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How to define command with 2 optional params such that it calls another command (accepting 1 optional param) to which it passes one of those 2 params?
Conditionals in newcommandPass key option inside a macro to a TikZ drawing commandWrite a command that dynamically calls the argument of another commandHow do you define one macro with arguments inside anothercustom hatching pattern : arbitrary direction of hatchingHow to define such a command with an optional argument in my class?How to define a command that defines another command?How to define a newcommand that expands into another newcommandDefine latex command in which argument is part of another commandHow to define a command with two optional arguments?
documentclassstandalone
usepackagetikz
newcountermyC
newcommandmyN % I need optional parameter here which is set to zero by default and which will replace zero below
thenumexpr(valuemyC-0)
% command below should accept 2 optional parameters (one of which is already defined as "north" but can contain other values, like "south")
newcommandmyL[1][north]
% I need to be able to call myN here either without parameter (like below), which will make it default to predefined value (of zero) or to call it with a value supplied by the user)
path[draw=red](myN.#1 west)--(myN.#1 east);
begindocument
begintikzpicture
path node[draw,/utils/exec=stepcountermyC](1)one;
myL
path node[draw,/utils/exec=stepcountermyC](2)two;
myL
endtikzpicture
enddocument
EDIT (for @Red-Cloud):
I can do
newcommandmyN[1]thenumexpr(valuemyC-#1)
NewDocumentCommandmyTO0Onorthpath[draw=red](myN0.west)--(1,0);
but as soon as myN is rewritten to allow for an optional argument, it doesn't work
newcommandmyN[1][0]thenumexpr(valuemyC-#1)
% square brackets now instead of curly braces
NewDocumentCommandmyTO0Onorthpath[draw=red](myN[0].west)--(1,0);
Why is that? I need myN to accept an optional arg.
macros
asked 4 hours ago
bp2017bp2017
879114
add a comment |
documentclassstandalone
usepackagetikz
newcountermyC
newcommandmyN % I need optional parameter here which is set to zero by default and which will replace zero below
thenumexpr(valuemyC-0)
% command below should accept 2 optional parameters (one of which is already defined as "north" but can contain other values, like "south")
newcommandmyL[1][north]
% I need to be able to call myN here either without parameter (like below), which will make it default to predefined value (of zero) or to call it with a value supplied by the user)
path[draw=red](myN.#1 west)--(myN.#1 east);
begindocument
begintikzpicture
path node[draw,/utils/exec=stepcountermyC](1)one;
myL
path node[draw,/utils/exec=stepcountermyC](2)two;
myL
endtikzpicture
enddocument
EDIT (for @Red-Cloud):
I can do
newcommandmyN[1]thenumexpr(valuemyC-#1)
NewDocumentCommandmyTO0Onorthpath[draw=red](myN0.west)--(1,0);
but as soon as myN is rewritten to allow for an optional argument, it doesn't work
newcommandmyN[1][0]thenumexpr(valuemyC-#1)
% square brackets now instead of curly braces
NewDocumentCommandmyTO0Onorthpath[draw=red](myN[0].west)--(1,0);
Why is that? I need myN to accept an optional arg.
macros
asked 4 hours ago
bp2017bp2017
879114
I'm not quite understanding. I see howmyLhas one optional parameter, and can be called bymyLormyL[south]. How does the other optional parameter fit in? How do you intend to callmyL?
– Teepeemm
2 hours ago
path[draw=red](myN.#1 west)--(myN.#1 east);makes no sense here because it doesn't use the second optional parameter #2 (default north)
– Red-Cloud
1 hour ago
add a comment |
documentclassstandalone
usepackagetikz
newcountermyC
newcommandmyN % I need optional parameter here which is set to zero by default and which will replace zero below
thenumexpr(valuemyC-0)
% command below should accept 2 optional parameters (one of which is already defined as "north" but can contain other values, like "south")
newcommandmyL[1][north]
% I need to be able to call myN here either without parameter (like below), which will make it default to predefined value (of zero) or to call it with a value supplied by the user)
path[draw=red](myN.#1 west)--(myN.#1 east);
begindocument
begintikzpicture
path node[draw,/utils/exec=stepcountermyC](1)one;
myL
path node[draw,/utils/exec=stepcountermyC](2)two;
myL
endtikzpicture
enddocument
EDIT (for @Red-Cloud):
I can do
newcommandmyN[1]thenumexpr(valuemyC-#1)
NewDocumentCommandmyTO0Onorthpath[draw=red](myN0.west)--(1,0);
but as soon as myN is rewritten to allow for an optional argument, it doesn't work
newcommandmyN[1][0]thenumexpr(valuemyC-#1)
% square brackets now instead of curly braces
NewDocumentCommandmyTO0Onorthpath[draw=red](myN[0].west)--(1,0);
Why is that? I need myN to accept an optional arg.
macros
asked 4 hours ago
bp2017bp2017
879114
documentclassstandalone
usepackagetikz
newcountermyC
newcommandmyN % I need optional parameter here which is set to zero by default and which will replace zero below
thenumexpr(valuemyC-0)
% command below should accept 2 optional parameters (one of which is already defined as "north" but can contain other values, like "south")
newcommandmyL[1][north]
% I need to be able to call myN here either without parameter (like below), which will make it default to predefined value (of zero) or to call it with a value supplied by the user)
path[draw=red](myN.#1 west)--(myN.#1 east);
begindocument
begintikzpicture
path node[draw,/utils/exec=stepcountermyC](1)one;
myL
path node[draw,/utils/exec=stepcountermyC](2)two;
myL
endtikzpicture
enddocument
EDIT (for @Red-Cloud):
I can do
newcommandmyN[1]thenumexpr(valuemyC-#1)
NewDocumentCommandmyTO0Onorthpath[draw=red](myN0.west)--(1,0);
but as soon as myN is rewritten to allow for an optional argument, it doesn't work
newcommandmyN[1][0]thenumexpr(valuemyC-#1)
% square brackets now instead of curly braces
NewDocumentCommandmyTO0Onorthpath[draw=red](myN[0].west)--(1,0);
Why is that? I need myN to accept an optional arg.
macros
macros
asked 4 hours ago
bp2017bp2017
879114
asked 4 hours ago
bp2017bp2017
879114
edited 18 mins ago
bp2017
asked 4 hours ago
bp2017bp2017
879114
asked 4 hours ago
bp2017bp2017
879114
asked 4 hours ago
bp2017bp2017
879114
879114
I'm not quite understanding. I see howmyLhas one optional parameter, and can be called bymyLormyL[south]. How does the other optional parameter fit in? How do you intend to callmyL?
– Teepeemm
2 hours ago
path[draw=red](myN.#1 west)--(myN.#1 east);makes no sense here because it doesn't use the second optional parameter #2 (default north)
– Red-Cloud
1 hour ago
add a comment |
I'm not quite understanding. I see howmyLhas one optional parameter, and can be called bymyLormyL[south]. How does the other optional parameter fit in? How do you intend to callmyL?
– Teepeemm
2 hours ago
path[draw=red](myN.#1 west)--(myN.#1 east);makes no sense here because it doesn't use the second optional parameter #2 (default north)
– Red-Cloud
1 hour ago
I'm not quite understanding. I see how
myL has one optional parameter, and can be called by myL or myL[south]. How does the other optional parameter fit in? How do you intend to call myL?– Teepeemm
2 hours ago
I'm not quite understanding. I see how
myL has one optional parameter, and can be called by myL or myL[south]. How does the other optional parameter fit in? How do you intend to call myL?– Teepeemm
2 hours ago
path[draw=red](myN.#1 west)--(myN.#1 east); makes no sense here because it doesn't use the second optional parameter #2 (default north)– Red-Cloud
1 hour ago
path[draw=red](myN.#1 west)--(myN.#1 east); makes no sense here because it doesn't use the second optional parameter #2 (default north)– Red-Cloud
1 hour ago
add a comment |
2 Answers
2
active
oldest
votes
newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax
usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
path[draw=red](myN.#1 west)--(myN.#1 east);%
But makes no real sense in your example
answered 1 hour ago
Red-CloudRed-Cloud
1,61911
Please checkEDITpart (on the bottom) in my question.
– bp2017
17 mins ago
add a comment |
It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:
documentclass[tikz, border=5mm]standalone
usepackagexparse
newcountermyC
NewDocumentCommandmyLOnorth O0%
defmyCthenumexpr(themyC-#2)
path[draw=red](myC.#1 west)--(myC.#1 east);
begindocument
begintikzpicture[mystep/.code=stepcountermyC]
path node[draw,mystep](1)at (themyC,0)one;
myL
path node[draw,mystep](2)at (themyC,0)two;
myL
endtikzpicture
enddocument
Here is the output:
Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.
answered 1 hour ago
AndrewAndrew
32.5k34684
I neednewcommandwhich you removed. I also use it for other means.
– bp2017
11 mins ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax
usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
path[draw=red](myN.#1 west)--(myN.#1 east);%
But makes no real sense in your example
answered 1 hour ago
Red-CloudRed-Cloud
1,61911
Please checkEDITpart (on the bottom) in my question.
– bp2017
17 mins ago
add a comment |
newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax
usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
path[draw=red](myN.#1 west)--(myN.#1 east);%
But makes no real sense in your example
answered 1 hour ago
Red-CloudRed-Cloud
1,61911
Please checkEDITpart (on the bottom) in my question.
– bp2017
17 mins ago
add a comment |
newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax
usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
path[draw=red](myN.#1 west)--(myN.#1 east);%
But makes no real sense in your example
answered 1 hour ago
Red-CloudRed-Cloud
1,61911
newcountermyC
newcommandmyN[1][0]thenumexprvaluemyC-#1relax
usepackagexparse
NewDocumentCommandmyL O1 Onorth %. #1 is a number, #2 north, ..
path[draw=red](myN.#1 west)--(myN.#1 east);%
But makes no real sense in your example
answered 1 hour ago
Red-CloudRed-Cloud
1,61911
answered 1 hour ago
Red-CloudRed-Cloud
1,61911
answered 1 hour ago
Red-CloudRed-Cloud
1,61911
answered 1 hour ago
Red-CloudRed-Cloud
1,61911
1,61911
Please checkEDITpart (on the bottom) in my question.
– bp2017
17 mins ago
add a comment |
Please checkEDITpart (on the bottom) in my question.
– bp2017
17 mins ago
Please check
EDIT part (on the bottom) in my question.– bp2017
17 mins ago
Please check
EDIT part (on the bottom) in my question.– bp2017
17 mins ago
add a comment |
It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:
documentclass[tikz, border=5mm]standalone
usepackagexparse
newcountermyC
NewDocumentCommandmyLOnorth O0%
defmyCthenumexpr(themyC-#2)
path[draw=red](myC.#1 west)--(myC.#1 east);
begindocument
begintikzpicture[mystep/.code=stepcountermyC]
path node[draw,mystep](1)at (themyC,0)one;
myL
path node[draw,mystep](2)at (themyC,0)two;
myL
endtikzpicture
enddocument
Here is the output:
Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.
answered 1 hour ago
AndrewAndrew
32.5k34684
I neednewcommandwhich you removed. I also use it for other means.
– bp2017
11 mins ago
add a comment |
It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:
documentclass[tikz, border=5mm]standalone
usepackagexparse
newcountermyC
NewDocumentCommandmyLOnorth O0%
defmyCthenumexpr(themyC-#2)
path[draw=red](myC.#1 west)--(myC.#1 east);
begindocument
begintikzpicture[mystep/.code=stepcountermyC]
path node[draw,mystep](1)at (themyC,0)one;
myL
path node[draw,mystep](2)at (themyC,0)two;
myL
endtikzpicture
enddocument
Here is the output:
Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.
answered 1 hour ago
AndrewAndrew
32.5k34684
I neednewcommandwhich you removed. I also use it for other means.
– bp2017
11 mins ago
add a comment |
It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:
documentclass[tikz, border=5mm]standalone
usepackagexparse
newcountermyC
NewDocumentCommandmyLOnorth O0%
defmyCthenumexpr(themyC-#2)
path[draw=red](myC.#1 west)--(myC.#1 east);
begindocument
begintikzpicture[mystep/.code=stepcountermyC]
path node[draw,mystep](1)at (themyC,0)one;
myL
path node[draw,mystep](2)at (themyC,0)two;
myL
endtikzpicture
enddocument
Here is the output:
Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.
answered 1 hour ago
AndrewAndrew
32.5k34684
It is not clear to me what you are trying to do, but I don't think that you need two macros and that this following code might do want you want:
documentclass[tikz, border=5mm]standalone
usepackagexparse
newcountermyC
NewDocumentCommandmyLOnorth O0%
defmyCthenumexpr(themyC-#2)
path[draw=red](myC.#1 west)--(myC.#1 east);
begindocument
begintikzpicture[mystep/.code=stepcountermyC]
path node[draw,mystep](1)at (themyC,0)one;
myL
path node[draw,mystep](2)at (themyC,0)two;
myL
endtikzpicture
enddocument
Here is the output:
Note in particular the use of a .code statement to step the counter. I also added some coordinates for placing the nodes in the path statements since otherwise everything is drawn on top of each other.
answered 1 hour ago
AndrewAndrew
32.5k34684
answered 1 hour ago
AndrewAndrew
32.5k34684
answered 1 hour ago
AndrewAndrew
32.5k34684
answered 1 hour ago
AndrewAndrew
32.5k34684
32.5k34684
I neednewcommandwhich you removed. I also use it for other means.
– bp2017
11 mins ago
add a comment |
I neednewcommandwhich you removed. I also use it for other means.
– bp2017
11 mins ago
I need
newcommand which you removed. I also use it for other means.– bp2017
11 mins ago
I need
newcommand which you removed. I also use it for other means.– bp2017
11 mins ago
add a comment |
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I'm not quite understanding. I see how
myLhas one optional parameter, and can be called bymyLormyL[south]. How does the other optional parameter fit in? How do you intend to callmyL?– Teepeemm
2 hours ago
path[draw=red](myN.#1 west)--(myN.#1 east);makes no sense here because it doesn't use the second optional parameter #2 (default north)– Red-Cloud
1 hour ago