may be present.
At low temperatures it is the scattering of free electrons by impurities and crystallographic defects high determine the resistivity rather than the thermal excitation of the copper ions.
The parameter which is often measured is the residual resistance ratio $dfracR_text273 KR_4.2,rm K$ which for fairly pure copper wire as used for telephone lines might be of the order of $100$.
Large single crystals of very pure copper can be produced with residual resistance ratios in the thousands.
.
Update as answers to some of @AJK’s questions.
Annotated graph to illustrate the non-linear logarithmic scale and the resistivity of copper at $3, rm K$.
$endgroup$
$begingroup$
so it's impossible to use copper at any temperature around 3k as a conductor
$endgroup$
– AJK
6 hours ago
$begingroup$
@AJK That is not what I wrote. From the graph you can get an estimate of the resistivity of “ordinary” copper at around $3,rm K$. At this temperature the copper is a much better conductor of electricity than at room temperature.
$endgroup$
– Farcher
6 hours ago
1
$begingroup$
How do we get the estimate
$endgroup$
– AJK
6 hours ago
$begingroup$
@AJK From the graph noting that it is a log-log graph.
$endgroup$
– Farcher
6 hours ago
1
$begingroup$
I have no clue what that means
$endgroup$
– AJK
6 hours ago
|
show 3 more comments
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
There is a problem with answering your question in that at such a low temperature the resistivity of copper is very much determined by the impurities and crystallographic defects eg dislocations, voids etc, which may be present.
At low temperatures it is the scattering of free electrons by impurities and crystallographic defects high determine the resistivity rather than the thermal excitation of the copper ions.
The parameter which is often measured is the residual resistance ratio $dfracR_text273 KR_4.2,rm K$ which for fairly pure copper wire as used for telephone lines might be of the order of $100$.
Large single crystals of very pure copper can be produced with residual resistance ratios in the thousands.
.
Update as answers to some of @AJK’s questions.
Annotated graph to illustrate the non-linear logarithmic scale and the resistivity of copper at $3, rm K$.
$endgroup$
$begingroup$
so it's impossible to use copper at any temperature around 3k as a conductor
$endgroup$
– AJK
6 hours ago
$begingroup$
@AJK That is not what I wrote. From the graph you can get an estimate of the resistivity of “ordinary” copper at around $3,rm K$. At this temperature the copper is a much better conductor of electricity than at room temperature.
$endgroup$
– Farcher
6 hours ago
1
$begingroup$
How do we get the estimate
$endgroup$
– AJK
6 hours ago
$begingroup$
@AJK From the graph noting that it is a log-log graph.
$endgroup$
– Farcher
6 hours ago
1
$begingroup$
I have no clue what that means
$endgroup$
– AJK
6 hours ago
|
show 3 more comments
$begingroup$
There is a problem with answering your question in that at such a low temperature the resistivity of copper is very much determined by the impurities and crystallographic defects eg dislocations, voids etc, which may be present.
At low temperatures it is the scattering of free electrons by impurities and crystallographic defects high determine the resistivity rather than the thermal excitation of the copper ions.
The parameter which is often measured is the residual resistance ratio $dfracR_text273 KR_4.2,rm K$ which for fairly pure copper wire as used for telephone lines might be of the order of $100$.
Large single crystals of very pure copper can be produced with residual resistance ratios in the thousands.
.
Update as answers to some of @AJK’s questions.
Annotated graph to illustrate the non-linear logarithmic scale and the resistivity of copper at $3, rm K$.
$endgroup$
$begingroup$
so it's impossible to use copper at any temperature around 3k as a conductor
$endgroup$
– AJK
6 hours ago
$begingroup$
@AJK That is not what I wrote. From the graph you can get an estimate of the resistivity of “ordinary” copper at around $3,rm K$. At this temperature the copper is a much better conductor of electricity than at room temperature.
$endgroup$
– Farcher
6 hours ago
1
$begingroup$
How do we get the estimate
$endgroup$
– AJK
6 hours ago
$begingroup$
@AJK From the graph noting that it is a log-log graph.
$endgroup$
– Farcher
6 hours ago
1
$begingroup$
I have no clue what that means
$endgroup$
– AJK
6 hours ago
|
show 3 more comments
$begingroup$
There is a problem with answering your question in that at such a low temperature the resistivity of copper is very much determined by the impurities and crystallographic defects eg dislocations, voids etc, which may be present.
At low temperatures it is the scattering of free electrons by impurities and crystallographic defects high determine the resistivity rather than the thermal excitation of the copper ions.
The parameter which is often measured is the residual resistance ratio $dfracR_text273 KR_4.2,rm K$ which for fairly pure copper wire as used for telephone lines might be of the order of $100$.
Large single crystals of very pure copper can be produced with residual resistance ratios in the thousands.
.
Update as answers to some of @AJK’s questions.
Annotated graph to illustrate the non-linear logarithmic scale and the resistivity of copper at $3, rm K$.
$endgroup$
There is a problem with answering your question in that at such a low temperature the resistivity of copper is very much determined by the impurities and crystallographic defects eg dislocations, voids etc, which may be present.
At low temperatures it is the scattering of free electrons by impurities and crystallographic defects high determine the resistivity rather than the thermal excitation of the copper ions.
The parameter which is often measured is the residual resistance ratio $dfracR_text273 KR_4.2,rm K$ which for fairly pure copper wire as used for telephone lines might be of the order of $100$.
Large single crystals of very pure copper can be produced with residual resistance ratios in the thousands.
.
Update as answers to some of @AJK’s questions.
Annotated graph to illustrate the non-linear logarithmic scale and the resistivity of copper at $3, rm K$.
edited 6 hours ago
answered 6 hours ago
FarcherFarcher
55k3 gold badges44 silver badges118 bronze badges
55k3 gold badges44 silver badges118 bronze badges
$begingroup$
so it's impossible to use copper at any temperature around 3k as a conductor
$endgroup$
– AJK
6 hours ago
$begingroup$
@AJK That is not what I wrote. From the graph you can get an estimate of the resistivity of “ordinary” copper at around $3,rm K$. At this temperature the copper is a much better conductor of electricity than at room temperature.
$endgroup$
– Farcher
6 hours ago
1
$begingroup$
How do we get the estimate
$endgroup$
– AJK
6 hours ago
$begingroup$
@AJK From the graph noting that it is a log-log graph.
$endgroup$
– Farcher
6 hours ago
1
$begingroup$
I have no clue what that means
$endgroup$
– AJK
6 hours ago
|
show 3 more comments
$begingroup$
so it's impossible to use copper at any temperature around 3k as a conductor
$endgroup$
– AJK
6 hours ago
$begingroup$
@AJK That is not what I wrote. From the graph you can get an estimate of the resistivity of “ordinary” copper at around $3,rm K$. At this temperature the copper is a much better conductor of electricity than at room temperature.
$endgroup$
– Farcher
6 hours ago
1
$begingroup$
How do we get the estimate
$endgroup$
– AJK
6 hours ago
$begingroup$
@AJK From the graph noting that it is a log-log graph.
$endgroup$
– Farcher
6 hours ago
1
$begingroup$
I have no clue what that means
$endgroup$
– AJK
6 hours ago
$begingroup$
so it's impossible to use copper at any temperature around 3k as a conductor
$endgroup$
– AJK
6 hours ago
$begingroup$
so it's impossible to use copper at any temperature around 3k as a conductor
$endgroup$
– AJK
6 hours ago
$begingroup$
@AJK That is not what I wrote. From the graph you can get an estimate of the resistivity of “ordinary” copper at around $3,rm K$. At this temperature the copper is a much better conductor of electricity than at room temperature.
$endgroup$
– Farcher
6 hours ago
$begingroup$
@AJK That is not what I wrote. From the graph you can get an estimate of the resistivity of “ordinary” copper at around $3,rm K$. At this temperature the copper is a much better conductor of electricity than at room temperature.
$endgroup$
– Farcher
6 hours ago
1
1
$begingroup$
How do we get the estimate
$endgroup$
– AJK
6 hours ago
$begingroup$
How do we get the estimate
$endgroup$
– AJK
6 hours ago
$begingroup$
@AJK From the graph noting that it is a log-log graph.
$endgroup$
– Farcher
6 hours ago
$begingroup$
@AJK From the graph noting that it is a log-log graph.
$endgroup$
– Farcher
6 hours ago
1
1
$begingroup$
I have no clue what that means
$endgroup$
– AJK
6 hours ago
$begingroup$
I have no clue what that means
$endgroup$
– AJK
6 hours ago
|
show 3 more comments
AJK is a new contributor. Be nice, and check out our Code of Conduct.
AJK is a new contributor. Be nice, and check out our Code of Conduct.
AJK is a new contributor. Be nice, and check out our Code of Conduct.
AJK is a new contributor. Be nice, and check out our Code of Conduct.
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