Link of a singularityClosed image of a product of morphismsThe link of a singular quintic hypersurface in CP^4Smoothing of a hyperquotient singularityHow can one determine if a singularity is simple?Étale coverings of cubics and gluingsDoes the link of a hypersurface singularity determine its analytic type?A direct proof of a property of symmetric 2x2-determinantsLength of fibers of $(mathbbA^n)^dtomathrmSym^d(mathbbA^n)$Intersection of two quadrics in $mathbbR P^5$Resolving the base locus of a linear system on product projective space

Link of a singularity


Closed image of a product of morphismsThe link of a singular quintic hypersurface in CP^4Smoothing of a hyperquotient singularityHow can one determine if a singularity is simple?Étale coverings of cubics and gluingsDoes the link of a hypersurface singularity determine its analytic type?A direct proof of a property of symmetric 2x2-determinantsLength of fibers of $(mathbbA^n)^dtomathrmSym^d(mathbbA^n)$Intersection of two quadrics in $mathbbR P^5$Resolving the base locus of a linear system on product projective space













4












$begingroup$


I would like to understand the topological type of a link of a singularity in a simple example. Consider for instance the cone $xy-z^2=0subsetmathbbC^3$.
If we set $x = x_1+ix_2, y = y_1+iy_2, z = z_1+iz_2$ then this corresponds to the $4$-dimensional real subvariety of $mathbbR^6$ given as the complete intersection $x_1y_1-x_2y_2-z_1^2+z_2^2 = x_1y_2+x_2y_1-2z_1z_2 = 0$.



Therefore the link of the singularity is given by



$x_1y_1-x_2y_2-z_1^2+z_2^2 = 0, x_1y_2+x_2y_1-2z_1z_2 = 0, x_1^2+x_2^2+y_1^2+y_2^2+z_1^2+z_2^2 = 1$



What is the topological type of this link?



Can we determine the topological type of the link from these three equations?










share|cite|improve this question











$endgroup$
















    4












    $begingroup$


    I would like to understand the topological type of a link of a singularity in a simple example. Consider for instance the cone $xy-z^2=0subsetmathbbC^3$.
    If we set $x = x_1+ix_2, y = y_1+iy_2, z = z_1+iz_2$ then this corresponds to the $4$-dimensional real subvariety of $mathbbR^6$ given as the complete intersection $x_1y_1-x_2y_2-z_1^2+z_2^2 = x_1y_2+x_2y_1-2z_1z_2 = 0$.



    Therefore the link of the singularity is given by



    $x_1y_1-x_2y_2-z_1^2+z_2^2 = 0, x_1y_2+x_2y_1-2z_1z_2 = 0, x_1^2+x_2^2+y_1^2+y_2^2+z_1^2+z_2^2 = 1$



    What is the topological type of this link?



    Can we determine the topological type of the link from these three equations?










    share|cite|improve this question











    $endgroup$














      4












      4








      4


      2



      $begingroup$


      I would like to understand the topological type of a link of a singularity in a simple example. Consider for instance the cone $xy-z^2=0subsetmathbbC^3$.
      If we set $x = x_1+ix_2, y = y_1+iy_2, z = z_1+iz_2$ then this corresponds to the $4$-dimensional real subvariety of $mathbbR^6$ given as the complete intersection $x_1y_1-x_2y_2-z_1^2+z_2^2 = x_1y_2+x_2y_1-2z_1z_2 = 0$.



      Therefore the link of the singularity is given by



      $x_1y_1-x_2y_2-z_1^2+z_2^2 = 0, x_1y_2+x_2y_1-2z_1z_2 = 0, x_1^2+x_2^2+y_1^2+y_2^2+z_1^2+z_2^2 = 1$



      What is the topological type of this link?



      Can we determine the topological type of the link from these three equations?










      share|cite|improve this question











      $endgroup$




      I would like to understand the topological type of a link of a singularity in a simple example. Consider for instance the cone $xy-z^2=0subsetmathbbC^3$.
      If we set $x = x_1+ix_2, y = y_1+iy_2, z = z_1+iz_2$ then this corresponds to the $4$-dimensional real subvariety of $mathbbR^6$ given as the complete intersection $x_1y_1-x_2y_2-z_1^2+z_2^2 = x_1y_2+x_2y_1-2z_1z_2 = 0$.



      Therefore the link of the singularity is given by



      $x_1y_1-x_2y_2-z_1^2+z_2^2 = 0, x_1y_2+x_2y_1-2z_1z_2 = 0, x_1^2+x_2^2+y_1^2+y_2^2+z_1^2+z_2^2 = 1$



      What is the topological type of this link?



      Can we determine the topological type of the link from these three equations?







      ag.algebraic-geometry at.algebraic-topology gn.general-topology differential-topology singularity-theory






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited 9 hours ago







      japin

















      asked 9 hours ago









      japinjapin

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          3 Answers
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          6












          $begingroup$

          More generally, consider the singularity given by $$x_1^2+cdots+x_n+1^2=0$$ in $mathbfC^n+1$. (Your case is $n=2$ after a change of variables.) Identifying $mathbfC^n+1=mathbfR^n+1timesmathbfR^n+1$ we see at once that the link is the Stiefel manifold $mathrmV_2(mathbfR^n+1)$ of pairs of orthonormal vectors in $mathbfR^n+1$. (For $n=2$ this is $mathrmSO(3)$, which is homeomorphic to $mathbfRP^3$.) If you allow more complicated exponents in the defining equation of the singularity, the link can be very interesting.
          For example, the links of the singularities defined by
          $$x_1^2+x_2^2+x_3^2+x_4^3+x_5^6k-1=0 (1leqslant kleqslant 28)$$
          give all 28 differentiable structures on $S^7$. (See for example E. Brieskorn's classic paper Beispiele zur Differentialtopologie von Singularitäten).






          share|cite|improve this answer











          $endgroup$




















            4












            $begingroup$

            For singularities of the form $g(x,y)+z^n = 0$ there is a nice description: if you project onto the $xy$-plane (and you take a very small neighbourhood of the origin), you can view the link of the (surface) singularity as the cyclic $n$-fold cover of $S^3$ branched over the link of the (curve) singularity determined by $g$.



            In the case at hand, $g(x,y) = xy$ and $n=2$, so its link is the Hopf link in $S^3$, and the double cover of $S^3$ branched over it is the lens space $L(2,1)$ (also known as $mathbbRP^3$). More generally, for arbitrary $n$ (and the same $g$), you get the lens space $L(n,n-1)$ ($+n$-surgery on the unknot).






            share|cite|improve this answer









            $endgroup$




















              4












              $begingroup$

              To add to the excellent answers already provided, here are some general facts in the case of rational surface singularities (1 and 2) and hypersurface singularities (3).



              1. Many interesting singularities are obtained by quotienting $C^2$ by the action of a finite subgroup $Gsubset U(2)$. Since $U(2)$ preserves the unit sphere, you can get the link just by quotienting $S^3$ by $G$. The example you gave is equivalent to the singularity you get by taking the quotient of $C^2$ by the subgroup $G=I,-I$, so that tells you the link is $RP^3$, as Marco pointed out. For cyclic quotient singularities, you'll get a lens space. There are more exotic examples, for example, for the spin double cover of the symmetry group of the icosahedron (under the covering map $SU(2)to SO(3)$), the link of the quotient singularity will be the Poincaré homology sphere. If you want to understand these singularities as affine varieties, they're obtained by taking Spec of the ring of invariants for the finite group action on the ring of polynomial functions on $C^2$ (for $G=I,-I$the invariant functions are generated by $u=x^2,v=xy,w=y^2$ with the obvious relation $uw=v^2$, which is where your equation comes into it).


              2. Take the minimal resolution of the singularity. Let's suppose the exceptional divisor is a tree T of spheres with negative self-intersection numbers. A neighbourhood of the exceptional divisor is then a plumbing (according to the tree) of disc bundles over spheres with Euler numbers given by these self-intersection numbers. This has a surgery description: you take a bunch (one for each vertex of T) of unknots in $S^3$ such that two of them link like a Hopf link if they are connected by an edge in T (and are pairwise unlinked otherwise). Give each unknot a framing of minus the self-intersection of the corresponding sphere. This is both a Kirby diagram of the minimal resolution and a Dehn surgery presentation of the link (the exceptional curves in the minimal resolution are given by slice discs for the unknots capped off by the cores of the 2-handles you attach).


              3. If you have a complex hypersurface singularity (i.e. one defined by a single equation over C) then you can use the ideas of Milnor to get at the topology of the link (see his book on isolated singularities of complex hypersurfaces). This will give you an "open book decomposition" of the link, i.e. you end up finding a collection of knots (called the "binding") in the link of the singularity whose complement fibres over the circle (the fibres are real surfaces called the "pages"). In higher dimensions, the binding is a real codimension 2 contact submanifold of the link and the pages are real codimension 1 Stein domains.






              share|cite|improve this answer











              $endgroup$















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                3 Answers
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                active

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                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                6












                $begingroup$

                More generally, consider the singularity given by $$x_1^2+cdots+x_n+1^2=0$$ in $mathbfC^n+1$. (Your case is $n=2$ after a change of variables.) Identifying $mathbfC^n+1=mathbfR^n+1timesmathbfR^n+1$ we see at once that the link is the Stiefel manifold $mathrmV_2(mathbfR^n+1)$ of pairs of orthonormal vectors in $mathbfR^n+1$. (For $n=2$ this is $mathrmSO(3)$, which is homeomorphic to $mathbfRP^3$.) If you allow more complicated exponents in the defining equation of the singularity, the link can be very interesting.
                For example, the links of the singularities defined by
                $$x_1^2+x_2^2+x_3^2+x_4^3+x_5^6k-1=0 (1leqslant kleqslant 28)$$
                give all 28 differentiable structures on $S^7$. (See for example E. Brieskorn's classic paper Beispiele zur Differentialtopologie von Singularitäten).






                share|cite|improve this answer











                $endgroup$

















                  6












                  $begingroup$

                  More generally, consider the singularity given by $$x_1^2+cdots+x_n+1^2=0$$ in $mathbfC^n+1$. (Your case is $n=2$ after a change of variables.) Identifying $mathbfC^n+1=mathbfR^n+1timesmathbfR^n+1$ we see at once that the link is the Stiefel manifold $mathrmV_2(mathbfR^n+1)$ of pairs of orthonormal vectors in $mathbfR^n+1$. (For $n=2$ this is $mathrmSO(3)$, which is homeomorphic to $mathbfRP^3$.) If you allow more complicated exponents in the defining equation of the singularity, the link can be very interesting.
                  For example, the links of the singularities defined by
                  $$x_1^2+x_2^2+x_3^2+x_4^3+x_5^6k-1=0 (1leqslant kleqslant 28)$$
                  give all 28 differentiable structures on $S^7$. (See for example E. Brieskorn's classic paper Beispiele zur Differentialtopologie von Singularitäten).






                  share|cite|improve this answer











                  $endgroup$















                    6












                    6








                    6





                    $begingroup$

                    More generally, consider the singularity given by $$x_1^2+cdots+x_n+1^2=0$$ in $mathbfC^n+1$. (Your case is $n=2$ after a change of variables.) Identifying $mathbfC^n+1=mathbfR^n+1timesmathbfR^n+1$ we see at once that the link is the Stiefel manifold $mathrmV_2(mathbfR^n+1)$ of pairs of orthonormal vectors in $mathbfR^n+1$. (For $n=2$ this is $mathrmSO(3)$, which is homeomorphic to $mathbfRP^3$.) If you allow more complicated exponents in the defining equation of the singularity, the link can be very interesting.
                    For example, the links of the singularities defined by
                    $$x_1^2+x_2^2+x_3^2+x_4^3+x_5^6k-1=0 (1leqslant kleqslant 28)$$
                    give all 28 differentiable structures on $S^7$. (See for example E. Brieskorn's classic paper Beispiele zur Differentialtopologie von Singularitäten).






                    share|cite|improve this answer











                    $endgroup$



                    More generally, consider the singularity given by $$x_1^2+cdots+x_n+1^2=0$$ in $mathbfC^n+1$. (Your case is $n=2$ after a change of variables.) Identifying $mathbfC^n+1=mathbfR^n+1timesmathbfR^n+1$ we see at once that the link is the Stiefel manifold $mathrmV_2(mathbfR^n+1)$ of pairs of orthonormal vectors in $mathbfR^n+1$. (For $n=2$ this is $mathrmSO(3)$, which is homeomorphic to $mathbfRP^3$.) If you allow more complicated exponents in the defining equation of the singularity, the link can be very interesting.
                    For example, the links of the singularities defined by
                    $$x_1^2+x_2^2+x_3^2+x_4^3+x_5^6k-1=0 (1leqslant kleqslant 28)$$
                    give all 28 differentiable structures on $S^7$. (See for example E. Brieskorn's classic paper Beispiele zur Differentialtopologie von Singularitäten).







                    share|cite|improve this answer














                    share|cite|improve this answer



                    share|cite|improve this answer








                    edited 1 hour ago

























                    answered 9 hours ago









                    Mere ScribeMere Scribe

                    1,1062 gold badges8 silver badges21 bronze badges




                    1,1062 gold badges8 silver badges21 bronze badges





















                        4












                        $begingroup$

                        For singularities of the form $g(x,y)+z^n = 0$ there is a nice description: if you project onto the $xy$-plane (and you take a very small neighbourhood of the origin), you can view the link of the (surface) singularity as the cyclic $n$-fold cover of $S^3$ branched over the link of the (curve) singularity determined by $g$.



                        In the case at hand, $g(x,y) = xy$ and $n=2$, so its link is the Hopf link in $S^3$, and the double cover of $S^3$ branched over it is the lens space $L(2,1)$ (also known as $mathbbRP^3$). More generally, for arbitrary $n$ (and the same $g$), you get the lens space $L(n,n-1)$ ($+n$-surgery on the unknot).






                        share|cite|improve this answer









                        $endgroup$

















                          4












                          $begingroup$

                          For singularities of the form $g(x,y)+z^n = 0$ there is a nice description: if you project onto the $xy$-plane (and you take a very small neighbourhood of the origin), you can view the link of the (surface) singularity as the cyclic $n$-fold cover of $S^3$ branched over the link of the (curve) singularity determined by $g$.



                          In the case at hand, $g(x,y) = xy$ and $n=2$, so its link is the Hopf link in $S^3$, and the double cover of $S^3$ branched over it is the lens space $L(2,1)$ (also known as $mathbbRP^3$). More generally, for arbitrary $n$ (and the same $g$), you get the lens space $L(n,n-1)$ ($+n$-surgery on the unknot).






                          share|cite|improve this answer









                          $endgroup$















                            4












                            4








                            4





                            $begingroup$

                            For singularities of the form $g(x,y)+z^n = 0$ there is a nice description: if you project onto the $xy$-plane (and you take a very small neighbourhood of the origin), you can view the link of the (surface) singularity as the cyclic $n$-fold cover of $S^3$ branched over the link of the (curve) singularity determined by $g$.



                            In the case at hand, $g(x,y) = xy$ and $n=2$, so its link is the Hopf link in $S^3$, and the double cover of $S^3$ branched over it is the lens space $L(2,1)$ (also known as $mathbbRP^3$). More generally, for arbitrary $n$ (and the same $g$), you get the lens space $L(n,n-1)$ ($+n$-surgery on the unknot).






                            share|cite|improve this answer









                            $endgroup$



                            For singularities of the form $g(x,y)+z^n = 0$ there is a nice description: if you project onto the $xy$-plane (and you take a very small neighbourhood of the origin), you can view the link of the (surface) singularity as the cyclic $n$-fold cover of $S^3$ branched over the link of the (curve) singularity determined by $g$.



                            In the case at hand, $g(x,y) = xy$ and $n=2$, so its link is the Hopf link in $S^3$, and the double cover of $S^3$ branched over it is the lens space $L(2,1)$ (also known as $mathbbRP^3$). More generally, for arbitrary $n$ (and the same $g$), you get the lens space $L(n,n-1)$ ($+n$-surgery on the unknot).







                            share|cite|improve this answer












                            share|cite|improve this answer



                            share|cite|improve this answer










                            answered 5 hours ago









                            Marco GollaMarco Golla

                            5,4043 gold badges28 silver badges47 bronze badges




                            5,4043 gold badges28 silver badges47 bronze badges





















                                4












                                $begingroup$

                                To add to the excellent answers already provided, here are some general facts in the case of rational surface singularities (1 and 2) and hypersurface singularities (3).



                                1. Many interesting singularities are obtained by quotienting $C^2$ by the action of a finite subgroup $Gsubset U(2)$. Since $U(2)$ preserves the unit sphere, you can get the link just by quotienting $S^3$ by $G$. The example you gave is equivalent to the singularity you get by taking the quotient of $C^2$ by the subgroup $G=I,-I$, so that tells you the link is $RP^3$, as Marco pointed out. For cyclic quotient singularities, you'll get a lens space. There are more exotic examples, for example, for the spin double cover of the symmetry group of the icosahedron (under the covering map $SU(2)to SO(3)$), the link of the quotient singularity will be the Poincaré homology sphere. If you want to understand these singularities as affine varieties, they're obtained by taking Spec of the ring of invariants for the finite group action on the ring of polynomial functions on $C^2$ (for $G=I,-I$the invariant functions are generated by $u=x^2,v=xy,w=y^2$ with the obvious relation $uw=v^2$, which is where your equation comes into it).


                                2. Take the minimal resolution of the singularity. Let's suppose the exceptional divisor is a tree T of spheres with negative self-intersection numbers. A neighbourhood of the exceptional divisor is then a plumbing (according to the tree) of disc bundles over spheres with Euler numbers given by these self-intersection numbers. This has a surgery description: you take a bunch (one for each vertex of T) of unknots in $S^3$ such that two of them link like a Hopf link if they are connected by an edge in T (and are pairwise unlinked otherwise). Give each unknot a framing of minus the self-intersection of the corresponding sphere. This is both a Kirby diagram of the minimal resolution and a Dehn surgery presentation of the link (the exceptional curves in the minimal resolution are given by slice discs for the unknots capped off by the cores of the 2-handles you attach).


                                3. If you have a complex hypersurface singularity (i.e. one defined by a single equation over C) then you can use the ideas of Milnor to get at the topology of the link (see his book on isolated singularities of complex hypersurfaces). This will give you an "open book decomposition" of the link, i.e. you end up finding a collection of knots (called the "binding") in the link of the singularity whose complement fibres over the circle (the fibres are real surfaces called the "pages"). In higher dimensions, the binding is a real codimension 2 contact submanifold of the link and the pages are real codimension 1 Stein domains.






                                share|cite|improve this answer











                                $endgroup$

















                                  4












                                  $begingroup$

                                  To add to the excellent answers already provided, here are some general facts in the case of rational surface singularities (1 and 2) and hypersurface singularities (3).



                                  1. Many interesting singularities are obtained by quotienting $C^2$ by the action of a finite subgroup $Gsubset U(2)$. Since $U(2)$ preserves the unit sphere, you can get the link just by quotienting $S^3$ by $G$. The example you gave is equivalent to the singularity you get by taking the quotient of $C^2$ by the subgroup $G=I,-I$, so that tells you the link is $RP^3$, as Marco pointed out. For cyclic quotient singularities, you'll get a lens space. There are more exotic examples, for example, for the spin double cover of the symmetry group of the icosahedron (under the covering map $SU(2)to SO(3)$), the link of the quotient singularity will be the Poincaré homology sphere. If you want to understand these singularities as affine varieties, they're obtained by taking Spec of the ring of invariants for the finite group action on the ring of polynomial functions on $C^2$ (for $G=I,-I$the invariant functions are generated by $u=x^2,v=xy,w=y^2$ with the obvious relation $uw=v^2$, which is where your equation comes into it).


                                  2. Take the minimal resolution of the singularity. Let's suppose the exceptional divisor is a tree T of spheres with negative self-intersection numbers. A neighbourhood of the exceptional divisor is then a plumbing (according to the tree) of disc bundles over spheres with Euler numbers given by these self-intersection numbers. This has a surgery description: you take a bunch (one for each vertex of T) of unknots in $S^3$ such that two of them link like a Hopf link if they are connected by an edge in T (and are pairwise unlinked otherwise). Give each unknot a framing of minus the self-intersection of the corresponding sphere. This is both a Kirby diagram of the minimal resolution and a Dehn surgery presentation of the link (the exceptional curves in the minimal resolution are given by slice discs for the unknots capped off by the cores of the 2-handles you attach).


                                  3. If you have a complex hypersurface singularity (i.e. one defined by a single equation over C) then you can use the ideas of Milnor to get at the topology of the link (see his book on isolated singularities of complex hypersurfaces). This will give you an "open book decomposition" of the link, i.e. you end up finding a collection of knots (called the "binding") in the link of the singularity whose complement fibres over the circle (the fibres are real surfaces called the "pages"). In higher dimensions, the binding is a real codimension 2 contact submanifold of the link and the pages are real codimension 1 Stein domains.






                                  share|cite|improve this answer











                                  $endgroup$















                                    4












                                    4








                                    4





                                    $begingroup$

                                    To add to the excellent answers already provided, here are some general facts in the case of rational surface singularities (1 and 2) and hypersurface singularities (3).



                                    1. Many interesting singularities are obtained by quotienting $C^2$ by the action of a finite subgroup $Gsubset U(2)$. Since $U(2)$ preserves the unit sphere, you can get the link just by quotienting $S^3$ by $G$. The example you gave is equivalent to the singularity you get by taking the quotient of $C^2$ by the subgroup $G=I,-I$, so that tells you the link is $RP^3$, as Marco pointed out. For cyclic quotient singularities, you'll get a lens space. There are more exotic examples, for example, for the spin double cover of the symmetry group of the icosahedron (under the covering map $SU(2)to SO(3)$), the link of the quotient singularity will be the Poincaré homology sphere. If you want to understand these singularities as affine varieties, they're obtained by taking Spec of the ring of invariants for the finite group action on the ring of polynomial functions on $C^2$ (for $G=I,-I$the invariant functions are generated by $u=x^2,v=xy,w=y^2$ with the obvious relation $uw=v^2$, which is where your equation comes into it).


                                    2. Take the minimal resolution of the singularity. Let's suppose the exceptional divisor is a tree T of spheres with negative self-intersection numbers. A neighbourhood of the exceptional divisor is then a plumbing (according to the tree) of disc bundles over spheres with Euler numbers given by these self-intersection numbers. This has a surgery description: you take a bunch (one for each vertex of T) of unknots in $S^3$ such that two of them link like a Hopf link if they are connected by an edge in T (and are pairwise unlinked otherwise). Give each unknot a framing of minus the self-intersection of the corresponding sphere. This is both a Kirby diagram of the minimal resolution and a Dehn surgery presentation of the link (the exceptional curves in the minimal resolution are given by slice discs for the unknots capped off by the cores of the 2-handles you attach).


                                    3. If you have a complex hypersurface singularity (i.e. one defined by a single equation over C) then you can use the ideas of Milnor to get at the topology of the link (see his book on isolated singularities of complex hypersurfaces). This will give you an "open book decomposition" of the link, i.e. you end up finding a collection of knots (called the "binding") in the link of the singularity whose complement fibres over the circle (the fibres are real surfaces called the "pages"). In higher dimensions, the binding is a real codimension 2 contact submanifold of the link and the pages are real codimension 1 Stein domains.






                                    share|cite|improve this answer











                                    $endgroup$



                                    To add to the excellent answers already provided, here are some general facts in the case of rational surface singularities (1 and 2) and hypersurface singularities (3).



                                    1. Many interesting singularities are obtained by quotienting $C^2$ by the action of a finite subgroup $Gsubset U(2)$. Since $U(2)$ preserves the unit sphere, you can get the link just by quotienting $S^3$ by $G$. The example you gave is equivalent to the singularity you get by taking the quotient of $C^2$ by the subgroup $G=I,-I$, so that tells you the link is $RP^3$, as Marco pointed out. For cyclic quotient singularities, you'll get a lens space. There are more exotic examples, for example, for the spin double cover of the symmetry group of the icosahedron (under the covering map $SU(2)to SO(3)$), the link of the quotient singularity will be the Poincaré homology sphere. If you want to understand these singularities as affine varieties, they're obtained by taking Spec of the ring of invariants for the finite group action on the ring of polynomial functions on $C^2$ (for $G=I,-I$the invariant functions are generated by $u=x^2,v=xy,w=y^2$ with the obvious relation $uw=v^2$, which is where your equation comes into it).


                                    2. Take the minimal resolution of the singularity. Let's suppose the exceptional divisor is a tree T of spheres with negative self-intersection numbers. A neighbourhood of the exceptional divisor is then a plumbing (according to the tree) of disc bundles over spheres with Euler numbers given by these self-intersection numbers. This has a surgery description: you take a bunch (one for each vertex of T) of unknots in $S^3$ such that two of them link like a Hopf link if they are connected by an edge in T (and are pairwise unlinked otherwise). Give each unknot a framing of minus the self-intersection of the corresponding sphere. This is both a Kirby diagram of the minimal resolution and a Dehn surgery presentation of the link (the exceptional curves in the minimal resolution are given by slice discs for the unknots capped off by the cores of the 2-handles you attach).


                                    3. If you have a complex hypersurface singularity (i.e. one defined by a single equation over C) then you can use the ideas of Milnor to get at the topology of the link (see his book on isolated singularities of complex hypersurfaces). This will give you an "open book decomposition" of the link, i.e. you end up finding a collection of knots (called the "binding") in the link of the singularity whose complement fibres over the circle (the fibres are real surfaces called the "pages"). In higher dimensions, the binding is a real codimension 2 contact submanifold of the link and the pages are real codimension 1 Stein domains.







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                                    Jonny EvansJonny Evans

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