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Surely they can fit?


Find a heptagon with mirror symmetry that can tile a flat planeMax 4x1 pattern fit within 11x11 areaFit as many overlapping generators as possible













1












$begingroup$


Suppose you have a grid of squares that has even dimensions, with at least one dimension greater than or equal to 4 squares, and from one corner you remove a 1x4 rectangle of those squares



for example:



□□□□□□
□□□□□□
□□□□□□
XXXX□□


Can you fill in that grid using as many copies of the following shapes as you like?



(Each shape can be rotated any of the four ways, and can be flipped/mirrored)



□□
□□



□□
□□



□□□□
□□□□


If you can, provide an example solution. If you cannot, then you should provide a reasonable argument to why it can't be done.










share|improve this question









$endgroup$
















    1












    $begingroup$


    Suppose you have a grid of squares that has even dimensions, with at least one dimension greater than or equal to 4 squares, and from one corner you remove a 1x4 rectangle of those squares



    for example:



    □□□□□□
    □□□□□□
    □□□□□□
    XXXX□□


    Can you fill in that grid using as many copies of the following shapes as you like?



    (Each shape can be rotated any of the four ways, and can be flipped/mirrored)



    □□
    □□



    □□
    □□



    □□□□
    □□□□


    If you can, provide an example solution. If you cannot, then you should provide a reasonable argument to why it can't be done.










    share|improve this question









    $endgroup$














      1












      1








      1





      $begingroup$


      Suppose you have a grid of squares that has even dimensions, with at least one dimension greater than or equal to 4 squares, and from one corner you remove a 1x4 rectangle of those squares



      for example:



      □□□□□□
      □□□□□□
      □□□□□□
      XXXX□□


      Can you fill in that grid using as many copies of the following shapes as you like?



      (Each shape can be rotated any of the four ways, and can be flipped/mirrored)



      □□
      □□



      □□
      □□



      □□□□
      □□□□


      If you can, provide an example solution. If you cannot, then you should provide a reasonable argument to why it can't be done.










      share|improve this question









      $endgroup$




      Suppose you have a grid of squares that has even dimensions, with at least one dimension greater than or equal to 4 squares, and from one corner you remove a 1x4 rectangle of those squares



      for example:



      □□□□□□
      □□□□□□
      □□□□□□
      XXXX□□


      Can you fill in that grid using as many copies of the following shapes as you like?



      (Each shape can be rotated any of the four ways, and can be flipped/mirrored)



      □□
      □□



      □□
      □□



      □□□□
      □□□□


      If you can, provide an example solution. If you cannot, then you should provide a reasonable argument to why it can't be done.







      tiling






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 2 hours ago









      micsthepickmicsthepick

      2,49111127




      2,49111127




















          1 Answer
          1






          active

          oldest

          votes


















          3












          $begingroup$

          No, you cannot:




          Color the grid like this.

          enter image description here


          Since the grid (before removal of the four cells) has even dimensions, it is made up of 2x2 blocks with each color once. So each color appears the same number of times.


          All of the given shapes will always cover the same number of squares of each color: the first two cover one of each, and the last covers two of each. But after marking off the unused cells, the grid has more red and blue cells than yellow and green. So you can't cover the grid perfectly.







          share|improve this answer









          $endgroup$












          • $begingroup$
            that’s pretty much my reasoning!
            $endgroup$
            – micsthepick
            30 mins ago











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          1 Answer
          1






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          active

          oldest

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          active

          oldest

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          3












          $begingroup$

          No, you cannot:




          Color the grid like this.

          enter image description here


          Since the grid (before removal of the four cells) has even dimensions, it is made up of 2x2 blocks with each color once. So each color appears the same number of times.


          All of the given shapes will always cover the same number of squares of each color: the first two cover one of each, and the last covers two of each. But after marking off the unused cells, the grid has more red and blue cells than yellow and green. So you can't cover the grid perfectly.







          share|improve this answer









          $endgroup$












          • $begingroup$
            that’s pretty much my reasoning!
            $endgroup$
            – micsthepick
            30 mins ago















          3












          $begingroup$

          No, you cannot:




          Color the grid like this.

          enter image description here


          Since the grid (before removal of the four cells) has even dimensions, it is made up of 2x2 blocks with each color once. So each color appears the same number of times.


          All of the given shapes will always cover the same number of squares of each color: the first two cover one of each, and the last covers two of each. But after marking off the unused cells, the grid has more red and blue cells than yellow and green. So you can't cover the grid perfectly.







          share|improve this answer









          $endgroup$












          • $begingroup$
            that’s pretty much my reasoning!
            $endgroup$
            – micsthepick
            30 mins ago













          3












          3








          3





          $begingroup$

          No, you cannot:




          Color the grid like this.

          enter image description here


          Since the grid (before removal of the four cells) has even dimensions, it is made up of 2x2 blocks with each color once. So each color appears the same number of times.


          All of the given shapes will always cover the same number of squares of each color: the first two cover one of each, and the last covers two of each. But after marking off the unused cells, the grid has more red and blue cells than yellow and green. So you can't cover the grid perfectly.







          share|improve this answer









          $endgroup$



          No, you cannot:




          Color the grid like this.

          enter image description here


          Since the grid (before removal of the four cells) has even dimensions, it is made up of 2x2 blocks with each color once. So each color appears the same number of times.


          All of the given shapes will always cover the same number of squares of each color: the first two cover one of each, and the last covers two of each. But after marking off the unused cells, the grid has more red and blue cells than yellow and green. So you can't cover the grid perfectly.








          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 43 mins ago









          DeusoviDeusovi

          64.1k6221277




          64.1k6221277











          • $begingroup$
            that’s pretty much my reasoning!
            $endgroup$
            – micsthepick
            30 mins ago
















          • $begingroup$
            that’s pretty much my reasoning!
            $endgroup$
            – micsthepick
            30 mins ago















          $begingroup$
          that’s pretty much my reasoning!
          $endgroup$
          – micsthepick
          30 mins ago




          $begingroup$
          that’s pretty much my reasoning!
          $endgroup$
          – micsthepick
          30 mins ago

















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